Answer:
i don't know the correct answer
but this is what i found on web
Explanation:
Changes of state are physical changes in matter. They are reversible changes that do not change matter's chemical makeup or chemical properties. Processes involved in changes of state include melting, freezing, sublimation, deposition, condensation, and evaporation. Energy is always involved in changes of state.
A sphere of mass 15 kg possess kinetic energy of 1200 J. Calculate its
velocity
Answer:
12.65 Meters / Second (m/s)
Explanation:
the problem is really easy to solve, we begin by stating the kinetic energy formula which is:
KE = (1/2)(mass)(velocity)^2
We equate 1200 J to the formula, substitute the mass, and solve for velocity either using a CAS, app, or by hand
1200J = (0.5)(15kg)v^2
v = 12.65 m/s
An important diagnostic tool for heart disease is the pressure difference between blood pressure in the heart and in the aorta leading away from the heart. Since blood within the heart is essentially stationary, this pressure difference can be inferred from a measurement of the speed of blood flow in the aorta. Take the speed of sound in stationary blood to be c.
a. Sound sent by a transmitter placed directly inline with the aorta will be reflected back to a receiver and show a frequency shift with each heartbeat. If the maximum speed of blood in the aorta is v, what frequency will the receiver detect? Note that you cannot simply use the textbook Doppler Shift formula because the detector is the same device as the source, receiving sound after reflection.
b. Show that in the limit of low blood velocity (v <
f= 2fo v/c
Answer:
a) f ’’ = f₀ \(\frac{1 + \frac{v}{c} }{1- \frac{v}{c} }\) , b) Δf = 2 f₀ \(\frac{v}{c}\)
Explanation:
a) This is a Doppler effect exercise, which we must solve in two parts in the first the emitter is fixed and in the second when the sound is reflected the emitter is mobile.
Let's look for the frequency (f ’) that the mobile aorta receives, the blood is leaving the aorta or is moving towards the source
f ’= fo\(\frac{c+v}{c}\)
This sound wave is reflected by the blood that becomes the emitter, mobile and the receiver is fixed.
f ’’ = f’ \(\frac{c}{ c-v}\)
where c represents the sound velocity in stationary blood
therefore the received frequency is
f ’’ = f₀ \(\frac{c}{c-v}\)
let's simplify the expression
f ’’ = f₀ \frac{c+v}{c-v}
f ’’ = f₀ \(\frac{1 + \frac{v}{c} }{1- \frac{v}{c} }\)
b) At the low speed limit v <c, we can expand the quantity
(1 -x)ⁿ = 1 - x + n (n-1) x² + ...
\(( 1- \frac{v}{c} ) ^{-1} = 1 + \frac{v}{c}\)
f ’’ = fo \(( 1+ \frac{v}{c}) ( 1 + \frac{v}{c} )\)
f ’’ = fo \(( 1 + 2 \frac{v}{c} + \frac{v^2}{ c^2} )\)
leave the linear term
f ’’ = f₀ + f₀ 2\(\frac{v}{c}\)
the sound difference
f ’’ -f₀ = 2f₀ v/c
Δf = 2 f₀ \(\frac{v}{c}\)
a horse was at rest.what was the final velocity of the horse if it covered 200 meters in 16 seconds?
Answer:
12.5m/s
Explanation:
Simplify the proportion.
200/16 = 100/8 = 50/4 = 25/2 = 12.5
When you roll a ball across a rug, what slows it to a stop?
The ball isn’t moving fast enough.
Friction resists the ball’s forward motion.
The rug doesn’t have enough force to keep the ball rolling.
The rug doesn’t have enough momentum to keep the ball rolling.
Friction resists the ball’s forward motion.
A kettle transfers 1000) of energy every 2 seconds. Calculate its power.
Water is to be heated from 10°C to 80°C as it flows through a 2-cm-internal-diameter, 13-m-long tube. The tube is equipped with an electric resistance heater, which provides uniform heating throughout the surface of the tube. The outer surface of the heater is well insulated, so that in steady operation all the heat generated in the heater is transferred to the water in the tube. If the system is to provide hot water at a rate of 5 L/min, determine the power rating of the resistance heater. Also, estimate the inner surface temperature of the pipe at the exit.
Answer:
- the power rating of the resistance heater is 24139.5 W
- the inner surface temperature of the pipe at the exit is 96.34°C
Explanation:
Given the data in the question;
Flow rate of water in the tube V" = 5L/min = 8.333 × 10⁻⁵ m³/s
The water is to be heated from 10°C to 80°C;
so Average or mean temperature \(T_{avg\) will be;
\(T_{avg\) = (T₁ + T₂) / 2 = (10 + 80) / 2 = 90/2 = 45°C
Now, from the Table " Properties of Water " at average temperature;
at \(T_{avg\) = 45°C
density p = 990.1 kg/m³
specific heat \(C_p\) = 4180 J/kg-k
thermal conductivity k = 0.637 W/m-°C
Now, we determine the mass flow;
m" = pV"
we substitute
m" = 990.1 × 8.333 × 10⁻⁵
m" = 0.08250 kg/s
we know that the power rating of the resistance heater is equal to the heat transfer rate to the water;
Q' = m"\(C_p\)( T₂ - T₁ )
we substitute
Q' = (0.08250 × 4180 ) ( 80 - 10 )
Q' = 344.85 × 70
Q' = 24139.5 W
Hence, the power rating of the resistance heater is 24139.5 W
Next, we determine the average velocity of water in the tube;
\(V_{avg\) = V" / \(A_c\)
\(V_{avg\) = V" / ( \(\frac{1}{4}\)πD² )
given that; flows through a 2-cm-internal-diameter; D = 0.02 m
we substitute
\(V_{avg\) = (8.333 × 10⁻⁵) / ( \(\frac{1}{4}\)π × (0.02)² )
\(V_{avg\) = (8.333 × 10⁻⁵) / ( 3.14159 × 10⁻⁴ )
\(V_{avg\) = 0.265 m/s
Also, from table " saturated water property table "
At 45°C
viscosity μ = 0.596 × 10⁻³ kg/m-s
Prandtl number Pr = 3.91
Now, we determine the kinematic viscosity
v = μ / p
we substitute
v = ( 0.596 × 10⁻³ ) / 990.1
v = 6.01959 × 10⁻⁷ m²/s
so, Reynolds number in the flow region will be;
Re = (\(V_{avg\) × D) / v
we substitute
Re = ( 0.265 × 0.02) / (6.01959 × 10⁻⁷)
Re = 8804.586
we can see that our Reynolds number ( 8804.586 ) more than 2300 and less than 10,000.
Hydraulic and thermal entry length are equal in this flow region,
such that;
\(L_h\) = \(L_t\)
⇒ 10 × D = 10 × 0.02 = 0.2 m
we can see that the entry length ( 0.2 m ) is smaller than the given length ( 13 m ) in the question; the flow is a turbulent flow.
So we the Nuddelt number
Nu = \(0.023Re^{0.8} Pr^{0.4\)
Nu = 0.023 × \(8804.586^{0.8\) × \(3.91^{0.4\)
Nu = 56.8
Hence, the heat transfer coefficient h will be;
h = \(\frac{k}{D}\) × Nu
we substitute
h = \(\frac{0.637}{0.02}\) × 56.8
h = 31.85 × 56.8
h = 1809.1 W/m²-°C
Now, area of the heat transfer will be
A\(_s\) = πDL
we substitute
A\(_s\) = π × 0.02 × 13
A\(_s\) = 0.8168 m²
Finally we determine the inner temperature of the pipe at exit. using the relation;
Q' = hA\(_s\)( T₃ - T₂ )
we substitute
24139.5 = 1809.1 × 0.8168( T₃ - 10 )
24139.5 = 1477.67288( T₃ - 80 )
24139.5 = 1477.67288T₃ - 118213.8304
24139.5 + 118213.8304 = 1477.67288T₃
1477.67288T₃ = 142353.3304
T₃ = 142353.3304 / 1477.67288T
T₃ = 96.34°C
Therefore, the inner surface temperature of the pipe at the exit is 96.34°C
a. If the frequency of light is increased above the threshold frequency, the
energy of the electrons emitted will _________________.
b. If the frequency of light is decreased to below the threshold frequency, the
rate at which electrons are emitted will _______________.
c. If the intensity of light is decreased, the energy of the electrons emitted will ____________________.
d. If the intensity of light is decreased, the rate at which electrons are emitted will ________________.
Answer:
a. If the frequency of light is increased above the threshold frequency, the energy of the electrons emitted will increase.
b. If the frequency of light is decreased to below the threshold frequency, the rate at which electrons are emitted will decrease.
c. If the intensity of light is decreased, the energy of the electrons emitted will remain the same, but fewer electrons will be emitted.
d. If the intensity of light is decreased, the rate at which electrons are emitted will decrease.
Question 5 of 10
Two billiard balls, each with a mass of 0.21 kg, collide with each other on a
pool table. Before the collision, one ball is moving north at 1.7 m/s and the
other ball is moving south at 2.6 m/s. What is the momentum of this system
after the collision?
A. 0.19 kg-m/s south
B. 0.19 kg-m/s north
O C. 0.90 kg-m/s north
D. 0.90 kg-m/s south
The momentum of this system after the collision (final momentum) is 0.90 kg m/s towards the south direction. Thus, the correct option is D.
What is Momentum?Momentum is the mass in motion. All objects have mass, so if an object is moving, then it has momentum. The amount of momentum which an object has is dependent upon two variables which are how much stuff is moving and how fast the stuff is moving.
Momentum of the system after the collision can be calculated through the law of conservation of momentum. The final momentum of the system is equal to the initial momentum of the system.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
m₁ = m₂ = 0.21kg
u₁ = 1.7m/s
u₂ = 2.6m/s
0.21 × 1.7 + 0.21 × 2.6 = 0.357 + 0.546
Final momentum of the system = 0.903 kg m/s towards south.
Therefore, the correct option is D.
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Answer:
A. 0.19 kg m/s south
Explanation:
how much heat is needed to convert 1.0kg of ice at -10°C to steam at 100°C?
Q= Q1 +Q2 +Q3+Q4+ Q5
3066 J
Which term refers to the ability to do work?
o energy
power
force
motion
PLEAEE HURRY IM DOING MY EXAM PLEASE HELP WILL MARK BRAINLIEST
Answer:
Energy
Explanation:
work is actually a transfer of energy. When work is done to an object , energy is transferred to that object.
The ability to do work is called energy.
What is work ?"Work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement."
What is energy ?"Energy is defined as the “ability to do work, which is the ability to exert a force causing displacement of an object.” energy is just the force that causes things to move. Energy is divided into two types: potential and kinetic."
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An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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-0,32 m - 4.2 At the instant the marble leaves the canon, the canon starts moving backwards (recoils) at a constant velocity. 4.1 State the principle of conservation of linear momentum in words. that is stationary canon is placed 0,32 m from a fixed bare After firing, the canon takes 0,33 s to collide with a barrier at a distance of 0,32 m. Calculate the speed the: W< 1 >E S 4.2.1 Canon collides with the barrier
The cannon will completely stop when it collides with the barrier.
To calculate the speed at which the cannon collides with the barrier, we can follow these step-by-step calculations:
Determine the initial momentum of the system.
Since the cannon is initially stationary, the initial momentum is zero.
Apply the conservation of linear momentum.
According to the principle of conservation of linear momentum, the initial momentum of the system (zero) is equal to the final momentum of the system. The final momentum is the momentum of the cannon after firing.
Calculate the final momentum of the system.
Let's assume the mass of the cannon is represented by 'm' and the final velocity of the cannon is represented by 'v'. The final momentum of the system is given by: final momentum = m × v.
Set up the equation.
Since the initial momentum is zero, we have: 0 = m × v.
Solve for the final velocity of the cannon.
Dividing both sides of the equation by 'm', we get: v = 0.
