In which type of collision is no kinetic energy converted to heat or sound
energy?

Answers

Answer 1

Answer:

elastic collision

An elastic collision occurs when the two objects "bounce" apart when they collide. Two rubber balls are a good example. In an elastic collision, both momentum and kinetic energy are conserved. Almost no energy is lost to sound, heat, or deformation.

I hope it's helpful!


Related Questions

28g of copper pellets are removed from a 300∘C oven and immediately dropped into 90 mL of water at 25∘C in an insulated cup.

Answers

The final temperature of the water and copper pellets is 43.8°C.

We can use the equation:

\(mc\Delta T = mwCw\Delta T\)

Substituting the values given in the problem:

m c = 28 g

m w = 90 mL = 90 g

c = 0.385 J/g°C

Cw = 4.18 J/g°C

ΔT = T f - 25°C

where T f is the final temperature of the water and copper pellets.

Simplifying the equation:

28 g x 0.385 J/g°C x (T f - 300°C) = 90 g x 4.18 J/g°C x (T f - 25°C)

Solving for T f:

T f = (90 g x 4.18 J/g°C x 25°C + 28 g x 0.385 J/g°C x 300°C) / (90 g x 4.18 J/g°C + 28 g x 0.385 J/g°C)

T f = 43.8°C

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--The complete Question is, What are the final temperature of the water and the copper pellets after thermal equilibrium is reached, assuming no heat is lost to the surroundings?  --

A. Organized process to test a hypothesis
B. An educated guess about the solution to a problem
C. Observations & measurements recorded
D. A summary based on the results of an experiment
E. The response that is measured in an experiment
F. The factor that is manipulated during an experiment

Answers

The scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable.

What is an observation in science?

Observation is the first step of the scientific method, which then requires to raise a question that will be answered by a testable hypothesis.

The scientific method is a series of well-established steps used to collect scientific empirical data/evidence, which allow to test a given hypothesis.

In conclusion, the scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable..

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asap hurry

Part 1

1. Using a graduated cylinder, measure 70 mLof water. Pour this water into a small, empty glass

jar. Dry the graduated cylinder.

2. Remember the old saying: “Do like you ‘oughter’—add the acid to the water.” This means to

add acid to water—never the other way around. Do not add water toacid.

3. Make sure you are working in a well-ventilated area, such as next to an open window. Using

extreme caution, and wearing safety goggles or protective eyeware, protective gloves, and

long sleeves and long pants, measure out 30 mL of the muriatic acid into the graduated

cylinder. Slowly pour this acid into the jar of water. (Add the acid carefully, because heat will be

produced when the two substances mix.)

4. Screw the lid onto the jar and gently swirl the jar to mix the contents fully.

5. Remove the lid and place the galvanized nail into the jar.

6. Loosely cover the jar with the lid (do not screw it on).

7. Allow the reaction in the jar to continue for 20 seconds, recording observations during this

time.

8. Light the wooden splint (toothpick) with the candle and prepare to test for the gas.

Testing and Producing Gases

9. Very carefully, remove the lid from the jar and bring the burning splint to the mouth of the jar.

10. Be prepared for a reaction. Record your observations.

11. Place the lid back on the jar and allow more gas to accumulate.

12. Complete Steps 7, 8, and 9 again to repeat this trial. After your second trial, rinse and dry the

graduated cylinder to prepare for Part 2.


Part 2

13. Measure 50 mL of hydrogen peroxide using the graduated cylinder. Pour thehydrogen

peroxide into the second jar.

14. Add approximately 1 teaspoon of yeast to the hydrogen peroxide. Loosely cover the jar with

the lid (do not screw it on). Record your observations.

15. Light the wooden splint (toothpick) with the candle and allow the toothpick to burn for a few

seconds.

16. Extinguish the flame by blowing on it so that the wood is just glowing.

17. Remove the lid on the jar and hold the glowing splint to the mouth of the jar. Record your

observations.

