in the electrolysis of a solution containing , metallic deposits on the cathode. using a current of 1.09 a for 4.40 hours, what mass of silver forms?

Answer:

ABintense pressure and breathin

Explanation:

because scientist never have the tech to go deeper

Answer:

B. Problems with breathing

C. Intense pressure

Answer:

0.36mol

Explanation:

Given parameters:

Volume of NaCl  = 0.4L

Molarity  = 0.9M

Unknown:

Number of moles  = ?

Solution:

To find the number of moles, the molarity of a solution is the amount of solute contained in a solution.

 Molarity  = \(\frac{number of moles}{volume}\)  

 Number of moles = molarity x volume

 Insert the parameters and solve;

 Number of moles = 0.4 x 0.9  = 0.36mol

there are 3.77 x 1022 H2O molecules in a 1.40 L sample of H2O gas at STP.

At STP, the volume of 1 mole of any gas is 22.4 L.

This means that the number of moles of gas can be calculated by dividing the volume of the gas by 22.4 L. The number of moles of H2O gas in a 1.40 L sample can be calculated as follows:

1.40 L ÷ 22.4 L/mol = 0.0625 mol H2O

To find the number of H2O molecules in 0.0625 moles of H2O, we can use Avogadro's number, which is 6.02 x 1023 molecules per mole.

This gives us:

Number of H2O molecules = 0.0625 mol

H2O x 6.02 x 1023 molecules/mol = 3.77 x 1022 H2O molecules

Therefore, there are 3.77 x 1022 H2O molecules in a 1.40 L sample of H2O gas at STP.

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The temperature at which reactions with ΔH = -126 and ΔS = 84 become spontaneous is 271.65 K or -1.5 degree celsius.

To explain why, we must first examine the relationship between ΔH, ΔS, and temperature.

The Gibbs free energy change, ΔG, is given by the equation ΔG = ΔH - TΔS, where T is the temperature in Kelvin.

If ΔG is negative, the reaction is spontaneous; if it is positive, the reaction is non-spontaneous; and if it is zero, the reaction is at equilibrium.

We can rearrange this equation to solve for T and find the temperature at which the reaction becomes spontaneous:

ΔG = ΔH - TΔS < 0

ΔH - TΔS < 0

TΔS > ΔH

T > ΔH/ΔS

The temperature at which the reaction becomes spontaneous is greater than ΔH/ΔS.

Given: ΔH = -126, ΔS = 84

T > ΔH/ΔS

T > -126/84

T > -1.5 or T > 271.65 K.

Thus, the temperature at which reactions with ΔH = -126 and ΔS = 84 become spontaneous is 271.65 K or greater than this temperature.

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Answer:

A derived unit is a unit that results from a mathematical combination of SI base units. We have already discussed volume and energy as two examples of derived units.

Answer:

The answer is E) none of the above.

In all of the given reactions, mass and charge are conserved. The law of conservation of mass states that the mass of reactants must be equal to the mass of the products in a chemical reaction. The law of conservation of charge states that the total charge of the reactants must be equal to the total charge of the products.

In reaction A, the water molecule dissociates into a hydrogen ion (H+) and a hydroxide ion (OH-), but the total mass and charge are still conserved.

In reaction B, the reduction of CIO2 to Cl- is balanced by the oxidation of water to form OH-. The electrons and charge are conserved.

In reaction C, H2SO4 reacts with NaOH to form Na2SO4, H+ and OH-. The mass and charge are conserved.

In reaction D, ZnCl reacts with water to form ZnOH, H+ and Cl-. The mass and charge are also conserved.

Answer:

It's not that hard to do figure it out yourself

Explanation:

too simple

Sodium chloride reacts with silver nitrate.  NaCl + AgNO3 → AgCl + NaNO3

intermolecular forces present in it.

The attracting and repellent forces that develop between the molecules of a substance are known as intermolecular forces or IMF for short. Individual molecules of a substance interact with one another through the mediation of these forces.

Most of the physical and chemical features of matter are caused by intermolecular forces.

An intermolecular force is an attractive force that develops between the protons or positive parts of one molecule and the electrons or negative parts of another molecule. This force affects a substance's many physical and chemical properties. The strength of a material's intermolecular forces directly relates to the boiling point of that substance; the stronger the intermolecular forces, the higher the boiling point.

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Answer:

70°C,130.9 ................,...

Answer:

When air is admitted into the well, the water recedes from the level of static head to the bottom of the discharge pipe. The displaced column of liquid rises up the discharge pipe. Air bubbles mix with water and this reduces the specific gravity of the column of water sufficiently to lift it to the surface.

Explanation:

Answer:

allows the atoms of different elements to bond together to form new substances

The negatively charged electrons are held together by electrostatic force by the positively charged atomic nucleus.

Electrostatic forces are non-contact forces that pull or push on objects without contacting them.

The positively charged atomic nucleus holds the negatively charged electrons together with electrostatic force.

Thus, in this way electrostatic forces affect the electrons in an atom.

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Answer:

Ca(OH)2 chemical of lime water.

it is alkali in nature if it is only lime then it is an example of critic acid and it is know as. acid

lime wate is alikali

limes is acid

Explanation:

Answer:

Alkali

Explanation:

Limewater is the calcium hydroxide. It is Alkali

The pH of the solution is 3.74.  pH stands for "potential of hydrogen" and is a measure of the acidity or alkalinity of a solution.

What is Solution?

A solution is a homogeneous mixture of two or more substances, where the particles of the substances are evenly distributed at the molecular or ionic level. In a solution, the substance that is present in the greatest amount is called the solvent, and the substances that are present in smaller amounts are called solutes.

In this case, acetic acid  is the weak acid and its conjugate base is acetate . The pKa for acetic acid is 4.75.

The initial concentrations of acetic acid and acetate in the solution can be calculated using the formula:

n = C x V, where n is the number of moles, C is the concentration, and V is the volume in liters.

n(\(CH_{3} CO_{2} H\)) = (0.10 mol/L) x (0.025 L) = 0.0025 moles

n(\(CH_{3} CO_{2}Na\)) = (0.010 mol/L) x (0.025 L) = 0.00025 moles

The total volume of the solution is 50.00 mL or 0.050 L.

The final concentrations of the acid and its conjugate base can be calculated using the formula:

0.0025 moles / 0.050 L = 0.050 M

0.00025 moles / 0.050 L = 0.0050 M

Now we can plug these values into the Henderson-Hasselbalch equation:

pH = 4.75 + log(0.0050/0.050)

pH = 4.75 - 1

pH = 3.75

Therefore, the pH of the solution is 3.75.

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First, we need to calculate the moles of nitroglycerin used in the reaction:

12.0 g C3H5(NO3)3 x (1 mol C3H5(NO3)3 / 227.09 g) = 0.0528 mol C3H5(NO3)3

Now, we can use the balanced equation to determine the moles of each product formed:

2 moles C3H5(NO3)3 produce 6 moles CO2, so 0.0528 mol C3H5(NO3)3 produces 0.1584 mol CO2

2 moles C3H5(NO3)3 produce 5 moles H2O, so 0.0528 mol C3H5(NO3)3 produces 0.132 mol H2O

2 moles C3H5(NO3)3 produce 3 moles N2, so 0.0528 mol C3H5(NO3)3 produces 0.0792 mol N2

2 moles C3H5(NO3)3 produce 1/2 mole O2, so 0.0528 mol C3H5(NO3)3 produces 0.0264 mol O2

Next, we can calculate the overall change in enthalpy using the enthalpies of formation of the products and reactants:

ΔH = (3 mol CO2 x -393.5 kJ/mol) + (0.132 mol H2O x -241.8 kJ/mol) + (0.0792 mol N2 x 0 kJ/mol) + (0.0264 mol O2 x 0 kJ/mol) - (1 mol C3H5(NO3)3 x -364 kJ/mol)

ΔH = -2370.1 kJ/mol

Finally, we can calculate the enthalpy change for the amount of nitroglycerin used in the reaction:

ΔH = -2370.1 kJ/mol x (0.0528 mol C3H5(NO3)3 / 2 mol C3H5(NO3)3) = -62.5 kJ

Therefore, the enthalpy change that occurs when 12.0 g of nitroglycerin is detonated is -62.5 kJ.

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Answer:

1. 1.72 moles of potassium.

2. All of the answers are true

3. Are used up during a reaction

Explanation:

Recall that the number of moles is obtained from;

Number of moles= Mass of potassium/ molar mass of potassium

Mass of potassium= 67 g

Molar mass of potassium= 39 gmol-1

Number of moles of K= 67 g/ 39 gmol-1

Number of moles = 1.72 moles of potassium.

2. When we look at all the options, we will realize that all the options are true. The rate of reaction doubles for each 10°C rise in temperature, increasing reactant concentration increases particle collision and ultimately increases the rate of reaction. Rate of reaction deals with rate of disappearance of reactants or rate of appearance of products.

3. Catalysts remain unchanged in a chemical reaction because they do not actually participate in the reaction. Hence they are not used up in any chemical reaction.

If a battery acid solution is a strong electrolyte, battery acid is highly ionized. So the correct option is d.

If a solution is a strong electrolyte, it means that it ionizes completely in solution, resulting in a high concentration of ions. In the case of battery acid, which is typically sulfuric acid, it is a strong electrolyte because it ionizes almost completely in solution, producing a high concentration of hydrogen ions (H+) and sulfate ions (SO42-). This high ion concentration allows for a flow of electrons between the positive and negative terminals of the battery, producing an electric current. Therefore, option C is the correct answer.

If a battery acid solution is a strong electrolyte, this means that it is highly ionized. In other words, when the acid is dissolved in water, it breaks apart into ions that can conduct electricity. A strong electrolyte dissociates completely into its constituent ions when dissolved in water, meaning that there is a high concentration of ions in solution. This is in contrast to a weak electrolyte, which only partially dissociates in water and has a lower concentration of ions in solution. The fact that battery acid is a strong electrolyte is important because it allows it to conduct electricity, which is essential for its use in batteries. However, it also means that the acid is highly corrosive and can cause serious injury if not handled properly.

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The type of adaptation shown by the dart frog is physiological adaptation while the one shown by the Hosta plant is structural adaptation.

Adaptation generally refers to the process by which living organisms adjust in order to continue to survive in an environment.

There are 3 main types of adaptations:

In behavioral adaptation, organisms change their behavior for their continued survival in their environments. Without these modifications, they may find it to survive and reproduce in the environment.

Physiological adaptation refers to changes that are encoded into the system of organisms. Changes that are not behavioral nor structural but ensure the continued survival of organisms in their environment.

Structural adaptation refers to the modification of physical structures for continued survival. These modifications become necessary because the environment keeps changing.

Thus, bright coloration as a warning to predators by the dart frog is a physiological adaptation while the development of big leaves that ensures that as much sunlight as possible is received by the Hosta plant is a structural adaptation.

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The number of moles in 25 grams of oxygen is equal to 1.56 moles, as 16 grams of oxygen contain one mole.

A mole is a unit measurement that is used to calculate a large number of chemical entities such as atoms, molecules, ions, or other particular particles.

The mass of the one mole of any chemical element in the periodic table is called atomic mass and that of any compound is known as molar mass.

The number of chemical entities present in one mole was found to be equal to approximately 6.023 × 10 ²³ which is known as Avogadro’s number. In the calculation of the number of moles of a substance the given mass of the substance is divided by its molecular mass.

Given, the mass of the oxygen = 25 grams

As we know the atomic mass of oxygen is equal to 16g/mol

So 16 g of oxygen contains moles = 1

Then 25 g of oxygen will contain moles = 25/16 = 1.56 mol

Therefore, the moles of oxygen in 25 grams are equal to 1.56.

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True, variations can be subtle or extreme.

The degree of variation depends on the context and the nature of the subject being examined. Some variations may be slight and difficult to detect, while others may be extreme and easily identifiable. Regardless of the extent of the variation, it is an essential concept that allows for diversity and creativity in various fields.

This is because variations refer to differences or changes in something. For instance, in genetics, variations can range from small changes in the genetic code to large-scale mutations that alter the entire genetic sequence. Similarly, in language, variations can be subtle, such as different pronunciations or word usage, or extreme, such as different languages altogether.

In other areas such as art, variations can also be subtle or extreme. For example, an artist may create variations of a painting by changing the color scheme, brushstrokes, or composition, resulting in subtle differences. Alternatively, an artist may create an extreme variation by creating a completely different piece that only shares a few similarities with the original.

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Answer:

The area is important for climate science research because they can look at the glaciers and see over the years what is happening with them, are they multiplying or are they decreasing and if so at what rate.

Answer:

Melting glaciers are causing sea levels to rise. It’s important to study natural conditions in the Northern Patagonian Ice Field because the landscape there is dynamic and the effects of climate change can easily be seen. The retreat of the Nef Glacier and the disappearance of icebergs on the lake are evidence of rising temperatures and climate change.

Explanation:

The Average Atomic Mass of copper is 63.5521 amu.

The average atomic mass of an element is calculated by multiplying the masses of all of its isotopes by the element's natural abundance (the decimal associated with percent of atoms of that element that are of a given isotope).

Given:

One isotope is 62.9298 amu and occurs 69.09%

Other cu isotope is 64.9433 amu and occurs  30.91%

Let

\(^{63}C\) % of abundance = x

\(^{65}C\) % of abundance = (100-x),

We have, the formula of average mass

Average mass = \(\frac{M_1x_1+M_2x_2}{x_1+x_2}\)

Average mass= 62.9298 ×69.09+ 64.9433 × 30.91/100

                       = 4347.819882+2007.397403/100

                       = 6355.217285/100

Average mass= 63.55217285

Therefore, The average mass of copper is  63.5521 amu

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The correct options are:1.

Conditional probability that the selected compound actually has an impurity is 0.74.2.

Conditional probability that the selected compound is actually free of an impurity is 0.0185.3.

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

Here, we need to find out the probability that a selected compound has an impurity given that the test indicates an impurity is present.

P(A) = probability that a compound has impurity = 0.15

P(B) = probability that the test indicates an impurity is present

= 0.15 x 0.9 + 0.85 x 0.05

= 0.14 + 0.0425

= 0.1825P

(B|A) = probability that the test indicates an impurity is present given that the compound has impurity = 0.9

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / P(B)

         = 0.9 * 0.15 / 0.1825

         = 0.7370

         ≈ 0.74

Conditional probability that the selected compound actually has an impurity is 0.74.10.

Here, we need to find out the probability that a selected compound is actually free of an impurity given that the test indicates an impurity is not present.

P(A) = probability that a compound has impurity = 0.15

P(B) = probability that the test indicates an impurity is not present = 0.85 x 0.95 + 0.15 x 0.1 = 0.8075

P(B|A) = probability that the test indicates an impurity is not present given that the compound has impurity

          = 0.1

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / P(B)

          = 0.1 * 0.15 / 0.8075

          = 0.0185

Conditional probability that the selected compound is actually free of an impurity is 0.0185.11.

Here, we need to find out the probability that the selected roll is from Process I given that it is defective.

Let A denote the event that a roll is from Process I and B denote the event that a roll is defective.

Then, we need to find out P(A|B).

P(A) = probability that a roll is from Process I = 0.6

P(B|A) = probability that a roll is defective given that it is from Process I = 0.03

P(B|A') = probability that a roll is defective given that it is from Process II = 0.01

P(A'|B) = probability that a roll is from Process II given that it is defective

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / [P(B|A) * P(A) + P(B|A') * P(A')]

= 0.03 * 0.6 / (0.03 * 0.6 + 0.01 * 0.4)

= 0.6429

≈ 0.64

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

Hence, the correct options are:1.

Conditional probability that the selected compound actually has an impurity is 0.74.2.

Conditional probability that the selected compound is actually free of an impurity is 0.0185.3.

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

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Answer:

1. Mg²⁺   2. Cl⁻    3. PO₄³⁻

Explanation:

Answer:

1. Mg²⁺

2. Cl⁻

3. PO₄³⁻

Explanation:

Feel free to give brainliest.

Have a great day!

Answer:

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

From the question

velocity = 35.0 mi/hr

time = 2455 s = 0.68 hr

We have

distance = 35 × 0.68

We have the final answer as

Hope this helps you

Using the absorbance of the permanganate in the diluted waste solution, we get A = log(1/0.461) = 0.330. The concentration of Mn2+ ions in the original waste solution is 0.00824 M.

To find the absorbance of the permanganate in the diluted waste solution, we need to use the equation A = log(1/T) where T is the percent transmittance. Therefore, A = log(1/0.461) = 0.330.

Using the equation for the calibration curve, we can find the concentration of permanganate in the diluted waste solution:

0.330 = 1730x + 0.043, which gives x = 0.000181 M.

Since permanganate is formed by oxidizing Mn2+ ions, the concentration of Mn2+ ions in the original waste solution is equal to the concentration of permanganate in the diluted solution multiplied by the dilution factor (250.0 mL/5.50 mL):

0.000181 M × (250.0 mL/5.50 mL) = 0.00824 M. Therefore, the concentration of Mn2+ ions in the original waste solution is 0.00824 M.

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Answer:

For example, a suitcase jam-packed with clothes and souvenirs has a high density, while the same suitcase containing two pairs of underwear has low density. Size-wise, both suitcases look the same, but their density depends on the relationship between their mass and volume. Mass is the amount of matter in an object.

\(*CreativeGirl*\)

HIGH density: lead, water on the bottom of the ocean, concrete

LOW density: fresh water, oil, wood

Explanation:

Hope  it helps!

\(*JoyousLass*\)

Answer:

B

Explanation:

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Answer:

Q = 319.49 J

Explanation:

Given that,

Mass, m = 16.6 g

Initial temperature, \(T_i=40.2^{\circ} C\)

We need to find the heat needed to warm the water to 44.8 °C. The formula that is used to find the heat required is given by :

\(Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q=16.6\ g\times 4.184\ J/g^{\circ} C\times (44.8-40.2)^{\circ} C\\\\Q=319.49\ J\)

So, 319.49 J of heat is needed to warm water.

The total number of electron pairs shared between the two atoms in an o2 molecule are two.

The O2 Lewis structure has a double bond between two oxygen atoms. According to the octet rule, oxygen atoms need to bond twice.  The O2 molecule is a diatomic, meaning that two atoms of the same element are connected in a pair. The two bonds appear as the two parallel lines between the O atoms. This is called a double bond. Each bond is a pair of electrons, one from each connected O atom. So the double bond, the two parallel lines, represents a total of 4 electrons.

Each O is surrounded is by four dots and two sticks or lines, representing another 4 electrons in the O2 double bond. So each O is surrounded by 8 total valence electrons, giving it an octet also and making it stable.

The two letter O’s in the O2 Lewis structure represent the nuclei or the centers of the oxygen atoms.

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