___is the process that exchanges gases between body and the outside air.

At the point X after 2 seconds, the stone has a magnitude of velocity equal to 10 m/s, and its direction is purely horizontal.

When a stone is projected horizontally in a vacuum, it only experiences horizontal motion due to the absence of air resistance. The vertical motion is governed by the force of gravity alone. In this scenario, the stone will undergo uniform horizontal motion with a constant horizontal velocity.

Given that the stone is projected horizontally with a velocity of 10 m/s, its horizontal velocity remains constant throughout the motion. After 2 seconds, the stone will have traveled a horizontal distance equal to the product of its horizontal velocity and the time, which is 10 m/s * 2 s = 20 m. Therefore, the stone will be located 20 meters horizontally from the point of projection. Since the stone is moving horizontally, its vertical velocity remains zero throughout the motion. The magnitude of the velocity at this point is equal to the horizontal velocity, which is 10 m/s. However, since the stone is moving horizontally, there is no vertical component of velocity.

For such more questions on velocity

https://brainly.com/question/29396365

#SPJ11

Answer: 4.486N

Explanation:

The Gravitational force of attraction 'F' between two masses m1 and m2 is given by:

F= Gm1m2 / r^2

Where ; r = distance between the bodies

G = gravitational constant = 6.67 × 10^-11

The mass of the earth (m1) = 5.98 × 10^24 kg

Mass of the moon (m2) = 7.35 × 10^22 kg

Mass of rocket (m3) = 1200 kg

the net gravitational force on the rocket from the earth and moon equals

Difference in the gravitational force between the earth and rocket and that exerted between th e moon and rocket.

Net F = (Gm1m3 / r^2) - (Gm2m3) /r^2

Net F = Fa - Fb

Fa = Gm1m3 / r^2 =

(6.67 × 10^-11 × 5.98 × 10^24 × 1200) /(3 × 10^8)^2

(6.67×5.8×1200)/ 9 × 10^(-11 + 24 - 16)

= 5318 × 10^-3 = 5.32N

Fb = Gm2m3 / r^2 =

r = (3.84 × 10^8 - 3.0×10^8) = 0.84 × 10^8

(6.67 × 10^-11 × 7.35 × 10^22 × 1200) /(8.4× 10^7)^2

(6.67×7.35×1.2)/ 70.56 × 10^(-11 + 22 + 3 - 14)

= 0.83375N

Fnet = 5.32N - 0.83375N = 4.48625N

= 4.486N

Answer:

B.

Explanation:

Answer:

c

Explanation:

The texture of the string. I took this test a week ago I got a 90% it is c!

Skid takes his dog, neutrino, out for a walk after midnight. he brings along his special dog flashlight so he can see in the forest behind his mansion. the flashlight has a 1.75 watt bulb inside of it and passes 150 c of charge during the 5 minute walk out to neutrinos favorite tree.

(a) The amount of current flows through the bulb is (I)= 0.5 A

(b) The amount of voltage of the battery to power this flashlight (V)= 3.5 V.

The voltage is a physical term that means that the current flow  in a wire create a quantity for the resistance of the wire. That is called the voltage. It can be measured in volt.

(a) To calculate the current we are using the formula,

I= q/t

Here we are given,

q= The amount of charge flowing through the wire. = 150 C.

t= The amount of time been the current flowing. = 5 min= 5*60 S.

We have to calculate the current flows in it. = I

Now we put the values in above equation, we get

I= q/t

Or, I=150/(5*60)

Or, I=0.5 A

So, now we can say that the amount of current flows through the bulb is (I)= 0.5 A.

(b) To calculate the voltage we are using the formula here is,

P= vI

Or, v= P/I

Here we are given,

P = The amount of power of the light. = 1.75 Watt.

Now we put the values in the equation we get,

v= P/I

Or, v= 1.75/0.5

Or, v=3.5 V.

Now we can say that, the amount of voltage of the battery to power this flashlight (V)= 3.5 V.

