It a car travels 2km in 1 hour what is the speed

Answer:

The minimum coefficient of friction required is 0.35.  

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

\( -F_{f} + F = 0 \)      

\( -F_{f} + ma = 0 \)      

\( \mu mg = ma \)

\( \mu = \frac{a}{g} \)

Where:

μ: is the coefficient of friction

m: is the mass of the crate

g: is the gravity

a: is the acceleration of the truck

The acceleration of the truck can be found by using the following equation:

\( v_{f}^{2} = v_{0}^{2} + 2ad \)

\( a = \frac{v_{f}^{2} - v_{0}^{2}}{2d} \)

Where:  

d: is the distance traveled = 46.1 m

\( v_{f}\): is the final speed of the truck = 0 (it stops)      

\(v_{0}\): is the initial speed of the truck = 17.9 m/s

\( a = \frac{-(17.9 m/s)^{2}}{2*46.1 m} = -3.48 m/s^{2} \)        

If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.  

\( \mu = \frac{a}{g} \)  

\( \mu = \frac{3.48 m/s^{2}}{9.81 m/s^{2}} \)

\( \mu = 0.35 \)

Therefore, the minimum coefficient of friction required is 0.35.  

I hope it helps you!

Answer:

Explanation:

Use Archimedes' principle, that states something of this nature: "The buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced"

Say, you take a cube of wood(for example) and place it in a bucket of water. Your cube is bound to sink, until, the upthrust force equals its weight.

Where does this upthrust come from?

As the cube sinks, it displaced some volume of water(if the bucket were full you would see water pouring out)

Archimedes simply stated that: Upthrust,

U=mg

People use drugs for many reasons: they want to feel good, stop feeling bad, or perform better in school or at work, or they are curious because others are doing it and they want to fit in. The last reason is very common among teens.Drugs excite the parts of the brain that make you feel good. But after you take a drug for a while, the feel-good parts of your brain get used to it. Then you need to take more of the drug to get the same good feeling. Soon, your brain and body must have the drug just to feel normal. You feel sick, awful, anxious, and irritable without the drug. You no longer have the good feelings that you had when you first used the drug. This is true if you use illegal drugs or if you misuse prescription drugs. Misuse includes taking a drug differently than how your doctor tells you to (taking more or crushing pills to "shoot up" or snort), taking someone else’s prescription, or taking it just to get “high.”

If a rose with the genotype Yy is pale yellow in color, then there is not complete dominance for neither allele and it is a case of incomplete dominance. Nonetheless, since allele Y is for pale yellow and the hybrid has this phenotype, then it is partially dominant (pale yellow, Y, option 3).

Incomplete dominance is a genetic phenomenon in which one of the two alleles present for a given gene locus is expressed more strongly when compared to the other allele, which is called partially dominant and partially recessive alleles, respectively.

Conversely, complete dominance is due to the presence of an allele that completely masks the expression of the recessive allele in heterozygous hybrid individuals.

Therefore, with this data, we can see that incomplete dominance is associated with the expression of both alleles in the heterozygous hybrid individuals.

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The temperature of a substance is determined by the average kinetic energy of its particles, so Substance X and Substance Y have higher temperatures because their particles have more kinetic energy. The number of particles does not affect temperature. The correct options are (A) and (C).

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Answer:

B) Mass is a measurement of force

Explanation:

Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.

Answer:

that is the right answer

Explanation:

Image is missing, so i have attached it

Answer:

Tension in back wire = 24.5 N

Explanation:

let the tension in the back wire be Tₒ

let the tension in the front wire be T

Applying static equilibrium in the vertical direction, we have:

T + Tₒ = (5 × 9.8) + (2.5 × 9.8)

T + Tₒ = 73.5

Where Tₒ = (2.5 × 9.8) = 24.5 N

Thus, Tension in back wire = 24.5 N

The tension in the back wire equals 24.5 N.

We can arrive at this answer with the static equilibrium formula, for that, let's consider that the tension in the back wire is represented by the letter "t," while the tension in the front wire is represented by the letter "T."

Therefore, we can use the following formula:

\(t= W*g\\t= 2,5*9.8\\t= 24.5 N\)

In this case, the letter "W" refers to the tool weight, while the letter "g" refers to gravity.

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Answer:

\( {3}^{n} \)

Explanation:

https://www.doubtnut.com/question-answers/a-cellphone-weighs-about-28x10n-pounds-which-value-of-n-is-most-reasonable-a-3-b-2-c-0-d-1-433477

The value of  the missing resistance, R₃ = 10.35 ohms.

The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.

The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.

The values of the missing component of the circuit is calculated by applying the following formula.

The total resistance of the circuit;

For R₂, R₃, 1/R = 1/R₂ + 1/R₃

1/R = 1/12 +  1/R₃

1/R = (R₃ + 1)/(12R₃)

R = 12R₃ / (R₃ + 1)

For, R₁, R₂ and R₃, total resistance;

R = 12R₃ / (R₃ + 1) + R₁

R = [12R₃ / (R₃ + 1)] + 2

R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)

R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)

R = (14R₃ + 2 ) / (R₃ + 1)

The total current in circuit is calculated as;

I = V/R

I = 30 / R

I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)

I = (30R₃ + 30) / (14R₃ + 2) ------- (1)

The voltage in parallel circuit is the same

V₂ = V₃ = 24 V

V₃ = IR₃

24 = IR₃

I = 24/R₃  --------- (2)

Solve (1) and (2) together as follows;

24/R₃ = (30R₃ + 30) / (14R₃ + 2)

30R₃² - 306R - 48 = 0

Solve the quadratic equation, using formula method.

R₃ = 10.35 ohms

I₃ = V₃/R₃

I₃ = 24 V / 10.35

I₃ = 2.32 A

If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V

The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

0.82

Explanation:

constant velocity.means acceleration a = 0, so net force = 0

F - μmg = ma = 0

so μ = F/(mg) = 200/(25*9.8) = 0.82

Answer:

U calculate from CREST to REST POSITION

Answer:

Explanation:

The speed of the second car after the collision can be found using the law of conservation of momentum. The law states that the total momentum of a system remains constant if no external forces act on it.The initial momentum of the first car is (15g)(22 cm/s) = 330 g cm/s to the right.

The initial momentum of the second car is (22g)(-31 cm/s) = -682 g cm/s to the left.

The total initial momentum of the system is 330 g cm/s - 682 g cm/s = -352 g cm/sAfter the collision, the final momentum of the first car is (15g)(-42 cm/s) = -630 g cm/s to the left.

The final momentum of the second car is (m)(v) where m is the mass of the second car and v is the speed after the collision.

The total final momentum of the system is -630 g cm/s + (m)(v) = -352 g cm/s (since it remains constant)Therefore, m*v = -630 g cm/s + 352 g cm/s = -278 g cm/sTo find v, we need to divide the momentum by the mass

v = -278 g cm/s / 22 g = -12.6 cm/sSo the speed of the second car after the collision is -12.6 cm/s to the left.

Answer:

The smallest and largest areas could be 6400 m and 7500 m, respectively.

Explanation:

The area of a rectangle is given by:

\( A = l*w \)

Where:

l: is the length = 100 m

w: is the width

We can calculate the smallest area with the lower value of the width.

\( A_{s} = 100 m*64 m = 6400 m^{2} \)                            

And the largest area is:

\( A_{l} = 100 m*75 m = 7500 m^{2} \)  

Therefore, the smallest and largest areas could be 6400 m and 7500 m, respectively.            

I hope it helps you!                        

Answer:

the largest areas that the field could be is \(A_l\)=7587.75 m

the smallest areas that the field could be is \(A_s\)=6318.25 m

Explanation:

to the find the largest and the smallest area of the field measurement error is to be considered.

we have to find the greatest possible error, since the measurement was made nearest whole mile, the greatest possible error is half of 1 mile and that is 0.5m.

therefore to find the largest possible area we add the error in the mix of the formular for finding the perimeter with the largest width as shown below:

\(A_l\)= (L+0.5)(W+0.5)

(100+0.5)(75+0.5) = (100.5)(75.5) = 7587.75 m

To find the smallest length we will have to subtract instead of adding the error factor value of 0.5 as shown below:

\(A_s\)= (L-0.5)(W-0.5)

(100-0.5)(64-0.5) = (99.5)(63.5) = 6318.25 m

The current that flows through the 75 ohm resistor in the circuit shown below is 0.12A.

The current flowing through a circuit can be calculated using the Ohm's law equation as follows;

V = IR

Where;

According to this question, a circuit is shown in the above image. A 75 ohm resistor is given alongside a voltage of 9V. The current can be calculated as follows;

9 = I × 75

I = 0.12A

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Answer:

inertia of motion

Explanation:

it's because when a passenger is jumping from a bus his/her body is in motion after falling in a road he/she remains or tends to remain in the state of motion that is the reason

The three ways an emf can be induced in the loop are changing the magnetic field, changing the area of the loop and changing the angle between the field and the loop.

Faraday's first law of electromagnetic induction states that whenever a conductor is placed in a varying magnetic field, an electromotive force is induced.

Mathematically, the formula for Faraday's first law is given as;

E = - ( N dФ ) / ( dt )

where;

The three ( 3 ) ways an emf can be induced in the loop is listed below;

To induced an emf in a loop, there must be change in the magnetic flux of the loop.

Mathematically, the formula for magnetic flux is given as;

Ф = BA cosθ

where;

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The following vector components are:

a) A+ B - 84.21°

b) A-B - 18.74°

c) B-A - -84.21°

To use components to find the given vectors, break each vector into its x and y components using trigonometry.

