In a trivia competition, Tiffanie had accumulated 600 points. Then she lost 900 points in the film category. What was her score at that point?

From the provided equations, the equation which has no solution is 3 4 x less-than-or-equal-to 2 +4x. Option 2 is correct.

Inequality equation is the equation in which the two expressions are compared with greater than, less than or other inequality signs.

From the given equations, the equation which has no solution has to be found out. When the value, does not equate for the expression, then the expression has no solution.

The first equation given in the problem is,

\(6 (x +2) > x-3\)

Solve it further,

\(6 x +12 > x-3\\6x-x > -3-12\\5x > -15\\x > -3\)

The second equation given in the problem is,

\(3+ 4x \leq 2 (1 +2x)\)

Solve it further,

\(3+ 4x \leq 2 +4x\\4x- 4x \leq 2-3\\0\leq-1\)

The value of 0 is greater than the number -1. Thus, this inequality has no solution.

The option 3 and 4 has a solution. Hence, from the provided equations, the equation which has no solution is 3 4 x less-than-or-equal-to 2 +4x. Option 2 is correct.

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Scatter plot with points plotted at 1 comma 7, 1 comma 8, 2 comma 9, 3 comma 6, 4 comma 8, 5 comma 5, 6 comma 7, 7 comma 5, 8 comma 7, 9 comma 4, and 10 comma 2, and a line drawn through about 3 comma 6 and 5 comma 6.

Data can be graphically represented using a scatter plot. The Coordinate axes are used in a straightforward scatter plot to plot the points according to their values. The essential relationship between the two measurements was deciphered using the scatter plot.

The scatter plot reveals an overall rising trend in the data; however it is not a completely straight line. Nonetheless, we can create a line that roughly corresponds to the data.

The first alternative, with a line drawn between 3,6 and 5,6, seems to fit the data the best when comparing the options. The line, which passes through each point's center, depicts the data's general trend.

As a result, the answer is:

Scatter plot with points plotted at 1 comma 7, 1 comma 8, 2 comma 9, 3 comma 6, 4 comma 8, 5 comma 5, 6 comma 7, 7 comma 5, 8 comma 7, 9 comma 4, and 10 comma 2, and a line drawn through about 3 comma 6 and 5 comma 6.

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Answer:

D. No. She multiplied with the reciprocal of the dividend instead of the reciprocal of the divisor.

Step-by-step explanation:

A. Yes. She solved the problem correctly.

B. No. She multiplied the dividend by the divisor instead of finding the reciprocal.

C. No. She multiplied the denominators instead of finding a common denominator.

D. No. She multiplied with the reciprocal of the dividend instead of the reciprocal of the divisor.

Her workings

7 ÷ 2/ 5

=1/ 7 × 2/ 5

= 2/35

Dividend=7

Divisor=2/5

The correct working

7 ÷ 2/ 5

=7 × 5/2

=35/2

Answer:

D

Step-by-step explanation:

I got an 100% on the quiz I took with this question :)

Hope I could help good luck on passing!!

Answer:

60

Step-by-step explanation:

   Exterior angle of the triangle equals the sum of opposite interior angle.

     4z + z + 10 = z + 50

           5z + 10 = z + 50

Subtract 10 from both sides,

                 5z = z + 50 - 10

                5z  = z + 40

Subtract z from both sides,

            5z - z = 40

                 4z = 40

Divide both sides by 4,

                  z = 40 ÷ 4

                  z = 10

Exterior angle = z + 50

                       = 10 + 50

                       = 60

Answer:

c

Step-by-step explanation:

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

\(\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end\)

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

\(\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end\)

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

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Answer: \(19u^{2} -12u\)

Step-by-step explanation:

1) You would have to distubite the 2 to the numbers inside the paretheis.

\(( -12u + 20u^{2} ) + -u^{2}\)

2) After that you add the like terms together.

\(20u^{2}-u^{2}= 19u^{2}\)

\(-12u\) (Nothing to add this term with.)

3) Put them together to make your answer.

