In an RC circuit, if we were to change the resistor to one with a larger value, we would expect that:
A. The area under the curve changes
B. The capacitor discharges faster
C. The capacitor takes longer to achieve Qmax
D. The voltage Vc changes when the capacitor charges.
Answers
The correct answer is option (C): The capacitor takes longer to achieve Qmax. In an RC circuit, the resistor and capacitor are connected in series.
When a capacitor is charging in an RC circuit, it gradually reaches its maximum charge, denoted as Qmax, over time.
If we were to change the resistor to one with a larger value, we would expect the following:
A. The area under the curve changes: This statement is not necessarily true. The area under the curve, which represents the charge stored in the capacitor over time, depends on the time constant of the circuit (RC time constant).
Changing the resistor value affects the time constant, but it does not directly determine whether the area under the curve changes. Other factors, such as the voltage applied and the initial charge on the capacitor, can also influence the area under the curve.
B. The capacitor discharges faster: This statement is not applicable to changing the resistor value. The discharge rate of a capacitor in an RC circuit is primarily determined by the value of the resistor when the capacitor is being discharged, not when it is being charged.
C. The capacitor takes longer to achieve Qmax: This statement is true. In an RC circuit, the time constant (τ) is determined by the product of the resistance (R) and the capacitance (C) values (τ = RC).
A larger resistor value will increase the time constant, which means it will take longer for the capacitor to charge to its maximum charge (Qmax). So, the capacitor will indeed take longer to achieve Qmax.
D. The voltage Vc changes when the capacitor charges: This statement is true. When a capacitor charges in an RC circuit, the voltage across the capacitor (Vc) gradually increases until it reaches the same value as the applied voltage.
Changing the resistor value affects the charging time constant, which in turn affects the rate at which the voltage across the capacitor changes during charging. Therefore, changing the resistor value will impact the voltage Vc during the charging process.
In summary, the correct answer is C. The capacitor takes longer to achieve Qmax.
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Related Questions
The force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires. If a force of 0.750 N exists between wires that are 1.75 cm apart, what is the force between them if they are separated by 2.50 cm?
Answers
the force between the two wires if they are separated by 2.50 cm is 0.525 N.
Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.
Let the initial force be F₁ and the initial distance be d₁.
Therefore, we can write the relationship between force and distance as;
F₁d₁ = F₂d₂
Where
;F₁ = 0.750 N (initial force)
d₁ = 1.75 cm (initial distance)
F₂ = ? (force at new distance)
d₂ = 2.50 cm (new distance)
Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂
Now substitute the values we know;
F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N
Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.
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a piece of 14-gauge copper wire (meaning that it has a diameter of 1.63mm) has a resistance of 0.128 . the resistivity of copper is . what must be the length of the wire?
Answers
The length of the copper wire must be approximately 44.2 meters for it to have a resistance of 0.128 ohms, assuming a 14-gauge wire with a diameter of 1.63 mm and using the resistivity of copper.
To find the length of the wire, we can use Ohm's Law, which states that the resistance (R) is equal to the product of the resistivity (ρ), the length (L), and the cross-sectional area (A) of the wire, divided by the diameter (d) of the wire squared.
The formula can be written as:
R = ρ * (L / A)
Resistance (R) = 0.128 ohms
Resistivity of copper (ρ) = (1.68 × 10^-8) ohm-meter (at 20°C)
Diameter (d) = 1.63 mm = 0.00163 meters (converted from millimeters to meters)
We need to find the length (L) of the wire.
To calculate the cross-sectional area (A) of the wire, we can use the formula for the area of a circle:
A = π * (d/2)^2
Plugging in the values, we have:
A = 3.14159 * (0.00163 / 2)^2
A ≈ 2.08 x 10^-6 square meters
Rearranging Ohm's Law to solve for the length (L), we get:
L = (R * A) / ρ
Substituting the given values:
L = (0.128 * 2.08 x 10^-6) / (1.68 x 10^-8)
L ≈ 44.2 meters
The length of the copper wire must be approximately 44.2 meters for it to have a resistance of 0.128 ohms, assuming a 14-gauge wire with a diameter of 1.63 mm and using the resistivity of copper.
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Which is NOT something that all green plants have in common?
1.They make their own food.
2. They reproduce.
3 .They grow.
4 .They produce flowers.
Answers
Answer:
4
Explanation:
Not all plants can grow flowers. Only the ones thay have buds can.
Not all plants produce flowers. Hence, this is the characteristic which is not common in all plants.Therefore, the correct option is 4.
