in the electron-transport chain in deinococcus geothermalis, an extremely radiationresistant bacterium isolated from hot springs, which subunits are found in nadh dehydrogenase and in cytochrome c oxidase?

Answer:

Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. Changes like these have triggered climate change, soil erosion, poor air quality, and undrinkable water.

Explanation:

Humans impacted the environment in numerous ways. Due to this, the environment alters dramatically and has toxic effects on the whole biological diversity.

An environment may be defined as anything which is present in the surroundings of an organism. The term environment is given by Carlyle.

Humans drastically impacted the natural scenario of an environment. Some of the activities like pollution, combustion of fossil fuels, cutting down of forests, overpopulation, etc. completely rupture the environment.

All such activities result in climate change, global warming, soil erosion, scarcity of potable water, etc.

Therefore, it is well described above.

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To find the total number of students surveyed, we add up the number of students in each category after finding the number of students who had 4 dimes.

The total number of students who had 0, 1, 2, 3, 4, 5 or 6 dimes is 2 + 4 + 8 + 9 + x + 4 + 2 = 29 + x

So the equation we get for 12.5% is:

0.125(x+29) = 4,  x is the number of students who had 4 dimes.

To solve the equation 0.125(x+29) = 4 for x, we can start by simplifying the left-hand side of the equation:

0.125(x+29) = 4

0.125x + 3.625 = 4 (distributing the 0.125)

0.125x = 0.375 (subtracting 3.625 from both sides)

x = 3 (dividing both sides by 0.125)

Therefore, approximately 3 students had one dime.

Total students is now 29 + x = 29 + 3 = 32.

The percentage of students with either 0 or 6 dimes is got when we add the number of students in these categories and divide by the total number of students surveyed:

(2 + 2) / 32 * 100 = 12.5%

To find the percentage of students who had either 1 dime or 5 dimes, we add the number of students in these categories and divide by the total number of students surveyed:

(4 + 4) / 32 * 100 = 25%

The data distribution is skewed to the left since more students have 0,1 and 2 dimes than 4,5 and 6 dimes.

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The kind of relationship that exists between the two robins is competition (option A).

Competition in biology is an interaction between organisms or species in which both require a resource that is in limited supply.

The limited resource can be biotic or abiotic such as;

According to this question, a male and female robin fight for territory but mate in the spring. This relationship is an example of competition.

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Answer:

B The correct ANwser is B

Explanation:

Gel electrophoresis is a technique used to separate DNA fragments by size.

It is commonly used in molecular biology research to analyze DNA samples for research purposes. In gel electrophoresis, DNA is placed in a gel matrix and an electric current is applied.

The negatively charged DNA fragments move through the gel towards the positive electrode, and the smaller fragments move faster than the larger fragments, thus separating the fragments by size. The gel is then stained with a fluorescent dye, which allows the DNA fragments to be visualized under ultraviolet light.

Gel electrophoresis can be used to determine the size, quantity, and purity of DNA samples. It can also be used to detect mutations and to study the genetic relationships between different organisms.

In summary, gel electrophoresis separates DNA fragments by length to determine the number and position of different nucleotides or to detect mutations.

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Answer:

3. It is the site where oxygen combines with small molecules and releases large amounts of energy.

Explanation:

Mitochondria is a cell organelle

It produces ATP, which is considered as energy currency of cell.

Answer:

C

:D

Explanation:

Answer:

Regulatory genes is involved in controlling the expression of one or more other genes. In prokaryotes regulatory genes often code for repressor proteins.

Explanation:

Answer:

It is an increase in available food amount.

Explanation:

An increase in predators would result in the prey species dying off. A decrease in habitat size would result in the species not having a place to live or hide from predators. A decrease in amount of available water would make the species die of dehydration.

The prey species would disappear as there would be more predators. The species wouldn't have a place to reside or hide from predators if the habitat's size shrank.

If the amount of water available decreased, the animal would become dehydrated and die.

An exponential function's curve is created by a pattern of data called exponential growth, which exhibits higher increases over time.

Linear growth, which is additive, and geometric growth can be contrasted with exponential growth, which is multiplicative.

Therefore, The prey species would disappear as there would be more predators. The species wouldn't have a place to reside or hide from predators if the habitat's size shrank.

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If the trybutyrin agar is expired, you cannot expect any results from a lipase-positive or lipase-negative bacterium.

A medium for the detection of lipase activity, trybutyrin agar, is used. Nutrient agar, yeast extract, tryptone, and trybutyrin are included in the medium. If the medium is fresh, the emulsion is cream to light beige, with no visible evidence of bacterial contamination.

A lipase-positive bacterium will turn the medium clear after 24 hours of incubation at 37°C, while a lipase-negative bacterium will not. This is because the lipase enzyme breaks down the triglycerides in the agar, causing the medium to become transparent.

However, if the trybutyrin agar has expired, the medium's composition may have changed or become degraded. It is also possible that bacterial contamination has occurred. As a result, no results can be anticipated from a lipase-positive or lipase-negative bacterium if the trybutyrin agar is expired.

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Carnivores that feed on herbivores (or on detritivores) are referred to as: secondary consumers.

Secondary consumers generally occupy the third trophic level in food chain. They are the ones that feed on the animals that feed in producers. The example of secondary consumers are lions, tiger, snake, etc. In a food chain, the grass if being eaten by rabbit, and the rabbit is being eaten by a lion. Hence, lion becomes a secondary consumer.

Herbivores are the animals that feed on plants only. They do not have any form of flesh in their diet. The example of herbivores are rabbit, grasshopper, cows, etc. Herbivores generally occupy the second trophic level of the food chain and are primary consumers.

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Answer:

nitrogen

Explanation:

Answer:

Tract is the system of body parts , they perform functions together .

Explanation:

A Scientific tract , designed for instruction and entertainment, and adapted to schools, lyceums and families.

Answer:

The forensic scientific method is a modified form of the scientific method that compares anamnestic evidence obtained by investigators with observable physical findings discovered at the crime scene, in the crime laboratory, or in the autopsy suite.Explanation:

The hormone sensitive lipase that is involved in triglyceride breakdown to FFA is under strong hormonal control at higher work rates leading to the trapping of FFA in the adipose cell. Hormone-sensitive lipase (HSL) is responsible for the catabolism of triacylglycerols (TAGs) stored in adipose tissue, releasing free fatty acids (FFAs) and glycerol into the bloodstream.

The lipolytic rate is determined by the hormonal status of the organism and the metabolic status of adipose tissue. The lipolytic rate is regulated by hormone-sensitive lipase (HSL) and is controlled by a variety of hormonal and neural inputs. HSL is activated by catecholamines and glucagon, which cause phosphorylation of the enzyme and activation of its catalytic activity.

Insulin inhibits HSL activity by dephosphorylating the enzyme and rendering it inactive. Thus, the action of insulin is to prevent lipolysis in adipose tissue, while the action of catecholamines and glucagon is to stimulate it. At higher work rates, the FFA is trapped in the adipose cell due to the strong hormonal control of the hormone-sensitive lipase. Therefore, the correct option is (A) hormone-sensitive lipase.

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Answer:

Mammary Glands.  

Three Bones in the Middle Ear.  

Warm-Blooded Metabolisms.  

Diaphragm.  

Here are 4, two extra! Hope it helped:D

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Such a finding would imply that life may have arisen independently on both planets.

If scientists find a living unicellular organism on another planet that can carry out aerobic respiration with enzymes and electron transport proteins that share functional and structural similarities to those found in aerobic bacteria on Earth, it would imply that life may have arisen independently on both planets. This could indicate that life on Earth is not unique and that other planets may also be able to sustain some form of life.

Thus, this finding would confirm the possibility of life on other planets and bring us closer to understanding the origins of life in the universe.

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The following statements about the anaphase-promoting complex (APC) are true:

1. It promotes the degradation of proteins that regulate M-phase.

2. It tags cyclin with ubiquitin, so it gets sent to the proteasome.

3. It promotes the breakdown of cohesins.

4. Its activity is stimulated by M-Cdk.

Thus, the correct options are A, B, E, and F.

The anaphase promoting complex or cyclosome (APC/C) is a large multi-subunit E3 ubiquitin ligase that orchestrates cell cycle progression by mediating the degradation of important cell cycle regulators. The statements above are accurate because the APC plays a crucial role in regulating the progression of the cell cycle, specifically during the M-phase (mitosis). It promotes the degradation of key proteins, helps break down cohesins to separate sister chromatids, and is regulated by the M-Cdk complex.

