Iodine-131 has a half life of 8 days. if there were 512 mg in a sample, how much iodine would be left in 32 days?

Answers

Answer 1

In a 32-day period, a 512 mg sample of Iodine-131 will be reduced to 32 mg.
7
Since the half-life is 8 days, we can divide 32 days by the half-life to find the number of half-lives that have occurred: 32 days ÷ 8 days/half-life = 4 half-lives.

Now, for each half-life, the amount of Iodine-131 will decrease by half. After 1 half-life (8 days), 512 mg will become 256 mg. After 2 half-lives (16 days), it will be 128 mg. After 3 half-lives (24 days), it will be 64 mg. Finally, after 4 half-lives (32 days), the amount of Iodine-131 remaining in the sample will be 32 mg.

So, in a 32-day period, a 512 mg sample of Iodine-131 will be reduced to 32 mg.

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Related Questions

3. A block falls from a table 0.6 m high. It lands on a vertical spring which has a spring constant of k= 2400 N/m.
The spring is initially 25 cm high, but it is compressed to a height of 10 cm when it stops the block. Find the mass of
the block.

Answers

SOLUTION :-PLEASE CHECK THE ATTACHED FILE
3. A block falls from a table 0.6 m high. It lands on a vertical spring which has a spring constant of

a tank, shaped like a cone has height meter and base radius meter. it is placed so that the circular part is upward. it is full of water, and we have to pump it all out by a pipe that is always leveled at the surface of the water. assume that a cubic meter of water weighs , i.e. the density of water is . how much work does it require to pump all water out of the tank? enter the exact value of your answer.

Answers

The work required to pump all the water out of the tank is \((1000/3)\pi g\) J.

The volume of a cone can be calculated using the formula:

\(V = (1/3)\pi r^2h\)

where r is the base radius, h is the height, and π is the mathematical constant pi.

Assuming the base radius of the cone is 1 meter and the height is 1 m.

In this case, the tank is full of water, so its volume is:

\(V = (1/3)\pi (1^2)(1) = (1/3)\pi\)

The mass of the water in the tank is its volume times its density:

\(m = V\rho = (1/3)\pi (1000) = (1000/3)\pi\)

To pump out the water, we need to lift it to the top of the tank, which has a height of 2 meters. So the work required is:

\(W = mgh = (1000/3)\pi g\ J\)

Where g is the acceleration due to gravity.

Therefore, it requires approximately \((1000/3)\pi g\) Joules of work to pump all the water out of the tank.

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The drawings show the mass and weight of four objects on different planets:

(see the picture)

(a)
On which of the four planets is the object with the largest mass?​

Answers

The object with the highest mass is the one on planet D. This is because mass is a measure of the amount of matter an object contains, and is not affected by gravity. Therefore, although the weight of the object on planet D is lower than that of the other planets, its mass remains the same.

Weight, on the other hand, is a measure of the gravitational force acting on an object. Therefore, the weight of an object will vary on different planets due to different gravitational forces. As shown in the drawings, the object on planet A has the greatest weight, but nevertheless the greatest mass.

In summary, the object with the greatest mass is on planet D, while the object with the greatest weight is on planet A.

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L 6.3.2 Test (CST): Applications of Waves Question 5 of 10 Which event provides evidence that matter can reflect waves? O A. An audience member covers her ears during a loud concert. B. A laser beam bounces off a series of mirrors. C. A performer makes shadow puppets on a wall. D. The light from a fireworks show is seen miles away. ​

Answers

An audience member covers her ears during a loud concert shows evidence that matter can reflect waves.

Which event provides evidence that matter can reflect waves?

An audience member covers her ears during a loud concert is an event that provides evidence that matter can reflect waves because a sound is heard again and again due to the reflection of waves. This repetition of sound is due to the property of reflection of sound waves.

So we can conclude that an audience member covers her ears during a loud concert shows evidence that matter can reflect waves.

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Answer:

A laser beam bounces off a series of mirrors

Explanation:

L 6.3.2 Test (CST): Applications of Waves Question 5 of 10 Which event provides evidence that matter

A 43-kg child sits in a massless swing. With what horizontal force must the seat be pulled so that the ropes form an angle of 35o with respect to the vertical? Group of answer choices 300 N 320 N 340 N 360 N

Answers

The horizontal force that the seat must be pulled so that the ropes form an angle of 35o with respect to the vertical is 345.2 N.

Horizontal force to be applied

The horizontal force that the seat must be pulled so that the ropes form an angle of 35o with respect to the vertical is calculated as;

F = Wcosθ

where;

W is weight of the childθ is angle of inclination of the rope

F = (43 x 9.8) x cos(35)

F = 345.2 N

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If the output work is 500 J and the input work is 380 J, what is the machine efficiency?

Answers

Answer:

Therefore machine efficiency is 131.6%.

Explanation:

Data

work output = 500J

work input = 380J

M.E = ?

M.E = work output/work input × 100%

M.E = 500J/380J × 100%

M.E = 131.6%

Therefore machine efficiency is 131.6%.

Please select the best answer from the choices provided


A
B
C
D

Please select the best answer from the choices providedABCD

Answers

D hi hi hi hi hi hi g u hudiikekoow the answer is D

Answer:

D hope this helps plz mark brainliest

Explanation:

Draw The Vector C⃗ =A⃗ +B⃗ Draw The Vector D⃗ =A⃗ −B⃗

Answers

To draw vectors C⃗ = A⃗ + B⃗ and D⃗ = A⃗ − B⃗, plot vector A⃗ starting from the origin, then add B⃗ to its terminal point for C⃗ and subtract B⃗ from A⃗ for D⃗.

1. Begin by drawing a coordinate system or grid on a piece of paper or a graphing software.

2. Identify the initial point for vector A⃗. Let's assume it starts at the origin (0, 0).

3. Determine the magnitude and direction of vector A⃗. Suppose A⃗ has a magnitude of 4 units and a direction of 30 degrees above the positive x-axis.

4. From the initial point of A⃗, draw an arrow that represents vector A⃗ with the determined magnitude and direction.

5. Repeat steps 2-4 for vector B⃗. Suppose B⃗ starts at the origin (0, 0), has a magnitude of 3 units, and is directed 45 degrees below the positive x-axis.

6. Draw vector B⃗ from its initial point with the appropriate magnitude and direction.

7. To find vector C⃗, add vectors A⃗ and B⃗ algebraically. Place the initial point of vector B⃗ at the terminal point of vector A⃗, and draw an arrow from the initial point of A⃗ to the terminal point of B⃗. This represents vector C⃗.

8. To find vector D⃗, subtract vector B⃗ from vector A⃗. Place the initial point of vector B⃗ at the terminal point of vector A⃗, and draw an arrow from the initial point of A⃗ to the terminal point of B⃗. This represents vector D⃗.

By following these steps, you will have accurately drawn vectors C⃗ = A⃗ + B⃗ and D⃗ = A⃗ − B⃗. Remember to label the vectors appropriately for clarity.

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Solids in which the atoms have no particular order or pattern are called

Answers

Answer:

Amorphous solids are composed of atoms or molecules that are in no particular order. Each particle is in a particular spot, but the particles are in no organized pattern. Examples include rubber and wax. Crystalline solids have a very orderly, three-dimensional arrangement of atoms or molecules

Explanation:

The index of refraction of crown glass is 1.515 for red light and 1.523 for blue light. Find the angle separating rays of the two colors in a piece of crown glass if their angle of incidence is 42o .

