In a study of synthetic fuels, 0.100 mol of CO and 0.100 mol of water vapor are added to a 20.00-L container at 900. °C, and they react to form CO₂ and H₂. At equilibrium, [CO] is 2.24x10⁻³ M.(b) Calculate Ptotal in the flask at equilibrium.

pH after addition − pH before addition = pH change= 9.11.

When 0.073 mol KOH is added to 1.00 L of a buffer solution that is 0.304 M in HNO2 and 0.218 M in NO2-, the pH change can be determined as follows:

pH before addition of KOH can be calculated using the Henderson-Hasselbalch equation:pH = pKa + log([A-]/[HA])

where pKa = -log(Ka) = -log(4.5 x 10^-4) = 3.35[A-] = concentration of the conjugate base (NO2-) = 0.218 M[HA] = concentration of the weak acid (HNO2) = 0.304 M

Therefore, pH before addition of KOH = 3.75Now, KOH reacts with HNO2 to form KNO2 and H2O.KOH + HNO2 → KNO2 + H2O0.073 mol of KOH reacts with 0.073 mol of HNO2.0.304 - 0.073 = 0.231 M HNO20.218 + 0.073 = 0.291 M NO2-KNO2 does not hydrolyze.

Therefore, [OH-] = 0.073/1 L = 0.073 M.pOH = -log[OH-] = -log(0.073) = 1.14pH after addition = 14.00 - pOH = 12.86pH change = pH after addition - pH before addition= 12.86 - 3.75 = 9.11

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Answer:

Explanation:

Atoms are the thing that make up molecules and compounds. Molecules contain two or more atoms and are held together by covalent bonds

A covalent bond is formed by the overlap of orbitals. Hybrid orbitals are formed to explain bond angles.

According to valence bond theory, a covalent bond is formed by the overlap of orbitals from two atoms.

In order to explain the observed bond angles in many species, it is proposed that the atomic orbitals first form hybrid orbitals, which differ from the orbitals of the isolated atoms.

These hybrid orbitals are created by mixing atomic orbitals in a way that maximizes overlap and stabilizes the bond.

The type and number of hybrid orbitals formed depend on the number of electron groups surrounding the central atom.

This concept of hybridization has been widely accepted and is used to explain the geometry of molecules in organic and inorganic chemistry.

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The compound dibromobis(ethylenediamine)cobalt(III) sulfate, there are 3 individual ions per formula unit: one cobalt(III) complex ion [Co(en)2Br2]+3, one sulfate ion (SO4)^2-, and three water molecules as each formula unit contains three waters of hydration.

For Dibromobis(ethylcuediamine)cobalt(III) sulfate, the number of individual ions per formula unit and the coordination number of the metal ion are: - Number of individual ions per formula unit: There are a total of 6 ions per formula unit.

The compound has the following formula: [Co(ethylenediamine)2Br2]SO4. This means that there are two ethylenediamine ligands, each contributing 2 nitrogen atoms for a total of 4 nitrogen atoms.

Each nitrogen atom has a lone pair of electrons that can coordinate with the cobalt ion. There are also 2 bromide ions and 1 sulfate ion in the formula.

So, the total number of individual ions per formula unit is 4 nitrogen atoms + 2 bromide ions + 1 sulfate ion = 6 ions. - Coordination number of the metal ion: The metal ion in this compound is cobalt(III). Cobalt(III) has a coordination number of 6, which means that it can coordinate with 6 ligands. In this compound, there are 2 ethylenediamine ligands, each contributing 2 nitrogen atoms for a total of 4 nitrogen atoms.

The coordination number of the metal ion (cobalt) in this compound is 6, as there are two ethylenediamine (en) ligands, each with two nitrogen atoms coordinating to cobalt, and two bromine atoms also coordinating to cobalt (2x2 + 2 = 6).

The 4 nitrogen atoms coordinate with the cobalt ion, leaving 2 open coordination sites. These sites are occupied by the 2 bromide ions, giving a coordination number of 6 for the cobalt ion.

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Answer:

I think the answer is A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

Explanation:

I hope this helps.

Answer:

Physical change is the same substance, while a chemical change is a new substance.

i believe the answer is 2, good luck

Equations represents the law of conservation of mass is 2H₂O → 2H₂ + O₂

Law of conservation of mass stated that energy neither be created nor destroyed called as law of conservation of mass and as the same no of each atom present in the both side of the reaction this reaction represents the law of conservation of mass so in the equation 2H₂O → 2H₂ + O₂ the energy cannot be created nor destroyed water can form 2 mole of hydrogen and 1 mole of oxygen which form water

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Copper has an electron configuration of [Ar] 3d10 4s1. This means that its d shell is completely filled, while its s subshell contains only one electron. Due to the phenomenon known as the shielding effect, the electrons in the d shell are shielded from the nucleus by the electrons in the lower energy level (in this case, the filled s subshell).