18. Place the lid back on the jar and allow more gas to accumulate.

19. Repeat Steps 14 and 15 to complete a second trial

2 of 5

Science | Testing and Producing Gases

Name Date


• Dispose of nail by taking it out of the acid solution (with gloves on), wrapping it in a paper

towel, and putting it into the trash.

• Dispose of liquid substances by pouring them down a drain. Run plenty of cold water while you

pour these substances down the drain and for several minutes afterward.

• Do not breathe in fumes. Make sure the area you are working in is wellventilated.

• Be sure toothpicks are completely extinguished in water before disposing of them.

Data and Observations

Observations for Part 1

Trial 1:

Trial 2:

Observations for Part 2

Trial 1:

Trial 2:

3 of 5

Science | Testing and Producing Gases



1. Do you think a chemical reaction took place in Part 1 when you added the galvanized nail to

the acid and water, and in Part 2 when the yeast was added to the hydrogen peroxide? Explain

your answer. (3 points)

2. Did the same result occur in both parts when you held up a lighted splint to the jar’s mouth?

What can you conclude from this about the identity of the gas(es) in Parts 1 and 2? (3

points)

3. In both parts of the activity, you conducted a second trial without having to remix the

chemicals. How was this possible? (3 points)

4. In 1937, a large passenger airship called the Hindenburg mysteriously caught fire. Because

the airship was filled with hydrogen gas, it immediately exploded once the fire reached the gas.

Given this information, do you think one of the reactions above may have produced hydrogen?

Use your data to explain your answer. (3 points)

4 of 5

Science | Testing and Producing Gases

Answers

Answer:

Yes, a chemical reaction took place in Part 1 when the galvanized nail was added to the acid and water, and in Part 2 when the yeast was added to the hydrogen peroxide. This is evidenced by the observations recorded in the trials, such as the production of bubbles and the release of gas.Yes, the same result occurred in both parts when a lighted splint was held up to the jar's mouth. This indicates that the gas produced in both parts was flammable and therefore likely to be hydrogen.In both parts of the activity, a second trial was conducted without having to remix the chemicals because the reactions continued to produce gas even after the first trial, allowing for further testing.Yes, one of the reactions above may have produced hydrogen. Part 2 specifically involved the addition of yeast to hydrogen peroxide, which likely produced oxygen gas and water as byproducts. This means that the gas produced in Part 2 was likely hydrogen gas, as hydrogen peroxide is composed of hydrogen and oxygen. The flammability of the gas produced in both parts also supports the possibility that it was hydrogen.

Explanation:

Sorry if I made some mistakes, I completed it as fast as I could.

What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m

Answers

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is applied in the same direction to each steering wheel. What is the ratio of the torque produced by this force in the truck to the torque produced in the car

Answers

Answer:

\(\frac{T_t}{T_c} = 1.32\)

Explanation:

The torque applied on an object can be calculated by the following formula:

\(T = Fr\)

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

\(T_c = Fr_c\\\)

For truck wheel:

\(T_t = Fr_t\)

Dividing both:

\(\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}\)

for the same force applied on both wheels:

\(\frac{T_t}{T_c} = \frac{r_t}{r_c} \\\)

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

\(\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\\)

\(\frac{T_t}{T_c} = 1.32\)

Suppose that a car is initially moving at a speed of 100 m / s to the right. Take right a positive. The driver hits the brakes, and the car comes to a stop in a time of 20 s. What is the acceleration of the car?

Answers

The required acceleration of the car, when the driver hits the brake, is \(-5 m/s^2\), the negative sign indicates that the car is slowing down.

From the question we can see that the:

initial velocity(u) is + 100 m/s (to the right)

Final velocity (v) is 0 since the car comes to stop

Time (t) is 20 s

We can use the formula

a= (v-u)/t to find the acceleration(a) of the car.

Now Substituting the values in the formula given above we get:

a=(0-100)/20

a= \(-5m/s^2\)

Therefore, the acceleration of the car is \(-5 m/s^2\). The negative sign in the answer indicates that the acceleration is in the opposite direction to the initial velocity, which means that the car is slowing down or decelerating.

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How does energy change from kinetic to potential?

