is an atom with one valence electron more reactive than an atom with two electrone? ​

By using uniform motion, the speed before hitting the ground is 23.00 m/s.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

t = 1.45 s

y = 27 m

g = 9.8 m/s²

By using the second equation, we can calculate the speed before hit the ground.

vt² = vo² + 2a . s

vt² = 0² + 2g . 27

vt² = 2 . 9.8 . 27

vt² = 529.2

vt = 23.00 m/s

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The method by which machines increase range of motion and speed of movement so that resistance can be moved farther or more quickly than an applied force is not described in the following.

The earth pulls your body downward, which is known as gravity. The location where your body's mass is concentrated is known as your center of gravity. A hypothetical location where the force of gravity seems to act is the center of gravity (COG) of an organism.

No relative motion exists between the two contact surfaces in a rolling motion. Therefore, in a rolling motion, the friction does not do any work. Because of this, rolling friction is lower than sliding or kinetic friction.

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Answer:

Democritus and Dalton has similar ideas about the atom, but Democritus based his theory more on reason than science. ... His ideas were similar to those of Democrites in that he believed that atoms were indivisible and that atoms of one substance are all alike but are different from atoms of another substance.

Explanation:

PLS MAKE ME AS BRAINLIST

Answer:

Democritus and Dalton has similar ideas about the atom, but Democritus based his theory more on reason than science. ... His ideas were similar to those of Democrites in that he believed that atoms were indivisible and that atoms of one substance are all alike but are different from atoms of another substance.

Explanation:

The instantaneous velocity at t=2 is 21 units per second.

To find the instantaneous velocity, we need to take the derivative of the position function with respect to time.

Given s(t) = 2t^2 + 5t + 5, taking the derivative with respect to t, we get:

v(t) = d(s(t))/dt = d(2t^2 + 5t + 5)/dt

v(t) = 4t + 5

To find the instantaneous velocity at t=2, substitute t=2 into the velocity function:

v(2) = 4(2) + 5 = 8 + 5 = 13 units per second

Therefore, the instantaneous velocity at t=2 is 13 units per second.

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Answer:

THANK YOUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU

Explanation:

I REALLY NEED THIS

Answer:

Oh my gosh yayyy one of the asnwers got deleted!!!! Yay thx for the points

Explanation:

Explanation:

t = usin©/g

Where t is the time to reach the maximum height

Time spent in air is T = 2t

Hence, T = 2usin©/g

T = 2 x 20 x sin 65°/ 9.8

T = 3.69s

The type of system that utilizes sensors to detect tire slippage during acceleration is the Traction Control system.

The Traction Control system (TCS) with help of these wheel speed sensors to measures the vehicle's speed along with the rate of speed at which the drive wheels are rotating, to detect and analyze if there is any slip taking place in between the tire and the road.

This system places piggybacks on the antilock brake system (ABS) to detect and capture tire slip during acceleration and maintain the movement traction while accelerating.

Furthermore, the advantages of the Traction Control system are

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The direction of the induced current in the wire loop is anti-clockwise.

The direction of the induced current if the wire loop was on the left side of the wire is clockwise.

Lenz's law and the direction of the induced current are the key concepts needed to address this issue.

To determine the direction of the induced current under various circumstances, use Lenz's law.

The induced emf of the coil is proportional to the negative of the rate of change of magnetic flux, according to Faraday's law.

The following expression represents the typical emf that is generated in the coil during the course of the time period: \($$\varepsilon=-\frac{\Delta \Phi}{\Delta t}$$\)

Here, \($\varepsilon$\) is the average emf that is induced in the coil during the time interval and \($\Delta \Phi / \Delta t$\) is the rate of change of magnetic flux.

A magnetic field is induced in the rectangular loop as a result of the current in the wire. The plane is the intended target of this magnetic field.

As the current in the wire grows, the magnetic flux in the rectangular coil rises.

An emf and current are induced by Faraday's law.

Following is noted from Lenz's law:

The inwards growing flux is opposed by the generated current. Therefore, the induced current must flow counterclockwise in order to meet this.

When the rectangular loop is kept to the left of the wire, the magnetic flux will be directed outward.

If the wire loop was on the left side of the wire, the induced current would flow clockwise.

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Answer:

D. 72.9 cm/s towards the wall

The statement that pressure refers to the ratio of force to the area over which the force is applied is True.

Pressure is defined as the amount of force exerted per unit area, and is expressed in units such as pounds per square inch (psi) or pascals (Pa). This means that the greater the force applied over a smaller area, the higher the pressure will be.

For example, if you press down on a table with your hand, the pressure you exert will be lower than if you press down with the same force using just the tip of your finger, because the force is distributed over a larger area in the first case. Understanding pressure is important in fields such as physics, engineering, and medicine.

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The space shuttle travels approximately 0.00794 football fields in one blink of an astronaut's eye.

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The minimum thickness of the GRIN lens to focus a parallel beam is approximately 6.25 μm.

How can we determine the minimum thickness of a GRIN lens to achieve focus for a parallel beam?

The minimum thickness of a GRIN lens can be determined using the formula:

\[ d_{\text{min}} = \frac{\pi \cdot a^2}{\lambda \cdot \Delta} \]

where \( d_{\text{min}} \) is the minimum thickness, \( a \) is the aperture radius, \( \lambda \) is the wavelength of the incident light, and \( \Delta \) is the index difference of the GRIN material.

Given \( \Delta = 0.01 \), \( n_1 = 1.5 \), and \( a = 20 \) μm, we need to find \( \lambda \).

Using the formula \( n = \frac{c}{v} \), where \( c \) is the speed of light and \( v \) is the velocity of light in the medium, we can find \( \lambda \) using the relation \( \lambda = \frac{c}{f} \), where \( f \) is the frequency of light.

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The exact temperature at which the average speed of helium atoms equals the escape speed from the Earth is approximately 1.052 x \(10^6\) Kelvin.

To determine the temperature at which the average speed of helium atoms equals the escape speed from the Earth, we can use the kinetic theory of gases and the equation for average kinetic energy.

The average kinetic energy of gas particles is given by the equation:

\(KE_a_v_g\) =\((3/2) \times k \times T\)

where \(KE_a_v_g\) is the average kinetic energy, k is the Boltzmann constant (1.38 × \(10^-^2^3\) J/K), and T is the temperature in Kelvin.

The escape speed from the Earth is the minimum speed required for an object to escape the gravitational pull of the Earth, which is approximately 1.12 × \(10^4\) m/s.

To find the temperature at which the average speed of helium atoms equals the escape speed, we can equate the average kinetic energy to the kinetic energy corresponding to the escape speed:

\((1/2) \times m \times v^2 = (3/2) \times k \times T\)

Here, m is the mass of a helium atom, and v is the escape speed.

Simplifying the equation, we find:

\(v^2 = (3 \times k \times T) / m\)

Solving for T:

\(T = (m \times v^2) / (3 \times k)\)

Substituting the mass of a helium atom (m = 6.64 x \(10^-^2^7\) kg) and the escape speed (v = 1.12 × \(10^4\) m/s) into the equation, we can calculate the temperature T.

T = (6.64 x \(10^-^2^7\) kg \(\times\)(1.12 × \(10^4\) m/s)^2) / (3 \(\times\)1.38 × \(10^-^2^3\) J/K)

Calculating this expression gives:

T = 1.052 x \(10^6\) K

Therefore, the exact temperature at which the average speed of helium atoms equals the escape speed from the Earth is approximately 1.052 x \(10^6\) Kelvin.

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To determine the reject rate (RR) for each scenario, we need to consider the capability indices Cp and Cpk along with the specifications for tensile strength. The reject rate represents the proportion of parts that do not meet the specifications.

1. RR = 0.27%

2. RR = 16.03%

3. RR = 0%

4. RR = 0.003%

5. RR = 0.27%

6. RR = 2.28%

7. RR = 29.93%

8. RR = 0%

9. RR = 5.87%

Please note that these calculations assume a normal distribution of tensile strength and that the process is in statistical control. The reject rate is obtained by evaluating the proportion of values falling outside the specified limits based on the process capability indices Cp and Cpk.

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Answer:

KE=800,000

Explanation:

The formula for kinetic energy is KE=1/2mv^2 or Kinetic Energy= 0.5*mass*velocity^2

so 1000 is the mass and 40 is the velocity

KE=0.5*1000*40^2

KE=0.5*1,000*1,600

KE=800,000 Joules

Answer:

Its either B or A

Explanation:

Answer:

I think its dense and solid and located near a star.

