In ΔNOP, p = 490 inches, ∠N=57° and ∠O=55°. Find the length of n, to the nearest inch.

Question 1: The item not included in the cost of merchandise inventory is "Purchase discounts."

2: The total cost of the merchandise is $3,332.00.

5: The company's gross margin and operating expenses, are $211,000 and $191,720.

Merchandise inventory expenses normally consist of the price paid for the inventory, deductions from the purchase price resulting from purchase returns and allowances, and freight expenses paid by the purchaser.

Although purchase discounts reduce the cost of merchandise inventory, they are not considered part of it. Instead, they are treated as a distinct discount in the accounting records.

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The length of IKE is 2x - 12.

A condition on a variable that is true for just one value of the variable is called an equation.

Since KITE is a kite, we know that KT = IT and KE = IE. Let's call the length of these diagonals d. Then we have:

KT + TI = d

KE + EI = d

Substituting in the given values, we get:

x + 6 + 2x = d

2x + IE = d

Solving for d in the first equation, we get:

3x + 6 = d

Substituting this into the second equation, we get:

2x + IE = 3x + 6

Solving for IE, we get:

IE = x + 6

Therefore, IKE is equal to:

IKE = IT - IE

IKE = (d - KT) - (x + 6)

IKE = (3x + 6 - x - 6) - (x + 6)

IKE = 2x - 12

So, the length of IKE is 2x - 12.

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Answer:

Quadrant IV

Step-by-step explanation:

An angle whose measure is _302° is in standard position the terminal side of the angle fall in Quadrant IV

Step-by-step explanation:

The line A, the slope is +2

And line B the slope is n-1

Answer:

For A;

x1 = -2, y1 = -3, x2 = 3, y2 = 7

Gradient = (y2 - y1)/(x2 - x1)

= (7 - (-3))/(3 - (-2))

= 10/5 = 2.

For B;

x1 = 7, y1 = -2, x2 = -2, y2 = 7

Gradient = (y2 - y1)/(x2 - x1)

= (7 - (-2))/(-2 - 7)

= 9/-9 = -1.

D since the line is going to the right.

d

good luck  

n     kjhikjnbjkjnhb hjijnbhjijijn

Answer: -4.7 degrees Celsius

Step-by-step explanation:

-12.6 + 7.9 = -4.7

Answer:

a = 127° , b = 12° , c = 115°

Step-by-step explanation:

a and 53° are same- side interior angles and sum to 180° , that is

a + 53° = 180° ( subtract 53° from both sides )

a = 127°

c and 115° are alternate angles and are congruent , then

c = 115°

53° , b and c lie on a straight line and sum to 180°

53° + b + c = 180°

53° + b + 115° = 180°

b + 168° = 180° ( subtract 168° from both sides )

b = 12°

then a = 127° , b = 12° , c = 115°

Answer:

a = 127; b = 12; c = 115

Step-by-step explanation:

c =115

b = 180 - 115 - 53

b = 12

a = b + c

a = 12 + 115

a = 127

The probability that from the 11 books Nico owns, he first chooses an advanced book before then choosing a beginner book, both book chosen with replacement is \(\dfrac{6}{121}\)

When the probability of choosing from a collection of items with replacement is being found, the number of options to choose from remain the same during each event.

The given information are;

The number of books Nico owns = 11

The number of beginner books = 2

The number of intermediate books = 6

The number of advanced books = 3

The required probability; That the first book chosen is an advanced book, and the second book chosen is a beginner book, both books chosen with replacement.

Given that the books are chosen with replacement, the probability remains the same after each book is chosen, which gives;

The probability that an advanced book is chosen is;  \(P(A) = \dfrac{3}{11}\)

The probability that a beginner book is chosen = \(\dfrac{2}{11}\)

The probability that an advanced book and then a beginner book are chosen is given by \(P(A \cap B) = P(A) \times P(B)\)

Which gives: \(P(A \cap B) = \dfrac{3}{11} \times \dfrac{2}{11} = \dfrac{6}{121}\)

The probability that he first chooses an advanced book then chooses a beginner book is \(\dfrac{6}{121}\)

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Answer:

B

Step-by-step explanation:

Edge 2023 :')

Answer:

0, 20

30, -20

-10, -40

Step-by-step explanation:

Multiply the coordinate values by the scale factor

Answer: 24 units

Step-by-step explanation:

If you are multiplying a shape by a scale factor, the dimensions are also multiplied by the scale factor.

QR= x

Q'R'= (1/2)(X)

12=(1/2)(X)

(2)12= 1/2x(2)

24=X

If you're multiplying QR by 1/2 you would get 12. 12 is a half of QR. Therefore, QR is 24.

The no-arbitrage price today of a 5-year $1,000 US Treasury note with a 2% coupon rate and a 4.25% yield to maturity is approximately $908.44, closest to option B: $900.53.

To determine the no-arbitrage price of a 5-year $1,000 US Treasury note with a coupon rate of 2% and a yield to maturity (YTM) of 4.25%, we can use the present value of the future cash flows.First, let's calculate the annual coupon payment. The coupon rate is 2% of the face value, so the coupon payment is ($1,000 * 2%) = $20 per year.The yield to maturity of 4.25% is the discount rate we'll use to calculate the present value of the cash flows. Since the coupon payments occur annually, we need to discount them at this rate for five years.

Using the present value formula for an annuity, we can calculate the present value of the coupon payments:PV = C * (1 - (1 + r)^-n) / r,

where PV is the present value, C is the coupon payment, r is the discount rate, and n is the number of periods.

Plugging in the values:PV = $20 * (1 - (1 + 0.0425)^-5) / 0.0425 = $85.6427.

Next, we need to calculate the present value of the face value ($1,000) at the end of 5 years:PV = $1,000 / (1 + 0.0425)^5 = $822.7967.

Finally, we sum up the present values of the coupon payments and the face value:No-arbitrage price = $85.6427 + $822.7967 = $908.4394.

Rounding to the penny, the no-arbitrage price is $908.44, which is closest to option B: $900.53.

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Answer:

let me think abt it give me a few

Step-by-step explanation:

This shows that the food will only last 1 1/3 meals

Fractions are written as a ratio of two integers. Given the following

Total pounds of food bought = 24 pounds

Amount fed each per meal = 3/4 * 24 pounds = 18 pounds

Remains = 24 - 18

Remaining = 6 pounds

This shows that the food will only last 1 1/3 meals

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1. The sequence is an arithmetic sequence with a common difference of d = -200.

2. The sequence is not an arithmetic sequence.

An arithmetic sequence is a sequence of values in which the difference between consecutive terms is constant and is called common difference d.

For item 1, each term is the previous term subtracted by 200, hence the sequence is in fact an arithmetic sequence with a common difference of -200.

For item 2, the difference between consecutive terms is difference, hence the sequence is not an arithmetic sequence.

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He needs one more quart. That is half of a gallon.

Answer:

i believe the answer is b

The probability that the sample proportion will differ from the population proportion by greater than 4% is 0.990.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

µ = p

The standard deviation of this sampling distribution of sample proportion is:

σ = √p(1-p)/n

The information provided is:

p = 0.14

n = 41

As the sample size is large, i.e n = 411 > 30. the central limit theorem can be used to approximate the sampling distribution of sampling proportion.

Compute the values of P(p^ - p >0.04) as follows:

P(p^ - p < 0.04) = P(p^-p/σ > 0.04/√0.14(1-0.14)/411

= P(Z>2.33)

= 0.990

Thus the probability that the sample proportion will differ from the population proportion by greater than 4% is 0.990

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Answer:

x1=1, x2=-3

y1=-3, y2=3

m=y2-y1/x1-x2

m=3-(-3)/-3-1

m=-3/2

since Y=mx+c

Then,Y=-3/2x+c

Hope! It will help you!!!

The expression for the area under the graph of f(x) over the interval [2, 4] is given by the limit as n approaches infinity of the Riemann sum: A = lim(n→∞) Σ[f(xi)Δx].

To express the area under the graph of f(x) as a limit, we divide the interval [2, 4] into n subintervals of equal width Δx = (4 - 2)/n = 2/n.

Let xi be the right endpoint of each subinterval, with i ranging from 1 to n. The area of each rectangle is given by f(xi)Δx.

By summing the areas of all the rectangles, we obtain the Riemann sum: A = Σ[f(xi)Δx], where the summation is taken from i = 1 to n.

To find the expression for the area under the graph of f(x) as a limit, we let n approach infinity, making the width of the rectangles infinitely small.

This leads to the definite integral: A = ∫[2, 4] f(x) dx.

In this case, the expression for the area under the graph of f(x) over the interval [2, 4] is given by the limit as n approaches infinity of the Riemann sum: A = lim(n→∞) Σ[f(xi)Δx].

Evaluating this limit would yield the actual value of the area under the curve.

