a student was marked tardy five different time in a 40 day period. What percent of the times was the student tardy
Answer:
12.5%
Hope this helps!
Answer:
The percentage of times the students marked will be 12.5%.
Thus, 2% is two-hundredth, which means 2%=2/100=0.02.
As per the given,
A student was marked tardy five different times in a 40-day period.
Percentage of 5 among 40 →
(5/40) x 100 = 12.5%
Is this equation an infinite solution, no solution, or one solution?? 7(2+5x) = 3x + 14
Answer:
One Solution
Step-by-step explanation:
Once you solve the equation, you get 0 which satisfies for X, therefore it has a solution.
Answer the question provided in the picture below. (Write a paragraph) 70 points and a brainiest.
how many positive odd factors of 48 are greater than 2 and less than 10
Answer:
Just 1 positive, odd factor
Step-by-step explanation:
48 has many factors. But not many odd factors. Only 3 is odd and bigger than 2 and less than 10.
So, just one odd, positive factor.
S. Maya is spending money at the average rate of $3 per day. After 14 days she has $68 left. The amount left depends on the number of days that have passed. Hint: Is spending money a positive or negative.
1. Write an equation for the situation.
B. Use your equation to find out when she will have $35 left.
C. How much money does Maya have after 9 days?
C. How much money does Maya have after 9 days?
E. Explain what the slope and y-intercept represent for this problem
a) The slope equation representing Maya's spending situation is x - 3n = 68, where x is the initial amount Maya has and n is the number of days she has spent her money.
b) Using the above equation, after 25 days, Maya will have $35 left.
c) Using the above equation, after 9 days, Maya will have $83 left.
d) The slope is the average rate Maya spends per day, which is $3 while the y-intercept represents the initial amount she has.
What is a slope equation?A slope equation is written in the slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
Maya's average spending rate per day = $3
The number of days Maya has spent money = 14 days
The amount left after 14 days = $68
Let the initial amount Maya has = x and the number of days she has spent her money = n
Equation:a) x - 3n = 68
x = 68 + 3n
x = 68 + 3(14)
x = 68 + 42
x = 110
= $110
b) 110 - 3n = 35
-3n = -75
n = 25
c) 110 - 3(9)
= 110 - 27
= 83
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Assume that the sample is a random sample from a distribution that is reasonably normally distributed and that we are doing inference for a population mean. Find the area in a t-distribution to the right of 2.6 if the sample has size n
The area to the right of 2.6 in a t-distribution with n degrees of freedom is 0.9082, assuming the sample is a random sample from a distribution that is reasonably normally distributed and that we are doing inference for a population mean.
We can use a t-distribution table or a statistical software program to find the area to the right of 2.6. Here, I'll show you how to use a t-distribution table:
Determine the degrees of freedom (df) for the t-distribution. This is equal to n - 1.
Look up the t-value that corresponds to a one-tailed probability of 0.05 and df.
Multiply the t-value by -1 to get the positive value for the right tail. In other words, we need the value for the right tail, so we flip the sign of the t-value.
Add 0.5 to the result to account for the area to the left of 2.6. This gives us the cumulative probability from negative infinity to 2.6.
Subtract the result from 1 to get the area to the right of 2.6.
For example, suppose we have a sample of size n = 10. Then, the degrees of freedom for the t-distribution would be df = 10 - 1 = 9. Using a t-distribution table, we can look up the t-value that corresponds to a one-tailed probability of 0.05 and df = 9:
t-value = 1.833
Since we need the positive value for the right tail, we multiply by -1 to get:
t-value = -1.833
Adding 0.5 to account for the left tail gives:
t-value + 0.5 = -1.333
Finally, subtracting this result from 1 gives us the area to the right of 2.6:
Area to the right of 2.6 = 1 - 0.0918 = 0.9082
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i dont understand please answer seriously will give brainliest
8. Center
As the location of the center of the circle is (3, 3).
Therefore, the coordinates of the center are (3, 3)9. Endpoints of a diameter
As we know that the diameter is the magnitude (often called the length) of the line through the center.
