Is square root 49 smaller or is power of 3 square root of 216

Answer:a) The 12 o'clock position: Al and Betty are 35 feet above the ground when they are at the 12 o'clock position on the Ferris wheel.

b) The 9 o'clock position: Al and Betty are 5 feet above the ground when they are at the 9 o'clock position on the Ferris wheel.

c) The 6 o'clock position: Al and Betty are 20 feet above the ground when they are at the 6 o'clock position on the Ferris wheel.

d) The 8 o'clock position: Al and Betty are 5 feet above the ground when they are at the 8 o'clock position on the Ferris wheel.

e) 10 seconds after passing the 11 o'clock position: Al and Betty are 35 feet above the ground when they are 10 seconds after passing the 11 o'clock position on the Ferris wheel.

2) Al and Betty are 30 feet above the ground when they are at the 2 o'clock position on the Ferris wheel.

Step-by-step explanation:

The given matrix is an elementary matrix that represents an elementary row operation of multiplying the second row by 4k. The determinant of this matrix is determinant of the original matrix, which is 4k.

Therefore, the determinant of the given elementary matrix is 4k.

To verify this result, we can also compute the determinant using the formula for a 3x3 matrix. The matrix obtained by applying the elementary row operation to the identity matrix is:

\(\left[\begin{array}{ccc}1&0&0\\0&4k&0\\0&0&1\end{array}\right]\)

The determinant of this matrix is calculated as: det(A) = 1 * (4k) * 1 - 0 * 0 * 0 - 0 * (4k) * 0 = 4k. So, the determinant of the given elementary matrix is indeed 4k, which matches our previous result.

In summary, the determinant of the elementary matrix is 4k, and this can be verified by calculating the determinant using the formula for a 3x3 matrix.

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Answer:

y-y1=m(x-x1)

y+1=-2(x-7)

y+1=-2x+14

-1           -1

y=-2x+13

Step-by-step explanation:

Answer:

Whats the answer???

Step-by-step explanation:

13 was subtracted from a number and that difference was then divided by 5. After which, that quotient was multiplied by 7. The resulting product was -7. What was the number? (

By using the formula and substituting the z-score, Rylee did approximately 58.6 sit-ups.

The mean, also known as the average, is a measure of central tendency that represents the sum of a set of numbers divided by the number of items in the set. It is calculated by adding all the numbers in the set and dividing the sum by the total number of numbers.

A z-score, also known as a standard score, is a measure of how many standard deviations a data point is from the mean of a data set. It is calculated by subtracting the mean of the data set from the value of the data point and dividing the result by the standard deviation of the data set.

To find the number of sit-ups that Rylee did, we can use the formula for converting a z-score to a raw score:

X = μ + z * σ

where X is the raw score (the number of sit-ups in this case), μ is the mean, z is the z-score, and σ is the standard deviation.

Plugging in the given values, we get:

X = 46 + 1.8 * 7 = 46 + 12.6 = 58.6

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Answer:  D) 11/9

Step-by-step explanation:

LCM of 5, 9, 3, 8, 7 = 5 x 9 x 8 x 7 = 2520

Convert each fraction so the denominator = 2520

\(\dfrac{3}{5}\bigg(\dfrac{9\times 8 \times 7}{9\times 8 \times 7}\bigg)=\dfrac{1512}{2520}\\\\\\\dfrac{5}{9}\bigg(\dfrac{5\times 8 \times 7}{5\times 8 \times 7}\bigg)=\dfrac{1400}{2520}\\\\\\\dfrac{2}{3}\bigg(\dfrac{5\times 3\times 8 \times 7}{5\times 3\times 8 \times 7}\bigg)=\dfrac{1680}{2520}\\\\\\\dfrac{5}{8}\bigg(\dfrac{5\times 9 \times 7}{5\times 9 \times 7}\bigg)=\dfrac{1575}{2520}\\\\\\\dfrac{4}{7}\bigg(\dfrac{5\times 9 \times 8}{5\times 9 \times 8}\bigg)=\dfrac{1440}{2520}\\\\\\\)

The smallest number is  \(\dfrac{1400}{2520}=\dfrac{5}{9}\)  and the largest number is \(\dfrac{1680}{2520}=\dfrac{2}{3}\)

\(\dfrac{5}{9}+\dfrac{2}{3}\\\\\\=\dfrac{5}{9}+\dfrac{2}{3}\bigg(\dfrac{3}{3}\bigg)\\\\\\=\dfrac{5+6}{9}\\\\\\=\large\boxed{\dfrac{11}{9}}\)

Hey there!

