Answer: I am assuming it is decreases
Explanation: a straight line is 180 degrees. 2 angles both add up to 180 degrees on a straight line. When one increases, the other has to decrease to keep it 180 degrees on a straight line
a ball is thrown horizontally from the top of s vertical tower and strikes the ground at point 50m from the bottom of the tower. Given that the height of the tower is 45m, determine the
a)time taken for the ball to hit the ground
b)the initial horizontal velocity of the ball
c)The vertical height of the ball just before striking the ground(take acceleration due to gravity as 10m/s)
Answer:
B
Explanation:
A 7.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball. How fast does the ball need to be moving in order to send the man off at a speed of 3.00 m/s?
Answer:
35.14 m/s
Explanation:
The Law of Conservation of Momentum states that the momentum before and after a collision is the same.
m₁ v₁ + m₂ v₂ = m₁ v₁ + m₂ v₂Let's set the ball to have the subscript of 1 and the man to have the subscript of 2.
The initial and final mass of the ball is the same, so m₁ = 7.00 kg on both sides of the equation.
The initial velocity of the ball, v₁ on the left side of the equation, is the unknown variable we are trying to find.
The initial and final mass of the man is the same, so m₂ = 75.0 kg on both sides of the equation.
The man starts at rest, meaning that his initial velocity is v₂ = 0 m/s on the left side of the equation.
The final velocity of both the ball and the man is 3.00 m/s, so we can set v₁ and v₂ on the right side of the equation to equal 3.00 m/s.
Left side of the equation:
m₁ = 7.00 kg v₁ = ?m₂ = 75.0 kgv₂ = 0 m/sRight side of the equation:
m₁ = 7.00 kg v₁ = 3.00 m/sm₂ = 75.0 kgv₂ = 3.00 m/sSubstitute these values into the Law of Conversation of Momentum formula.
(7.00) v₁ + (75.0)(0) = (7.00)(3.00) + (75.0)(3.00)Multiply and simplify.
7.00 v₁ = 21 + 225 7 v₁ = 246Divide both sides of the equation by 7.
v₁ = 35.14 m/sThe ball needs to be moving at a speed of 35.14 m/s in order to send the man off at a speed of 3.00 m/s.
Complete the light transformation diagrams in the given situations. Choose from the given words below. Answers may be repeated.
Here are the answers you can choose from:
chemical energy
electricity
heat energy
sound energy
kinetic energy
light energy
Here are the diagrams:
sunlight -------> solar panels -------> stereo playing
1. ____________ - 2. ____________ - 3. ____________
sunlight -------> land absorbs -------> changes in air temperature result in the movement of winds
4. ____________ - 5. ____________ - 6. ____________
sunlight -------> photosynthesis -------> horses can move after feeding on plants
7. ____________ - 8. ____________ - 9. ____________
sunlight -------> wearing a dark-colored shirt
10. ____________ - 11. ____________
sunlight -------> solar panel -------> cars operated via solar panel
12. ____________ - 13. ____________ - 14. ____________
1) Light energy ----> 2) Electricity ----- > 3)Sound energy
4) Light energy ------> 5) Heat energy ----> 6) Kinetic energy
7) Light energy ----> 8) Chemical energy -----> 9) Kinetic energy
10) Light energy -----> 11) Heat energy
12) Light energy ------> 13) Electrical energy -----> 14) Kinetic energy
What is energy transformation?We know that energy transformation has to do with the change of the energy from one form to the other. We have to note that from the first law of thermodynamics, it is clear that energy can not be created nor destroyed but it can be transformed from one form to the other.
Now, we have to note that in all the cases that we have below, there is the transformation of energy from one form to the other as shown above.
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Sam heaves a 16 lblb shot straight upward, giving it a constant upward acceleration from rest of 36.0 m/s2m/s2 for a height 68.0 cmcm. He releases it at height 2.30 mm above the ground. Ignore air resistance.
A) What is the speed of the shot when he releases it?Express your answer with the appropriate units.
B) How high above the ground does it go?Express your answer with the appropriate units.
C) How much time does he have to get out of its way before it returns to the height of the top of his head, a distance 1.73 mm above the ground?
Express your answer with the appropriate units.
The time taken by the shot to reach the height of Sam's head is 0.196 s.
The initial velocity of the shot u = 0 m/s.
Acceleration, a = 36.0 m/s²
Displacement, s = 68 cm = 0.68 m
We can use the formula v² = u² + 2as, where v is the final velocity of the shot.
v² = u² + 2asv² = 0 + 2(36.0 m/s²)(0.68 m)
= 49.536 m²/s²v = √(49.536 m²/s²) = 7.04 m/s
Therefore, the speed of the shot when Sam releases it is 7.04 m/s. (DETAIL ANS)
B) Let h be the maximum height the shot reaches above the ground.
Using the equation v² = u² + 2as, we can find the maximum height, h.
v² = u² + 2ash = (v² - u²) / (2a)h = (7.04 m/s)² / (2 × 36.0 m/s²) = 0.707 m
Therefore, the height that the shot reaches above the ground is 0.707 m. (DETAIL ANS)
C) Sam's height is 1.73 m above the ground.
We can find the time taken by the shot to reach the height of Sam's head using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken
.v = u + atv = 0 + (36.0 m/s²)t = 36.0tt = v / at = (7.04 m/s) / (36.0 m/s²) = 0.196 s
Therefore, the time taken by the shot to reach the height of Sam's head is 0.196 s. .
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Approximately how many seconds does it take for sound to travel 15 metres in freshwater at 25oC
The time it will take for a sound to travel 15 metres in freshwater at 25°C = 0.0097sec.
Calculation of speed of soundThe speed of sound in freshwater at 25°C = 1531 m/s
If 1531meters = 1 second
15 meters = ?
Make ? the subject of formula,
? = 15×1/1531
? = 0.009797517
Therefore, the time it will take for a sound to travel 15 metres in freshwater at 25°C =0.0097 sec.
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What determines the speed of a mechanical wave?
Answer:
Waves and Energy:
The speed of a wave is dependant on four factors: wavelength, frequency, medium, and temperature. Wave speed is calculated by multiplying the wavelength times the frequency (speed = l * f).
Explanation:
brainlest pls if u can ty ! i hope its helped.
Which type of bond and how many bonds would occur as carbon dioxide.. (CO2) is formed from carbon in Group IVA and oxygen in Group VIA?
A. three metallic bonds
B. two ionic bonds
C. one covalent bond
D. four covalent bonds
Anything helps.
Answer:
four covalent bonds is the answer
a police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of:
Answer:
50 feet or more
Explanation:
In order to quickly respond to hazardous situation in a timely manner, it is important to be alert with all senses and there are situations such as while driving , the present of an hazard can only be heard, such as when other cars honk their horns
As such a citation can be issued by a police officer when a vehicle travels through the highway while using a sound amplification system which can be heard at a distance of 50 or more ft. outside the vehicle.
A police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of Fifty (50) feet or more.
Reaching one destination safely without any accidents is largely in the hand of the driver. As the auto vehicle can be a most deadly weapon and highway may be the most dangerous place in the world some of the rules is been implemented to ensure the safety of the people on the highways.
With open senses, the driver prevents any accidents. To prevent any accidents and respond within time. Driver must keep open his ears if any other driver is honking their horns.
Thus, A police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of Fifty (50) feet or more.
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The intensity of the distributed lood acting on the beams 25 kN/m.) Determine the magnitude of reaction at Express your answer to three significant figures and include the appropriate units O ? N Value Units Submit Request Answer Figure Part 6 1 of 1 Delane te zand y components of reaction all sing scalar notation Express your answers using three significant figures separated by a comma HV AED vec ?
The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.
What is the magnitude of reaction to the distributed load?The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.
Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.
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a boat can travel with a speed of 12km/hr in still water if the speed of the stream is 3km/hr, find the time taken by the boat to go 60 km downstream
With a speed of 12 km/hr in still water and a stream speed of 3 km/hr, the boat's downstream speed is calculated to be 15 km/hr. Hence, it would take 4 hours for the boat to cover a distance of 60 km downstream.
Speed of boat in still water = 12 km/hr
Speed of stream = 3 km/hr
Time taken by the boat to go 60 km downstream
We know that Speed = Distance/Time.
So, Time = Distance/Speed.
Let the distance covered downstream be D.
The speed of the boat downstream is calculated by adding the speed of the boat in still water and the speed of the stream:
Speed of boat downstream = Speed of boat in still water + Speed of stream
= 12 + 3
= 15 km/hr
Using the formula Time = Distance/Speed, we can determine the time taken by the boat to go 60 km downstream:
Time taken by the boat to go 60 km downstream = Distance/Speed
= 60/15
= 4 hours.
Therefore, the time taken by the boat to go 60 km downstream is 4 hours.
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Asking a question is the same thing as creating a hypothesis.
Answer:
That's not true. With an hypothesis, you are sure this whatever is going to work, open to being wrong. A question is just a question.
Explanation:
Hope this helps
when a test has the ability to measure what it is intended to measure, it is said to be:
When a medical test has the ability to measure what it is intended to measure, it is said to be valid.
Validity is a fundamental property of a test that refers to the degree to which it measures what it is intended to measure.
A test that is valid is one that accurately measures the construct or characteristic it is designed to measure.
For example, if a test is designed to measure reading comprehension, it should accurately measure reading comprehension, rather than measuring some other unrelated construct.
Validity is typically assessed through various methods, such as content validity, criterion validity, and construct validity.
Content validity refers to the extent to which a test measures the content it is supposed to measure, while criterion validity refers to the degree to which a test correlates with an established criterion or gold standard.
Construct validity refers to the degree to which a test measures the construct it is intended to measure, based on a theoretical framework or model.
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Using the results from your post-fitness assessment, write a three-paragraph reflection addressing the following questions. Be sure to address all portions of the prompt in your reflection.
Journal prompt to be answered in 3 fully developed paragraphs citing specific examples from the pre-assessment.
In paragraph 1, summarize your results for each part of the assessment. Were there areas that surprised you about your results(able to complete more or less than you thought)?
In paragraphs 2 and 3, respond to the following: What is the purpose of completing a post-assessment? How can you analyze the data and use it to create a plan? What areas of the assessment would like to improve upon? How have you improved from your pre-assessment?
In reflecting on the assessment results I found that I was generally able to complete most parts successfully
The areas covered in the assessmentHowever I was surprised by my performance in the section that required complex problem-solving skills as I struggled more than expected On the other hand I was pleased with my ability to communicate effectively in the written portion
The purpose of completing a post-assessment is to evaluate progress and identify areas for improvement By analyzing the data from the assessment I can identify strengths and weaknesses which helps in creating a development plan For instance if time management was an issue during the assessment strategies can be implemented to improve efficiency and task prioritization Analyzing the data allows for a focused approach to skill enhancement
One area I would like to improve upon is critical thinking I noticed that I sometimes struggled to analyze complex information and draw logical conclusions To address this I plan to practice critical thinking exercises engage in analytical discussions and seek out relevant resources On a positive note I have improved my time management skills since the pre-assessment becoming more conscious of time constraints and allocating my time more efficiently across different sections
In conclusion the post-assessment provides an opportunity for self-reflection and growth Analyzing the data identifying areas for improvement and implementing targeted strategies are key steps towards enhancing skills and performance
The progress made since the pre-assessment highlights the effectiveness of intentional practice and focused effort Continuous self-assessment and improvement will contribute to further strengthening of abilities and the achievement of personal goals
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Convert 5 (mi/hr) to [m/s]
Answer:
2.2352 m/s
Explanation:
divide the number of meter in a mile by the number of second in an hour
How dogs can help scientists better understand human disease
Answer:
They can also help us better understand human diseases. Because the development, progression and behavior of several disorders afflicting humans and dogs are so similar, understanding the genetic components of these diseases in dogs can give us an idea of what may be happening in humans.
Explanation:
.
The spool has a mass of 64kg and a radius of gyration kG = 0.3m If it is released from rest, determine how far its center descends down the plane before it attains an angular velocity omega = 10 rad / s Neglect the mas of the cord which is wound around the central core.
The coefficient of kinetic friction between the spool and plane at A is μk = 0.2
The spool center will descend up to 0.468 m before it attains an angular velocity omega = 10 rad / s
The Normal force can be calculated on a surface inclined by angle theta
Normal force = mass × gravitational acceleration × cos(theta)
since the angle of the plane is not mentioned, we will consider theta equal to 0.
Normal force = mass × gravitational acceleration × cos(theta)
Normal force = 64 kg × 9.8 m/s^2 × cos(0°)
Normal force = 627.2 N
The friction force can be calculated using the coefficient of kinetic friction:
Friction force = μk × Normal force
Friction force = 0.2 * 627.2 N
Friction force = 125.44 N
The work done by friction is equal to the change in kinetic energy,
Since the initial kinetic energy is 0:
Work done by friction = (1/2) × I × ω² - 0
Work done by friction = (1/2) × I × ω²
= (1/2) × (64 kg × (0.3 m)^2) × (10 rad/s)^2
Work done by friction = 288 J
To find the height h, we can now set the work done by friction equal to the gravitational potential energy:
Work done by friction = m × g × h
h = Work done by friction / (m × g)
h = 288 J / (64 kg ×9.8 m/s^2)
h ≈ 0.468 m
Therefore, the center of the spool descends approximately 0.468 meters down the plane before attaining an angular velocity of 10 rad/s.
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How much work do you do when you lift a 100 N child 0.5 m?
Answer:
50 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 100 × 0.5
We have the final answer as
50 JHope this helps you
Una sirena que emite un sonido de f=100Hz se mueve alejandose de un observador en reposo y dirigiendose hacia un acantilado con velocidad constante de v1=20 m/s.
Given that,
Frequency = 100 Hz
Velocity = 20 m/s
Suppose, Determinar la diferencia de frecuencia entre la onda que recibe el observador directamente de la sirena y la onda que le llega reflejada en el acantilado.
We need to calculate the frequency heard by the observer directly from source
Using formula of frequency
\(f_{1}=f\times(\dfrac{v}{v-v_{s}})\)
Where, v = speed of sound
\(v_{s}\) = speed of source
f = frequency of source
Put the value into the formula
\(f_{1}=100\times\dfrac{340}{340-20}\)
\(f_{1}=106.25\ Hz\)
We need to calculate the frequency heard by the observer coming after reflection from cliff
Using formula of frequency
\(f_{2}=f\times(\dfrac{v}{v+v_{s}})\)
Put the value into the formula
\(f_{2}=100\times\dfrac{340}{340+20}\)
\(f_{2}=94.4\ Hz\)
We need to calculate the difference of frequency
Using formula for difference of frequency
\(\Delta f=f_{1}-f_{2}\)
Put the value into the formula
\(\Delta f=106.25-94.4\)
\(\Delta f=11.85\ Hz\)
Hence, The difference of frequency is 11.85 Hz.
A ball is rolled twice across the same level laboratory table and allowed to roll off
the table and strike the floor. In each trial, the time it takes the ball to travel from the
edge of the table to the floor is accurately measured. [Neglect friction.]
a) In trial A, the ball is traveling at 2.50 meters per second when it reaches
the edge of the table. The ball strikes the floor 0.391 second after rolling
off the edge of the table. Calculate the height of the table. (Organize your
given variables. Do not mix x-variables with the y-variables)
Answer:
Explanation:
To calculate the height of the table in this scenario, we can use the equations of motion. Let's define the variables first:
Initial velocity (u) = 2.50 m/s (given)
Time taken to reach the floor (t) = 0.391 s (given)
Acceleration due to gravity (g) = 9.8 m/s² (assuming the ball falls freely near the surface of the Earth)
Now, we can use the kinematic equation:
h = u * t + (1/2) * g * t²
Plugging in the given values, we have:
h = (2.50 m/s) * (0.391 s) + (1/2) * (9.8 m/s²) * (0.391 s)²
Simplifying the equation:
h = 0.97875 m + 0.07511 m
h = 1.05386 m
Therefore, the height of the table is approximately 1.05386 meters.
Compare the ball's accelerations, both direction and magnitude, immediately after they leave her hand. is one acceleration larger than the other? or are the magnitudes equal?
Both balls soon after they left her palm experienced the same amount of acceleration, but in opposite directions.
Further equation :We define acceleration a as the rate of change of velocity with respect to time for linear motion:
a = dv/dt = d²x/dt²
According to Newton's second law, a force F is required to accelerate a mass m:
F= ma
The forces exerted on the ball govern its acceleration. There is just one force acting on both balls at the moment they are released from the student's hand: gravity. Therefore, the amount and direction of the acceleration of both balls are the same:
F = mg with,
|g| = 9.81 m/s², pointing straight down.
Both balls soon after they left her palm experienced the same amount of acceleration, but in opposite directions.
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(b) During one day, 250 kg of water is pumped through
the solar panel. The température of this
water rises from 16°C to 38°C.
The water absorbs 25% of the energy incident on the solar panel. The
specific heat capacity
of water is 4200J/(kg °C).
Calculate the energy incident on the solar panel during that day.
Please explain how to find the incident energy
Answer: The energy incident on the solar panel during that day is \(9.24 \times 10^{7} J\).
Explanation:
Given: Mass = 250 kg
Initial temperature = \(16^{o}C\)
Final temperature = \(38^{o}C\)
Specific heat capacity = 4200 \(J/kg^{o}C\)
Formula used to calculate the energy is as follows.
\(q = m \times C \times (T_{2} - T_{1})\)
where,
q = heat energy
m = mass of substance
C = specific heat capacity
\(T_{1}\) = initial temperature
\(T_{2}\) = final temperature
Substitute the values into above formula as follows.
\(q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\)
As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.
\(\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J\)
Thus, we can conclude that the energy incident on the solar panel during that day is \(9.24 \times 10^{7} J\).
Ready=to-eat breakfast cereal that has been in stock for nearly 15 months is being served. To prevent this from recurring, the dietetic technician should establish inventory procedures that include
a. dating all foods upon delivery
b. back-dating all the foods on the shelf
c. moving old stock to the trayline
d. rearranging the store room
The dietetic technician should establish inventory procedures that include dating all foods upon delivery in order to prevent ready-to-eat breakfast cereal that has been in stock for nearly 15 months from being served again. This will ensure that stock is rotated and any expired or nearly expired items are removed from inventory. So the correct option is a .
a) Dating all foods upon delivery: It is essential to label and date all food items upon delivery. This ensures that the oldest stock is used first, following the principle of "first in, first out" (FIFO). By clearly marking the arrival date on the cereal boxes or containers, staff can easily identify the older stock and prioritize its use.
Additionally, it is worth noting that option b) is missing in your list. Option b) could potentially be "monitoring expiration dates" or "conducting regular inventory audits" to ensure that outdated or expired stock is identified and removed from the inventory.
c) Moving old stock to the tray line: If the cereal has been sitting in the inventory for an extended period, it is advisable to move the older stock to the tray line or display area, where it can be used or served first. This practice ensures that older products are used before newer ones, reducing the chances of expiration or wastage.
d) Rearranging the store room: Proper organization and arrangement of the store room can contribute to effective inventory management. The technician should establish a systematic layout, ensuring that older stock is placed in easily accessible areas and clearly labeled. This allows for efficient stock rotation and prevents the accumulation of expired or outdated items.
By implementing these inventory procedures, the dietetic technician can help prevent the recurrence of serving outdated breakfast cereal and maintain proper inventory control in the future.Therefore ,option a is correct.
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how many chromosomes does an elephant's egg cell have ?
Answer:
Diploid is often noted as 2N where N is the number of chromosomes. So in humans 2N=46. During sexual reproduction, the sex cells of parent organisms unite with one another and form a fertilized egg cell. In this situation, each sex cell is a gamete.
Explanation:
Which force is most important inside an atom?
