in which of the following types of circuits can the total power of the circuit be determined by adding the power dissipation of all the parts of the circuit?

(a) The location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.

(b) The magnitude and direction of the electric field at the top corner due to the two charges at the base is  1.732 kq/a².

The electric field is zero at the center of the equilateral triangle whose magnitude is equal to √3a/6.

E = E₁ + E₂

where;

E = kq/a²[(cos 60i + sin 60j) + (-cos 60i + sin 60j)]

E = kq/a²[2(sin 60j)] = 1.732 kq/a²

Thus, the location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.

The magnitude and direction of the electric field at the top corner due to the two charges at the base is  1.732 kq/a².

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Answer:

Role of government in regulating production

Explanation:

The role of government in regulating show , provides the legal and social framework, uphold competition, provides public goods and services.

The community's role in conserving and enhancing common-property resources is well known.

In extra, its role in helping market growth by its power to execute trade agreements among transacting parties belonging to the community network is stressed.

Thus, it provides the legal and social framework, maintains competition, and provides public goods and services.

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Answer:

A = 21 î + 28 ĵ

B = 12 î + 5 ĵ

Explanation:

a.

To write A and B in terms of î and ĵ, we need to use the trigonometric ratios and the vector notation

According to the diagram, we have:

tan a = 4/3 tan ß = 5/12

Using the identity tan θ = opposite/adjacent, we can find the x and y components of A and B.

For A, we have:

x component = 35 cos a y component = 35 sin a

Using tan a = 4/3, we can find cos a and sin a by using Pythagoras’ theorem:

cos a = 3/5 sin a = 4/5

Therefore, the x and y components of A are:

x component = 35 cos a = 35 (3/5) = 21 y component = 35 sin a = 35 (4/5) = 28

Using the vector notation, we can write A as:

A = 21 î + 28 ĵ

Similarly, for B, we have:

x component = 13 cos ß y component = 13 sin ß

Using tan ß = 5/12, we can find cos ß and sin ß by using Pythagoras’ theorem:

cos ß = 12/13 sin ß = 5/13

Therefore, the x and y components of B are:

x component = 13 cos ß = 13 (12/13) = 12 y component = 13 sin ß = 13 (5/13) = 5

Using the vector notation, we can write B as:

B = 12 î + 5 ĵ

b.

To show that A + B makes an angle of 45° to the x-axis, we need to find the resultant vector R and its angle θ with the x-axis.

To find R, we can use the vector addition rule :

R = A + B R = (21 î + 28 ĵ) + (12 î + 5 ĵ) R = (21 + 12) î + (28 + 5) ĵ R = 33 î + 33 ĵ

To find θ, we can use the inverse tangent function :

tan θ = y component / x component tan θ = 33 / 33 tan θ = 1

θ = tan^-1(1) θ = 45°

Therefore, A + B makes an angle of 45° to the x-axis.

The acceleration of the jet when it speeds up = 7.5 m/s²

The initial speed, u = 100 m/s

Distance travelled, s = 2. km

s = 2 x 1000m

s = 2000 m

Final speed, v = 200 m/s

The acceleration is found by using the equation of motion below

Substitute v = 200 m/s, u = 100 m/s, s = 2000 m

The acceleration of the jet when it speeds up = 7.5 m/s²

mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.

An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.

De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.

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Assume that you reduce Vo back to 5 V and switch the trigger slope polarity from '+' to '-' without changing the trigger level dial. V and ωt when the scope is triggered now 2.5 volts 150 degrees.

An oscilloscope (informally a scope) is a sort of digital take a look at instrument that graphically shows various electrical voltages as a -dimensional plot of one or extra signals as a feature of the time. the main functions are to show repetitive or unmarried waveforms on the screen that might in any other case arise too briefly to be perceived via the human eye.

The displayed waveform can then be analyzed for homes consisting of amplitude, frequency, upward thrust time, time c program language period, distortion, and others. at first, the calculation of these values required manually measuring the waveform in opposition to the scales built into the display of the instrument. current digital units might also calculate and display those residences without delay.

Oscilloscopes are used within the sciences, medicine, engineering, car, and telecommunications industry. general-reason devices are used for the preservation of digital devices and laboratory paintings. unique-motive oscilloscopes may be used to analyze an automobile ignition device or to show the waveform of the heartbeat as an electrocardiogram, for instance.

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The list of the object in order of least to greatest momentum is Y, W, X, Z (last option)

To obtain the list in order of least to greatest momentum, we shall obtain the momentum of each object. Details below:

For W

Momentum = mass × velocity

= 12 × 5 m/s

= 60 Kg.m/s

For X

Momentum = mass × velocity

= 15 × 8 m/s

= 120 Kg.m/s

For Y

Momentum = mass × velocity

= 18 × 2 m/s

= 36 Kg.m/s

For Z

Momentum = mass × velocity

= 28 × 10 m/s

= 280 Kg.m/s

From the above, we have the following:

Thus, the list from least to greatest of the momentum is Y, W, X, Z (last option)

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Complete question:

See attached photo

The ball that correctly relates the kinetic energy of a ball is;  Ball C

The kinetic energy of an object is the energy generated by an object in motion ( i.e. object whose speed is greater than zero )

and the formula for Kinetic energy = 1/2 mv^2 .

Ball B :

mass = 4kg , speed = 8 m/s . kinetic energy = 130 J

K.E = 1/2 ( 4 * 8^2 )

      = 128 J   ( 130 J ≠ 128 J ) ( does not correctly relate the kinetic energy

Ball C :

mass = 5 kg, speed = 8 m/s , kinetic energy = 160 J

K.E = \(1/2*\) \(( 5 * 8^2 )\)

      = 160 J  ( 160 J = 160 J )  ( correctly relates the kinetic energy )

Hence we can conclude that The ball that correctly relates the kinetic energy of a ball is;  Ball C.

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Answer:

b=c or b,c

Explanation:

At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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Answer:

We’re imagining imagining imagining an imagination...

78% of the houses in Elizabeth's town were for sale last summer.

To find the percentage of houses that were for sale last summer in Elizabeth's town, we need to divide the number of houses for sale by the total number of houses and then multiply by 100.

The total number of houses in Elizabeth's town is given as 9,000. Last summer, 7,020 houses were for sale. To calculate the percentage, we divide 7,020 by 9,000:

Percentage = (7,020 / 9,000) * 100

Simplifying the calculation:

Percentage = 0.780 * 100

Percentage = 78.0%

To explain further, we take the number of houses for sale (7,020) and divide it by the total number of houses (9,000) to get the ratio of houses for sale to the total. Multiplying this ratio by 100 gives us the percentage. In this case, 78.0% indicates that a significant portion of the houses in Elizabeth's town were available for sale during the summer.

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False: Waves are generated when the wave's crest crashes into the bottom of the wave, which is travelling more quickly.

A wave is an energetic disturbance in such a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, a magnetic or electrical intensity, an electric potential, or a change in temperature are a few examples.

Transverse and longitudinal waves are the two types of waves. While longitudinal waves are similar to those of sound, composed of alternating compressions & rarefactions in a medium, transverse waves were like those on water, having their surface moving up and down.

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The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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Answer:

(i) The pressure exerted by the piston on the gas in the chamber can be calculated using the formula:

Pressure = Force / Area

The force exerted by the piston on the gas is equal to its weight, which can be calculated as:

Force = mass x gravitational acceleration

= 3.5 kg x 9.81 m/s^2

= 34.335 N

The area of the piston is 450 cm^2, which is equal to 0.045 m^2.

Therefore, the pressure exerted by the piston on the gas is:

Pressure = Force / Area

= 34.335 N / 0.045 m^2

= 763 N/m^2 or 763 Pa

(ii) The work done when the cylinder is heated at a constant pressure of 1 atm can be calculated using the formula:

Work = Pressure x Change in Volume

The initial volume of the cylinder is Vo, and the final volume is 3Vo. Therefore, the change in volume is:

Change in Volume = 3Vo - Vo

= 2Vo

The pressure is given as 1 atm, which is equal to 101,325 Pa.

Therefore, the work done is:

Work = Pressure x Change in Volume

= 101,325 Pa x 2Vo

= 202,650 Pa.Vo or 202,650 J:

When a car is traveling north, its acceleration vector can point south when it is slowing down.

A vector quantity has both magnitude and direction. The direction of a vector is always shown by the direction to which the arrow points.

If the car is travelling north, the direction of the acceleration vector will continue to point northwards.

However, when the car slows down, the direction of the accelerating vector will now point southwards.

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Answer: B

Explanation:

Answers A and C are examples of physical weathering while B is chemical weathering when water and lime mix it creates a reaction

C

It is right because I took this and I got this answer correct

The amount of force that must have been applied is 100 N.

option D is the correct answer.

The amount of force applied to overcome the load is calculated by applying the formula for work done as shown below.

Mathematically, the formula for work done is given as;

W = Fd

where;

If the distance moved by the effort arm is 10 meters, the amount of effort or force applied to overcome the load is calculated as follows;

F = W / d

F = ( 400 J ) / 4 m

F = 100 N

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Answer:

the moment of inertia is 4.5 × 10⁻⁵ kg.m²  

Explanation:

Given that;

point mass m = 0.005 g = ( 0.005 / 1000 ) = 5 × 10⁻⁶ kg

perpendicular distance r = 3m

We know that a point mass doesn't have a moment of inertia around its own axis but, but using the parallel axis theorem, a moment of inertia around a distant axis of rotation can be determined using;

\(I_{}\) = mr²

so we substitute

\(I_{}\) = (5 × 10⁻⁶ kg) × (3 m)²

\(I_{}\) = (5 × 10⁻⁶ kg) × 9 m²

\(I_{}\)  = 4.5 × 10⁻⁵ kg.m²  

Therefore; the moment of inertia is 4.5 × 10⁻⁵ kg.m²  

The moment of inertia of given point mass is 4.5 × 10⁻⁵ kgm² at a perpendicular distance of 3 m.

The moment of inertia of given point mass can be determined by,

\(I = mr^2\)

Where,

\(I\)- moment of inertia

\(m\)- mass = 0.005 g = ( 0.005 / 1000 ) = 5 × 10⁻⁶ kg

\(r\) - perpendicular distance = 3 m

Put the values in the formula,

\(I = (5 \times 10^{-6}{\rm \ kg}) \times (3 {\rm \ m})^2\\\\I = 5 \times 10^{-6}{\rm \ kg} \times 9 {\rm \ m}\\\\I = 4.5 \times 10^{-5} kgm^2\)

Therefore; the moment of inertia of given point mass is 4.5 × 10⁻⁵ kgm².

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Answer: D. movement of material along a coast by waves that approach at an angle to the shore.​

Explanation:

Longshore drift is also referred to as the littoral druft and it means the sediment that is moved by the longshore current.

Longshore drift is the movement of material along a coast by waves which approach at an angle to the shore but then recede down the beach.

Therefore, the correct option is D.

Answer:

a survey

Explanation:

how kids like the playground or they do not like it at all

Answer:

What is the question though?

Explanation:

Answer:

5,000J

Explanation:

Work = Force x Distance

Distance back and forth is canceled out, so either the answer is + or -

5.0m + 5.0m = 10.0m

500N x 10.0m = 5,000J

Answer:

Those are all right

Explanation:

Answer:

They are right! Nice job!

Explanation:

Complete Question

A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string,  If the breaking strength of the string is 120 N, what's the minimum angle the string can make with the horizontal?

Answer:

The value is \(\theta = 4.41^o\)      

Explanation:

From the question we are told that

  The mass of the rock is  \(m_r = 940 \ g = 0.94 \ kg\)

   The length of the string is \(l = 1.30 \ m\)

    The breaking strength(i.e the maximum tension) on the string is \(T = 120 \ N\)

Gnerally the vertical component of the tension experienced by the string is mathematically represented as

     \(T_v = T sin(\theta)\)

Generally this vertical component  of tension is equivalent to the weight of the rock

So

     \(Tsin (\theta) = mg\)

=>  \(\theta = sin^{-1} [\frac{mg}{ T} ]\)

=>    \(\theta = sin^{-1} [\frac{0.940 *9.8 }{ 120} ]\)

=>    \(\theta = 4.41^o\)      

(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

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The potential and kinetic energy of the system at the following time instances is zero and maximum.

From the given,

The displacement of the system is, x = A cos(3πt/T)

1) At t =0, the displacement of the system is given by, x = cos(3π×0/T)= cos(0) = 1. The displacement is maximum at t=0. Hence, the potential energy is maximum and kinetic energy is zero.

2) At t=T, the displacement, x = cos(3πT/T)= cos(3π) = -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

3) At t = T/6, the displacement x = cos(3πT/6T)=cos(π/2)=0, the displacement is zero, and hence, both the potential and kinetic energy is zero.

4) At t=T/3, the displacement, x= cos(3πt/T)=cos(3πT/3)= -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

5) At t=T/2, the displacemetn x = cos(3πt/T) = cos(3πT/2T) = cos (3π/2)=0. Hence, both the potential and kinetic energy is zero.

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(a) The time it takes for you to change your displacement by 16 m east is 8.67 s.

(b) The time it takes for you to change your displacement by 26 m north is 35.3 s.

(a) The time it takes for you to change your displacement by 16 m east is calculated as follows;

s = vt + ¹/₂at²

where;

16 = 1.9 x cos(13.8)t

16 = 1.845t

t = 16/1.845

t = 8.67 s

(b) The time it takes for you to change your displacement by 26 m north is calculated as follows;

16 = 1.9 x sin(13.8)t

16 = 0.453t

t = 16/0.453

t = 35.3 s

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