Is what I selected right? Which step has a mistake?

Hello !

you made a typo with the c^-2 because otherwise it does not make a round result

\(a^{2} *b^{2} *c^{2} \\\\= 1^{2} *2^{2}* (-3)^{2} \\\\= 1*4*9\\\\\boxed{= 36}\)

Answer:

at least 160 students have to buy a ticket to cover the show's cost.

Step-by-step explanation:

1200 divided by 7.50 = 160.

Answer:

for the y=5

for the x=-1 2/3

minimum

axis is (-1,2)

Step-by-step

explanation:

f(0)=5

-3x=5

x=-5/3

Answer: The numerators must be the same for the fractions to be equal.

The denominator of a fraction is the bottom number. Take a look at these two fractions.

¾ & ¾

The numbers at the bottom are the same. If I eat ¾ of an apple and you eat ¾ of an apple, we both eat the same amount.

Now look at these fractions.

⅗ & ¾

They both have the same top number (numerator), but they have different denominators. If I eat ¾ of an apple and you eat ⅗ of an apple, we both do not eat the same amount.

So if both the numerator and denominator are the same they are equal.

This means that the numerators must be the same for the fractions to be equal.

I hope this helps & Good Luck <3 !!!

Answer:

6 boxes

Step-by-step explanation:

HCF of 42 and 49 gives us 7.

So, 7 is the greatest number of boxes used if all cookies were packed.

Mark me brainliest thenkss :)

Answer:

Factor by grouping. (3r + 5)(r-3)

Step-by-step explanation:

Answer:

33× w^3 × w^2 or

33w^5

Step-by-step explanation:

Let the unknown variable be w

\(33\times w^3\times w^2\)

Simplify

\(=33w^5\)

Answer:

33w^3 w^2

Step-by-step explanation:

The ^3 is supposed to cube the first w

and ^2 is supposed to square the second w

Answer:

x = 3

Step-by-step explanation:

The first option is the correct one for the line y = x - 2:

" coordinate plane with a line starting at (negative 2, negative 4), passing through (0, negative 2)"

Here we want to identify the graph of the linear equation:

y = x - 2

First, notice that when we evaluate this in x = 0 we get the y-intercept:

y = 0 - 2

y = -2

Then the y-intercept there is (0, -2)

Also, evaluating the linear equation in x = -2, then we will get:

y = -2 - 2

y = -4

So we have the point (-2, -4)

Then the correct option is the first one:

" coordinate plane with a line starting at (negative 2, negative 4), passing through (0, negative 2)"

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Answer:

x=100 degree's

Step-by-step explanation:

Its 100 degrees because you add 80 and 20 degrees and because I think they might be called congruent angles.

Answer:

pretty sure it's just 100, just add 80 and 20, angles are opposite of each other.

Answer:

3.5

Step-by-step explanation:

bc its higher hope helps

Answer:

\(\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}\)

This can be easily calculated by substituting the value of radius in the formula of area ~

\(Area \: = \pi \: r {}^{2} \\ \\ \implies \: \frac{22}{7} \times 8 \times 8 \\ \\ \implies \: \frac{1408}{7} \\ \\ \implies \: 201.14 \: miles {}^{2} \)

hope helpful ~

\(\huge\color{pink}\boxed{\colorbox{Black}{♔︎Answer♔︎}}\)

200.96 miles²

Step-by-step explanation:

\( \textsf{\underline{\large{To find :-}}}\)

The area of circle

\( \textsf{\underline{\large{Given :-}}}\)

radius of circle (r) = 8 miles

\( \textsf{\underline{\underline{\huge{Solution :-}}}}\)

\( \sf \blue {Area \: of \: circle = \pi {r}^{2} }\)

now we will substitute the value of r

\( \sf \implies Area = \pi {8}^{2} \\ \\ \sf \implies Area = \pi \times 8 \times 8\)

\( \sf \pi = \frac{22}{7} \: or \: 3.14 \\ \sf here \: we \: will \: use \: \pi = 3.14\)

\( \sf \implies Area = 3.14 \times 8 \times 8 \\ \\ \sf \implies { \green{ Area = 200.96 \: {miles}^{2} }}\)

Answer:

5 hours

Step-by-step explanation:

5.6 all you have to use is .6 times 5hours to make 3kmapart

The correct pairings are:

a) Four less than the quotient of a number cubed and seven, increased by three: (n³/7) - 4 + 3

b) Five times the difference of a number squared and six: 5(n² - 6)

c) Nine more than the quotient of six and a number cubed, decreased by four: (6/n³) + 9 - 4

d) O twice the difference of nine and a number squared: 2(9 - n²)

The correct pairings of descriptions and expressions are as follows:

Four less than the quotient of a number cubed and seven, increased by three: (n³/7) - 4 + 3

This expression represents taking a number, cubing it, dividing the result by seven, subtracting four, and then adding three.

Five times the difference of a number squared and six: 5(n² - 6)

This expression represents taking a number, squaring it, subtracting six, and then multiplying the result by five.

Nine more than the quotient of six and a number cubed, decreased by four: (6/n³) + 9 - 4

This expression represents taking the cube of a number, dividing six by the cube, adding nine, and then subtracting four.

O twice the difference of nine and a number squared: 2(9 - n²)

This expression represents taking a number, squaring it, subtracting it from nine, and then multiplying the result by two.

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Answer:

The answer is 16pi or 50.3cm² to 1 d.p

Step-by-step explanation:

The non shaded=area of shaded

d=8

r=d/2=4

A=pir³

A=p1×4²

A=pi×16

A=16picm² or 50.3cm² to 1d.p

Answer:

3.45 cm (3 s.f.)

Step-by-step explanation:

We have been given a 5-sided regular polygon inside a circumcircle. A circumcircle is a circle that passes through all the vertices of a given polygon. Therefore, the radius of the circumcircle is also the radius of the polygon.

To find the radius of a regular polygon given its side length, we can use this formula:

\(\boxed{\begin{minipage}{6 cm}\underline{Radius of a regular polygon}\\\\$r=\dfrac{s}{2\sin\left(\dfrac{180^{\circ}}{n}\right)}$\\\\\\where:\\\phantom{ww}$\bullet$ $r$ is the radius.\\ \phantom{ww}$\bullet$ $s$ is the side length.\\\phantom{ww}$\bullet$ $n$ is the number of sides.\\\end{minipage}}\)

Substitute the given side length, s = 8 cm, and the number of sides of the polygon, n = 5, into the radius formula to find an expression for the radius of the polygon (and circumcircle):

\(\begin{aligned}\implies r&=\dfrac{8}{2\sin\left(\dfrac{180^{\circ}}{5}\right)}\\\\ &=\dfrac{4}{\sin\left(36^{\circ}\right)}\\\\ \end{aligned}\)

The formulas for the area of a regular polygon and the area of a circle given their radii are:

\(\boxed{\begin{minipage}{6 cm}\underline{Area of a regular polygon}\\\\$A=\dfrac{nr^2\sin\left(\dfrac{360^{\circ}}{n}\right)}{2}$\\\\\\where:\\\phantom{ww}$\bullet$ $A$ is the area.\\\phantom{ww}$\bullet$ $r$ is the radius.\\ \phantom{ww}$\bullet$ $n$ is the number of sides.\\\end{minipage}}\)

\(\boxed{\begin{minipage}{6 cm}\underline{Area of a circle}\\\\$A=\pi r^2$\\\\where:\\\phantom{ww}$\bullet$ $A$ is the area.\\\phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}\)

Therefore, the area of the regular pentagon is:

\(\begin{aligned}\textsf{Area of polygon}&=\dfrac{5 \cdot \left(\dfrac{4}{\sin\left(36^{\circ}\right)}\right)^2\sin\left(\dfrac{360^{\circ}}{5}\right)}{2}\\\\&=\dfrac{5 \cdot \left(\dfrac{4}{\sin\left(36^{\circ}\right)}\right)^2\sin\left(72^{\circ}\right)}{2}\\\\&=\dfrac{\dfrac{80\sin\left(72^{\circ}\right)}{\sin^2\left(36^{\circ}\right)}}{2}\\\\&=\dfrac{40\sin\left(72^{\circ}\right)}{\sin^2\left(36^{\circ}\right)}\\\\&=110.110553...\; \sf cm^2\end{aligned}\)

The area of the circumcircle is:

\(\begin{aligned}\textsf{Area of circumcircle}&=\pi \left(\dfrac{4}{\sin\left(36^{\circ}\right)}\right)^2\\\\&=\dfrac{16\pi}{\sin^2\left(36^{\circ}\right)}\\\\&=145.489779...\; \sf cm^2\end{aligned}\)

The area of the shaded area is the area of the circumcircle less the area of the regular pentagon plus the area of the small central circle.

The area of the unshaded area is the area of the regular pentagon less the area of the small central circle.