Learn more about voltage:

https://brainly.com/question/1176850

#SPJ4

According to the given statement, the coefficient of friction between the block and the surface is approximately 0.000772.

The coefficient of friction is a measure of the interaction between two surfaces in contact. It represents the amount of resistance or friction between the surfaces. In the given problem, we need to find the coefficient of friction between the block and the surface.

To find the coefficient of friction, we can use the equation:

μ = (k * x) / (m * g)

where:
- μ is the coefficient of friction
- k is the stiffness constant of the spring
- x is the distance the spring is compressed
- m is the mass of the block
- g is the acceleration due to gravity (approximately 9.8 m/s²)

Given values:
- k = 500.0 N/m
- x = 5.0 cm = 0.05 m
- m = 3.3 kg

First, let's convert the distance x to meters by dividing it by 100:
x = 0.05 m

Now, we can substitute the given values into the equation:

μ = (500.0 N/m * 0.05 m) / (3.3 kg * 9.8 m/s²)

Calculating this expression:

μ = 0.025 / 32.34

μ ≈ 0.000772

Therefore, the coefficient of friction between the block and the surface is approximately 0.000772.

To more about mass visit:

https://brainly.com/question/11954533

#SPJ11

Answer:

KE = 1/2(m)(v^2)

Explanation:

Answer:

I hope this helps

Explanation:

The magnitude of the velocity of ball B along the y-axis after the collision (v'_{By}) is approximately 0.864 m/s.

To analyze the collision between the two billiard balls, we can use the principle of conservation of momentum and kinetic energy.

Let's assign some variables to the given values:

Initial velocity of ball A along the y-axis (before collision): v_{Ay} = 2.0 m/s (upward direction)

Initial velocity of ball B along the x-axis (before collision): v_{Bx} = 3.7 m/s (rightward direction)

Since the collision is elastic, both momentum and kinetic energy will be conserved.

Conservation of momentum: The total momentum before the collision is equal to the total momentum after the collision.

Momentum is a vector quantity, so we need to consider both the magnitude and direction of the momentum.

Before the collision:

Momentum of ball A along the y-axis: p_{Ay} = m * v_{Ay} (upward direction)

Momentum of ball B along the x-axis: p_{Bx} = m * v_{Bx} (rightward direction)

After the collision:

Momentum of ball A along the y-axis: p'{Ay} = 0 (since the ball is not moving along the y-axis anymore)

Momentum of ball B along the y-axis: p'{By} = m * v'_{By} (upward direction)

Using the conservation of momentum, we can write the equation as:

p_{Ay} + p_{Bx} = p'{Ay} + p'{By}

m * v_{Ay} + m * v_{Bx} = 0 + m * v'_{By}

Simplifying the equation:

2.0m + 3.7m = v'{By}m

5.7m = v'{By}m

Therefore, the magnitude of the velocity of ball B along the y-axis after the collision (v'_{By}) is equal to 5.7 m/s.

Now let's consider the kinetic energy before and after the collision.

Kinetic energy is given by the formula: KE = (1/2) * m * v², where m is the mass and v is the velocity.

Before the collision:

Kinetic energy of ball A: KE_{A} = (1/2) * m * v_{Ay}²

Kinetic energy of ball B: KE_{B} = (1/2) * m * v_{Bx}²

After the collision:

Kinetic energy of ball A: KE'{A} = 0 (since the ball is not moving)

Kinetic energy of ball B: KE'{B} = (1/2) * m * v'_{By}²

Using the conservation of kinetic energy, we can write the equation as:

KE_{A} + KE_{B} = KE'{A} + KE'{B}

(1/2) * m * v_{Ay}² + (1/2) * m * v_{Bx}² = 0 + (1/2) * m * v'_{By}²

Substituting the given values:

(1/2) * 2.0m * (2.0 m/s)² + (1/2) * 3.7m * (3.7 m/s)² = (1/2) * 5.7m * v'_{By}²

Simplifying the equation:

