Is table salt a mixture ?


True

False

The amount, in grams, of hydrofluoric acid that will be formed when 173.63 grams of hydrogen reacts with 173,63 grams of fluorine would be 182.8 grams.

The balanced equation of the reaction is written as:

\(H_2 + F_2 -- > 2HF\)

According to the equation, the mole ratio of hydrogen and fluorine that react to produce hydrofluoric acid is 1:1.

Recall that: mole of substance = mass of the substance/molar mass

Molar mass of \(H_2\) = 1x2 = 2 g/mol

Molar mass of \(F_2\) = 19x2 = 38 g/mol

Mole of 173.63 grams  \(H_2\) = 173.63/2

                                             = 86.82 moles

Mole of 173.63 grams  \(F_2\)  = 173.63/38

                                        = 4.57 moles.

Considering the mole ratio of the two reactants, it appears that fluorine is limited in availability and will, therefore, determine the amount of hydrofluoric acid that will be produced.

Mole ratio of fluorine to hydrofluoric acid = 1:2.

Equivalent mole of hydrofluoric acid = 4.57 x 2 = 9.14 moles.

Mass of 9.14 moles HF = 9.14 x 20

                                     = 182.8 grams

Thus, the amount of hydrofluoric acid formed from the reaction is 182.8 grams.

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Answer:

Scientists interpret data based on their background knowledge and experience; thus, different scientists can interpret the same data in different ways.

Therefore the answer to your question is

Hope this helps you...

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The amount of energy required to heat 100 g of water is 268000 J.

Energy is the ability or the capacity to perform work.

To calculate the amount heat energy required to change the water to steam, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the amount of energy required is 268000 J.

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Answer:

which?........................

Answer:

Below :))

Explanation:

I would suggest having a space/rocket theme, which fits your project.

What you do really depends on how much you want to put into it.

If its a black board, you could draw/make rockets to put on the board, and some planets. You could also make/draw some baking soda and vinegar bottles/cans. From what I have done, I have pictures/writing to put on the board. I suggest priting these if you have them, and putting them around the board. You should probably put theses on first, and then draw/make things to put on the board afterward.

Hope this gives you some ideas, if not though, comment down below and I can help more!

Answer:

To make a 0.160 M aqueous solution of cobalt(II) fluoride using a 300 mL volumetric flask, you should add 7.68 grams of solid cobalt(II) fluoride.

Explanation:

Step 1: Calculate the number of moles of cobalt(II) fluoride needed to make the solution.

Molarity = moles of solute / liters of solution

0.160 M = moles of cobalt(II) fluoride / 0.3 L

moles of cobalt(II) fluoride = 0.160 M x 0.3 L = 0.048 moles

Step 2: Calculate the mass of cobalt(II) fluoride needed based on its molar mass.

The molar mass of cobalt(II) fluoride is:

CoF2 = 58.933 g/mol (cobalt) + 2 x 18.998 g/mol (fluorine) = 97.929 g/mol

Mass of cobalt(II) fluoride = moles of cobalt(II) fluoride x molar mass

Mass of cobalt(II) fluoride = 0.048 moles x 97.929 g/mol = 4.697 g

Step 3: Add the calculated mass of cobalt(II) fluoride to the volumetric flask, then add enough water to fill up to the 300 mL mark.

However, note that solid cobalt(II) fluoride may not be readily available in the lab, and proper safety measures should be taken when handling any chemicals.

Explanation:

though the statements were not given let just give you a brief review of normative system.

A normative statement explains what should be base of the subject according to the belief through valued judgement that describes the fairness of the subject on public policy. Therefore, the unemployment rate should be lowered is a valued judgement based on the belief that it will bring economic welfare.

Normative systems, i.e., sets of norms, have two main. tions: a) to evaluate human actions, and b) to guide peop. The guidance and the evaluation based on a normativ. be good or bad.In social psychology three different normative behaviours have been identified: obedience, conformity and compliance.In the context of a normative system like law (or religion or morality), every statement of what one ought to do (or ought not to do) requires justification from a more general or basic statement. Such statements lead upward through the normative hierarchy until one reaches a foundational normative premise.

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Answer:

Explanation:

The density would be 4.

Answer:

439.7nm

Explanation:

Energy of a quantum can be calculated using below formula

E=hv...........eqn(1)

But v=λ/ c .........eqn(2)

If we substitute eqn(2) into eqn(1) we have

E= hc/(λ)

Where E= energy

h= Plank's constant= 6.62607004 × 10-34 m2 kg / s

c= speed of light

c= 2.998 × 10^8 m/s

λ= wavelength= ?