What are flowers?Flowers are the structures of plants. They are responsible for producing seeds that will grow into new plants. Flowers typically consist of a colorful or ornamental part called the corolla, which attracts pollinators such as bees and butterflies, and a reproductive part called the stamen and pistil, which contain the plant's male and female organs.
Not all green plants produce flowers. Flowering plants are a type of plant that belong to the group Angiosperms, but there are also non-flowering plants like ferns and mosses that do not produce flowers. Therefore, the correct option is 4.
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i need help with this lab. i have to answer the lab questions 4-10. i will upload the graphs u need to use. someone please answer these questions. i will upload the pictures in different questions because it won’t let me upload 3…
Answers
The speed of an object is the rate of change of its position, and the object's velocity includes its speed as well as its direction of motion. The rate of change of the object's velocity gives the acceleration.
Explain Speed,Velocity and Acceleration?When an object's reference frame is chosen, its motion can be precisely characterized. The pace at which an object's position changes while it is moving is referred to as speed. The object's speed indicates how quickly or slowly it is going. But which way is the item traveling? The velocity of an object includes information about its direction of motion. The rate of change of an object's velocity, or the change in velocity per unit of time, is known as its acceleration.
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why is ism transparent at near-infrared and radio but opaque in visual wavelengths
Answers
The interstellar medium (ISM) is transparent at near-infrared and radio wavelengths but opaque in visual wavelengths due to the following reasons:
1. Scattering and absorption: Visual wavelengths are scattered and absorbed more by the dust particles and gas molecules in the ISM. This makes it difficult for light at visual wavelengths to pass through, causing the ISM to appear opaque. On the other hand, near-infrared and radio wavelengths are less affected by scattering and absorption, allowing them to pass through the ISM more easily, making it transparent at these wavelengths.
2. Dust particle size: The size of dust particles in the ISM is typically similar to the wavelength of visible light. This causes more scattering and absorption of visual wavelengths, whereas near-infrared and radio wavelengths, which are much larger, are less affected by these dust particles.
3. Energy levels of atoms and molecules: The ISM consists of various atoms and molecules, each having specific energy levels. Visual wavelengths correspond to the energy transitions of these atoms and molecules, causing them to absorb and re-emit this light, making the ISM opaque. Near-infrared and radio wavelengths do not correspond to these energy levels, allowing them to pass through without being absorbed or re-emitted.
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explain the oscillations or motion of both types of waves
Answers
A flywheel is rotating with an angular velocity of 1.4 rad/s and is acted on by an acceleration of 0.6 rad/s².
a) What angular velocity will it have attained after three complete turns?
b) How long will it take to do those three turns?
Answers
(a) The final angular velocity of the flywheel after 3 complete revolutions is 4.96 rad/s.
(b) The time taken for the flywheel to make 3 complete revolutions is 5.93 s.
Final angular velocityThe final angular velocity of the flywheel after 3 complete revolutions is determined by applying third kinematic equation as shown below;
θ = 2π (rad/rev) x (3 rev) = 18.85 rad
ωf² = ωi² + 2αθ
ωf² = (1.4)² + 2(0.6)(18.85)
ωf² = 24.58
ωf = √24.58
ωf = 4.96 rad/s
Time of motionThe time taken for the flywheel to make 3 complete revolutions is calculated as follows;
ωf = ωi + αt
t = (ωf - ωi)/α
t = (4.96 - 1.4)/0.6
t = 5.93 s
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Express 48 m/s in terms of
1.km/h
2.m/min
3.km/s
4.km/minutes
Answers
48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.
To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.
1 km (kilometer) = 1000 meter
1 h (hour) = 3600 seconds
1 minutes = 60 seconds
To convert m/s into km/h,
48 m/s * 3600/1000 = 172.8 km/h
To convert m/s into m/min,
48 m/s * 60 = 2880 m/min
To convert m/s into km/s,
48 m/s ÷ 1000 = 0.048 km/s
To convert m/s into km/minutes,
48 m/s * 60 / 1000 = 2.88 km/min
Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.
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48 m/s is equivalent to 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
To express 48 m/s in different units of velocity:
km/h (kilometers per hour):
To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.
48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h
Therefore, 48 m/s is equivalent to 172.8 km/h.
m/min (meters per minute):
To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.
48 m/s * (60 m/min / 1 s) = 2880 m/min
Therefore, 48 m/s is equivalent to 2880 m/min.
km/s (kilometers per second):
Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.
