Iron (III) nitrate (Fe(NO3)3) solution reacts with sodium hydroxide (NaOH) solution to form a
brown precipitate of iron (III) hydroxide (Fe(OH)3). Sodium nitrate (NaNO3) remains in solution as
it is a soluble compound.
Write the word equation and the balanced formula equation for this reaction.​

Answer:

10 g

Explanation:

Right from the start, just by inspecting the values given, you can say that the answer will be  

10 g

.

Now, here's what that is the case.

As you know, a substance's specific heat tells you how much heat is needed to increase the temperature of  

1 g

of that substance by  

1

∘

C

.

Water has a specific heat of approximately  

4.18

J

g

∘

C

. This tells you that in order to increase the temperature of  

1 g

of water by  

1

∘

C

, you need to provide  

4.18 J

of heat.

Now, how much heat would be required to increase the temperature of  

1 g

of water by  

10

∘

C

?

Well, you'd need  

4.18 J

to increase it by  

1

∘

C

, another  

4.18 J

to increase it by another  

1

∘

C

, and so on. This means that you'd need

4.18 J

×

10

=

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

.

Now look at the value given to you. If you need  

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

, what mass of water would require  

10

times as much heat to increase its temperature by  

10

∘

C

?

1 g

×

10

=

10 g

And that's your answer.

Mathematically, you can calculate this by using the equation

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

418

J

=

m

⋅

4.18

J

g

∘

C

⋅

(

20

−

10

)

∘

C

m

=

418

4.18

⋅

10

=

10 g

The mass of 88 milliliters of the substance in pounds is approximately 1.1748 pounds.

To determine the mass of the substance in pounds, we can use the given density and the volume of the solution.

Density of the solution = 6.05 kg/L

Volume of the solution = 88 milliliters = 88/1000 L (since 1 liter = 1000 milliliters)

First, we need to convert the density from kg/L to pounds per liter:

1 kg = 2.2 lbs

1 L = 2.2046 lbs (approximately)

Density in pounds per liter = 6.05 kg/L * 2.2046 lbs/kg ≈ 13.35 lbs/L

Now, we can calculate the mass of the substance in pounds by multiplying the density by the volume:

Mass in pounds = (13.35 lbs/L) * (88/1000 L) ≈ 1.1748 lbs

Therefore, the mass of 88 milliliters of the substance is approximately 1.1748 pounds.

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Answer:0.125 moles of CaCl2

Option D 0.13moles

Explanation:

Molarity= number of moles/ volume of solution

0.25M×.5 = number of moles

0.125 moles

Answer:

A 3s orbital is at a greater average distance from the nucleus than a 2s orbital

Explanation:

As the principal quantum number n increases, the distance of the orbital from the nucleus increases. Hence if we consider the 2s and 3s orbitals, it is easy to see that the 3s orbital is at a greater distance from the nucleus than the 2s orbitals.

This is clearly seen when we plot the radial distribution against the distance from the nucleus. This enables us to visualize the region in space in which an electron may be found.

The heat capacity of 185g of liquid water is 4.421 J/g°C

Heat capacity is defined as the amount of heat energy required to raise the temperature of a given quantity of matter by one degree Celsius

Here given data is

Mass =  185g

We have to calculate the heat capacity = ?

So the formula is

q = m×c×ΔT

c = ?

q =  4.184 J

m = 185g

ΔT = 100°C

c =  m× ΔT/q

c =  185g ×100°C/ 4.184 J

c = 4.421 J/g°C

Heat capacity of 185g of liquid water is 4.421 J/g°C

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A helical section that moves dramatically when NTP (nucleoside triphosphate) is bound is called the "P-loop". P-loop NTPases are a family of proteins that hydrolyze NTPs, and the conformational change in the P-loop region is a critical step in the catalytic cycle of these proteins.

