Is amalee wearing purple?

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Answer:

4sec

Explanation:

Since we know the initial velocity=0, acceleration = -4; and the displacemnt =14, we use the equation d = vi • t + ½ • a • t2. So, just plug in the values and solve for t in this case it's 4 sec

A body is said to be in freefall when it moves solely under the influence of  gravity.

The time it took for the ball to crash at the surface = 3 sec.

acceleration of gravity on the moon is 4 m/s^2.

the height of 14 m.

The formula for free fall:

\(h= \frac{1}{2}gt^2\)

t^2 = 2h /g = 2 x 14 /4 = 7

t = \(\sqrt{7} = 2.65\) sec ≅ 3 sec.

The time it took for the ball to crash at the surface = 3 sec.

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Answer:

It would take 3 seconds approximately.

Explanation:

since it's going to stop it's final velocity is 0m/s

Now,

acceleration = (v-u)/t

or, a = (0-35)/t

or, -12 = -35/t

or, t = -35/-12

so, t = 2.9 seconds.

Answer: Neptune

Explanation:

Explanation:

neptune is correct

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Answer:

ोोञककतकषगकषषमषघ

Explanation:

zzjjjfkgkzgkggkkkammmmmmatAllzy##pglCsg

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²

according to kinematics,

s = ut + 1/2 at²

s =  1/2 ×9.8×3.4²

s = 56.6 m

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Answer:

First get the time in the air from

h = gt2/2 ⇒

t = √(2h/g)

Plug in

h = 100 m

g = 9.8 m/s2

and get t in seconds. Then multiply t by the constant horizontal speed.

x = vt

Plug in

v = 40 m/s

t = ? (result from above)

and get x in meters.

(b)

Vertical speed:

v(t) = v0 + gt

Plug in

v0 = 0

g and t from above

and get v(t) in m/s.

(c) It is the same as the initial velocity when released, which is 40 m/s.

(d) The horizontal component is the same as the answer for part (c). The vertical component is the result for part (b), in the downward direction.

a ) The final direction of ball A is along x-axis in positive direction.

b ) The speed of ball A is 5.1 m / s and that of ball B is 1.6 m / s

In an elastic collision between two objects of same mass, the balls would move at right angles with each other. So, it is given that, the final direction of ball B is along positive Y-axis. So the final direction of ball A must be perpendicular to that direction which is positive x-axis.

The initial velocity of ball A = 1.6 m / s

The initial velocity of ball B = 5.1 m / s

In an elastic collision between two objects of same mass, the balls would  exchange velocities.

Final velocity of ball A = 5.1 m / s

Final velocity of ball B = 1.6 m / s

Therefore,

a ) The final direction of ball A is along x-axis in positive direction.

b ) The speed of ball A is 5.1 m / s and that of ball B is 1.6 m / s

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Given data:

* The mass of the cannon is 52.07 kg.

* The recoil velocity of the cannon is 7.75 m/s.

* The mass of the cannon ball is 9.06 kg.

Solution:

By the law of conservation of the momentum,

The momentum of the cannon ball before the collision is the same as the momentum of the cannon ball from the cannon.

The momentum of the cannon ball from the cannon is,

where m is the mass of the cannon and v is the recoil velocity of the cannon,

Substituting the known values,

Thus, the momentum of the cannon ball before the collision is 403.54 kgm/s.

Answer:

required vertical distance below the edge is 0.6648 m

Explanation:

Given the data in the question;

Horizontal speed of water falls v = 2.73 m/s

direction of water falls 52.9° below the horizontal

The vertical velocity must be such that;

tanθ = v\(_y\) / v\(_x\)

