in the past, the federal reserve (fed) mandated that member commercial banks must hold a certain fraction of their checkable deposits in the form of bank deposits at the fed and/or vault cash because the sum of these two accounts equals reserves. the fraction of checkable deposits that banks must hold in reserve form is called the required reserve ratio (r). suppose no excess reserves were in the banking system and the required reserve ratio(r) was 10%. the fedbought a government bond worth $250,000 from raphael, a client of first main street bank. raphael deposited the money into his checking account at first main street bank. given the required reserve ratio (r), first main street bank was required to hold as required reserves and could use to make loans.

Answer:

C 3/2

Step-by-step explanation:

Since triangle PRQ is the original and is getting bigger proportionally (can tell by side lengths) you can eliminate options A and B since you have to multiply by a number/fraction greater than one since it's getting bigger. Then pick a side corresponding to another side of the other triangle. For example, the side length of PQ is 8. Side length P'Q' is 12. You will need to consider how you get from that 8 since it's the original to the 12. To do that you will need to multiply by 1.5 to get to 12. this is what it means by dilation. Since 3/2=1.5 that would be your answer.

Answer:

Drawing : Actual

Scale

           2 : 10

     2 cm : 10 feet

Length

    6 cm : 30 feet

Width

    4 cm : 20 feet

The actual dimensions of the room are - Length=30 feet, Width=20 feet.

The answer is the second one.

Step-by-step explanation:

Answer:

second one

Step-by-step explanation:

Answer:

D. \(-\frac{\sqrt{2} }{2}\)

Step-by-step explanation:

So, on a regular coordinate plane, coordinates are written (x,y)

well, in trig, coordinates are written (cosθ, sinθ).

if sinθ=\(\frac{\sqrt{2} }{2}\) in the second quadrant, then look for the "y-value" that says

if you don't have a unit circle to look at, then it helps to know that the fraction \(\frac{\sqrt{2} }{2}\) is ONLY found with ITSELF OR THE NEGATIVE OF ITSELF. it is never paired with another number.

this means that this number will only be seen in the coordinates

\((\frac{\sqrt{2} }{2} ,\frac{\sqrt{2} }{2})\\(-\frac{\sqrt{2} }{2},\frac{\sqrt{2} }{2})\\(-\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})\\(\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})\)

use this knowledge along with knowing the signs in each quadrant:

Q1: (+,+)

Q2: (–,+)

Q3: (–,–)

Q4: (+,–)

Answer:

6/1 GO GO GO

Step-by-step explanation:

The answer of the given question based on differential equation is ,

y² = (3/13)(C - x⁴)

An equation is mathematical statement that indicates  equality of two expressions. It consists of variables, constants, and mathematical operations like addition, subtraction, multiplication, division, exponentiation, etc. An equation can be written in different forms depending on the type of equation, like linear, quadratic, polynomial, trigonometric, exponential, or logarithmic.

The given differential equation is:

dy/dx = 4x³/(3x² + 13y²)

To find  general solution, we need to separate variables and integrate both sides:

(3x² + 13y²) dy = 4x³ dx

Integrating both sides:

∫(3x² + 13y²) dy = ∫4x³ dx

Simplifying and solving the integrals:

x⁴ + (13/3)y³ = x⁴ + C

where C is the constant of integration.

Therefore, the general solution to the given differential equation is:

y² = (3/13)(C - x⁴)

where C is an arbitrary constant.

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Answer: I would say 68 i believe this because if i do remember correctly you have to make it equal 192 and 68 did that.

Step-by-step explanation: Sorry if im wrong.

Self-confidence is an attitude about your skills and abilities. It means you accept and trust yourself and have a sense of control in your life. You know your strengths and weakness well, and have a positive view of yourself. You set realistic expectations and goals, communicate assertive

Answer:

All possible are:

(G,L,S)

(G,L,R)

(G,L,P)

(G,S,R)

(G,S,P)

(G,R,P)

(L,S,R)

(L,S,P)

(S,R,P)

{L,R,P)

Probability of 1st/2nd/10th sample = 1/10

Step-by-step explanation:

All the possible combinations of the 3 size samples from a 5 size population have been listed without repetition.