But the energy was given in Kj , it must be converted to Kj/ photon for unit consistency.

Energy E= 272 kJ/mol × 1mol/6.02× 10^23

Energy= 451.83× 10^-24 Kj/ photon

E= hc/(λ)...........eqn(1)

If we make λ subject of the formula

λ= hc/E

Then substitute the values we have

λ= [(6.626 × 10^-34) × (2.998 × 10^8)]/451.83× 10^-24

λ=(0.00043965) × (1Kj/1000J) × (10^9nm/1m)

λ=439.7nm

Hence, the longest wavelength of radiation with enough energy to break carbon-sulfur bonds is 439.7nm

The mass percent of MgCO3 in the mixture is 18.33%.

In the mixture we have:

MgCO3 + (NH4)2CO3 but the percentage by mass of carbonate CO3 is 64.16%

Hence,

Total mass = 100 grams

Let the mass of MgCO3 = x grams

Let the mass of (NH4)2CO3 = y grams

So we have,       x + y = 100 ------------(1)

If the mass of CO3 = 64.16% = 64.16 g

But the molar mass of CO3 = 60 g/mol

Then,

Number of moles of CO3 = 64.16 g/60 g.mol-1 = 1.069 moles

Since we obtained the number of moles of CO3 from CO3 in MgCO3 and (NH4)2CO3.

Therefore,

moles MgCO3 + moles (NH4)2CO3 = 1.069

mass of MgCO3 present/molar mass MgCO3 + mass of (NH4)2 CO3 present/molar mass = 1.069

So,

x/84 + y/96 = 1.069---------(2)

From equation 1;

 y =100 - x  

x/84 + (100-x)/96 = 1.069

x = 18.33 g

Mass of MgCO3 = 18.33 g

Mass percent of MgCO3 = 18.33%

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In the given reaction, the limiting reactant is C₆H₆ (benzene).

To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.

The number of moles for each reactant:

Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol

Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂

                     = 45 g / 71 g/mol

                     = 0.634 moles of Cl₂

Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol

Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆

                        = 45 g / 78 g/mol = 0.577 moles of C₆H₆

Determine the stoichiometry between Cl₂ and HCl:

Cl₂ + C₆H₆ → C₆H₅Cl + HCl

Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.

Thus, the limiting reactant is C₆H₆ (benzene).

Calculate the mass of HCl produced:

Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol

Moles of HCl produced = moles of C₆H₆ = 0.577 moles

Mass of HCl produced = moles of HCl produced × molar mass of HCl

Mass of HCl produced = 0.577 moles × 36.5 g/mol

                                     ≈ 21.04 g

Therefore, approximately 21.04 grams of HCl will be produced.

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Sally is wrong because copper is less electropositive than hydrogen, thus, can not displace hydrogen from dilute acids.

The reactions to prepare copper (ii) chloride are:

the chlo­ri­na­tion of cop­per sul­fide at a high tem­per­a­ture

reaction of copper (ii) oxide with dilute hydrochloric acid

The equations of the given reactions are as follows:CuS + Cl₂ ---> CuCl₂ + SCuO + 2HCl ----> CuCl₂ + H₂O

Reactive metals are metals that readily give up their electrons to form positive ions.

Reactive metals displace hydrogen from dilute acids. They are found in group 1A and 2A of the periodic table. Copper is not a reactive metal and will not displace hydrogen from acids.

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Sally is wrong because copper chloride is not made from the reaction of copper and dilute hydrochloric acid.

2. Copper (ii) chloride can be prepared as follows:

3. the equations of the reaction are:

Single replacement reactions are reactions in which a more reactive atom replaces another atom in a compound.

An example of a single replacement reaction is the reaction of chlorine gas with copper sulfide at high temperatures to form copper chloride.

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During high-intensity interval training, the body's metabolism shifts to meet the increased energy demands of the workout. The most important metabolic processes during high-intensity interval training include:

1. Glycolysis: The breakdown of glucose to produce energy in the form of ATP (adenosine triphosphate).

2. Lipolysis: The breakdown of fats to release fatty acids into the bloodstream, which can then be used as fuel.

3. Oxidative phosphorylation: The production of ATP through the process of cellular respiration, in which glucose and fatty acids are oxidized to produce energy.

The regulatory enzyme involved in these metabolic processes is AMPK (AMP-activated protein kinase), which increases in activity during exercise to stimulate the breakdown of glucose and fatty acids and the production of ATP.

The regulation of metabolism during exercise involves changes in enzyme activity, which can be either covalent or allosteric. In the case of high-intensity interval training, enzyme activity is increased through allosteric regulation, which involves the binding of regulatory molecules to the enzyme to alter its activity.

Metabolic products such as lactic acid and hydrogen ions can affect fatigue during high-intensity interval training. Lactic acid buildup in the muscles can cause fatigue and muscle pain, while the accumulation of hydrogen ions can disrupt muscle function and lead to fatigue.

We are tired in the sarcoplasmic reticulum after exercise because it has been depleted of its energy stores (ATP and glycogen) during the workout. Additionally, the increased levels of metabolic by-products such as lactic acid and hydrogen ions can cause fatigue and disrupt muscle function. The sarcoplasmic reticulum is responsible for storing and releasing calcium ions, which are necessary for muscle contraction. When it is depleted of energy, it can no longer perform this function effectively, leading to fatigue.

Answer:

During high-intensity interval training (HIIT), the body undergoes a number of metabolic processes to provide energy for the muscles. The most important processes are anaerobic glycolysis, which involves the breakdown of glucose to produce energy, and aerobic respiration, which involves the breakdown of glucose and fatty acids in the presence of oxygen.

The regulatory enzyme involved in metabolism during exercise is AMP-activated protein kinase (AMPK). AMPK helps to regulate energy balance in the cells by increasing glucose uptake and fatty acid oxidation, while decreasing glucose production and lipid synthesis.

Metabolism during exercise is regulated through a combination of covalent and allosteric modifications of enzyme activity. Covalent modifications involve the phosphorylation of enzymes, which changes their activity. Allosteric modifications involve the binding of regulatory molecules to enzymes, which changes their conformation and activity.

During exercise, a number of metabolic products can affect fatigue, including lactic acid and hydrogen ions, which can disrupt the acid-base balance in the muscles and lead to fatigue. Another important factor is the depletion of glycogen stores, which can lead to a reduction in energy production.

In the sarcoplasmic reticulum, the accumulation of calcium ions can lead to fatigue after exercise. This is because the increased levels of calcium ions can disrupt the normal functioning of the sarcoplasmic reticulum, which is responsible for regulating muscle contractions. The accumulation of calcium ions can also lead to the activation of proteolytic enzymes, which can break down proteins and contribute to muscle fatigue.

Explanation:

Answer:

The inner core is solid, the outer core is liquid, and the mantle is solid/plastic. This is due to the relative melting points of the different layers (nickel–iron core, silicate crust and mantle) and the increase in temperature and pressure as depth increases.

Explanation:

By decreasing agitation, rate of dissolution of a solid in a liquid can be decreased. Therefore, the correct option is option C.

To dissolve means to move a solute into a solution in chemistry. Dissolution is another word for dissolving. Dissolution often entails a solid transitioning into such a liquid phase, although it can also involve additional changes.

For instance, when alloys develop, a solid solution is created when one resulting effect into another. A process must fulfill specific requirements in order to be deemed dissolution. By decreasing agitation, rate of dissolution of a solid in a liquid can be decreased.

Therefore, the correct option is option C.

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Answer:

11.45

Explanation:

The ph is just 14-pOH so

14-2.55=ph=11.45

To dilute the Kool-Aid solution to a concentration of 2.00 M, we need to calculate the volume of water (Vw) that needs to be added.

The initial concentration of Kool-Aid solution is 13.2 M, and the initial volume is 0.512 L. Let's assume that Vw is the volume of water we need to add to dilute the solution to a concentration of 2.00 M.

Since the total volume after dilution will be the sum of the initial volume of Kool-Aid solution and the volume of water added, we can set up the following equation based on the dilution formula:

C1V1 = C2V2

where

C1 = initial concentration of Kool-Aid solution = 13.2 M

V1 = initial volume of Kool-Aid solution = 0.512 L

C2 = final concentration of Kool-Aid solution = 2.00 M

V2 = final volume of Kool-Aid solution after adding water = 0.512 L + Vw

Substituting the given values into the equation, we get:

13.2 M x 0.512 L = 2.00 M x (0.512 L + Vw)

Simplifying the equation, we get:

6.7584 L·M = 1.024 L·M + 2.00 M·Vw

Subtracting 1.024 L·M from both sides, we get:

5.7344 L·M = 2.00 M·Vw

Dividing both sides by 2.00 M, we get:

Vw = 2.8672 L

Therefore, we need to add 2.8672 L of water to 0.512 L of 13.2 M Kool-Aid solution to dilute it to a concentration of 2.00 M.