Interpret the result.
The calculation shows that the final velocity of the cannon is zero. This means that the cannon comes to a complete stop when it collides with the barrier.
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As the captain of the scientific team sent to Planet Physics, one of your tasks is to measure g. You have a long, thin wire labeled 1.73 g/m and a 1.30 kg weight. You have your accurate space cadet chronometer but, unfortunately, you seem to have forgotten a meter stick. Undeterred, you first find the midpoint of the wire by folding it in half. You then attach one end of the wire to the wall of your laboratory, stretch it horizontally to pass over a pulley at the midpoint of the wire, then tie the 1.30 kg weight to the end hanging over the pulley. By vibrating the wire, and measuring time with your chronometer, you find that the wire's second harmonic frequency is 200 Hz . Next, with the 1.30 kg weight still tied to one end of the wire, you attach the other end to the ceiling to make a pendulum. You find that the pendulum requires 313 s to complete 200 oscillations. Pulling out your trusty calculator, you get to work.
What value of g will you report back to headquarters?
Answer:
The value of g is \(g =76.2 m/s^2\)
Explanation:
From the question we are told that
The mass of the weight is \(m = 1.30 kg\)
The spring constant \(k = 1.73 g/m = 1.73 *10^{-3} \ kg/m\)
The second harmonic frequency is \(f = 100 \ Hz\)
The number of oscillation is \(N = 200\)
The time taken is \(t = 315 \ s\)
Generally the frequency is mathematically represented as
\(f = \frac{v}{\lambda}\)
At second harmonic frequency the length of the string vibrating is equal to the wavelength of the wave generated
\(l = \lambda\)
Noe from the question the vibrating string is just half of the length of the main string so
Let assume the length of the main string is \(L\)
So \(l = \frac{L}{2}\)
The velocity of the vibrating string is mathematically represented as
\(v = \sqrt{\frac{T}{\mu} }\)
Where T is the tension on the string which can be mathematically represented as
\(T = mg\)
So
\(v = \sqrt{\frac{mg}{k} }\)
Then
\(f = \frac{v}{\frac{L}{2} }\)
=> \(v = \frac{fL }{2}\)
=> \(\sqrt{\frac{mg}{k} } = \frac{fL}{2}\)
=> \(g = \frac{f^2 L^2 \mu}{4m}\)
substituting values
\(g = \frac{(100) * (1.73 *10^{-3} )}{(4 * 1.30)} L^2\)
\(g = 3.326 m^{-1} s^{-2} L^2\)
Generally the period of oscillation is mathematically represented as
\(T_p = 2 \pi \sqrt{\frac{L}{g} }\)
=> \(L = \frac{T^2 g}{4 \pi ^2}\)
The period can be mathematically evaluated as
\(T_p = \frac{t}{N}\)
substituting values
\(T_p = \frac{315}{200}\)
\(T_p = 1.575 \ s\)
Therefore
\(L = \frac{1.575^2 * g }{4 \pi ^2}\)
\(L = 0.0628 ^2 g\)
so
\(g = 3.326 m^{-1} s^{-2} L^2\)
substituting for L
\(g = 3.326 ((0.0628) g)^2\)
=> \(g = \frac{1}{(3.326)* (0.0628)^2}\)
\(g =76.2 m/s^2\)
in 1994, mata jagdamba of india had very long hair. it was 4.32 m long. suppose mata conducted experiments with her hair. first, she determined that one hair strand could support a mass of 25g. she then attached a smaller mass to the same hair strand and swung it in the horizontal plane. if the strand broke when the tangential speed of the mass reached 8.1 m/s, how large was the mass?
As a result, the maximum mass that the hair strand can sustain before breaking is 0.91 kg, or 910 grams.
What is speed?Speed is a measure of how fast an object is moving. It is defined as the distance traveled by an object per unit of time, typically in meters per second (m/s) or kilometers per hour (km/h). Speed is a scalar quantity, which means that it has only a magnitude (i.e. the numerical value) and no direction. This is different from velocity, which is a vector quantity that also takes into account the direction of motion. Speed can be constant or variable. When an object moves at a constant speed, it covers equal distances in equal intervals of time. When an object moves at a variable speed, its speed changes over time and its distance traveled also changes. Speed is an important concept in physics and is used in many real-world applications, such as transportation, sports, and engineering. Understanding speed and how it is affected by different factors can help us design better and more efficient systems, and can also help us make better decisions in our daily lives.
Here,
To solve this problem, we can use the concept of centripetal force, which is the force that is required to keep an object moving in a circular path. The centripetal force is given by:
F = (m * v²) / r
where F is the centripetal force, m is the mass of the object, v is its tangential speed, and r is the radius of the circular path.
In this case, the mass of the hair strand is not given, but we can assume that it is negligible compared to the mass of the attached mass. Therefore, we can use the given mass of 25g in our calculations.
We can also assume that the radius of the circular path is equal to the length of the hair strand, or 4.32 m.
We are given that the hair strand broke when the tangential speed of the mass reached 8.1 m/s. Therefore, we can set the centripetal force equal to the force that the hair strand can support before breaking:
F = m * g = 25g * 9.81 m/s²= 245.25 N
where g is the acceleration due to gravity.
Setting the centripetal force equal to the force that the hair strand can support, we can solve for the mass:
F = (m * v²) / r
245.25 = (m * 8.1²) / 4.32
m = (245.25 * 4.32) / 8.1²
m = 0.91 kg
Therefore, the mass that the hair strand could support before breaking is 0.91 kg, or 910 grams.
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A certain radar installation transmits electromagnetic radiation with a wavelength of 3.5 cm. What is the frequency of this radiation?
The frequency of the radiation = 10GHz
Explanation:The wavelength of the electromagnetic radiation, λ = 3.5 cm
λ = 3.5/100 m
λ = 0.035 m
The speed of light, c = 3 x 10⁸ m/s
Calculate the frequency (f) of the radiation using the formula:
\(\begin{gathered} f=\frac{c}{\lambda} \\ \\ f=\frac{3\times10^8}{0.035} \\ \\ f=10^{10}Hz \\ \\ f=10\times10^9Hz \\ \\ f=10GHz \end{gathered}\)The frequency of the radiation = 10GHz
Which of the following describes what will happen when one lowers the kinetic energy of the particles in a sample of matter?
A motorboat, which has a speed of 5 meters per sec-
ond in still water, is headed east as it crosses a river
flowing south at 3.3 meters per second. What is the
magnitude of the boat’s resultant velocity with respect
to the starting point?
1. 3.3 m/s
2. 5.0 m/s
3. 6.0 m/s
4. 8.3 m/s
The magnitude of the boat’s resultant velocity with respect to the starting point is 6.0 m/s. Hence, option (3) is correct.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
The velocity of the boat in still water = 5 meters per second along east.
The velocity of stream = 3.3 meters per second along south.
Hence, the magnitude of the boat’s resultant velocity with respect to the starting point is = √(5² + 3.3²) m/s
=6.0 m/s.
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WHAT IS THE MEAING OF- Grouping Data
Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.
It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.
This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.
For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.
Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.
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why might calcium be a important in the diet of many living things
Answer:
Calcium is an essential mineral that is important in the diet of many living things as it plays several important roles in the body:
1. Bone and teeth formation: Calcium is a key component of bones and teeth, making them strong and healthy.
2. Muscle function: Calcium plays a critical role in muscle contraction and relaxation, helping muscles function properly.
3. Nerve function: Calcium is involved in the transmission of nerve impulses, which allows for proper communication between nerve cells.
4. Blood clotting: Calcium is required for blood clotting, which is important for preventing excessive bleeding after an injury.
5. Cellular signaling: Calcium is involved in many cellular signaling pathways, helping to regulate various physiological processes in the body.
Therefore, having an adequate amount of calcium in the diet is crucial for the overall health and well-being of many living organisms.
4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V
The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.
To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.
Given:
R1 = 4 Ω
R2 = 30 Ω
R3 = 10 Ω
R4 = 5 Ω
Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:
RT1-2 = R1 + R2
RT1-2 = 4 Ω + 30 Ω
RT1-2 = 34 Ω
Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:
1/RTotal = 1/RT1-2 + 1/R3
1/RTotal = 1/34 Ω + 1/10 Ω
1/RTotal = (10 + 34) / (34 * 10) Ω
1/RTotal = 44 / 340 Ω
1/RTotal ≈ 0.1294 Ω
RTotal ≈ 1 / 0.1294 Ω
RTotal ≈ 7.74 Ω
Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:
RTotalCircuit = RTotal + R4
RTotalCircuit = 7.74 Ω + 5 Ω
RTotalCircuit ≈ 12.74 Ω
Therefore, the total resistance of the circuit is approximately 12.74 Ω.
To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:
I = V / RTotalCircuit
I = 56 V / 12.74 Ω
I ≈ 4.39 A
Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).
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A soccer player runs 75m in a straight line down a soccer field in 11 seconds. What
was her average speed?
Answer:
6.9m
Explanation:
I divide 75m by 12 seconds.
Please give BRAINLIEST
You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
110
32°
36°
120
40°
128
440
133
48°
127
52
119
56°
109
60°
100
64°
91
68°
77
72°
63
At which angle will the performer travel the longest distance?
Answer:
44°
Explanation:
Look for the longest distance under the 'Distance ' column....look to the left to find the corresponding angle
Table clearly shows that the longest distance (133 ft) occurs at angle of 44°
laser light (λ = 568.7 nm) is incident on a single slit. what is the maximum width of the slit (in nm) for which no diffraction minima are observed? round to the closest integer.
The maximum width of the slit (in nm) for which no diffraction minima are observed is 569 nm.
What is the maximum width of the slit?The maximum width of the slit (in nm) for which no diffraction minima are observed is calculated by applying the following equation.
sinθ = mλ/a
where;
m is = 1 order integerthe maximum angle for diffraction to occur = 90⁰λ is the wavelength = 568.7 nma is the maximum width of the slitSubstitute the given parameters and solve for the maximum width of the slit (in nm) for which no diffraction minima are observed.
sin(90) = (1 x 568.7 nm) / a
1 = (568.7 nm) / a
a = (568.7 nm) /1
a = 568.7 nm
to the closest integer = 569 nm
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A rectangular block weighting 320N has dimensions 4metre by 10metre what is the greater pressure and the least pressure it can be exerted on the ground
The pressure exerted by a rectangular block on the ground is 8 Pascal (Pa) when its weight is 320 N and its dimensions are 4 meters by 10 meters. The greatest pressure occurs when the block is vertically placed at 20 Pa, while the least pressure occurs when it is horizontally placed at 8 Pa.
To calculate the pressure exerted by the rectangular block on the ground, we need to consider the formula for pressure:
Pressure = Force / Area
Given that the weight of the block is 320 N and the dimensions of the block are 4 meters by 10 meters, we can calculate the area of the block in contact with the ground. In this case, it is the length multiplied by the width of the block.
Area = length * width
Area = 4 meters * 10 meters
Area = 40 square meters
Now, we can calculate the pressure exerted by the block on the ground:
Pressure = 320 N / 40 square meters
Pressure = 8 N/m^2 (Pascal)
Therefore, the pressure exerted by the rectangular block on the ground is 8 Pascal (Pa).
To determine the greatest pressure and the least pressure that can be exerted on the ground, we need to consider the orientation of the block.
The greatest pressure occurs when the block is placed vertically on one of its smallest faces. In this case, the entire weight of the block (320 N) is concentrated on a smaller area.
The area in contact with the ground is given by the length multiplied by the width of the smallest face.
Area = 4 meters * 4 meters = 16 square meters
Greatest Pressure = 320 N / 16 square meters = 20 \(N/m^2\)(Pascal)
The least pressure occurs when the block is placed horizontally on one of its largest faces. In this case, the weight of the block is distributed over a larger area.
The area in contact with the ground is given by the length multiplied by the width of the largest face.
Area = 4 meters * 10 meters = 40 square meters
Least Pressure = 320 N / 40 square meters = 8 \(N/m^2\)(Pascal)
Therefore, the greatest pressure that can be exerted on the ground is 20 Pascal (Pa), and the least pressure is 8 Pascal (Pa).
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1. A material emits electrons when the electromagnetic radiation with a frequency equal to or less than the material's threshold frequency strikes the material.
True
False
2. In a particle model to show energy transfer, which of the following is correct?
a. Energy jumps are best described of electrons in packages known as photons
b. In energy transfers, electrons can absorb or emit energy
c. Photons carry energy from one location or object to another
d. All of the above are correct of particle models
1) The photoelectric effect is the phenomena by which, the metals release electrons when they are exposed to electromagnetic radiation with the suitable frequency. The photoelectrons are the electrons that are released in this process.
So, the statement is true.
2) In a particle model, energy transfer can be done through many ways such as:
The energy jumps between the particles in the form of photons.
Electrons can absorb or emit energy during energy transfer.
The energy is transferred between different objects in the form of photons.
So, all of them are true.
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What is the horizontal layer of soil called
The horizontal layer of soil called are called soil horizons.
What is the horizontal layer of soil called?Soil is made up of clear horizontal layers; these layers are called horizons. They range from rich, organic upper layers (humus and topsoil) to basic rocky layers ( subsoil, regolith, and bedrock). Soils are named and confidentially based on their horizons.
The soil profile has four distinct layers a soil horizon is a horizontal layer of soil with physical or chemical attributes that separate it from layers above and below. More simply, each horizon. Soil is made up of clear horizontal layers. These layers are called horizons.
So we can conclude that A soil horizon is a layer parallel to the soil aspect whose physical, chemical, and biological quality differ from the layers.
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Calculate the magnitude of the electric field strength at a point in a field where an electronn experiences a force with a magnitude of 3.9 * 10^(-16) N.
ANSWER
\(2,434.46N\/C\)EXPLANATION
To find the strength of the electric field, apply the formula below:
\(E=\frac{F}{q}\)where F = electric force, q = charge of the electron
Hence, the strength of the electric field is:
\(\begin{gathered} E=\frac{3.9\cdot10^{-16}}{1.602\cdot10^{-19}} \\ E=2,434.46N\/C \end{gathered}\)That is the answer.
2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times
When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.
The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.
Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:
Mass of air = Mass of filled container - Mass of empty container
= 0.428 kg - 0.419 kg
= 0.009 kg
Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:
Volume of air = Volume of perplex box * Number of times air inside
= 1000 cm³ * 7.2
= 7200 cm³
Convert the volume of air to cubic meters (m³) by dividing by 1000000:
Volume of air = 7200 cm³ / 1000000
= 0.0072 m³
Calculate the density of air using the formula:
Density = Mass / Volume
Density = 0.009 kg / 0.0072 m³
≈ 1.25 kg/m³
Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.
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Describe an example of an assignment that could be used in science, technology, engineering, or mathematics that would allow a student to apply a concept he has learned.
Answer:
A notebook because they can take notes of what they have learned
Explanation:
A 86.0 kg person climbs stairs, gaining 3.30 meters in height. Find the work done (in J) to accomplish this task.
W = mgh= 66* 9.83.7=2393J.
What is Work?
Force applied across a distance is called work. Examples of work include dragging down a captive helium balloon, driving a car up a hill, and lifting an object against the gravitational attraction of the Earth.
Energy manifests mechanically as work. The joule (J), or newton-meter (N m), is the accepted unit of work. In base International System of Units (SI) units, this equals one kilogram-meter squared per second squared (kg m 2 /s 2 or kg m 2 /s -2).
As a substitute, the erg, which is equal to a dyne-centimeter (dyn-cm), can be used to measure work. In base SI units, one erg is equal to one gram-centimeter squared per second squared (g cm 2 /s 2 or g cm 2 s -2).
Therefore, W = mgh= 66* 9.83.7=2393J.
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