The P-loop is named after the conserved motif (GxxxxGKS/T) that forms the base of the loop and interacts with the phosphate groups of the NTP substrate. When NTP is bound, the P-loop undergoes a conformational change that results in the formation of a catalytic site for NTP hydrolysis. Therefore, the P-loop is a key structural element in the function of P-loop NTPases.

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he NCNH- ion has a total of two sigma (σ) bonds and two pi (π) bonds. N≡C-N: One sigma bond and two pi bonds

C-N: One sigma bond

To determine the number of sigma (σ) and pi (π) bonds in the NCNH- ion, we need to examine the bonding structure and electron arrangement.

In the NCNH- ion, nitrogen (N) and carbon (C) atoms are present. Both nitrogen and carbon can form multiple bonds due to their valence electron configuration.

The Lewis structure of NCNH- can be represented as:

N≡C-N:H-

In this structure, the triple bond (≡) between the two nitrogen atoms (N≡C-N) consists of one sigma bond and two pi bonds. The single bond between the carbon and nitrogen (C-N) also represents one sigma bond.

It is important to note that the number of sigma and pi bonds can vary depending on the specific bonding arrangement and molecular structure of a given compound or ion. The information provided here pertains specifically to the NCNH- ion.

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Answer:126

Explanation:

To deploy configuration profiles for computers from Jamf Pro, the Apple Push Notification service (APNs) must be available.

APNs is a cloud-based service provided by Apple that enables the secure transfer of data between Apple devices and servers. It is essential for communication between Jamf Pro and Apple devices during the deployment of configuration profiles.

APNs is used to initiate the connection between the devices and Jamf Pro, allowing for the transfer of the configuration profiles. Without APNs, it would be impossible to deploy configuration profiles to Apple devices using Jamf Pro.

Therefore, it is critical to ensure that APNs is available and functioning correctly before attempting to deploy configuration profiles using Jamf Pro.

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Sodium from Na3PO4(aq) could be prepared by electrolysis of the aqueous solution shown. Based on the provided options, the element that could be prepared by electrolysis of the aqueous solution shown

Potassium from KCl(aq)
Here's why:
- Sodium from Na3PO4(aq) and Nitrogen from AgNO3(aq) are not possible because these ions are more stable in solution than undergoing electrolysis.
- Sulfur from K2S04(ed) is not valid as the compound should be K2SO4(aq) and even then, it would produce oxygen at the anode instead of sulfur.
- Oxygen from H2SO4(aq) can be prepared through electrolysis, but this is not an element directly obtained from the compound.
Potassium from KCl(aq) can be prepared by electrolysis. During this process, K+ ions are reduced to potassium metal at the cathode, and Cl- ions are oxidized to chlorine gas at the anode.

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The standard molar enthalpy for the reaction C(s) + ½ O2(g) → CO(g) is -111KJ.

Molar enthalpy is the amount of energy per mole. In light of this, the primary distinction between enthalpy and molar enthalpy is that the former refers to the total heat content of a thermodynamic system, whereas the latter refers to the total heat per mole of reactant in the system.

C(s) + O₂(g) → CO₂(g)    ΔHO = -394 kJ ----(1)

CO₂(g) → CO(g) + 1/2O₂(g)      ΔHO = +283 kJ -----(2)

Adding 1 & 2

C(s) + ½ O₂(g) → CO(g)  

ΔHO = -394 kJ + 283 kJ

ΔHO = -111KJ.

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Complete question is " Find the standard molar enthalpy for the reaction C(s) + ½ 02(g) → CO(g)

Given that

C(s) + O2(g) → CO2(g) AHO = -394 kJ

CO2(g) → CO(g) + ¹/2O2(g) AHO = +283 kJ ".

Answer:NH4, because nitrogen needs four electrons, and each hydrogen needs one electron.

Explanation:

Answer:Tennis ball?

Explanation:

Well, an example would be DNA so a non-example could be a tennis ball. Or anything that isn't nucleic acids like lipids, perhaps.

