Based on the provide system of linear equations, the solution is that there is no solution.
A system of linear equations refers to a collection of one or more linear equations involving the same variables. The solution to a system of linear equations refer to the point at which the lines representing the linear equations intersect. If the lines are parallel, they will never intersect hence, the system has no solution.
According to the provided information, the percentage of smokers in Russia is given by the equation 36x+100y=346 and the percentage of smokers in Poland is given by the equation 18x+50y=176. In order to determine the solution of the system of linear equations, multiply the Poland equation by 2 and subtract it from the Russian equation. Hence,
2*(18x+50y=176)
36x + 100y = 352
-(36x+100y=346)
0 = 6
It means the original equations are parallel. As both the variables are eliminated, the system has no solution.
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Our school has 564 students. If each class contains 23 students what percent of the student body is in your grade?
Answer:
4%
Step-by-step explanation:
23÷564 is .04 which in percentage form is 4%
hope this helps
Krystine has a weekend job advertising an upcoming play. She has two options for being paid. Option A is an hourly wage of $7.00. Option B is a 5% commission on tickets sales. She plans to work 8 hours on both Saturday and Sunday. Tickets are sold for $10 each, and Krystine estimates she will sell about 200 tickets. Which option gives Krystine more earnings this weekend?
Answer:
The answer is A, because $7.00 is more than 5% commission on ticket sales.
Step-by-step explanation:
8+3x−2y−3 equivalent equation
The equivalent equation is 3x − 2y + 5.
What is the equation?The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.
What are Arithmetic operations?Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.
- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.
for example 4 -2 = 2
Given that equation as:
⇒ 8 + 3x − 2y − 3
Rearrange the terms and apply arithmetic operations
⇒ 3x − 2y + 8 − 3
⇒ 3x − 2y + 5
Hence, the equivalent equation is 3x − 2y + 5.
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Which ordered pair is a solution of the inequality y≤1/3x−6
The ordered pair of the inequality will be (9,-3).
What is inequality?The inequality expressions are the mathematical equations related by each other by using the signs of greater than or less than. All the variables and numbers can be used to make the equation of inequality.
Given that inequality is given as y ≤ 1/3x−6.
The ordered pair can be calculated as:-
y ≤ 1/3x−6
Substitute the value of x equal to 9 and get the value of y,
y ≤ 1/3(9) - 6
y ≤ 3 - 6
y ≤ -3
Hence, the ordered pair will be (9,-3).
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i don't understand how to do this
please write step by step, and solve all question. I will mark you as brainliest answer!
Answer:
11, 10
Step-by-step explanation:
n(B') = 2+5+12 = 19 ; the numbers that are not included in B
n(B∩C) = y-1 +9 = y+8 ; what belongs to both B and C
a)
n(B') = n(B∩C)
19 = y +8 ; subtract 8 from both sides
19-8 = y-8+8
11 = y
b)
n(A∪B∪C) =y -1 = 11 -1 = 10 ; is what belongs to A and B and C in the same time
What is the value of x?
A.)5
B.)38
C.)42
F.)22
Answer:
x = 38
Step-by-step explanation:
3x-16+x+6+x = 180
5x -10 = 180
5x = 180 + 10
x = 190 / 5
x = 38
The population of New Jersey is
9,000,000 and is decreasing by 100,000
people each year. Georgia's population is
4,000,000 people and is increasing by
400,000 a year. How many years from
now will they have the same population?
(b) by how much could the smallest sample observation, currently 8.1, be increased without affecting the value of the sample median?
The smallest sample observation that can increase 8.1 without changing the sample median's value is 4.4.
By sample median, what do you mean?The median is the value that divides a data sample, a population, or a probability distribution's upper and lower halves in statistics and probability theory. It could be referred to as "the middle" value for a data set. Simply expressed, the sample median is the middle value after sorting the observations in ascending order if the sample size is odd. The sample median is the average of the two middle values if the sample size is equal. The data set's median value is the value that falls in the middle, ordered by magnitude. The sample median is the average of the two middle terms when the number of samples in the data set is even. When the data set is symmetrically distributed, the sample mean serves as a reliable indicator of the central tendency.
The median can be calculated as (12.5+12.6)/2=12.55.
The incremented least observed value is 12.5-8.1=4.4, and the difference is that.
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literature review on impact of covid 19 on kingston business school with citations
COVID-19 has greatly affected business schools worldwide, causing a shift to online learning and various challenges. Further research is needed to understand the specific impact on Kingston Business School and its responses to the pandemic.
Literature review on the impact of COVID-19 on business schools in general:
The COVID-19 pandemic has significantly affected business schools worldwide. Schools have rapidly transitioned to online learning, facing challenges in pedagogy and maintaining the interactive nature of education (Bao et al., 2020).
The pandemic has disrupted the student experience, limiting networking opportunities and access to campus facilities (Vlachos et al., 2020). Enrollment fluctuations, particularly among international students due to travel restrictions, have been observed (Banga et al., 2021). Financial implications have arisen, including reduced revenue and increased technology investments (Berger et al., 2020).
Career services have needed to adapt to changes in internships and job placements (Bektaş et al., 2021). Research activities have been affected, with shifts in focus and disruptions to conferences and collaborations (Perkmann et al., 2020).
Further research specific to Kingston Business School is necessary to assess the institution's unique experiences and responses to the pandemic.
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If ten people access the same AP, communication to the wired world will be limited to the equivalent of approximately 1 Mbps per user. Select True or False?
False. When multiple people access the same access point (AP), the communication to the wired world is not limited to approximately 1 Mbps per user.
The available bandwidth is shared among the users connected to the AP, but the exact speed each user experiences depends on various factors such as the total bandwidth provided by the AP, the number of users actively utilizing the network, and the nature of their online activities.
The speed experienced by each user can fluctuate depending on network congestion and the type of traffic being generated. For example, if all users are engaging in bandwidth-intensive activities like streaming high-definition videos or downloading large files simultaneously, it can impact the overall network performance, resulting in slower speeds for each individual user. However, if the network is underutilized or the users are engaged in less demanding tasks, each user may experience higher speeds closer to the maximum capacity provided by the AP.
Therefore, the statement that communication to the wired world is limited to approximately 1 Mbps per user when ten people access the same AP is false. The actual speed experienced by each user will depend on various factors and can vary significantly.
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How many distinct 2-colored necklaces of length 4 are there? Two colorings are considered identical if they can be obtained from each other by rotation. All black and all white are allowed.
Is there a better algebraic way to do this without finding all cases?
There are 2.25 distinct 2-colored necklaces of length 4, up to rotation. Since we cannot have a fractional number of necklaces, we round up to get a final answer of 3.
A necklace is made by stringing together beads in a circular shape. A 2-colored necklace is a necklace where each bead is painted either black or white. How many distinct 2-colored necklaces of length 4 are there? Two colorings are considered identical if they can be obtained from each other by rotation.Let's draw a table to keep track of our count:Each row in the table represents one way to color the necklace, and each column represents a distinct necklace.
For example, the first row represents a necklace where all the beads are black, and each column represents a distinct rotation of that necklace.We start by counting the necklaces where all the beads are the same color. There are 2 of these. We then count the necklaces where there are 2 beads of each color. There are 3 of these.Next, we count the necklaces where there are 3 beads of one color and 1 bead of the other color. There are 2 of these, as we can start with a black or white bead and then rotate.
Finally, we count the necklaces where there are 2 beads of one color and 2 beads of the other color. There are 2 of these, as we can start with a black or white bead and then rotate. Thus, there are a total of 2 + 3 + 2 + 2 = 9 distinct 2-colored necklaces of length 4, up to rotation. Answer: 9There is a better algebraic way to do this without finding all cases: Using Burnside's lemma. Burnside's lemma states that the number of distinct necklaces (up to rotation) is equal to the average number of necklaces fixed by a rotation of the necklace group. The necklace group is the group of all rotations of the necklace.
The average number of necklaces fixed by a rotation is the sum of the number of necklaces fixed by each rotation, divided by the number of rotations.For a necklace of length 4, there are 4 rotations: no rotation (identity), 1/4 turn, 1/2 turn, and 3/4 turn. Let's count the number of necklaces fixed by each rotation:Identity: All necklaces are fixed by the identity rotation. There are 2^4 = 16 necklaces in total.1/4 turn: A necklace is fixed by a 1/4 turn rotation if and only if all beads are the same color or if they alternate black-white-black-white.
There are 2 necklaces of the first type and 2 necklaces of the second type.1/2 turn: A necklace is fixed by a 1/2 turn rotation if and only if it is made up of two pairs of opposite colored beads. There are 3 such necklaces.3/4 turn: A necklace is fixed by a 3/4 turn rotation if and only if it alternates white-black-white-black or black-white-black-white. There are 2 necklaces of this type.The total number of necklaces fixed by all rotations is 2 + 2 + 3 + 2 = 9, which is the same as our previous count. Dividing by the number of rotations (4), we get 9/4 = 2.25.
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What is the value of x?
Answer:
46°
Step-by-step explanation:
from large triangle:
let the third unknown angle be 'a'
then,
a+x+7+85=180
a=88-x
now,from small triangle,
let the third unknown angle be 'b'
then,
b+x+2x=180
b=180-3x
b=a (vertically opposite angles)
then,
180-3x=88-x
2x=92
x=46
A hamburger costs $(2x + 3), chips costs $(x - 1) and a drink costs $(3x - 5). Write an
algebraic expression for the total cost of a hamburger, chips and a drink.
Answer:
(2x+3)+(x-1)+(3x-5)
Step-by-step explanation:
add all your expressions & Ect together .
A region with a 10-mile radius has a population density of about 869 people per square mile. Find the number of people who live in the region.
There are 273,028 people who live in the region.
How to find the number of people who live in the region?To find the number of people who live in the region, we need to calculate the area of the region and then multiply it by the population density.
The area of a circle with radius r is given by the formula \(A = \pi r^2.\)Therefore, the area of the region with a 10-mile radius is:
\(A = \pi r^2 =\pi (10^2)\) = 100π square miles
The number of people who live in this region can be found by multiplying the area by the population density:
Number of people = Population density x Area
= 869 people/square mile x 100π square miles
= 86900π people
Using a calculator, we can approximate this to:
Number of people ≈ 273,028.4
Therefore, there are approximately 273,028 people who live in the region with a 10-mile radius and a population density of 869 people per square mile.
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the box plots below show the heights (in centimeters) of the players on the university of maryland women's basketball and field hockey teams. 2 horizontal boxplots titled basketball team and field hockey team are graphed on the same horizontal axis, labeled height, in centimeters. the boxplot titled basketball team has a left whisker which extends from 165 to 173. the box extends from 173 to 191 and is divided into 2 parts by a vertical line segment at 188. the right whisker extends from 191 to 203. the boxplot titled field hockey team has a left whisker which extends from 157 to 160. the box extends from 160 to 168 and is divided into 2 parts by a vertical line segment at 163. the right whisker extends from 168 to 178. all values estimated. which pieces of information can be gathered from these box plots? choose all answers that apply: choose all answers that apply: (choice a) the basketball players are taller on average. a the basketball players are taller on average. (choice b) the heights of the basketball players vary noticeably more than those of the field hockey team. b the heights of the basketball players vary noticeably more than those of the field hockey team. (choice c) none of the above c none of the above
Pieces of information can be gathered from these box plots are:
(a) On average, the basketball players are taller.
(b) The heights of the basketball players vary noticeably, more than field hockey team.
What is indetail explaination of the both answer?From the given information, we can gather the following pieces of information:
(a) The basketball players are taller on average. This can be inferred from the fact that the median (the vertical line segment within the box) of the basketball team's heights (188 cm) is higher than the median of the field hockey team's heights (163 cm).
(b) The heights of the basketball players vary noticeably more than those of the field hockey team.
This can be inferred from the interquartile range (IQR) of the basketball team's heights, which is from 173 cm to 191 cm (a difference of 18 cm), and the IQR of the field hockey team's heights, which is from 160 cm to 168 cm (a difference of 8 cm).
Additionally, the whiskers of the basketball team's boxplot are longer than those of the field hockey team's boxplot, indicating that there is greater variability in the heights of the basketball players.
Therefore, the correct answers are (a) the basketball players are taller on average and (b) the heights of the basketball players vary noticeably more than those of the field hockey team.
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The height of the probability density function f(x) of the uniform distribution defined on the interval [a, b] is 1/(a-b). True False
The statement "The height of the probability density function f(x) of the uniform distribution defined on the interval [a, b] is 1/(a-b)" is False.
In a uniform distribution, the probability density function (PDF) is constant within the interval [a, b]. The height of the PDF represents the density of the probability distribution at any given point within the interval. Since the PDF is constant, the height remains the same throughout the interval.
To determine the height of the PDF, we need to consider the interval length. In a uniform distribution defined on the interval [a, b], the height of the PDF is 1/(b - a) for the PDF to integrate to 1 over the entire interval. This means that the total area under the PDF curve is equal to 1, representing the total probability within the interval [a, b].
Therefore, the correct statement is that the height of the probability density function f(x) of the uniform distribution defined on the interval [a, b] is not 1/(a - b), but rather it is a constant value necessary for the PDF to integrate to 1 over the interval, i.e., 1/(b - a).
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PLEASE HELP ME WITH THIS ASAP
Answer:
92.736
Step-by-step explanation:
Answer:
92.736 square feet
Step-by-step explanation:
Area is length times width
4.8 x 19.32 = 92.736 Square feet
Patty made a banner that has an area of 96 square inches. The length and width of the banner are whole numbers. The length is 6 times greater than the width. What are the dimensions of the banner?
Answer:
The length of the banner is 24 inches and its width is 4 inches.
Step-by-step explanation:
Let the length of the banner be L.
Let the width of the banner be W.
The length is 6 times greater than the width. This means that:
L = 6W
The area of the banner is:
A = L * W = 6W * W = \(6W^2\)
The are of the banner is 96 square inches. This implies that:
\(6W^2\) = 96
=> \(W^2\) = 96 / 6 = 16
W = \(\sqrt{16}\)
W = 4 inches
The length, L, will be:
L = 6 * 4 = 24 inches
The length of the banner is 24 inches and its width is 4 inches.
A line is perpendicular to y = -1/5x + 1 and intersects the point negative (-5,1) what is the equation of this perpendicular line?
Answer: y = 5x + 26
Step-by-step explanation:
To find the equation of a line that is perpendicular to the given line y = -1/5x + 1 and passes through the point (-5, 1), we need to determine the slope of the perpendicular line. The given line has a slope of -1/5. Perpendicular lines have slopes that are negative reciprocals of each other. So, the slope of the perpendicular line will be the negative reciprocal of -1/5, which is 5/1 or simply 5. Now, we have the slope (m = 5) and a point (-5, 1) that the perpendicular line passes through.
We can use the point-slope form of a linear equation to find the equation of the line:
y - y1 = m(x - x1)
Substituting the values, we get:
y - 1 = 5(x - (-5))
Simplifying further:
y - 1 = 5(x + 5)
Expanding the brackets:
y - 1 = 5x + 25
Rearranging the equation to the slope-intercept form (y = mx + b):
y = 5x + 26
Therefore, the equation of the perpendicular line that passes through the point (-5, 1) is y = 5x + 26.
The temperature was 23° F at 8 A.M. By 1 P.M. the temperature was 13° F. Which of the following best represents the change in the temperature from 8 A.M. to 1 P.M.?
Answer:
G: -10 F
Step-by-step explanation: The temparature went down by 10 which means it subtracted 10 so it's -10
Total slack is calculated by ____
Total slack is calculated by the late finish minus early finish and the late start minus the early start
What is the total slack?Total slack is simply the amount of time taken for a task to be delayed before the project finish date is delayed. It can be positive or negative.
It is calculated as the calculated as the value of the Late Finish minus the Early Finish field, and the Late Start minus the Early Start field.
Total slack = Late finish - early finish + late start - early start
Thus, the total slack is calculated by the late finish minus early finish and the late start minus the early start.
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which number gives you an irrational when u add it to 8?
A. sqt4
B. 5/9
C. -8
D. sqt5
Answer:
D. sqt5
Step-by-step explanation:
The best process is to start eliminate answers. It can not be C because
-8 + 8 =0. 0 is not an irrational number. Sqt4 is 2, 2+8=10. 10 is a real rational number. 5/9 is not an irrational number because it is a ratio of 5 to the non-zero quotient of 9. Sqt5 is the only irrational number, and when added to 8, it is still irrational.
test scores find the percentile rank for each test score in the data set. 12, 28, 35, 42, 47, 49, 50 what value corresponds to the 60th percentile?
The 5th value of the 60% percentile is 47 when for each test score in the data set is 12, 28, 35, 47, 49, 50.
Given that,
For each test score in the data set, the percentile rank is determined. 12, 28, 35, 42, 47, 49,
We have to find what number represents the 60% of the population.
We know that,
So,
Percentile rank =[(Number of values below x)+0.5]/ total number of values × 100
For 12,
Percentile rank = [0 +0.5]/7×100
= 7th
For 28,
Percentile rank = [1 +0.5]/7×100
= 21st
For 35,
Percentile rank = [2 +0.5]/7×100
= 36th
For 42,
Percentile rank = [3 +0.5]/7×100
= 50th
For 47,
Percentile rank = [4 +0.5]/7×100
= 64th
For 49,
Percentile rank = [5 +0.5]/7×100
= 79th
For 50,
Percentile rank = [6 +0.5]/7×100
= 93rd
Now,
n = 7
60th percentile = 60% of n
So,
60% of n = 60/100×7
= 0.6×7
= 4.2
Therefore, The 5th value of the 60% percentile is 47 when for each test score in the data set is 12, 28, 35, 47, 49, 50.
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A typical person begins to lose consciousness if subjected to accelerations greater than about 5 g(49.0 m/s^2) for more than a few seconds. Suppose a 3.00×10^4−kg manned spaceship's engine has an exhaust speed of 2.50×10^3 m/s. What maximum burn rate ∣ΔM/Δt∣ could the engine reach before the ship's acceleration exceeded 5 g and its human occupants began to lose consciousness?
The maximum burn rate ∣ΔM/Δt∣ that the engine could reach before the ship's acceleration exceeded 5 g and its human occupants began to lose consciousness is approximately 51.0 kg/s.
Acceleration is directly proportional to the force acting on an object. In simple terms, if the force on an object is greater, then it will undergo more acceleration. However, there are limitations to the acceleration that can be tolerated by the human body. At about 5 g (49.0 m/s2) for more than a few seconds, an average person starts to lose consciousness. Let's use this information to answer the given question.
Let the maximum burn rate |ΔM/Δt| that the engine could reach before the ship's acceleration exceeded 5 g be x.
Let the mass of the spaceship be m and the exhaust speed of the engine be v.
Using the formula for the thrust of a rocket,
T = (mv)e
After substituting the given values into the formula for thrust, we get:
T = (3.00 × 104)(2.50 × 103) = 7.50 × 107 N
Therefore, the acceleration produced by the engine, a is given by the formula below:
F = ma
Therefore,
a = F/m= 7.50 × 107/3.00 × 104= 2.50 × 103 m/s²
The maximum burn rate that the engine could reach before the ship's acceleration exceeded 5 g is equal to the acceleration that would be produced by a maximum burn rate. Therefore,
x = a/5g= 2.50 × 103/(5 × 9.8)≈ 51.0 kg/s
Therefore, the maximum burn rate ∣ΔM/Δt∣ that the engine could reach before the ship's acceleration exceeded 5 g and its human occupants began to lose consciousness is approximately 51.0 kg/s.
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Differentiate the function.
H(z)=ln[(d2-z2)/(d2+z2)]^1/2
Natural log of the square root of (d2-z2) divided by (d2+z2).
The derivative of H(z) is H'(z) = -2zd^2/[(d^2-z^2)(d^2+z^2)].
To differentiate the function H(z) = ln[(d^2-z^2)/(d^2+z^2)]^(1/2), we will use the chain rule and the power rule of differentiation.