Now, vertical speed of water falls;

v\(_y\) = v\(_x\) × tanθ

we substitute

v\(_y\) = 2.73 × tan(52.9°)

v\(_y\) = 2.73 × 1.322237

v\(_y\) = 3.6097

Now, at the top of falls, initial speed u = 0

v² - u² = 2as

s = ( v² - u² ) / 2as

we substitute

s = ( 0² - (3.6097)² ) / (2 × 9.8)

s = 13.029934 / 19.6

s = 0.6648 m

Therefore, required vertical distance below the edge is 0.6648 m

Answer: See the diagram,from the vevtor addition we can say,net force acting on the apple is =

√

2.25

2

+

1.05

2

+

2

⋅

2.25

⋅

1.05

cos

90

=

2.48

N

And,this resultant force makes an angle of

tan

−

1

(

1.05

2.25

)

or,

25

degrees w.r.t vertical

Answer:

66 km

Explanation:

Given that:

The speed of the two trains = 33 km/h

The speed of the bird = 60 km/h

The distance apart between the two trains =  60 km

From the given information, we are being told that the two trains are going at the same speed. Therefore, they will definitely collide at 30 km

We know that:

speed  of the train = distance traveled × time

Making the time t the subject of the formula:

time = speed of the train / distance traveled

time = 30 km / 33 km/h

time = 0.909 / hr

Thus, the bird flying at a given speed of 60 km/h in a time of 0.909 / hr will cover a total distance of :

distance (d) = speed of the bird/ time

distance (d) = \(\dfrac{60 \ km/hr}{0.909 \ /hr}\)

distance (d) = 66 km

The magnitude of the masses in planes B and E is 40 kg, and their positions are 120° and 240°, respectively, from the reference point on the shaft to achieve complete rotating balance.

To achieve complete rotating balance, the sum of the moments of the masses in planes A, C, D, B, and E should be equal to zero. Let's determine the magnitude of the masses in planes B and E and their positions.

Consider the moments of the masses in planes A, C, and D. The moment of a mass is given by the product of its magnitude and the sine of the angle between the mass and a reference line. The moments of masses A, C, and D are:

Moment of A = 50 kg * sin(0°) = 0 kg·m,

Moment of C = 40 kg * sin(90°) = 40 kg·m,

Moment of D = 80 kg * sin(135°) = -80 kg·m.

Since the moments of A, C, and D are known, we can use the principle of complete rotating balance to determine the magnitude and position of the masses in planes B and E.

Let's assume the magnitude of the masses in planes B and E as M. The moments of masses B and E can be represented as:

Moment of B = M * sin(120°) = M * √(3)/2,

Moment of E = M * sin(240°) = -M * √(3)/2.

Using the principle of complete rotating balance, the sum of the moments should be zero. Thus, we have:

Moment of A + Moment of C + Moment of D + Moment of B + Moment of E = 0.

0 + 40 kg·m + (-80 kg·m) + M * √(3)/2 + (-M * √(3)/2) = 0.

Simplifying the equation:

40 kg·m - 80 kg·m + M * √(3)/2 - M * √(3)/2 = 0,

-40 kg·m = 0.

From the equation, we can deduce that M must be equal to 40 kg to satisfy the condition of complete rotating balance.

Finally, we determine the positions of masses B and E. Since planes A, C, D, B, and E are equidistant from one another, and the angle between A and C is 90°, we divide the circle into 360°/5 = 72° sections. Thus, the positions of masses B and E are:

Position of B = 0° + 2 * 72° = 144°,

Position of E = 0° + 4 * 72° = 288°.

Therefore, the magnitude of the masses in planes B and E is 40 kg, and their positions to put the shaft in complete rotating balance are 144° and 288°, respectively, from the reference point on the shaft.

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Here, we are given a velocity-time graph which shows how the main voltage varies in Barbados.

Let's solve for the following:

• (a) What is the peak voltage.

Peak voltage can be said to be the highest point of voltage.

From the given graph, the peak voltage is 160 volts.

• (b) What is the frequency.

To find the frequency, apply the formula:

Where:

T is the time taken to complete one full revolution.

Here, T = 0.02 seconds

Hence, we have:

The frequency is 50 Hz.