Answer:

32 gm O

Explanation:

there are 16 gm of O in each 18 gm of water ....the other two grams are H

so there would be 32 gm of oxygen in 36 gm water

For the reaction of lead(II) nitrate with potassium chloride, the balanced full ionic equation is Pb(NO3)2(aq) + 2 KCl(aq) PbCl2(s) + 2 KNO3 PbCl2(s) + 2 KNO3 (aq) To formulate the whole ionic equation.

we divide all soluble ionic compounds into their constituent ions: Pb2+(aq) + 2 NO3-(aq) + 2 K+(aq) + 2 Cl-(aq) PbCl2(s) + 2 K+(aq) + 2 NO3-(aq) + 2 Cl-(aq) (aq) The potassium and nitrate ions are spectator ions, appearing on both sides of the equation but not participating in the process. By deleting the spectator ions, the net ionic equation is obtained: PbCl2 = Pb2+(aq) + 2 Cl-(aq) (s) As a result, the net ionic equation for the reaction is as follows PbCl2 = Pb2+(aq) + 2 Cl-(aq) (s).  the correct balanced complete ionic equation for the reaction of lead(ii) nitrate with potassium chloride.

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Order of stability will be D>C>B>A
D= This free radical has two effects that make it most stable,i.e the free radical is

allylic

as well as tertiary.
C= It is the only allylic position. So, it is 2nd most stable
B= It is tertiary free radical.
A= It is secondary free

radical

A radical is an unstable, highly reactive molecule or atom with one or more unpaired valence electrons. Because of their unpaired electrons, radicals are extremely reactive and able to take part in a wide range of chemical processes.

Chemical reactions, radiation exposure, or other sorts of chemical processes can all result in the formation of radicals. Radicals that are frequently encountered include hydroxyl radicals (•OH) and methyl radicals (•CH3). Radicals frequently take part in organic chemistry reactions because they can start chain reactions and take part in processes like radical polymerization. Radicals are difficult to study and manage because of their reactivity and instability, but they are crucial to many chemical and biological processes.

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question:

5 Signs of dehydration are chills, dry mouth, muscle cramps, dark urine, and lightheadedness.

When the body loses more fluid than it takes in, it becomes dehydrated and is unable to function normally. This can result in a number of problems if it isn't treated, like losing strength and stamina, brain damage, or even death.

In addition to thirst, these are the top five symptoms of dehydration:

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Answer:

B

Explanation:

Answer:

3.82 g.

Explanation:

To calculate the mass of sulfuric acid produced from 1.25 g of sulfur, we'll have to balance the chemical equations and use stoichiometry.

Starting with the first reaction:

2S(s) + 3O2(g) → 2SO3(g)

Since 1.25 g of sulfur is reacted, the number of moles of sulfur can be calculated as:

moles = mass / molar mass = 1.25 g / 32 g/mol = 0.03906 mol

Next, using the mole ratio from the balanced chemical equation, we can find the number of moles of sulfur trioxide produced:

2 moles of sulfur produce 2 moles of sulfur trioxide, so:

moles of SO3 = moles of S x (moles of SO3 / moles of S) = 0.03906 mol x (2 mol / 2 mol) = 0.03906 mol

Finally, we move on to the second reaction, the dissolution of sulfur trioxide in water:

SO3(g) + H2O(l) → H2SO4(l)

Using the mole ratio from this balanced equation, we can find the number of moles of sulfuric acid produced:

1 mole of sulfur trioxide reacts with 1 mole of water to produce 1 mole of sulfuric acid, so:

moles of H2SO4 = moles of SO3 x (moles of H2SO4 / moles of SO3) = 0.03906 mol x (1 mol / 1 mol) = 0.03906 mol

The mass of sulfuric acid produced can be calculated using the moles and the molar mass of sulfuric acid:

mass = moles x molar mass = 0.03906 mol x 98 g/mol = 3.82 g

Therefore, if 1.25 g of sulfur is reacted, the mass of sulfuric acid produced is approximately 3.82 g.

Answer:

chemical

Explanation:

The room temperature densities of nitrogen (N₂), oxygen (O₂), and carbon dioxide (CO₂) gases are approximately 1.250 g/L, 1.429 g/L, and 1.964 g/L, respectively.

To calculate the densities, we need to use the ideal gas law, which states that the density (ρ) of a gas is equal to its molar mass (M) divided by the molar volume (V) at a given temperature and pressure.

At room temperature, which is approximately 298 K, and assuming standard pressure, the molar volume of a gas is approximately 22.4 L/mol.

For nitrogen (N₂):

Density (N₂) = M(N₂) / V = 28 g/mol / 22.4 L/mol ≈ 1.250 g/L

For oxygen (O₂):

Density (O₂) = M(O₂) / V = 32 g/mol / 22.4 L/mol ≈ 1.429 g/L

For carbon dioxide (CO₂):

Density (CO₂) = M(CO₂) / V = 44 g/mol / 22.4 L/mol ≈ 1.964 g/L

Therefore, the room temperature densities of nitrogen, oxygen, and carbon dioxide gases are approximately 1.250 g/L, 1.429 g/L, and 1.964 g/L, respectively.

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Cooling the reaction mixture before adding water helps to prevent premature precipitation of the product and ensures better control of the precipitation process, yielding a higher-purity product.

To avoid early or uncontrolled precipitation, which can result in reduced product purity, the reaction mixture is frequently cooled before water is added to precipitate the product. As a result of the product's reduced solubility in the solvent and slowed molecular mobility, cooling increases the likelihood that it may precipitate.

Additionally, cooling might lessen adverse effects that could happen at higher temperatures. In many chemical processes, it enables greater control of the precipitation process, resulting in a larger yield and a purer product.

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Mass percent of Sodium Chloride solution prepared by mixing is 21.875%.

A mixture is a chemical substance comprised of two or more unrelated chemical components. A mixture is a physical combination of two or more distinct substances that can take the form of solutions, suspensions, or colloids. Solutions of salt and water are an example of a homogeneous mixture, whereas sand and water and oil and water are instances of heterogeneous mixtures.

Density of Water = 1g/mL

So, 125 mL of water weighs 125g

Mass of \(NaCl\) = 35.0g

Total mass of solution = 125g+35g = 160g

Mass % of \(NaCl\) =(Mass of \(NaCl\) / Total Mass ) × 100

                         = (35/160) × 100

                          = 21.875%

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Answer:

Explanation:

Dimples B)

The closest relative to HIV-1 is Chimp SIV.

HIV-1 is believed to have originated in chimpanzees that were infected with simian immunodeficiency virus (SIV).

Specifically, the strain SIVcpz found in the subspecies Pan troglodytes troglodytes is associated with the transmission of SIV to humans.

The transmission occurred through the hunting and butchering of chimpanzees for food.

SIV is a retrovirus that causes immunosuppression or weakens the immune system in infected primates.

In some species of African nonhuman primates, such as sooty mangabeys and African green monkeys, SIV infections are normal and asymptomatic.

Therefore, Chimp SIV is considered the closest relative to HIV-1

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Fractional bond orders are frequently produced by partial bonding, such as when it's a component of a resonance hybrid.

Resonance hybrid: what is it?

Resonance structures are collections of two or more Lewis structures, including fractional bonds and fractional charges, that collectively represent the electronic bonding of a single polyatomic species.

Resonance structures can represent delocalized electrons that are not described by a single Lewis formula with an integral number of covalent bonds.

Do resonance hybrids include any partial charges?

A resonance structure must never have any net formal charge. On the other hand, the weighted average of the formal plus partial charges on an atom in each resonance contributor is the net partial charge on that atom.

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