Please note that the diameter touches two points on the edge of the circle. Diameter is often called the longest possible chord.From the diagram, it is clear that:
The points of the diameter are (6, 3) and (0, 3).Also, observe the length of a diameter is 6 units.
10. A point of Tangency
We know that at the point of Tangency, the tangent to a circle will always be perpendicular to the radius.
From the diagram, it is clear that:
(6, 3) is the point of tangency. Here the tangent is perpendicular to the radius.11. Endpoints of a chord that is not a diameter
A chord is basically a line that touches two points.
From the diagram, it is clear that:
The coordinates of the chord other than the diameter are (3, 0) and (0, 3).12. Endpoints of a radius
We know that a radius is basically a straight line from the center of a circle to the circumference of a circle.
The length of a radius r = diamter length/2
From the diagram, it is clear that:
The coordinates of the endpoints of the radius are (3, 3) and (6, 3)Which of the following is the independent variable of G(F(y)) ?
A. F(x)
B. x
C.у
D. G(F(y))
SUBMIT
Given:
The composition of functions is G(F(y)).
To find:
The independent variable of G(F(y)).
Solution:
Independent variable is the variable whose value independent from other variable. It means the value of independent variables is not depend on the other variable.
We know that G(F(y)) can be written as
\(G(F(y))=(G\circ F)(y)\)
Here, the value of function G depends on F(y) and the value of F(y) depend on variable y. But value of y does not depend on any variable. So, y is the independent variable of G(F(y)).
Therefore, the correct option is C.
7. Ifa = 3an * db = - 2 . find the values of: (a + b)ab
The Values of (a+b)ab are undefined.
Given that, a = 3an and db = -2We need to find the values of (a+b)
Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1
From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),
we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0
Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined
Therefore, the values of (a+b)ab are undefined.
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An airplane is flying at an altitude of 33,000 feet. It needs to reduce its altitude by 6% to avoid some turbulence. After it passes the turbulence, it increases its altitude by 5000 feet.
What is the final altitude of the airplane?
Enter your answer in the box.
Step-by-step explanation:
100% = 33,000 ft
1% = 100%/100 = 33000/100 = 330 ft
6% = 1% × 6 = 330 × 6 = 1980 ft
that means the plane has to go down 1980 ft to
33,000 - 1980 = 31,020 ft
and then it goes up by 5000 ft :
31,020 + 5000 = 36,020 ft
that is the final altitude.
Answer:
The final altitude of the airplane is 36,020
Step-by-step explanation:
I took the test
Jack and Joan Mitchell, married taxpayers and residents of a separate property state, elect to file a joint return for Year 4 during which they received the following dividends:
Received byJackJoanAlert Corporation (a qualified, domestic corporation)$400$50Canadian Mines, Inc. (a Canadian company)300Eternal Life Mutual Insurance Company (dividends on life insurance policy)200
Total dividends received to date on the life insurance policy do not exceed cumulative premiums paid. For Year 4, what amount should the Mitchells report on their joint return as dividend income?
The Mitchells should report a total of $700 as dividend income on their joint return for Year 4.
Only the dividends received from Alert Corporation, a qualified domestic corporation, and Canadian Mines, Inc., a corporation incorporated in Canada, are taxable. The dividend from Eternal Life Mutual Insurance Company is not taxable since it is a dividend on a life insurance policy and the total dividends received on the policy do not exceed the cumulative premiums paid.
Therefore, the taxable dividends are $400 + $300 = $700.
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DOES SOMEONE KNOW THISSS!!!
Answer:
Step-by-step explanation:
\(a<\sqrt{20}<b\\ \\ a^2<20<b^2\\ \\ 4^2<20<5^2\\ \\ 16<20<25\\ \\ \text{So }\sqrt{20} \text{ is between 4 and 5}\)
5. Find the lowest number which is exactly divisible by 14 and 16.
Answer:
112
Step-by-step explanation:
Find the lowest common multiple of 14 and 16.
To find the lowest common multiple:
1) Break the numbers down into their prime factors.