Total Numbers of Samples = 10

To find the probability of finding the first sample from random sampling procedure,

Probability = Number of desired outcomes/ Total number of outcomes

Where Number of desired outcome is 1 and total number of outcomes is 10.

Probability = 1/10

Similarly, to find 2nd sample or 10th sample, the number of desired outcomes is same i.e 1, hecne the probability remains the same i.e 1/10

Possible samples:

(G,L), (G,S), (G,A), (G,P), (L,S), (S,A), (A,P), (L,P), (S,P), (A,L).

a) Given:

Population size \(N=5\).

Sample size \(n=2\)

Possible sample (without replacement)

\(\Rightarrow 5C_{2}=\frac{5!}{2!\times 3!}\)

\(=\frac{5\times 4}{2}\)

\(=10\)

\(10 samples:-\)

Governor, Lieutenant Governor, secretary of state, Attorney General, Press (P)

Possible samples:

(G,L), (G,S), (G,A), (G,P), (L,S), (S,A), (A,P), (L,P), (S,P), (A,L).

b) Event: \(E\to\)choosing sample second and tenth.

\(E=\left\{\left ( G,S \right ),\left ( A,L \right ) \right\}\\n\left ( E \right )=2\\n(S) =10\)

The Probability of that it is the first sample.

Second and tenth sample\(=\frac{n\left ( E \right )}{n(S)}\)

                                           \(=\frac{2}{10}\)

                                           \(=\frac{1}{5}\)

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Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

To find the Taylor polynomials centered at x = 0 for the function f(x) = 16tan(x), we can use the Taylor series expansion for the tangent function and truncate it to the desired degree.

The Taylor series expansion for tangent function is:

tan(x) = x + (1/3)x^3 + (2/15)x^5 + (17/315)x^7 + ...

Using this expansion, we can find the Taylor polynomials of degree 2 and 3 centered at x = 0:

Degree 2 Taylor polynomial:

P2(x) = f(0) + f'(0)(x - 0) + (1/2!)f''(0)(x - 0)^2

= 16tan(0) + 16sec^2(0)(x - 0) + (1/2!)16sec^2(0)(x - 0)^2

= 0 + 16x + 8x^2

Degree 3 Taylor polynomial:

P3(x) = P2(x) + (1/3!)f'''(0)(x - 0)^3

= 0 + 16x + 8x^2 + (1/3!)(48sec^2(0)tan(0))(x - 0)^3

= 16x + 8x^2

Therefore, the Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

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Answer:

5x when x = -7 is equal to -35

Step-by-step explanation:

When x = -7

5(-7) = -35

Answer:

120.00

Step-by-step explanation:

Let x be the original price

The price is 10% off, or we pay 90% of the original price

.9 x

Then we have to pay 7% sales tax

.9x * 7%

.9x * .07

.063x is the tax

Add this to the .9x we have to pay for the jacket

.9x + .063x = .963x

This is the cost of the jacket

.963x = 115.56

Divide each side by.963

.963x/.963 = 115.56/.963

x =120.00

The cost of the jacket before discount and tax is 120.00

The area of the garden whose length and width as given in the task content is; 30 (x + 2) square units.

It follows from the task content that the expression which represents the area of the garden plot whose dimensions are as given.

Recall that Area, A = length × width.