Given the shaded area is equal to the unshaded area:

\(\begin{aligned}\textsf{Shaded area}&=\textsf{Unshaded area}\\\\\sf Area_{circumcircle}-Area_{polygon}+Area_{circle}&=\sf Area_{polygon}-Area_{circle}\\\\\sf 2\cdot Area_{circle}&=\sf 2\cdot Area_{polygon}-Area_{circumcircle}\\\\2\pi r^2&=2 \cdot \dfrac{40\sin\left(72^{\circ}\right)}{\sin^2\left(36^{\circ}\right)}-\dfrac{16\pi}{\sin^2\left(36^{\circ}\right)}\\\\2\pi r^2&=\dfrac{80\sin\left(72^{\circ}\right)}{\sin^2\left(36^{\circ}\right)}-\dfrac{16\pi}{\sin^2\left(36^{\circ}\right)}\\\\\end{aligned}\)

                                                 \(\begin{aligned}2\pi r^2&=\dfrac{80\sin\left(72^{\circ}\right)-16\pi}{\sin^2\left(36^{\circ}\right)}\\\\r^2&=\dfrac{40\sin\left(72^{\circ}\right)-8\pi}{\pi \sin^2\left(36^{\circ}\right)}\\\\r&=\sqrt{\dfrac{40\sin\left(72^{\circ}\right)-8\pi}{\pi \sin^2\left(36^{\circ}\right)}}\\\\r&=3.44874763...\sf cm\end{aligned}\)

Therefore, the radius of the small circle is 3.45 cm (3 s.f.).

Answer:

A

Step-by-step explanation:

Part A: To find the x-intercepts of the graph of f(x), we set f(x) equal to zero and solve for x:

2x² - x - 10 = 0

This equation can be factored as:

(2x + 5)(x - 2) = 0

Setting each factor equal to zero, we get:

2x + 5 = 0 => 2x = -5 => x = -5/2

x - 2 = 0 => x = 2

Therefore, the x-intercepts of the graph of f(x) are x = -5/2 and x = 2.

Part B: The vertex of the graph of f(x) can be determined using the formula x = -b/2a, where a and b are the coefficients of the quadratic equation in standard form (ax² + bx + c = 0).

In this case, a = 2 and b = -1. Plugging these values into the formula, we have:

x = -(-1) / (2 * 2) = 1/4

To determine if the vertex is a maximum or a minimum, we can examine the coefficient of the x² term. Since the coefficient a is positive (a = 2), the parabola opens upwards, and the vertex represents a minimum point

Therefore, the vertex of the graph of f(x) is (1/4, f(1/4)), where f(1/4) can be obtained by substituting x = 1/4 into the equation f(x).

Part C: To graph f(x), we can follow these steps:

Plot the x-intercepts: Plot the points (-5/2, 0) and (2, 0) on the x-axis.

Plot the vertex: Plot the point (1/4, f(1/4)) as the vertex, where f(1/4) can be obtained by substituting x = 1/4 into the equation f(x).

Determine the direction of the graph: Since the coefficient of the x² term is positive, the graph opens upwards from the vertex.

Determine additional points: Choose a few x-values on either side of the vertex and calculate their corresponding y-values by substituting them into the equation f(x). Plot these points on the graph.

Draw the graph: Connect the plotted points smoothly, following the shape of the parabola. Ensure the graph is symmetrical with respect to the vertex.

The answers obtained in Part A (x-intercepts) and Part B (vertex) provide crucial points to plot on the graph, helping us determine the shape and position of the parabola.

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The x-intercepts from the graph attached are

The vertex  from the graph attached is

Part A: To find the x-intercepts of the graph of f(x), we set f(x) equal to zero and solve for x:

2x² - x - 10 = 0

x = (-b ± √(b² - 4ac)) / (2a)

a = 2, b = -1, c = -10

Plugging these values into the quadratic formula:

x = (-(-1) ± √((-1)² - 4 * 2 * (-10))) / (2 * 2)

x = (1 ± √(1 + 80)) / 4

x = (1 ± √81) / 4

x = (1 ± 9) / 4

x₁ = (1 + 9) / 4 = 10 / 4 = 2.5

x₂ = (1 - 9) / 4 = -8 / 4 = -2

Therefore, the x-intercepts of the graph of f(x) are 2.5 and -2.

Part B

To find the coordinates of the vertex, we can use the formula:

x = -b / (2a)

x = -(-1) / (2 * 2) = 1 / 4 = 0.25

we substitute this value back into the original function:

f(0.25) = 2(0.25)² - 0.25 - 10

f(0.25) = 0.125 - 0.25 - 10

f(0.25) = -10.125

Therefore, the vertex of the graph of f(x) is located at (0.25, -9.125).

Part C: The steps to graph f(x) include:

Plotting the x-intercepts: Based on the results from Part A, we know that the x-intercepts are 2.5 and -2. We mark these points on the x-axis.

Plotting the vertex: Using the coordinates from Part B, we plot the vertex at (0.25, -9.125). This represents the minimum point of the graph.

Drawing the shape of the graph: Since the coefficient of the x² term is positive, the graph opens upward. From the vertex, the graph will curve upward on both sides.

Additional points and smooth curve: To further sketch the graph, we can choose additional x-values and calculate their corresponding y-values using the equation f(x) = 2x² - x - 10. Plotting these points and connecting them smoothly will give us the shape of the graph.

By using the x-intercepts and vertex obtained in Part A and Part B, we have the necessary information to draw the graph accurately and show the key features of the quadratic function f(x)

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Answer:

11, 13, 17, 19

Step-by-step explanation:

If you look at the prime numbers chart between 10 and 20, there are:

11, 13, 17, 19

Those are all of the prime numbers that are between 10 and 20.

We can complete the blanks with the following ratios:

(7.5 mi/1) * (1 mi/ 5280 ft) * (400ft/1 yd) * (3 ft/1 ft) =33 flags

Since we do not need a flag at the starting line, then 32 flags will be required in total.

To solve the problem, we would first convert 400 yds to feet and miles.

To convert to feet, we multiply by 3. This gives us: 400 yd * 3 = 1200 feet.

To convert to miles, we would have 0.227 miles.

Now, we divide the entire race distance by the number of miles divisions.

This gives us:

7.5 mi /0.227 mi

= 33 flags

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We are given the following information

f(-1) = 16 and f(5) = -8

Which means that

a. Find the distance between these points

Recall that the distance formula is given by

Let us substitute the given points into the above distance formula

Therefore, the distance between these points is √612 = 24.738

b. Find the midpoint between these points

Recall that the midpoint formula is given by

Let us substitute the given points into the above midpoint formula

Therefore, the midpoint of these points is (2, 4)

c. Find the slope between these points

Recall that the slope is given by

Let us substitute the given points into the above slope formula

Therefore, the slope of these points is -4.

Im sorry this isnt a question this is a statement so I dont really understand what i am suppose to be answering here if there is no question

Option a

How?

\(\\ \sf\longmapsto \dfrac{\sqrt{100}}{3}\)

\(\\ \sf\longmapsto \dfrac{10}{3}\)

Hence correct option is a

Hi there! :)

Answer:

\(\huge\boxed{15.87kg}\)

To solve, simply set up a proportion. Let "x" represent the mass of a 95 kg person on the moon:

\(\frac{14.2kg}{85kg} = \frac{x}{95kg}\)

Cross multiply:

\(14.2 * 95 = 85 * x\)

\(1349 = 85x\)

Divide both sides by 85:

\(1349/85 = 85x/85\)

\(x = 15.87 kg\)

Answer:

15kg

Step-by-step explanation:

85/14.2=5.98

95/6=15

Answer:

you divide the cm by 100 to get it in metres form. eg: 500cm=5m

Answer:

If you talking about iready. It's the first pink one.

Step-by-step explanation:

Answer:

the answer should be B, because I think the collection of fruits is right

Answer:

i think its b

Step-by-step explanation:

The missing code that can be used to replace / missing code / so that the code segment works as intended is x >= 10.

The code segment is intended to store the sum of all multiples of 10 between 10 and 100, inclusive. The value of x starts at 100 and is decremented by 10 on each iteration of the loop, until it reaches 10. The sum of all the multiples of 10 between 10 and 100 is stored in the variable total.

The missing code in the while statement determines when the loop will stop. If we use x >= 10 as a replacement for / missing code /, the loop will run as long as x is greater than or equal to 10. When x reaches 10, the loop will stop.

Here's the complete code:

int x = 100;

int total = 0;

while(x >= 10)

{

   total = total + x;

   x = x - 10;

}

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Your question is incomplete but probably the complete question is:

Consider the following code segment, which is intended to store the sum of all multiples of 10 between 10 and 100, inclusive (10 + 20 + ... + 100), in the variable total.

int x = 100;

int total = 0;

while( / missing code / )

{

total = total + x;

x = x - 10;

}

Which of the following can be used as a replacement for / missing code / so that the code segment works as intended?

A x < 100

B x <= 100

C x > 10

D x >= 10

E x != 10

Answer:

D. A pair of intersecting lines

Step-by-step explanation:

A conic section is a fancy name for a curve that you get when you slice a double cone with a plane. Imagine you have two ice cream cones stuck together at the tips, and you cut them with a knife. Depending on how you cut them, you can get different shapes. These shapes are called conic sections, and they include circles, ellipses, parabolas and hyperbolas. If you cut them right at the tip, you get a point. If you cut them slightly above the tip, you get a line. If you cut them at an angle, you get two lines that cross each other. That's what happened in your question. The plane cut the cone at an angle, so the curve is two intersecting lines. That means the correct answer is D. A pair of intersecting lines.

I hope this helps you ace your math question.