Assume the positive x-axis points to the right and the positive y-axis points up.

For vector A, the magnitude of the x-component is given by Acos(60°) and the magnitude of the y-component is given by Asin(60°),

Ax = Acos(60°) = 2.8 cm × 0.5 = 1.4 cm

Ay = Asin(60°) = 2.8 cm × 0.866 = 2.425 cm

For vector B,  the negative sign since the vector is below the x-axis,

Bx = Bcos(60°) = 1.9 cm × 0.5 = 0.95 cm

By = -Bsin(60°) = -1.9 cm × 0.866 = -1.6494 cm

a) To find A + B, add the x and y components separately:

(A + B)x = Ax + Bx = 1.4 cm + 0.95 cm = 2.35 cm

(A + B)y = Ay + By = 2.425 cm - 1.6494 cm = 0.7756 cm

Then, the vector A + B has a magnitude of √[(2.35 cm)² + (0.7756 cm)²] = 2.466 cm and an angle of tan⁻¹(0.7756 cm / 2.35 cm) = 18.74° above the positive x-axis.

b) To find A - B, subtract the x and y components separately:

(A - B)x = Ax - Bx = 1.4 cm - 0.95 cm = 0.45 cm

(A - B)y = Ay - By = 2.425 cm + 1.6494 cm = 4.0744 cm

Then, the vector A - B has a magnitude of √[(0.45 cm)² + (4.0744 cm)²] = 4.091 cm and an angle of tan⁻¹(4.0744 cm / 0.45 cm) = 84.21° above the positive x-axis.

c) To find B - A, subtract the x and y components separately:

(B - A)x = Bx - Ax = 0.95 cm - 1.4 cm = -0.45 cm

(B - A)y = By - Ay = -1.6494 cm - 2.425 cm = -4.0744 cm

Then, the vector B - A has a magnitude of √[(-0.45 cm)² + (-4.0744 cm)²] = 4.091 cm and an angle of tan⁻¹(-4.0744 cm / -0.45 cm) = -84.21° below the positive x-axis.

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Answer:

The sun and the stars

Explanation:

I hope this helps!

Answer:

Northstar & North Pole

Explanation:

yyggggggggggggggg

Answer:

HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!

Explanation:

HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!

Icecaps and Glaciers

Explanation:

Icecaps and Glaciers hold 68 percent of fresh water on earth :)

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

c

Explanation:

The final speed of the cars after the collision is determined as 6.16 m/s.

The final speed of the cars after the collision is calculated from the principle of conservation of linear momentum as shown bellow.

m1v1 + m2v2 = v(m1 + m2)

where;

Substitute the given parameters and solve for "v".

1250(0) + 3550(8.33) = v(1250 + 3550)

29,571.5 = 4800v

v = 29571.5/4800

v = 6.16 m/s

Thus, the final speed of the cars after the collision is determined as 6.16 m/s.

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Answer:

REVIEWS

Wing-Kuen Ling, in Nonlinear Digital Filters, 2007

Controllability and observability

For a continuous time system, assume that x(0) = 0. ∀x1, if ∃t1 > 0 and u(t) such that x(t1) = x1, then the continuous time system is said to be reachable. Similarly, for a discrete time system, assume that x(0) = 0. ∀x1, if ∃n1 > 0 and u(n) such that x(n1) = x1, then the discrete time system is said to be reachable. For a continuous time system, if ∀x0, x1, ∃t1 > 0 and u(t) such that x(0) = x0 and x(t1) = x1, then the continuous time system is said to be controllable. Similarly, for a discrete time system, if ∀x0, x1, ∃n1 > 0 and u(n) such that x(0) = x0 and x(n1 = x1, then the discrete time system is said to be controllable. For LTI systems, the set of reachable state is R(|BAB… AnB|), where R(A) is defined as the range of A, that is R(A) = {y : y = Ax}. Also, the LTI systems are controllable if and only if R(A) = Rn Or in other words, rank(|BAB… AnB|) = n.

The moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

To calculate the moment M applied to the disc that holds the system in equilibrium, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the counterclockwise moments about the same point.

Let's consider point C as the pivot point. The clockwise moments are produced by the weight of BC and the unknown moment M, while the counterclockwise moments are produced by the weight of AB.

The weight of BC can be calculated as W_BC = linear density * length = 1 kg/m * 0.3 m = 0.3 kg.

The clockwise moment is given by M_clockwise = W_BC * BC = 0.3 kg * 0.3 m = 0.09 Nm.

Since the system is in equilibrium, the clockwise moments must balance the counterclockwise moments. Therefore, the counterclockwise moment produced by the weight of AB is also 0.09 Nm.

Hence, the moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

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Answer:

b

Explanation: