Answer:
the average velocity in which mario Jones ran the 100m dash and won the gold medal was 9.30m/s
a horse mass of 150kg it has force of 50n what is its acceleration
Remember, there's 2 types of accelaration formula.
1st formula :
a = ( final speed - initial speed ) ÷ time
2nd formula :
resultant force (f) = mass × a
or
a = resultant force (f) ÷ mass
So the ans shld be,
a = 50 x 150
= 7500 m/s²
The acceleration of the body is 0.33 m/s².
What is meant by acceleration of an object ?Acceleration of an object having mass is defined as the net force acting on the object per unit mass.
Here,
Mass of the body, m = 150 kg
Force acting on the body, F = 50 N
The net force acting on an object is defined as the product of mass and acceleration of the object.
The expression for the net force acting on the body is given by,
F = ma
Therefore, the acceleration of the body,
a = F/m
Applying the values of F and m,
a = 50/150
a = 0.33 m/s²
Hence,
The acceleration of the body is 0.33 m/s².
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A block weighing 10 newtons is on a ramp inclined at 30° to the horizontal. A 3-newton force of friction acts on the
block as it is pulled up the ramp at a constant velocity. The force applied to pull the box up the ramp acts parallel to the
incline. Draw the FBD for this problem and determine the magnitude of the force applied.
The force applied to pull the box up the ramp acts parallel to the incline is 8N
The force applied to pull the box is expressed as:
\(F_N = F_m + F_f\)
Fm is the moving force
Ff is the force of friction
Get the moving force and frictional fice
\(F_m = 10sin30^0 = 5N\\F_f = 3N\)
The force applied to pull the box up the ramp acts parallel to the incline = 5N + 3N = 8N
Hence the force applied to pull the box up the ramp acts parallel to the incline is 8N
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(b) Complete the sentence about longitudinal
waves.
The vibrations of the air particles are.....
to the
direction of energy transfer.
(C) A stationary car horn emits a sound wave frequency 400 Hz. The wavelength of the wave is 0.85 m. Calculate the speed of sound.
Answer:
see below
Explanation:
b ) the vibrations of the air particles are parallel to the direction of energy transfer.
c) use formula
speed = wavelength x frequency
speed = 0.85 x 400
speed = 340 m/s
hope you get it
please mark
A vehicle travels a distance of 300km. It took the vehicle 6 hours to make the trip.
What is the speed of the vehicle?
Answer:
50 kmph
Explanation:
300 / 6 = 50
how you would orient the magnets and what you would do with the magnets to achieve maximum repulsion
The orientation of the magnets that gives the strongest repulsion because these poles and facing each other that is then leaves highest flux density of the poles for a force of repulsion to be very high
A iPhone charger system producing 14.5 Volts with a current flow of 43.5 Amps. What is the circuit resistance?
Answer:
The resistance of the circuit is 0.\(\bar 3\) Ω
Explanation:
The given parameters are;
The voltage the charger produces = 14.5 Volts
The current flow of the charger = 43.5 Amps
Therefore, the resistance of the circuit, R = Voltage V/(Current, I)
R = V/I = 14.5/43.5 = 1/3 = 0.\(\bar 3\) Ohms
The resistance of the circuit = 0.\(\bar 3\) Ohms
Which can be written with the symbol for the unit of resistance Ω as follows;
The resistance of the circuit = 0.\(\bar 3\) Ω.
Every day, every hour, every second one of the most important events in life is going on in your body—cells are dividing. When cells divide, they make new cells. A single cell divides to make two cells and these two cells then divide to make four cells, and so on. We call this process "cell division" and "cell reproduction," because new cells are formed when old cells divide. The ability of cells to divide is unique for living organisms. 3.A) _________ is a type of cell division which results in the formation of gametes. *
Answer:
the answer to the question is mitosis
suppose you start an antique car by exerting a force of 250 n on its crank for 0.19 s. What angular momentum is given to the engine if the handle of the crank is 0.300 m from the pivot and the force is exerted to create maximum torque the entire time?
The angular momentum given to the engine is: L = I × ωL = 1 kg·m² × 69.8 rad/sL = 69.8 kg·m²/s
Torque (τ) = F × r
Maximum torque is produced when force is applied perpendicular to the radius, i.e. at 90°.So, sin 90° = 1
τ = F × r × 1
= F × r
The formula for the angular momentum is: Angular momentum (L) = I × ω
Where,I is the moment of inertiaω is the angular velocity. We know that,
τ = Iα .............(1)
From rotational equations,α = τ / I ..............(2)
The formula for the angular velocity is:ω = ωo + αt...............(3)
Substituting equation (2) in equation (1), we get,
τ = I(τ / I)
τ = τ
Therefore,τ = τ. So,α = τ / I. Substituting values of τ and r in equation (1), we get,
F × r = Iα
F × r = I(τ / I)
F × r = τ
I = (F × r) / τ
Substituting values of F, r and τ, we get ,I = (250 N × 0.300 m) / (250 N × 0.300 m)I = 1 kg·m²
The angular velocity is:ω = ωo + αt.
As the car is started from rest, ωo = 0. So, ω = αt. Substituting values of α and t, we get,
ω = (τ / I) × t
ω = (250 N × 0.300 m) / (1 kg·m² × 0.19 s)
ω = 69.8 rad/s.
Therefore, the angular momentum given to the engine is: L = I × ωL = 1 kg·m² × 69.8 rad/sL = 69.8 kg·m²/s
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5 ohms resistors are connected in parallel, the equivalent resistance is?
a light board that is 10 m long is supported by two sawhorses, one at one end of the board and a second at the midpoint. a 48-n object is placed between the two sawhorses, 3.2 m from the end and 2.2 m from the center. a second object, with a weight of 15 n, is placed on the supported end. what magnitude forces do the sawhorses exert on the board?
Magnitude forces do the sawhorses exert on the board 11.6N and 36.4N
Calculation:
Given that a light board that is 10 meters long is supported by two sawhorses, one at each edge and the middle. Between the two sawhorses, 3.2 meters from the edge and 2.2 meters from the center, is a small 48-N weight.
We must take into account the balance of forces operating on the board in order to determine the forces that the sawhorses are exerting on it.
Let P1 and P2 represent the two upward forces generated by the saw horses.Considering that the weight is insignificant
The descending pressures are equal to the sum of the upward forces.
P1 + P2 = 48....... (1) (1)
Additionally, the anticlockwise moments are equal to the sum of the clockwise moments.
Take for granted that the board is uniform. The center will be where the weight acts.
Spending a moment in the middle:P1 × 5 + 48× 2 = 0\sP1 = 58/ 5\sP1 = 11.6N
P1 should be replaced in equation 1.11.6 + P2 = 48\sP2 = 48 - 11.6\sP2 = 36.4N
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Blocks A and B oscillate at the ends of identical springs. The period of B’s oscillation is twice as long as that of A’s. How many times more massive is block B than block A?
The period of oscillation is the time it takes for an object to complete one full oscillation, and it is inversely proportional to the square root of the spring constant and directly proportional to the square root of the mass of the object. The period of oscillation is given by the formula T = 2π √(m/k) where T is the period, m is the mass of the object, and k is the spring constant.
Let's assume that the period of A's oscillation is T1 and the period of B's oscillation is T2. From the problem statement, we know that T2 = 2T1. Using the formula for the period of oscillation, we can write:
T2 = 2π √(m2/k) = 2 * 2π √(m1/k) = 2T1 = 2π √(m1/k)
Dividing the equation T2 = 2T1 by T1, we get T2/T1 = 2
So m2/m1 = (k*(T2/T1)^2) = (k*2^2) = 4k
Therefore, block B is 4 times more massive than block A.
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Question 29 of 43
Which is true of infrared waves?
They have shorter wavelengths than X-rays.
They give off more energy than gamma rays.
Ο Ο Ο Ο
o They have longer wavelengths than ultraviolet waves.
They have higher frequencies than visible light waves
Infrared wave basically have shorter wavelengths than X-rays. The correct option is A.
What is infrared wave?A section of the electromagnetic radiation spectrum with wavelengths ranging from roughly 700 nanometers (nm) to one millimetre is known as infrared radiation (IR), or simply infrared (mm).
While shorter than radio waves, infrared waves are longer than visible light waves.
Infrared radiation has the ability to ease muscle tension and encourage local blood circulation.
Infrared radiation has been used in conventional medicine to treat conditions including autoimmune diseases and issues with wound healing in addition to relieving muscle pain and tension.
Infrared waves are shorter than radio waves but longer than visible light waves.
Thus, the correct option is A.
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If the human ear could not detect differences in the amplitude of sound waves, people would not be able to detect differences in the?
People wouldn't be able to distinguish between differences in sound volume if the human ear couldn't detect variations in the amplitude of undulations.
What determines the amplitude of a sound?
The amplitude of a sound wave is the life of the peak of the wave. The amplitude of a sound wave is outlined because the loudness or the quantity of most displacement of moving particles of the medium from their mean position once the sound is produced.
Amplitude of Sound. The strength or level of sound pressure. The amount of molecules in the sound wave in b is greater than the amount within the undulation in a, thus the amplitude of the sound wave in b is larger.To learn more about Amplitude of a sound, visit:
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A machine produces a larger force than you exert to operate the machine. How does this input distance of the machine compare to its output distance?
Answer:
Because the output force is greater than the input force, the input distance must be greater than the output distance.
Explanation:
Sound waves are produced when something is caused to
*reflect.
*vibrate.
*slow down.
*get warmer.
Sound waves are produced when something is caused to vibrate.
What is Sound wave?
This can be defined as the pattern of disturbance caused by the movement of energy traveling through a medium.
Sound is produced when a substance vibrates leading to movement in surrounding air molecules.
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Unpolarised light of intensity I is incident on a system of two polarizers
Unpolarized light of intensity I is incident on a system of two polarizes, A followed by B. The intensity of emergent light is I/2. If a third polarizer C is placed between A and B, the intensity of emergent light is reduced to I/3. The angle between the polarizers A and C is θ
When unpolarized light of intensity I passes through a system of two polarizers A and B, with an angle θ between A and C, and a third polarizer C placed between A and B, the intensity of the emergent light is reduced to I/3.
The given scenario involves unpolarized light with an initial intensity of I passing through two polarizers, A and B. When the emergent light passes through this system, its intensity reduces to I/2.
However, if a third polarizer, C, is introduced between A and B, the intensity of the emergent light further decreases to I/3. The angle between polarizers A and C is denoted as θ.
The interaction of polarizers with unpolarized light is due to their ability to transmit light waves oscillating in a specific plane while blocking those oscillating perpendicular to that plane.
When unpolarized light passes through the first polarizer A, it allows only a portion of the light oscillating in a specific plane to pass through, reducing the intensity to I/2.
When polarizer C is inserted between A and B, it further restricts the passage of light oscillating in the plane perpendicular to its transmission axis. This leads to a decrease in the intensity of emergent light to I/3.
The angle θ between A and C influences the extent to which light is transmitted through this intermediate polarizer C.
Overall, the polarizers A and B, in combination with the intermediate polarizer C, work together to reduce the intensity of unpolarized light incident on the system. The specific angle θ between polarizers A and C determines the resulting intensity of emergent light.
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Consider the
29
65
Cu nucleus. Find approximate values for its (a) radius, (b) volume, and (c) density
The approximate radius is 3.704 x 10⁻¹⁵ meters. The approximate volume is 2.166 x 10⁻⁴³ cubic meters. The density cannot be determined without the mass of the nucleus.
The radius, volume, and density of the Cu nucleus can be approximated using the given information.
a) To find the approximate radius of the Cu nucleus, we need to consider the atomic number of Cu, which is 29. The atomic number represents the number of protons in the nucleus. In a neutral atom, the number of protons is equal to the number of electrons.
The radius of a nucleus can be estimated using the formula:
radius = r0 x A^(1/3),
where r0 is a constant (approximately 1.2 x 10⁻¹⁵ meters) and A is the atomic mass number. In this case, A is equal to the atomic number, which is 29 for Cu.
Therefore, the approximate radius of the Cu nucleus is:
radius = 1.2 x 10⁻¹⁵ x 29^(1/3) = 1.2 x 10⁻¹⁵ x 3.087 = 3.704 x 10⁻¹⁵meters.
b) The volume of a nucleus can be calculated using the formula for the volume of a sphere:
volume = (4/3) x π x radius³.
Substituting the approximate radius value we found earlier, we get:
volume = (4/3) x π x (3.704 x 10⁻¹⁵)³ ≈ 2.166 x 10⁻⁴³ cubic meters.
c) To find the density of the Cu nucleus, we need to know its mass. However, the question does not provide information about the mass of the nucleus. Therefore, we cannot determine the density without this information.
In conclusion, for the given Cu nucleus:
(a) The approximate radius is 3.704 x 10⁻¹⁵ meters.
(b) The approximate volume is 2.166 x 10⁻⁴³ cubic meters.
(c) The density cannot be determined without the mass of the nucleus.
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is noise energy a kind of energy or not
a firecracker streaks to its highest point and breaks into many pieces, one of which has a mass of 0.27 kg and moves in the x-direction at 70.7 m/s. a second piece has a mass of 0.47 kg and moves in the y-direction at 30.3 m/s. calculate the magnitude of the total momentum of these two pieces.
The magnitude of the total momentum of these two pieces is 23.815 kg·m/s.
In Newtonian mechanics, momentum is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction.
To calculate the magnitude of the total momentum of the two pieces of a firecracker, we will use the given information on their masses and velocities, and the formula for momentum.
Calculate the momentum of each piece using the formula:
momentum = mass × velocity
Piece 1 (x-direction):
momentum1 = (0.27 kg) × (70.7 m/s) = 19.089 kg·m/s
Piece 2 (y-direction):
momentum2 = (0.47 kg) × (30.3 m/s) = 14.241 kg·m/s
Since the two pieces are moving in perpendicular directions, we can use the Pythagorean theorem to find the magnitude of the total momentum:
total_momentum = √(momentum1² + momentum2²)
total_momentum = √((19.089 kg·m/s)² + (14.241 kg·m/s)²)
= √(364.38721 kg²·m²/s² + 202.79881 kg²·m²/s²)
= √(567.18602 kg²·m²/s²)
= 23.815 kg·m/s
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The Coulomb force between two charges q1 and q2 at separation r in the air is 10N. If half of the separation is filled with medium of dielectric constant 7, what will be the value of new coulomb force?
Answer:
The value of new coulomb force is 1.43 N.
Explanation:
Given;
Coulomb's force in vacuum (air), \(F_v\) = 10 N
dielectric constant, K = 7
The Coulomb's force between two charges separated by a distance r in a vacuum is given as;
\(F_v = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2}\)
The Coulomb's force between two charges separated by a distance r in a medium with dielectric constant is given as
\(F_m = \frac{1}{4\pi K\epsilon_0} \frac{q_1q_2}{r^2}\)
Take the ratio of the two forces;
\(\frac{F_v}{F_m} = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r^2} \ \times \ \frac{4\pi K\epsilon_0 r^2}{q_1q_2} = K\\\\\frac{F_v}{F_m} = K\\\\\frac{10}{F_m} = 7\\\\F_m = \frac{10}{7} \\\\F_m = 1.43 \ N\)
Therefore, the value of new coulomb force is 1.43 N.
What are the 3 Newton's Laws
Explanation:
Newton's first law of motion
state If a body is at rest it remain at reast and if it is in a motion it continue it's motion unless a net external force acting on it.
This law also called law of inertia
Newton's second law motion
states that acceleration to the force acting on the body and inversely proportional to the mass of the body
Newton's third law motion It is not to exert a force abody without the body exerting a forces in the opposite direction
These forces are called action and reaction force.
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THANK YOU
How can you tell when the forces acting on a system are balanced?
a. no lift
b. no accelleration
c. no displacement
d. no gravity
Answer:
a. no lift
Explanation:
To determine if the forces acting upon an object are balanced or unbalanced, an analysis must first be conducted to determine what forces are acting upon the object and in what direction. If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced.
plz give me a brianliest
10) What is the astronomer's notation for ionization states of an atom?
The astronomer's notation for the ionization states of an atom is typically written with a Roman numeral indicating the number of electrons that have been removed from the neutral atom.
For example, Fe II represents an ionized iron atom that has lost one electron, while Fe III represents an ionized iron atom that has lost two electrons. This notation is used to describe the different levels of ionization that an atom can undergo.
The astronomer's notation for ionization states of an atom is represented using a Roman numeral system. In this notation:
- Neutral atom: The notation is written with the element symbol followed by the Roman numeral I (e.g., H I for neutral hydrogen).
- Ionized atom: The notation is written with the element symbol followed by a Roman numeral indicating the number of electrons lost during ionization. For example, H II represents a hydrogen atom that has lost one electron, and O III represents an oxygen atom that has lost two electrons.
In summary, the astronomer's notation uses element symbols and Roman numerals to indicate the ionization state of an atom, with the Roman numeral denoting the number of electrons lost during the ionization process.
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PLEASE HELP MEEE!!!
In a science experiment showing the splitting of water into Oxygen and hydrogen, two inverted test tubes of water were placed over the site of the reaction. (see the pic) How can you tell which one was catching the oxygen and which one was catching the hydrogen?
A. The hydrogen is a positive ion and will be located close to the negative terminal of the battery.
B. The oxygen is a negative ion which will be located next to the negative terminal of the battery.
C. There are 2 hydrogen atoms for every oxygen atom. The hydrogen will take up more space and is pushing the water lower in the test tube.
D. The hydrogen, being a smaller atom, will take up less space than the oxygen. It will push the water down less.
Answer:
Option C
Explanation:
Answer C is the correct option. water can be written as H₂O, which means that there are 2 Hydrogen atoms for every oxygen atom, therefore it will occupy more space than oxygen and push more. there is also one more possibility, if the splitting takes place in Hoffman's Voltameter then the Hydrogen will be close to the cathode as hydrogen is positive. Otherwise, option C is correct answer. Hope this Helps you!
Mass of a car is given as 6000 kg is moving with a velocity of 40 m/s. Calculate the momentum of the car
try mass by velocity and Ur answer will come
Answer:
Explanation:
given
m = 6000kg
v = 40 m/
p = ?
solution
p = mv
p = 6000kg × 40m/
p =240000kg.m/
a converging lens is used to project a real image onto a screen. a piece of black tape is then placed over the upper half of the lens. will only the lower half of the image be visible on the screen? justify your answer by drawing light rays from various points on the object to the corresponding points on the screen.
The whole image will be seen. To see this, draw one ray from the top of the image through the center. Then draw another ray from the top of the image through the focus of the lens, emerging paraxially on the real side. These two lines crisscross below the axis, and this is where the image of the top of the object is; the image is inverted. Finally, draw similar lines from the bottom of the object.
These strains meet closer to the axis, and that is where the picture of the bottom of the object is. surely, then, the whole photo can be visible because you could see the top and the lowest. however, because fewer rays reach the picture, the intensity of the picture could be much less than without the tape.
A lens is a transmissive optical tool that focuses or disperses a light beam by means of refraction. An easy lens includes a single piece of transparent cloth, even as a compound lens consists of several simple lenses (elements), commonly arranged along a not-unusual axis. Lenses are made from materials together with glass or plastic, and are floor and polished or molded to a favored shape.
A lens can awareness mild to shape an image, in contrast to a prism, which refracts mildly without focusing. gadgets that similarly attention or disperse waves and radiation apart from visible mild are also referred to as lenses, consisting of microwave lenses, electron lenses, acoustic lenses, or explosive lenses.
Lenses are used in numerous imaging devices like telescopes, binoculars, and cameras. they may be extensively utilized as visible aids in glasses to correct defects of imagination and prescient which includes myopia and hypermetropia.
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art integration in superconductors
copper wire is the example of superconductor
Find the net force acting on a box that has a force of 50 newtons pulling at an angle of 30 degrees and a force of 90 newtons pulling at a 160 degree angle
Answer:
Approximately \(69\; {\rm N}\) at approximately \(126^{\circ}\).
Explanation:
Assume that both angles in the question are relative to the positive \(x\)-axis (towards the positive horizontal direction.)
Horizontal component (\(x\)-component) of the two forces would be:
\((50\; {\rm N}) \, \cos(30^{\circ}) = \left(25\, \sqrt{3}\right)\; {\rm N} \approx 43.3\; {\rm N}\).\((90\; {\rm N}) \, \cos(160^{\circ}) \approx (-84.6) \; {\rm N}\).Note that the \(x\)-component of the \(90\; {\rm N}\) force is negative since this components points away from the positive \(x\!\)-direction.
Hence, the net force in the \(x\)-component would be:
\((50\; {\rm N}) \, \cos(30^{\circ}) + (90\; {\rm N}) \, \cos(160^{\circ}) \approx (-41.3) \; {\rm N}\).
(Again, this component is negative since it points away from the positive \(x\)-axis.)
Similarly, the vertical component (\(y\)-component) of the two forces would be:
\((50\; {\rm N}) \, \sin(30^{\circ}) = 25\; {\rm N}\).\((90\; {\rm N}) \, \sin(160^{\circ}) \approx 30.8 \; {\rm N}\).Hence, the net force in the \(y\)-component would be:
\((50\; {\rm N}) \, \sin(30^{\circ}) + (90\; {\rm N}) \, \sin(160^{\circ}) \approx 55.8\; {\rm N}\).
Refer to the diagram attached. The resultant net force is the vector sum of the components. Apply the Pythagorean Theorem to find this net force:
\(\begin{aligned}(\text{net force}) &= \sqrt{(\text{$x$-component})^{2} + (\text{$y$-component})^{2}} \\ &\approx \sqrt{(-41.3)^{2} + (55.8)^{2})}\; {\rm N} \\ &\approx 69\; {\rm N}\end{aligned}\).
Find the angle of this net force relative to the positive \(x\)-axis using the inverse cosine function \(\arccos\):
\(\begin{aligned}\arccos\left(\frac{(\text{$y$-component})}{(\text{net force})}\right) &\approx \arccos\left(\frac{55.8\; {\rm N}}{69\; {\rm N}}\right) \\ &\approx 126^{\circ}\end{aligned}\).
(The units might need to be converted into degrees.)
A series RLC circuit driven by a source with an amplitude of 120.0 V and a frequency of 50.0 Hz has an inductance of 792 mH, a resistance of 278 Ω, and a capacitance of 44.3 µF.
(a) What are the maximum current and the phase angle between the current and the source emf in this circuit?
Imax = A
φ = Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.°
(b) What are the maximum potential difference across the inductor and the phase angle between this potential difference and the current in the circuit?
VL, max
= V
φ = °
(c) What are the maximum potential difference across the resistor and the phase angle between this potential difference and the current in this circuit?
VR, max
= V
φ = °
(d) What are the maximum potential difference across the capacitor and the phase angle between this potential difference and the current in this circuit?
VC, max
= V
φ = °
The maximum current and the phase angle between the current and the source emf in this circuit is 0.339 A.
The maximum potential difference across the inductor and the phase angle between this potential difference and the current in the circuit are 33.8 V and 73.4°.
The maximum potential difference across the capacitor and the phase angle between this potential difference and the current in this circuit are 24.4 V and -106.6°.
How does impedance work?
Impedance is a unit of measurement for the resistance to electrical flow, and it is represented by the letter Z. It is measured in ohms. For DC systems, the quantities resistance and impedance—which are determined by dividing the voltage across an element by the current—are equivalent.
The maximum current and phase angle in this circuit between the current and the source emf are:
Xl = 2πfL = 2π × 50.0 × 0.792 = 99.36 Ω
Xc = 1/(2πfC) = 1/(2π × 50.0 × 44.3 × 10^-6) = 72.06 Ω
Z = √(R² + (Xl - Xc)²) = √(278² + (99.36 - 72.06)²) = 353.3 Ω
φ = arctan((Xl - Xc)/R) = arctan((99.36 - 72.06)/278) = 0.289 rad = 16.6°
Imax = V/Z = 120.0/353.3 = 0.339 A
The maximum potential difference across the inductor and the phase angle between this potential difference and the current in the circuit:
VL, max = Imax Xl = 0.339 × 99.36 = 33.8 V
90° - φ = 73.4°.
The maximum potential difference across the capacitor and the phase angle between this potential difference and the current in this circuit:
VC, max = Imax Xc = 0.339 × 72.06 = 24.4 V
-90° - φ = -106.6°.
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Define 1 joule work ?
Explanation:
Force is applied to lift a body against the force of gravity. Example: If an object is lifted to a certain height (h)