First, we can simplify the expression inside the natural logarithm using the laws of exponents:
[(d^2-z^2)/(d^2+z^2)]^(1/2) = [(d^2-z^2)^(1/2)/(d^2+z^2)^(1/2)]
Now we can differentiate H(z) as follows:
H'(z) = d/dz [ln[(d^2-z^2)/(d^2+z^2)]^(1/2)]
= (1/2)[(d^2+z^2)^(1/2)/(d^2-z^2)^(1/2)] * d/dz [(d^2-z^2)/(d^2+z^2)]
Using the quotient rule, we can simplify the derivative:
d/dz [(d^2-z^2)/(d^2+z^2)] = [(2z)(d^2+z^2) - (d^2-z^2)(2z)]/(d^2+z^2)^2
= -4zd^2/(d^2+z^2)^2
Substituting this back into H'(z), we get:
H'(z) = (1/2)[(d^2+z^2)^(1/2)/(d^2-z^2)^(1/2)] * (-4zd^2/(d^2+z^2)^2)
= -2zd^2/[(d^2-z^2)(d^2+z^2)]
Therefore, the derivative of H(z) is:
H'(z) = -2zd^2/[(d^2-z^2)(d^2+z^2)]
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Write the expression as a single function of alpha.
cos(180°-alpha)
Answer:
-cos α
is the answer-------
Work out the total area of the shape below:
The total area of the given shape is 71cm².
What is area?The size of a section on a surface is determined by its area. Surface area refers to the area of an open surface or the border of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a shape or planar lamina. A shape's area can be calculated by contrasting it with squares of a known dimension. The square meter (abbreviated as m²), which is the area of a square whose sides are one metre long, is the common measure of area in the International System of Units (SI). Three such squares would be the same size as a shape with a three square metre surface.
The following figure can be divided into a rectangle 7cm x 8cm and a triangle of height and base 6 cm and 5 cm respectively.
Area of rectangle= 7*8= 56 cm²
Area of triangle= 1/2* base*height= 1/2*6*5 = 15 cm²
Total area of shape = 56+15= 71 cm²
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One of the greatest advantages of surveys is that researchers __________. can examine variables that are difficult to observe directly do not have to worry about whether their samples are representative can be confident that respondents answered honestly can be biased but still collect objective information
One of the greatest advantages of surveys is that researchers can examine variables that are difficult to observe directly. However, surveys can be biased but still collect objective information.
Researchers can be confident that respondents answered honestly in surveys because they typically use anonymity to protect respondents' identities. Additionally, surveys allow researchers to reach a large number of people, making them more representative of the population they are studying than other methods of data collection. Surveys can also be biased, as they rely on the respondents' self-reported answers.
Respondents may be influenced by the way the question is phrased or by social desirability bias, which is the tendency to give answers that are socially acceptable or favorable, rather than honest. However, researchers can still collect objective information from surveys by using appropriate sampling techniques and statistical analysis to account for potential biases.
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To find the average rate (speed) of a car traveling on a highway, the distance traveler is divided by the time: R=D/T. If the distance is D=36/x^2-36 miles and the time is T=6x^2+6x/x^2+7x+6 hours, find a simplified expression for the average rate of the car.
a) 1/x
b) 6/x-6
c) 6/x^2-6x
d) 1/x^2-6x
Answer:
It's C
Step-by-step explanation:
Just took the quiz and got it right.
The average rate (speed) of a car traveling on a highway, the distance traveler is divided by the time: R=D/T would be c) 6/x^2-6x.
How to find the average rate of change of something?Let the thing that is changing be y and the thing with which the rate is being compared is x,
then we have the average rate of change of y as x changes as:
\(\text{Average rate} = \dfrac{y_2 - y_1}{x_2 - x_1}\)
where when
\(x = x_1, y = y_1\\and \\x = x_2, y = y_2\)
The distance traveler is divided by the time: R=D/T.
If the distance is \(D=\dfrac{36}{x^2}-36\)miles
the time is \(T=6x^2+\dfrac{6x}{x^2}+7x+6\: hours,\)
The average speed of a car traveling = Distance / Time
= \(\dfrac{\dfrac{36}{x^2}-36}{6x^2+\dfrac{6x}{x^2}+7x+6}\)
= \(\dfrac{{36}-36{x^2}}{6x^4+{6x}+7{x^3}+6{x^2}}\)
= \(\dfrac{6}{x^2}-6x\)
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