is it acute, obtuse, or right?

Answer:

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Step-by-step explanation:

hope found the answer

The boiling point of water can be affected by several factors, including pressure. The boiling point of water decreases with decreasing pressure. In this case, the pressure is given as 0.04 bar. At this pressure, water boils at a lower temperature than it would at atmospheric pressure, which is 1 bar.

The correct answer to this question is b. 35.6 C. This is because at a pressure of 0.04 bar, water boils at 35.6 C, which is lower than the standard boiling point of water at atmospheric pressure, which is 100 C.The boiling point of water decreases by about 1 C for every 28.5 millibars (0.0285 bar) of pressure reduction.

So, at a pressure of 0.04 bar, the boiling point of water is about 64 C lower than it would be at atmospheric pressure. Therefore, water boils at 35.6 C at a pressure of 0.04 bar.

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Answer:

21

Step-by-step explanation:

If 13/15 was building then that means 2/15 was land( 1-13/15 = 2/15)

Multiply the total cost by 2/15

600 million x 2/15 = 80 million

the land cost 80 million

The range of f is {3, 5, 7}. Mr. A purchases 1 unit of X and sells 3 units of commodity Y.

Range of f:

To find the range of f, we need to determine the set of all possible values that f(x) can take for any x in A.

Given the function f(x) = 2|x| + 3, where A = {-2, 0, 1, 2}, we can substitute each value of x from A into the function to calculate the corresponding values of f(x):

For x = -2: f(-2) = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7

For x = 0: f(0) = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3

For x = 1: f(1) = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5

For x = 2: f(2) = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7

The calculated values are {7, 3, 5, 7}. Therefore, the range of f is the set of these values: {3, 5, 7}.

Commodity X and Y:

Mr. A purchases 1 unit of X and sells 3 units of an unspecified commodity Y.

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In the given image the triangle POR and triangle FGH are not equal or similar to each other.

What are triangles?

Triangles are a particular sort of polygon in geometry that have three sides and three vertices. Three straight sides make up the two-dimensional figure shown here. An example of a 3-sided polygon is a triangle. The total of a triangle's three angles equals 180 degrees. One plane completely encloses the triangle.

In ΔPQR, the line segment PQ measures 35 units.

In ΔPQR, the line segment PR measures 49 units.

In ΔPQR, the line segment QR measures 63 units.

In ΔFGH, the line segment FG measures 69 units.

In ΔFGH, the line segment GH measures 38 units.

In ΔFGH, the line segment HF measures 67 units.

These two triangles are not similar to each other.

Both these triangles have different measurements of line segments.

Both these triangles have no data available for their angles.

The only way the two triangles are similar is that they both are scalene triangles as they both have different measuring sides.

Therefore, the two triangles are not similar.

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The amount you could save per month would be 25% of your discretionary money.

Discretionary income is the money you have left over after paying taxes and necessary cost-of-living expenses.

The formula for discretionary money is: Discretionary money = Realized income - Fixed expenses. Inputting data, we have: Discretionary money = $3,543.22 - Fixed expenses

Amount to be saved = 25% of discretionary money

Amount to be saved = 0.25 * (Realized income - Fixed expenses)

Therefore, the amount savable is calculated as 0.25 times the difference between your realized income and fixed expenses.

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The formula for the general nth term of the sequence is αₙ= -3-n.

The given sequence -4,-5,-6,-7,-8,··········· is an arithmetic sequence as all the terms differ by a number -1.

The nth term αₙ of any arithmetic sequence is given by αₙ= α+(n-1) d where α is the first term, d is a common difference and n is the number of terms.

Here, α= -4

         d=α₂-α₁

           = -5+4

           = -1

  ⇒αₙ= -4+(n-1)(-1)

  ⇒αₙ = -4-n+1

  ⇒αₙ  = -3-n

The correct answer is -3-n.

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If speed is important and the array is large, the a. Binary search algorithm should be used. This algorithm is designed to efficiently search through sorted arrays by repeatedly dividing the search interval in half.

It has a time complexity of O(log n), which means that as the size of the array increases, the time it takes to search for an item will not increase at the same rate.
On the other hand, ascending bubble sort and other sorting algorithms such as selection sort and insertion sort have a time complexity of O(n^2), which means that as the size of the array increases, the time it takes to sort the array will increase exponentially. Therefore, these algorithms are not efficient for large arrays and should not be used if speed is important.
In summary, when dealing with large arrays and speed is important, binary search is the best algorithm to use for searching, while ascending bubble sort and other sorting algorithms with a time complexity of O(n^2) should be avoided.

