Is oxygen the deadliest gas?

Answer:

It depends through where the glucose goes through

Explanation:

The molarity of the KMnO4 solution is 0.532 M (rounded to three decimal places).

To calculate the molarity of the KMnO4 solution, we need to use the stoichiometry of the reaction and the volume of the KMnO4 solution used in the titration.

Given:

Mass of H2O2 solution = 1.0 g

Concentration of H2O2 solution = 30 wt% (weight percent)

Volume of KMnO4 solution used = 22.143 mL

Molar mass of H2O2 = 34.01 g/mol

Step 1: Calculate the moles of H2O2 in the solution.

Moles of H2O2 = (Mass of H2O2 solution) / (Molar mass of H2O2)

= 1.0 g / 34.01 g/mol

= 0.0294 mol

Step 2: Calculate the moles of KMnO4 based on the stoichiometry of the reaction.

According to the balanced equation, the ratio of KMnO4 to H2O2 is 2:5.

Therefore, moles of KMnO4 = (Moles of H2O2) * (2/5)

= 0.0294 mol * (2/5)

= 0.01176 mol

Step 3: Calculate the molarity of the KMnO4 solution.

Molarity (M) = (Moles of KMnO4) / (Volume of KMnO4 solution in liters)

= 0.01176 mol / 0.022143 L

= 0.5316 M

Therefore, the molarity of the KMnO4 solution is 0.532 M (rounded to three decimal places).

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Answer:

1.85 × 10⁻⁶

Explanation:

0.0003 ÷ 162 = 1.851851852 × 10⁻⁶ ⇒ 1.85 × 10⁻⁶

Hope that helps.

The significant figure in the answer should be one here, since the number 0.0003 contains only one significant figure. Hence, the answer is 2 × 10⁻⁶.

Significant figures are digits in a quantity with certain values along with some uncertain digits. The counting of significant figures of a number should follow some rules.

The zeros after the decimal point which is not following a nonzero number are not significant. Therefore, there is only one significant figure in the number 0.0003.

For any arithmetic operation, the number of significant figures in the result should be equal to the one in operation that is with least significant figures.

Here.  162 have 3 significant figures. Therefore, the result should contain only one significant figure.

0.0003 /162 = 1.85  × 10⁻⁶.

Then the result with correct significant figures is rounded to 2 × 10⁻⁶.

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The new volume will be 10.41 L.

P₁V₁ = P₂V₂ , where

P₁V₁ = Volume and the pressure of the gas at initial stage
P₂V₂ = Volume and the pressure of the gas at final stage

To get V₂, rearrange the equation,
V₂ = P₁/P₂ * V₁
     = 81.3 kPa / 16.4 kPa * 2.1 L
     = 10.41 L


The frequency and force of the collisions between the gas molecules and the container walls determine the gas pressure. Because the molecules are travelling with the same average kinetic energy, they must collide with the container walls less frequently.

The only way to do this is to increase the volume. Boyle's Law states that pressure and volume have an inverse relationship when temperature and the number of moles are held constant. This results from the requirement that the volume-pressure product remain constant during this process.

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The total mass of 4 tin is in grams is 580 grams and in kg is 0.58kg.

One tin of chopped tomatoes weight is 145 grams

and we have to calculate it for 4

so for 4

145*4 =580 grams

and we have to change it into kilograms so

580 /1000  = .58kg

By 1,000, divide the number of grams.

To convert from grams to kilograms, simply divide by 1,000 because there are 1,000 grams in every kilogram. If necessary, construct the equation using fractions. Put the number of grams over 1 and divide it by the conversion factor, which is 1 kg / 1,000 g. Your answer in kilograms will result from the cancellation of the grams. Remember to use the appropriate units to mark your response.

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Explanation:

In a solid particles are firmly together and are stuck in a regular pattern

in a liquid particles still touch but arent in a fixed pattern

in a gas particles move quickly in all directions

Rust is a flaky reddish brown layer that forms on metal. Rust is a Hydrated Iron (III) Oxide with the chemical formula Fe₂O₃ + H₂O.

