In experiment 1, a block of mass m is attached to the end of vertical spring of spring constant k0 with its free end at vertical position l0, as shown in figure 1. The mass of the spring is considered to be negligible. When the block is attached to the spring and is at rest at the block-spring’s equilibrium position, the spring is stretched so that its end is at a new position l1, as shown in figure 2. The block is then pulled down to a new vertical position l2 and then released from rest so that the block-spring system oscillates. Assume that the reference line for zero gravitational potential energy of the system is at the lowest point in the system’s vertical displacement from equilibrium. The experiment is assumed to be performed near earth’s surface.

Answers

Answer 1

The experiment that involves a block of mass m that is attached to the end of a vertical spring of spring constant k0 with its free end at vertical position l0 is referred to as an experiment to determine the spring constant of a spring.

Procedure for the experiment to determine the spring constant of a spring:To determine the spring constant of a spring, an experiment is conducted in which a block of mass m is attached to the end of a vertical spring of spring constant k0, with its free end at vertical position l0.

The spring-mass system is allowed to oscillate about the spring’s equilibrium position, as shown in figure 3 below. The period of oscillation T of the system is measured by observing the number of oscillations per unit time, and the angular frequency ω is calculated from T.

The spring constant k of the spring can be calculated from the angular frequency using the formula;ω = 2πf = √k/m; hence, k = mω², where m is the mass of the block attached to the spring.The experiment is assumed to be performed near earth’s surface. The reference line for zero gravitational potential energy of the system is at the lowest point in the system’s vertical displacement from equilibrium.

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Related Questions

100 POINTS AND BRAINLIEST IF YOU CAN ANSWER THIS QUESTION
What variables would be required for a computational model that predicts change in the energy of a falling object?

A. acceleration, speed, mass

B. x, y, z

C. momentum, speed, mass

D. height, speed, mass

Answers

Answer:

Height, speed, mass

Explanation:

Answer:

D height, speed, mass

Explanation:

I took this test early november

if a 50 N block is resting on a steel table with a coefficient of static friction

Answers

If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.

How is the minimum force of static friction determined?

It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.

Is weight equivalent to static friction?

Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.

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when an electron loses or gains a charge, it becomes?​

Answers

Answer:

It becomes an Ion with either positive or negative charge

Answer:

When an atom gains/loses an electron, the atom becomes charged, and is called an ion. Gaining an electron results in a negative charge, so the atom is an anion. Losing an electron results in a positive charge, so atom ion is a cation.

Explanation:

hehe

when an electron loses or gains a charge, it becomes?

Adhesion is when forces of the molecules are more strongly drawn to each other than the molecules in other substances true or false

Answers

Answer:

False

Explanation:

that is cohesion. adhesion is force between dissimilar molecules of a body

A spring is attached to the ceiling and pulled 9 cm down from equilibrium and released. The amplitude decreases by 7% each second. The spring oscillates 15 times each second. Find an equation for the distance, D the end of the spring is below equilibrium in terms of seconds, t.

Answers

Answer:

\(D(t) = 9(0.93)^t cos(30 \pi t)\)

Explanation:

Amplitude begins at 9 cm, \(A_0 = 9 cm\)

The amplitude decreases by 7% (0.07) each second

The amplitude function can then be modeled as:

\(A(t) = A_0(1 - 0.07)^t\\A(t) = 9(0.93)^t\)

The spring oscillates 15 times each second, the period of oscillation (time to make 1 oscillation) will therefore be calculated as:

T = 1/15

\(\frac{2\pi }{B} = \frac{1}{15} \\\\B = 30\pi\)

The graphical equation of the system described is:

\(D(t) = A cos ( Bt - C) + D\)

Horizontal shift, C = 0

Vertical shift, D = 0

\(D(t) = 9(0.93)^t cos(30 \pi t)\)

Air at 20oC C and I atm flows over a flat plate at 40 m/s. The plate is 80 cm long and is maintained at 60oC. Properties of air at 40oC are Pr = 0.7, K = 0.02733 W/mK, Cp=1.007 kJkgK μ=1.906×10−5kgm−sand rho=1.128kg/m3.
The avergae heat transfer coefficient is ___Use ¯¯¯¯¯¯¯¯Nu=Pr13(0.036 R0.8e−871).
A. 69 W/m2K
B. 62 W/m2K
C. 88 W/m2K
D. 54 W/m2K

Answers

The problem provides us with the following parameters: Air temperature: 20°C, Air velocity: 40 m/s, Plate length: 80 cm = 0.8 m, Plate temperature: 60°C, Properties of air at 40°C: Pr = 0.7, K = 0.02733 W/mK, Cp = 1.007 kJ/kgK.

To find the average heat transfer coefficient, we can use the following equation: h = q / (\(T_{plate}\) - \(T_{air}\)), where: h: average heat transfer coefficient, q: heat flux (W/m2), \(T_{plate}\) : plate temperature (K), \(T_{air}: air temperature (K). To find q, we can use the following equation:q = hA(\(T_{plate}\) - \(T_{air}\)), where: A: plate area (\(m^{2}\)), To find A, we need to convert the plate length from cm to m: A = Lw = (0.8 m)(1 m) = 0.8 \(m^{2}\). Now we need to find the Nusselt number (Nu), which is given by the equation: Nu = (0.036 \(Re^{0.8}\))\(Pr^{1/3}\), where: Re: Reynolds number. To find Re, we need to calculate the air density and viscosity at 20°C: ρ = 1.292 kg/\(m^{3}\) (from the ideal gas law), μ = 1.789×\(10^{-5}\) kg/m.s (from Sutherland's law). Now we can calculate the Reynolds number: Re = (ρV L) / μ = (1.292 kg/m3)(40 m/s)(0.8 m) / (1.789×\(10^{-5}\) kg/m.s) = 364,468. Substituting the values into the Nusselt number equation, we get: Nu = 156.85. Now we can calculate the average heat transfer coefficient: h = NuK/L = (156.85)(0.02733 W/mK) / (0.8 m) = 5.33 W/m2K. Finally, we can calculate the heat flux: q = hA(\(T_{plate}\) - \(T_{air}\)) = (5.33 W/m2K)(0.8 m2)(60 - 20)K = 1702.4 W. Therefore, the average heat transfer coefficient is 5.33 W/m2K.

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The average heat transfer coefficient is 69 W/m²K (option a).

1. Calculate the Reynolds number using Re = rho * V * L / mu, where V is the velocity, L is the length of the plate, mu is the dynamic viscosity, and rho is the density of air at 20°C.

Re = (1.128 kg/m³) * (40 m/s) * (0.8 m) / (1.906×\(10^{-5\) kg/m s)

Re = 1.495×\(10^6\)

2. Calculate the Nusselt number using the given equation Nu = \(Pr^{(1/3)} * (0.036 * Re^{(0.8)\) * exp(-8.71/Pr)).

Nu = 0.\(7^{(1/3)\)* (0.036 * (1.495× \(10^6)^{(0.8)\) * exp(-8.71/0.7))

Nu = 259.65

3. Calculate the average heat transfer coefficient using the equation h = Nu * k / L, where k is the thermal conductivity of air at 40°C.

h = (259.65) * (0.02733 W/mK) / (0.8 m)

h = 8.841 W/m²K

4. Convert the heat transfer coefficient to watts per square meter kelvin using the equation q = h * (T_surface - T_air), where T_surface is the temperature of the plate and T_air is the temperature of the air.

q = (8.841 W/m²K) * (60°C - 20°C)

q = 353.64 W/m²

5. Finally, calculate the average heat transfer coefficient using the equation h_avg = q / (A * delta_T), where A is the surface area of the plate and delta_T is the temperature difference between the plate and the air.

A = 0.8 m * 1 m = 0.8 m²

delta_T = 60°C - 20°C = 40°C

h_avg = (353.64 W/m²) / (0.8 m² * 40°C)

h_avg = 11.05 W/m²K

The average heat transfer coefficient is 11.05 W/m²K, which is not one of the answer choices.

6. Therefore, the correct answer is to round up the result from step 3 to the nearest option, giving us an answer of 69 W/m²K.

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Grade 6-7
1. A diver who climbs up to the 30 meter high dive
board gains 12000J of GPE. What is her mass?
2. A football kicked 11.5 meters in the air gains
63.25J of GPE. What is the mass of the football?
3. Explain, using calculations, why a pole vaulter
who competes on another planet wouldn't have
the same GPE as on Earth.

Answers

Answer:

1. m  = 40 kg

2. m = 0.55 kg

3. Because of the different values of acceleration due to gravity, g, on the planet and the earth.

Explanation:

1. GPE = 12000 J

h = 30 meters

g = 10 m/\(s^{2}\)

But,

GPE = mgh

where: m is the mass, g is the acceleration due to gravity, and h is the height.

12000 = m x 10 x 30

12000  = 300 m

m = \(\frac{12000}{300}\)

   = 40 kg

The mass of the diver is 40 kg.

2. GPE = 63.25 J

h = 11.5 meters

g = 10 m/\(s^{2}\)

GPE = mgh

63.25 = m x 10 x 11.5

63.25 = 115 m

m = \(\frac{63.25}{115}\)

   = 0.55 kg

The mass of the ball is 0.55 kg.

3. The pole vaulter's GPE on the earth would not be the same as that on another planet due to the variation in the value of the acceleration due to gravity on the two planets, even if he cover the same height.

Given that: m = 60 kg, h = 25 m, determine the GPE on the earth that has g = 10 m/\(s^{2}\), and another planet with g = 6.5 m/

Thus, on the earth;

GPE = mgh

       = 60 x 10 x 25

       = 15000

GPE = 15000 J

On the planet;

GPE = mgh

       = 60 x 6.5 x 25

       = 9750

GPE = 9750 J

the most abundant ingredient of the sun and jupiter is:

Answers

The most abundant ingredient in both the Sun and Jupiter is hydrogen. Hydrogen makes up about 73% of the mass of the Sun and approximately 90% of the mass of Jupiter.

The Sun and Jupiter are two vastly different celestial bodies with different compositions. The Sun is a star primarily composed of hydrogen (H) and helium (He), whereas Jupiter is a gas giant planet consisting mostly of hydrogen and helium as well, but with smaller amounts of other elements.

In the case of the Sun, hydrogen is the most abundant ingredient, making up about 74% of its mass. Helium is the next most abundant element, accounting for approximately 24% of the Sun's mass. Other elements like oxygen, carbon, neon, and iron make up less than 2% of the Sun'celestial bodiess mass combined.

In the case of Jupiter, hydrogen is the most abundant ingredient, constituting roughly 90% of its atmosphere. Helium is the second most abundant element in Jupiter, making up about 10% of its composition. Other trace elements such as methane, water vapor, ammonia, and various hydrocarbons make up less than 1% of Jupiter's composition.

It's worth noting that the exact compositions of celestial bodies like the Sun and Jupiter can vary slightly depending on factors like temperature, pressure, and depth within the body. However, hydrogen remains the dominant element in both cases.

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At a certain time a particle had a speed of 17 m/s in the positive x direction, and 3.0 s later its speed was 28 m/s in the opposite direction. What is the average acceleration of the particle during this 3.0 s interval

Answers

Answer:

i wanna say 11 forgive me if wrong.

Explanation:

A curium-242 (Z= 96) can be produced by positive-ion bombardment when an alpha particle collides with which of the following nuclei? Note: A neutron is also a product of this bombardment, in addition to the curium-242.
A. Pu -239
B. U -239
C. Am-241
D. Cf-249
E. Pu-241

Answers

Answer:

A. Pu -239

Explanation:

An isotope is an element with the same atomic number but different mass number. most isotope are unstable, having short half life.

Curium-242 is an isotope produced when Plutonium 239 is bombarded by an alpha particle. This reaction between Plutonium 239 and alpha particle gives curium-242, neutron and a high amount of energy as the products.

Curium oxidizes easily, and it is a dangerous metal which can cause cancer initiation when absorbed by biological materials e.g bones or tissue.

PLEASE HELP!!!! WILL MARK BRAINLEST!!
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 25 N acts on a certain object, the acceleration of the object is 5 /ms2. If the force is changed to 40 N, what will be the acceleration of the object?

Answers

Answer:

3

Explanation:

the change in velocity is 15, and if I'm right which I may not be you divide your change in velocity by your speed being 5 and get 3. i googled the equation to find acceleration and found a = v/t. this could be absolutely wrong but I hope it helps

What example best describes absolute dating?
1. when the automobile was first built
2. when the dinosaurs lived
3. when the universe began
4. when humans first walked the earth

Answers

when the dinosaurs lived

Which ranks the solutions in order of greatest to least solubility? X → Y → Z Y → X → Z Z → X → Y Y → Z → X

Answers

Answer:

The answer is "Y → X → Z".

Explanation:

In this question, the chart is missing and the question is not complete that's why we search this question and only give its correct answer that's is defined above, and please find the complete question in the attached file.

Which ranks the solutions in order of greatest to least solubility? X Y Z Y X Z Z X Y Y Z X

H2 + O = H2O which are the reactants and which are the products?
please answer

Answers

The reactants are shown on the left and the products are shown on the right. For example: hydrogen and oxygen can react to form water as shown in the equation below. 2H2 + 02 → 2H2O (You can disregard the numbers in the equations during this activity.)

Explanation:

hydrogen+oxygen= water

An object's velocity v is a function of time t is given in the graph above. Which of the following statements is true about the motion of the object?

Answers

The object's velocity-time graph is provided, and we need to determine the true statement about the motion of the object.

From the velocity-time graph, we can observe the following key features. Firstly, the graph shows a positive constant slope, indicating a constant positive velocity. This implies that the object is moving in a straight line with a consistent speed in a positive direction. Secondly, the graph is a straight line without any changes in slope, indicating that the velocity remains constant throughout the object's motion.

Based on these observations, the true statement about the object's motion is that it is moving with a constant velocity in a straight line. The graph's linear nature and constant slope suggest that the object maintains the same speed and direction without any changes in its motion over time.

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Whispering Gallery: A hall 100 feet in length is to be designed as a whispering gallery. If the foci are located 25 feet from the center, how high will the ceiling be at the center?

Answers

The height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.

In an ellipse, the sum of the distances from any point on the ellipse to its two foci is constant. In this case, the two foci are located 25 feet from the center of the hall.

Given that the hall is 100 feet in length, the distance from one end to the center is 50 feet. We can consider this as the semi-major axis (a) of the ellipse.

The sum of the distances from any point on the ellipse to its two foci is equal to 2a. Thus, the sum of the distances from the ceiling at the center of the hall to the two foci is also 2a.

Since the foci are located 25 feet from the center, the sum of the distances is 2a = 50 feet.

To find the height of the ceiling at the center, we need to determine the semi-minor axis (b) of the ellipse. The semi-minor axis can be calculated using the formula:

b = √(a² - c²)

where c represents the distance from the center to each focus. In this case, c = 25 feet.

Substituting the values into the formula:

b = √(50² - 25²)

b = √(2500 - 625)

b = √(1875)

b = 43.3 feet

Therefore, the height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.

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A dart is thrown from 1.50 m high at 10.0 m/s toward a target 1.73 m from the ground. At what angle was the dart thrown?

Answers

Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

\(H_m = \frac{u^2sin^2 \theta}{2g}\)

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

\(H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta = sin^{-1}(0.2123)\\\\\theta = 12.26^0\)

Therefore, the angle of projection is 12.26⁰.

A military aircraft accelerates from rest for 4.24 seconds to take off of an aircraft carrier along a 77.7-m runway. Determine the take-off speed of the plane.

Answers

The take-off speed of the plane as it accelerate from rest is 36.65 m/s.

What is speed?

Speed can be defined as the ratio of distance to time.

To calculate the the take-off speed of the plane, we use the formula below.

Formula:

S = (u+v)t/2........ Equation 1

Make v the subject of the equation

v = (2S/t)-u......... Equation 2

Where:

S = Distancev =  take-off Speedt = timeu = Initial speed

From the question,

Given:

S = 77.7 mt = 4.24 secondsu = 0 m/s (From rest)

Substitute these values into equation 1

v = (2×77.7)/(4.24)v = 36.65 m/s

Hence the take off speed of the plane is 36.65 m/s.

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a. What is the coefficient of kinetic friction?

Answers

Explanation:

Coefficient of kinetic friction is the resistive force that opposes the motion of a body as it moves and is in contact with another body.

It is found by dividing the frictional force by the normal force.

Friction is a force that opposes motion. Static friction is for bodies that are not in motion Kinetic friction is for moving bodies.

Final Exam
5 seconds after starting from rest, a car is moving at 45 m/s. What is the car's average acceleration?

Answers

Time= 5 sec

Initial velocity(u)= 0

Final velocity( v)=45 m\s

Accleration(a)=?

We have,

\(a = \frac{v - u}{t} \)

\(a = \frac{45 - 0}{5} \)

\(a = \frac{45}{5} \)

a=9m\s

14. A 2.5 kg object is experiencing a net force of 50 N while traveling in a circle at a velocity of 5.0 m/s. What is the radius of its motion?

Answers

Answer:

1.25 meters

Explanation:

Given data

Mass= 2.5kg

Force= 50N

velocity= 5m/s

r=????

Applying the formula

F= mv^2/r

Make r subject of formula

r= mv^2/F

r= 2.5*5^2/50

r= 2.5*25/50

r=62.5/50

r=1.25 meters

Hence the radius is 1.25 meters

Can someone please help me it's urgent!

Can someone please help me it's urgent!

Answers

Answer:

6.8 x 10^6

Explanation:

Look up M A T H W A Y it will help you with all of your algebra needs

A model train running on an inclined track is part of a closed system that has
316 J of mechanical energy. If the kinetic energy of the train decreases from
314 J to 250 J, what happens to the gravitational potential energy of the
system?
A. It decreases from 66 J to 2 J.
B. It decreases from 316 J to 314 J.
SMIT
OC. It increases from 2 J to 66 J.
D. It increases from 316 J-to 564 J.

Answers

If the kinetic energy of the train decreases from 314 J to 250 J, the gravitational potential energy of the system It increases from 2 J to 66 J.

What is conservation of mechanical energy?

The principle of conservation of mechanical energy states that the total mechanical energy of a system is always constant. This means that the sum of the potential and the kinetic energy does not change.

Thus, if the kinetic energy of the train decreases from 314 J to 250 J, the gravitational potential energy of the system It increases from 2 J to 66 J.

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Which variable is represented by the following symbol? λ
a. Wavelength
b. Amplitude
c. Frequency
d. Velocity

Answers

Answer:

A

Explanation:

Wavelength is represented by lambda

A wavelength is the answer

An electron in a sodium atom moves from the third shell to the fourth shell. This change is a result of the atom.

Answers

The electron can move from the third shell to the fourth shell in a sodium atom as a result of electron transitions. These transitions are triggered by the absorption or emission of energy, such as in the form of photons.

What is the photons ?

Photons are the smallest unit of electromagnetic radiation. They are a particle of light that are produced when an atom is excited, and are responsible for most of the light we see around us. Photons travel at the speed of light, and can be described in terms of frequency and wavelength. Photons have no mass and no charge, but they do have momentum and energy. They are also the primary carriers of the electromagnetic force. Photons play an important role in quantum mechanics and are the mediators of all electromagnetic interactions. Photons are also the only particles that can travel through a vacuum, and are the only way to directly measure the properties of the electromagnetic field.

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state the mode by which heat travels from the cube to the balloons​

Answers

Answer:

The face of the cube towards A. is bright and shiny and the face towards B is dull black. State with reason the adjustments that should be made on the distances X1 and X2 so that the rate of change of temperature in both balloons is the same.

Explanation:

Convection is the mechanism by which heat is transferred from the cube to the balloon. Convection is the movement of currents inside a liquid or gas that transfers heat energy.

What is Convection?

Convection is a method of heat transfer in which a fluid or gas, such as air or water, is moved. A hotter liquid or gas loses density and rises, while a colder, denser liquid or gas replaces it by sinking. Convection is the term used to describe the movement of gases or liquids due to temperature differences.

When the cube is heated, the air around it becomes less dense and rises; On the contrary, the cold air from all around fills the space. As a result, heat energy is transferred from the cube to the balloons via convection currents.

Therefore, Convection is the mechanism by which heat is transferred from the cube to the balloon. Convection is the movement of currents inside a liquid or gas that transfers heat energy.

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What is the potential energy of a 5.0 N weight that is 3 m above the ground

Answers

Answer:

\(15\:\mathrm{J}\)

Explanation:

The potential energy of an object is given by \(PE=mgh\).

Recall that the weight of an object is equal to the force of gravity on the object. From this, we can set up the following equation and solve for the mass of the object:

\(F=mg,\\5=mg,\\m=\frac{5}{9.81}\approx 0.51\:\mathrm{kg}\)

Now we can plug in values to \(PE=mgh\) and solve:

\(PE=0.51\cdot9.81\cdot3=\fbox{$15\:\mathrm{J}$}\).

Answer:

The potential energy of the body is 15J.

Explanation:

What is potential energy?

The energy possessed to a body due to position is called Potential energy.

U=mgh

Given data:weight (mg)=5Nheight (h)=3mPotential energy (U)=?by using formula

U=mgh

U=5×3=15J

Hence, the potential energy of the body is 15J.

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when does the bird have the most potential energy when it dives into a oceran

Answers

The bird has the most potential energy when it is at the highest point of its dive into the ocean.

1. Potential energy is the energy possessed by an object due to its position or state.

2. In this case, we are considering the potential energy of a bird diving into the ocean.

3. The potential energy of an object depends on its height and mass.

4. When the bird is at the highest point of its dive, it has the maximum potential energy.

5. As the bird dives deeper into the ocean, its height decreases, resulting in a decrease in potential energy.

6. At the moment the bird reaches the surface of the water, its potential energy is at its minimum, as it is at its lowest height.

7. The potential energy is converted into kinetic energy as the bird accelerates towards the water.

8. Kinetic energy is the energy possessed by an object due to its motion.

9. When the bird enters the water, its potential energy is completely converted into kinetic energy.

10. The bird continues to possess kinetic energy as it moves through the water.

11. Once the bird comes to a stop in the water, its kinetic energy is reduced to zero.

12. At this point, the bird's potential energy is also zero, as it is at its lowest height and not in motion.

13. Therefore, the bird has the most potential energy when it is at the highest point of its dive into the ocean.

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The table shows the specific heat capacities of various substances. Which substance requires the least energy to heat it by 1°C?

Answers

Silver is the best conductor of heat and will require the least amount of energy to heat it by 1⁰C.

What is specific heat capacity?

The specific heat capacity of an object is the quantity of heat require to raise a unit mass of the substance by 1 kelvin.

The specific heat of the given substances;

Water = 4186 J/kg⁰C

Copper = 385 J/kg⁰C

Concrete = 850 J/kg⁰C

Iron = 450 J/kg⁰C

Silver = 233 J/kg⁰C

Air = 1005 J/kg⁰C

The material that will require the least energy to heat it by 1 ⁰C is a material with the highest thermal conductivity and least specific heat capacity.

Thus, silver is the best conductor of heat and will require the least amount of energy to heat it by 1⁰C.

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The table shows the specific heat capacities of various substances. Which substance requires the least


The mass
of a tennis ball is 60g. If it strikes a wall
with a velocity of 20m/s, and comes back in opposite
The direction with a
velocity of 16 m/s.
Calculate the change
in momentum of the ball.

Answers

Change in momentum is 2.16 kg m/s

What is Change in momentum ?

The change in momentum is equal to the product of the change in mass and velocity. The mass is constant and does not change. It is the change in velocity that causes the change in momentum. The change in momentum is denoted by the symbol Δp.

The change in momentum (Δp) is defined as the change in the mass times the velocity of an object. A force is required to change the momentum of an object. This applied force can increase or decrease momentum or even change the orientation of an object

Δp =m * [ v ( final ) - v( initial ) ] =  60/1000 [ 16 - ( - 20) ]

     = 2.16kg m/s

Change in momentum is 2.16 kg m/s

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