Explanation:

Hope this helps, good luck.

Answer:

The heating element of the heater is made up of alloy which has very high resistance so when current flows through the heating element, it becomes too hot and glows red. But the resistance of cord which is usually of copper or aluminum is very low so it does not glow.

Answer:they are in group 17 and called halogens

Explanation:

It's probably B or A

Answer:

B: its gas burns up

Explanation:

Because when it close to the sun it burns it gas of how hot the sun is.

The magnitude of electrical force on charge \(q_{3}\) due to the others is 0.102 newtons.

The vector position of each particle respect to origin are described below:

\(\vec r_{1} = (-0.500, 0)\,[m]\)

\(\vec r_{2} = (+0.500, 0)\,[m]\)

\(\vec r_{3} = (0, +0.500)\,[m]\)

Then, distances of the former two particles particles respect to the latter one are found now:

\(\vec r_{13} = (+0.500, +0.500)\,[m]\)

\(r_{13} = \sqrt{\vec r_{13}\,\bullet\,\vec r_{13}} = \sqrt{(0.500\,m)^{2}+(0.500\,m)^{2}}\)

\(r_{13} =\frac{\sqrt{2}}{2}\,m\)

\(\vec r_{23} = (-0.500, +0.500)\,[m]\)

\(r_{23} = \sqrt{\vec r_{23}\,\bullet \,\vec r_{23}} = \sqrt{(-0.500\,m)^{2}+(0.500\,m)^{2}}\)

\(r_{23} =\frac{\sqrt{2}}{2}\,m\)

The resultant force is found by Coulomb's law and principle of superposition:

\(\vec R = \vec F_{13}+\vec F_{23}\) (1)

Please notice that particles with charges of same sign attract each other and particles with charges of opposite sign repeal each other.

\(\vec R = \frac{k\cdot q_{1}\cdot q_{3}}{r_{13}^{2}}\cdot \vec u_{13} +\frac{k\cdot q_{2}\cdot q_{3}}{r_{23}^{2}}\cdot \vec u_{23}\) (2)

Where:

If we know that \(k = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}\), \(q_{1} = 2\times 10^{-6}\,C\), \(q_{2} = 2\times 10^{-6}\,C\), \(q_{3} = 2\times 10^{-6}\,C\), \(r_{13} =\frac{\sqrt{2}}{2}\,m\), \(r_{23} =\frac{\sqrt{2}}{2}\,m\), \(\vec u_{13} = \left(-\frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2} \right)\) and \(\vec u_{23} = \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\), then the vector force on charge \(q_{3}\) is:

\(\vec R = \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + \frac{\left(8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot (2\times 10^{-6}\,C)\cdot (2\times 10^{-6}\,C)}{\left(\frac{\sqrt{2}}{2}\,m \right)^{2}} \cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\)

\(\vec R = 0.072\cdot \left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right) + 0.072\cdot \left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2} \right)\,[N]\)

\(\vec R = 0.072\cdot \left(0, -\sqrt{2}\right)\,[N]\)

And the magnitude of the electrical force on charge \(q_{3}\) (\(R\)), in newtons, due to the others is found by Pythagorean theorem:

\(R = 0.102\,N\)

The magnitude of electrical force on charge \(q_{3}\) due to the others is 0.102 newtons. \(\blacksquare\)

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Explanation:

Assuming the 10 m distance is the vertical displacement, the work done by both people is the same.

Work = force × distance

W = (250 N) (10 m)

W = 2500 J

The power of the first person is:

Power = work / time

P = 2500 J / 120 s

P = 20.83 W

The power of the second person is:

P = 2500 J / 60 s

P = 41.67 W

Answer:

Alpha decay forms new element with two fewer protons and two fewer neutrons, Beta decay forms new element with one more proton and one fewer neutron. Gamma decay forms NO new element, but now the element has less energy because energy is released as gamma rays.

Explanation:

ANSWER AND EXPLAINATION:
Gamma decay differs from alpha and beta decay in several ways:

1. Particle emitted: In gamma decay, no particles are emitted. Instead, a high-energy photon called a gamma ray is released. Alpha decay involves the emission of an alpha particle, which consists of two protons and two neutrons. Beta decay involves the emission of either a beta-minus particle (an electron) or a beta-plus particle (a positron).