Now, as per the question:

Mass of Iron = 51.85g

Mass of Oxygen = 22.22g

Mass of Water = 16.67g

Therefore,

Moles of Iron, Fe = \(\frac{ 51.85}{ 55.84}\) mol

Moles of Oxygen, O =  \(\frac{22.22}{15.99 }\) mol

Moles of Water, H₂O = \(\frac{16.67}{18.01}\) mol

Simplest mole ratio:

Fe: O: H₂O ::   \(\frac{ 51.85}{ 55.84}\) :   \(\frac{22.22}{15.99 }\) :  \(\frac{16.67}{18.01}\)

Fe: O: H₂O :: 0.92 : 1.38 : 0.92

Thus, the simplest mole ratio of Fe: O: H₂O is 0.92 : 1.38 : 0.92.

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The longest wavelength light capable of ionizing a hydrogen atom in the n=7 state is approximately 913.4 nanometers.

To determine the longest wavelength of light capable of ionizing a hydrogen atom in the n=7 state, we need to consider the energy levels of hydrogen atoms and the ionization process.

In hydrogen atoms, electrons occupy different energy levels or shells, labeled by the principal quantum number (n). The energy of an electron in a specific energy level is inversely proportional to the square of the principal quantum number. This means that higher energy levels have lower binding energies.

The ionization of a hydrogen atom occurs when an electron is completely removed from the atom, breaking the electrostatic attraction between the electron and the proton in the nucleus. Ionization requires supplying enough energy to overcome the binding energy of the electron.

The energy required to ionize a hydrogen atom in the n=7 state is equal to the energy difference between the n=7 energy level and the ionization energy level, which corresponds to the electron being completely removed from the atom.

The ionization energy of hydrogen is approximately 13.6 eV (electron volts). Using the energy equation E = hc/λ, where E is the energy of a photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of light, we can calculate the wavelength of the longest wavelength light capable of ionizing the hydrogen atom.

First, we convert the ionization energy from electron volts to joules:

1 eV =\(1.602 \times 10^{-19\) J

Ionization energy = 13.6 eV × 1.602 ×\(10^{-19\) J/eV = 2.179 × 10^-18 J

Next, we rearrange the energy equation to solve for wavelength:

λ = hc/E

Plugging in the known values:

λ = (6.626 × 10^-34 J·s × 3.00 × \(10^8\) m/s) / (2.179 × \(10^{-18\) J)

Calculating this equation yields:

λ ≈ 913.4 nm

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Reaction 1 is an oxidation/reduction reaction. This is because Magnesium(Mg) is oxidized (0 to +2) while H is reduced (+1 to 0), which means that the reaction is an oxidation/reduction reaction.

An oxidation-reduction reaction(ORR) is a type of chemical reaction that occurs when electrons are transferred between molecules. One atom or molecule loses electrons (oxidation) while another atom or molecule gains electrons (reduction) in the process. The reaction is commonly referred to as a redox reaction.

Lewis acids and Lewis bases are compounds that can form a complex. The acid is an electron-pair acceptor(EPA), while the base is an electron-pair donor. This reaction results in a coordinate covalent bond. The acid-base reaction is a Lewis acid-Lewis base reaction. When a Lewis base is combined with a Lewis acid, the acid-base complex that forms has a coordinate covalent bond.

Double replacement reactions(DDR) involve an exchange of ions between two different compounds. The anions and cations of both compounds switch places to create two entirely different compounds. A double replacement reaction may be in one of two forms: Precipitation Reaction and Neutralization Reaction.

An ionization reaction occurs when an atom or molecule loses or gains electrons, resulting in the formation of ions. The ionization reaction may occur in two forms: neutral atoms/molecules → ions and ions → neutral atoms/molecules.

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Answer:

C

Explanation:

Brainliest

I tried my best

The term "catalyst" best describes the role of platinum in the system.

Let us explore the role that platinum plays as a catalyst. Catalysts are defined as substances that speed up the rate of chemical reactions without changing their own mass or chemical properties in the process.

The amount of energy required to activate a process is reduced when catalysts are added. It is stated in the question that if the system incorporates platinum, then the amount of energy that is required is going to be lower. Therefore, platinum is functioning as a catalyst in this situation because it is lowering the required activation energy of the reaction.

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Answer: Particles in all states of matter are in constant motion and this is very rapid at room temperature. A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. ... Individual particles in liquids and gases have no fixed positions and move chaotically.

HOPE THIS HELPS

Volatile organic compounds are organic chemicals that form toxic fumes.

Volatile organic compounds, or VOCs, are organic chemicals that readily vaporize at room temperature. They are emitted from a wide range of products and processes. Benzene, toluene, and xylene are examples of volatile organic compounds (VOCs). VOCs have been linked to a variety of health problems, including asthma and headaches. They can also cause irritation of the eyes, nose, and throat.

VOCs are released by a variety of sources, including paint, building materials, and household cleaning products. Gasoline, diesel fuel, and other fuels are also sources of VOCs. Many VOCs are also produced by natural sources like trees and vegetation, which is why they are present in outdoor air in addition to indoor air.

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Answer:

See explanation

Explanation:

We know that photosynthesis involves the combination of carbon dioxide and water in the presence of sunlight to yield glucose.

If the atmosphere is rich in carbon dioxide such as  in a green house where air is filled with carbon dioxide, the rate of photosynthesis is increased.

As the rate of photosynthesis is increased, the growth of plants is also increased.

Hence, in a greenhouse where the air contains more carbon dioxide, the rate of plant growth increases.

Answer:

1. The compound 2NaCl consists of:

» B. 1 atom of chlorine element.

» D. 1 atom of sodium element.

2. The valency of iron in iron (III) sulphate is:

» A. 3 [ valency of only iron ]

» B. 2 [ valency of only sulphate ion ]

3.The systematic name of the compound CuSO4:

» B. Copper (II) sulphate

Explanation:

\(.\)

Answer:

1) A.

2) A.

3) A.

Answer:

The answer according to me.............

Explanation:

Answer:

The new volume of the car tire is approximately 11.784 litres

Explanation:

The initial pressure of the air in the car tire, P₁ = 2.18 atm

The volume occupied by the air in the tire, V₁ =  10.0 L

The new pressure of the air in the tire, P₂ = 1.85 atm.

According to Boyle's Law, we have;

P₁·V₁ = P₂·V₂

Where;

P₁ = The initial pressure of the car tire = 2.18 atm

V₁ - The initial volume of the tire = 10.0 L

P₂ = The new pressure of the tire = 1.85 atm

V₂ = The new volume of the car tire = The required volume

Therefore;

\(V_2 = \dfrac{P_1 \cdot V_1}{P_2}\)

Plugging in the values gives;

\(V_2 = \dfrac{2.18 \ atm \times 10.0 \ L}{1.85 \ atm} = \dfrac{436}{37} \ L \approx 11.784 \, L\)

The new volume of the car tire, V₂ ≈ 11.784 L.

Out of the given options, 1.0 m glucose (aq) will have the lowest freezing point.

What is Freezing point?

Freezing point is the temperature at which a liquid transitions into a solid state at a given pressure. It is the temperature at which the vapor pressure of a solid and liquid phase of a substance are equal, and the liquid becomes a solid by releasing its latent heat of fusion.

The freezing point of a solution is lower than that of the pure solvent because the solute particles disrupt the formation of the solvent's crystal lattice. The extent of this effect depends on the concentration and nature of the solute.

The phenomenon is described by the equation ΔTf = Kf × m, where ΔTf is the change in freezing point, Kf is the cryoscopic constant for the solvent, and m is the molality of the solute.

In this case, glucose and Kf are both solutes added to water, so we can compare their molality values to determine which solution will have the lowest freezing point.

Since glucose is a non-electrolyte, it will not dissociate into ions in water, so its molality value is equal to its molarity value: 1.0 m.

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Answer:

Mass and charge is conserved

Explanation:

According to the law of conservation of mass, matter is neither created or destroyed. With the exception of nuclear reactions where mass is converted to energy thereby leading to an apparent loss in mass, this law applies to chemical reactions.

A redox reaction is a type of chemical reaction which involves a transfer of electrons. In a redox reaction, the mass of reactant particles is conserved. Also, as electrons are transferred between atoms, one donates and the other accepts. The charge of atoms depends on this gain or loss of electrons. A gain of electrons reduced the charge of an atom whereas a loss of electrons increases the charge. This two processes occur concurrently, therefore, charge is also conserved.

The percent composition of each element in C₂H₄O₂ is:

Carbon: 40 %

Hydrogen: 6.67 %

Oxygen: 53.33 %

The molar mass of C₂H₄O₂ can be calculated by adding the atomic masses of all the elements in the compound:

Molar mass = (2 x 12) + (4 x 1) + (2 x 16)

= 60 g/mol

Now we can calculate the percent composition of each element in C₂H₄O₂:

Percent composition of carbon is calculated as follows;

= (2 x 12 x 100%) / 60

= 40 %

Percent composition of hydrogen is calculated as follows;

= (4 x 1 x 100%) / 60

= 6.67 %

Percent composition of oxygen is calculated as follows;

= (2 x 16 x 100%) / 60

= 53.33 %

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The labs in this chemistry class use a green approach, which means they prioritize environmentally friendly practices.

In this chemistry class, the term "green approach" refers to a set of practices and principles that prioritize environmental sustainability and minimize negative impacts on the ecosystem. These labs aim to reduce their carbon footprint, conserve resources, and promote responsible waste management. By adopting a green approach, the class strives to align its scientific pursuits with the goal of environmental stewardship.

One of the key aspects of the green approach in these chemistry labs is the conscious selection and utilization of environmentally friendly materials and chemicals. This includes opting for safer alternatives to hazardous substances whenever possible, such as using non-toxic solvents or reagents. Additionally, the labs may encourage the use of renewable resources and promote the recycling or repurposing of materials to reduce waste generation.

Another important component of the green approach is energy conservation. The labs may employ energy-efficient equipment and lighting systems, as well as implement strategies to minimize energy consumption during experiments. For instance, they may encourage students to turn off equipment when not in use and adopt efficient heating or cooling methods.

Furthermore, the labs may focus on water conservation by promoting responsible water usage and minimizing water wastage during experiments. This could involve using water-efficient techniques, such as microscale experiments that require smaller amounts of water, or implementing recycling systems to capture and reuse water when appropriate.

By embracing a green approach, these chemistry labs aim to instill environmental awareness and responsibility in students while demonstrating that scientific progress can coexist with sustainable practices. Through this approach, students gain valuable knowledge and skills that they can apply in their future scientific endeavors, contributing to a more sustainable and eco-friendly society.

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Answer:

it's because the liquid in the bottle is supercooled

The major organic product obtained from the reaction of 1-butene with HCl is CH3CH2CH2Cl.

The reaction is an example of a substitution reaction, where a hydrogen atom of the alkene is replaced by a chlorine atom. This is known as an "E2" reaction (Elimination - bimolecular).
The reaction proceeds with a "Backside Attack" by the chlorine atom. This attack is facilitated by the electron-withdrawing effect of the chloride ion, which polarizes the double bond and allows the chlorine atom to attack the less substituted carbon atom.

Attack from the Backside: During a backside attack, the nucleophile targets the electrophilic centre on the side that is opposite the departing group. The product's stereochemistry changes when a backside assault takes place. There is configuration inversion.

The result is the formation of a secondary halide, CH3CH2CH2Cl.

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Answer:

When sodium hydroxide (NaOH) dissolves in water, it separates into positively - charged sodium ions (cations) and negatively - charged hydroxide ions (anions).

Hope this helped.

The value of the parameter k in the equation for Fick's Law is:

Fick's Law is given by the equation:

J = -D * A * (∆n / ∆x)

where:

J is the flux or rate of diffusion,

D is the diffusion coefficient,

A is the surface area of the membrane,

∆n is the change in concentration,

∆x is the thickness of the membrane.