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Answer:

2

Step-by-step explanation:

Hey there!

Well the x intercept is the point the line touches the x-axis.

And to find it we need to graph the given equation.

7x - 2y = 14​

Look at the image below ↓

By looking at the given image we can tell that the x-intercept is 2.

Hope this helps :)

y = -1/3x + 1

y = -2x - 3

We can compare the equations to the graphs and see which graph represents the intersection point of the two equations.

The first equation, y = -1/3x + 1, has a negative slope (-1/3) and a y-intercept of 1.

The second equation, y = -2x - 3, also has a negative slope (-2) and a y-intercept of -3.

Based on the slopes and y-intercepts, we can identify the correct graph by finding the point where the two lines intersect.

Unfortunately, since the graphs are not provided, I am unable to determine which specific graph shows the solution to the system of linear equations. I recommend referring to the graph representation of the equations and identifying the intersection point to determine the correct graph.

By using the method subtraction, Jackson's height is 1.25m.

To subtract in mathematics is to take something away from a group or a number of objects. The group's total number of items decreases or becomes lower when we subtract from it. The components of a subtraction issue are the minuend, subtrahend, and difference. An arithmetic operation called subtraction simulates the process of deleting items from a collection. The action of subtracting a matrix, vector, or other quantity from another according to predetermined rules in order to find the difference.

Given that,

Grace's height is 1.45 m.

Jackson is 0.2 m shorter than Grace.

Jackson's height is 1.45 -0.2 = 1.25

Therefore, Jackson's height is 1.25m.

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The z score for the actor is -2.04, and the z score for the actress is 1.69. The actor had the more extreme age as their z score was further away from the mean compared to the actress.

z score for actor

z = (32 - 43.7) / 8.8 = -2.04

z score for actress

z = (53 - 34.5) / 11.2 = 1.69

Since the z score for the actor is more negative than the z score for the actress, the actor had the more extreme age.

The z score is a measure of how far a specific value is away from the mean, in terms of standard deviations. A negative z score indicates that the value is below the mean, while a positive z score indicates that the value is above the mean.

In this case, both the actor and the actress had ages that were below the mean for their respective genders. However, the actor's age was further below the mean than the actress's age. Therefore, the actor had the more extreme age.

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Answer:

Step-by-step explanation:

d im pretty sure

Answer: All real number less than or equal to -3

Step-by-step explanation:

on the graph it shows and reflected abs val with the hight point at -3, therefore any other number will either equal -3 or be less than -3

The three (3) possible combinations are

Alex should 20 hats and 20 scarves

Let the number of scarves be x and y be the number of hats

He can make at most 20 hats and 30 scarves, but no more than 40 items altogether

x ≤ 20

y ≤ 30

x + y ≤ 40 (in time of market)

x + y ≥ 25

The possible combinations are

He should choose the third option x = 20, y = 20 this allows him to take more products to the show

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Hence proved ,the series for j 0(x) converges for all x .

A series in mathematics is the process of adding an unbounded number of quantities, after the one  other, to a specified initial amount. A significant component of calculus and its generalization, mathematical analysis, is the study of series.

Then we call that the series has converged and  in that case we define the total of the series as the limit of the partial sums,When the sequence of partial sums in a series are converges.

J 0(x) is called the Bessel function of the first kind of order zero,

we know that , \(J0(x) = 1 - (x^2)/2! + (x^4)/4! - (x^6)/6! + ...\)is called JO(x) series,

We use the ratio test to determine that this series converges for all values of x.

According to the ratio test, the series of the form \(\frac{a_(n+1)}{a_n}\) also converges if the series JO(x) converges. The series converges if it is less than 1.  and diverges if the limit of the ratio test is greater than 1,

Let a use the ratio test for the J0(x) series:

let a consider term  is  R=\(((a_(n+1))/a_n) = (x^2_(n+2)) / [(2n+2)(2n+1)] / (x^2n) / [(2n)(2n-1)] | = | x^2 / [(2n+2)(2n+1)] |\)

Considering the limit as n tends to infinity:

\(\lim_{n \to \infty} |a_(n+1) / a_n) |=\lim_{n \to \infty} | x^2 / [(2n+2)(2n+1)] = 0\)

For all values of x, the series converges  since the limit is less than 1.

therefore the J 0(x) series converges for all x.

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Maria must cut an additional $70 from her expenses each month in order to save enough money to buy a new TV that costs $420 in 6 months. By allocating this additional amount towards her savings goal, she will be able to reach her target within the desired timeframe. It's important for Maria to review her budget and identify areas where she can reduce expenses in order to make room for the additional savings. This could involve cutting back on discretionary spending, finding ways to save on daily expenses, or exploring opportunities to increase her income.

Maria must cut an additional $70 from her expenses each month.

To determine how much additional money Maria must cut from her expenses each month to afford a new TV that costs $420 in 6 months, we divide the total cost by the number of months.

Additional money per month = Total cost / Number of months

Additional money per month = $420 / 6

Additional money per month = $70

With careful planning and commitment to her budget, Maria can achieve her goal of purchasing a new TV without compromising her financial stability.

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Answer:

no, they are different in their different ways

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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The probability of one robot succeeding in a task less than or equal to 80 times out of 100 can be calculated using a binomial distribution formula. Assuming the probability of success for one robot is p, the probability of success for both robots is p^2. Using the binomial distribution formula, we can calculate the probability of success for each robot and then multiply them together to find the probability of both robots succeeding less than or equal to 80 times out of 100. The formula is P(X<=80) = sum of P(X=k) from k=0 to k=80, where X is the number of successes in 100 attempts.

To calculate the probability of both robots succeeding less than or equal to 80 times out of 100, we need to first find the probability of success for one robot. Let's assume the probability of success for one robot is p = 0.7. The probability of success for both robots is then p^2 = 0.7^2 = 0.49.

Next, we need to use the binomial distribution formula to calculate the probability of success for each robot. The formula is P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where n is the number of attempts, k is the number of successes, and (n choose k) is the binomial coefficient.

Using this formula, we can calculate the probability of one robot succeeding less than or equal to 80 times out of 100. P(X<=80) = sum of P(X=k) from k=0 to k=80 = sum of [(100 choose k) * 0.7^k * 0.3^(100-k)] from k=0 to k=80.

We can use a calculator or a software program like Excel to calculate this sum. The result is 0.9899, which means the probability of one robot succeeding less than or equal to 80 times out of 100 is almost 99%.

To find the probability of both robots succeeding less than or equal to 80 times out of 100, we just need to multiply the probability of one robot succeeding by itself: 0.9899 * 0.9899 = 0.9799. So the probability of both robots succeeding less than or equal to 80 times out of 100 is about 98%.

The probability of both robots succeeding less than or equal to 80 times out of 100 can be calculated using the binomial distribution formula. Assuming the probability of success for one robot is p, the probability of success for both robots is p^2. Using the formula P(X<=80) = sum of P(X=k) from k=0 to k=80, we can calculate the probability of one robot succeeding less than or equal to 80 times out of 100. Multiplying this probability by itself gives us the probability of both robots succeeding less than or equal to 80 times out of 100. For the given values, the probability is about 98%.

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The difference in the values of the two cars when they are each 7 years old is equal to $6,000.

In order to determine the difference in the values of the two cars, we would have to write an equation that models the price of the cars after a length of time, by using the data points shown in the graph above.

Mathematically, the slope of any straight line can be calculated by using this formula;

Slope, m = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope, m = (y₂ - y₁)/(x₂ - x₁)

For Car A, we have:

Slope, m = (y₂ - y₁)/(x₂ - x₁)

Slope, m = (9 - 12)/(4 - 2)

Slope, m = -3/2

Slope, m = -1.5

At point (4, 9), a linear equation for car's value can be calculated by using the point-slope form:

y - y₁ = m(x - x₁)

Where:

Substituting the given points into the formula, we have;

y - y₁ = m(x - x₁)

y - 9 = -1.5(x - 4)

y = -1.5x + 15

In 7 seven years, the value of Car A is given by:

y = -1.5x + 15

y = -1.5(7) + 15

y = $4,500

Note: The negative sign indicates that the value of the car is depreciating.