2. Mass and charge: Gamma decay does not change the mass or atomic number of the nucleus since no particles are emitted. Alpha decay reduces the atomic number by 2 and the mass number by 4, as an alpha particle is emitted. Beta decay changes the atomic number, with beta-minus decay increasing it by 1 and beta-plus decay decreasing it by 1. The mass number remains the same in beta decay.

3. Penetrating power: Gamma rays have the highest penetrating power among the three types of decay. They can pass through most materials and require dense shielding (e.g., lead or concrete) to attenuate them. Alpha particles have low penetrating power and can be stopped by a sheet of paper or a few centimeters of air. Beta particles have intermediate penetrating power and can be stopped by a few millimeters of aluminum.

4. Energy release: Gamma decay releases energy in the form of high-energy photons. Alpha decay releases a significant amount of energy since an alpha particle carries substantial kinetic energy. Beta decay releases energy in the form of the kinetic energy of the emitted beta particle.

gamma decay is a process that involves the emission of high-energy photons, while alpha and beta decay involve the emission of particles with mass and charge. Gamma rays have higher penetrating power and do not cause changes in the mass or atomic number of the nucleus, distinguishing them from alpha and beta particles.

The strength of the magnetic field at the center of the solenoid is 0.006 T

The strength of the magnetic field at the center of a solenoid is given by:

B = μ₀ * n * I

where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.

In this case, the length of the solenoid is not given, but we can assume that it is much greater than the diameter of the solenoid, so we can treat it as a long solenoid. The number of turns per unit length is given as 200 loops divided by the length of 6.5 cm, or:

n = 200 / 0.065 m = 3076.92 turns/m

The current flowing through the solenoid is 5 A.

The permeability of free space, μ₀, is a constant with a value of 4π x 10^-7 T m/A.

Therefore, the magnetic field strength at the center of the solenoid is:

B = μ₀ * n * I

= 4π x 10^-7 T m/A * 3076.92 turns/m * 5 A

= 0.006 T

So the strength of the magnetic field at the center of the solenoid is 0.006 T. The north pole of the solenoid is the end from which the magnetic field emerges, and the south pole is the end where it enters.

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The distance traveled by the object from t=0 to the first time that it stops is 2/3. So, option C. is correct.

To find the distance traveled by the object from t=0 to the first time it stops, we first need to determine when the object stops. The object stops when its velocity v(t) is equal to 0:

v(t) = 2cos(3t) = 0

This occurs when cos(3t) = 0.

The first positive value for t that satisfies this equation is when 3t = π/2, which gives us t = π/6.

Now, we need to find the distance traveled. Since we know the velocity function v(t), we can find the position function s(t) by integrating v(t):
s(t) = ∫v(t)dt = ∫2cos(3t)dt

Integrating the function gives:
s(t) = (2/3)sin(3t) + C

As the initial condition is s(0) = 0, we find C = 0.

So, the position function is:
s(t) = (2/3)sin(3t)

Now, we can find the distance traveled by the object from t=0 to t=π/6:

Distance = s(π/6) - s(0)

= (2/3)sin(3(π/6)) - (2/3)sin(0)

= (2/3)sin(π/2) - 0

= (2/3)(1)

= 2/3

So, the correct answer is C option.

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answer

200

Explanation:

5000-5200=200

Machine weights are safer when used correctly, but free weights can be dropped and cause injury. These are safety considerations to keep in mind whether using free weights or machine weights. But because they aren't big, complicated machinery, free weights are less expensive.

Resistance machines and free weights are very different from one another in terms of how they work and the results they can create.

Machines are set in place and can only move in a few directions, whereas free weights can be moved in whatever direction the user selects. This is the main distinction between machines and free weights. Free weights require you to utilize more stabilizing muscles to control them, whereas resistance machines help you by stabilizing you while you move.

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If the following forces act on an object: 20 N North, 50 N South, and 40 N west, then the magnitude of the net force would be 50 Newtons.

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

As given in the problem if the following forces act on an object: 20 N North, 50 N South, and 40 N west.

The net force = √ ( 30² + 40² )

                      = 50 Newtons

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Answer:

The one on the left

Explanation:

Answer:

The one on the left

Explanation: