In the electrolysis of molten NaBr,(a) What product forms at the anode?

Answer:

349.5 moles

Explanation:

(I am assuming that there is a typo at the end, where Cuci solution = CuCl solution)

The formula for molarity is:

Molarity = moles in solution / volume of solution

Here, we are given both the Molarity and the volume. So we can plug it into the equation above and get:

2.33 = moles / 150

Now we solve for the moles by doing:

moles = 2.33 * 150

This gives us the answer of 349.5 moles.

The additional information that is required to obtain the enthalpy of neutralization is the density of the solution.

We know that the enthalpy of neutralization is defined as the heat that is evolved when  an acid is neutralized by a base under standard conditions. We can be able to obtain the enthalpy of the neutralization of the acid and the base by performance of some simple chemical calculations.

To carry out this calculations we need the all of the pieces of information that have been listed in the question such as the masses of the solution, the temperature of the solution in the initial and final states and so on.

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12.308% of the chemical is sulfur. The compound's whole sulfur content is transformed into barium sulfate. Therefore, the mass for sulfur from barium sulfate will match the mass for sulfur in the compound.

People are not highly poisonous to sulfur. However, consuming far to much sulfur may result in diarrhea or a burning feeling. Sulfur dust inhalation might irritate the airway or make one cough. The eyes and skin may also become irritated by it.

Sulfur can indeed be found in sulfide ores and in nature. It is native to areas close to volcanoes and hot springs. The tenth most common element, sulfur, is found in almost all types of plant and animal life, meteorites, ocean ocean, the humankind's crust, and or the atmosphere.

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A mixture has a mas of 450 grams. Of that mixture,35 grams is sulfur . Therefore, 11% is the percentage of sulfur in the mixture.

The mass percent equation is defined as the mass of each element in one mole of the compound, as well as the molar mass. With these masses, you can calculate each element's mass proportion.

In order to represent the mass percent of a solution, the kilograms of solute are divided by the kilograms of solution, and the result is multiplied by 100.

percentage of sulfur = mass of sulfur/ mass of mixture×100

mass of sulfur= 5 grams

mass of mixture =450 grams

substituting all the given values in the above equation, we get

percentage of sulfur = 5 / 450=0.011×100= 11%

Therefore,  11% is the percentage of sulfur in the mixture.

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Answer:

154

Explanation:

Due to an increase in the number of electrons, Group 17 elements become less volatile as they move down the group.

Simply put, an element is any substance that cannot be converted into another substance. Each of the approximately 150 elements has a unique form of atom. Atoms from at least two atom, and maybe more, are present in every item in the cosmos. Every known element is listed in the periodic table, and related elements are grouped together.

A fundamental object that is difficult to divide into smaller bits is known as an ingredient. An element is anything that cannot be broken by quasi reactions in chemistry and physics. One of humanity's most beneficial components to humanity is silicon.

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This problem is providing us with the moles of both sugar and ammonia and asks for a comparison between the moles and their amounts in grams. At the end, one concludes they have different amounts as 1,743.42 g and 119.21 g.

In chemistry, mole-mass relationships are used to calculate grams from moles or vice versa, according to specific conditions. In such a way, for sugar and ammonia, one can first calculate their molar masses with:

\(MM_{C_6H_{12}O_{11}}=6*12.01+12*1.01+11*16.00=249.06g/mol\\ \\MM_{NH_3}=14.01+1.01*3=17.03g/mol\)

Next, we calculate grams with the following proportional factors:

\(7molC_6H_{12}O_{11}*\frac{249.06gC_6H_{12}O_{11}}{1molC_6H_{12}O_{11}} =1743.42g\\\\7molNH_3*\frac{17.03gNH_3}{1molNH_3}=119.21gNH_3\)

Thus, we conclude that despite having equal number of moles, they differ in the amount of grams because of their dissimilar molar masses.

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Answer:

B

Explanation:

Answer:

Mitosis

Explanation:

This is the process that cells reproduce and replace old or damaged cells.

Answer:

hi hehe I'm new here hehehe

Answer:

2,400,000 torr (3 s.f.)

Explanation:

Convert the pressure from Pascal to atm first:

\(\boxed{1 \: atm = 101325 \:Pa }\)

3.20 ×10⁸ Pa

= [(3.20 ×10⁸) ÷101325] atm

= 3158.2 atm (5 s.f.)

Convert atm to torr:

\(\boxed{1 \: atm = 760 \: torr}\)

3158.2 atm

= (3158.2 ×760) torr

= 2400000 torr (3 s.f.)

Answer:

energy transformation

Explanation:

energy transformation is when energy changes from one form to another. like in a hydroelectric dam that transforms the kinetic energy of water into electrical energy.

The interaction energy between the dipoles in the given configuration is 1/2 * k * p1 * p2 * (1/r^3) * (3cos^2(theta) - 1) r is the distance between the dipoles.

Given, the distance between the dipoles = a. The formula to calculate the interaction energy between two dipoles is given by, Interaction energy between two dipoles = (1/4πε) [(p1.p2 - 3(p1.r)(p2.r)/r^3]Where, p1 and p2 are magnitudes of the dipoles, r is the distance between the dipoles, and ε is the permittivity of free space.

Interaction energy between the dipoles = (1/4πε) [(p1.p2 - 3(p1.r)(p2.r)/r^3]On substituting the values in the above formula, we get, Interaction energy between the dipoles = 1/2 * k * p1 * p2 * (1/r^3) * (3cos^2(theta) - 1)where k is Coulomb's constant, p1 and p2 are the magnitudes of the dipoles, r is the distance between the dipoles, and theta is the angle between the dipole moments.

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Answer:

The molecular weight of CO is 28.01g/mole.

The amount of sample of K-42 yesterday at the same time is equal to 136.8 mg.

The half-life of the radioactive material can be described as the time required to decrease its original amount to half after decay. The half-life of a radioactive element does not depend on the initial amount of the substance.

Consider that N₀ is the initial amount of the K-42 sample

Consider that 'n' is the number of half-lives of K-42.

The time for which K-42 decay, t = 24 hrs

Half-life of substance (t½) =  12 hrs

t = n ×t½

24 = n × 12

n = 2

Assume that N₀ is the amount of the K-42 before decay for 24 hours.

N ×2² = N₀

34.2 × 4 = N₀

N₀ = 136.8 mg

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The molarity of the alkali potassium hydroxide is 4.167 M.

Molarity (M) is the amount of a substance in a sure quantity of answers. Molarity is described because the moles of a solute according to liters of an answer. Molarity is also called the molar attention of an answer.

Calculation:-

V = 24 cm³ = 0.024 L

V = 20 cm³ = 0.020 L

molarity of sulphuric acid = 2.5

Mv = MV

M  0.024 = 0.02 × 2.5 × 2

M = 0.1 /0.024

    = 4.167 M

Molar concentration is a measure of the attention of a chemical species, specifically of a solute in an answer, in terms of the amount of substance in step with the unit extent of the answer. In chemistry, the most generally used unit for molarity is the number of moles in keeping with liter, having the unit symbol mol/L or mol/dm³ in SI unit.

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As the volume of  the sound is seen to increase, the sound that we hear is louder as the amplitude of the sound increases.

Sound is a kind of wave that moves through a medium. We know that sound has to move via several compressions and rare factions. This implies that sound is as well propagated through air. The movement of the sound waves through air is because the air is set into vibration by the sound. Thus, the air is very imprtant in the movement of the sound waves.

With this much said, we can see that if there is more air, there would more molecules that can be set into vibration and the sound wave would tend to increase and that is the deal that we are trying to communicate here.

Thus, the amplitude of air increases as the volume of  the sound gets higher and the sound that we hear is much louder.

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The layers of the atmosphere are;

Exosphere - A

Thermosphere - E

Mesosphere - B

Stratosphere - E

Troposphere - C

The troposphere, which is the lowest part of the atmosphere, rises from the surface of the Earth to an average height of roughly 18 kilometers (12 miles) at the equator and 12 kilometers (7.5 miles) in the poles. The majority of the Earth's air mass is present there, making it the location of weather occurrences. In the troposphere, temperature typically drops as altitude rises.

The thermosphere is located above the mesosphere and stretches from a height of around 85 kilometers (53 miles) up to 600 kilometers (370 miles). Due to the incredibly low molecular density in the thermosphere, despite the high temperatures that are there, it does not feel warm. The auroras also appear in this layer.

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Answer: D inverse . The product of Ka and Kb equals the auto-dissociation constant for water.

Explanation: i hoped that helped and Plz give as a brainliest !!