14 = \(2^{1}\) x \(7^{1}\)
16 = 2 x 8 = 2 x 2 x 4 = 2 x 2 x 2 x 2 = \(2^{4}\)
2) Multiply the highest power of each prime number.
We have three numbers, but only two are unique: \(2^{1}\) , \(7^{1}\) and \(2^{4}\)
\(2^{4}\) > \(2^{1}\) , so we will use \(2^{4}\)
\(7^{1}\) x \(2^{4}\) = 7 x 16 = 112
Please help! (Also show work)
Tutorials :D
The five-number summary is:
Minimum: 9
First Quartile: 16.5
Median: 25.5
Third Quartile: 39
Maximum: 51
3. Range = 42
4. Interquartile range = 22.5
How to Find the Five-number Summary of a Data?Given the data for the lengths as, 36, 15, 9, 22, 36, 14, 42, 45, 51, 29, 18, 20, to find the five-number summary of the data set, we would follow the steps below:
1. The numbers in ordered from the smallest to the largest would be:
9, 14, 15, 18, 20, 22, 29, 36, 36, 42, 45, 51
2. The five-number summary for the lengths in minutes would be:
Minimum value: this is the smallest lengths, which is 9First Quartile (Q1): this is the middle of the first half of the data set of the lengths in minutes, which is 16.5.Median: the median is the center of the data distribution which is 25.5.Third Quartile: this is the middle of the second half of the data set of the lengths in minutes, which is 39.Maximum: this is the largest length in minutes, which is, 51.3. Range of the data = max - min = 51 - 9 = 42
4. The interquartile range for the data set = Q3 - Q1 = 39 - 16.5
Interquartile range for the data set = 22.5
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Use Fermat' s Little Theorem to find all the zeros in Z5 of 2x²¹⁹ + 3x⁷⁴ +2x⁵⁷ +3x⁴⁴.
please help me i need the solution
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Answer:
D, B, D, DStep-by-step explanation:
#17 5/6 - 2 3/5 = 7 25/30 - 2 18/30 = 5 7/30, Option D#24 2/5 + 6/8 = 4 + 2/5 + 3/4 = 4 + 8/20 + 15/20 = 4 23/20 = 5 3/20, Option B#33/8 + 3/4 + 2/6 - 1/2 = 3/8 + 6/8 + 2/6 - 3/6 = 11/8 - 1/6 = 33/24 - 4/24 = 29/24 = 1 5/24, Option D#43 1/2 + 2 1/4 = 3 2/4 + 2 1/4 = 5 3/4, Option DWhat is the solution to 3x + 30+ I= 10 + 2 + 5x + 2? O 6 018 9/2
Answer:
x=8.5
Step-by-step explanation:
3x+31=14+5x
17=2x
x=8.5
Use symmetry to evaluate the double integral. 8xy / (1 + x^4) dA, R R = {(x, y) | −2 ≤ x ≤ 2, 0 ≤ y ≤ 1}
The double integral over the region R is zero
To evaluate the given double integral using symmetry, we can exploit the symmetry of the region of integration, R.
The region R is defined as R = {(x, y) | −2 ≤ x ≤ 2, 0 ≤ y ≤ 1}.
Since the limits of integration for y are from 0 to 1, we notice that the integrand 8xy does not depend on y symmetrically about the x-axis. Therefore, we can conclude that the integral over the entire region R is equal to twice the integral over the lower half of R.
So, we can evaluate the double integral as follows:
∬R (8xy / (1 + x⁴)) dA = \(2\int_{-2}^2 \int_0^1\frac{8xy}{1+x^4} dydx\)
Now, let's evaluate the integral in terms of x:
\(\int_0^1\frac{8xy}{1+x^4}dy\)
This integral is independent of y, so we can treat it as a constant with respect to y:
= \(\frac{8x}{1+x^4} \int_0^1ydy\)
= \(\frac{8x}{1+x^4}[\frac{y^2}{2}]_0^1\)
= (8x / (1 + x⁴)) * (1/2)
= 4x / (1 + x⁴)
Now, we can evaluate the remaining integral with respect to x:
\(2\int_{-2}^2\frac{4x}{1+x^4}dx\) = \(8\int_{-2}^2\frac{x}{1+x^4}dx\)
We can evaluate this integral using symmetry as well. Since the integrand (x / (1 + x⁴)) is an odd function, the integral over the entire range [-2, 2] is equal to zero.
Therefore, the double integral over the region R is zero:
∬R (8xy / (1 + x⁴)) dA = 0.
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Find the mean of the following numbers: 2, 5, 10, 12, 20.
Answer:
9.8
Step-by-step explanation:
Add up all of the numbers, then divide by how many numbers there are
MARKING BRAINLIEST ⚠️⚠️ question is in image
-
**last number in table is 2
HAVING A BAD DAY PLEASE HELP
Find the slope of each line (each block is one unit):
Answer:
1. 7
2. -3
4. -4/6
Step-by-step explanation:
i solved using y2-y1/x2-x1
Answer:
1. slope= 7
2. slope= -3
3. slope= -2/3
Step-by-step explanation
you find slope by doing rise over run (how much you have to go up/down and left/right to get to the next point.
for the first one, to get from the bottom point to the top point, you have to rise 7, and go to the right 1, which makes 7/1, simplified to 1.
for the second one, you go to rise 6, and then go to the left 2, which makes 6/-2, it is negative because when you have to go left, it just means a negative slope. this simplifies to -3
for the third one, you rise 4 and go to the left 6 from the bottom point to the top point. this makes 4/-6, simplifies to -2/3/
hope this help, i'm not the best explainer though, sorry :(
Can someone explain this to me?
Answer:
Its the first answer choice, basically just plug 3a +1 for a and solve
How many solutions does the linear system below have? -8x+2y=6 and -4x+y=3
Answer:
Step-by-step explanation:
Try dividing the first equation by 3. The result will be identical to the second equation. Thus, we have two lines that coincide, and therefore there are an infinite number of solutions.
In the equation a = v/r, if a is plotted against v then what will be the shape of the graph? How about if a is plotted against r?
9514 1404 393
Answer:
a) a straight line
b) a hyperbola
Step-by-step explanation:
a) When a = v/r is plotted against v as the independent variable, it will be a straight line through the origin with a slope of 1/r.
__
b) When a = v/r is plotted against r as the independent variable, it will be a hyperbola with a "constant of proportionality" of v. Here, a is inversely proportional to r.
Please review the toy description below. Answer the following questions:
Jenga is a game played with 54 rectangular blocks. Blocks are stacked into a tower of 13 levels - 3 blocks on each level. Once the tower is built, players take turns removing one block from one of the levels and placing in on the top of the tower. Players can only use one hand to take remove a block from the tower and then place it on the top. The game ends when the tower falls over.
A) What developmental age group(s) is/are this toy appropriate for (e.g., infant & toddler, early childhood, middle childhood, adolescence, young adult)?
B)Why (e.g., what aspects of cognitive, physical, and socioemotional development do you think needs to have already occurred?)? Explain how this toy could promote cognitive, physical, and socioemotional development. Use specific concepts in this explanation.
Clearly define concepts (in your own words!) and be explicit in how you link the toy to each concept. Stronger responses will synthesize a variety of concepts and ideas (e.g., your discussion should not be limited to discussing one theoretical framework). Highlight or bold all concepts used in your explanation.
Answer:
A) The Jenga game is appropriate for the middle childhood age group, typically ranging from around 6 to 12 years old.
B) Jenga promotes cognitive, physical, and socioemotional development in middle childhood through enhancing spatial reasoning and problem-solving skills, improving fine motor skills and proprioceptive input, and fostering social interaction, cooperation, and risk assessment.
Step-by-step explanation:
Jenga, a game played with rectangular blocks, can promote cognitive, physical, and socioemotional development through various concepts.
Cognitive Development: Jenga enhances spatial reasoning as players analyze the tower's structure, evaluate block stability, and strategize their moves. They mentally manipulate objects in space, building an understanding of spatial relationships and balance. Problem-solving skills are fostered as players make decisions about which block to remove, considering the consequences of their actions. They must anticipate the tower's reaction to their moves, think critically, and adjust their strategies accordingly.
Physical Development: Jenga improves fine motor skills as players carefully remove and stack blocks using only one hand. Precise finger movements, hand-eye coordination, and grip strength are required for successful manipulation of the blocks. The game also provides proprioceptive input as players gauge the weight and balance of each block, refining their sense of touch and motor control.
Socioemotional Development: Jenga promotes social interaction and cooperation when played with multiple players. Taking turns, discussing strategies, and supporting each other's successes and challenges enhance communication, collaboration, and empathy skills. Players learn to respect and consider others' perspectives, negotiate and compromise, and work together towards a common goal. Sportsmanship is nurtured as players accept both victory and defeat gracefully, fostering resilience and emotional regulation.
Furthermore, Jenga offers opportunities for developing patience and perseverance. As the tower becomes increasingly unstable, players must exercise self-control, focus, and delayed gratification. They learn to take their time, plan their moves carefully, and tolerate the suspense of potential collapse. The game also presents a low-risk environment for risk assessment, allowing children to assess the consequences of their decisions and make calculated judgments.
By engaging in Jenga, children actively participate in a multi-dimensional activity that combines physical manipulation, cognitive analysis, and social interaction. Through the concepts of spatial reasoning, problem-solving, fine motor skills, proprioceptive input, social interaction, cooperation, sportsmanship, patience, perseverance, and risk assessment, Jenga supports holistic development in cognitive, physical, and socioemotional domains.
As an estimation we are told 5 miles is 8 km. Convert 22.5 miles to km.
Answer:
36 kilometers
Step-by-step explanation:
5 miles = 8 kilometers
22.5 miles = x kilometers
Cross multiply.
22.5 × 8 = 5 × x
180 = 5x
Divide both sides by 5.
180/5 = x
x = 36
\(3 {}^{2} + ( - 4 {}^{2} ) + 5 {}^{2} \)I'm confused on that can you help me please?
We have to replace the values in the equation
\(x^2+y^2+z^2=(3)^2+(-4)^2+(5)^2=9+16+25=50\)Since the square of a negative number is a positive number, (-4)^2 = +16
PLEASE HELP I NEED TO MAKE A COMPOUND INEQUALITY (I ATTACHED THE IMAGE THIS TIME)
Answer:
I think you need to draw it with graph.
Step-by-step explanation:
Kareem plans to get eight hours of sleep but looses a half hour of sleep every time his dog barks. Therefore between his hours of sleep (h) and number of dog barks (b) will be:
h = 8 – (b/2)
So that if b = 0,
Kareem’s hours of sleep:
h = 8-(0/2)
= 8-0
= 8
if b = 5
h = 8 -(5/2)
h = (16-5)/2
h = 11/2
h = 5.5
And...Draw a graph about it
Hope this help you.
It nearly took me about a life to understand the question :")
describe a dataset where defining a confidence interval would be important for testing validity of data
The sample's data values ought to be unrelated to one another. The sample data need to be consistent. Data from the quantitative ordered pair sample should be gathered at random or in a way that is representative of the overall population. The sample's data values ought to be unrelated to one another.
A confidence interval is a much better tool to use if we wish to communicate the level of uncertainty surrounding our point estimate (CI). A confidence interval (CI) is a symmetrical range of values where the results of repeated, related experiments are likely to fall. The middle of this range corresponds to our point estimate.
Confidence intervals, which describe how closely study results match reality or how dependable they are based on statistical theory, are regularly mentioned in scientific publications.
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Use the variable 'x' to represent number of apps downloaded and the variable 'y' to represent earnings.
Answer:
\(x = 0.4y\)
\(x \: \alpha \: y \\ x = ky \\ k = \frac{x}{y} = \frac{8}{20} = 0.4 \\ the \: relationship \: is : \\ x = 0.4y\)