48 m/s / 1000 = 0.048 km/s
Therefore, 48 m/s is equivalent to 0.048 km/s.
km/minute (kilometers per minute):
To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.
0.048 km/s * 60 = 2.88 km/minute
So, 48 m/s is equivalent to 2.88 km/minute.
Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
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Jada runs exactly 2 laps around a 400 meter track. What is the displacement?
a:
0
b:
400
c:
800
Answers
Answer:
Option B 400meters
Explanation:
What is displacement
Displacement is a vector whose length is the shortest distance from the initial to the final position of a point P undergoing
Given data
number of laps = 2
length of lap= 400meters
Since after every one lap she returns to her initial position ]
the displacement is 400meters
two point masses are placed 10.0 cm apart and attract each other with a force of 10.0 n. find the force of gravitational attraction between the masses when they are placed 5.00 cm apart.
Answers
The final gravitational force after they are placed 5cm apart is 40 N.
We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as
F = G.m1.m2 / R²
where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.
From the question above, we know that
Ra = 10 cm
Rb = 5 cm
Fa = 10 N
The gravitational force is inversely proportional to squared distance. Hence
Fa / Fb = Rb² / Ra²
10 / Fb = 5² / 10²
Fb = 40 N
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One drops a penny from top of the Empire State Building on the ground below. The hight of the Empire State Building is 443m How long will it take for a penny yo strike the ground assuming no air resistance
Answers
Answer:
See below
Explanation:
Assuming no resistance
DISTANCE = 1/2 a t^2
443 = 1/2 (9.81)t^2 Shows t = 9.5 seconds
T/F the orbits of most of the planets have eccentricities close to zero.
Answers
False. The orbits of most planets have eccentricities greater than zero. Eccentricity is a measure of how much an orbit deviates from a perfect circle. A value of zero would indicate a perfect circle, while a value closer to one indicates a more elongated, elliptical orbit.
In our solar system, only Venus and Neptune have orbits with eccentricities close to zero, while the other planets have eccentricities ranging from 0.01 (Jupiter) to 0.25 (Mercury). The dwarf planet Pluto has the most eccentric orbit of all, with a value of 0.25.
The eccentricity of a planet's orbit can have important implications for its climate and potential habitability. For example, a planet with a highly elliptical orbit would experience extreme variations in temperature between its closest approach to the sun (perihelion) and farthest point (aphelion), which could make it difficult for life to survive.
In summary, most planets in our solar system have elliptical orbits with eccentricities greater than zero, which can affect their climate and potential for habitability.
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Identify the medium for the following waves:
ripples
The sound waves from a radio speakers
Seismic waves
Answers
Answer:
The sound waves from a radio speakers
Explanation:
1. A 2.5 kg led projector is launched as a projectile off a tall building. At one point, as it
is flying through the air it has a velocity of 24 m/s and a height of 14 m.
a) Find the potential energy
b) Find the kinetic energy
c) Find the total mechanical energy
d) Find the potential energy at a height of 8.7 m
e) Find the kinetic energy at that same height. (Hint – the total energy is always the same
as in part c)
f) Find the velocity at that height
g) Find the velocity at a height of 11.6 m
h) At what height would the velocity be 26 m/s?
i) What is the velocity just before it smashes into the ground?
See
Answers
Answer:
Explanation:
I got everything but i. Don't know why but it's eluding me. So let's do everything but that.
a. PE = mgh so
PE = (2.5)(98)(14) and
PE = 340 J
b. \(KE=\frac{1}{2}mv^2\) so
\(KE=\frac{1}{2}(2.5)(14)^2\) and
KE = 250 J
c. TE = KE + PE so
TE = 340 + 250 and
TE = 590 J
d. PE at 8.7 m:
PE = (2.5)(9.8)(8.7) and
PE = 210 J
e. The KE at the same height:
TE = KE + PE and
590 = KE + 210 so
KE = 380 J
f. The velocity at that height:
\(380=\frac{1}{2}(2.5)v^2\) and
\(v=\sqrt{\frac{2(380)}{2.5} }\) so
v = 17 m/s
g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:
590 = KE + PE and
PE = (2.5)(9.8)(11.6) so
PE = 280 then
590 = KE + 280 so
KE = 310 then
\(310=\frac{1}{2}(2.5)v^2\) and
\(v=\sqrt{\frac{2(310)}{2.5} }\) so
v = 16 m/s
h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:
\(v=v_0+at\) and
26 = 0 + 9.8t and
26 = 9.8t so the time at 26 m/s is
t = 2.7 seconds. Now we use that in the equation for displacement:
Δx = \(v_0t+\frac{1}{2}at^2\) and filling in the time the object was at 26 m/s:
Δx = 0t + \(\frac{1}{2}(-9.8)2.7)^2\) so
Δx = 36 m
i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.
