in the figure, two solenoids are approaching each other with speed v as shown. the induced current through the resistor r is

The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.

The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.

Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.

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Answer: The statement when the motion energy of an object changes, energy is being transferred is true.

Explanation:

Motion energy is also called mechanical energy and it is the summation of kinetic energy and potential energy stored in an object required for work.

As kinetic energy is the energy acquired due to motion of an object and potential energy is the energy acquired by an object due to its position.

For example, when a moving ball strikes another ball causing it to move then energy is being transferred from one ball to another.

Therefore, the statement when the motion energy of an object changes, energy is being transferred is true.

The current of 4.00 A must be applied for approximately 3.53 hours to produce 2.0 grams of copper metal.

The problem can be solved using Faraday’s Law. Faraday’s Law states that the mass of a substance produced is directly proportional to the amount of electricity (in Coulombs) used. This is usually written as:

m = z × F × n

where: m is the mass of substance produced

            z is the number of moles of electrons transferred (the number of electrons involved in the reaction)n is the number of moles of the substance.

            F is the Faraday constant (96,485 coulombs/mole)

The first step is to balance the equation for the reaction. The half-reaction for the reduction of copper ions to copper metal is:

Cu2+ + 2e- → Cu

The number of moles of electrons transferred (z) is 2. The number of moles of copper produced (n) is found from the number of grams of copper given. The atomic mass of copper is 63.55 g/mol, so:

2.0 g Cu / 63.55 g/mol = 0.0315 mol Cu

To find the amount of charge (in Coulombs) needed to produce this amount of copper, we rearrange Faraday’s Law:

m / (z × n × F) = q

The charge is found by multiplying the current (I) by the time (t):q = I × t

We can combine these two equations to get the time needed to produce the desired amount of copper: t = m / (z × n × F × I). Plugging in the values:

t = (0.0315 mol Cu) / (2 mol e- / mol Cu × 96,485 C/mol e- × 4.00 A) = 12,700 s or 3.53 hours

Therefore, the current of 4.00 A must be applied for approximately 3.53 hours to produce 2.0 grams of copper metal.

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Answer:

NASA satellites help scientists study Earth and space. Satellites looking toward Earth provide information about clouds, oceans, land and ice. They also measure gases in the atmosphere, such as ozone and carbon dioxide, and the amount of energy that Earth absorbs and emits. And satellites monitor wildfires, volcanoes and their smoke.

Explanation:

Hope this helps! :) have a great day.

1. GPS

2. Internet

3. Weather forecast

4. Observation

5. Experiments

6. Discovery

Prior to an exam, it is customary for you to read the relevant legal texts, repeat them out to yourself, and then pray that no one from your town remembers you when you are in the exam room.

The exact meaning of law is up for debate, but it is generally understood to be a set of regulations that are made and enforced by social or governmental institutions to control behavior. It has been called both a science and the practice of justice in diverse contexts.

A law is a behavior guideline or set of behavior guidelines that the majority of people believe to be appropriate and significant for moral, religious, or emotional reasons.

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Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

The ball will hit the ground after 0.408 sec and the horizontal range of the projectile is 1.414 m.

When a particle throws obliquely near the surface, it follows along a curved path under constant acceleration directed towards the center of the earth. The path followed by the particle and the motion is called projectile motion.

Consider the 'u' is the initial velocity of the particle and θ is the angle with the horizon,

The time of the flight =  (2u sinθ)/g

The horizontal range (R) = (u² sin2θ)/g

Given, the initial velocity of the projectile, u 4 m/3

The angle above the horizon, θ = 30°

The time  the ball falls back and hits the ground (t):

t = (2u sinθ)/g = (2 × 4 sin30)/9.8 = 0.408 s

The horizontal range (R) of the projectile = (u² sin2θ)/g

R = (4² sin60)/9.8

R = 1.413 m

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False. The orbits of most planets have eccentricities greater than zero. Eccentricity is a measure of how much an orbit deviates from a perfect circle. A value of zero would indicate a perfect circle, while a value closer to one indicates a more elongated, elliptical orbit.

In our solar system, only Venus and Neptune have orbits with eccentricities close to zero, while the other planets have eccentricities ranging from 0.01 (Jupiter) to 0.25 (Mercury). The dwarf planet Pluto has the most eccentric orbit of all, with a value of 0.25.

The eccentricity of a planet's orbit can have important implications for its climate and potential habitability. For example, a planet with a highly elliptical orbit would experience extreme variations in temperature between its closest approach to the sun (perihelion) and farthest point (aphelion), which could make it difficult for life to survive.

In summary, most planets in our solar system have elliptical orbits with eccentricities greater than zero, which can affect their climate and potential for habitability.

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Explanation:

The units of pressure is called derived units because it is simply derived from base unit which is distance and a derived unit which is force, which is derived from acceleration, a derived unit as well, and mass, a base unit. As we all know, work is defined as the force x distance. Thus making work a derived unit.

To calculate the average torque that produces this change in angular momentum, we can use the formula: Average Torque = Change in Angular Momentum / Time, Change in Angular Momentum = 50 kg x m^2/s (final) - 0 kg x m^2/s (initial) = 50 kg x m^2/s and Time = 0.25 s

Average Torque = (50 kg x m^2/s) / 0.25 s = 200 Nm
The average torque that produces this change in angular momentum is 200 Nm.
Angular velocity at the end of the 0.25 s, we can use the formula:
Angular Velocity = Angular Momentum / Moment of Inertia
Angular Momentum = 50 kg x m^2/s
Moment of Inertia = 2.2 kg x m^2
Angular Velocity = (50 kg x m^2/s) / (2.2 kg x m^2) ≈ 22.73 rad/s
At the end of the 0.25 s, Sarah's twist angular velocity is approximately 22.73 rad/s.

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The Perseid meteors repeat regularly around August 11th or so, despite everything in the solar system moving around, because the debris that creates them follows a consistent orbit.

The orbit of the debris producing the meteor shower is consistent, and it orbits the Sun in the same manner every year. When the Earth crosses through the debris stream, the debris enters the Earth's atmosphere and burns up, producing the Perseid meteor shower.This means that even if the Earth's movement is unpredictable, as it revolves around the Sun, the Perseid meteor shower will occur around the same time every year.

Hence, it's not because of the Earth's movement or other bodies in the solar system that the Perseid meteors repeat regularly around August 11th or so, but because of the consistent orbit of the debris that creates them.

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Answer:

F = 9.177*10^-9N

Explanation:

Gravitational force between the two bodies is expressed as;

F = GMm/r²

Given tha

M = 55kg

m = 10kg

r = 2m

G = 6.67408 × 10-11 m³ kg-1 s-2

Substitute;

F = GMm/r²

F = 6.67408 × 10-11*55*10/2²

F = 3,670.744× 10-11/4

F = 9.177*10^-9N

Answer:

4 is the answer I know it it came to me also if it is worng i am sorry

Explanation:

Answer:

I don't know

Explanation:

The impulse on the car is 12 kg m/s. Impulse is the integral of the force applied on the object and the time period for which it is applied.

Impulse is the integral of a force, F, over the time interval, t, for which it acts on an object. Since, force is a vector quantity, therefore impulse is also a vector quantity because it has both the magnitude and direction. Impulse applied to an object produces an equivalent vector change in its linear momentum. The SI unit of impulse is the newton second (N⋅s) or kilogram meter per second (kg⋅m/s).

Impulse = Change in momentum

ΔP = F × ΔT

where, F = Force applied on the object,

ΔT = change in time

ΔP = Pf - Pi

where, ΔP = change in momentum,

Pf = final momentum = m × v,

Pi = initial momentum = m × u

Pf = 1.5 kg × 10 = 15 kg m/s

Pi = 1.5 × 2.0 = 3.0 kg m/s

ΔP = 15 - 3

ΔP = 12 kg m/s

Therefore, the impulse is 12 kg m/s.

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Objective:The objective of this experiment is to design a body ("slider") that can slide as quickly as possible down an inclined plane that is lubricated with SAE 10W-40.

The experiment is intended to identify the most efficient slider design, including material selection and weight, to optimize the slide down an inclined plane.In the following, we will explore the design for the slider and the inclined plane, which includes size and material specifications.Slider:Size:The slider should have a mass of no more than 0.5 kg. It's critical to ensure that the slider's weight doesn't create too much friction, slowing it down and making it less efficient.Material: Any metal alloy can be used for the slider's production.

However, lighter metal alloys, such as aluminum and titanium, are preferred because they reduce friction and improve sliding speed.Inclined Plane (Runway):Material:The runway is made of Lexan sheets on a wooden substrate. Lexan is a tough polycarbonate plastic that is commonly used in the construction of bulletproof windows and skylights. Its high-impact resistance and strength make it an excellent option for the inclined plane, reducing the possibility of damage from repeated testing.Length (sliding direction):

The sliding direction of the inclined plane is 2.0ft, providing sufficient distance for the slider to reach maximum speed.Inclination:The inclination of the inclined plane is 2.7 degrees, enabling the slider to slide quickly while still retaining control.Width:The inclined plane is 1.0ft wide, providing ample room for the slider to move freely while also ensuring that it does not wobble or shift sideways during the test.

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Storm surge occurs when a large and powerful storm, such as a hurricane or typhoon, moves across a body of water and pushes the water towards the shore. This results in a sudden and dangerous rise in sea level, which can cause devastating flooding and destruction in coastal areas.

The storm surge of super-typhoon Haiyan was so dangerous because it was one of the strongest storms ever recorded, with sustained winds of up to 195 mph. As it made landfall in the Philippines, it pushed a massive wall of water towards the shore, which reached heights of up to 30 feet in some areas. This caused widespread flooding and destruction, and was responsible for many of the more than 6,000 deaths that occurred as a result of the storm. The storm surge also caused significant damage to infrastructure, homes, and businesses, and made rescue and relief efforts more difficult and dangerous. Overall, the storm surge of super-typhoon Haiyan serves as a stark reminder of the devastating power of these types of storms, and the importance of preparedness and emergency planning in coastal communities.

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Coefficient of friction is calculated to be 0.4. Therefore, a) will be the correct answer .

Frictional force is that force which is generated by two surfaces that contact and slide against each other. Factors affecting the frictional force are the surface texture and the amount of force impelling them together.

The frictional force is said to be a contact force as frictional force occur when two surfaces come in contact with each other.

Given applied force = 60 N

weight of object = 50N;  friction force = 20N

As we know that, Coefficient of friction =  force of friction/normal force

= 20/50

Coefficient of friction = 0.4

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The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:

1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.

2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.

3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.

4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.

5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.

These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.

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Answer:

His third law states that for every action or force in nature there is an equal and opposite reaction.

Explanation:

The heavier the books get, the harder it is for Molly to exert enough force to move the cart.

I hope this helps!!!!!!   Please mark me brainliest!!

Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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The launch angle of the projectile is approximately 30.96 degrees. To determine the launch angle of the projectile, we can use the relationship between the maximum height and horizontal range.

The maximum height is related to the horizontal range through trigonometric functions. By solving the equation for the given ratio of maximum height to horizontal range, we can find the launch angle. In this case, the launch angle of the projectile is approximately 30.96 degrees.

Let's assume the launch angle of the projectile is θ. We know that the maximum height (H) is related to the horizontal range (R) by the equation H = (2/5)R.

The maximum height can be calculated using the equation H = (v² * sin²θ) / (2g), where v is the initial velocity of the projectile and g is the acceleration due to gravity.

The horizontal range can be calculated using the equation R = (v² * sin2θ) / g.

By substituting these equations into the given ratio (H = (2/5)R), we have:

(v² * sin²θ) / (2g) = (2/5) * (v² * sin2θ) / g.

Simplifying the equation, we get sin²θ = (4/5) * sin2θ.

Using the double-angle identity for sine, sin2θ = 2sinθcosθ, we can rewrite the equation as sin²θ = (4/5) * 2sinθcosθ.

Further simplifying, we have sin²θ = (8/5)sinθcosθ.

Dividing both sides by sinθ, we get sinθ = 8/5cosθ.

Now, we can use the trigonometric identity sin²θ + cos²θ = 1 to solve for cosθ: cosθ = √(1 - sin²θ).

Substituting sinθ = 8/5cosθ into the equation, we have cosθ = √(1 - (8/5cosθ)²).

Squaring both sides of the equation, we get cos²θ = 1 - (64/25)cos²θ.

Rearranging the equation, we have (25/25)cos²θ + (64/25)cos²θ = 1.

Simplifying, we find (89/25)cos²θ = 1.

Dividing both sides by (89/25), we have cos²θ = 25/89.

Taking the square root of both sides, we get cosθ = √(25/89).

Finally, we can find the launch angle θ by taking the inverse cosine \((cos^(-1))\) of √(25/89).

Evaluating the expression, we find θ ≈ 30.96 degrees.

Therefore, the launch angle of the projectile is approximately 30.96 degrees.

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Answer:

When you put un-like poles together (South facing North) you can feel magnetic attraction. In the Northern Hemisphere, your compass needle points North, but if you think about it for a moment, you will discover that the magnetic pole in the Earth's Northern Hemisphere has to be a South polarity.

Answer:

It depends...

Explanation:

If you know how much watts the pair of hair straighteners use, you can use that as the energy every second. A normal flat iron for hair would be 300 watts, so we could say that it uses 300 jolts or watts of energy per second.

Answer: No.

Explanation:

Firstly, I want to make the argument that objects moving in a straight line can have angular momentum (you'll see why later).

