In what compartment of the feature control frame is the datum located?
Answers
The datum is located in the third compartment of the feature control frame and serves as a reference for measuring and controlling geometric tolerances.
In a feature control frame, the datum is located in the compartment following the geometric tolerance compartment. A feature control frame is a rectangular box containing multiple compartments that provide information about geometric tolerances, datums, and other relevant specifications for a feature on a technical drawing. The first compartment of a feature control frame displays the geometric characteristic symbol, representing the type of tolerance (e.g., flatness, perpendicularity, etc.). The second compartment indicates the geometric tolerance value, which specifies the allowable deviation from the ideal geometry. The third compartment, where the datum is located, identifies the datum reference(s) used to establish the measurement reference frame. Datums are labeled with capital letters (e.g., A, B, C) and are necessary to define the position and orientation of the part during inspection.
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Related Questions
what is the difference between zinc and galvanized zinc
Answers
Answer:
Both zinc plating and galvanizing is an application of zinc plating. The big difference is thickness: zinc plating is normally 0.2 mils thick. Hot dip galvanizing might be 1.0 mil thick – you get over 5 times the protection with galvanizing. ... After 20 years outdoors a galvanized product will not show signs of rust.
Explanation:
hope this helps! a brainiest is always appreciated
How do i untange my headphone cords? If you give me a good answer i will mark u brainliest
Answers
Answer:
scissors best way 100%
Explanation:
Describe the steps in the PDCA (Deming or Shewhart) cycle.
Answers
PDCA (Plan-Do-Check-Act) is a four-step iterative management method. Plan: Set objectives and devise a plan. Do: Implement the plan on a small scale.
Check: Evaluate the results against objectives and identify deviations. Act: Adjust and refine the plan based on the evaluation. Repeat the cycle to continuously improve processes.
The PDCA cycle begins with planning, where objectives are set and a plan is developed. Next is the implementation stage, where the plan is executed on a small scale. The check phase involves evaluating the results and comparing them with the objectives to identify any deviations or gaps. In the act phase, necessary adjustments and refinements are made to the plan based on the evaluation. The cycle repeats to foster continuous improvement and maintain a dynamic process of goal-setting, implementation, evaluation, and refinement.
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You have accumulated several parking tickets while at school, but you are graduating later in the year and plan to return to your home in another jurisdiction. A friend tells you that the authorities in your home jurisdiction will never find out about the tickets when you re-register your car and apply for a new license. What should you do?
Answers
Answer:
pay off the parking tickets
Explanation:
In the scenario being described, the best thing to do would be to pay off the parking tickets. The parking tickets stay under your name, and if they are not paid in time can cause problems down the road. For starters, if they are not paid in time the amount will increase largely which will be harder to pay. If that increased amount is also not paid, then the government will suspend your licence indefinitely which can later lead to higher insurance rates.
Your new boss wants to know if they are compliant with the latest (2017) OWASP Top 10. Which of the following IS NOT one of the 2017 Top 10 Top Application Security Risks.?a) Cross Site Request Forgery b)Cross Site Scripting c)Injection d)Broken Authentication
Answers
After gaining access to the user's account, the attacker can steal any sensitive information they desire or perform any action that the user is authorized to perform.
In 2017, the Open Web Application Security Project (OWASP) created a list of the Top 10 Application Security Risks. The list is as follows:
InjectionBroken Authentication and Session ManagementSensitive Data ExposureXML External Entities (XXE)Broken Access ControlSecurity MisconfigurationCross-Site Scripting (XSS)Insecure DeserializationUsing Components with Known VulnerabilitiesInsufficient Logging and MonitoringNow, the given alternatives include:
a) Cross Site Request Forgery
b) Cross Site Scripting
c) Injectiond)
Broken AuthenticationFrom the above alternatives, we can say that all of the options are part of OWASP Top 10, except Cross Site Request Forgery.
Therefore, the correct answer is (a) Cross Site Request Forgery.
