is a specific document that provides an overview of the proposed research and methodology, and it serves as a written contract between decision makers and researchers.

Answer:

When two fair dice are rolled, 6×6=36 observations are obtained.

P(X=2)=P(1,1)=

36

1

​

P(X=3)=P(1,2)+P(2,1)=

36

2

​

=

18

1

​

P(X=4)=P(1,3)+P(2,2)+P(3,1)=

36

3

​

=

12

1

​

P(X=5)=P(1,4)+P(2,3)+P(3,2)+P(4,1)=

36

4

​

=

9

1

​

P(X=6)=P(1,5)+P(2,4)+P(3,3)+P(4,2)+P(5,1)=

36

5

​

P(X=7)=P(1,6)+P(2,5)+P(3,4)+P(4,3)+P(5,2)+P(6,1)=

36

6

​

=

6

1

​

P(X=8)=P(2,6)+P(3,5)+P(4,4)+P(5,3)+P(6,2)=

36

5

​

P(X=9)=P(3,6)+P(4,5)+P(5,4)+P(6,3)=

36

4

​

=

9

1

​

P(X=10)=P(4,6)+P(5,5)+P(6,4)=

36

3

​

=

12

1

​

P(X=11)=P(5,6)+P(6,5)=

36

2

​

=

18

1

​

P(X=12)=P(6,6)=

36

1

​

Therefore, the required probability distribution is as follows.

Then, E(X)=∑X

i

​

⋅P(X

i

​

)

=2×

36

1

​

+3×

18

1

​

+4×

12

1

​

+5×

9

1

​

+6×

36

5

​

+7×

6

1

​

+8×

36

5

​

+9×

9

1

​

+10×

12

1

​

+11×

18

1

​

+12×

36

1

​

=

18

1

​

+

6

1

​

+

3

1

​

+

9

5

​

+

6

5

​

+

6

7

​

+

9

10

​

+1+

6

5

​

+

18

11

​

+

3

1

​

=7

E(X

2

)=∑X

i

2

​

⋅P(X

i

​

)

=4×

36

1

​

+9×

18

1

​

+16×

12

1

​

+25×

9

1

​

+36×

36

5

​

+49×

6

1

​

+64×

36

5

​

+81×

9

1

​

+100×

12

1

​

+121×

18

1

​

+144×

36

1

​

=

9

1

​

+

2

1

​

+

3

4

​

+

9

25

​

+5+

6

49

​

+

9

80

​

+9+

3

25

​

+

18

121

​

+4

=

18

987

​

=

6

329

​

=54.833

Then, Var(X)=E(X

2

)−[E(X)]

2

=54.833−(7)

2

=54.833−49

=5.833

∴ Standard deviation =

Var(X)

​

=

5.833

​

=2.415

Answer:

it's says potential that something not moving.

incorrectly cutting ties or securing devices because

this is so dangerous thing I know because being electrocuted is here this for me.

'Material Handling Injuries' are characterized as the 'injuries caused at work due to the carrying or holding of heavy loads.'

The probable hazards associated with 'materials' in terms of material handling injuries include:

A). Being crushed by machines, falling materials, or improper materials.

C). Being struck by materials or caught in pinch points

D). Improper manual lifting or carrying loads that are too heavy.

E). Incorrectly cutting ties or securing devices.

The probable injury threats to the workers while handling materials include all the above-mentioned situations.

Thus, options A, C, D, and E are the correct answers.

Learn more about 'material handling' here:

brainly.com/question/22312462

Answer:

The wind force on the screen is approximately 5,341.5936 \(lb_f\)

Explanation:

The speed of the wind, v = 36 mph

The width of the outdoor movie, w = 70 ft. wide

The height of the outdoor movie, h = 20 ft. tall

The drag coefficient, Cd = 1.15

We have;

\(C_d = \dfrac{F}{\dfrac{\rho \cdot v^2 \cdot A}{2} }\)

From which we have;

The wind force, F = 0.00256·\(C_d\)·v²·A

Where;

A = The cross sectional area of the rectangular outdoor movie screen, A = w × h

∴ A = 70 ft. × 20 ft. = 1,400 ft.²

The wind force, F = 0.00256 × 1.15 × (36 mph)² × 1,400 ft.² = 5,341.5936 \(lb_f\)

The wind force on the screen, F = 5,341.5936 \(lb_f\).