One major concern of acid rain is that it can -
A. change the pH of soil and lakes
B. burn holes in the skin of humans and animals
C. it makes vegetation grow out of control
D. it turns trees red
Answers
Answer:
C. it makes vegetation grow out of control
Explanation:
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A runner weighing 70 kg, moving at a speed of 8.8 m/s, rounds
a bend with a radius of 25 m. What is the centripetal force
needed to keep this runner on the curve?
a 250 N
b 100 N
C 217 N
d 158 N
Answers
Answer:
217 N
Explanation:
Answer:217N
Explanation:
An airplane is heading south at a speed of 600km/h. If a wind begins blowing from the southwest at a speed of 100km/h, calculate: a) The velocity (magnitude and direction) of the plane relative to the ground. b) How far away from its intended position will it be after 10min if the pilot takes no corrective action? c) In what direction should the pilot aim in order to fly due south?
Answers
Answer:
Here's what I got:
Let's assume that N and E are + directions while S and W are - directions.
Wind is blowing from SW; thus, it is blowing towards NE (or at 45 deg N of E).
Dividing the wind's speed into components:y-component: +70.71 km/h; x-component: +70.71 km/h
Dividing the airplane's speed into components:y-component: -600 km/h; x-component: 0 km/h
Adding the components to get the resulting components:y-component: -529.29 km/h; x-component: +70.71
Using the Pythagorean Theorem to find the resulting speed:v^2 = y^2 + x^2 so v = 533.99 km/h
To find the angle of direction, use arctan (y/x):arctan (529.29/70.71) = 82.39 deg
ANSWER: velocity = 533.99 km/h at 82.39 deg S of E
Explanation:
What's the free body diagram for:
Mr. Seifert needs to push a cardboard box down the hallway for Ms. Wang. The box has a mass of 40 kg and he is pushing it with an acceleration of 2 m/s/s. Because the cardboard does not slide easily, there is a friction force of 25 Newtons acting on the box to the LEFT. How much force is Mr. Seifert applying to the box to move it forward to the RIGHT?
Answers
(a) The free body diagram for representing all the forces acting on an object.
(b) The force Mr. Seifert is applying to the box to move it forward to the RIGHT is 105 N.
What is free body diagram?
A free body diagram is a graphical illustration of all the forces acting on an object.
The force applied by Mr Seifert is calculated by applying Newton's second law of motion as follows;
F - Ff = ma
where;
F is the applied forceFf is the force of frictionm is the mass of the cardboarda is the acceleration of the cardboardThe given parameters include;
mass of the cardboard = 40 kg
force of friction = 25 N
acceleration of the cardboard = 2 m/s²
The force applied by Mr Seifert is calculated as follows;
F = Ff + ma
F = 25 N + (40 kg x 2 m/s²)
F = 105 N
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A wave moving with a speed of 0.5 m/s has a frequency of 50 Hz. What is the wavelength of the wave?
Answers
The wavelength of the wave moving with speed of 0.5 m/s and frequency of 50 Hz is 0.01 m.
Wavelength represents the distance between two successive crests or troughs of the wave.
Wavelength is calculated as follows:
λ = v / f
where λ, v, and f represent the wavelength, velocity, and frequency of the wave respectively.
v = 0.5 m/s
f = 50 Hz
Calculating the wavelength based on the above data:
λ = 0.5 / 50 = 0.01 m
Hence, the wavelength of the wave moving with speed of 0.5 m/s and frequency of 50 Hz is 0.01 m.
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The wavelength of the wave is 0.01m.
Given,
Speed of the wave, c = 0.5m/s.
Frequency of the wave, u = 50Hz.
Frequency is the number of complete vibration cycles of a medium in one second. And wavelength is the distance over which the waveshape repeats .
Now we have an equation frequency of an electromagnetic wave u = c/l. Wher u is the frequency of the waveform, c is the speed at which the wave is propagating and l is the wavelength.
Thus we can obtain wavelength l = c/ u = 0.5/50 = 0.01 meter.
Similarly, time period T can be obtained from this.
T= 1/u.
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HI can anybody tell me what newtons first law is pls don't make it sound too professional pls tyy
Answers
how are sound vibrations amplified in a vertebrate ear?
Answers
Answer:
by movement of the bones of the middle ear and by differences in the surface area of the eardrum versus the oval window.
Explanation:
All interactions between the atmosphere and the geosphere involve
gases or particles in air and water
water and living things.
soil and gases or particles in the air
soil and living things
Answers
Answer:
The geosphere consists of the solid Earth and the atmosphere consists of the gaseous components in the air. Thus, the answer is C.
Explanation:
Answer:
C
Explanation:
Which letter explains why no machine is 100 percent efficient.
A.Mechanical energy is transformed into thermal energy by friction.
B.Mechanical energy is transformed into electrical energy by a spark.
C.Thermal energy is transformed into mechanical energy by friction.
Answers
Answer:
A
Explanation:
Think about rubbing your hands together- the friciton produces heat
if a boat is traveling a distance of 60 km at a speed of 13km/s how long will it take to reach its destination
Answers
Answer:
4.61
60/13=4.61 so that is your answer : )
scott travels north 5 miles, then goes west 3 miles, and then goes south for 2 miles.
what is the distance he went?
10 miles
8 miles
7 miles
6 miles
Answers
Question 7 of 10
What could you do to increase the electric potential energy between two
positively charged particles by a factor of 16?
A. Increase the distance by a factor of 16.
B. Reduce the distance by a factor of 4.
C. Reduce the distance by a factor of 16.
D. Increase the distance by a factor of 4.
Answers
U = k * (q1 * q2) / r
where U is the electric potential energy, k is Coulomb's constant, q1 and q2 are the charges of the particles, and r is the distance between them.
To increase the electric potential energy between two positively charged particles by a factor of 16, we can rearrange the above equation as follows:
U' = 16U
k * (q1 * q2) / r' = 16 * (k * (q1 * q2) / r)
where U' and r' are the new potential energy and distance, respectively.
Simplifying the above equation, we get:
r' = (1/4) * r
Therefore, the distance between the positively charged particles must be reduced by a factor of 4.
So, the correct option is:
B. Reduce the distance by a factor of 4.
What will be the mass of a body at the center of the earth as compared to other places on
the earth?
Answers
Answer:
The mass of the object does not change by moving it to another place. ... At the center of the earth the net gravitational force is zero, so the weight will be zero, but its masses will remain same. Hence the mass at the centre of earth will be equl to 50 kg.
Explanation:
It's because the mass of the object doesn't change by moving it to next place.
La punta de la aguja de una máquina de coser se mueve en MAS, sobre el eje x con una frecuencia de 2,5 [Hz]. En t = 0, sus componentes de posición y velocidad son, respectivamente, +1,1 [cm] y -15 [cm/s]. A) Calcule la componente de aceleración de la aguja en t = 0. B) Escriba ecuaciones para las componentes de posición, velocidad y aceleración de la punta en función del tiempo. (15 puntos)
Answers
Answer:
A) El componente de aceleración de la aguja en \(t = 0\,s\) es -236,206 centímetros por segundo al cuadrado.
B) Las ecuaciones para la componentes de posición, velocidad y aceleración de la punta en función del tiempo son, respectivamente:
\(x(t) = 1,458\cdot \cos (15,708\cdot t +0,228\pi)\)
\(v(t) = -22,902\cdot \sin (15,708\cdot t + 0,228\pi)\)
\(a(t) = -359,749\cdot \sin (15,708\cdot t + 0,228\pi)\)
Explanation:
El movimiento armónico simple es un movimiento periódico de carácter sinusoidal que está descrito por la siguiente ecuación cinemática:
\(x(t) = A\cdot \cos (\omega\cdot t + \phi )\) (1)
Donde:
\(x(t)\) - Posición actual de la aguja con respecto a la posición de equilibrio, en centímetros.
\(A\) - Amplitud, en centímetros.
\(\omega\) - Frecuencia angular, en radianes por segundo.
\(\phi\) - Ángulo de fase, en radianes.
Por Cálculo Diferencial, obtenemos las fórmulas cinemáticas para la velocidad (\(v(t)\)), en metros por segundo, y la aceleración (\(a(t)\)), en metros por segundo cuadrado, de la aguja:
\(v(t) = -\omega\cdot A \cdot \sin (\omega\cdot t + \phi)\) (2)
\(a(t) = -\omega^{2}\cdot A \cdot \cos (\omega\cdot t + \phi)\) (3)
Por otra parte, la frecuencia angular está descrita por la siguiente fórmula:
\(\omega = 2\pi\cdot f\) (4)
Donde \(f\) es la frecuencia, en hertz.