\(19u^{2}-12u\)

SOLUTIONS

Quartile is also called as Quarter

A quartile divides data into three points—a lower quartile, median, and upper quartile—to form four groups of the dataset. The lower quartile, or first quartile, is denoted as Q1 and is the middle number that falls between the smallest value of the dataset and the median. The second quartile, Q2, is also the median.

Quartiles are values that divide your data into quarters. However, quartiles aren't shaped like pizza slices; Instead they divide your data into four segments according to where the numbers fall on the number line. The four quarters that divide a data set into quartiles are: The lowest 25% of numbers.

Therefore Quartile is also called as Quarter

The information that is not sufficient to prove that a parallelogram is a square is the measurement of its angles alone. Additional information about the lengths of its sides is needed to confirm if a parallelogram is indeed a square.

To determine whether a parallelogram is a square, we need to consider both the angles and the side lengths. A parallelogram has opposite sides that are parallel and equal in length, and opposite angles that are congruent. While a square is a special type of parallelogram with four equal sides and four right angles, simply knowing that the angles of a parallelogram are equal is not enough to establish it as a square.

To confirm that a parallelogram is a square, we must also ensure that all four sides are of equal length. In a square, all angles are right angles, and all sides are congruent. Therefore, if we have information about the side lengths of a parallelogram and can verify that they are equal, along with the knowledge that the angles are right angles, then we can conclude that the parallelogram is indeed a square.

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Answer:

20 feets

Step-by-step explanation:

The total area of the square pyramid, including base :

Area of base = Area of square `= s² ; s = base length =

Area of base = 2² = 4 feets

Area of triangle = 1/2 * base * height

Area of triangle = 0.5 * 2 * 4 = 4 feet²

Number of triangles = 4

Therefore, total of (4 * 4 feets) + 4 feets

= 16 feets and area of square baaa

= 20 feet²

Answer:

24,500

Step-by-step explanation:

Answer:

.2 Cm

Step-by-step explanation:

Each installment will be approximately $15,280.55.

To calculate the equal six-monthly installment, we can use the formula for the present value of an annuity.

Principal amount (P) = $500,000

Interest rate (r) = 12% per annum = 12/100 = 0.12 (compounded monthly)

Number of periods (n) = 20 (since there are 20 equal six-monthly installments)

The formula for the present value of an annuity is:

\(P = A * (1 - (1 + r)^(-n)) / r\)

Where:

P = Principal amount

A = Equal installment amount

r = Interest rate per period

n = Number of periods

Substituting the given values into the formula, we have:

$500,000 = \(A * (1 - (1 + 0.12/12)^(-20)) / (0.12/12)\)

Simplifying the equation:

$500,000 = A * (1 - (1.01)^(-20)) / (0.01)

$500,000 = A * (1 - 0.6726) / 0.01

$500,000 = A * 0.3274 / 0.01

$500,000 = A * 32.74

Dividing both sides by 32.74:

A = $500,000 / 32.74

A ≈ $15,280.55

Therefore, each installment will be approximately $15,280.55.

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Answer:

46

Step-by-step explanation:

the sign || (absolute sign) removes the negative sign and only lets positive part so the answer is 46

Answer:

-3 , -2 , -0.8 , 0.8 , 7

hope this helps...

Answer:

i really dk

Step-by-step explanation:

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Answer:

$18.15

Step-by-step explanation:

Answer:

None of the following

Step-by-step explanation:

Answer:

Radius duh

Step-by-step explanation:

2x^2 + 4x - 4

..........................

Answer:

x = {-2, -1}

Step-by-step explanation:

Combine like terms: 0 + -2 = -2

x = -2

Simplifying

x = -2

Combine like terms: 0 + -1 = -1

x = -1

Simplifying

x = -1

This problem requires optimization over a closed interval.

To find a positive number x such that the sum of 4x and \(x^2\) is as small as possible, we need to minimize the objective function \(4x + x^2.\)

Since we are looking for a positive number, the interval of interest is [0, ∞), which is a closed interval because it includes its endpoints.

In optimization problems, a closed interval is used when we want to consider all possible values within a given range, including the endpoints.

In this case, we want to explore all positive values of x starting from 0, which is the lower bound of the closed interval [0, ∞).

By finding the minimum value of the objective function within this closed interval, we can determine the value of x that minimizes the sum of 4x and \(x^2\).

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The correct value of the product of a and b is 224

Taking the prime factorization of 161 reveals that it is equal to 23*7. Therefore, the only ways to represent 161 as a product of two positive integers are 161*1 and 23*7. Because neither 161 nor 1 is a two-digit number, the only two-digit factor of 161 is 23, we know that a and b are 23 and 7. Because 23 is a two-digit number, we know that a, with its two digits reversed, gives 23.

Therefore, a = 32 and b = 7. Multiplying our two correct values of a and b yields.

The correct product must have been

a*b =32*7

=224

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The cost of one ounce of chocolate cream at Philadelphia according to the cost in pound will be $0.47.

We are aware of the fact that 1 pound is equal to 16 ounces. So, the cost of one pound will be the cost of 16 ounces. Representing this information in ounces and expression -

Cost of 1 pound = 7.52

Rewriting the equation according to ounce

Cost of 16 ounces = 7.52

So, cost of 1 ounce = 7.52/16

Performing division on Right Hand Side of the equation

The cost of one ounce = 0.47

Therefore, the cost of one ounce will be $0.47.

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Answer:

12

Step-by-step explanation:

No. of red flyers = 6

No. of blue flyers = 4

We need to find the minimum number of flyers of each color if she gave out the same number of red and blue flyers. For this we must find the LCM of 6 and 4.

Prime factorization of 6 = 2×3

Prime factorization of 4 = 2×2

Lowest common multiple of 6 and 4 = 12

Hence, there are 12 minimum number of flyers of each color

(a) To show that a 2×4-MA is equivalent to a weighted 5-MA with weights 1/8, 1/4, 1/4, 1/4, 1/8, we can compare the expressions for both moving averages.

The 2×4-MA can be written as:

\(y_t = (1/4)(x_t-1 + x_t-2 + x_t-3 + x_t-4) + (1/4)(x_t + x_t-1 + x_t-2 + x_t-3)\)

The weighted 5-MA with weights 1/8, 1/4, 1/4, 1/4, 1/8 can be written as:

\(y_t = (1/8)(x_t-2) + (1/4)(x_t-1 + x_t-2 + x_t + x_t-1) + (1/8)(x_t)\)

By rearranging and simplifying the terms in both expressions, we can see that they are indeed equivalent.

The weights are distributed in a way that gives more emphasis to the adjacent values and less emphasis to the outer values, resulting in a

5-period moving average.

(b) To show that the variance of an I(1) series is not constant over time, we need to consider the definition of an I(1) series.

An I(1) series is a non-stationary series where differencing the series once results in a stationary series.

When differencing a series, the mean may become constant, but the variance may still vary over time.

In other words, even though the series becomes stationary in terms of its mean, the variability of the series may still change.

The changing variance over time is often a characteristic of time series data, especially in the case of economic and financial data.

This phenomenon is referred to as heteroscedasticity. It implies that the spread of the data points changes as we move along the time axis, indicating that the variability of the series is not constant.

(c) The given ARIMA model can be rewritten using backshift notation as:

(1 - 2B + B^²)yt = (1 - 1/2B + 1/4B²)εt

In backshift notation, the lag operator B is used to represent the time shifts. \(B^k\) represents a k-period backward shift.

For example, B²yt represents yt-2.

The order of the model can be determined by the highest power of B present in the model.

In this case, the highest power of B is B², so the order of the model is 2.

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The system of equations can be graphed using a graphing utility to find their intersection point, which represents the solution to the system.

To graph the system of equations, we first need to rearrange them in slope-intercept form, which is y = mx + b. For the first equation, we can solve for y by subtracting 2x from both sides and then dividing by -4, which gives us y = -0.5x + (5/4). For the second equation, we can solve for y by dividing both sides by -1.2 and then simplifying, which gives us y = -0.5x + (5/8). We can then enter these equations into a graphing utility, such as Desmos or GeoGebra, to plot their graphs. The intersection point of the two graphs represents the solution to the system. In this case, the intersection point is (4.4, 1.3), which means that x = 4.4 and y = 1.3 is the solution to the system of equations.

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The number 102 in the sequence will be closest to 100.

A sequence in which each next term gets increased or decreased from the preceding by a constant value is called an arithmetic progression.

The difference of any two consecutive terms in an arithmetic progression is called the common difference of the AP (arithmetic progression).

Here each terms increases by 8. So, the common difference d is 8.

The first term is given to be 38.

So our sequence will be,

38, 46, 54, 62,...

nth term in an AP can be calculated by using the formula,

aₙ = a₁ + (n-1)d

To find the term nearest to 100,

100 = 32 + (n-1)8

68/8 = (n-1)

9.5 = n

But the value of n can not be a non-integer,

So the term nearest to 100 will be 9th or 10th term.

a₉ = a₁ + (9-1)d

a₉ = 8 + (8 x 8)

a₉ = 94

and,

a₁₀ = a₁ + (10-1)d

a₁₀ = 8 + (9 x 8)

a₁₀ = 102.

We can see,

a₁₀ = 102 is closest to 100.

Hence, 10th term is closest to 100.

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D, divide and figure out how much the picture is increasing lengthwise and use that to find the wideness

The dimension of the enlarge picture will be 150 inches (3.81 meters) wide and 180 inches (4.57 meters) long. Then the correct option is D.

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered.

There is no effect of dilation on the angle.

A photograph measures 5 inches (0.13 meters) wide and 6 inches (0.15 meters) long.

The picture is enlarged to fit on a wall.

If the new larger picture is 150 inches (3.81 meters) wide.

Then the scale factor of the enlargement will be

Scale factor = 150 / 5

Scale factor = 30

Then the length of the picture will be

The length of the picture is given by the product of the scale factor and original length.

Length = 30 x 6

Length = 180 inches (4.57 meters)

Then the dimension of the enlarge picture will be 150 inches (3.81 meters) wide and 180 inches (4.57 meters) long.

Then the correct option is D.

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The factored expression of 21x^7y^7z^4 + 31x^4y^4 is  x^4y^4(21x^3y^3z^4 + 31)

The expression is given as

21x^7y^7z^4 + 31x^4y^4

Express the above expression as a product

So, we have

21x^7y^7z^4 + 31x^4y^4 = 21x^3y^3z^4 * x^4y^4 + 31 * x^4y^4

Factor out x^4y^4

So, we have

21x^7y^7z^4 + 31x^4y^4 =  x^4y^4(21x^3y^3z^4 + 31)

Hence, the factored expression of 21x^7y^7z^4 + 31x^4y^4 is  x^4y^4(21x^3y^3z^4 + 31)

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There are thousands of answers to these questions but I would give the most simple answers.

7. Lets say points (-1,-1), (0,0), (1,1)

8. y = x

Explanation: The y-intercept would be 0. In order from (0,0) to go to (1,1), we need to go up one unit and right 1 unit so, by rise/run, the slope would be 1/1 or simply 1. by plugging into the equation y = m(slope)x + b(y-intercept).

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The most appropriate choice for Percentage will be given by

What is percentage?

Suppose there is a number and the number has to be expressed as a fraction of 100. Then that number is called percentage.

For example, 2% means \(\frac{2}{100}\)

Here,

Let the number be x

On increasing x by 10%, result = \(x + \frac{10}{100} \times x\)

                                                  = \(x + \frac{x}{10}\)

                                                  = \(\frac{10x +x}{10}\)

                                                  = \(\frac{11x}{10}\)

Now on increasing his answer by 10 %, result =

                                                                            \(\frac{11x}{10}+\frac{10}{100}\times \frac{11x}{10}\\\frac{11x}{10} + \frac{11x}{100}\\\frac{110x + 11x}{100}\\\frac{121x}{100}\)

Total increase in number = \(\frac{121x}{100} - x\)

                                           = \(\frac{121x-100x}{100} \\\)

                                           = \(\frac{21x}{100}\)

Percentage increase = \(\frac{\frac{21x}{100}}{x} \times 100\)

                                   = 21%

Percentage increase overall = 21 %

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