The wind force on the outdoor movie screen is;

F = 23437.26 N

We are given;

Wind speed; v = 36 mph = 16.0934 m/s

Width of screen; w = 70 ft = 21.336 m

Height of screen; h = 20 ft = 6.096 m

Drag coefficient; Cd = 1.15

Now formula for the drag force is;

F = ½•C_d•ρ•A•v²

Where;

F is drag force

C_d is drag coefficient

ρ is density of object

v is speed of object

A is area

Let us use density as 1.21 kg/m³

Area; A = wh = (21.336 × 6.096)

Thus;

F = ½ × 1.15 × 1.21 × (21.336 × 6.096) × 16.0934²

F = 23437.26 N

Read more about drag force at; https://brainly.com/question/11442373

Technician B will be involved in the situation's  Holds suitable response.

A pressure test is performed to evaluate a pipeline's integrity following installation, before commissioning, and throughout its service life. In order to prevent leaks or ruptures in pipelines carrying hazardous liquid or gas under normal operating conditions, this test is particularly helpful for integrity evaluations.

The cooling system should never be pressurized above the designated pressure cap rating, according to technician B's statements.

Learn more about cooling pressure tests:

https://brainly.com/question/16514006

#SPJ1

Answer:

final temperature = 26.5°

Explanation:

Initial volume of water is 1 x 1 x 1 = 1 \(m^{3}\)

Initial temperature of water = 20° C

Density of water = 1000 kg/\(m^{3}\)

volume of copper block = 0.46 x 0.46 x 0.46 = 0.097 \(m^{3}\)

Initial temperature of copper block = 100° C

Density of copper = 8960 kg/\(m^{3}\)

Final volume of water = 1 - 0.097 = 0.903 \(m^{3}\)

Assumptions:

mass of water remaining in the tank will be density x volume = 1000 x 0.903 = 903 kg

specific heat capacity of water c = 4186 J/K-kg

heat content of water left Hw = mcT = 903 x 4186 x 20 = 75.59 Mega-joules

mass of copper will be density x volume = 8960 x 0.097 = 869.12 kg

specific heat capacity of copper is 385 J/K-kg

heat content of copper Hc = mcT = 869.12 x 385 x 100 = 33.46 Mega-joules

total heat in the system = 75.59 + 33.46 = 109.05 Mega-joules

this heat will be distributed in the entire system

heat energy of water within the system = mcT

where T is the final temperature

= 903 x 4186 x T = 3779958T

for copper, heat will be

mcT = 869.12 x 385 = 334611.2T

these component heats will sum up to the final heat of the system, i.e

3779958T + 334611.2T = 109.05 x \(10^{6}\)

4114569.2T = 109.05 x \(10^{6}\)

final temperature T = (109.05 x \(10^{6}\))/4114569.2 = 26.5°

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

The statement that is incorrect among the given options is "The cumulative distribution of a continuous uniform random variable is a constant."

The cumulative distribution function (CDF) of a random variable is a function that gives the probability that the random variable takes on a value less than or equal to a given value. It is defined for both discrete and continuous random variables.
In the given options, the first three statements are correct. The CDF has a range that is [0,1] because it represents probabilities and probabilities are always between 0 and 1. The CDF of a random variable is always a monotone non-decreasing function, meaning that as the value increases, the probability of being less than or equal to that value also increases. Additionally, the CDF is always nonnegative because probabilities cannot be negative.
The fourth statement is also correct for discrete random variables. The CDF of a discrete random variable has jumps at integer values since the probability distribution is defined for specific values.
However, the fifth statement is incorrect. The cumulative distribution of a continuous uniform random variable is not a constant. For a continuous uniform distribution, the CDF is a linear function that increases uniformly from 0 to 1 as the value increases.
In summary, the incorrect statement is that "The cumulative distribution of a continuous uniform random variable is a constant."

Learn more about cumulative distribution here
https://brainly.com/question/30402457

 #SPJ11

Answer:

A CS degree focuses on sequential programming and software design while a computer systems engineering degree divides the focus evenly between high-level and low-level programming.

Both are correlated to technology which makes it hard for the students to choose the best suitable course.

Explanation:

SOURCE: www.computersciencedegree.hub

The expression for the current in the form i(t) = im*cos(ωt+θ) is: i(t) = 28.28*cos(2π x 1000 t + 0.942) A

To write the expression for the given sinusoidal current i(t) in the form i(t) = im*cos(ωt+θ), we need to determine the amplitude im, the angular frequency ω, and the phase angle θ.

The given current has an rms value of 20A, which means that the amplitude of the current is:

im = √2 * Irms = √2 * 20A = 28.28A (approx.)

The period of the current is 1ms, which corresponds to a frequency of:

f = 1 / T = 1 / (1ms) = 1 kHz

The angular frequency is:

ω = 2πf = 2π * 1 kHz = 2π x 1000 rad/s

The current reaches a positive peak at t = 0.3ms, which corresponds to a phase angle of:

θ = ωt - π/2 = (2π x 1000 rad/s) x (0.3 x 10^-3 s) - π/2 ≈ 0.942 radians

Therefore, the expression for the current in the form i(t) = im*cos(ωt+θ) is:

i(t) = 28.28*cos(2π x 1000 t + 0.942) A

To know more about angular frequency visit:

https://brainly.com/question/30885221

#SPJ11

The criteria for a guard having to be used on a machine is;

As a safety measure If the operation exposes you to an injury.

When operating a machine, there are possibilities that the operator could be injured or exposed to injury.

Due to the possible safety issues when operating a machine, the Occupational Safety and Health Administration (OSHA) in their 29 code mandated that a safeguard must be put at each machine to ensure that there is adequate safety that prevents or minimizes the risk of getting injured.

Read more on Occupational Safety and Health Administration (OSHA) rules at; https://brainly.com/question/17069021

Answer:

The appropriate solution will be "6.4 cm".

Explanation:

The given values are:

Length,

l = 0.2 m

Thermal conductivity,

K₁ = 1.82 W/m-K

K₂ = 0.095 W/m-K

Temperature,

T = 950 K

T = 300 K

Heat transfer rate,

Q = 830 W/m²

Now,

⇒  \(Q = \frac{\Delta T}{\frac{L_1}{K_1 A} +\frac{L_2}{K_2 A} }=\frac{A \Delta T}{\frac{L_1}{K_1 } +\frac{L_2}{K_2 } }\)

⇒ \(\frac{Q}{A} =\frac{\Delta T}{\frac{L_1}{K_1} +\frac{L_2}{K_2} }\)

On substituting the above given values in the equation, we get

⇒ \(830=\frac{(980-300)}{\frac{0.2}{1.82} +\frac{x}{0.095} }\)

On applying cross-multiplication, we get

⇒ \(\frac{0.2}{1.82} +\frac{x}{0.095} =\frac{950-300}{830}\)

⇒ \(\frac{0.2}{1.82} +\frac{x}{0.095} =\frac{650}{830}\)

⇒                \(x =0.639 \ m\)

⇒                \(x=6.345 \ i.e., 6.4 \ m\)  

Answer:

D) these connections are not user friendly

Explanation:

DC current is the unidirectional movement of electric charge. The current generated by electrochemical cell is an example of direct current. DC current can flow through vacuum and also through semiconductors, insulators and wires.