2.0 m²/s² + 13.645 m²/s² = 2.85 m²/s² + 2.85 m²/s² + 5.7 m * v'_{By}²

Rearranging the terms:

15.645 m²/s² = 11.4 m²/s² + 5.7 m * v'_{By}²

Subtracting 11.4 m²/s² from both sides:

4.245 m²/s² = 5.7 m * v'_{By}²

Dividing both sides by 5.7 m:

0.745 m/s² = v'_{By}²

Taking the square root of both sides:

v'_{By} = √(0.745 m/s^2) ≈ 0.864 m/s

Therefore, the magnitude of the velocity of ball B along the y-axis after the collision (v'_{By}) is approximately 0.864 m/s.

know more about momentum here

https://brainly.com/question/904448#

#SPJ11

Main answer:A ball floats on the surface of water in a container exposed to the atmosphere pressure. The ball will remain immersed at its former depth. Explanation: When a ball is placed in a container containing water, it will float. The weight of the ball is lesser than the weight of the water displaced by it, hence, the ball floats on the surface of the water.

Therefore, the ball floats in water and it will remain immersed at its former depth if the container is exposed to the atmosphere, whether the container is covered or uncovered.The density of the ball and the water are the two important things to remember here. If the density of the ball is less than the density of the water, the ball will float on the surface of the water. If the density of the ball is greater than the density of the water, the ball will sink.Long answer in 100 words:When a ball is placed in a container containing water, it will float.

The weight of the ball is lesser than the weight of the water displaced by it, hence, the ball floats on the surface of the water. Therefore, the ball floats in water and it will remain immersed at its former depth if the container is exposed to the atmosphere, whether the container is covered or uncovered. If the container is covered and the air is removed, the ball will sink as there is no air pressure to support the ball, but if the container is covered and the air is compressed, the ball will still float as there is no change in the weight of the ball or the water and hence, the ball continues to float.

To know more about atmospheric pressure visit:

brainly.com/question/31634228

#SPJ11

Newton's law of universal gravitation doesn't say anything about the cause of gravity.

Einstein's theory of relativity does.

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

Learn more about centre of mass here ;

https://brainly.com/question/30389896

#SPJ11

Answer:

it loses its momentum. In simpler ways it is really slow

Explanation:

The tension required for the vibrating wire to produce its correct frequency of 4.1 kHz. is  187 N

The tension required for the vibrating wire can be calculated using the wave equation:

f = (1/2L) √(T/μ)

where f is the frequency of the vibrating wire, L is the length of the wire, T is the tension in the wire, and μ is the linear mass density of the wire (mass per unit length).

We can first calculate the linear mass density of the wire using its diameter and density:

μ = (π/4) d²ρ

= (π/4) (3.5 × 10⁻⁴ m)² (7.8 × 10³ kg m⁻³)

= 0.076 kg m⁻¹

Substituting the given values into the wave equation and solving for T:

T = (4π²μL²f²) / 1

= (4π²)(0.076 kg m⁻¹)(0.050 m)²(4.1 × 10³ Hz)²

= 187 N

Therefore, a tension of 187 N is required for the vibrating wire to produce its correct frequency of 4.1 kHz.

Learn more about tension below.

https://brainly.com/question/24994188

#SPJ1

Answer:126N

Explanation:

The photosynthesis chemical equation states that the reactants

(carbon dioxide, water and sunlight), yield two products, glucose and oxygen gas. The single chemical equation represents the overall process of photosynthesis.

hope this help you!

Explanation:

In a parallel circuit the current flows trough different paths.

Then, A parallel circuit is described as a type of circuit in which there are several current paths.

The most reasonable unit to measure the height of an oak tree would be (choice b) meters.

The most reasonable unit to measure the height of an oak tree is meters. Because  Centimeters would likely be too small and impractical for such a large object, while kilometers would be too large and unnecessary for measuring the height of a single tree.