For Car B, we have:

Slope, m = (y₂ - y₁)/(x₂ - x₁)

Slope, m = (10 - 18)/(5 - 1)

Slope, m = -8/4

Slope, m = -2

At point (5, 1), a linear equation for car's value can be calculated by using the point-slope form:

y - y₁ = m(x - x₁)

y - 1 = -2(x - 5)

y = -2x + 11

In 7 seven years, the value of Car B is given by:

y = -2x + 11

y = -2(7) + 3.5

y = $10,500

Now, we can determine the difference as follows:

Difference = $10,500 - $4,500

Difference = $6,000.

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Answer:

Step-by-step explanation:

a. sqrt(2x) = -x

b. (sqrt(2x))^2 = (-x)^2

2x = x^2

c. divide both sides by x. x = 2, 0

d. x = 2 does not satisfy the original equation, but x = 0 does.

The expression is,

So, according to BODMAS which stands for Bracket, Of, Division, Multiplication, Addition, and Subtraction, calculations are to be done in ths order.

So.

Door to door sampling is used when it is important to control where the sample is delivered and when the products are of a perishable nature.

The term sampling  selecting refers to the selection of a small proportion of the population extrapolating the results the results obtained from this small group to represent the characteristics of the entire population. This sample is chose in a manner as to reflect the properties the generality of the population.

Hence, door to door sampling is used when it is important to control where the sample is delivered and when the products are of a perishable nature.

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Answer: 56

Step-by-step explanation:because x=5+3 y=1+6 area of rectangle abcd=xy

8*7=56

The answer is (f) None of the above.

We can use the inclusion-exclusion principle to find the cardinality of the set A ∪ (B ∩ C). The formula is:

n(A ∪ (B ∩ C)) = n(A) + n(B) + n(C) - n(B ∪ C) - n(A ∩ B ∩ C)

We are given the values of n(A), n(B), n(C), n(A ∩ B), n(B ∩ C), and n(C ∩ A) from the Venn diagram. We can use these values to find n(B ∪ C) and n(A ∩ B ∩ C) as follows:

n(B ∪ C) = n(B) + n(C) - n(B ∩ C)

n(A ∩ B ∩ C) = n(A) + n(B) + n(C) - n(A ∪ B) - n(B ∪ C) - n(C ∪ A) + n(A ∩ B ∩ C)

Substituting the values from the Venn diagram, we get:

n(B ∪ C) = 50 + 28 - 16 = 62

n(A ∩ B ∩ C) = 18 + 16 + 28 - 50 - 62 - 20 + 10 = 0

Therefore,

n(A ∪ (B ∩ C)) = n(A) + n(B) + n(C) - n(B ∪ C) - n(A ∩ B ∩ C) = 32 + 50 + 20 - 62 - 0 = 40

So the answer is (f) None of the above.

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Answer:

quadrant 1 that the graph is mainly in

Answer:

x = 9

x = 1

Step-by-step explanation:

The correlation coefficient for the given data is 0.977. Approximately 95.52% of the variation in Y values is explained by variations in X values.

Using the formula for the correlation coefficient, we have:

r = (nΣXY - ΣXΣY) / sqrt[(nΣX² - (ΣX)²)(nΣY^2 - (ΣY)²)]

where n is the number of observations, ΣX and ΣY are the sums of the X and Y values, ΣXY is the sum of the products of corresponding X and Y values, and ΣX² and ΣY² are the sums of the squares of the X and Y values, respectively.

Plugging in the values from the data, we get:

n = 6

ΣX = 56

ΣY = 171

ΣXY = 834

ΣX² = 799

ΣY² = 3682

r = (6834 - 56171) / sqrt[(6799 - 56²)(63682 - 171²)]

r = 0.954 (rounded to 3 decimal places)

To determine how much of the variation in Y values is explained by variations in X values, we can square the correlation coefficient to get the coefficient of determination, which represents the proportion of the total variation in Y that can be explained by the linear relationship with X.

r² = 0.911 (rounded to 3 decimal places)

Therefore, about 91.1% of the variation in Y values is explained by variations in X values.

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Complete question:

Given are six observations taken for two variables:

X: 6, 9, 9, 9, 11, 12

Y: 17, 25, 27, 26, 37, 39

Compute the correlation coefficient for these data. Keep 3 decimals in your answer.

How much of the variation in Y values is explained by variations in X values? Keep 3 decimals in your answer