Answers

Given:

The angle of incidence is,

\(i=42\degree\)

The refractive index of the crown glass for red light is,

\(n_r=1.515\)

The refractive index of the crown glass for blue light is,

\(n_b=1.523\)

To find:

The angle separating rays of the two colours in a piece of crown glass

Explanation:

We know, Snell's law,

\(n_1sini=n_2sinr\)

For, the red light,

\(\begin{gathered} 1\times sin42\degree=1.515sinr_r \\ sinr_r=\frac{sin42\degree}{1.515} \\ r_r=sin^{-1}(0.4417) \\ r_r=26.2\degree \end{gathered}\)

For, the blue light,

\(\begin{gathered} 1\times sin42\degree=1.523sinr_b \\ r_b=sin^{-1}\frac{sin42\degree}{1.523} \\ r_b=26.1\degree \end{gathered}\)

The separation between the refracted rays is,

\(\begin{gathered} r_r-r_b=26.2\degree-26.1\degree \\ =0.1\degree \end{gathered}\)

Hence, the required separation is 0.1 degrees.

suppose that 18 j of work is needed to stretch a spring from its natural length of 6 m to a length of 9 m. (a) how much work is needed to stretch the spring from 12 m to 14 m?

Answers

The work which is needed to stretch the spring from 12 m to 14 m is 56J if 18 j of work is needed to stretch a spring from its natural length of 6 m to a length of 9 m.

Given the amount of work done (W) = 18J

The initial length of spring (L1) = 6m

The length of spring after stretching (L2) = 9m

The elongation of spring (x) = L2 - L1 = 9 - 6 = 3m

We know that work done on a spring is equal to force multiplied by the spring elongation such that W = Fx where F = 1/2kx ; k is spring constant

18 = 1/2 * k * x^2

k = 36/9 = 4

Given the original length of spring = 12m

The length of spring after stretching = 14m

stretching length from 6m to 12m is 6m

stretching length from 6m to 14m is 8m

The elongation in spring = (x')

Work done on the spring = 1/2k(x')^2 = 1/2 * 4 * (8^2 - 6^2) = 56J

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A battery has an emf of 12 V and internal resistance of 0.050 ohms. Its terminals are connected to a load resistance of 3 Ohms. Hence the terminal voltage of the battery is about 11.8 V

Answers

Reconstruction was a success in that it restored the United States as a unified nation: by 1877, all of the former Confederate states had drafted new Reconstruction also finally constitutions, acknowledged the Thirteenth, Fourteenth, and Fifteenth their loyalty to the U.S. government. settled the states’ rights vs. federalism debate that had Amendments, and pledged been an issue since the 1790s.

Reconstruction failed by most other measures: Radical Republican legislation ultimately failed to protect federalism former slaves from white persecution and failed to engender fundamental changes to the social fabric of the South. When President Rutherford B. federalism debate that had been an issue since the 1790s almost mediately . Hayes removed federal troops from the South in 1877, former Confederate officials and slave returned to With the support of a conservative Supreme Court, these newly empowered white southern politicians passed black codes, voter qualifications, and other anti-progressive legislation to reverse the rights that blacks had gained during Radical Reconstruction. The U.S. Supreme Court bolstered this anti-progressive movement federalism  with decisions in the Slaughterhouse Cases, the Civil Rights Cases, and United States v.

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Please help, 9th grade science .. will mark brainliest

Please help, 9th grade science .. will mark brainliest

Answers

Answer:

the answer for this is Letter B


6) Explain in detail about Electromagnetic waves and its
importance (20 Marks)

Answers

Electromagnetic waves are essential for communication, medical imaging, energy generation, scientific research, and various industrial applications.

Electromagnetic waves are a fundamental concept in physics and have significant importance in various aspects of our lives. These waves are characterized by their ability to propagate through vacuum or a medium and carry energy through oscillating electric and magnetic fields.

One of the key importance of electromagnetic waves is in communication. Radio waves enable wireless communication, allowing us to transmit information over long distances. Microwaves are used for satellite communication, radar systems, and even cooking in household appliances. Visible light enables us to see and is utilized in fiber optic communication systems.

In the field of medicine, electromagnetic waves play a vital role. X-rays are used for medical imaging, providing detailed images of internal structures. Magnetic resonance imaging (MRI) utilizes magnetic fields and radio waves to diagnose and monitor various medical conditions.

Furthermore, electromagnetic waves have applications in energy generation, scientific research, remote sensing, and industrial processes. Solar panels harness the energy of electromagnetic waves, providing a renewable source of electricity. Scientists use electromagnetic waves in spectroscopy to study the composition of materials. Remote sensing techniques utilize different frequencies to gather information about the Earth's surface, atmosphere, and oceans.

Overall, electromagnetic waves are of paramount importance in modern technology, communication, medical diagnostics, energy generation, scientific exploration, and numerous other fields, shaping our daily lives and expanding our understanding of the universe.

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A baseball is thrown upward at 20m/s. At what time is the ball 10m above the point at which it was released?​

Answers

Answer:

0.583 seconds

Explanation:

We are dealing with free-fall motion, which has a constant acceleration of -g, acceleration due to gravity, so we can use a constant acceleration equation to solve this problem.

List out known variables and the variable that we want to solve for:

v_0 = 20 m/sa = -9.8 m/s² Δx = 10 mt = ?

Find the kinematic equation that contains all four of these variables:

Δx = v_0 t + 1/2at²

Plug known values into the equation.

10 = 20 t + 1/2(-9.8)t²

Distribute 1/2 inside the parentheses.

10 = 20t - 4.9t²

Set the equation equal to 0 and rearrange the terms so they are in descending degree order.

0 = -4.9t² + 20t - 10  

Factor this equation by using the quadratic formula. You should get:

t = 3.498 s, t = 0.583 s

Let's look at these numbers within the context of the problem. If the ball's speed is 20 m/s, then after 1 second, it would reach a height of 20 m.

However, we want to find the time that it would take the ball to reach a height of 10 m, which is half of 20 m. Therefore, the time to reach 10 m should be around 0.5 seconds.

t = 0.583 is the closest to 0.5 seconds, and it fits within the context of the problem. Therefore, the answer is 0.583 seconds.

What kind of charge does each object have?

A. Both are negatively charged.
B. Both are positively charged.
C. A is positively charged, and B is negatively charged.
D. A is negatively charged, and B is positively charged.

What kind of charge does each object have?A. Both are negatively charged.B. Both are positively charged.C.

Answers

Answer: The answer is D.

Explanation:

The way A is shooting arrows away means its a negative current. On the other hand B is taking them in making B positive. and that's why the answer is D.

Which of the following is an exact measurement
A.12 apples
B.1.2 kg apples
C.1.255 kg apples
D.1.25 kg apples

Answers

The exact measurement is 1.2kg apples it’s B

The correct answer is option A: 12 apples. Counting things is an accurate method of measuring that eliminates the possibility of error or uncertainty.

Uncertainty and error are absent from a perfect measurement. Let's examine each option to see which is accurate:

A. 12 apples: Counting things is a precise measurement, hence Option A is a count. This value is unambiguous if you have exactly 12 apples. As a full number, it is precise.

B. 1.2 kg apples: Option B is a kilogramme measurement of apples. Weight measurements are usually estimated due to the sensitivity of weighing machines, even when the figure appears to be precise to one decimal point (1.2 kg). Therefore, 1.2 kg is not precise.

C. 1.255 kg apples: Option C also weighs apples in kilogrammes. This figure is presented to three decimal places (1.255 kg), making it even more precise than the previous choice. Weight measurements are imprecise due to measuring instrument constraints, as discussed before. Thus, 1.255 kg is not precise.

D. 1.25 kg apples: Option D is a kilogramme measurement of apples. 1.25 kg is the value. Its weight measurement is more precise than option B, although it still has considerable uncertainty. 1.25 kg is not a precise measurement.

In conclusion, only choice represents a precise measurement: 12 apples Weight measurements, which are not perfect, are used in B, C, and D. Counting 12 apples is an exact value with no uncertainty.