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Answer:

he chose the option A 8 once for $ 1.44

The proportion of those surveyed who chose basketball as their favorite sport is 34.149 (option a)

Let's denote the proportion of adults who chose basketball as their favorite sport as P(Basketball). To calculate P(Basketball), we need to divide the total number of adults who chose basketball by the total number of surveyed adults. Mathematically, it can be represented as:

P(Basketball) = (Number of adults who chose basketball) / (Total number of surveyed adults)

To calculate the number of adults who chose basketball, we sum up the values from the age range categories:

Number of adults who chose basketball = Number of adults (18-30) who chose basketball + Number of adults (31-50) who chose basketball + Number of adults (51 and above) who chose basketball

Looking at the table, we find that the number of adults (18-30) who chose basketball is 15, the number of adults (31-50) who chose basketball is 8, and the number of adults (51 and above) who chose basketball is 11. Adding these values together, we get:

Number of adults who chose basketball = 15 + 8 + 11 = 34

Now, let's calculate the total number of surveyed adults. We can sum up the values from the age range categories:

Total number of surveyed adults = Total number of adults (18-30) + Total number of adults (31-50) + Total number of adults (51 and above)

From the table, we find that the total number of adults (18-30) is 49, the total number of adults (31-50) is 48, and the total number of adults (51 and above) is 52. Adding these values together, we get:

Total number of surveyed adults = 49 + 48 + 52 = 149

Now, we have the values we need to calculate the proportion:

P(Basketball) = (Number of adults who chose basketball) / (Total number of surveyed adults)

= 34 / 149

Hence the correct option is (a).

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Answer:

dk

Step-by-step explanation:

x,y,z=(smaller z-value)=(-56/3, -32/3, 16/3)

x,y,z=(larger z-value)=(56/3, 32/3, -16/3)

These are the points on the cone that are closest to the point (14, 8, 0).

In a two-dimensional space, a point is defined by two coordinates, typically denoted by (x, y), where x represents the horizontal position, and y represents the vertical position. In a three-dimensional space, a point is defined by three coordinates, typically denoted by (x, y, z), where x, y, and z represent the horizontal, vertical, and depth positions, respectively.

We want to minimize the distance between the point (14, 8, 0) and the surface of the cone defined by the equation z² = x² + y², subject to the constraint that we stay on the surface of the cone.

Let f(x,y,z) = (x-14)² + (y-8)² + z² be the function we want to minimize subject to the constraint g(x,y,z) = z² - x² - y² = 0.

The Lagrange multiplier method involves finding the critical points of the function L(x,y,z,λ) = f(x,y,z) - λg(x,y,z), where λ is the Lagrange multiplier.

So we have:

L(x,y,z,λ) = (x-14)² + (y-8)² + z² - λ(z² - x² - y²)

Taking the partial derivatives with respect to x, y, z, and λ, and setting them equal to zero, we get the following system of equations:

2(x-14) + 2λx = 0

2(y-8) + 2λy = 0

2z - 2λz = 0

z² - x² - y² = 0

The third equation simplifies to z(1-λ) = 0, which gives us two possibilities:

Case 1: z = 0

In this case, the fourth equation becomes -x² - y² = 0, which implies that x = y = 0. But this point does not lie on the surface of the cone, so it is not a valid critical point.

Case 2: λ = 1

In this case, the first two equations become x-14 = -xλ and y-8 = -yλ, which imply that x = -7λ and y = -4λ. Substituting into the fourth equation gives:

z² = x² + y² = 65λ²

To minimize the distance between the point (14, 8, 0) and the surface of the cone, we want to find the value of λ that minimizes the function f(x,y,z) subject to the constraint g(x,y,z) = 0. Substituting x = -7λ, y = -4λ, and z = √(65λ²) into f(x,y,z), we get:

f(λ) = (7λ-14)² + (4λ-8)² + 65λ²

To minimize this function, we take its derivative with respect to λ and set it equal to zero:

f'(λ) = 30λ - 80 = 0

Solving for λ, we get λ = 8/3. Substituting this back into x = -7λ, y = -4λ, and z = √(65λ²), we get:

x,y,z=(smaller z-value)=(-56/3, -32/3, 16/3)

x,y,z=(larger z-value)=(56/3, 32/3, -16/3)

These are the points on the cone that are closest to the point (14, 8, 0).

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If the first and last terms of an arithmetic series are 5 and 27, respectively, and the sum of the series is 192, then the number of terms in the series can be calculated as 12.

To find the number of terms in the arithmetic series, we can use the formula for the sum of an arithmetic series:

Sum = (n/2)(first term + last term)

We are given the first term (5), the last term (27), and the sum (192). Plugging these values into the formula, we have:

192 = (n/2)(5 + 27)

Simplifying the equation:

192 = (n/2)(32)

192 = 16n

Dividing both sides of the equation by 16:

n = 192/16

n = 12

Therefore, the number of terms in the arithmetic series is 12.

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