Ahora, necesitamos calcular la amplitud y el ángulo de fase mediante el sistema de ecuaciones que hemos formado: \(t = 0\,s\), \(x(t) = 1,1\,cm\), \(v(t) = -15\,\frac{cm}{s}\) and \(f = 2,5\,hz\):
Por (4):
\(\omega = 2\pi\cdot f\)
\(\omega = 2\pi\cdot (2,5\,hz)\)
\(\omega \approx 15,708\,\frac{rad}{s}\)
Por (1) y (2):
\(A\cdot \cos \phi = 1,1\) (1b)
\(-15,708\cdot A \cdot \sin \phi = -15\) (2b)
Al dividir (2b) por (1b) y despejar el ángulo de fase tenemos que:
\(-15,708\cdot \tan \phi = -13,636\)
\(\tan \phi = 0,868\)
\(\phi = \tan^{-1} 0.868\)
\(\phi \approx 0,228\pi\,rad\)
Por (1) tenemos el valor de la amplitud: (\(\phi \approx 0,228\pi\,rad\))
\(A = \frac{1,1}{\cos \phi}\)
\(A = \frac{1,1}{\cos 0,228\pi}\)
\(A \approx 1,458\,cm\)
A) El componente de aceleración de la aguja se calcula por (3) evaluada en \(t = 0\,s\):
\(a(t) = -359,749\cdot \sin (15,708\cdot t + 0,228\pi)\)
\(a(0) = -236,206\,\frac{cm}{s^{2}}\)
B) Las ecuaciones para la componentes de posición, velocidad y aceleración de la punta en función del tiempo son, respectivamente:
\(x(t) = 1,458\cdot \cos (15,708\cdot t +0,228\pi)\)
\(v(t) = -22,902\cdot \sin (15,708\cdot t + 0,228\pi)\)
\(a(t) = -359,749\cdot \sin (15,708\cdot t + 0,228\pi)\)
based on the data collected and the hypothesis, what happens to the diffraction angle when the wavelength is increased?
Answers
The wavelength will be longer, increasing the diffraction angle.
Define the wavelength?The separation between two successive wave crests or troughs is known as a wavelength.
Here are some wavelength illustrations: Yellow Light, for instance. All visible light has a wavelength between 400 and 700 nanometers (nm).
Radio waves, light waves, and infrared (heat) waves are examples of electromagnetic radiation that flow through space in distinct patterns.
The symbol for the wavelength in the SI is often the letter m. Additionally, multiples or fractions of a metre are employed when calculating wavelength. The use of exponential powers of 10 is noteworthy when wavelengths are a significant feature.
To learn more about wavelength refer to:
https://brainly.com/question/10728818
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Answer:
Simple Response: The diffraction angle of the waves is approximately equal to the wavelength divided by the gap width. Therefore, increasing the wavelength will increase the diffraction angle.
Explanation:
Light waves are electromagnetic waves that travel at 3.00 x 10^8 m/s. The eye is most sensitive to light having a wavelength of 5.50 x 10^-7 m.
a. Find the frequency of this light wave.
b. Find its period.
Answers
Answer:
a. Frequency is 5.45 x 10^14 hz
b. The period = 1.8 x 10^-15 sec {or 1.8 femptoseconds]
Explanation:
The velocity of an electromagnetic wave is given by the product of the wave's frequency(f) times its wavelength(λ).
V = λ f where,
V is the wave speed,
f is the wave frequency,
λ is the wavelength.
To find frequency, rearrange to:
f = V/ λ
Light travels at 3.00x10^8 m/sec.
λ is 5.50 x 10^-7 m
f = (3.00x10^8 m/sec)/(5.50 x 10^-7 m) meters cancels, secs is on the bottom]
f = (3.00/5.50)*(10^15) [The base 10 exponent on the bottom ius subtracted from the one on top: 98-(-7)) = 15)
f = 0.545 x 10^15 1/s or hz
f = 5.45 x 10^14 hz
b. The period of a wave is the inverse of it's frequesncy. It is the time it takes for 1 wave to pass. Invert the frequency:
Period = 1/f
Period = 1/(0.545 x 10^15 1/s)
Period = 1.8 x 10^-15 sec {or 1.8 femptoseconds]