Thus, the correct options are A, B, E, and F.

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Answer:

Genetic engineering is accomplished in three basic steps.

These are

(1) The isolation of DNA fragments from a donor organism;

(2) The insertion of an isolated donor DNA fragment into a vector genome and

(3) The growth of a recombinant vector in an appropriate host.

Explanation:

Stages of genetic engineering include:

Genetic engineering is a method of modifying or manipulating the DNA of organisms to change their characteristics or create new ones. Here are the six steps of genetic engineering:

1. Identification of target gene

2. Isolation of the target gene

3. Insertion of the target gene into a vector

4. Transformation of host cells

5. Selection and screening of transformed cell

6. Verification of gene expression

Finally, the expression of the target gene is verified to ensure that it is functioning properly and producing the desired trait or characteristic in the organism.

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Based on the DNA sequence, the species that is most closely related to the unknown species is species 1, as it has more homologies than species 2. A bigger distance can be traduced in a higher number of mutations or modifications in the DNA sequence.

The correct answer is: Species 1.

In a process called transcription, an RNA copy of a gene sequence on the DNA molecule is made.

Transcription is the first step in gene expression. This involves copying the DNA sequence of a gene to create an RNA molecule. Transcription is done by an enzyme called RNA polymerase, which joins nucleotides together to form an RNA chain. All RNA in the cell is made by DNA transcription. This process has some similarities with the process of DNA replication described in the chapter.

Transcription begins by opening and unwinding small sections of the DNA double helix to reveal the bases of each strand of DNA. During transcription, the enzyme RNA polymerase uses DNA as a template to create pre-mRNA transcripts. Pre-mRNA is processed to form mature mRNA molecules that can be translated to build the protein molecules encoded by the original gene.

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The connective tissues support and protect and give stricture. The smooth muscles are involuntary non straighter muscles. The epithelial cells that line the surface of the body. The correct option is C

Tissue can be defined as a group of cells that have similar structure and that function together as a unit.

There are primary types of body tissues are :

Therefore, Connective tissue is the most abundant tissue type in our body. It connects other cells and tissues together. It is typically found in our bones, cartilage, adipose, collagen, blood and many other areas in our body

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Explanation:

With adequate pollination, wildflowers:

Reproduce and produce enough seeds for dispersal and propagation.

Maintain genetic diversity within a population.

Develop adequate fruits to entice seed dispersers.

Answer:

it's a deletion!!!!!!!!

Answer:

inversion chromosome

Exocytosis is a cellular mechanism by which cells secrete products outside the cell via vesicles that fuse with the plasma membrane. Here option D is the correct answer.

The products can range from proteins to waste products. Large molecules are also secreted via exocytosis. Exocytosis is responsible for adding components to the cell membrane and secreting macromolecules.

The other options are true statements regarding exocytosis: A is a true statement regarding exocytosis. Intracellular vesicles are formed by the inward folding of the plasma membrane.

B is a true statement regarding exocytosis. Fusion of vesicles with the plasma membrane is required for exocytosis to occur. C is a true statement regarding exocytosis. It secretes large molecules out of the cell. Therefore option D is the correct answer.

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Answer:

•function of the ovary is to produce the egg which develops in the Graafian follicle. The ovary is also responsible for the production of the hormones progesterone and estrogen.

In the splicing step of gene expression, introns are spliced out, and exons are stitched together.

Gene expression refers to the process of protein synthesis that begins with a gene in DNA and finishes with a functional protein. The genetic code is translated to make protein during gene expression. Gene expression is a complex process that requires many different molecules, including RNA polymerases, transcription factors, and other regulatory proteins.

In eukaryotic cells, pre-mRNA is modified before it exits the nucleus. RNA splicing is a crucial aspect of pre-mRNA processing, in which non-coding introns are excised and exons are joined to produce mature mRNA molecules. The splicing process is carried out by a complex machinery consisting of small nuclear ribonucleoprotein particles (snRNPs).

The snRNPs in spliceosomes recognize introns and bring together the flanking exons for precise excision. Intron removal is followed by the ligation of exons, which results in the formation of a mature mRNA molecule that can be exported from the nucleus to the cytoplasm, where it can be translated into a functional protein.

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