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Answer:

Option C. The same number of energy levels.

Explanation:

From the diagram given above, element (i) belong to group 2 while element (ii) belong to group 6.

Also, both element i and ii belong to the same period (i.e period 4). This simply means that both element i and ii have the same number of energy levels.

NOTE: Elements in the same period have the same number of shells of electrons which simply means they have the same energy levels.

For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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Answer: 1.3 moles Fe

Explanation:

I think you do this by unitary method that is

3 moles O2 react with 4 moles Fe

∴ 1 mole O2 react with 4/3 = 1.3 moles Fe

An average brightness was calculated for each length of graphite tested to get a better understanding of the relationship between the length of the graphite and the brightness of the line it produced.

Graphite has many uses in various industries. Some of its uses include: Pencils, Lubricants, Refractories, Batteries, Electrodes, Nuclear reactors, Aerospace industry.

By calculating the average, it is possible to see if there is a trend in the data and if longer or shorter lengths of graphite produce brighter or duller lines. This information can be useful in determining the best length of graphite to use for a particular task or project.

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Answer:

Oxygen has 8 protons in the nucleus while nitrogen only has 7. A bonding pair will experience more attraction from the oxygen's nucleus than from nitrogen's, and so the electronegativity of oxygen is greater.

ANSWER

EXPLANATION

Given that;

The two compounds given are CaCl2 and Ag2SO4

Firstly, write a balance chemical equation between the two compounds

To write a balanced equation, apply the law of conservation of mass

The law of conservation mass states that matter can neither be created nor destroyed but can be transformed from one form to another.

Hence, we have

In an aqueous solution, precipitation is the process of transforming a dissolved substance into an insoluble substance.

Therefore, the precipitate in the above molecular equation is AgCl

Part B

Follow the steps below to write the total ionic equation

Firstly, write the compounds in aqueous inform of ions

Part C

Eliminate the spectator ions to write the net ionic equation.

Recall, spectators ions are ions that appear on both reactant and product sides

Answer:

no of moles=mass in gm÷molar mass so let x be the mass in gm

4.5=x÷35.5×2

x=4.5×35.5×2 grams

x=319.5 gm

Explanation:

formula

Answer: the asnwer would be cycle

Explanation:cycle it

Isotope notation is written as the element symbol (in this case, S for sulfur) followed by the atomic mass number and the atomic number.

An element is a chemical substance that consists of one type of atom. All elements are made up of protons, neutrons, and electrons. The number of protons in an atom is what makes it a unique element. Each element has its own atomic number, which is the number of protons in the nucleus of an atom. Elements are the building blocks of all matter, and they are found in all living things, as well as in a variety of nonliving materials. Examples of elements include hydrogen, oxygen, nitrogen, carbon, and iron.

Since the number of protons is 16, the atomic number is also 16. The number of neutrons is 17, and the number of electrons is 18. Therefore, the correct isotope notation is 32S-2.

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Answer:

water is 9/10

chemical would be 1/10

Explanation:

180/200 would be water concentration in solution

and 20/200 would be chemical solution concentration in solution (if the chemical were to be polar and mix)

Answer:

50.76 g/cm³

Explanation:

We'll begin by converting 18.361 Kg to g. This can be obtained as follow:

1 Kg = 1000 g

Therefore,

18.361 Kg = 18.361 Kg × 1000 g / 1 Kg

18.361 Kg = 18361 g

Next, we shall express the dimension in the same unit of measurement.

Dimension = 22.35 cm x 7.34 cm x 22.05 mm

Thus, we shall convert 22.05 mm to cm. This can be obtained as follow:

10 mm = 1 cm

Therefore,

22.05 mm = 22.05 mm × 1 cm / 10 mm

22.05 mm = 2.205 cm

Thus, the dimension is 22.35 cm x 7.34 cm x 2.205 cm.

Next, we shall determine the volume of the metal. This can be obtained as follow:

Dimension = 22.35 cm x 7.34 cm x 2.205 cm.

Volume = 361.728045 cm³

Finally, we shall determine the density of the metal. This can be obtained as follow:

Mass of metal = 18361 g

Volume of metal = 361.728045 cm³

Density of metal =?

Density = mass / volume

Density of metal = 18361 / 361.728045

Density of metal = 50.76 g/cm³