Answers

Answer:

A: An object has potential energy (stored energy) when it is not in motion. Once a force has been applied or it begins to move the potential energy changes to kinetic energy (energy of motion).

Explanation:

In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

Look at this model of an atom. Where are the protons located and how many are there?

Look at this model of an atom. Where are the protons located and how many are there?

Answers

Protons are in the nucleus

There are 6 protons

Answer:

protons are in the nucleus .

Explanation:

there are 6 protons

Point charge 3.0 μC is located at x = 0, y = 0.30 m, point charge -3.0 μC is located at x = 0 y = -0.30 m. What are (a)the magnitude and (b)direction of the total electric force that these charges exert on a third point charge Q = 4.5 μC at x = 0.40 m, y = 0?

Answers

The total electric force that these charges exert on a third point charge is 11.9 N and the direction is towards positive y axis.

Magnitude of the electric force between the charges

The force between the first charge and the third charge is calculated as follows;

F₁₃ = kq₁q₃/r₁₃²

F₁₃ = (9 x 10⁹ x 3 x 10⁻⁶ x 4.5 x 10⁻⁶) / (0.1)²

note: distance between charge 3.0 μC and Q = 4.5 μC  = 0.4 m - 0.3 m = 0.1 m

F₁₃ = 12.15 N

The force between the second charge and the third charge is calculated as follows;

F₂₃ = kq₂q₃/r₂₃²

F₂₃ = (9 x 10⁹ x -3 x 10⁻⁶ x 4.5 x 10⁻⁶) / (0.7)²

note: distance between charge -3.0 μC and Q = 4.5 μC  = 0.4 m - (-0.3 m) = 0.7 m

F₂₃ = -0.248 N

Net force between the charges

F(net) = F₁₃ + F₂₃

F(net) = 12.15 - 0.248

F(net) = 11.9 N

Thus, the total electric force that these charges exert on a third point charge is 11.9 N and the direction is towards positive y axis.

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The Image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic force is the strongest.
N

The Image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic

Answers

Answer:

strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

Explanation:

The lines of magnetic force are drawn so that the density of lines is proportional to the intensity of the magnetic field.

Therefore, the sections where the magnetic field is strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

Can someone please help me with these two they go together to make one question

Can someone please help me with these two they go together to make one question

Answers

1) Since the truck is moving, it has kintic energy. The formula for calculating kinetic energy is expressed as

KE = 1/2mv^2

where

m = mass

v = velocity

From the information given,

m = 60000

v = 27

Thus,

Kinetic energy = 1/2 x 60000 x 27^2 = 21870000 J

The amount of work that must be done to stop the truck must be equal to or greater than the kinetic energy. Thus,

amount of work that must be done to stop the truck = 21870000 J

2) Net force applied = - 300000 N

Recall,

Net Force = mass x acceleration

acceleration = net force/mass

acceleration of the truck = - 300000 /60000 = - 5 m/s^2

Since the acceleration is negative, it is decelerating.

To find the distance before it stops, we would apply one of Newton's formula of motion which is expressed as

v^2 = u^2 + 2as

where

v = final velocity

u = initial velocity

a = acceleration

s = distance

From the information given,

v = 0(becuase it will stop moving)

u = 27

a = - 5

By substituting these values into the formula,

0^2 = 27^2 - 2 x 5 x s

0 = 729 - 10s

10s = 729

s = 729/10

s = 72.9

The truck will move 72.9 meters before stopping

An environmentally conscious physics student 250 N
mows her lawn with a push mower, exerting
a force of 250 N along the handle as shown. 40°
How much force is actually being used to push
the mower along the grou

Answers

The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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An 845–g bar of ice is initially at –25 °C. The latent heat of fusion of ice is 334 kJ/kg, the specific heat of ice is 2050 J/(kg·°C), and the specific heat of water is 4180 J/(kg·°C). Determine how much energy is required if the final temperature of the system is to reach 39 °C.

Answers

Taking into account the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 463.28 kJ.

Calorimetry, sensible heat and latent heat

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

Energy required in this case-25°C to 0 °C

In firts place, the melting point of water (temperature at which it changes state from solid to liquid) is 0°C.

So, first of all you must increase the temperature from -25 ° C (in solid state) to 0 ° C, in order to supply heat without changing state (sensible heat).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

c(ice)= 2050 \(\frac{J}{kgC}\) m= 845 g= 0.845 kgΔT= Tfinal - Tinitial= 0 °C - (-25) °C= 25 °C

Replacing:

Q1= 2050 \(\frac{J}{kgC}\)  × 0.845 kg× 25 °C

Solving:

Q1= 43,306.25 = 43.3 kJ

Change of state

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

n= 0.845 kgΔHfus= 334 \(\frac{kJ}{kg}\)

Replacing:

Q2= 0.845 kg× 334\(\frac{kJ}{kg}\)

Solving:

Q2= 282.23  KJ

0 °C to 39 °C

Similar to sensible heat previously calculated, you know:

c(liquid)= 4180\(\frac{J}{kgC}\)m= 0.845 kgΔT= Tfinal - Tinitial= 39 °C - 0 °C= 39 °C

Replacing:

Q3= 4180 \(\frac{J}{kgC}\) × 0.845 kg× 39 °C

Solving:

Q3= 137,751.9 J= 137.75 kJ

Total heat required

The total heat required is calculated as:  

Total heat required= 43.3 kJ + 282.23 kJ + 137.75 kJ

Total heat required= 463.28 kJ

In summary, the amount of heat required is 463.28 kJ.

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The amount of energy required if the final temperature of the system is to reach 39 °C is 463288.15 J

How to determine the heat required change the temperature from –25 °C to 0 °C Mass  (M) = 845 g = 845 / 1000 = 0.845 KgInitial temperature (T₁) = –25 °C Final temperature (T₂) = 0 °Change in temperature (ΔT) = 0 – (–25) = 25 °C Specific heat capacity (C) = 2050 J/(kg·°C) Heat (Q₁) =?

Q = MCΔT

Q₁ = 0.845 × 2050 × 25

Q₁ = 43306.25 J

How to determine the heat required to melt the ice at 0 °Mass (m) = 0.845 KgLatent heat of fusion (L) = 334 KJ/Kg = 334 × 1000 = 334000 J/KgHeat (Q₂) =?

Q = mL

Q₂ = 0.845 × 334000

Q₂ = 282230 J

How to determine the heat required to change the temperature from 0 °C to 39 °C Mass  (M) = 0.845 KgInitial temperature (T₁) = 0 °C Final temperature (T₂) = 39 °Change in temperature (ΔT) = 39 – 0 = 39 °C Specific heat capacity (C) = 4180 J/(kg·°C)Heat (Q₃) =?

Q = MCΔT

Q₃ = 0.845 × 4180 × 39

Q₃ = 137751.9 J

How to determine the heat required to change the temperature from –25 °C to 39 °CHeat for –25 °C to 0°C (Q₁) = 43306.25 JHeat for melting (Q₂) = 282230 JHeat for 0 °C to 39 °C (Q₃) = 137751.9 JHeat for –25 °C to 39 °C (Qₜ) =?

Qₜ = Q₁ + Q₂ + Q₃

Qₜ = 43306.25 + 282230 + 137751.9

Qₜ = 463288.15 J

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I need this TODAY!!!
Calcium oxide and carbon dioxide combine to form calcium carbonate in the reversible reaction:

CaO + CO2 ⇌ CaCO3

When the reaction is at dynamic equilibrium, which statement must be true?
The reaction has run out of carbon dioxide or calcium oxide.

Calcium carbonate and calcium oxide are formed at the same rate.

The concentration of calcium carbonate is increasing.

The forward and reverse reactions have stopped.
DUB THY BRAINLIEST IF YOU CAN ANSWER IT

Answers

The statement that is true is that Calcium carbonate and calcium oxide are formed at the same rate.

What is a reversible reaction?

We say that a reversible reaction is taking place when the reaction could either move in the forward or in the reverse directions. Now we know that if a reaction is reversible, a time would come when the concentration of the reactants would be equal to the concentration of the products in the system.

This essentially implies that the products are formed just at the same rate as the products are decomposing the reform the reactants. We often show that a reaction is a reversible reaction by the use of double arrow as we have done in the reaction that is in the question above.

Thus at the point of dynamic equilibrium, we have just as much of the reactants as we have the products that are in the system.

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Matter can undergo chemical reactions which feature of the components only stays the same in chemical reactions

Answers

In chemical reactions, the total mass of the components remains the same.

Chemical reactions involve the transformation of substances into new substances with different chemical properties. During these reactions, various changes occur, such as the rearrangement of atoms, the breaking and forming of chemical bonds, and the conversion of reactants into products. However, one fundamental principle that remains constant is the law of conservation of mass.

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. This means that the total mass of the reactants must be equal to the total mass of the products. No matter can be lost or gained during the reaction; it simply undergoes a rearrangement at the atomic or molecular level.

This principle holds true regardless of the complexity of the chemical reaction. Whether it involves simple reactions between two elements or complex reactions with multiple reactants and products, the total mass before and after the reaction remains constant.

This concept is vital in understanding stoichiometry, which is the quantitative relationship between reactants and products in a chemical reaction. By balancing chemical equations and applying the law of conservation of mass, scientists can determine the relative amounts of substances involved in a reaction.

Overall, while the physical and chemical properties of substances may change during a chemical reaction, the total mass of the components involved in the reaction remains constant.

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According to Howard Gardner's theories, who among the following would need to have good linguistic intelligence to be successful?

Answers

A psychologist will need to have good linguistic intelligence in other to be successful.

Who is a Psychologist?

This is referred to as a professional who specializes in the handling of mental health challenges in individuals.

It is best for such professional to have a good linguistic intelligence as the right words being said to the patient will solve the problem thereby bringing in more success.

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How do motion and Newton's laws apply to your everyday life? (all of the laws)​

Answers

Answer:

This may help

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

Does anyone understand this?

A cannon is recovered from a shipwreck. Why does the buoyant force on the cannon stay the same as long as it is fully under water? Explain your reasoning. (3 points)

Answers

The buoyant force on the cannon stays the same as long as it is fully under water because the buoyant force is determined by the volume of fluid that the cannon displaces and not by the weight or mass of the cannon itself.

Archimedes' Principle states that the buoyant force on an object in a fluid is equal to the weight of the fluid that the object displaces. This means that as long as the cannon remains fully submerged in the water and does not change its volume, the amount of water it displaces and thus the buoyant force on the cannon will also remain the same.

In other words, the buoyant force is dependent on the fluid's density and the volume of the object, not its weight. So, as long as the volume of the cannon and the density of the fluid surrounding it remain constant, the buoyant force will also stay constant.

The buoyant force on the cannon will stay the same as long as it is fully under water.

The buoyant force on an object is equal to the weight of the fluid displaced by the object. The buoyant force is always directed upwards, and it opposes the force of gravity. As long as the cannon is fully under water, the amount of water displaced by the cannon will stay the same. This means that the buoyant force on the cannon will also stay the same.

The buoyant force on an object depends on the density of the fluid, the volume of the object, and the acceleration due to gravity. The density of water is constant, so the buoyant force on the cannon will only change if the volume of the cannon changes or if the acceleration due to gravity changes.

Neither of these factors change. The volume of the cannon does not change as it is being recovered from the shipwreck. The acceleration due to gravity also does not change, as it is the same on Earth's surface as it is underwater.

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What is an ellipse?

a plane that slices between orbits

an oval-shaped orbit

a circular orbit

the center of gravity between orbiting objects​

Answers

Answer:

i think it's C thx correct me if wrong

For every particle there is a corresponding ______________.

Answers

Answer:

Anti-Particle

Determine whether the inertia of an object changes as the object's
velocity changes.

Answers

Answer:

The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.

:

What is Sound? How can you produce a loud sound?​

Answers

Answer:

Sound is a type of energy made by a vibrating object.

Explanation:

You can create sounds by:

- A string plucked with force has greater amplitude

- A vibrating guitar string makes the sound, if you pluck the string harder, it will make a louder sound.

b) A ball is kicked by a footballer. The average force on the ball and the impact last for time interval 0.25 s. Calculate the cha momentum and also state the direction of change in more (Ans: 60 kg m/s) b)​

Answers

60 kg m/s is the answer because you gave it and I thought you are telling ruth also you are a big questioner and also you should check with your doctor and go out and go touch the grass.

What is her velocity?
O 1.5 m/s
O 2 m/s
O 2.5 m/s
O 5 m/s

What is her velocity?O 1.5 m/sO 2 m/sO 2.5 m/sO 5 m/s

Answers

2.5 m/s is the correct answer. Please give brainliest if that helps!

Answer:

C. 2.5

Explanation:

It said it was right, so that's cool.

Lava from a volcano becomes solid as a result of
A. cooling
B. heating.
C. evaporating.
D. condensing.
E. melting.

Answers

Answer:

B. heating.

Explanation:

Answer:

A. Cooling

Explanation:

Because when Lava cools down, it hardens and becomes a solid, and is less hotter.

A graph of the net force on an object is shown as a function of position as the object travels 3 meters. Which of the following conclusions about the object's motion can be drawn from the graph? a. The object’s kinetic energy changes by is 18 J.b. The object’s momentum changes by 18 kg•m/s.c. The acceleration of the object is 4 m/s^2.d. The speed on the object is 4 m/s.e. The power delivered to the object is 4 W.

A graph of the net force on an object is shown as a function of position as the object travels 3 meters.

Answers

We know that in a force-position graph the area under the graph is equal to the work done by the force.

In this case the area under the graph is a triangle with base 3 and height 12, then the work done is:

\(\begin{gathered} W=\frac{1}{2}(3)(12) \\ W=18 \end{gathered}\)

Now, we also know that the work is equal to the change of kinetic energy, that is:

\(\Delta K=W\)

Then:

\(\Delta K=18\)

Therefore, we can conclude from the graph that the object's kinetic energy changes by 18 J and that the asnwer is a.

I need help with part B plsss !!

I need help with part B plsss !!

Answers

The time taken for the object to travel the given height is determined as 12.48 seconds.

What is time of motion?

Time of motion of an object is the total time taken by the object to travel a given height or distance.

Time taken for the boulder to reach the ground

The time of motion of the boulder is calculated as follows;

h = vt + ¹/₂gt²

where;

h is the height of fallv is the initial velocityt is the time of motiong is acceleration due to gravity

1300 = 43t  +  0.5(9.8)t²

1300 = 43t + 4.9t²

4.9t² + 43t - 1300 = 0

solve the quadratic equation using formula method as shown below;

a = 4.9, b = 43, c = -1300

t = 12.48 seconds

Thus, the time taken for the object to travel the given height is determined as 12.48 seconds.

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ball is dropped from a height of 45 m on a floor. If at each collision with the floor the ball loses the nineteen percent of kinetic energy then the speed of the ball just after striking the floor second time, is (g = 10 m s–2)​

Answers

The speed of the ball just after striking the floor a second time, is 30.0 m/s.

Initial height (h) = 45 m

Acceleration due to gravity (g) = 10 m/s²

Energy loss per collision (k) = 19% = 0.19

At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).

When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:

K₁ = PE = mgh

Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:

h = (1/2)gt²

t = sqrt(2h/g)

Using this time, we can calculate the initial kinetic energy (K₁):

K₁ = mgh = m * 10 m/s² * 45 m

Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:

K₂ = K₁ * 0.81

The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):

v₂ = v₁

To find the speed just before the first collision (v₁), we can use the equation of motion:

v = gt

Substituting the time (t) we found earlier, we have:

v₁ = g * sqrt(2h/g)

Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:

v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)

v₂ = v₁

By evaluating the expression, we find:

v₁ ≈ 30.0 m/s

v₂ ≈ 30.0 m/s

Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.

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How far does a roller coaster travel if it accelerates at 2.83 m/s2 from an initial
velocity of 3.19 m/s for 12.0 s?

Answers

Answer:

b

Explanation:

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