Therefore, since length = 6 (√(x + 2)) units

The width = (5 √(x + 2) ) units

Hence, the area of the garden plot as required in the task content is; 6 (√(x + 2)) × ( 5 √(x + 2) )

= 30 (x + 2) square units

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a. The probability of exactly 4 successes is approximately 0.2967.

b. The probability of 5 or more successes is approximately 0.5332.

c. The probability of exactly 6 successes is approximately 0.1399.

d. The expected value of the random variable is 3.96

To solve these problems, we'll use the binomial probability formula:

P(X = k) = C(n, k)× \(p^{k}\)× \((1-p)^{(n-k)}\)

where:

P(X = k) is the probability of getting exactly k successes,

n is the sample size,

p is the probability of success,

C(n, k) is the number of combinations of n items taken k at a time.

Now let's solve each part of the problem:

a. The probability of exactly 4 successes:

P(X = 4) = C(6, 4) × (0.66)⁴ × (1 - 0.66)⁽⁶⁻⁴⁾

C(6, 4) = 6! / (4! × (6 - 4)!) = 6! / (4! × 2!) = (6 × 5) / (2 × 1) = 15

P(X = 4) = 15 × (0.66)⁴ × (0.34)² ≈ 0.2967 (rounded to four decimal places)

b. The probability of 5 or more successes:

P(X ≥ 5) = P(X = 5) + P(X = 6)

P(X = 5) = C(6, 5) × (0.66)⁵ × (1 - 0.66)⁽⁶⁻⁵⁾ = 6 × (0.66)⁵ × (0.34)¹ ≈ 0.3933

P(X = 6) = C(6, 6) × (0.66)⁶ × (1 - 0.66)⁽⁶⁻⁶⁾ = 1 × (0.66)⁶× (0.34)⁰ = 0.1399

P(X ≥ 5) = P(X = 5) + P(X = 6) = 0.3933 + 0.1399 ≈ 0.5332 (rounded to four decimal places)

c. The probability of exactly 6 successes:

P(X = 6) = C(6, 6) × (0.66)⁶ × (1 - 0.66)⁽⁶⁻⁶⁾ = 1 × (0.66)⁶ × (0.34)⁰= 0.1399

d. The expected value of the random variable:

The expected value (mean) of a binomial distribution is given by:

E(X) = n × p

E(X) = 6 × 0.66 = 3.96

Therefore:

a. The probability of exactly 4 successes is approximately 0.2967.

b. The probability of 5 or more successes is approximately 0.5332.

c. The probability of exactly 6 successes is approximately 0.1399.

d. The expected value of the random variable is 3.96

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The number of full revolutions that Liz's front wheel completed is  16,037 full revolutions.

First, we need to find the circumference of the wheel. The formula for the circumference of a circle is C = 2πr, where r is the radius of the circle. In this case, the radius of the wheel is 54 cm, so we can plug that into the formula:

C = 2π(54 cm) = 108π cm

Next, we need to convert the total distance traveled from kilometers to centimeters, so that we can divide by the circumference of the wheel in centimeters.

There are 100,000 centimeters in a kilometer, so we can multiply the distance traveled in kilometers by 100,000 to get the distance in centimeters:

54.82 km * 100,000 cm/km = 5,482,000 cm

Now we can divide the total distance traveled by the circumference of the wheel to find the number of full revolutions:

5,482,000c m / 108π cm = 16,037.35

So, Liz's front wheel completed approximately 16,037 full revolutions.

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Answer:

perpendicular gradient = - \(\frac{1}{4}\)

Step-by-step explanation:

given a line with gradient m then the gradient of a line perpendicular to it is

\(m_{perpendicula}\) = - \(\frac{1}{m}\) = - \(\frac{1}{4}\)

By using the approximation of 62,500 inches to the mile, you can simplify and expedite various calculations involving distances and conversions between inches and miles, providing a convenient tool for numerical analysis and problem-solving

The approximation of 62,500 inches to the mile is commonly used in various calculations, especially in scenarios where conversions between inches and miles are involved. This approximation simplifies the conversion process and allows for easier calculations.

For example, if you need to convert a distance from miles to inches, you can simply multiply the number of miles by 62,500 to obtain the equivalent distance in inches. Conversely, if you have a measurement in inches and want to convert it to miles, you divide the number of inches by 62,500 to get the distance in miles.

Additionally, this approximation can be useful in other applications, such as determining the number of inches in a given number of miles, or calculating the length of a specific distance in miles based on its measurement in inches.

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.

Answer:

I do strongly believe that it is none other than option 4: cone with a height of 5 meters and a radius of 3 meters

Step-by-step explanation:

To find the percentage, we can use the following formula:

Percentage = (Part / Whole) * 100

So, $131,701.32 is approximately 16.67% of $790,207.91.

In this case, the part is $131,701.32 and the whole is $790,207.91.

Percentage = ($131,701.32 / $790,207.91) * 100

Calculating the value:

Percentage ≈ 0.1667 * 100

Percentage ≈ 16.67%

Therefore, $131,701.32 is approximately 16.67% of $790,207.91.

Alternatively, we can calculate the percentage by dividing the part by the whole and multiplying by 100:

Percentage = ($131,701.32 / $790,207.91) * 100 ≈ 0.1667 * 100 ≈ 16.67%

So, $131,701.32 is approximately 16.67% of $790,207.91.

If you have any further questions, feel free to ask!

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Therefore, we cannot answer this question by giving a specific memory address or a specific value as the answer. However, we can state that the answer is unknown.

In this scenario, we are looking for the address of the machine instruction in decimal which follows the line of code, given that the values in LEGv8 registers are decimal numbers.

This means that we are looking for a memory address which is also a decimal number. Given that we do not have any additional information, we can assume that this machine instruction follows the line of code which includes the registers whose values are given.

Let us break down the registers:X1 = 7X2

= 13X3

= 2X4

= 20X5

= 9From the above registers, it appears that the machine instruction which follows the line of code that includes these registers, is not yet known or provided.

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There were 7 students who signed up but did not attend the field trip. There were 36 students who initially signed up to go on the field trip. However, on the day of the trip, only 29 students showed up.

On the day of the field trip, only 29 students were present out of the 36 students who initially signed up.

There were 36 students who initially signed up to go on the field trip. However, on the day of the trip, only 29 students showed up. This means that 7 students who had originally signed up did not attend the trip.

The difference between the initial number of sign-ups (36) and the number of students present (29) gives us the number of students who did not show up:

36 - 29 = 7.

Therefore, there were 7 students who signed up but did not attend the field trip.

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An.swer:

171.68

Step-by-step explanation:

It's B.

You can think of the action of multiplying matrix A onto any other matrix X as

• preserving the first row of X due to the +1 in the first column of the first row,

• negating the second row of X due to the -1 in the second column of the second row, and

• preserving the third row of X due to the +1 in the third column of the third row.

Answer: B.

Step-by-step explanation: I got this right on Edmentum.

Answer:

1 = x

Step-by-step explanation:

x+5/4 = 2x+1/2

We can use cross products to solve

2(x+5) = 4(2x+1)

Distribute

2x+10 = 8x+4

Subtract 2x from each side

2x+10-2x = 8x-2x+4

10 = 6x+4

Subtract 4 from each side

10-4 = 6x+4-4

6 = 6x

Divide by 6

6/6 = 6x/6

1 = x

Solution

The following are all 5 quiz scores of a student in a statistics course. Each quite was graded on a 10-point scale

Where, n = 5

To find the standard deviation, firstly we will find the mean

Secondly, we will subtract the mean from each score

The standard deviation will be

Hence, the standard deviation is 0.63 (two decimal places)

(a) Solve the normal equation (A^T A)x = A^T b to find all least squares solutions of the linear system Ax = b. (b) Compute projcol(A) b using the projection matrix P = A(A^T A)^(-1) A^T. (c) Calculate the least squares error ||b - projcol(A) b||, which measures the fitting error of b to col(A).

(a) To find all the least squares solutions of the linear system Ax = b, we need to find the vector x that minimizes the squared norm of the residual vector Ax - b. This can be done by solving the normal equation (A^T A)x = A^T b.

(b) The orthogonal projection projcol(A) b of b onto col(A) can be found by projecting b onto the column space of A. This can be done by computing the projection matrix P = A(A^T A)^(-1) A^T and applying it to b, i.e., projcol(A) b = P b.

(c) The least squares error ||b - projcol(A) b|| is the norm of the residual vector, which represents the difference between the original vector b and its orthogonal projection onto col(A). It quantifies the error in fitting b to the column space of A.

To provide specific numerical values and solutions for parts (a), (b), and (c), the complete matrix A and vector b need to be provided. Without the complete information, it is not possible to give a detailed explanation or solve the problem.

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Answer:

991041.2

Step-by-step explanation:

You just have to use a calculator and the order of operations

a) The bird would fly approximately 4.17 km in a straight line from the starting point to the final point. b) The bird would fly at an angle of approximately 47.46 degrees counterclockwise from the east.

To find the distance and angle that a bird would fly in a straight line from the starting point to the final point, we can use the concept of vector addition.

(a) Distance:

The person's total displacement can be represented as a vector sum of their individual movements: 2.8 km north + 2.9 km west - 5.8 km south.

To simplify this, we can break it down into horizontal (x-axis) and vertical (y-axis) components:

Horizontal displacement = -2.9 km (west)

Vertical displacement = 2.8 km (north) - 5.8 km (south) = -3 km (south)

Now, we can calculate the straight-line distance using the Pythagorean theorem:

Distance = √(Horizontal displacement² + Vertical displacement²)

= √((-2.9 km)² + (-3 km)²)

= √(8.41 km² + 9 km²)

= √(17.41 km²)

≈ 4.17 km

Therefore, the bird would fly approximately 4.17 km in a straight line from the starting point to the final point.

(b) Angle:

To determine the angle counterclockwise from the east, we can use trigonometry. The angle can be found using the inverse tangent function:

Angle = arctan(Vertical displacement / Horizontal displacement)

= arctan((-3 km) / (-2.9 km))

= arctan(1.034)

≈ 47.46 degrees

Therefore, the bird would fly at an angle of approximately 47.46 degrees counterclockwise from the east.

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Answer:

9x=9×0=0

∴y=0+4=4

Answer:

no por que ella no te ama lo siento

Answer:

1/2

Step-by-step explanation:

Given that,

\(\lim_{n \to 1} (\dfrac{1+\cos\pi x}{\tan^2\pi x})\)

Using L Hospital's rule to find it :

\(\lim_{n \to a} \dfrac{f(x)}{g(x)}= \lim_{n \to a} \dfrac{f'(x)}{g'(x)}\)

We have,

a = 1, \(f(x)=1+\cos\pi x, \ \ g(x)=\tan^2\pi x\)

\(f'(x)=\dfrac{d}{dx}(1+\cos\pi x)\\\\=-\pi \sin \pi x\ .....(1)\)

\(g'(x)=\dfrac{d}{dx}(\tan^2\pi x)\\\\=2\tan\pi x\times \sec^2\pi x\times \pi\ .....(2)\)

From equation (1) and (2) :

\(\lim_{n \to 1} \dfrac{f(x)}{g(x)}= \lim_{n \to 1} \dfrac{-\pi \sin\pi x}{2\tan \pi x\times \sec^2\pi x \times \pi}\\\\\lim_{n \to 1} \dfrac{-\pi \sin\pi x}{2\tan \pi x\times \sec^2\pi x \times \pi}\\\\=\lim_{n \to 1} \dfrac{-1}{2}\times\cos^3\pi x\\\\=\dfrac{-1}{2}\times \cos^3\pi \\\\=\dfrac{1}{2}\)

So, the value of the given function is 1/2.