In this case, we need to find the value of the parameter k in the equation for Fick's Law.

The value of k is related to the diffusion coefficient (D) by the equation:

k = D / (∆n / ∆x)

We are given the following information:

Membrane thickness (∆x) = 5 × 10^(-8) m

Surface area (A) = 4 × 10^(-8) m

Initial concentration inside the cell (n(0)) = 1.4 M

Concentration after observation (n(0.8)) = 0.91 M

Concentration outside the cell (n(outside)) = 0.9 M

To find the change in concentration (∆n), we can subtract the concentration after observation from the initial concentration:

∆n = n(0.8) - n(0)

∆n = 0.91 M - 1.4 M

∆n = -0.49 M

Substituting the given values into the equation for k, we have:

k = D / (∆n / ∆x)

k = D / (-0.49 M / 5 × 10⁻⁸ m

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Answer:

Pure crystals of the substance of interest are recovered using crystalization

It can be used to obtain substances that decompose on heating.

Explanation:

Crystalization is the process of converting a liquid solution to a crystalline solid. It is a common method of extracting the solid product of a reaction from solution. It can also be a separation method especially for obtaining pure crystals from a solution.

Crystalization does not require heating. Common methods of inducing crystalization include; addition of crystals of the same substance as seeds or scratching the vessel containing the solution.

The advantage of crystalization over evaporation is that it can be used to recover substance that decompose on heating. Also crystalization yields pure crystals of the substance of interest compared to evaporation in which soluble impurities may not be completely removed.

The reaction transformation of converting a ketone to an alcohol is classified as a reduction reaction.

The conversion of a ketone to an alcohol involves the addition of hydrogen (H₂) or a reducing agent to the ketone molecule, resulting in the reduction of the carbonyl group (C=O) to a hydroxyl group (C-OH). This process is known as a reduction reaction.

In a reduction reaction, the ketone molecule gains electrons and undergoes a decrease in oxidation state. The reducing agent donates electrons to the ketone, leading to the formation of a new C-O bond and the conversion of the carbonyl carbon into a secondary alcohol.

The reduction of a ketone to an alcohol can be achieved through various methods, such as catalytic hydrogenation using a metal catalyst (e.g., hydrogen gas over a platinum or palladium catalyst) or using reducing agents like sodium borohydride (NaBH₄) or lithium aluminum hydride (LiAlH₄). These reagents provide a source of electrons for the reduction process, resulting in the formation of the desired alcohol product.

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Answer: it transfers out of the metal the heat stops and the energy is absorbed by other things

Explanation:

the bond order for one carbon-carbon bond in the benzene molecule, taking σ and π bonding into consideration will be 1.5.

In the benzene molecule, there are 6 carbon atoms arranged in a hexagonal ring, with alternating single and double bonds. Each carbon atom is covalently bonded to two other carbon atoms, with one single bond and one double bond.

To calculate the bond order for one carbon-carbon bond in benzene, we need to take into account both the σ (sigma) and π (pi) bonding. The σ bond is formed by the overlap of two atomic orbitals along the internuclear axis, while the π bond is formed by the overlap of two atomic orbitals perpendicular to the internuclear axis.

In the case of benzene, each carbon-carbon bond has one σ bond and one π bond. The total bond order for each bond can be calculated as the sum of the bond orders for the σ and π bonds. The bond order for a σ bond is 1, while the bond order for a π bond is 0.5.

Therefore, the bond order for one carbon-carbon bond in the benzene molecule is:

Bond order = (σ bond order) + (π bond order) = 1 + 0.5 = 1.5

So the bond order for one carbon-carbon bond in the benzene molecule is 1.5.

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Answer:

\(m_{undissolved}=27g\)

Explanation:

Hello,

In this case, we first define the solubility as the maximum amount of a solute that is completely dissolved in an specific amount of solvent and it is temperature-dependent. Thus for potassium iodide, its solubility at 30°C is 153 g per 100 cm3 of water, therefore, with the given amount, the undissolved amount results:

\(m_{undissolved}=180g-153g=27g\)

Best regards.