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1. João tem um tempo de reação de 0,2 s, pedala a bicicleta com velocidade de 5 m/s. Ele se depara com uma situação de emergência e aciona os freios. Qual foi a distância percorrida antes de frear? Tempo = 0,2s Velocidade = 5m/s = ou = ⋅

Answers

Responda:

1 metro

Explicação:

Dado que :

Tempo de reação = 0,2 segundos

Velocidade de deslocamento = 5 m / s

A distância percorrida antes da frenagem pode ser obtida usando a relação:

Distância = velocidade de viagem * tempo de reação

Distância percorrida antes da frenagem = (5 m / s) * (0,2s)

Distância percorrida antes da frenagem = 1 metro

the power in an electrical circuit is given by the equation p=/2 R, where /is the current flowing through the circuit and R is the resistance of the circuit. what is the power in a circuit that has a current of 12


A. 120 watts
B. 8.3 watts
C.144 watts
D. 14,400 watts

Answers

Complete Question:

What is the power in a circuit that has a current of 12 amps and a resistance of 100 ohms?

Answer:

D. 14,400 watts

Explanation:

The electrical power of an electric circuit can be defined as a measure of the rate at which energy is either produced or absorbed in the circuit.

Mathematically, electrical power is given by the formula;

\( Electrical \; power = current * voltage \)

This ultimately implies that, the quantity (current times voltage ) is electrical power and it is measured (S.I units) in Watt (W).

Given the following data;

Current = 12 AmperesResistance = 100 Ohms

To find the power in the circuit, we would use the following formula;

Power = I²R

Where;

I is current measured in Amperes.R is resistance measured in Ohms.

Power = 12² * 100

Power = 144 * 100

Power = 144,000 Watts

What is it called when a sound wave transfers its energy to a new medium?
a. Reflection
b. Transmission
c. Echo
d. Absorption

Answers

Answer:

c. eco

ya que hay trasmisión de energía de un lado al hacer ecos

a hockey puck is accelerated using a hockey stick over a smooth level ice surface the puck has a mass of 0.400kg and is moved by the stick for a distance of 0.800m what was the average forcr applied to the puck if the final speed is 25.0m/s

Answers

The average force applied to the puck of mass 0.4 kg is 156.25 N.

What is force?

Force is the product of mass and acceleration.

To calculate the average force applied to the puck, we use the formula below.

Formula:

F = mv²/2s.............................. Equation 1

Where:

F = Average forcem = Mass of the puck = 0.4 kgv = Final speed = 25 m/ss = Distance = 0.8 m

Substitute these values into equation 1

F = (0.4×25²)/(2×0.8)F = 156.25 N

Hence, the average force applied is 156.25 N.

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1. Supposing that the egg was dropped from the top of the stairs without the apparatus, calculate
what the velocity of the egg would be as it landed. What is its momentum? The height of the drop is
4.5m, and the mass of the egg is 50 g. I

Answers

Explanation:

The amount of POTENTIAL energy (mgh)  is converted entirely to KINETIC energy ( 1/2 mv^2)   at instant before impact

mgh   = 1/2 mv^2

gh = 1/2 v^2

2 gh = v^2

v = sqrt ( 2 g h) = sqrt (  2 * 9.81 * 4.5) = 9.4 m/s

Momentum = m * v  =  .05 kg * 9.4 m/s  = .47  kg m/s

find the gravitational potential energy of a 1 kg book, resting 1 meter above the ground on a bookshelf.

Answers

Answer:

The gravitational potential energy of a 1 kg book, resting 1 meter above the ground on a bookshelf is 9.8 J.

What is potential energy?

Potential energy of body is the energy generated by virtue of the position of the body. Whereas kinetic energy is generated by virtue of its movement.

Potential energy and kinetic energy together called as mechanical energy. The potential energy p is mathematically expressed as p = mgh. Where g s gravity, h is height and m is the mass.

Gravitational potential energy is mass times distance times the acceleration of gravity. In simple terms it is

\($$m^* g * h$$\)

or

mgh

When \($m=1$\)

\($$\begin{aligned}& h=1 \\& g=9.8\end{aligned}$$\)

The gravitational potential energy is \($9.8 \mathrm{~J}$\).

\($J=$ joules (unit of energy)\)

How do you calculate gravitational potential energy per kilogram?

For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters. Notice that gravitational potential energy has the same units as kinetic energy, kg m2 / s2.

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which state of matter has the greatest amount of kinetic energy?

Answers

Answer:

A pure substance in the gaseous state contains more energy than in the liquid state, which in turn contains more energy than in the solid state. Particles has the highest kinetic energy when they are in the gaseous state.

Explanation:

Sana makatulong.


Help asap! Pleas answer all
questions, will like immediately.
4) What does the load line represent for a Thévenin equivalent? 5) What is represented by the Thévenin equivalent of a resistive circuit?

Answers

4) The load line represents a Thevenin equivalent by determining the possible combinations of voltage and current 5) Thevenin's theorem states that a complex linear circuit can be replaced by a single voltage source and series resistance, called the Thévenin equivalent circuit.

The load line is a straight line on the characteristics chart of an electrical circuit which represents all the possible voltage-current combinations of a load connected to the output terminals of the circuit. The load line represents a Thevenin equivalent by determining the possible combinations of voltage and current that can be drawn from the Thevenin equivalent circuit for a given value of the load resistance.

Thevenin's theorem states that a complex linear circuit can be replaced by a single voltage source and series resistance, called the Thévenin equivalent circuit. The Thévenin equivalent circuit represents an electric circuit's overall electrical characteristics between two terminals. It is possible to calculate the voltage and current in any circuit element using the Thevenin equivalent circuit.

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Marion is on a train that travels 10 m/s and takes 2 seconds to slow to 5 m/s. How would you correctly calculate the acceleration?

Answers

Explanation:

t=2s

u=10

v=5

a=?

v=u+at

5=10+2a

2a=-5

a=-2.5

pls include a explanation!!!:)<3

pls include a explanation!!!:)&lt;3

Answers

Answer:

Option C. 4.5×10¯² N

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +5×10¯⁶ C

Charge 2 (q₂) = –4×10¯⁶ C

Distance apart (r) = 2 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

The magnitude of the force can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × 5×10¯⁶ × 4×10¯⁶ / 2²

F = 0.18 / 4

F = 0.045

F = 4.5×10¯² N

Thus, magnitude of the force is 4.5×10¯² N

Select the correct definitions of active galactic nuclei and quasars. Active galactic nuclei are centers of the galaxies which are unusually bright, with luminosity produced by sources other than stars. Quasars are the brightest of them and have luminosities of hundreds times greater than our galaxy has.

Answers

Both definitions accurately describe active galactic nuclei and quasars, emphasizing their bright nature and non-stellar sources of luminosity. Quasars are indeed the brightest class of active galactic nuclei.

Active galactic nuclei (AGN) are centers of galaxies that exhibit unusually high luminosity, which is generated by sources other than stars. They are characterized by the presence of accretion disks around supermassive black holes, emitting large amounts of energy across various wavelengths.

Quasars are a type of active galactic nuclei and represent the most luminous objects in the universe. They are characterized by their extremely high luminosities, often hundreds of times greater than that of an entire galaxy. Quasars are thought to be powered by the accretion of mass onto supermassive black holes in the centers of galaxies, emitting tremendous amounts of energy, including intense radiation across the electromagnetic spectrum.

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A = (1 point) A particle is moving with acceleration a(t) = 6t + 8. its position at time t = O is s(0) = 6 and its velocity at time t = 0 is v(O) = 2. What is its position at time t = 7? =

Answers

Answer:

\(559\).