This makes it harder for the electrons in the d shell to be removed, as they are held more tightly by the positive charge of the nucleus. On the other hand, the electron in the s subshell experiences less shielding and is more loosely bound to the atom. This is why copper more readily loses an electron from its s subshell. The stability of the atom is related to how easily it can lose or gain electrons, as this affects its reactivity and chemical behavior.

Copper easily loses an electron from its s subshell instead of its d shell due to its electron configuration. Copper has a configuration of [Ar] 3d10 4s1, with one electron in the 4s subshell and a filled 3d subshell. This arrangement provides increased stability for the atom. The 4s electron is at a higher energy level, making it easier to remove compared to a 3d electron. Moreover, the filled 3d subshell offers greater stability as it's a completely filled subshell. Hence, copper tends to lose an electron from the 4s subshell to achieve a stable configuration, resulting in a Cu+ ion.

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The correct answer is False. Recovery from drug addiction involves much more than just willpower to abstain from using the substance. It is a complex process that requires a combination of physical, emotional, and psychological interventions.

Willpower alone may not be enough to overcome the strong urges and cravings associated with drug addiction. Treatment often involves detoxification, counseling, support groups, and medication-assisted therapy. In addition, addressing underlying mental health issues and making lifestyle changes may be necessary for long-term recovery. It is important to seek professional help and support to effectively overcome drug addiction. This often includes psychological counseling, medical intervention, peer support, and behavioral therapies. A comprehensive treatment plan addresses the physical, emotional, and social aspects of addiction to promote long-lasting recovery.

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Answer:

Explanation:

The pressure required can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

Since we are finding the required pressure

\(P_2 = \frac{P_1V_1}{V_2} \\\)

From the question we have

\(P_2 = \frac{6 \times 1200}{200} = \frac{7200}{200} = \frac{72}{2} \\ \)

We have the final answer as

Hope this helps you

Answer:

SeCl6

this is the correct formula.

The correct formula for selenium hexachloride is SeCl₆.

What is selenium hexachloride

Selenium hexachloride is a compound composed of one selenium atom (Se) and six chlorine atoms (Cl). The prefix "hexa-" indicates that there are six chlorine atoms bonded to the selenium atom.

The chemical formula SeCl₆ represents the composition of selenium hexachloride, indicating that there are six chlorine atoms bonded to one selenium atom.

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The missing parts in the table is given below

An atom is composed of a centrally placed nucleus (containing protons and neutrons) and a cloud of electrons revolving round it.

Mass number (number of nucleon) = Proton + Neutron

Charge = Proton – Electron

i. Determination of the nucleon number

Nucleon number = Proton + Neutron

Nucleon number = 11 + 12

Nucleon number = 12

ii. Determination of the symbol

We'll begin by determining the charge of the particle. This is illustrated below:

Charge = Proton – Electron

Charge = 11 – 10

Charge = +1

From the periodic table, the element with proton number of 11 is sodium, Na. Since the particle B has a charge of +1, the symbol of particle of B is Na⁺

i. Determination of the number of electrons

Charge = Proton – Electron

–2 = 8 – Electron

Collect like terms

–2 – 8 = – Electron

– 10 = – Electron

Electron = 10

ii. Determination of the nucleon number

Nucleon number = Proton + Neutron

Nucleon number = 8 + 8

Nucleon number = 16

i. Determination of the number of protons

Charge = Proton – Electron

3 = Proton – 10

Collect like terms

3 + 10 = Proton

Proton = 13

ii. Determination of the number of neutrons

Nucleon number = Proton + Neutron

28 = 13 + Neutron

Collect like terms

28 – 13 = Neutron

Neutron = 15

Complete question

See attached photo

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Answer:The temperature of the water in both beakers is greater than 8 °C. in beaker B

Explanation:

in the lewis resonance structure for ammonium ion (nh4 ) in which the central n atom is singly bonded to each of the four h atoms on the n atom positive charge is present.

Ammonia is a colorless, intensely unpleasant gas with a pungent, choke-inducing smell. It readily dissolves in water to produce an ammonium hydroxide solution that can irritate the skin and burn. Ammonia gas is easily compressed and, when put under pressure, turns into a clear, colorless liquid.

The ammonia has normally three hydrogen attached to central nitrogen atom carrying lone pair. When fourth hydrogen attaches to the central atom positive charge appear on the central atom.

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Answer:

where is the questions........

Answer:Wavelength can be defined as the distance between two successive crests or troughs of a wave. It is measured in the direction of the wave. Description: Wavelength is the distance from one crest to another, or from one trough to another, of a wave (which may be an electromagnetic wave, a sound wave, or any other wave).

Answer:

3

Explanation:

the half life of a radioactive isotope is the amount of time one half of the isotope takes to decay

after 5 minutes the mass will be 24

after 10 minutes the mass will be 12

after 15 minutes the mass will be 6

after 20 minutes the mass will be 3

Answer:

Only the valence shell are shown in the Lewis electron dot structures because, the chemical reactivity of an atom of an element is determined by the valence electrons of the atom and not by all the electrons of the atom including the inner electrons.

Explanation:

Lewis electron dot structures are structures that show the bonding between atoms of a molecule, as well as the lone pairs of electrons that may exist in the molecule.

In the Lewis symbol for an atom, the chemical symbol of the element is written, and the valence electrons of the atom are represented as dots surrounding it. Only the electrons in the valence shell are shown using the Lewis electron dot structures.

Lewis structures for molecules show each atom and its position in the structure of the molecule using its chemical symbol. Dots or lines are drawn between atoms to show the electrons that are involved in the chemical bonding between the atoms in the molecule. Valence electrons in each atom that are not involved in bonding known as lone pairs, are represented as pairs of dots, and are placed next to each atom bearing the electron.

Electrons that are not in the valence level are not shown in the Lewis electron dot structures . This is because, the chemical reactivity of an atom of an element is determined by the valence electrons of the atom and not all the electrons of the atom including the inner electrons.

Answer:

covalent

Explanation:

option A is the correct one

It represents Mp orBp of a substance at a specific pressure

The percent of s character of the hybrid oxygen orbital in water is 25%.

The oxygen atom in water undergoes sp3 hybridization, which means that its three 2p orbitals and one 2s orbital combine to form four hybrid orbitals.

These hybrid orbitals are oriented towards the corners of a tetrahedron and have a mixture of s and p character.

The hybrid orbitals in water are often referred to as sp3 hybrid orbitals, which suggests that they have 25% s character and 75% p character.

However, this is an oversimplification, as the hybrid orbitals in water have a more complex wave function that cannot be described by a single percentage value.

The hybridization of the oxygen atom in water involves the combination of the 2s orbital and three 2p orbitals of the oxygen atom.

The resulting hybrid orbitals are called sp3 hybrid orbitals because they are made up of one s orbital and three p orbitals, which combine to form four hybrid orbitals that are oriented tetrahedrally around the oxygen atom.

The sp3 hybrid orbitals have a mixture of s and p character. This means that they are not purely s orbitals or purely p orbitals, but rather a combination of both.

The amount of s and p character in each hybrid orbital depends on the exact geometry of the molecule and the particular hybridization scheme.

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Answer:

184.113 g/mol

Explanation:  The atomic mass of Mg is 24.3 amu. The atomic mass of bromine is 79.9. Therefore, the formula weight of MgBr2 equals 24.3 amu + (2 × 79.9 amu), or 184.1 amu. Because a substance's molar mass has the same numerical value as its formula weight, the molar mass of MgBr2 equals 184.1 g/mol.

To determine whether a substance is acidic or basic using filter paper and a pH indicator, you can follow these steps:

Obtain a filter paper and moisten it with a small amount of the substance in question; Touch the filter paper with a pH indicator, such as litmus paper or universal indicator; Observe the color change of the pH indicator in contact with the substance; Compare the color change with the reference chart for the pH indicator being used to determine the pH of the substance.

If the substance turns the pH indicator blue, it is basic (alkaline) with a pH greater than 7. If the substance turns the pH indicator red, it is acidic with a pH less than 7. If the substance does not change the color of the pH indicator, it is neutral with a pH of 7.

Note: The pH scale ranges from 0 to 14, with 7 being neutral, less than 7 being acidic, and greater than 7 being basic.

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Answer:

valence electrons get closer but rest of them are remain same

Answer:

silicon

Explanation:

Carbon and silicon BOTH come from Group 14 of the Periodic Table , i.e. both formally have the same number of valence electrons, 4 such electrons

Answer:

silicon

Explanation:

Carbon and silicon both come from Group 14 of the Periodic Table

The volume of carbon dioxide gas produced at STP when 125 mL of a 0.10 M nitric acid solution reacts with excess calcium carbonate is 140 mL.

The balanced chemical equation for the reaction between nitric acid and calcium carbonate is:

2HNO3(aq) + CaCO3(s) → Ca(NO3)2(aq) + CO2(g) + H2O(l)

From the equation, we can see that 2 moles of nitric acid react with 1 mole of calcium carbonate to produce 1 mole of carbon dioxide gas.

To find the number of moles of nitric acid in 125 mL of a 0.10 M solution, we can use the formula:

moles = concentration x volume (in liters)

Converting the volume of the solution to liters:

125 mL = 0.125 L

Substituting the values into the formula:

moles of nitric acid = 0.10 M x 0.125 L = 0.0125 moles

Since 2 moles of nitric acid produce 1 mole of carbon dioxide gas, we can calculate the moles of carbon dioxide produced as:

moles of CO2 = 0.0125 moles of HNO3 ÷ 2 = 0.00625 moles

At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 L. Therefore, the volume of carbon dioxide gas produced at STP can be calculated as:

volume of CO2 = moles of CO2 x 22.4 L/mol = 0.00625 mol x 22.4 L/mol = 0.14 L or 140 mL (rounded to 2 significant figures)

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The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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