The transmission of DC current is costly and complex compared to the AC current. Its voltage also cannot be stepped up or down so one cannot get the desired voltage.

When selecting materials for use as furnace linings, several factors need to be carefully considered. Two important factors are:

Temperature Resistance: Furnaces operate at high temperatures, and the chosen lining material must have excellent temperature resistance to withstand the extreme heat. Different furnaces may require different temperature capabilities, so it is crucial to select a lining material that can withstand the specific operating temperature range. Factors such as melting point, softening point, and thermal conductivity of the material should be evaluated to ensure it can handle the heat without deteriorating or deforming. High-temperature-resistant materials, such as refractory ceramics (e.g., alumina, silica, zirconia), refractory metals (e.g., molybdenum, tungsten), or specialized heat-resistant alloys, are commonly used for furnace linings.

Chemical Compatibility: Furnaces often involve various chemical processes and environments, such as oxidation, reduction, acidic or alkaline atmospheres, or exposure to corrosive gases. The selected lining material must be chemically compatible with these conditions to prevent degradation or chemical reactions that could compromise the integrity of the lining. It is important to consider factors such as resistance to chemical attack, stability in different atmospheres, and potential reactions with the process materials or by-products. Suitable lining materials may include refractory materials that are chemically inert or have specific chemical resistance properties, such as high-alumina refractories, silica-based refractories, or certain types of specialty coatings.

By carefully evaluating temperature resistance and chemical compatibility, the selection of a suitable lining material can ensure optimal performance, longevity, and safety of furnace operations.

Learn more about selecting materials for furnace linings here: https://brainly.com/question/32850632

#SPJ11

The purification of a wide range of materials involves the use of distillation, a significant commercial procedure.

The purification of a wide range of materials involves the use of distillation, a significant commercial procedure. However, it would definitely be helpful to clarify the terms that describe the procedure and related qualities before we start a discussion of distillation.

Although you may be familiar with several of these terms, you might not be aware of their precise definitions. Let's start by outlining the procedure for changing a material from its condensed phase to its gas phase. This process is known as sublimation for solids and vaporization for liquids. Both procedures call for heat.

To know more about distillation click here:

https://brainly.com/question/29037176

#SPJ4

Answer:

b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.

Explanation:

An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.

It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.

The number of hours that must be travelled by car to make the risks of fatality by car equal to the risk of fatality by rock climbing is = 65hours

The FAR of car = 52

This means for every one hour there is risk of 52 people dying by car accident.

The FAR of rock climbing = 3400

This means that for every one hour there is risk of 3400 dying by car accident.

If FAR for 1 hour = 52

X hours = 3400

Make X the subject of formula,

X hours = 3400/52

= 65 hours approximately

Therefore, the number of hours that must be travelled by car to make the risks of fatality by car equal to the risk of fatality by rock climbing is = 65 hours.

Learn more about hours here:

https://brainly.com/question/1739912

#SPJ1

Answer:

The answer ix below

Explanation:

There are 12 apple pies left.

Given that:

n = number of apple pies left = 12

x = number of food banks = 6

1) For the 12 apple pies to be distributed among 6 food banks. The number of ways in which this can be done is:

C(n + x - 1, x - 1) = C(12 + 6 -1, 6 - 1) = C(17, 5) = \(\frac{17!}{(17-5)!5!} =\frac{17!}{12!5!}=6188 \ ways\)

12 apple pies can be distributed among 6 food banks in 6188 ways

2) For the 12 apple pies to be distributed among 6 food banks if each food bank must receive one pie, 6 pies would be remaining. The number of ways in which this can be done is:

C((n - x) + x - 1, n - x) = C(12 - 6 + 6 - 1, 12 - 6) = C(11, 6) = \(\frac{11!}{(11-6)!6!} =\frac{11!}{6!5!}=462 \ ways\)

12 apple pies can be distributed among 6 food banks if each food bank must receive one pie in 462 ways

there is no smoke its a electric train

Note that  the magnitudes of the two forces are F1 = √6 N and F2 = 2 N.

Let F1 and F2 be the magnitudes of the two forces. If they act at right angles, their resultant R is given by:

R = √(F1^2 + F2^2)

If they act at 60 degrees, their resultant R' is given by:

R' = √(F1^2 + F2^2 + 2F1F2cos60°) = √(F1^2 + F2^2 + F1F2)

We can set up a system of equations to solve for F1 and F2:

√(F1^2 + F2^2) = √10 ...(1)

√(F1^2 + F2^2 + F1F2) = √13 ...(2)

Squaring both sides of equation (1), we get:

F1^2 + F2^2 = 10

Squaring both sides of equation (2), we get:

F1^2 + F2^2 + F1F2 = 13

Substituting F1^2 + F2^2 = 10 from equation (1), we get:

10 + F1F2 = 13

F1F2 = 3

Now, we can solve for F1 and F2 using the equations:

F1^2 + F2^2 = 10

F1F2 = 3

Multiplying the second equation by 4, we get:

4F1F2 = 12

Substituting F1F2 = 3, we get:

12 = 3(F1^2 + F2^2)

Simplifying, we get:

F1^2 + F2^2 = 4

Using this equation and F1F2 = 3, we can solve for F1 and F2:

F1^2 + F2^2 = 4

F1F2 = 3

Multiplying the first equation by F1F2, we get:

F1^2F2 + F1F2^2 = 12

Substituting F1F2 = 3, we get:

F1^2 + 3F2^2 = 12

Substituting F1^2 = 4 - F2^2 from the first equation, we get:

4 - F2^2 + 3F2^2 = 12

Simplifying, we get:

2F2^2 = 8

F2^2 = 4

F2 = 2

Substituting F2 = 2 in F1^2 + F2^2 = 10, we get:

F1^2 + 4 = 10

F1^2 = 6

F1 = √6

Therefore, the magnitudes of the two forces are F1 = √6 N and F2 = 2 N.

Learn more about magnitude at:

https://brainly.com/question/14452091

#SPJ1

Wheelbase, trackwidth, and tire load data can be used to determine the longitudinal CG location. The distance in inches between the center of gravity and the front wheel.

Wheelbase, trackwidth, and tire load data can be used to determine a car's longitudinal center of gravity (CG) location. The distance between the centers of the front and rear wheels is known as the wheelbase, while the distance between the left and right tire centerlines is known as the trackwidth. The amount of weight on each of the four tires that are in contact with the ground is known as the tire load. The entire weight of the vehicle is divided by the wheelbase and trackwidth, and the resulting number is multiplied by the wheelbase to determine the longitudinal center of gravity (CG) location. The resultant measurement, taken from the front wheel, is the longitudinal CG location in inches.

Learn more about distance here-

https://brainly.com/question/19915401

#SPJ4

Glue deterioration in wood aircraft structure is indicated by the appearance of cracks and separations between the wood pieces.

Wood was commonly used in the construction of aircraft structures during the early days of aviation, and glue was used to hold the wooden pieces together. However, over time, the glue can deteriorate due to exposure to heat, moisture, and other environmental factors. When the glue deteriorates, it can no longer hold the wooden pieces together, leading to cracks and separations between the wood pieces. To detect glue deterioration in a wood aircraft structure, a visual inspection is often performed. The inspector will look for signs of cracking or separation between the wooden pieces, as well as any signs of discoloration or softening of the wood. If glue deterioration is suspected, further testing may be necessary to confirm the extent of the damage. In some cases, it may be necessary to replace the affected parts or to perform repairs to reinforce the structure.

Learn more about deterioration here

https://brainly.com/question/30284491

#SPJ11

Employment growth is often used as a measure of economic expansion and a test for domestic economic health.

In this question all the choices were interlinked with each other therefore, the final answer is "Option d".

