ionic equation for the reaction between aqueous solution of potassium carbonate and dilute sulphuric acid​

The wavelength of the wave having a frequency of 60 Hz and a speed of 45 m/s is 0.75 m (Option A)

The velocity, frequency and wavelength are related according to the following equation:

v = λf

where

λ = v / f

λ = 45 / 60

λ = 0.75 m

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Answer:

The options (A) -The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.  and (C) -The rate laws of bimolecular elementary reactions are second order overall ,is true.

Explanation:

(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.

(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.

(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.

(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.

Therefore , the first and third statement is true.

Maddy made the error of multiplying by 10 rather than 100, which produced an answer that was 10 times off in the conversion of units.

The work of Maddy is flawed. We must multiply the value in grammes by 100 to convert it to centigrammes. Maddy gave the wrong answer of 7.5 cg by multiplying the weight in grammes by 10 rather than 100.

In order to convert 0.75 grammes to centigrammes, use the following formula:

100 cg/g x 0.75 g equals 75 cg

Consequently, 0.75 grammes is 75 centigrammes. Maddy made the error of multiplying by 10 rather than 100, which produced an answer that was 10 times off.

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Answer:

The answer is 825.5 because I multiplied 2.54 by 325.

I dont know if its right.

Answer:

825.5 cm

Explanation:

325 x 2.54 = 825.5

Hope this helps :)

The amount of dry solute it would take to prepare 118 mL of 0.105 M NaNO3 is 1.05g.

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows:

mass = no of moles × molar mass

However, the number of moles it took to prepare 118 mL of 0.105 M NaNO3 must be calculated as follows;

no of moles = 0.105 × 0.118 = 0.0124 moles

molar mass of sodium nitrate = 85g/mol

mass = 85g/mol × 0.0124 moles = 1.05g

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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Solid Snake (75 kg) carries 18 kg of equipment. If Solid Snake climbs 27 flights of stairs, each 5.5 m in height, the work done against gravity is 135.34 kJ (c).

In physics, work is the energy transferred to or from an object via the application of force along a displacement.

In this problem, the force that does the work is the one that opposes the weight.

Solid Snake is 75 kg and is carrying 18 kg of equipment. The total mass is:

m = 75 kg + 18 kg = 93 kg

We can calculate the weight using Newton's second law of motion.

F = m . g = 93 kg . 9.8 m/s² = 911.4 N

Solid Snake climbs 27 flights of stairs, each 5.5 m in height.

27 . 5.5 m = 148.5 m

We will use the definition of work.

w = F . s = (911.4 N) . (148.5 m) . (1 kJ/1000 J) = 135.34 kJ

Solid Snake (75 kg) carries 18 kg of equipment. If Solid Snake climbs 27 flights of stairs, each 5.5 m in height, the work done against gravity is 135.34 kJ (c).

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We can actually deduce here that the purpose of this assignment is to teach students about decomposition reactions and allow them to determine the percent yield.

By performing the experiment, students will gain a better understanding of the concepts involved and how they relate to their overall learning.

The specific focus of this assignment is the decomposition of sodium bicarbonate (NaHCO3) to produce sodium carbonate (Na2CO3), water (H2O), and carbon dioxide (CO2). The unbalanced chemical equation for this reaction is:

NaHCO3 (s) + heat -> Na2CO3 (s) + H2O (g) + CO2 (g)

To understanding the reaction itself, students will also learn about the concept of percent yield. Percent yield is a measure of the efficiency of a chemical reaction and is calculated by dividing the actual yield of the desired product by the theoretical yield, then multiplying by 100.

This calculation allows students to assess how well the reaction proceeds in terms of producing the expected amount of sodium carbonate.

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It is necessary for astronauts on the International Space Station to generate and recycle oxygen because There is not enough oxygen in space to sustain life.

The correct answer choice is" There is not enough oxygen in space to sustain life."

In space, there is no breathable air as there is on Earth, and the amount of oxygen available is limited. Astronauts need a constant supply of oxygen to breathe and to sustain their bodily functions.

Therefore, the International Space Station has a closed-loop life support system that generates and recycles oxygen. This system converts carbon dioxide exhaled by the astronauts into oxygen through a process called electrolysis.

The generated oxygen is then supplied back into the station's atmosphere. This process helps ensure that the astronauts have a constant supply of breathable air and can survive in the space station for extended periods of time.

Therefore "There is not enough oxygen in space to sustain life." is the correct answer.

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Jared marks the center of the kite-shaped area with a stake and measures 50 ft from the center in one direction, placing another stake. He then extends the rope from the center to the second stake, folds it in half, connects the ends, and drives a stake where they meet. Finally, he completes the kite shape by extending the remaining portion of the rope from the second stake back to the center stake.

To use all of the 100 ft rope to complete the kite shape for the food vendor area, Jared can follow the steps outlined below:

Jared starts by driving a stake into the ground to mark the center of the kite-shaped area.

Using the rope, Jared measures a distance of 50 ft from the center stake in one direction and places a stake there.

Next, Jared extends the rope from the center stake to the newly placed stake, forming one side of the kite.

To create the other side of the kite, Jared folds the rope in half, bringing the end that is still connected to the center stake to meet the newly placed stake.

Jared drives another stake at the point where the two halves of the rope meet, securing the second side of the kite.

Finally, Jared extends the remaining portion of the rope from the second stake back to the center stake, completing the kite shape.

Jared marks the center of the kite-shaped area with a stake and measures 50 ft from the center in one direction, placing another stake. He then extends the rope from the center to the second stake, folds it in half, connects the ends, and drives a stake where they meet. Finally, he completes the kite shape by extending the remaining portion of the rope from the second stake back to the center stake.

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The escape of the carbon dioxide molecules from the surface. Option 4.

The area where the soda and surrounding air come into contact when the soda bottle is opened rises. The exchange of gases between the soda and the atmosphere is facilitated by the increased surface area.

The molecules of carbon dioxide have a tendency to leave the liquid phase and transition into the gas phase as they come into contact with the air. The action in question is called degassing. The soda's concentration of dissolved carbon dioxide is decreased and its capacity to dissolve further due to the ongoing emission of carbon dioxide.

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Answer:

see below

Explanation:

.3 M/L ( .125 L) = .0375 mole required

.0375 mole / 2 mole / l = .01875 l required

take 18.75 ml of the 2.0 solution then dilute it to 125 ml

Answer:

i belive your talking about Conduction

Explanation:

if  im

wrong comment

There are 9.8 moles of sodium (Na) in a sample of 5.87 x 10²⁴ atoms of sodium.

The number of moles of a substance can be calculated by dividing the number of molecules in the substance by Avogadro's number. That is;

no. of moles = no. of atoms ÷ 6.02 × 10²³

According to this question, there are 5.87 x 10²⁴ atoms of sodium. The number of moles is as follows:

no. of moles = 5.87 x 10²⁴ atoms ÷ 6.02 × 10²³

no. of moles = 0.98 × 10¹

no. of moles = 9.8moles

Therefore, there are 9.8 moles of sodium (Na) in a sample of 5.87 x 10²⁴ atoms of sodium.

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The final volume of the ladybug's prison is approximately 0.4 liters.

To determine the final volume of the ladybug's prison, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. The equation for Boyle's Law is:

P1 * V1 = P2 * V2

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

In this scenario, the initial volume (V1) is given as 0.5 L, and the initial pressure (P1) is 1 atm. The final pressure (P2) is 1.25 atm. We need to find the final volume (V2).

Plugging the given values into the equation, we have:

1 atm * 0.5 L = 1.25 atm * V2

Simplifying the equation, we find:

0.5 L = 1.25 atm * V2

Dividing both sides of the equation by 1.25 atm, we get:

0.5 L / 1.25 atm = V2

V2 ≈ 0.4 L

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The correct match is as follows:

Pressure and heat - Metamorphic rock

Cooling magma - The Intrusive igneous rock

Cooling lava - The Extrusive igneous rock

Erosion and Deposition - Sedimentary rock

This is because Metamorphic rocks are formed as a result of past existing rocks changing form. If the igneous and sedimentary rocks are exposed to high temperature and pressure, they then become metamorphic rocks.

Intrusive igneous rocks form when magma cools slowly. This process soon results in the formation of large-crystal like structures. Whereas, when exposed to the atmosphere lava cools rather quickly. This faster cooling process forms extrusive igneous rocks. The fast cooling lava creates smaller crystals and a smoother surface.

The sediments that are formed as a result of weathered rocks are usually deposited on the surface of Earth, or at the bottom of rivers and oceans. Over time, sediments collect and form layers over the most recent layer. This leads to the formation of sedimentary rocks.

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Answer:

I believe this is your answer, or wait I know this is your answer

Explanation:

The frequency of a photon of yellow light with a wavelength of 4.63 X 10-⁷m is 6.48 × 10¹⁴ Hz.

The frequency of a wave can be calculated by using the following formula:

v = fλ

Where;

According to this question, a photon of yellow light with a wavelength of 4.63 X 10-⁷m is given. The frequency of this photon can be calculated as follows:

f = 3 × 10⁸m/s ÷ 4.63 X 10-⁷m

f = 6.48 × 10¹⁴ Hz

Therefore, the frequency of a photon of yellow light with a wavelength of 4.63 X 10-⁷m is 6.48 × 10¹⁴ Hz.

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Johannes Brsted and Thomas M. Lowry, two chemists, identified the Bromsted-Lowry acids and bases as a particular kind of acid-base reaction in 1923.

Acids are substances that give a base a proton (H+), whereas bases are substances that take a proton from an acid. In a Bromsted-Lowry acid-base reaction, the acid gives the base a proton in order to create the conjugate base and the conjugate acid, two new compounds.

Nitric acid (HNO3), sulfuric acid (H2SO4), and hydrochloric acid (HCl) are a few examples of acids. Sodium hydroxide (NaOH), ammonium hydroxide (NH4OH), and potassium hydroxide (KOH) are a few examples of bases.

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After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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2.39moles of LiOH are required to produce 165 g of LiNO\(_3\). The mole consists of precisely  6.022×10²³  elementary components.

In the Worldwide System of Units, the mole (sign mol) is indeed the unit of material quantity (SI). The quantity of a substance is a measurement about how many elementary units of a certain substance are present in an object as well as sample.

The mole consists of precisely  6.022×10²³  elementary components.

Cr(NO\(_3\))\(_3\)(aq) + LiOH(aq) → LiNO\(_3\)(aq) + Cr(OH)\(_3\)

moles of LiNO\(_3\) = 165/68.94=2.39moles

the mole ratio between LiOH and  LiNO\(_3\) is 1:1

moles of  LiNO\(_3\) = 2.39moles

Therefore, 2.39moles of LiOH are required to produce 165 g of LiNO\(_3\).

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\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Here's what we observed in the following two scenarios :

When the mixture of salt and sand is placed in a beaker, they form a heterogeneous mixture, and it is a bit troublesome to separate those two

But when water is added to the mixture, salt gets dissolved in it, whereas sand doesn't and it settles down with time, amd here we can easily separate sand and salt mixture, we just need to take out the water when sand has settled and just heat it to get salt back.

This equilibrium potential (ENa) of the sodium concentration extracellularly is 116.

The amount of solute contained in a specific amount of solution is the substance's concentration. The molecular weight of solution in 1 L aqueous solution, or molarity, is used to express concentrations. Molar concentration, molality, mass percentage, components per thousand, milligrams, and parts per billion are examples of quantitative measurements of concentration.

The responsibility of the parties to take specific procedural steps during particular stages of antagonistic hearings in order to expedite the proceedings and the court's decision constitutes the principle of concentrating as one of the main server principles of civil procedures.

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Answer:

a. 2.41 g

Explanation:

First we calculate the number of lithium ion moles (Li⁺) in the solution, multiplying the concentration times the volume:

500 mL ⇒ 500 / 1000 = 0.500 L

Then we convert moles of Li⁺ to moles of Li₃PO₄, keeping in mind that for each mole of Li₃PO₄ there are 3 Li⁺ moles:

Finally we convert Li₃PO₄ moles to grams, using its molar mass:

The mass of lithium phosphate, Li₃PO₄ required to prepare the solution is 2.41 g

The correct answer to the question is Option A. 2.41 g

We'll begin by calculating the concentration of Li₃PO₄. This can be obtained as follow:

Li₃PO₄(aq) —> 3Li⁺(aq) + PO₄³¯(aq)

From the balanced equation above,

3 moles of Li⁺ is present in 1 mole of Li₃PO₄.

Therefore,

0.125 M Li⁺ will be present in = 0.125 / 3 = 0.0417 M Li₃PO₄.

Thus, the concentration of Li₃PO₄ is 0.0417 M

Molarity of Li₃PO₄ = 0.0417 M

Volume = 0.5 L

Mole = Molarity x Volume

Mole of Li₃PO₄ = 0.0417 × 0.5

Mole of Li₃PO₄ = 0.02085 mole

Molar mass of Li₃PO₄ = (3×7) + 31 + (16×4) = 116 g/mol

Mass = mole × molar mass

Mass of Li₃PO₄ = 0.02085 × 116

Thus, the mass of Li₃PO₄ required to prepare the solution is 2.41 g

The correct answer to the question is Option A. 2.41 g

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Answer:

Molecules can be composed of two or more of the same atom

Explanation:

I think the answer as communicating findings.

The scientific method is the use of various steps to solve the question and reach the solution. A chemist writing report for making a new compound is following the communication findings. Thus, option C is correct.

The scientific method has been the use of various procedures and steps that involves observation, experimentation, measurement, testing, etc. to reach the solution for the formulated hypothesis. It allows the understanding of the solutions to the question asked.

It also includes communicating findings that include the writing of a report that has been using the scientific method to research the subject matter and has been constituted of introduction, results, experimentation methods, discussions, observations, etc.

A chemist writing a report shows communication findings as they are reporting the hypothesis and the scientific method to the other scientists and uses the knowledge to formulate the experiment.

Therefore, option C. communicating findings is the correct option.

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Answer:

Explanation:

To calculate the mass of carbon dioxide (CO2) produced by a quarter gallon of gasoline, we'll need the following information:

1. The molar mass of carbon dioxide (CO2): approximately 44.01 grams/mol.

2. The molarity of gasoline: 0.923 M.

3. The volume of gasoline: 1000 mL.

First, we need to convert the volume of gasoline from milliliters (mL) to liters (L):

1000 mL = 1000/1000 = 1 L

Next, we can use the equation relating molarity, volume, and number of moles:

Molarity (M) = Moles (mol) / Volume (L)

Rearranging the equation, we can solve for moles:

Moles (mol) = Molarity (M) * Volume (L)

Moles (mol) = 0.923 M * 1 L = 0.923 mol

Finally, we can calculate the mass of carbon dioxide produced by multiplying the number of moles by the molar mass:

Mass (g) = Moles (mol) * Molar mass (g/mol)

Mass (g) = 0.923 mol * 44.01 g/mol ≈ 40.60 g

Therefore, approximately 40.60 grams of carbon dioxide are produced by burning a quarter gallon of gasoline.