Suppose we have a particle located at \(\vec{r}=-y\hat{j}\), where r describes the position vector for any particle located at any point directly below the origin. Now suppose its momentum is described by \(\vec{p}=p\hat{j}\), where p is a positive scalar quantity (in other words, the particle has a momentum that drives its motion upward). Angular momentum is a vector quantity and is described by \(\vec{L} = \vec{r} \times \vec{p}\). Since both vectors point in the \(\hat{j}\) direction, their cross products will give us 0 (you should convince yourself of this property if you don't believe it). Now suppose we shift this object some distance d to the right, such that its new position vector is described by \(\vec{r}=d\hat{i}-y\hat{j}\). The \(\hat{j}\) components still cancel, but \(\hat{i} \times \hat{j} = \hat{k}\), so our cross product for angular momentum yields \(\vec{L}=\vec{r} \times \vec{p}=d\hat{i} \times p\hat{j}=dp\hat{k}\). So despite having the same motion (momentum), the particle has an angular momentum. This tells us two important characteristics about angular momentum:

Please see attachment for an image reference if you cannot picture/diagram this (ignore the gravitational force drawn on the particle).

Now, lets take a system of particles. Suppose we have two particles on the x-axis with mass m, a distance d from the origin on either side, and velocities such that one particle moves to the right and the other moves to the left. For a system, angular momentum is defined as the following:

\(\vec{L}=\sum_i \vec{r_i} \times \vec{p_i}=\sum_i m_i(\vec{r_i} \times \vec{v_i})\)

Note: mass is a scalar quantity, so the cross product is not defined for it.

For this system, we can write out the angular momentum as the following:

\(\vec{L}=m(d\hat{i} \times v\hat{i}) + m(-d\hat{i} \times -v\hat{i})\)

However, we established above that the cross product of two identical vectors yields a result of 0. So we get that the angular momentum is 0, and yet both particles move, just that one moves to the right while the other moves to the left. In other words, the total angular momentum of the system is zero while the particles are not at rest.

If this is confusing, think about it in a more mathematical way. Angular momentum is a vector quantity, and thus follows the rules of vector algebra. In other words,

\(\vec{L}=\vec{L_1}}+\vec{L_2}}+\vec{L_3}}+...+\vec{L_n}}\)

This is known as superposition. Suppose we constructed a system of two particles where their cross products didn't evaluate to 0. We can still use the principle of superposition to create a scenario where the angular momentum is 0.

Suppose we have a system of 2 particles where \(\vec{L_1} = -\vec{L_2}\). The total angular momentum would be defined as

\(\vec{L}=\vec{L_1}+\vec{L_2}=\vec{L_1}-\vec{L_1}=0\).

Now it doesn't matter if the particles move in a straight line, a circular path, or any other type of motion. If their individual angular momentums are equal in magnitude and opposite in direction, the angular momentum of the system is zero without the particles needing to be necessarily at rest.

Answer:

It is 37.4786

Answer:

Option B (350) is the correct answer.

Explanation:

Given:

The temperature is "88°F" i.e., x.

Let number of visitors be "y".

Let the two points will be:

84,225 = (x₁, y₁)

92, 450 = (x₂, y₂)

As we know,

⇒  \(y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})\)

On substituting the values, we get

⇒  \(y-225=\frac{450-225}{92-84}(88-84)\)

⇒  \(y=337.5\)

So that alternative B is the appropriate choice.

Answer:

Loudness of sound is determined by its amplitude.

Loudness of sound is determined by its amplitude.The intensity or loudness of a sound depends upon the extent to which the sounding body vibrates, i.e., the amplitude of vibration. A sound is louder as the amplitude of vibration is greater, and the intensity decreases as the distance from the source increases.

The speed of the ball, after it bounces back elastically toward you, is approximately 68333.33 m/s.

Initially, the rhino and the ball are moving in opposite directions, so their total momentum is zero. After the collision, the ball bounces back, and the rhino continues moving forward.

Let's calculate the momentum of the rhino before the collision:

Momentum of the rhino = mass of the rhino × velocity of the rhino

= 3000 kg × 4.10 m/s

= 12300 kg·m/s

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since the rhino continues moving forward, the ball's momentum must be equal in magnitude but opposite in direction.

Let's denote the final velocity of the ball as v:

Total momentum after the collision = momentum of the rhino + momentum of the ball

= 0 + (mass of the ball × final velocity of the ball)

= 0.180 kg × v

Setting the initial and final momenta equal, we have:

12300 kg·m/s = 0.180 kg × v

Solving for v, we find:

v = 12300 kg·m/s / 0.180 kg

v ≈ 68333.33 m/s speed of ball

To learn more about speed follow the link:

https://brainly.com/question/28224010

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