in a scalene triangle, one angle measures 50 degrees. what are the measures of the other two angles?

Taking into account the definition of a system of linear equations, the width has a value of 3.5 ft and the length has a value of 18 ft.

A system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.

Solving a system of equations consists of finding the value of each unknown, with which when replacing, they must give the solution proposed in both equations.

In this case, a system of linear equations must be proposed taking into account that:

You know:

So, the system of equations to be solved is

L= 11 + 2×W

63 = L× W

There are several methods to solve a system of equations, it is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.

In this case, substituting the first equation in the second you get:

63 = (11 + 2×W)× W

63= 11W + 2W²

0= -63 + 11W + 2W²

Being this a quadratic function of the form ax² + by +c, then it can be solved by: \(W1,W2= \frac{-b+-\sqrt{b^{2} -4ac} }{2a}\)

In this case, being a=2, b=11 and c= -63, the equation is solved by:

\(W1= \frac{-11+\sqrt{11^{2} -4x2x(-63)} }{2x2}\)

\(W1= \frac{-11+\sqrt{625} }{4}\)

\(W1= \frac{-11+25 }{4}\)

\(W1= \frac{14 }{4}\)

W1= 3.5

and

\(W2= \frac{-11-\sqrt{11^{2} -4x2x(-63)} }{2x2}\)

\(W2= \frac{-11-\sqrt{625} }{4}\)

\(W2= \frac{-11-25}{4}\)

\(W2= \frac{-36}{4}\)

W2= -9

Since the width cannot be a negative value, its value is 3.5 ft. Remembering that L= 11 + 2×W, then:

L= 11 + 2×3.5

L= 11 + 7

L= 18

Finally, the value of the length is 18 ft.

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The probability that each face appears at least once in seven throws of the six-sided die is :

P(each face appears at least once) = (6^7 - 6 * 5^7) / 6^7

For the probability that each face of a six-sided die appears at least once in seven throws, we can use the principle of inclusion-exclusion.

Let's calculate the total number of outcomes first. In each throw, there are 6 possible outcomes (one for each face of the die), so the total number of outcomes in seven throws is 6^7.

Now, let's calculate the number of outcomes where at least one face does not appear. We can do this by considering each face individually.

For any given face, there are 5 possibilities (the other five faces) in each throw. Therefore, the number of outcomes where a particular face does not appear in any of the throws is 5^7.

However, since there are six faces, we need to subtract the number of outcomes where each of the six faces does not appear. Therefore, we calculate 6 * 5^7.

Finally, we can calculate the probability of each face appearing at least once by subtracting the number of outcomes where at least one face does not appear from the total number of outcomes, and dividing by the total number of outcomes:

P(each face appears at least once) = (6^7 - 6 * 5^7) / 6^7

This will give you the probability that each face appears at least once in seven throws of the six-sided die.

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Answer: 38 Bags

Step-by-step explanation:

Since there are 19 people and each person needs 24 beads, the total number of beads needed is 19*24=456. Then if this total must be split up into groups of 12 beads, the answer would be 456/12=38.

Answer:

Option 4

Step-by-step explanation:

In this particular data set, 10 is the only value that occurs more than once, so it is the only mode

The mode is the value that occurs most frequently in a data set. In the given data set {10, 30, 10, 36, 26, 22}, we can see that the value 10 occurs twice, and all other values occur only once. Therefore, the mode of the data set is 10, since it occurs more frequently than any other value in the set.

Note that a data set can have multiple modes if two or more values occur with the same highest frequency. However, in this particular data set, 10 is the only value that occurs more than once, so it is the only mode.

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Answer:

-1

Step-by-step explanation:

-15-2(-7)

-15+2·7

-15+14

-1

By the finance the cost of two plans is  $202.50

what is finance?

Raising capital or funds for any kind of expenditure is referred to as finance. It is the process of directing different funds—whether they be in the form of invested capital, loans, or credit—to the economic entities that can use them most effectively or who are in the greatest need of them.

solution;

x = number of miles driven

y = total cost

First Plan:

If you drive 1 mile, then you are charged $0.70

y = 0.70x+45 for the first plan.

Second Plan:

There are no initial costs, but the cost per mile is higher.

y = 0.90x

Since y is equal to both 0.70x+45 and 0.90x,

for solve for x

0.90x = 0.70x+45

0.90x-0.70x = 45

0.20x = 45

x = 45/0.20

x = 225

The two plans cost the same when you drive exactly 225 miles.

y = 0.70x+45 = 0.70*225+45 = 202.50

You only need to pick on one equation, but doing both helps show that x = 225 leads to the same y value

The plans cost the same when you drive 225 miles.

Therefore, The cost is $202.50 when the plans cost the same.

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Step-by-step explanation:

Hope it helped

Pls mark BRAINLIEST

Answer:

is 4

Step-by-step explanation add

There are 2520 ways to seat 8 people around a circular table where two seatings are considered the same when everyone has the same two neighbors without regard to whether they are right or left neighbors.

There are a total of seven different ways for eight individuals to sit around a circular table: (8-1)!=7!. We are using the concept of circular permutation.

By using circular permutation we have,

7!=5040

All of the seating is included in these 5040 ways. Given that everyone has the same two neighbors, regardless of whether they are left or right neighbors, two seating are said to be equal. To achieve the desired outcomes, we must divide the total number of methods by 2.

5040/2

=2520 ways

Therefore, there are 2520 ways to seat 8 people around circular table where two seating are considered the same.

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A partial fraction calculator is a tool used to decompose a rational function into simpler fractions, known as partial fractions.

A partial fraction calculator is a tool used to decompose a rational function into simpler fractions. It is commonly used in algebra and calculus to simplify complex expressions and solve equations. The partial fraction calculator takes a rational function as input and breaks it down into simpler fractions that can be more easily integrated or manipulated. This process involves finding the partial fraction decomposition of the rational function by factoring the denominator into linear and quadratic factors and then solving for the coefficients of the partial fractions. This calculator can be useful for students, engineers, and anyone working with complex algebraic expressions.

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The entry to record the purchase will include: a debit to Supplies and a credit to Accounts Payable

Now, given: Purchased supplies = $500 (on account).

To find: What does entry to record the purchase include?

Now,

Hence, the entry to record the purchase will include: a debit to Supplies and a credit to Accounts Payable.

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The size of XYZ in the triangle based on the application of trigonometry ratio is 66.4°.

Based on the information given, it should be noted that we can apply trigonometry to solve the triangle.

In this case, the hypothenuse is 15cm and the adjacent is 6cm. The trigonometry ratio will be:

cos = adjacent / hypothenuse.

cos x = 6 / 15

cos x = 0.4

x will be the inverse cos to find the value. This will be 66.4°.

Therefore, the angle is 66.4°.

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Answer:

-1/6

Step-by-step explanation:

I looked it up

A scatter plot chart of stock returns versus past stock returns will typically appear as a random pattern mostly concentrated in the top-right and lower-left quadrants.

This pattern indicates that there is a positive correlation between past and current stock returns, but there are also instances where current returns are negative despite past positive returns.

The top-right quadrant represents instances where both past and current returns are positive, while the lower-left quadrant represents instances where both past and current returns are negative.

The random pattern indicates that stock returns cannot be predicted with certainty based on past returns alone.

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From the given options, the rational number that does not lie between 2/5 and 3/4 is option (d) 9/20.

We need to discover a number that is either smaller than 2/5 or greater than 3/4 in order to find a rational number that does not fall between these two numbers.

Let's contrast each choice with the range provided:

a. 17/20 does not fall between 2/5 and 3/4 because it is more than 3/4.

b. 13/20: This number falls inside the provided range and is not the solution we are seeking for because it is larger than 2/5 but smaller than 3/4.

c. 11/20: This number falls inside the provided range and is not the solution we are seeking for because it is larger than 2/5 but smaller than 3/4.

d. 9/20: Because this number is less than 2/5, it does not fall within the range.

From the given options, the rational number that does not lie between 2/5 and 3/4 is option (d) 9/20.

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Complete question =

Choose a rational number which does not lie between 2/5 and3/4.

a.17/20

b.13/20

c.11/20

d.9/20​

Answer:35x + 1.5

Step-by-step explanation:

The power series for the function\(f(x) = 8/(3x^2)\), centered at c = 5, is \(8/75 - 16/375(x-5) + 48/9375(x-5)^2 - 64/78125(x-5)^3 + ...\)

To find the power series for the function \(f(x) = 8/(3x^2)\)centered at c = 5, we can use the formula for the Maclaurin series:

\($f(x) = f(c) + \frac{f'(c)}{1!}(x-c) + \frac{f''(c)}{2!}(x-c)^2 + \frac{f'''(c)}{3!}(x-c)^3 + ...$\)

First, we need to find the derivatives of f(x):

\(f(x) = 8/(3x^2)\)

\(f'(x) = -16/(3x^3)\)

\(f''(x) = 48/(3x^4)\)

\(f'''(x) = -192/(3x^5)\)

Next, we evaluate these derivatives at c = 5:

\(f(5) = 8/(35^2) = 8/75\)

\(f'(5) = -16/(35^3) = -16/375\)

\(f''(5) = 48/(35^4) = 48/9375\)

\(f'''(5) = -192/(35^5) = -64/78125\)

Plugging these values into the formula, we get:

\(f(x) = 8/75 - 16/375(x-5) + 48/9375(x-5)^2 - 64/78125(x-5)^3 + ...\)

This is the power series for f(x) centered at c = 5.

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Answer:

x = -2

Step-by-step explanation:

2(4 - 3x) = 20

8 - 6x = 20

-8          -8

-6x = 12

÷-6    -6

x = -2

I hope this helps!

Answer:

14.3%

Step-by-step explanation:

subtract 320 with 280 which is 40. divide 40 with 280 and multiply that will 100. You get 14.3%

Answer:

14.28 %

Step-by-step explanation:

cost price of an umbrella = 280

selling price of an umbrella = 320

profit% = SP - CP / CP *100%

=320 - 280/280 * 100

=40/280 * 100

=4000/280

=14.28

II. Firms may utilize databases other than relational databases.

III. In mapping an E-R diagram to a set of tables in a relational database, only the entities in the E-R diagram are mapped to tables in the database.

II. The statement that firms may utilize databases other than relational databases is true. While relational databases are widely used, there are other types of databases available, such as hierarchical databases, network databases, and object-oriented databases. Each type has its own characteristics and may be suitable for different purposes or specific requirements of an organization.

III. The statement that, in mapping an E-R diagram to a set of tables in a relational database, only the entities in the E-R diagram are mapped to tables in the database is also true. In the entity-relationship (E-R) model, entities represent objects or concepts in the real world, and relationships define the associations between entities. When designing a relational database based on an E-R diagram, the entities are typically mapped to tables, and the relationships are represented through foreign keys and join operations between tables. Other elements, such as attributes and keys, are also considered in the mapping process, but not all of them are necessarily represented as separate tables.

IV. The statement that each attribute of an entity is given a separate table in the mapping of an E-R diagram to a set of tables in a relational database is not true. In a relational database, attributes are typically represented as columns within a table, where each row represents a record or instance of the entity. Attributes are not given separate tables, but rather they contribute to the structure and content of the table associated with the entity.

Therefore, the correct statements are II and III.

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Answer:

Step-by-step explanation:

 Allegro is Italian for ‘lively’ or ‘cheerful’ and it’s a term used on musical scores to indicate that the piece should be played at a relatively fast pace and in a bright and merry manner. It’s a similar term to vivace, which also means ‘lively’.

Different tempos are measured in beats per minute (BPM), and allegro is typically marked on a metronome as having between 120-168 BPM. This is slightly faster than allegretto (moderately fast), which itself is a little faster than moderato (moderate or medium).

Answer:fast, quickly and bright

Step-by-step explanation: Allegro – fast, quickly and bright (109–132 BPM) Vivace – lively and fast (132–140 BPM) Presto – extremely fast (168–177 BPM) Prestissimo – even faster than Presto (178 BPM and over)

Answer:

b/w 19 & 55

Step-by-step explanation:

average of four equally weighted 100-point tests,

mark has scored 90, 86, and 85 on the first three.

C average = 70 and 79

90+86+85+x = 4*70 = 280, so x=19

90+86+85+x = 4*79 = 316, so x=55

Answer:

linear

Step-by-step explanation:

its is linear I know this for a fact I had this same question

Answer:

the correct answer is B

Step-by-step explanation:

Answer:

the second choise is the answer

Answer: Two concentric circles have radii $1$ and $2$. Two points on the outer circle are chosen independently and uniformly at random. What is the probability that the chord joining the two points intersects the inner circle?

$\textbf{(A)}\ \frac{1}{6}\qquad \textbf{(B)}\ \frac{1}{4}\qquad \textbf{(C)}\ \frac{2-\sqrt{2}}{2}\qquad \textbf{(D)}\ \frac{1}{3}\qquad \textbf{(E)}\ \frac{1}{2}\qquad$

Solution

Let the center of the two circles be $O$. Now pick an arbitrary point $A$ on the boundary of the circle with radius $2$. We want to find the range of possible places for the second point, $A'$, such that $AA'$ passes through the circle of radius $1$. To do this, first draw the tangents from $A$ to the circle of radius $1$. Let the intersection points of the tangents (when extended) with circle of radius $2$ be $B$ and $C$. Let $H$ be the foot of the altitude from $O$ to $\overline{BC}$. Then we have the following diagram.

[asy] scale(200); pair A,O,B,C,H; A = (0,1); O = (0,0); B = (-.866,-.5); C = (.866,-.5); H = (0, -.5); draw(A--C--cycle); draw(A--O--cycle); draw(O--C--cycle); draw(O--H,dashed+linewidth(.7)); draw(A--B--cycle); draw(B--C--cycle); draw(O--B--cycle); dot("$A$",A,N); dot("$O$",O,NW); dot("$B$",B,W); dot("$C$",C,E); dot("$H$",H,S); label("$2$",O--(-.7,-.385),N); label("$1$",O--H,E); draw(circle(O,.5)); draw(circle(O,1)); [/asy]

We want to find $\angle BOC$, as the range of desired points $A'$ is the set of points on minor arc $\overarc{BC}$. This is because $B$ and $C$ are part of the tangents, which "set the boundaries" for $A'$. Since $OH = 1$ and $OB = 2$ as shown in the diagram, $\triangle OHB$ is a $30-60-90$ triangle with $\angle BOH = 60^\circ$. Thus, $\angle BOC = 120^\circ$, and the probability $A'$ lies on the minor arc $\overarc{BC}$ is thus $\dfrac{120}{360} = \boxed{\textbf{(D)}\: \dfrac13}$.

See Also

We know that the expression for the population is given by:

We want to know how long it takes to increase the population from 10500 to 13650. This means that we need to find the time it takes for the population to increase 3150; since this does not depends on the initial population but just in the exponential rate we have:

Therefore, it will take 537.01 years to increase the population.