Learn more:

brainly.com/question/13369562

The magnitude of the line voltage at the source end of the line is 4168 volts.

To find the magnitude of the line voltage at the source end of the line, we can use the power factor of the first load, which is cos⁡(ϕ) = 630/900 = 0.7. The total reactive power of the load is Q = 840 kvar, and the apparent power is S = 900 kVA.

Therefore, the reactive power of the load is Q = S sin(ϕ) = 900 sin(arccos(0.7)) = 610 kvar. The total reactive power of both loads is 610 + 840 = 1450 kvar. Using the power formula, we get P = √3 V L I L cos(ϕ) => V L = P / (√3 I L cos(ϕ)), where I L = S / (√3 V L), and P = 630 kW.

By solving these equations, we get V L = 4168 volts.

To know more about reactive power related problems visit:

brainly.com/question/14587561

#SPJ11

A disk drive is a device that reads and writes data to storage media, such as optical discs.

An optical disk drive is a type of disk drive that uses laser light to read from or write to optical discs, such as CD, DVD, and Blu-ray discs. When reading or writing data, the laser light reflects off the disc and is detected by a sensor in the drive. Optical disk drives are commonly found in computers, gaming consoles, and standalone players.

In conclusion, an optical disk drive is a useful device that allows for easy access to data stored on optical discs. Its use of laser light technology allows for fast and accurate data retrieval and storage.

To learn more about disk drive, visit:

https://brainly.com/question/13867015

#SPJ11

Electromagnetic Interference (EMI) is the intentional insertion in any manner of electromagnetic energy into transmission paths.

Electromagnetic Interference (EMI) is the deliberate insertion of electromagnetic energy into transmission paths in order to disrupt the proper functioning of an electronic system.EMI can be caused by a variety of sources, including radio and television broadcasts, cell phones, computers, electric motors, and power lines. Because EMI can disrupt the proper functioning of an electronic device, it is a significant issue that must be addressed by designers and manufacturers of electronic equipment.

There are a number of ways to reduce the effects of EMI. The first is to use shielding, which is the process of enclosing the electronic device in a metal box or casing to block electromagnetic signals. Another option is to use filters, which are devices that remove unwanted frequencies from a signal. Additionally, proper grounding and circuit design can help to reduce the effects of EMI.

Learn more about Electromagnetic Interference: https://brainly.com/question/12572564

#SPJ11

The intentional insertion in any manner of electromagnetic energy into transmission paths is called "Electromagnetic Interference" (EMI).

EMI refers to the disturbance caused by the presence of unwanted electromagnetic signals in the transmission paths or electronic systems. It can result from various sources such as electronic devices, power lines, radio signals, or other electromagnetic sources.

EMI can negatively impact the performance and functionality of electronic devices and communication systems. It can cause signal degradation, data corruption, malfunctions, or even complete system failures.

Learn more about Electromagnetic interference, here:

https://brainly.com/question/32635415

#SPJ4

The given problem is concerned with a company that has to produce goods for two quarters' period. The company has a regular time capacity and forecast demand, which is given in the table below per month.

We are required to determine the overtime capacity, overtime cost, backorder cost, inventory-holding cost, and the beginning inventory. Given data: Demand | Regular time capacity50 | 50Overtime capacity | 50% of regular time capacity × 1.5= 50% of 50 × 1.5= 25 × 1.5= 37.5 units per month Overtime cost.

Therefore, the overtime cost and backorder cost are zero. Inventory-holding cost= 50 units × R5 per unit= R250Therefore, the company needs to work at 100% of the regular time capacity and 74% of the overtime capacity to meet the forecast demand of 50 units per month for two quarters.

To know more about concerned visit:

https://brainly.com/question/20202196

#SPJ11

Answer:

The operating principle of a ramp type digital voltmeter is to measure the time that a linear ramp voltage takes to change from level of input voltage to zero voltage (or vice versa).

Answer:

oh god... i have no idea lm.ao

Explanation: