Answer:
did anyone figure it out
Explanation:
please help
Answer:
6.21
Explanation:
in a generator as the magnet spins opposite poles of the magnet push the electrons in opposite directions this back and forth movement of electrons is called
Answer: In a generator, the back and forth movement of electrons as the magnet spins and opposite poles of the magnet push the electrons in opposite directions is called Alternating Current (AC).
Explanation:
Answer:
alternating current and direct current
Explanation:
yall some of these questions arent that hard, use common sense
Explain the differences between horticulture and agriculture.
\( \tt{Difference \: Between \: \underline\red {Horticulture} \: And \: \underline\green{Agriculture}}\)
\( \text{\underline\red {Horticulture}}\)
The Cultivation of Fruits, Vegetables and Flowers for domestic and international markets are called Horticulture.
\( \text{\underline\green{Agriculture}}\)
It is science, art and occupation of cultivating the soil, producing crops and livestock. It is systematic and controlled use of living organisms and the environment to improve the human condition.
Hope This Helpsstate some important uses of magnet
A basketball player is getting ready to jump, pushing off the ground and accelerating upward.
A) Draw a force identification diagram.
B) Draw a free body diagram.
Answer:
B
Explanation:
B
If the 100 g mass is replaced by a 200 g mass, which variables in Tnet = la change, and which
remains constant? Justify your answer.
The moment of inertia (I) will changes and net torque (Tnet) will also change, while the angular acceleration (a) remains constant.
What is the changed variable in the equation?The formula for net torque acting on an object is given as;
T(net) = Ia
where;
a is the angular accelerationI is the moment of inertiaT(net) is the net torqueThe moment of inertia of an object is given as;
I ∝ MR²
where;
M is the massR is the radius of the objectSo mass, M changes, the moment of inertia (I) changes and net torque will also change, while the angular acceleration remains constant.
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Pls help and explain how to get the answer
(a) The magnitude of the gravitational force on the rock is 64.68 N and on the pebble is 5.488 x 10⁻³ N.
(b) The acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².
What is the gravitational force exerted on each object?The gravitational force exerted on each object is calculated by applying Newton's law of universal gravitation as follows;
Fg = Gm₁m₂ / R²
where;
G is universal gravitation constantm₁ is the mass of the rockm₂ is the mass of pebbleThe acceleration of each object will be constant and equal to acceleration due to gravity, the force on each object is calculated by using Newton's second law of motion.
Force on the rock;
F = mg
where;
g is acceleration due to gravityF = 6.6 kg x 9.8 m/s²
F = 64.68 N
The force on the pebble;
F = mg
F = 5.6 x 10⁻⁴ x 9.8
F = 5.488 x 10⁻³ N
Thus, the acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².
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give me 7 risk factors for heart attack
The seven risk factors for heart attack are Age, Tobacco usage, high blood pressure, high cholesterol level, obesity, diabetes and metabolic syndrome.
Some other risk factors for heart attack are:
Family history of heart attacksNot enough exerciseUnhealthy dietStressIllegal drug useHistory of preeclampsia An autoimmune conditionTo prevent heart attack, one must,
Follow a healthy lifestyleManage other health conditionsTake medications as directedTherefore, the seven risk factors for heart attack are Age, Tobacco usage, high blood pressure, high cholesterol level, obesity, diabetes and metabolic syndrome.
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Two stars M1 and M2 of equal mass make up a binary star system. They move in a circular orbit that has its center at the midpoint of the line that separates them. If M1 = M2 = 5.45 sm (solar mass), and the orbital period of each star is 3.20 days, find their orbital speed. (The mass of the sun is 1.99E30 kg.)
Since Two stars M1 and M2 of equal mass make up a binary star system. their orbital speed is 2.69E4 m/s.
What is the orbital speed about?The orbital period of a binary star system is given by the equation:
T = 2 * pi * sqrt(a³ / (G * (M1 + M2)))
where T is the orbital period, a is the semi-major axis of the orbit (half of the distance between the two stars at their closest approach), G is the gravitational constant, and M1 and M2 are the masses of the two stars.
Substituting the given values into this equation, we get:
3.20 days = 2 * pi * sqrt(a³ / (6.67E-11 m³ kg^⁻¹ s^⁻² * (5.45 sm * 1.99E30 kg/sm + 5.45 sm * 1.99E30 kg/sm)))
Solving for the semi-major axis, we find that a = 2.11E11 m.
The speed of each star in the orbit can be found using the equation:
v = sqrt(G * (M1 + M2) / a)
Substituting the values we have calculated, we find that v = 2.69E4 m/s. This is the speed of each star in the orbit.
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IS EARTH PLANET FALT OF ROUNDED?
Explanation:
Falt isn't a size. I guess you were trying to spell flat. No, the earth isn't flat. instead, it is round.
Answer:
Earth is round. But the map shows you flat.
A small heat engine has an energy input of 1,176 joules, and does 201 joules of work. What is the efficiency of the engine? (round your answer to the nearest whole number percent, but leave off the % symbol)
so, if you calculate it is 13.3%, enter your number as 13.
The efficiency of the engine is 17%.
Given the following data:
Energy input = 1,176 JoulesEnergy output = 201 JoulesTo find the efficiency of the engine:
Mathematically, the efficiency of an engine is calculated by using the formula:
\(Efficiency = \frac{E_O}{E_I}\) × \(100\)
Where:
Eo is the energy output.Ei is the energy input.Substituting the given parameters into the formula, we have;
\(Efficiency = \frac{201}{1176}\) × \(100\)
\(Efficiency = 0.171\) × \(100\)
Efficiency = 17%
Therefore, the efficiency of the engine is 17%.
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6 verify it in the laboratory. State Hooke's law. Describe how you can A force of 40 N stretches a wire through 30 cm. What force will stretch it through 5.00 and through what length will a force of 100N stretch it? What assumption have you made? State Hooke's law
Light can travel through materials that you cannot see through, like wood or aluminum foil.
agree or disagree
Answer:
Agree
Explanation:
Regarding the aluminium foil, its actually a transparent material, allowing almost all light to pass through. Non-visible light, such as radio waves, x-rays, and gamma-energy photons, can most definitely can travel through wood too. So yeah agree.
Light can travel through transparent materials which we can see through. Materials like, wood, aluminums foil etc. are opaque to light and does not pass light through it. Hence, disagreeing to the statement.
What is transparency?A material is said to be transparent if light can pass through it. Thus light any of the phenomenon like transmission, absorption or reflection. A fraction of light transmitting through the material is absorbed by it.
Mirror, glass, water etc. are transparent and light can transmit through it. These materials can absorb light and reflect a portion. The amount of incident light that is absorbed by the material is dependent on its nature.
Objects that does not pass light through them are called opaque. They cant absorb or reflect light. Objects such as wood, aluminum foil, metals such as iron etc. are opaque. Thus, the given statement is false.
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A 232g ball hangs on the end of a spring. When the spring is pulled down it oscillates with a period of .13s. When pull down too far to a point .56m below the equilibrium position, the ball flies off the spring when it reaches its equilibrium position, and flies into the air.
Find the spring constant
Find the height the ball reaches.
The spring constant is 542 N/m.
The height the ball reaches is 37.5 m.
Angular speed of the ball
The angular speed of the ball is calculated as follows;
ω = 2π/T
ω = (2π) / (0.13)
ω = 48.33 rad/s
Spring constantThe spring constant is calculated as follows;
ω = √(k/m)
ω² = k/m
ω²m = k
(48.33² x 0.232) = k
542 N/m
Linear speed of ballv = ωL
v = 48.33 x 0.56 m
v = 27.1 m/s
Height reached by the ballh = v²/2g
h = (27.1²) / (2 x 9.8)
h = 37.5 m
Thus, the spring constant is 542 N/m.
The height the ball reaches is 37.5 m.
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1.5 kg ball has an acceleration of 9.0 m/s^2 to the left. what is the net force acting on the ball
1.5 kg ball has an acceleration of 9.0 m/s^2 to the left. what is the net force acting on the ball 13.50 N Leftwards
What is acceleration ?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
Any object's mass and acceleration in the force's direction are multiplied together to form the net force exerted on it.
Here, F = m*a
F = 1.5*9.0 = 13.50 N
Since, the acceleration is to the left, the net force also acts towards left.
13.50 N Leftwards
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Which of the following could be an example of chemical weathering?
a. rocks tumbling against each other
b. water seeping into the ground, dissolving the limestone to form a cave
c. a waterfall boring out a whole in a rock under it
Answer: B
Explanation:
Answers A and C are examples of physical weathering while B is chemical weathering when water and lime mix it creates a reaction
A substance has a mass of 15,000 kg and a volume of 30 m 3 . What is the density of thesubstance?
ANSWER
500 kg/m³
EXPLANATION
Given:
• The mass of the substance, m = 15,000 kg
,• The volume of the substance, V = 30 m³
Find:
• The density of the substance, ρ
The density of a substance of mass m and volume V is,
\(\rho=\frac{m}{V}\)Substitute the known values and solve,
\(\rho=\frac{15,000kg}{30m^3}=500kg/m^3\)Hence, the density of the substance is 500 kg/m³.
You push a box along the floor against a constant force of friction. When you push with a horizontal force of 75 N, the acceleration of the box is 0.75 m/2. If the mass of the box is 10 kg. find the coefficient of kinetic friction between the box and the floor.
The coefficient of kinetic friction between the box and the floor, μ = 0.1 m/2.
Equation :To find out the coefficient of kinetic friction between the box and the floor we will the formula,
μ = F/N
where,
F is friction force
N is normal force
So by question given is mass and acceleration we have to calculate friction force,
So to find F we use,
F = ma
F = 10 x 0.75 m/2
F = 7.5 m/2
By using formula of coefficient of kinetic friction,
μ = F/N
μ = 7.5 / 75
μ = 0.1 m/2
Coefficient of kinetic friction :The kinetic friction coefficient (F) is the ratio of the kinetic friction force (F) between both the surfaces in contact during motion to the normal force Ff/N. The static and kinetic coefficients of friction are both affected by the surfaces in contact. Their values are determined through experimentation.
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A. Find the initial speed of the hot magma B. What horizontal distance (D in picture) did the hot magma travel?
Given,
The angle of projection, θ_D=35.0°
The time of flight, T=45.0 s
The height, h=3.30 km=3300 m
A.
The time of flight of a projectile is given by,
\(T=\frac{2u\sin \theta}{g}\)Where u is the initial velocity of the magma chunk and g is the acceleration due to gravity.
On substituting the known values,
\(\begin{gathered} 45.0=\frac{2\times u\times\sin 35.0\degree}{9.8} \\ \Rightarrow u=\frac{45.0\times9.8}{2\times\sin 35.0\degree} \\ =384.43\text{ m/s} \end{gathered}\)Thus the initial speed of the magma chunk is 384.43 m/s
B. The horizontal distance of the flight of the magma chunk is given by,
\(\begin{gathered} R=u_xT \\ =u\cos \theta\times T \end{gathered}\)Where u_x is the horizontal component of the initial velocity.
On substituting the known values,
\(\begin{gathered} R=384.43\times\cos 35.0\degree\times45.0 \\ =14170.8\text{ m} \\ =14.17km \end{gathered}\)Thus the horizontal distance of the magma is 14.17 km
A car starts at a position of 1 km and moves to a final position of -3 km. What is the total distance traveled by the car?
The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.
What is displacement?Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.
There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider
On the number line, we can see the movement as follows
1 0 -1 -2 -3= 4km
Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.
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Which term describes the force applied to an object multiplied by the time the force is applied
Answer:
Momentum
Explanation:
In order for an object's momentum to change,a force must be applied for a period of time
Think about a hot air balloon travelling around the world in 11 days. How can a balloon travel so far and fast without a engine or other system on board to move the balloon horizontally
Answer:
?
Explanation:
What is the speed of an electron traveling 32 cm in 2 ns?
Answer:
Speed, \(v=1.6\times 10^8\ m/s\)
Explanation:
Given that,
Distance covered by the electron, d = 32 cm = 0.32 m
Time, t = 2 ns
We need to find the speed of an electron. Speed is equal to distance covered divided by time. So,
\(v=\dfrac{0.32}{2\times 10^{-9}}\\\\v=1.6\times 10^8\ m/s\)
So, the speed of the electron is \(1.6\times 10^8\ m/s\).
An open organ pipe has a fundamental frequency of 262 Hz at room temperature (20oC). What is the length of the pipe?
Given:
Fundamental frequency = 262 Hz.
Temperature = 20 degrees celcius
Let's find the length of the pipe.
Apply the resonant frequency:
\(f_o=\frac{v}{2L}\)Where:
L is the length.
To find the length, rewrite the equation for L:
\(L=\frac{v}{2f_o}\)Where v is te speed, to find the speed, we have:
\(\begin{gathered} v=331\sqrt[]{1+\frac{T}{273}} \\ \\ \text{Where:} \\ T=20^0c \\ \\ v=331\sqrt[]{1+\frac{20}{273}} \\ \\ v=331\sqrt[]{1+0.07326} \\ \\ v=331(1.03598) \\ \\ v=342.9\text{ m/s} \end{gathered}\)Thus, to find the length, we have:
\(\begin{gathered} L=\frac{342.9}{2\times262} \\ \\ L=\frac{349.2}{524} \\ \\ L=0.67\text{ m} \end{gathered}\)Therefore, the length of the pipe is 0.67 m.
ANSWER:
0.67 m
Compare the rate of loss of heat from a metal sphere at 827°C with the rate of loss of heat from the same sphere at 427°C,if the temperature of the surrounding is 27°C
Answer:
The rate of heat loss from the metal sphere at 827°C is twice the rate of heat loss from the same sphere at 427°C.
Explanation:
The rate of heat loss from an object can be determined using Newton's law of cooling, which states that the rate of heat loss is proportional to the temperature difference between the object and its surroundings. Mathematically, this is expressed as...
\(Q = k \Delta T\)
Where...
"Q" is the heat loss/gain"k" is the constant of proportionality which is the cooling constant "ΔT" is the change in temperature\(\hrulefill\)
For the sphere at 827°C:
\(\Delta T_1= 827\°C - 27\°C \\\\\Longrightarrow \boxed{\Delta T_1=800\°C}\)
For the sphere at 427°C:
\(\Delta T_2= 427\°C - 27\°C \\\\\Longrightarrow \boxed{\Delta T_2=400\°C}\)
Assuming that the cooling constant k remains constant, we can compare the rates of heat loss.
\(\dfrac{Q_1}{Q_2} =\dfrac{\Delta T_1}{\Delta T_2}\\\\\Longrightarrow \dfrac{Q_1}{Q_2} =\dfrac{800\textdegree C}{400\textdegree C} =\boxed{2}\)
Thus, the rate of heat loss from the metal sphere at 827°C is twice the rate of heat loss from the same sphere at 427°C when the temperature of the surroundings is 27°C.
Nisha stands at the edge of an aquarium 3.0 m deep. She
shines a laser at a height of 1.7 m that hits the water of the pool
8.1 m from the edge. How far from the edge of the pool will the light hit bottom?
It's denoting to a right angle traingle
Perpendicular=P=3+1.7=4.7mBase=B=8.1mHypotenuse we need
Apply Pythagorean theorem
H²=P²+B²H²=4.7²+8.1²H²=87.7H=9.4mExplanation:
The graph of y = √x is reflected in the y-axis, is horizontally stretched by a factor of 2, shifted 3 units up and 1 unit left. What is the equation of the transformed graph?
Original: y = √(x)
Reflected in the y-axis: y = √(-x)
Horizontally stretched by a factor of 2: y = √(-x/2)
Shifted 3 units up: y = 3 + √(-x/2)
And 1 unit left: y = 3 + √(-(x+1)/2)
You have been managing your time for years so you probably already have some ideas about what works for you. What are some effective time management strategies you have used at home at school or in the workplace? Why were they successful?
One of the most effective time management strategies that I have used is creating a to-do list. They are successful because they help me to prioritize tasks, remain organized, increase productivity, and reduce stress.
One of the most effective time management strategies that I have used is creating a to-do list.
Creating a to-do list helps me to prioritize tasks and ensures that I do not forget any important tasks.
When creating a to-do list, I ensure that I put the most important tasks at the top of the list and then work my way down.
The to-do list has helped me to organize my work, manage my time effectively and reduce stress.
Another effective strategy that I have used is breaking large tasks into smaller manageable tasks.
When dealing with complex tasks, I break them down into smaller, more manageable chunks.
This helps me to focus on the individual parts of the task, which are easier to handle and manage.
When I focus on smaller tasks, I find it easier to get started, and I gain momentum as I make progress on each small task.
This method has helped me to increase my productivity and reduce the stress that comes with handling large tasks.
In conclusion, the above time management strategies have helped me to manage my time effectively at home, school, and in the workplace.
They are successful because they help me to prioritize tasks, remain organized, increase productivity, and reduce stress.
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WILL MARK BRAINLIST. HELP ASAP
A student on her way to school walks four blocks east, three blocks north, and another four blocks east, as shown in the diagram.
Compared to the distance she walks, the magnitude of her displacement from home to school is -
A) less than the distance.
B) zero.
C) the same as the distance.
D) greater than the distance.
Answer:
Less than the distance
The road runner was being chased and outsmart the coyote. He ran past the road runner an fell straight down off a cliff. He fell with the same acceleration as gravity (9.8). Calculate his displacement if he fell for 4 seconds
The displacement of the runner after four seconds is 78.4 m.
What is the displacement after 4 seconds?We know that in this case, we are dealing with a case of an object that has a motion under gravity. We are told that the road runner an fell straight down off a cliff. The fact that we have been told that the runner just fell down the cliff means that the initial velocity of the runner would have to be taken in this context as zero since the runner was dropped from a height as shown.
Acceleration of the runner (g) = 9.8 m/s^2
Initial velocity of the runner (u) = 0 m/s
Time take (t) = 4 seconds
We then have;
h = ut + 1/2gt^2
If we then know that the initial velocity of the person is zero, then we have;
h = 1/2gt^2
h = 0.5 * 9.8 * (4)^2
h = 78.4 m
The height is 78.4 m.
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A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?
The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.
Electrostatic attractionSince the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.
The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.
According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.
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n a ballistics test, a potato gun shoots a 0.34 kg potato into a 5.0 kg catching cart. The cart recoils at 3.7 m/s after catching the potato. Determine the initial velocity of the potato.
The initial velocity of the potato is 54.41 m/s.
The given parameters:
Mass of the potato, m = 0.34 kgMass of the cart, m = 5.0 kg Velocity of the recoil, u₂ = 3.7 m/sThe initial velocity of the potato is calculated by applying the principle of conservation of energy as follows;
\(m_1u_1 = m_2 u_2\\\\u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{5 \times 3.7}{0.34} \\\\u_1 = 54.41 \ m/s\)
Thus, the initial velocity of the potato is 54.41 m/s.
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