In which scenario does Einstein's theory apply, but not Newton's?


comparing the gravitational forces between two systems


measuring how much energy light loses while it travels


calculating the speed of a satellite orbiting Earth


landing a spaceship on the moon

The order of magnitude of the electrical potential generated is 1 (option A).

What is electric potential?

Electric potential, also known as voltage, is a measure of the electric potential energy per unit charge of an electric field at a given point in space. It is a scalar quantity that is expressed in units of volts (V).

The electric potential at a point in space is defined as the amount of work required to move a unit positive charge from infinity to that point, against the electric field. It is also given by the ratio of the potential energy of a charged particle in an electric field to its charge.

The electrical potential generated when work is done on an electron is given by the formula:

ΔV = ΔW/q

where ΔW is the work done on the electron, and q is the charge of the electron.

Substituting the given values, we get:

ΔV = (5000 eV) / (10 × 1.6 × 10^-19 C)

ΔV = 3.125 × 10^16 V

To determine the order of magnitude of this potential, we can round it to the nearest power of 10. In this case, the number is between 10^16 and 10^17, so we can round it to 10^16.

Therefore, the order of magnitude of the electrical potential generated is 1 (option A).

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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Answer:

\(\mu_s=0.51\)

Explanation:

Coefficient of friction

The static coefficient of friction is a measure of the force needed to start moving an object from rest along a rough surface.

It's calculated as:

\(\displaystyle \mu_s=\frac{F_r}{N}\)

Where Fr is the friction force and N is the normal force exerted by the surface over the object.

In the absence of any other vertical force, the normal is equal to the weight of the object:

\(N = W = m.g\)

The box has a mass of m=80 Kg, thus the normal force is:

\(N = 80\ Kg * 9.8\ m/s^2\)

N = 784 N

The student needs to push with a force of 400 N to make the box move. That is the force that barely outcomes the friction force. Thus:

\(F_r=400\ N\)

Calculating the coefficient:

\(\displaystyle \mu_s=\frac{400}{784}\)

\(\mathbf{\mu_s=0.51}\)

Answer:

Cultural anthropology

Explanation:

Answer:

It's B. physical anthropology for I took the quiz and got it correct with this answer.

Explanation:

ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

The final velocity of the red ball is 18 m/s.

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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Pipe of constant radius, we can use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid at two points in a flow system.the pressure of water in the pipe is approximately 105,142 Pa.

System refers to a collection of related components or parts that work together to achieve a specific goal or purpose. The concept of a system can be applied to a wide range of fields and disciplines, including science, engineering, economics, and social sciences.

In science, a system is often defined as a portion of the universe that is being studied or analyzed. This can include anything from a single atom or molecule to an entire ecosystem or planet. By defining the boundaries of a system, scientists can focus their attention on understanding the interactions and relationships between the various components within that system.

In engineering, a system refers to a collection of components that are designed to work together to perform a specific function or task. This can include everything from simple mechanical systems like gears and pulleys to complex electrical or computer systems.

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The stress in Magapascals is 80 Magapascals

This question can be solved by applying Young's modulus.

Young's modulus : Young's modulus states that, stress  is directly proportional to strain.

Where Stress is pressure acting the body. The s.i unit of stress is N/m² or Pascal. And it can be expressed mathematically as,

From the question,

\(P = 10000/(125*10^{-6} )\)

\(P =\) \(8*10^{7}\) Pascals

\(P =\) 80 Magapascals

Hence the stress in Magapascals is 80 Magapascals

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The stress experimented by the tie-bar is 80 megapascals.

The tie-bar is under axial load. Under the assumption that force is distributed uniformly in the cross-section area, we can use the following definition of normal stress (\(\sigma\)), in megapascals:

\(\sigma = \frac{F}{A}\) (1)

Where:

\(F\) - Axial force, in meganewtons.

\(A\) - Cross-section area, in square meters.

If we know that \(F = 10\times 10^{-3}\,MN\) and \(A = 125\times 10^{-6}\,m^{2}\), then the stress experimented by the tie-bar is:

\(\sigma = \frac{10\times 10^{-3}\,MN}{125\times 10^{-6}\,m^{2}}\)

\(\sigma = 80\,MPa\)

The stress experimented by the tie-bar is 80 megapascals.

As there is only one force acting on the ball i.e. gravitational force, the acceleration will be constant and downward. Also because ball moves in the direction of the acceleration, the velocity increases.

Acceleration - constant; velocity - increasing.

What is Acceleration?

Acceleration is the rate of change of velocity of an object over time. It can be positive, negative, or zero. Positive acceleration is when an object speeds up, negative acceleration is when an object slows down, and zero acceleration is when an object's velocity remains constant.

What is velocity?

Velocity is a measure of the speed and direction of an object's motion. It is typically measured in meters per second (m/s) or kilometers per hour (km/h). Velocity can also be expressed in other units, such as miles per hour (mph) or feet per second (ft/s). Velocity is related to a object's acceleration, as an object's acceleration is the rate of change in its velocity over time.

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The answer is e-10³⁰.

Solution:

The expression for find transmission co-efficient is

\(T = e^{-2CL}\)

Substitute values in the above equation

T = e -2(2.5-10³²)(2×10⁻³)

= e -10×10²⁹

≈ e-10³⁰

Magnitude estimation is a psychophysical method by which participants judge the perceived strength of a stimulus and assign a numerical estimate. Magnitude is an exponential change of plus or minus one in the value of a quantity or unit. The term is commonly used in relation to the 10th power scientific notation.

Magnitude is used to make the size of numbers and the scale of things more intuitive and understandable. A rough estimate of size helps the project manager estimate a rough figure for the total cost of the project. The approximate financial impact of future projects. Change the precision as needed.

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Answer:

Explanation:

The magnitude of the force on the box can be found by using the formula

\(f = \frac{w}{d} \\ \)

w is the workdone

d is the distance

From the question we have

\(f = \frac{80}{8} \\ \)

We have the final answer as

Hope this helps you

Answer:

10

Explanation:

80 divided 8 =10

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

increace

Explanation:

they are both going up

9.8 N is the magnitude of the force that maintains circular motion acting on the puck.

32.53 m/sec is the linear speed of the puck.

The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. An item does not have a force inside of it or within it. Another item applies a force to another. The concept of a force is not restricted to living or non-living entities. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

As we know, from free body diagram, when the system is in equillibrium, the force acting on the puck on the table is as follows:

When the air puck of mass is revolving round the circle, then the tension (T) in the top string and the bottom of the string is same.

F = T

F = 9.8 N

Now, calculate the velocity of the puck:

From the given data, the air puck moves in a circular path. Hence, the tension in the top string is equal to the centripetal force acting on the puck.

Thus, the expression for the tension in the top string is as follows:

T = mv² / R

The velocity of the puck is as follows:

Mg = mv² / R

v² = MgR / m

v² = (2.7 × 9.8 × 1.2 ) / 0.030

v² = 1058.4

v = \(\sqrt{1058.4}\)

v = 32.53 m/sec

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Answer:

v = 0.059 m/s

Explanation:

To find the final speed of Olaf and the ball you use the conservation momentum law. The momentum of Olaf and the ball before catches the ball is the same of the momentum of Olaf and the ball after. Then, you have:

\(mv_{1i}+Mv_{2i}=(m+M)v\)  (1)

m: mass of the ball = 0.400kg

M: mass of Olaf = 75.0 kg

v1i: initial velocity of the ball = 11.3m/s

v2i: initial velocity of Olaf = 0m/s

v: final velocity of Olaf and the ball

You solve the equation (1) for v and replace the values of all variables:

\(v=\frac{mv_{1i}}{m+M}=\frac{(0.400kg)(11.3m/s)}{0.400kg+75.0kg}=0.059\frac{m}{s}\)

Hence, after Olaf catches the ball, the velocity of Olaf and the ball is 0.059m/s

The average mechanical power in watts that the engine must supply during this time interval is 58600 watts.

CALCULATION:-

The work done on an object by means of a net pressure equals the change in kinetic energy of the object:

W = KEf - KEi

W = 1/2m(vf² - vi²)

     =1/2*1172*[30²-20²]

     =293000 JOULE

Power is the rate at which work is performed. it's miles the paintings/time ratio. Mathematically, it's far computed the use of the following equation.

Power = Work/time

P = W / t

   =293000/5

   =58600 joule

Whilst pressure acts upon an object to cause a displacement of the object, it's miles said that work became accomplished upon the item. The kinetic energy of an object is the strength that it possesses due to its movement.

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Answer:

Total distance = 80 m

Total displacement = 40 m north

Explanation:

Total distance = 20 m + 40 m + 20 m

Total distance = 80 m

Total displacement = 20 m east - 20 m west + 40 m north

Total displacement = 40 m north

The electric potential energy decreases as the spheres move farther away from each other.

Since, they are like charges, the charged spheres will repel. Therefore, when it moves away, the distance between them increases, as a result the electric potential energy decreases.

As the two spheres separate from one another, the electric potential energy of the system will be transformed into kinetic energy. The movement of the spheres will be in opposite directions, away from one another.

The system's overall energy must remain constant according to the law of conservation of energy, but when the spheres separate from one another, potential energy is transformed into kinetic energy.

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Answer:

N = 167 Newtons

R = 727 Newtons

Explanation:

i) For static equilibrium, moments about any convenient point must sum to zero.

A moment is the product of a force and a moment arm length. Only the force acting perpendicular to a moment arm passing through the pivot point makes a moment.

ii) I will ASSUME the two moment arms are 0.05m and 0.15 m

CCW moments about the fulcrum are

190 N(0.2 m) + 280 N(0.05 m) = 52 N•m

CW moments are (N)N(0.15 m + 90 N(0.3 m) = 27 + 0.15N N•m

For static equilibrium, these must be equal

27 + 0.15N = 52

       0.15N = 25

              N = 166.6666666...

Sum moments about N to zero

(Same as saying CW and CCW moments must balance)

190(0.2 + 0.15) + 280(0.05 + 0.15) - R(0.15) - 90(0.3 - 0.15) = 0

R = 726.6666666...

We could verify this by summing vertical forces to zero.

R - 190 - 280 - 166.666666 - 90 = 0

R = 726.6666666...

Answer:

Explanation:I Did the test and it said this was the right answer so it probally is

Answer:

That's the question that I wanted to ask!!

Explanation:

A. The average speed you can use to pull the safe is 1.02 m/s

B. The time needed to pull the safe up is 17.65 s

First, we shall obtain the force. This is shown below:

F = mg

F = 60 × 9.8

F = 588 N

Finally, we shall obtain the average speed. Details below:

Power = force × average speed

600 = 588 × average speed

Divide both sides by 588

Average speed = 600 / 588

Average speed = 1.02 m/s

The time needed to pull the safe up can be obtained as follow:

Time = Total distance / average speed

Time = 18 / 1.02

Time = 17.65 s

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Complete question:

You know you can provide 600 W

of power to move large objects. You need to move a 60-kg

safe up to a storage loft, 18 m

above the floor.

Part A

With what average speed can you pull the safe straight up?

Part B

What is the time needed to pull the safe up?

Answer:

The length of the pendulum depends on acceleration due to gravity (g) which varies in different Earth's location beacuse Earth is not perfectly spherical.

Explanation:

The period of oscillation is calculated as;

\(T = 2\pi\sqrt{\frac{l}{g} }\)

where;

L is the length of the pendulum bob

g is acceleration due to gravity

If we make L the subject of the formula in the equation above, we will have;

\(T = 2\pi\sqrt{\frac{l}{g}}\\\\\sqrt{\frac{l}{g} } = \frac{T}{2\pi} \\\\\frac{l}{g} = (\frac{T}{2\pi} \)^2\\\\\frac{l}{g} =\frac{T^2}{4\pi^2}\\\\L = \frac{gT^2}{4\pi^2}\)

The length of the pendulum depends on acceleration due to gravity (g).

Acceleration due to gravity is often assumed to be the same everywhere on Earth, but it varies because Earth is not perfectly spherical. The variation of acceleration due to gravity (g) as a result of Earth's geometry, will also cause the length of the pendulum to vary.

Answer:

Explanation:

Given

Initial velocity u = 200m/s

Final velocity = 4m/s

Distance S = 4000m

Required

Acceleration

Substitute the given parameters into the formula

v² = u²+2as

4² = 200²+2a(4000)

16 = 40000+8000a

8000a = 16-40000

8000a = -39,984

a = - 39,984/8000

a = -4.998m/s²

Hence the acceleration is -4.998m/s²

Answer:

C

Explanation:

C

The orientation of the magnet that is free to rotate is the wil be oriented as shown as the magnet in the option D.

The correct option is therefore, option D.

A magnet produces magnetic field and it also attracts magnetic materials.

The directions of the lines of flux from a magnetic field is from the north to the south, such that the lines of flux emerges from the north of the magnet and enters into the magnet from the south pole of the magnet.

The point Y on the diagram shows the lines of flux entering the magnet, which indicates that the point Y is located in the south pole of the magnet, and therefore, will attract the north pole of another magnet, aligning it with the north and south pole of the large magnet in the figure.

The magnet free to rotate will therefore, be oriented with the north pole on the right (closer due to the attraction to the point Y) and the south pole on the left, which corresponds to the magnet D.

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Answer:

B. 10.08

C.2448

Explanation: