In def x is a point on ef and y is a point on df so that xy ||de if xf =10 yf=5 and ef = 13 what is dy

Answer:

6.5 gallons

Step-by-step explanation:

if u see we have to divided 13 by 2 to see how much each bowl will have

13/2= 6.5 gallons

The equation of a line is 2x + 5y = 8.

The given equation is :

y = 5/2x + 4

Here we have to find the equation of a line perpendicular to the given line passing through the point (-1,2).

The slope of a line is 5/2.i.e., \(m_{1}\) = 5/2

To find the slope of a line perpendicular to the line we have a formula:

\(m_{1}\)×\(m_{2}\) = -1

\(m_{2}\) = -1 /\(m_{1}\)

\(m_{2}\)= -1 × 2/5

     =-2/5

The equation of a line is:

y = mx + c

The slope is -2/5 and the point is (-1,2)

c = y-intercept

So by putting the value we have:

2 = -2/5 × (-1) + c

c = 8/5

y   = -2/5x + 8/55

y = -2x + 82x + 5y = 8

Therefore the equation of a line is 2x + 5y = 8.

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I understand that algebraic operations can be confusing at first, but I'll do my best to explain them step by step. Let's start with addition and subtraction in algebra, and then move on to multiplication and division.

Addition in Algebra:

Start with two or more algebraic expressions or terms that you need to add together.

Identify like terms, which are terms that have the same variables raised to the same powers. For example, 3x and 5x are like terms because they both have the variable x raised to the power of 1.

Combine the coefficients (the numbers in front of the variables) of the like terms. For example, if you have 3x + 5x, you add the coefficients 3 and 5 to get 8.

Write the sum of the coefficients next to the common variable. In this case, it would be 8x.

If there are any remaining terms without a like term, simply write them as they are. For example, if you have 8x + 2y, you cannot combine them because x and y are different variables.

Subtraction in Algebra:

Subtraction is similar to addition, but instead of adding terms, we subtract them.

Start with two algebraic expressions or terms.

Identify like terms, as we did in addition.

Instead of adding the coefficients, subtract the coefficients of the like terms.

Write the difference of the coefficients next to the common variable.

Handle any remaining terms without a like term in the same way as in addition.

Multiplication in Algebra:

Multiply the coefficients of the terms together. For example, if you have 2x * 3y, multiply 2 by 3 to get 6.

Multiply the variables together. In this case, multiply x by y to get xy.

Write the product of the coefficients and variables together. So, 2x * 3y becomes 6xy.

Division in Algebra:

Divide the coefficients of the terms. For example, if you have 12x / 4, divide 12 by 4 to get 3.

Divide the variables. If you have x / y, you cannot simplify it further because x and y are different variables. So, you leave it as x / y.

Remember, these steps are general guidelines, and there might be additional rules and concepts specific to certain algebraic expressions.

It's important to practice and familiarize yourself with these operations to gain confidence and improve your understanding.

Answer:

d

Step-by-step explanation:

Answer:

x=5

y=3

then ,

x+2y= 5+2 *3

= 5+6

= 10

Answer:

Step-by-step explanation:

So bascially decay means shrinks or shrivels. Growth means like growing, bigger, sort of like a happy plant :D.

To find if this is getting bigger or is shrinking, lets plug in something simple like 1 for the time(t). Sooo:

20,000*.88^1

Since its a 1 exponent it does nothing so:

20,000*.88

Now this is 17600 you can use calculator but if you do this in head like me all I did is multiply 88 by 2 which was simply since 8 times 2 is 16 so 160+16 is 176 then I added zeros:

y=17600

As we can see this is smaller than 20,000, so it is a decaying problem.

By what percent tho.

Well this is pretty easy to reconize once you understand where to find it.

When they talk about percentage, they mean how much it decreased by.

This is 100%-the multiplyied value.

In this case the multiplyed value is 0.88, sooo:

100%-88%=18%

So the percent amount that the value decreased by is 18%.

Hope this helps!

The solution to the given boundary value problem is y(t) = 3e^2t + 6e^5t.

To solve the boundary value problem, we can first find the characteristic equation associated with the given second-order linear homogeneous differential equation:

r² - 7r + 10 = 0.

Factoring the quadratic equation, we have:

(r - 2)(r - 5) = 0.

This equation has two distinct roots, r = 2 and r = 5. Therefore, the general solution to the differential equation is:

y(t) = c₁e^(2t) + c₂e^(5t),

where c₁ and c₂ are constants.

Using the initial conditions, we can determine the specific values of the constants. Plugging in the first initial condition, y(0) = 10, we have:

10 = c₁e^(2*0) + c₂e^(5*0),

10 = c₁ + c₂.

Next, we use the second initial condition, y(t) = 9, to find the value of c₁ and c₂. Plugging in y(t) = 9 and solving for t = 0, we have:

9 = c₁e^(2t) + c₂e^(5t),

9 = c₁e^0 + c₂e^0,

9 = c₁ + c₂.

We now have a system of equations:

c₁ + c₂ = 10,

c₁ + c₂ = 9.

Solving this system, we find c₁ = 3 and c₂ = 6.

Therefore, the solution to the boundary value problem is y(t) = 3e^(2t) + 6e^(5t).

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The test to use when there's an independent group design and ordinal data is the Kruskal Wallis test

Given: Independent group and ordinal data. To find which test to use.

What's the Kruskal Wallis test?

The Kruskal Wallis test is used when you have one independent variable with two or further situations and an ordinal dependent variable. In other words, it's thenon-parametric interpretation of ANOVA and a generalized form of the Mann- Whitney test system since it permits two or further groups.

The Kruskal Wallis test is used when you have one independent variable with two or further situations and an ordinal dependent variable. In other words, it's thenon-parametric interpretation of ANOVA and a generalized form of the Mann- Whitney test system since it permits two or further groups.

The null thesis for the Kruskal- Wallis test simply states that there are no methodical or harmonious differences among the treatments being compared.

How to calculate the Kruskal Wallis test?

The computation of the Kruskal- Wallis statistic requires

Hence as is mentioned for an independent group design and ordinal data so we use the Kruskal Wallis test.

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We can use the Kruskal Wallis test when we have an independent group design and ordinal data.

We are given an independent group design and ordinate data.

We need to tell which test to use on them.

The Kruskal Wallis test is used when you have one independent variable with two or more situations and one ordinal dependent variable. In other words, it is an interpretation of ANOVA table and a generalized form of the Mann- Whitney test system.

The null hypothesis for the Kruskal- Wallis test tells us that:

There are no methodical or harmonious differences among the treatments being compared.

Therefore, we can use the Kruskal Wallis test when we have an independent group design and ordinal data.

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Answer:

48

Step-by-step explanation:

-12 x -4 = 48 (When we multiply two negetive numbers, the product becomes positive )

Answer:

48

Step-by-step explanation:

i did the quiz

Answer:

Literally. can't help. you dude.

Answer:

1)=-18x^5+60x^4-50x^3

2)k=3m/2-12

3)6x^2(x+2)(x-2)

Step-by-step explanation:

Hope dis helps :)

could i have brainliest

Answer:

11.2

Step-by-step explanation:

The answer is 11.2

11.2*.25=2.8

11.2-2.8=8.4

Answer:

Rational

Step-by-step explanation:

Answer:

x = 2

Step-by-step explanation:

3x – 5 = 1

    + 5  +5

3x  = 6

x = 6 ÷ 3

x = 2

Answer:

2

Step-by-step explanation:

Step 1:

3x - 5 = 1          Equation

Step 2:

3x = 6        Add 5 on both sides

Step 3:

x = 6 ÷ 3      Divide

Answer:

x = 2

Hope This Helps :)

The probability that the sum of the rolls is divisible by 6 is 1/1296, which is approximately 0.00077 or 0.077%.

To find the probability that the sum of the rolls is divisible by 6, we need to determine the favorable outcomes and the total number of possible outcomes.

First, let's identify the favorable outcomes. In this case, the sum of the rolls can be divisible by 6 if the sum is either 6 or 12.

1. For the sum of 6:
  - One possible outcome is rolling a 6 on the first roll and rolling a 1 on the remaining four rolls.
  - Another possible outcome is rolling a 5 on the first roll and rolling a 2 on the remaining four rolls.
  - We can also have rolling a 4 on the first roll and rolling a 3 on the remaining four rolls.
  - Similarly, rolling a 3 on the first roll and rolling a 4 on the remaining four rolls.
  - Finally, rolling a 2 on the first roll and rolling a 5 on the remaining four rolls.
  - This gives us a total of 5 favorable outcomes.

2. For the sum of 12:
  - One possible outcome is rolling a 6 on all five rolls.
  - This gives us a total of 1 favorable outcome.

Now let's determine the total number of possible outcomes. Since we are rolling a fair 6-sided die 5 times, the total number of possible outcomes is 6^5 (since each roll has 6 possible outcomes).

Therefore, the probability that the sum of the rolls is divisible by 6 is:

(total number of favorable outcomes) / (total number of possible outcomes)
= (5 + 1) / (6^5)
= 6 / 7776
= 1 / 1296

So, the probability that the sum of the rolls is divisible by 6 is 1/1296, which is approximately 0.00077 or 0.077%.

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Answer:

ask your teacher it would be good for you and also teachers give u good thing about that okay but i can't help you sorry.

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

girl honestly how does this question even come up

anyways you do 12 divided by 4 to get 3

Answer: hope it helps!!

0.0411251850633

Desmos graphing calculator is very helpful for these types of problems...

Answer:

Step-by-step explanation:

Expand    \(\frac{10}{243.16}\)

 by multiplying both numerator and the denominator by 100.

\(\frac{1000}{24316}\)

Reduce the fraction  

\(\frac{1000}{24316}\)

 to lowest terms by extracting and canceling out 4.

\(\frac{250}{6079}\)

​

Here the diameter = dm

Formula of circumference for circle: 2πr  or  πd

                                        where "d" is diameter and "r" is radius

For this question:

circumference:

Water quality concerns, as part of the water chemistry monitoring program, involve analyzing the presence of trace minerals and nutrients in surface water samples collected from Lake Louise and Louise Creek. Correct option is C.

To ensure water quality, it is crucial to assess the presence of various substances in the water samples. While trace minerals are essential to understand the composition of the water and detect any potential contaminants or harmful elements, nutrients also play a significant role.

Nutrients in water refer to substances such as nitrogen and phosphorus, which are essential for the growth and survival of aquatic organisms. However, excessive nutrient levels can lead to water quality issues such as eutrophication, harmful algal blooms, and oxygen depletion. Monitoring and analyzing nutrient levels in surface water samples help identify any imbalances and potential ecological impacts.

The ongoing water chemistry monitoring program at Faimont Chateau Lake Louise collects annual surface water samples from Lake Louise and Louise Creek to ensure the continued evaluation of trace minerals and nutrients. This proactive approach allows for the early detection of any deviations from desired water quality standards, enabling appropriate actions to maintain the ecological health of the water resources.

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The value(s) of x for which the instantaneous rate of change in f(x) = 2x positive is all set of real values

The equation of the function is given as

f(x) = 2x

The above function is a linear function

Next, we differentiate the function to determine the rate of change

So, we have

f'(x) = 2

When the instantaneous rate of change in f(x) = 2x positive, we have

f'(x) > 0

So, we have

2 > 0

The above is true

Hence, the value(s) of x for which the instantaneous rate of change in f(x) = 2x positive is all set of real values

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Answer:

B. 5/8

Step-by-step explanation:

because there are 8 boxes and 5 colored

1. Three examples of situations where consistency is important:

Healthcare: when treating patients, healthcare providers must follow consistent procedures and protocols to ensure that every patient receives the same level of care.

Financial transaction: when making financial transactions, it is important to follow regular security rules to prevent fraud.

Support rules: Adherence to consistent rules and regulations in sports is essential to ensure fair play and the safety of all participants.

2. The number 0 is important in mathematical systems because it represents the absence of a number and serves as a placeholder. Without zero, our mathematical system would be affected in many ways. For example, writing the number 100 would be difficult without the zero. Without the invention of zero, progress in mathematics would have been delayed.

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The probability that either event will occur is 0.83

From the question, we have the following parameters that can be used in our computation:

Event A = 18

Event B = 12

Other Events = 6

Using the above as a guide, we have the following:

Total = A + B + C

So, we have

Total = 18 + 12 + 6

Evaluate

Total = 36

So, we have

P(A) = 18/36

P(B) = 12/36

For either events, we have

P(A or B) = 30/36 = 0.83

Hence, the probability that either event will occur is 0.83

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Buying from Value World would cost Binita £0.72 less (in pounds) than buying from Letters2go.

To compare the costs of envelopes from both shops, we need to calculate the price per envelope.

At Letters2go, the price per envelope is:

3.29 pounds / 25 envelopes = 0.1316 pounds per envelope

At Value World, the price per envelope is:

(1.95 pounds * 2 packs) / (10 envelopes * 2 packs + 1 free pack) = 0.1300 pounds per envelope

So the price per envelope at Value World is slightly less than the price per envelope at Letters2go.

To buy 450 envelopes, Binita would need to purchase:

18 packs of 25 envelopes at Letters2go (18 x 25 = 450 envelopes)

45 packs of 10 envelopes at Value World (45 x 10 = 450 envelopes)

At Letters2go, the cost of 18 packs of 25 envelopes would be:

18 packs x £3.29 per pack = £59.22

At Value World, the cost of 45 packs of 10 envelopes (with 15 packs being free) would be:

30 packs x £1.95 per pack = £58.50

Therefore, buying from Value World would cost Binita £59.22 - £58.50 = £0.72 less than buying from Letters2go.

Correct Question :

Binita is going to buy 450 envelopes.

Here is some information about the cost of envelopes in two shops,

Letters2go : Pack of 25 envelopes for £3.29

Value World : Pack of 10 envelopes for £1.95, Buy 2 packs get 1 pack free

How much less, in pounds (£), will it cost Binita to buy the envelopes from Value World.

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Answer:

-33/56

Step-by-step explanation:

suppose: A,B are the 2 angles of a triangle

we have: A = arcsin\(\frac{-4}{5}\)

               B = arctan \(\frac{5}{12}\)

=> sin A = \(\frac{-4}{5}\) => cos A = \(\sqrt{1-\frac{(-4)^{2} }{5^{2} } } =\frac{3}{5}\) (because A is in quadrant IV)

    tan B = \(\frac{5}{12}\)

have:

\(1+ cot^{2}B=\frac{1}{sin^{2}B } => 1+\frac{1}{tan^{2} B}=\frac{1}{sin^{2}B } \\=> 1+\frac{1}{\frac{5^{2} }{12^{2} } } =\frac{1}{sin^{2}B }\\ => sin^{2}B=\frac{25}{169}\)

because B is in quadrant III => \(sin B=-\sqrt{\frac{25}{169} }=\frac{-5}{13}=>cosB=-\sqrt{1-\frac{5^{2} }{13^{2} } }=\frac{-12}{13}\)

tan(arcsin(-4/5)+arctan(5/12)) = tan( A + B)

but A,B are the 2 angles of a triangle => tan(A + B) = \(\frac{sin(A+B)}{cos(A+B)}\)

have: sin(A+B) = sinA.cosB + cosA.sinB = \(\frac{-4}{5}.\frac{-12}{13} +\frac{3}{5}.\frac{-5}{13}=\frac{33}{65}\)

cos(A + B) = cosA.cosB - sinA.sinB =\(\frac{3}{5}.\frac{-12}{13}-\frac{-4}{5}.\frac{-5}{13}=\frac{-56}{65}\)

=> tan(A + B) = \(\frac{33}{65}:\frac{-56}{65}=\frac{-33}{56}\)

Answer:

pie/6

Explaniation:

just took the test on k12