O A. Gravity
O B. Air resistance
O C. Friction
O D. Strong nuclear force
Answer:
D- fuerza nuclear fuerte
Explanation:
Need help ASAP!! Why does the ray bend as it enters the glass
Answer:
Explanation:
because as the light shines through the glass, The glass reflects the light from different places in the glass causing the light to bend
Answer: If light enters any substance with a higher refractive index it slows down. The light bends towards the normal line. If light travels enters into a substance with a lower refractive index it speeds up. The light bends away from the normal line.
HELP DUE IN AN HOUR!! said last answer choice was incorrect.
A bowling ball is moving at 3 m/s and has a momentum of 9 kg*m/s. What is the ball's mass
Answer:
Given
velocity( v) =3m/s
momentum (p) =9kg.m/s
mass (m) =?
Form
p=mv
m=p/v
(9kg.m/s) /3m/s
p=3kg
mass =3kg
Imagine that friction suddenly vanishes. how would life be affected? list ten such situations.
If friction suddenly vanished, it would have a significant impact on various aspects of life. Here are ten situations where the absence of friction would affect our daily lives:
Walking: Without friction, it would be challenging to walk. Each step would result in slipping, making it difficult to maintain balance and move forward.
Driving: The absence of friction would make it nearly impossible to control vehicles. Tires would not grip the road, leading to accidents and an inability to navigate turns.
Holding Objects: Without friction, it would be tough to hold objects firmly. They would constantly slip out of our hands, making everyday tasks like writing, cooking, and even using a smartphone extremely challenging.
Sports: Many sports rely on friction to function properly. Activities like soccer, basketball, and hockey would become extremely difficult or even impossible without the ability to stop or change direction quickly.
Stopping: Brakes would become ineffective without friction, making it nearly impossible to stop moving vehicles, bicycles, or even walking.
Manufacturing: Friction is essential in many manufacturing processes. Without it, assembly lines and machinery would not be able to function properly, impacting industries such as automotive, electronics, and textiles.
Climbing: In the absence of friction, climbing would be extremely hazardous. Holding on to ropes, rocks, or any surface would become almost impossible, making mountaineering and rock climbing impractical.
Writing: The act of writing requires friction between the pen or pencil and the paper. Without it, the pen would not leave a mark, rendering writing utensils useless.
Sliding Doors: Friction is crucial in allowing sliding doors to open and close smoothly. Without it, sliding doors would become challenging to operate and would likely get stuck.
Electrical Appliances: Friction is necessary for electrical appliances to function properly. For example, without friction, the fan blades wouldn't rotate, causing air circulation issues.
The absence of friction would have a profound impact on our daily lives. It would affect our ability to walk, drive, hold objects, play sports, and engage in various activities that rely on friction. It would also disrupt manufacturing processes, hinder climbing activities, make writing difficult, impair sliding doors, and interfere with the proper functioning of electrical appliances. Overall, friction plays a vital role in numerous aspects of our lives, and its absence would significantly alter our day-to-day activities.
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A 60 kg person runs with a velocity of 4 m/s and jumps onto a 5 kg skateboard and rolls away. What is the final velocity of the person on the skateboard?
(round your answer to the nearest tenth)
Answer: Final velocity is \(3.8 m/s\)
Explanation:
We are given mass and velocity, or mass in motion, known in physics as "momentum".
The formula for momentum is \(p=mv\) (mass*velocity)
First, calculate the momentum of the person running:
\(p=60kg*4m/s\)
\(p=240(kg*m/s)\)
When the person jumps on the skateboard, the mass changes and now we're solving for the velocity. Use the same formula above to solve.
\(240=(60+4)*v\) can be rewritten as \(v=\frac{240kg*m/s}{(60+4)kg}\) or \(v=\frac{p}{m}\)
Solve and the kg cancels out and you're left with a final velocity of \(3.75 m/s\) or \(3.8m/s\) rounded to nearest tenth.
79.8329 + 3.179 + 6.5263
And round
Answer:
90.0
Explanation:
Because 78.8329 + 3.179=83.0119
83.0119 + 6.5263=89.5382 rounded up is 90.0000
Hope this helps have a awsome afternoon:)