3(7n + 6) - 5n

= 3(7n) + 3(6) - 5n

= 21n + 18 - 5n

= 16n + 18

Therefore, your answer should be:

16n + 18

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

8 legs for every 4 ears

2 legs for every 1 ear

There are 8 legs for every 4 ears while there are 2 legs for every 1 ear.

The ratio is the division of the two numbers.

Proportion is the relation of a variable with another. It could be direct or inverse.

Given two mouse,

Number of ears of one mouse = 2

Number of legs of one mouse = 4

Ratio of legs to ear = 4/2 = 2

So,

Legs corresponding to 4 ears = 2×4 = 8

Legs corresponding to 1 ears = 2×1 = 2

Hence "There are 8 legs for every 4 ears while there are 2 legs for every 1 ear".

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Answer:

We know by given that OC bisects the angle, which means it divides the angle AOB in two equal parts. So,

\(m \angle AOB = 3x +5 + 3x +5 =6x+10\)

If \(x=9\), then we use this value to find each angle.

\(m \angle BOC = 3x+5 =3(9)+5=27+5=32\)

Therefore, angles BOC and AOC measure 32°.

Answer:

29

Step-by-step explanation:

5x5=25

25+4=29

First for 5 times 5 u do 5x5=25 and for (5x5) plus four u add 4 to the answer of 5 times five which makes 29.

Answer:

The answer is 29

Step-by-step explanation:

5 times 5 plus 4

5 × 5 + 4

Use BODMAS

(Bracket of Division, Multiplication, Addition and Subtraction)

(5 × 5) + 4 = 25 + 4 = 29

Thus, The answer is 29

-TheUnknownScientist 72

Answer:

G. 19 is your answer dear

Step-by-step explanation:

9(3)-4(2)

27-8 = 19

Where the above conditions are given,  the correct option is: Plan 1 is a better deal for more than 5 cards purchased.

To determine   which pricing plan is a better deal,we need to compare the total cost for a certain number of game cards purchased.

Let's calculate the   total cost for different numbers  of game cards.

For Plan 1  -

- Admission fee  - $5 (fixed)

- Cost per game card  - $1

For Plan 2  -

- Admission fee  - $2.50 (fixed)

- Cost per game card  - $1.50

Now, let's compare the total cost for different numbers of game cards  -

1. If you purchase 1 game card  -

  - Plan 1  - $5 (admission fee) + $1 (cost per game card) = $6

  - Plan 2  - $2.50 (admission fee) + $1.50 (cost per game card) = $4

2. If you purchase 5 game cards  -

  - Plan 1  - $5 (admission fee) + $5 (cost for 5 game cards) = $10

  - Plan 2  - $2.50 (admission fee) + $7.50 (cost for 5 game cards) = $10

3. If you purchase 8 game cards  -

  - Plan 1  - $5 (admission fee) + $8 (cost for 8 game cards) = $13

  - Plan 2  - $2.50 (admission fee) + $12 (cost for 8 game cards) = $14.50

Based on these calculations, we can conclude that  -

- Plan 1 is a better deal for more than 5 cards purchased.

- Plan 2 is a better deal for more than 8 cards purchased.

Therefore, the correct option is  - Plan 1 is a better deal for more than 5 cards purchased.

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The solution to the inequality 5x - 18 > 2(4x - 15) is x < 4.

To solve the inequality 5x - 18 > 2(4x - 15), we can simplify the expression and isolate the variable x.

First, distribute the 2 to the terms inside the parentheses:

5x - 18 > 8x - 30

Next, we want to isolate the x terms on one side of the inequality.

Let's move the 8x term to the left side by subtracting 8x from both sides:

5x - 8x - 18 > -30

Simplifying further, we combine like terms:

-3x - 18 > -30

Now, let's isolate the variable x.

We can start by adding 18 to both sides of the inequality:

-3x - 18 + 18 > -30 + 18

Simplifying further:

-3x > -12

To isolate x, we need to divide both sides of the inequality by -3. However, when we divide by a negative number, we need to flip the inequality sign:

(-3x) / (-3) < (-12) / (-3)

Simplifying gives us:

x < 4.

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The correct option is B. 0.0043

The P-value for this hypothesis test is 0.0043.

With the aid of a statistical test, researchers weigh the evidence in favor of and against the null and alternate hypotheses, which are two opposing claims:

The impact of the independent on the dependent variable is often the effect.

In this one-tailed test, the null and alternate hypotheses are as follows:

H₀ : p₁ - p₂ = 0

Ha : p₁ - p₂ > 0

A size-2 vector containing the test statistic's value statistic and the P-value is the result of the proportions ztest method from statsmodels.

A P-value for such one-tailed test becomes 0.0043 if the result is (3.25, 0.0043).

Therefore, the P-value for null and alternative hypotheses test is 0.0043.

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The complete question is -

The null and alternative hypotheses for a hypothesis test of the difference in two population means are: Alternative Hypothesis: p1 > p2 Null Hypothesis: Hi = uz Notice that the alternative hypothesis is a one-tailed test. Suppose proportions_ztest method from statsmodels is used to perform the test and the output is (3.25, 0.043).

What is the P-value for this hypothesis test?

A. 0.00215

B. 0.0043

C. 3.25

D. -3.25

For a two-dimensional potential flow, the potential is given by 1 r (x, y) = x (1 + arctan x² + (1+ y)², 2πT where the parameter A is a real number. Given potential function is;ϕ(x,y) = x(1 + arctan(x² + (1+y)²))/2πT

To find velocity components ux and uy, we need to take partial derivative of potential functionϕ(x,y) = x(1 + arctan(x² + (1+y)²))/2πTUsing the chain rule;    ∂ϕ/∂x = ∂ϕ/∂r * ∂r/∂x + ∂ϕ/∂θ * ∂θ/∂x                                                                                             = cosθ * (1/r) * x(1+arctan(x² + (1+y)²))/2πT           - sinθ * (1/r) * x(1+arctan(x² + (1+y)²))/2πT ∂ϕ/∂y = ∂ϕ/∂r * ∂r/∂y + ∂ϕ/∂θ * ∂θ/∂y                                                                                              = cosθ * (1/r) * x(1+arctan(x² + (1+y)²))/2πT           - sinθ * (1/r) * x(1+arctan(x² + (1+y)²))/2πTNow, replace cosθ and sinθ with x/r and y/r respectively∂ϕ/∂x = x/(x²+y²) * x(1+arctan(x² + (1+y)²))/2πT- y/(x²+y²) * x(1+arctan(x² + (1+y)²))/2πT= [x²-y²]/(x²+y²) * x(1+arctan(x² + (1+y)²))/2πT∂ϕ/∂y = y/(x²+y²) * x(1+arctan(x² + (1+y)²))/2πT + x/(x²+y²) * x(1+arctan(x² + (1+y)²))/2πT= [2xy]/(x²+y²) * x(1+arctan(x² + (1+y)²))/2πT(2) To find stagnation point, we have to find (x,y) such that ux = uy = 0 and ϕ(x,y) is finite. Here, from (1) we get two equations;  x(1+arctan(x² + (1+y)²))/2πT= 0 and  x(1+arctan(x² + (1+y)²))/2πT + y(1+arctan(x² + (1+y)²))/2πT= 0For (1), either x=0 or arctan(x² + (1+y)²) = -1, but arctan(x² + (1+y)²) can't be negative so x=0. Thus, we get the condition y= -1  from (2)So, stagnation point is (0, -1).(3) For the far field, pressure is p, density is P. In potential flow, we have;  P = ρv²/2 + P0,  where P0 is constant pressure. Here, P0 = P and v = ∇ϕ   so, P = ρ[ (∂ϕ/∂x)² + (∂ϕ/∂y)² ]/2Using expressions of ∂ϕ/∂x and ∂ϕ/∂y obtained above, we can find pressure at (0,-2).(4) Given flow is around a cylinder. For flow around cylinder, stream function can be written as;   ψ(r,θ) = Ur sinθ (1-a²/r²)sinθTo find centre and radius of the cylinder, we find point where velocity is zero. We know that ψ is constant along any streamline. So, at the boundary of cylinder, ψ = ψ0, and at the centre of the cylinder, r=0.Using stream function, it is easy to show that ψ0= 0.So, at boundary of cylinder; U(1-a²/R²) = 0, where R is radius of cylinder, which gives R=aSimilarly, at centre; U=0To find the resulting force on the cylinder, we first have to find the lift and drag coefficients;  C_d = 2∫_0^π sin²θ dθ = π/2   and  C_l = 2∫_0^π sinθ cosθ dθ = 0We know that C_d = F_d/(1/2 ρ U²L) and C_l = F_l/(1/2 ρ U²L)where L is length of cylinder.So, F_d = π/2 (1/2 ρ U²L) and F_l= 0. Thus, the resulting force is F= (π/2) (1/2 ρ U²L) at an angle 90° to the flow direction.

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Using these values, we can write Bernoulli's equation as: P + 1/2 * ρ * ((1 + arctan(5))^2 + (4/3)^2) = P_far

P = P_far - 1/2 * ρ * ((1 + arctan(5))^2 + (4/3)^2)

(1) To determine the expression for the velocity components ux and uy, we can use the relationship between velocity and potential in potential flow:

ux = ∂Φ/∂x

uy = ∂Φ/∂y

Taking the partial derivatives of the potential function Φ(x, y) with respect to x and y:

∂Φ/∂x = (1+arctan(x^2+(1+y)^2)) - x * (1/(1+x^2+(1+y)^2)) * (2x)

∂Φ/∂y = -x * (1/(1+x^2+(1+y)^2)) * 2(1+y)

Simplifying these expressions, we have:

ux = 1 + arctan(x^2+(1+y)^2) - 2x^2 / (1+x^2+(1+y)^2)

uy = -2xy / (1+x^2+(1+y)^2)

(2) To find the value of A such that the point (x, y) = (0,0) is a stagnation point, we need to find the conditions where both velocity components ux and uy are zero at that point. By substituting (x, y) = (0,0) into the expressions for ux and uy:

ux = 1 + arctan(0^2+(1+0)^2) - 2(0)^2 / (1+0^2+(1+0)^2) = 1 + arctan(1) - 0 = 1 + π/4

uy = -2(0)(0) / (1+0^2+(1+0)^2) = 0

For the point (x, y) = (0,0) to be a stagnation point, ux and uy must both be zero. Therefore, A must be chosen such that:

1 + π/4 = 0

A = -π/4

(3) To determine the pressure at the point (0, -2), we can use Bernoulli's equation for potential flow:

P + 1/2 * ρ * (ux^2 + uy^2) = constant

At the far field, where the velocity is assumed to be zero, the pressure is constant. Let's denote this constant pressure as P_far.

At the point (0, -2), the velocity components ux and uy are:

ux = 1 + arctan(0^2+(1-2)^2) - 2(0)^2 / (1+0^2+(1-2)^2) = 1 + arctan(5) - 0 = 1 + arctan(5)

uy = -2(0)(-2) / (1+0^2+(1-2)^2) = 4 / 3

Using these values, we can write Bernoulli's equation as:

P + 1/2 * ρ * ((1 + arctan(5))^2 + (4/3)^2) = P_far

Solving for P at the point (0, -2), we have:

P = P_far - 1/2 * ρ * ((1 + arctan(5))^2 + (4/3)^2)

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Considering the histogram, it is found that the team scored more than 50 points 26 times.

An histogram is a graph that shows the number of times each element of x was observed.

Researching this problem on the internet, we have that:

12 + 11 + 3 = 26, hence the team scored more than 50 points 26 times.

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Answer:

40

Step-by-step explanation:

200 ÷ 5 = 40.

Answer:

A.

\( - 1 \frac{1}{3} \)

Answer: it's \(\sqrt{5}\)

Step-by-step explanation:

Number of drivers that do not know the law = 65

Number of drivers that do not know the law but obeys the law = 50

Percentage of drivers that obey the law despite not knowing the law is

= 76.9 %

Answer:

45

Step-by-step explanation:

All you have to do is 1080/24 that gives you 45.

Taylor series for x^3tan^-1x^2 at x0 = 0 can be found by using the power series operations. The Taylor series for x^3tan^-1x^2 at x0 = 0 is:

x^3tan^-1x^2 = x^3(x^2 - (x^2)^3/3 + (x^2)^5/5 - ...)

To find the Taylor series, we need to express the function as a sum of terms with powers of (x - x0). We can start by using the power series for tan^-1x:

tan^-1x = x - x^3/3 + x^5/5 - ...

Then, we substitute x^2 for x and multiply by x^3 to get:

x^3tan^-1x^2 = x^3(x^2 - (x^2)^3/3 + (x^2)^5/5 - ...)

This gives us the Taylor series for x^3tan^-1x^2 at x0 = 0.

We can simplify the expression by expanding the powers of x:

x^3tan^-1x^2 = x^5 - x^7/3 + x^9/5 - ...

This means that the function can be approximated by the sum of these terms, which become more accurate as we include more terms. The Taylor series can be useful for approximating functions and making calculations easier, especially when using computers to perform calculations.

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The derivative of the given function \(\frac{(2x^2-x+6)^{2/3}}{2x^{-2}-2x+9}\) is \(\frac{\frac{2}{3}(2x^2-x+6)^{-1/3})(4x-1)(2x^{-2}-2x+9)+(2x^2-x+6)^{2/3})(4x^{-3}+2)}{(2x^{-2}-2x+9)^2}\).

We have to find the derivative for the given function.

Calculus and differential equations issues must be solved using derivatives. Futures contracts, options contracts, and credit default swaps are common types of derivatives.

The given function is

f(x) = \(\frac{(2x^2-x+6)^{2/3}}{2x^{-2}-2x+9}\) = h(x)/g(x)

Note that using the formula

(1) d/dx(f/g) = {gd/dx(f)-fd/dx(g)}/g^2

(2) d/dx(x^n) = nx^{n-1}

f'(x) = d/dx \(\frac{(2x^2-x+6)^{2/3}}{2x^{-2}-2x+9}\)

f'(x) = \(\frac{(2x^{-2}-2x+9)\frac{d}{dx}(2x^2-x+6)^{2/3})-(2x^2-x+6)^{2/3})\frac{d}{dx}(2x^{-2}-2x+9)}{(2x^{-2}-2x+9)^2}\)

f'(x) = \(\frac{(2x^{-2}-2x+9)\frac{2}{3}(2x^2-x+6)^{2/3-1})\frac{d}{dx}(2x^2-x+6)-(2x^2-x+6)^{2/3})(2(-2)x^{-3}-2)}{(2x^{-2}-2x+9)^2}\)

f'(x) = \(\frac{(2x^{-2}-2x+9)\frac{2}{3}(2x^2-x+6)^{2/3-1})(4x-1)+(2x^2-x+6)^{2/3})(4x^{-3}+2)}{(2x^{-2}-2x+9)^2}\)

f'(x) = \(\frac{\frac{2}{3}(2x^2-x+6)^{-1/3})(4x-1)(2x^{-2}-2x+9)+(2x^2-x+6)^{2/3})(4x^{-3}+2)}{(2x^{-2}-2x+9)^2}\)

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The right question is:

Find the derivative for the given function. Write your answer using positive and negative exponents and fractional exponents instead of radicals.

f(x) = \(\frac{(2x^2-x+6)^{2/3}}{2x^{-2}-2x+9}\)

Answer:

13x = 13

Step-by-step explanation: 2(5x-3)= 10x -6  3x + 10x = 13x-6=7

6+7=13=  13x =13

Answer:

 = 1

Step-by-step explanation:

3x + 2 (5 x - 3 ) = 7

3x + 10x - 6 = 7

your gonna combine 3x + 10x - 6 = 7

13x -6 = 7

(sorry if wrong)

1. The outcomes in the sample space of choosing a letter from the word STARK are: S, T, A, R, K.

2. Number of outcomes in the sample space = 6 (from THANKS) × 5 (from STARK) = 30.

3. The Probability of choosing the letters AA is 0, as there are no occurrences of the letter A in both words together.

1. The outcomes in the sample space of choosing a letter from the word THANKS are: T, H, A, N, K, S.

  The outcomes in the sample space of choosing a letter from the word STARK are: S, T, A, R, K.

2. To find the number of outcomes in the sample space, we multiply the number of outcomes for each word.

  Number of outcomes in the sample space = Number of outcomes for the first word × Number of outcomes for the second word

  Number of outcomes in the sample space = 6 (from THANKS) × 5 (from STARK) = 30.

3. The probability of choosing the letters AA would be the number of favorable outcomes (which is 0 in this case) divided by the total number of outcomes in the sample space.

  Probability of choosing AA = Number of favorable outcomes / Total number of outcomes

  Probability of choosing AA = 0 / 30 = 0.

Therefore, the probability of choosing the letters AA is 0, as there are no occurrences of the letter A in both words together.

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Answer:

their are 4 weeks in a month so 4*7=

28

so its 1/28 which is equals to (1 divided by 28)

3.57%

Hope This Helps!!!

Answer:

It depends on the amount of days in a month:

If 28 days: 3.57%

If 29 days: 3.45%

If 30 days: 3.33%

If 31 days: 3.23%

Step-by-step explanation:

1. Provided a month is defined as 30 days - change 30 days to correct amount for specified month. For days in a month, see table below.

2. Multiply daily income by days in a month: $3.50 * 30 days = $105.00/month.

2. Divide specified amount of $3.50 by monthly income: $3.50 ÷ $105.00 = 0.03333

3. Multiply faction by 100 to make into a percentage: 0.03333 * 100 = 3.333%

The duration of a month will vary.

January: 31 days; 3.23%

February: 28 days in a common year and 29 days in leap years; 3.57% or, if leap year, 3.45%

March – 31 days; 3.23%

April – 30 days; 3.33%

May – 31 days; 3.23%

June – 30 days; 3.33%

July – 31 days; 3.23%

August – 31 days; 3.23%

September – 30 days; 3.33%

October – 31 days; 3.23%

November – 30 days; 3.33%

December – 31 days; 3.23%.

Answer:

The best chart to show how your department's expenses compare to the total company's expenses, and hopefully save employee jobs, would be:

Pie Chart

Step-by-step explanation:

Answer:

n < 2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

2(n + 3) - 4 < 6

Step 2: Solve for n

Here we see that any value n smaller than 2 would work as a solution to the inequality.

The Lateral Surface Area of Cylinder 460π and volume is 2300π unit³.

We know the Formula for LSA of cylinder is

= 2πrh

Here, radius of cylinder = 20/2 = 10

Height of cylinder= 23

So, the Lateral Surface Area of Cylinder

=  2πrh

= 2 x 3.14 x 10 x 23

= 1444.4 unit²

= 460π

Now, Volume of cylinder

= πr²h

= π x 100 x 23

= 2300π unit³

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