• (c) Amy buys a laptop charger in Barbados. On the back it says rated for for Barbados 115Volts. Explain whether there has been a mistake.

In appliances, the RMS voltage is always written on the back.

To find the RMS volatge using the graph, we have:

Where Vo is the peak voltage = 160 v.

Hence, we have:

In this case, the rated voltage on the back of the charger is 115 volts where the RMS voltage is 113.14 volts. Therefore, we can say there is a mistake.

The speed of the artillery shell when it hits its target is 100 m/s.

Given:

Initial vertical displacement (y) = 200 m

Vertical displacement at 100 m in the air (y') = 100 m

Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)

Using the equation for vertical displacement in projectile motion:

y' = vy^2 / (2g),

where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).

100 m = vy^2 / (2 * 9.8 m/s^2),

vy^2 = 100 m * 2 * 9.8 m/s^2,

vy^2 = 1960 m^2/s^2,

vy = sqrt(1960) m/s,

vy ≈ 44.27 m/s.

Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.

Hence, the speed of the artillery shell when it hits its target is 100 m/s.

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Answer:

If you take out air they'll fall at the same time

Explanation:

for example a closed umbrella will fall faster than an open one because the air is holding the opened umbrella back

Answer: 1 Newton

Explanation:

"Every action has an equal and opposite reaction."

Please mark as Brainliest if it is correct.

Force is an action-reaction principle. It stated that the force always exists in a pair. The reaction force of the wall on the swimmer will be 1N.

Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.

Both occur in an action-reaction form. Hence for every action, there is an equal and opposite reaction.

\(\rm F_{action}=F_{reaction} \\\\ \rm F_{action= 1N\)

\(\rm F_{reaction} = 1N\)

Hence the reaction force of the wall on the swimmer will be 1N.

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Answer:

T1 = 417.48N

T2 = 361.54N

T3 = 208.74N

Explanation:

Using the sin rule to fine the tension in the strings;

Given

amass = 42.6kg

Weight = 42.6 * 9.8 = 417.48N

The third angle will be 180-(60+30)= 90 degrees

Using the sine rule

W/Sin 90 = T3/sin 30 = T2/sin 60

Get T3;

W/Sin 90 = T3/sin 30

417.48/1 = T3/sin30

T3 = 417.48sin30

T3 = 417.48(0.5)

T3 = 208.74N

Also;

W/sin90 = T2/sin 60

417.48/1 = T2/sin60

T2 = 417.48sin60

T2 = 417.48(0.8660)

T2 = 361.54N

The Tension T1 = Weight of the object = 417.48N

This question involves the concepts of thickness and length.

"40" gold atoms could stack on top of one another in the gold foil.

We will use the unitary method here to find out the no. of gold atoms that could stack on top of each other in the gold foil of thickness 1 x 10⁻⁷ m, when the side length of each cubic atom is 2.5 x 10⁻⁹ m.

Therefore,

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Claims that if temperature is kept constant, the end result of both volume and pressure is constant. The new level is 1036 Pa, which is how this can be expressed.

So either a strong force or a strong force applied over a short area can cause a lot of pressure. When we stand up compared to when we are walking, more of our feet are in proximity to the earth. Pressure would be lower if there was more surface area in contact.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. There are both living things and non-living objects in the concept of a force.

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Answer:

0.258 +- 0.0162

Explanation:

First change the uncertainty to percentage uncertainty :

%uncertainty =uncertainty /estimated value *100

0.1/51.6 * 100=0.19%

Do the same for the rest you will get:

0.1%, 1%, 5%

Then add the %uncertainties

0.19% + 0.1% + 1% +5%=6.29%

Find density:

51.6/10 * 100 * 0.20 = 0.258

Change the %percentage uncertainty to absolute uncertainty :

Absolute uncertainty = %uncertainty * the answer

6.29/100 * 0.258 = 0.0162

Answer = 0.258 +- 0.0162

After rounding:

0.26 +- 0.02

The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.

Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.

During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.

The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.

By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.

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Topic: The Effect of Temperature on Enzyme Activity in Plants
Hypothesis: I predict that as the temperature increases, the rate of enzyme activity in plants will also increase. As the temperature decreases, the rate of enzyme activity in plants will decrease.

Temperature is the measure of the average kinetic energy of the particles in a substance. It is measured in degrees Celsius (°C), Fahrenheit (°F), or Kelvin (K). Temperature is determined by the amount of heat present in a substance, which is a measure of the average kinetic energy of its particles. Heat is the energy transferred from a hotter object to a cooler one. When two objects of different temperatures come into contact, heat will flow from the hotter object to the cooler one until both objects reach the same temperature. Temperature can be affected by many factors, such as the weather, the amount of sunlight, and the activity of the particles in a substance.

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Answer:

a) angular acceleration  α = 5 rad/sec

b) MOI = 1.25 kgm^2

c) Tention in the string T = 12.5 N

Explanation:

The solution to the question has been provided in the attachment, please refer to that.

(i) The change in length is 8.78 x 10⁻⁸ m and the change in the width is -2.63 x 10⁻⁸ m

(ii) The change in volume of the bar is  7.53 x 10⁻¹¹ m³.

The bar undergoes elongation and reduction in cross-sectional area due to the applied loads.

Using the formula for longitudinal strain, we can calculate the change in length (ΔL) as follows:

ΔL = (180 × 10³ N) x (100 × 10⁻³ m) / (205 × 10⁹ N/m²)

ΔL = 8.78 x 10⁻⁸ m

The change in width (Δb) can be calculated using the formula for lateral strain:

Δb = -v x ΔL = -0.3 x  ΔL

Δb = -0.3 x 8.78 x 10⁻⁸ m

Δb = -2.63 x 10⁻⁸ m

The change in volume can be calculated as follows:

ΔV = (35 × 10⁻³ m)  x (35 × 10⁻³ m) x (ΔL + Δb)

ΔV =  (35 × 10⁻³ m) x  (35 × 10⁻³ m) x (ΔL - 0.3 x ΔL)

ΔV =  (35 × 10⁻³ m) x  (35 × 10⁻³ m) x (8.78 x 10⁻⁸m -2.63 x 10⁻⁸ m)

ΔV = 7.53 x 10⁻¹¹ m³

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Answer:

\(-3 m/s^{2}\)

Explanation:

Acceleration on a VT graph is the slope of the line at the given point. We can find the slope at 3 with Δy/Δx. This gives us (4-2)/(3-(-3)) which works out to be -3m/s^2

Recall that

\({v_f}^2={v_i}^2+2a\Delta y\)

where \(v_i\) and \(v_f\) are the lion's initial and final vertical velocities, \(a\) is its acceleration, and \(\Delta y\) is the vertical displacement.

At its maximum height, the lion has 0 vertical velocity, so we have

\(0={v_i}^2-2gy_{\rm max}\)

where g is the acceleration due to gravity, 9.80 m/s², and we take the starting position of the lion on the ground to be the origin so that \(\Delta y=y_{\rm max}-0=y_{\rm max}\).

Let v denote the initial speed of the jump. Then

\(v_i=v\sin(43.2^\circ)=\sqrt{2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(3.25\,\mathrm m)}\implies\boxed{v\approx11.7\dfrac{\rm m}{\rm s}}\)

The initial speed will be "11.7 m/s".

Given:

We know,

→ \(vf^2=v_i^2+2a\Delta y\)

At max. height, vertical height be zero, then

→ \(0 = v_i^2-2gy_{max}\)

or,

→ \(\Delta y = y_{max} -0 = y_{max}\)

now,

The initial speed,

→ \(v_i = v \ Sin(43.2^{\circ})\)

By substituting the values,

      \(= \sqrt{1\times 9.8\times 3.25}\)

      \(= 11.7 \ m/s\)

Thus the solution above is correct.

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