In a video game, a flying coconut moves at a constant velocity of 20 meters/second in the positive direction. The coconut hits an obstacle and moves in the opposite direction with a constant velocity of 10 meters/second. What’s the change in velocity of the coconut?


A.

-30 m/s

B.

-10 m/s

C.

10 m/s

D.

30 m/s




15 points

Answer:

The force of gravity on an object depends on the mass of the object and the mass and distance of the celestial body it is on or near. The formula for the force of gravity is:

F = G * (m1 * m2) / r^2

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

To compare the force of gravity on an 81 kg mass on the Moon's surface with the force on the Earth's surface, we need to calculate each force using the above formula and then compare the results.

First, let's calculate the force of gravity on an 81 kg mass on the Earth's surface:

F_Earth = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 5.97 x 10^24 kg) / (6.38 x 10^6 m)^2

= 7.92 x 10^2 N

So the force of gravity on an 81 kg mass on the Earth's surface is 792 N.

Next, let's calculate the force of gravity on an 81 kg mass on the Moon's surface:

F_Moon = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 7.35 x 10^22 kg) / (1.74 x 10^6 m)^2

= 1.32 x 10^3 N

So the force of gravity on an 81 kg mass on the Moon's surface is 1320 N.

Therefore, the force of gravity on the Moon's surface is greater than the force of gravity on the Earth's surface. The ratio of F_Earth to F_Moon is:

F_Earth / F_Moon = 792 N / 1320 N

= 0.6

So the force of gravity on the Moon's surface is about 60% of the force of gravity on the Earth's surface.

Answer:

B........................

When a solid disk, a ring and a solid sphere of the same mass are released from the top of an incline, the sphere will win the race. Hence option (a) is the answer.

An inclined plane is a straightforward device with a sloping surface that's used to lift heavy objects. Even after accounting for friction, the force needed to lift an object up an incline is less than the weight being raised.

The needed force approaches the real weight much more closely the higher the slope or incline. It is an "inclined plane" because it is an "inclined plane"—a flat surface that is slanted rather than level. You may also control how quickly something descends by using an inclined plane. On a steeper ramp, things fall more quickly.

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The correct question is:

A solid disk, a ring and a solid sphere of the same mass are released from the top of an incline, which object will win the race? Assuming that the objects do not slip.

a. The sphere

b. The ring

c. The disk

d. They will tie

e. Don't have enough information

The bus's displacement from Houston to Texas with average velocity = -16.170 km/h

Evaluation :

average velocity = ( initial velocity -- final velocity )

                                    ( v-u )

displacement = \(\frac{v-u}{t}\)

displacement =  \(\frac{0 - 76 }{4.7}\)

                            = - 16.170 km/h

Average velocity is determined  as the change in position or displacement (∆x) divided by the time period  (∆t) in which the displacement results . The average velocity could be positive or negative based upon the sign of the displacement. The SI unit of average velocity is defined as  meters per second (m/s or ms-1).

The displacement is commonly the difference in the position of the two marks and is independent of the path covered  when traveling between the two of the  marks. The distance covered , however, is the total length of the path chosen  between the two marks. Displacement defined  as a vector quantity that mean  to "how far out of  the place an object is"; it's the object  overall changes  in  the position.

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The subject depicted in the attached image is Astronomy and Astrophysics.

Astronomy is the scientific study of celestial objects such as stars, planets, galaxies, and other phenomena that exist outside of Earth's atmosphere.

Astronomers use a variety of methods to observe and study these objects, including telescopes, spacecraft, and computer simulations.

Astronomy is a broad field that includes many different sub-disciplines, such as astrophysics, planetary science, and cosmology.

Astronomers study the physical properties and behavior of celestial objects, such as their composition, temperature, motion, and evolution.

They also seek to understand the structure and history of the universe as a whole.

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Answer:

We must apply a force to keep the object moving at a constant velocity due to gravitational force or weight (in case of lifting), and due to frictional force (in case of pushing).

Explanation:

LIFTING:

When an object is lifted, we first need to overcome the force exerted on it by the field of gravity. Due to this force, which is also called the weight of object, we must apply a force on the object to keep it moving at constant speed, otherwise the gravity force will cause the object to slow down and eventually fall back on ground.

PUSHING:

When pushing an object the person must apply the force to first overcome the frictional force. The frictional force acts in opposite direction of motion. Thus, to move the object at constant speed we must apply force to it.

Hence, we must apply a force to keep the object moving at a constant velocity due to gravitational force or weight (in case of lifting), and due to frictional force (in case of pushing).

Answer:

The magnitude of displacement vector 2D-E is approximately 14.49 units. The calculation is done using the Pythagorean theorem after finding 2D-E by multiplying vector D by 2 and subtracting vector E.

Explanation:

The value of 2D-E must first be calculated in order to ascertain the displacement 2D-E's magnitude. Vector D may be multiplied by two to accomplish this, and the result can be obtained by deducting vector E:

2D-E = 2(6i + 3j - k) 4i + 5j + 3k = 8i + 11j - 5k - (4i - 5j + 3k) = 12i + 6j - 2k

We can use the Pythagorean theorem to determine the magnitude of the displacement vector now that we know it:

|2D-E| = √(8² + 11² + (-5)²) = √(64 + 121 + 25) = √210 ≈ 14.49

The displacement 2D-E magnitude is therefore 14.49 units or such. From the object's beginning location to its ultimate position, the displacement's entire length is shown by this. Being a scalar variable, the displacement's magnitude does not reveal the displacement's direction.

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Answer:

dependent variable

Explanation:

The vector quantities have both magnitude as well as direction.

The length of the vector is corresponding to there magnitude where as the arrow at the head of the vector represents the direction.

Thus, the given statement is false.

The value of V is 640 km/hr.

Average velocity is the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.

To calculate the value of V from the question, we use the formula below.

Making V the subject of the equation

From the question,

⇒ Given:

Substitute these values into equation 2

Hence, the value of V is 640 km/hr.

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Answer: 4500 m

Explanation:

\(15 min. * \frac{240 m}{min.} = 3600 m\)

\(10 min. * \frac{90m }{min.} = 900 m\)

\(3600m +900m = 4500m\)

The magnitude of the force acting at point O is determined as 240 N.

The magnitude of the force at point O is calculated by applying the principles of moment as shown below.

sum of the clockwise moment = sum of the anticlockwise moment

F₀(2 m + 2m + 2m) = 260 N (2m + 2 m ) +  200 N ( 2 m )

where;

6F₀ = 260 (4) + 200(2)

6F₀ = 1,440

F₀ = 1440 / 6

F₀ = 240 N

Thus, the magnitude of the force acting at point O is determined as 240 N.

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Answer: true

Explanation:

Answer:

Explanation:

It depends on the construction of the sphere.

Let's ASSUME it is thin wall sphere with a moment of inertia (2/3)mR²

The Change in potential energy will equal the change in kinetic energy

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½((2/3)mR²)(v/R)²

2gh = v² + 2/3v²

2gh = 5/3v²

v = √((6/5)gh)

v = √((6/5)(9.81)(10.0sin30.0))

A) v = 7.67 m/s  

B) ω = 7.67/0.345 = 22.2 radians/s

C)  ½mv² / ½Iω² = mv²/Iω² = mv²/((2/3)mR²)(v/R)² = 3/2

To better understand crash dynamics we have to look at "the laws of motion."

The laws of motion

The laws of motion were introduced by Sir Isaac Newton in 1687 in his book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), which defined the laws of motion, or three fundamental laws that govern the movement of bodies. The laws of motion, according to Newton, govern the motion of an object or a system of objects that interact.

It defines the concepts of force and mass, and the fundamental dynamics of motion.The following are the laws of motion:Every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. The velocity of an object changes proportional to the force applied to it, and the acceleration of an object is proportional to both its force and its mass. For every action, there is an equal and opposite reaction.

Therefore, these laws are necessary to fully grasp crash dynamics because they explain how objects respond to outside forces that cause them to accelerate or decelerate.

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The graph below shows the motion of a person leaving theater, line segment C represent : The person is moving away from the theater.

In physics, motion is a change with time of the position or orientation of a body. Motion along a line or a curve is called as translation whereas motion that changes orientation of a body is called rotation.

Motion is a change in position of an object over the  time and is described in terms of displacement, distance, velocity, acceleration, time and speed.

Change in position of a body with time when compared with another body is known as  motion.

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Answer:

Explanation:

a) The total distance traveled by the balloon = (100 + 60) m

                                                          = 160 metes

b) speed = \(\frac{distance covered}{time taken}\)

The average speed for the first flight = \(\frac{100}{10}\)

                                                    = 10 m/s

c) The speed during its next flight = \(\frac{60}{6}\)

                                                    = 10 m/s

d) Average speed for the entire trip = \(\frac{(10 + 10)}{2}\)

                                                    = 10 m/s

e) Total displacement = \(\sqrt{(100)^{2} + (60)^{2} }\)

                                   = \(\sqrt{13600}\)

                                   = 116.62 m

f) velocity = \(\frac{displacement}{time}\)

Average velocity during the first 10 seconds = \(\frac{100}{10}\)

                              = 10 m/s

g) Average velocity during the next 6 seconds = \(\frac{60}{6}\)

                               = 10 m/s

h) Average velocity for the entire trip = \(\sqrt{(10)^{2} + (10)^{2} }\)

                                                              = \(\sqrt{200}\)

                                                              = 14.14 m/s

Consider a circuit where the input voltage source is connected in series with a capacitor, inductor and resistor. Which of the following statements are true  (A) Voltage across the inductor must be continuous.

Due to the physical property of electric charge, charged material experiences a force when it is exposed to an electromagnetic field. You could be electrically positive or negative. While like charges repel one another, opposite charges attract.

Because the charge (Q) is constant and equal, the capacitor's value alone

V = Q /C

determines the voltage drop across the capacitor. Lower capacitance values will produce higher voltages, but bigger capacitance values will provide smaller voltage drops.

The voltage drop across a capacitor is correlated with its charge and is uncharged, as opposed to a resistor where the voltage drop is proportional to the initial current and there is an initial current.

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The car moving with a speed of 28.4 m/s.

The axis's calculated current speed, as determined by the change in the Transducer Counts status register, is known as the Actual Speed. It is measured in position units per second, or actual speed. In order to lessen the impact of quantizing errors, this value has been filtered.

Using newton's equation of motion,

s = (v+u)t/2 .............................. Equation 1

Where s = distance,  v = Final velocity, u = initial velocity, t = time.

making v the subject of the equation,

v = (2s/t)-u........................... Equation 2

Given: s = 3.3 km= ( 33×1000) m = 3300 m , t = 3.1 min = (3.1× 60 ) s = 186 s, u = 7.1 m/s.

substitute into equation 2

v = (2×3300/186)-7.1

v = 28.383 m/s

v ≈ 28.4 m/s

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In 60 minutes or 3600 seconds, the tip of the minute hand traverses the circumference of a circle with radius 3.00 cm, so it moves with a tangential speed of

(3.00 cm)/(3600 s) ≈ 0.00083 cm/s = 8.3 μm/s

Answer:

46 J

Explanation:

Simply calculate the 92% of 50 Joules as:

0.92 * 50 J = 46 J

Answer:

isotopes

Explanation:

Isotopes are atoms of the same element that have different numbers of neutrons but the same number of protons and electrons. The difference in the number of neutrons between the various isotopes of an element means that the various isotopes have different masses.

BRAINLIEST PLSS

Since the positive x-direction was established to be to the right, the sleigh's velocity is in this direction (the positive x-direction).

The whole horizontal momentum is conserved since there is no external force operating on the system (the sleigh plus Jonathan and Jane) in the horizontal direction.

Let's say that the positive x-direction is to the right and the positive y-direction is up. Then, we may divide Jonathan and Jane's velocities into their x- and y-components as follows:

vx1 = 5.00 cos 30.0° = 4.33 m/s and vy1 = 5.00 sin 30.0° = 2.50 m/s are the speeds of Jonathan.

Jane's speed is given by the formulas vx2 = 7.00 cos 36.9° = 5.61 m/s and vy2 = 7.00 sin 36.9° = 4.16 m/s.

The sleigh is initially at rest, hence there is no initial total momentum in the x-direction. The total x-direction momentum after Jonathan and Jane jumps out is:

px = (−800 N)(−4.33 m/s) + (600 N)(5.61 m/s) = 6430 N·s

The final momentum in the x-direction is:

p'x = (1000 N + 800 N + 600 N)vx'

where vx' is the final velocity of the sleigh in the x-direction.

Therefore, we can solve for xv:

vx' = px / (1000 N + 800 N + 600 N) = 6430 N·s / 2400 N = 2.68 m/s

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The work done to pull the object 7.0 m is the total area under the graph from 0.0 m to 7.0 m, determined as 245 J.

The area under force versus displacement graph is work done.

The total work done by pulling the object 7 m, can be grouped into two areas;

A1 = ¹/₂ bh

A1 = ¹/₂ x (2) x (20)

A1 = 20 J

A2 = ¹/₂(large base + small base) x height

A2  = ¹/₂[(7 - 2) + (7-3)] x 50

A2 = ¹/₂(5 + 4) x 50

A2 = 225 J

W = A1 + A2

W = 20 J + 225 J

W = 245 J

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The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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Answer:

the wavelength will decrease

Explanation:

If the frequency of a wave increases, the wavelength will decrease. This is because the speed of the wave is constant for a given medium, so if the frequency (the number of waves passing a fixed point per second) increases, then the distance between successive wave crests (i.e., the wavelength) must decrease to maintain a constant speed. This relationship is described by the wave equation:

v = f λ

where v is the speed of the wave, f is the frequency, and λ is the wavelength. If v is constant and f increases, then λ must decrease to keep the equation balanced.

convex lenses.

eyeglasses with convex lenses increase refraction, and accordingly reduce the focal lenght

The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.

The percent uncertainty in measuring the light weight object is calculated as follows;

\(= \frac{0.034}{11} \times 100\%\\\\= 0.309\%\)

The uncertainty of the heavy object if the scale remains constant is calculated as follows;

\(= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs\)

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Answer:

market economies

Answer : a market economy