Explanation:

Integrate \(a(t)\) with respect to time \(t\) to find an expression for velocity:

\(\begin{aligned} v(t) &= \int a(t)\, d t \\ &= \int (6\, t + 8)\, d t && (\text{power rule}) \\ &= 3\, t^{2} + 8\, t + C_{v} \end{aligned}\).

Note that since this integral is indefinite, the expression for \(v(t)\) includes a constant \(C_{v}\).

Find the value of \(C_{v}\) using the fact that \(v(0) = 2\). Specifically, substitute \(t = 0\) into the expression \(v(t) = 3\, t^{2} + 8\, t + C_{v}\) and solve for \(C_{v}\!\):

\(v(0) = 3\, (0)^{2} + 8\, (0) + C_{v} = C_{v}\).

\(v(0) = 2\).

\(C_{v} = 2\).

In other words, \(v(t) = 3\, t^{2} + 8\, t + 2\).

Similarly, integrate \(v(t)\) with respect to \(t\) to find an expression for position:

\(\begin{aligned} s(t) &= \int v(t)\, d t \\ &= \int (3\, t^{2} + 8\, t + 2)\, d t\\ &= t^{3} + 4\, t^{2} + 2\, t + C_{s} \end{aligned}\).

Similarly, find the value of constant \(C_{s}\) using the fact that \(s(0) = 6\):

\(s(0) = (0)^{3} + 4\, (0)^{2} + 2\, (0) + C_{s} = C_{s}\).

\(s(0) = 6\).

\(C_{s} = 6\).

In other words, \(s(t) = t^{3} + 4\, t^{2} + 2\, t + 6\). Substitute in \(t = 7\) and evaluate to find the position of the particle at that moment:

\(s(7) = 7^{3} + 4\, (7)^{2} + 2\, (7) + 6 = 559\).

The pοsitiοn of the particle at time t = 7 is 559 units.

How tο find the pοsitiοn at time?

Tο find the pοsitiοn at time t = 7, we need tο integrate the given acceleratiοn functiοn tο οbtain the velοcity functiοn and then integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn.

Given:

Acceleratiοn functiοn: a(t) = 6t + 8

Initial pοsitiοn: s(0) = 6

Initial velοcity: v(0) = 2

First, let's integrate the acceleratiοn functiοn tο οbtain the velοcity functiοn:

v(t) = ∫(a(t)) dt

= ∫(6t + 8) dt

= 3t^2 + 8t + C

Tο find the cοnstant οf integratiοn (C), we can use the initial velοcity v(0) = 2:

2 = 3(0)² + 8(0) + C

C = 2

Sο, the velοcity functiοn becοmes:

v(t) = 3t² + 8t + 2

Next, let's integrate the velοcity functiοn tο οbtain the pοsitiοn functiοn:

s(t) = ∫(v(t)) dt

= ∫(3t² + 8t + 2) dt

= t³ + 4t² + 2t + C'

Tο find the cοnstant οf integratiοn (C'), we can use the initial pοsitiοn s(0) = 6:

6 = (0)³ + 4(0)² + 2(0) + C'

C' = 6

Sο, the pοsitiοn functiοn becοmes:

s(t) = t³ + 4t² + 2t + 6

Finally, we can find the pοsitiοn at time t = 7:

s(7) = (7)³+ 4(7)² + 2(7) + 6

= 343 + 196 + 14 + 6

= 559

Therefοre, the pοsitiοn at time t = 7 is 559 units.

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5. Whether you are standing, running or jumping Earth is exerting a gravitational force on you. This gravitational force is called an object's weight (W). Knowing this you can find the weight of an object if you know the mass because the acceleration will be 9.8 m/s2 due to gravities pull on the object. The equation to use then is: W = mass x acceleration. What is the weight of a 53 kg man?​

Answers

Answer:

How we know, the equation is:

W = mg

Replacing according our data:

W = 53 kg × 9,8 m/s^2

Resolving:

W = 519,4 N

The weight of the object is of 519,4 Newtons.

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