A measure is a quantification of a physical quantity, typically expressed using a standard unit of measurement. Measures are used to describe and compare the properties or characteristics of different objects, substances, or systems. For example, length is a measure that describes the distance between two points and is typically expressed in units such as meters or feet. Other examples of measures include mass, time, temperature, volume, and energy. The choice of measure depends on the context and the properties being studied.

To learn more about  oak tree  visit: https://brainly.com/question/29791164

#SPJ11

Answer:

Explanation:

V = I*R

V/R = I

Answer:

b

Explanation:

he keep the thermoter in the water longer

Avg. Acc. = (V2 - V1)/t = (28 - 10)/6 = 3 m/s²

Answer: D

Rocket engine igniting is chemical energy when he in turn makes it launch and move which is kinetic energy

The amount of heat needed to increase the temperature of one unit mass of a gas by one degree when it is heated at constant volume is known as the specific heat of a gas at constant volume. It is denoted by the letter cv.

Therefore, it is often common to refer to a material's volume per unit mass as its "specific volume": v = (V/m). The material's density, or the mass per unit volume, is the reciprocal of the specific volume, or r, which equals (1/v) = (m/V).

The amount of energy needed to raise a kilogram of tissue's temperature by one Kelvin (=one degree Celsius) is measured by its specific heat capacity, or c [J/(kg K)].

Learn more about amount of heat

https://brainly.com/question/27991746

#SPJ4

Answer:

24 metre

Explanation:

From the available information in this question,

The swarm of bees moves at 0.20 per second

If it moves at

O.20 = 1 second,

We have a minute to be = 60 seconds

So in one 1 minute the velocity =

0.20 x 60 seconds

= 12 meters

The 2 minutes = 60 seconds x 2

2 minutes = 120 seconds

120 x 0.20 = 24 meters

So in 2 minutes these swarm of bees are going to travel a distance of 24 metres

Answer:

m = 8 kg

Explanation:

According to Newton's second law of motion, F = ma.

Solving for m using algebra:

m = F ÷ a

m = 48 N ÷ 6 m/s² = 8 kg

i. The gravitational force between the earth and sun can be obtained as follow:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 5.987×10²⁴ × 1.989×10³⁰) / (1.5×10¹¹)²

F = 3.53×10²² N

Thus, the gravitational force between the earth and sun is 3.53×10²² N

ii. The gravitational force between the earth and moon can be obtained as follow:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 5.987×10²⁴ × 7.347×10²²) / (3.844×10⁸)²

F = 1.99×10²⁰ N

Thus, the gravitational force between the earth and moon is 1.99×10²⁰ N

Comparison = G₁ / G₂

G₁ / G₂ = 3.53×10²² / 1.99×10²⁰

G₁ / G₂ = 177

Cross multiply

G₁ = G₂ × 177

Thus, we can say that the gravitational force between the earth and sun is 177 times bigger than the gravitational force between the earth and moon

Learn more about gravitational force:

https://brainly.com/question/24299568

#SPJ1

Answer:

Big Q represents the source charge which creates the electric field. Little q represents the test charge which is used to measure the strength of the electric field at a given location surrounding the source charge.

The source charge, or Big Q, is what generates the electric field. Little q stands for the test charge, that is used to gauge the intensity of the electromagnetic field around the source charge at a certain position.

Charged material experiences a force when it is exposed to an electromagnetic field because of the physical characteristic of electric charge.

You can have a positive or negative electric charge. Unlike charges attract one another, while like charges repel one another. Neutral refers to an object that carries no net charge.

Classical electrodynamics, the name given to early understanding of how charged particles interact, is still accurate for issues that do not call for taking into account quantum phenomena.

Electric current is a conserved attribute, meaning that the net charge—that is, the sum of the positive and negative charges in an isolated system—cannot change.

To know more about electric Charge:

https://brainly.com/question/9194793

#SPJ2

A word-forming element meaning "physical, physically; natural," from Latinized form of Greek physikos "natural, physical, pertaining to nature."