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TypeError Traceback (most recent call last) Input In [34], in () ----> 1 statistics([1, 1, 1, 1]) Input In [29], in statistics(x) 22 mean= round(np_list.mean(), 2) if str(type(np_list[0]))=="" else [round(i.mean(), 2) for i in np_list] 23 # find standard deviation ---> 24 std= round(unbias_std(np_list), 2) if str(type(np_list[0]))=="" else [round(unbias_std(i), 2) for i in np_list] 25 # find mininum 26 mini= np_list.min() if str(type(np_list[0]))=="" else [i.min() for i in np_list] Input In [29], in (.0) 22 mean= round(np_list.mean(), 2) if str(type(np_list[0]))=="" else [round(i.mean(), 2) for i in np_list] 23 # find standard deviation ---> 24 std= round(unbias_std(np_list), 2) if str(type(np_list[0]))=="" else [round(unbias_std(i), 2) for i in np_list] 25 # find mininum 26 mini= np_list.min() if str(type(np_list[0]))=="" else [i.min() for i in np_list] Input In [21], in unbias_std(lists) 15 def unbias_std(lists): 16 mean=lists.mean() ---> 17 var = sum(pow(x-mean,2) for x in lists) / (len(lists)-1) 18 std = np.sqrt(var) 19 return std TypeError: 'numpy.int32' object is not iterable
statistics([1, 1, 1, 1]) == {'mean': 1, 'std': 0, 'min': 1, 'median', 1, 'max': 1}
statistics([1, 2, 2, 3, 4]) == {'mean': 2.4, 'std': 1.14, 'min': 1, 'median': 2.0, 'max': 4}
TypeError: 'numpy.int32' object is not iterable
statistics([1, 1, 1, 1]) == {'mean': 1, 'std': 0, 'min': 1, 'median', 1, 'max': 1}
statistics([1, 2, 2, 3, 4]) == {'mean': 2.4, 'std': 1.14, 'min': 1, 'median': 2.0, 'max': 4}
good day
when i run the above i get this error message . TypeError: 'numpy.int32' object is not iterable. i need a code to rectify this error message and run all three
thank you.
this code provided below works for the code below to run.
statistics([[1, 2], [3, 4]]) == { 'mean': [1.5, 3.5], 'std': [0.71, 0.71], 'min': [1, 3], 'median': [1.5, 3.5], 'max': [2, 4] }
def calculate(lst):
import numpy as np
if len(lst) != 9:
return "List must contain nine numbers."
x = np.array(lst).reshape(3, 3)
result = {
k: [func(x, axis=ax).tolist()
for ax in [0, 1, None]]
for (k, func)
in zip(["mean", "variance", "standard deviation"],
[np.mean, np.var, np.std])
}
statistics([[1, 2], [3, 4]]) == { 'mean': [1.5, 3.5], 'std': [0.71, 0.71], 'min': [1, 3], 'median': [1.5, 3.5], 'max': [2, 4] }
Answers
It checks the type of the first element in `x` to determine if it's a single list or nested lists, and performs the calculations accordingly. The results are returned in a dictionary format.
"Could you provide a concise code snippet that calculates statistics (mean, standard deviation, minimum, median, and maximum) for a given list or nested lists, handling both cases in a single line?"Here's a version of the code that accomplishes the task in a single line:
import numpy as np
statistics = lambda x: {'mean': round(np.mean(x), 2) if isinstance(x[0], int) else [round(np.mean(i), 2) for i in x],
'std': round(np.std(x), 2) if isinstance(x[0], int) else [round(np.std(i), 2) for i in x],
'min': np.min(x).tolist() if isinstance(x[0], int) else [np.min(i).tolist() for i in x],
'median': round(np.median(x), 2) if isinstance(x[0], int) else [round(np.median(i), 2) for i in x],
'max': np.max(x).tolist() if isinstance(x[0], int) else [np.max(i).tolist() for i in x]}
This lambda function takes a list or nested lists as input (`x`) and calculates the mean, standard deviation, minimum, median, and maximum values.
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A power cycle receives QH by heat transfer from a hot reservoir at TH = 1200 K and rejects energy QC by heat transfer to a cold reservoir at TC = 400 K. For each of the following cases, determine whether the cycle operates reversibly, operates irreversibly, or is impossible.
a.QH = 900 kJ, Wcycle= 450 kJ
b. QH = 900 kJ, Qc = 300 kJ
c. Weycle = 600 kJ, Qc= 400 kJ
d. η = 75%
Answers
Answer:
a) Irreversible, b) Reversible, c) Irreversible, d) Impossible.
Explanation:
Maximum theoretical efficiency for a power cycle (\(\eta_{r}\)), no unit, is modelled after the Carnot Cycle, which represents a reversible thermodynamic process:
\(\eta_{r} = \left(1-\frac{T_{C}}{T_{H}} \right)\times 100\,\%\) (1)
Where:
\(T_{C}\) - Temperature of the cold reservoir, in Kelvin.
\(T_{H}\) - Temperature of the hot reservoir, in Kelvin.
The maximum theoretical efficiency associated with this power cycle is: (\(T_{C} = 400\,K\), \(T_{H} = 1200\,K\))
\(\eta_{r} = \left(1-\frac{400\,K}{1200\,K} \right)\times 100\,\%\)
\(\eta_{r} = 66.667\,\%\)
In exchange, real efficiency for a power cycle (\(\eta\)), no unit, is defined by this expression:
\(\eta = \left(1-\frac{Q_{C}}{Q_{H}}\right) \times 100\,\% = \left(\frac{W_{C}}{Q_{H}} \right)\times 100\,\% = \left(\frac{W_{C}}{Q_{C} + W_{C}} \right)\times 100\,\%\) (2)
Where:
\(Q_{C}\) - Heat released to cold reservoir, in kilojoules.
\(Q_{H}\) - Heat gained from hot reservoir, in kilojoules.
\(W_{C}\) - Power generated within power cycle, in kilojoules.
A power cycle operates irreversibly for \(\eta < \eta_{r}\), reversibily for \(\eta = \eta_{r}\) and it is impossible for \(\eta > \eta_{r}\).
Now we proceed to solve for each case:
a) \(Q_{H} = 900\,kJ\), \(W_{C} = 450\,kJ\)
\(\eta = \left(\frac{450\,kJ}{900\,kJ} \right)\times 100\,\%\)
\(\eta = 50\,\%\)
Since \(\eta < \eta_{r}\), the power cycle operates irreversibly.
b) \(Q_{H} = 900\,kJ\), \(Q_{C} = 300\,kJ\)
\(\eta = \left(1-\frac{300\,kJ}{900\,kJ} \right)\times 100\,\%\)
\(\eta = 66.667\,\%\)
Since \(\eta = \eta_{r}\), the power cycle operates reversibly.
c) \(W_{C} = 600\,kJ\), \(Q_{C} = 400\,kJ\)
\(\eta = \left(\frac{600\,kJ}{600\,kJ + 400\,kJ} \right)\times 100\,\%\)
\(\eta = 60\,\%\)
Since \(\eta < \eta_{r}\), the power cycle operates irreversibly.
d) Since \(\eta > \eta_{r}\), the power cycle is impossible.
A series RC circuit has a voltage of 24VAC and an impedance of 252ohms. What is the circuit current?
Answers
Answer:
the current in the circuit is 95.2 mA.
Explanation:
Given;
voltage in the circuit, V = 24 V
impedance of the circuit components, Z = 252 ohms
The current in the circuit is calculated as;
\(I = \frac{V}{Z} \\\\I = \frac{24}{252} \\\\I = 0.0952 \ A\\\\I = 95.2 \ mA\)
Therefore, the current in the circuit is 95.2 mA.
what document is the primary reference document when making ethical decisions?
Answers
A company wants to develop audio speakers using an inexpensive type of plastic that has a very high quality of sound output. Which customers would most likely give a high evaluation of this product?
Answers
Answer:A
Explanation:
Those who want to save money and will use the product for only a few years
Answer:
THE ANSWER is A - those who want to save money and will use the product for only a few years
Explanation: Got it right on edg 2021
Engineer drawing:
How can i draw this? Any simple way?
Answers
Using leftover paint colors is acceptable in a paint shop and will help cut down on waste.
True or false
Answers
Answer:
True
Explanation:
they put it through a process to be able to reuse it
Briefly explain thermal expansion using the potential energy–versus–interatomic spacing curve.
Answers
As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.
What are the uses of Thermal Expansion?Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.
It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.
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Match the use of the magnetic field to its respective description.
Answers
oooExplanation:
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Using p–v–T data for saturated water from the steam tables, calculate at 50°C:(a) hg - hf.(b) ug - uf.(c) sg - sf.Compare with values obtained from the steam tables.-Determine (hg - hf) at 50°C, in kJ/kg, using p–v–T data for saturated water from the steam tables.-Obtain the value of hfg at 50°C, in kJ/kg, directly from the steam tables.-(c) sg - sf
Answers
(a) hg - hf = 191.81 kJ/kg
(b) ug - uf = 1504.56 kJ/kg
(c) sg - sf = 5.603 J/gK
Using the p-v-T data for saturated water from the steam tables, we can calculate the enthalpy of vaporization (hg - hf) at 50°C, which is 191.81 kJ/kg. The value of hfg at 50°C can be obtained directly from the steam tables and is approximately 2391.7 kJ/kg. Finally, we can calculate the difference between the specific entropy of the saturated vapor and the saturated liquid (sg - sf) at 50°C, which is approximately 5.603 J/gK. These values can then be compared to the values obtained from the steam tables to ensure the accuracy of the calculations.
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Feature Engineering
When would binning be an appropriate feature engineering step?
a. When we want to create defined groups from a continuous feature
b. When we want to transform categorical features into continuous features
c. When we want to remove low-quality features
d. When we want to create a new feature by combining existing ones
Answers
The appropriate feature engineering step for binning would be:
a. When we want to create defined groups from a continuous feature.
Binning is a useful technique in feature engineering when we want to convert a continuous feature into discrete or categorical groups. It involves dividing the range of values of a continuous feature into bins or intervals and assigning each value to a corresponding bin. This allows us to create defined groups or categories based on the values of the continuous feature.
Binning can be beneficial in various scenarios. For instance, it can help simplify complex data patterns, handle outliers or noise, and capture non-linear relationships between the feature and the target variable. Binning can also be used to address issues related to model complexity, data sparsity, or limited sample sizes.
By transforming a continuous feature into discrete groups, binning can enable models to capture patterns and make predictions based on the created categories. It allows for a more interpretable representation of the data and can improve the performance of certain machine learning algorithms, especially those that work better with categorical or ordinal data.
In summary, binning is an appropriate feature engineering step when we want to create defined groups or categories from a continuous feature. It can help simplify complex data patterns, handle outliers, and capture non-linear relationships, ultimately enhancing the modeling and prediction capabilities of machine learning algorithms.
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A beaker is filled to the 500 ml mark with alcohol. What increase in volume (in ml) the beaker contain when the temperature changes from 5°C to 30°C? (Neglect the expansion of the beaker, evaporation of alcohol and absorption of water vapor by alcohol.) C°, Palcohol = 1.12 x 104/ °C
Answers
Answer:
1.4 mL
Explanation:
Given that:
volume of alcohol \(V_0\) = 500
Temperature change ΔT = (30° - 5°)C
=25° C
\(\beta_{ alcohol }= 1.12 \times 10^{-4} / ^0C\)
The increase in volume ΔV = \(\alpha \times V_o \times \Delta T\)
\(= 500 \times 1.12 \times 10^{-4} / ^0 C\times 25^0 C\)
= 1.4 mL
Consider the three-bus system of following Fig. The pu line reactances are indicated on the
figure; the line resistances are negligible. The magnitude of all the three-bus voltages is specified
to be 1.0 pu. The bus powers are specified in the following table.
Answers
To solve for the bus voltages and line currents, we will employ the power flow equations.
The power flow equations are given by:
P_1 = V_1I_1*
P_2 = V_2I_2*
P_3 = V_3I_3*
Q_1 = V_1I_1*sinθ_1
Q_2 = V_2I_2*sinθ_2
Q_3 = V_3I_3*sinθ_3
What is Power flow ?Power flow has been the transmission of the electricity from one point to another just through the power grid. It has the flow of the electrical energy from the source of the supply, which is just through an electrical network, that to the point of the consumption.
Power flow has a fundamental concept in the electricity transmission, as it is the actual flow of the electricity which has been affected by the generators, transformers, as well as the capacitors, loads, and other components in the system.
Therefore, The aim has to determine the bus voltages along with the line currents in the three-bus system.
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A light commercial building located in Philadelphia, Pa has construction and use characteristics much like a residence and design heating load of 120,000 Btu/h and cooling of 60,000 Btu/h. Determine the following: (a) Heating energy requirement, Btu(b) Gallons of No. 2 fuel oil/year, assuming efficiency of the furnace is 75 %(c) Cubic feet of natural gas/year(d) kWh of electricity for cooling for air conditioner with SEER of 8.5 using degree day method.(6 points)
Answers
Answer:
b
Explanation:
. A punch with a diameter of 15mm is used to make a circular hole in an 5mm steel plate. If a force of 80N is needed to produce the hole, what was the average shear stress acting over the newly formed surfaces of the hole
Answers
Given, Diameter of the punch, d = 15 mm Radius of the punch, r = d/2 = 15/2 mm = 7.5 mmThickness of the steel plate, t = 5 mmForce required to produce the hole, F = 80 N.
The average shear stress acting over the newly formed surfaces of the hole can be calculated using the formula:
τ = (4F)/(πd t) Where,τ = Shear stress F = Force required to produce the holed = Diameter of the punch t = Thickness of the steel plate Substituting the given values in the above formula:τ = (4F)/(πd t)τ = (4 x 80)/(π x 15 x 5)τ = 0.85 MP a Therefore, the average shear stress acting over the newly formed surfaces of the hole is 0.85 MP a.
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computer-aided manufacturing is an example of what?
Answers
Computer-aided manufacturing (CAM) is an example of a manufacturing process that involves the use of computer software to control the production of goods.
Computer-aided manufacturing (CAM) is an example of a manufacturing process that involves the use of computer software to control the production of goods. In CAM, the computer controls the manufacturing process, which means that there is less chance of human error. CAM systems use various types of software to control the process of manufacturing, including computer-aided design (CAD) and computer-aided engineering (CAE) software. The primary goal of CAM is to automate the manufacturing process to improve efficiency, accuracy, and speed. By using CAM, manufacturers can reduce the amount of time and money needed to produce goods.
CAM also enables manufacturers to produce complex designs that are difficult or impossible to create manually. CAM systems are used in many industries, including automotive, aerospace, and electronics manufacturing. CAM has revolutionized the manufacturing industry by making it possible to create products that are more efficient, accurate, and reliable.
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What are some sources of resistance? (Check all
that apply.)
worn or damaged cables
loose cable connections
weak springs on work clamps
painted surfaces
rusty tables
Answers
Answer:
All of them.
Explanation:
I take this class rn too and those are answers
10.9 Determine the critical load of a round wooden dowel that is 0.9 m long and has a diameter of (a) 10 mm, (b) 15 mm. Use E
Answers
these categories
THE NATURE OF MATERIALS
Review Questions
2.1
The elements listed in the Periodic Table can be divided into three categories. What are these categories and give an example of each?
Answer
. The three types of elements are metals (e.g., aluminum), nonmetals (e.g., oxygen), and semimetals
Air is a....
O Solid
O Liquid
O Gas
O Plasma
Answers
Answer:
Air is a gas
Explanation:
i think. beavuse it cant be a liqued or a solid. i dont think a plasma. i would answer gas
Assignment 1: Structural Design of Rectangular Reinforced Concrete Beams for Bending
Perform structural design of a rectangular reinforced concrete beam for bending. The beam is simply supported and has a span L=20 feet. In addition to its own weight the beam should support a superimposed dead load of 0.50 k/ft and a live load of 0.65 k/ft. Use a beam width of 12 inches. The depth of the beam should satisfy the ACI stipulations for minimum depth and be proportioned for economy. Concrete compressive strength f’c = 4,000 psi and yield stress of reinforcing bars fy = 60,000 psi. Size of stirrups should be chosen based on the size of the reinforcing bars. The beam is neither exposed to weather nor in contact with the ground, meaning it is subjected to interior exposure.
• Use the reference on "Practical Considerations for Rectangular Reinforced Concrete Beams"
• Include references to ACI code – see slides from second class
• Include references to Tables from Appendix A
• Draw a sketch of the reinforced concrete beam showing all dimensions, number and size of rebars, including stirrups.
Answers
Answer:
Beam of 25" depth and 12" width is sufficient.
I've attached a detailed section of the beam.
Explanation:
We are given;
Beam Span; L = 20 ft
Dead load; DL = 0.50 k/ft
Live load; LL = 0.65 k/ft.
Beam width; b = 12 inches
From ACI code, ultimate load is given as;
W_u = 1.2DL + 1.6LL
Thus;
W_u = 1.2(0.5) + 1.6(0.65)
W_u = 1.64 k/ft
Now, ultimate moment is given by the formula;
M_u = (W_u × L²)/8
M_u = (1.64 × 20²)/8
M_u = 82 k-ft
Since span is 20 ft, it's a bit larger than the average span beams, thus, let's try a depth of d = 25 inches.
Effective depth of a beam is given by the formula;
d_eff = d - clear cover - stirrup diameter - ½Main bar diameter
Now, let's adopt the following;
Clear cover = 1.5"
Stirrup diameter = 0.5"
Main bar diameter = 1"
Thus;
d_eff = 25" - 1.5" - 0.5" - ½(1")
d_eff = 22.5"
Now, let's find steel ratio(ρ) ;
ρ = Total A_s/(b × d_eff)
Now, A_s = ½ × area of main diameter bar
Thus, A_s = ½ × π × 1² = 0.785 in²
Let's use Nominal number of 3 bars as our main diameter bars.
Thus, total A_s = 3 × 0.785
Total A_s = 2.355 in²
Hence;
ρ = 2.355/(22.5 × 12)
ρ = 0.008722
Design moment Capacity is given;
M_n = Φ * ρ * Fy * b * d²[1 – (0.59ρfy/fc’)]/12
Φ is 0.9
f’c = 4,000 psi = 4 kpsi
fy = 60,000 psi = 60 kpsi
M_n = 0.9 × 0.008722 × 60 × 12 × 22.5²[1 - (0.59 × 0.008722 × 60/4)]/12
M_n = 220.03 k-ft
Thus: M_n > M_u
Thus, the beam of 25" depth and 12" width is sufficient.
Plumbing
The should indicate the materials, fixtures, and faucets to be
used.
A. specifications
B. plumbing code
C. mechanical code
D. plumbing instructor
Answers
Answer:
B....................
Find and write the mathematical problem formulation of shortest path problem
Answers
Shortest path (A, C, E, D, F) between vertices A and F in the weighted directed graph
The problem of finding the shortest path between two intersections on a road map may be modeled as a special case of the shortest path problem in graphs, where the vertices correspond to intersections and the edges correspond to road segments, each weighted by the length of the segment.
How do u walk dogs and they have to park in the car
Answers
Answer: walk dog on leash for one and two you csnt park in a car you park the car and walk the dog on a leash
Explanation: did you phrase the question wrong?
7
Here is a precast concrete unit which is 2.0m tall, 1.2m wide and the foot is 1.0m deep. Taking
the density of concrete as 24kN/m3 and assuming the thickness is 150mm throughout. What
is the unfactored overturning moment in the most resistant direction when it is plainly sat on
the ground?
Answers
To calculate the unfactored overturning moment in the most resistant direction for the precast concrete unit, we first need to determine its weight.
Volume of the precast concrete unit = height x width x depth = 2.0m x 1.2m x 0.15m = 0.36m3
Weight of the precast concrete unit = volume x density = 0.36m3 x 24kN/m3 = 8.64kN
Next, we need to consider the moment created by the weight of the unit. Assuming that the center of gravity of the unit is at its geometric center (which is a reasonable assumption for a symmetrical object), the moment can be calculated as follows:
Moment = weight x distance from the center of gravity to the edge of the base
Distance from center of gravity to edge of base = 0.5 x width = 0.5 x 1.2m = 0.6m
Moment = 8.64kN x 0.6m = 5.184 kNm
Therefore, the unfactored overturning moment in the most resistant direction for the precast concrete unit when it is plainly sat on the ground is 5.184 kNm.
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LOLOLOLOKOLLOLLOLOLOO STRIKER KID THINKS HES SO GOOD LLOLOLOLOLOLOLOLOLOLOOLOLOLOLOLOLOL
Answers
Answer:
UUUUUUMMMM do you mean in soccer ????????????????
Explanation: