In a laboratory experiment, a chemist prepared different concentrations of solution with a light absorbing solute and measured the absorbance of each solution. In the absorbance measurements, the solutions were placed in sample holders where light propagates through 5.00 cm of sample. So, the length, I, equals 5.00 cm in all these measurements. The following data is collected:
Concentration: 0, Absorbance : 0: Concentration: 0,102; Abs: 0,0089
Concentration : 0.249 Abs: 0.0205
Concentration: 0.502 Abs: 0.0463
Concentration: 0.748 Abs: 0.0641
Concentration: 1.052 Abs: 0.0903
Concentration: 1.485 Abs: 0.1335
a- Which variable is the independent variable?
b- Which variable is the dependent variable?
c- Using Excel, make a plot of the data with the appropriate variables as x and y. Using the linear regression analysis of the plotting program, determine the best-fit slope and y-intercept of the data. Be sure to include units!

Answers

Answer 1

a- The independent variable is the concentration of the solution, b- The dependent variable is the absorbance of the solution.

c- In Excel, the concentration data can be entered in one column and the absorbance data in another column. The concentration data would be plotted on the x-axis and the absorbance data would be plotted on the y-axis. By selecting the option for linear regression b, the best-fit slope and y-intercept can be determined.

For example, if the best-fit slope is 0.2 L/mol and the y-intercept is 0.05, the equation for the best-fit line would be y = 0.2x + 0.05, where y is the absorbance and x is the concentration in mol/L. The units for the slope would be absorbance per concentration (L/mol) and the units for the y-intercept would be absorbance (L). These values represent the relationship between the concentration of the solution and its absorbance, with the slope indicating how absorbance changes with increasing concentration.

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Related Questions

the male and female sex cells combine to form a

Answers

Answer:

zygote

Explanation:

In human beings, each gamete contains 23 chromosomes, half the number found in the other cells of the body. When the male and female gametes fuse, they become a zygote containing the full 46 chromosomes, half of which came from the father and half from the mother.

Answer:

zygote

Explanation:

In human beings, each gamete contains 23 chromosomes, half the number found in the other cells of the body. When the male and female gametes fuse, they become a zygote containing the full 46 chromosomes, half of which came from the father and half from the mother.

What are some properties that can be used to describe a solid, liquid and gas?

Answers

Answer:

Solids have a defined shape and volume.

Liquids have a definite volume but can take the shape of a container.

Gas has no definite volume or shape.

Answer:

See Explanation for more details...

Explanation:

Solid: defined form, minimal potential energy, it is not compressible, defined mass.

Liquid: No defined form, has more potential energy than the solids, it is not compressible, defined mass.

Gas: No defined form, high potential energy, it is compressible, defined mass.

Use the atomic masses of the elements to determine the percent composition by mass of sodium and chlorine in sodium chloride.

Answers

Answer:

Explanation:

Percent composition of sodium chloride .

NaCl

Mol weight = 23 + 35.5 = 58.5 g

58.5 g of NaCl contains 23 g of Na

100 g of NaCl contains 23 x 100 / 58.5 g of Na

= 39.3 %

Na = 39.3 %

58.5 g of NaCl contains 35.5  g of Cl

100 g of NaCl contains 35.5 x 100 / 58.5 g of Na

= 60.7 %

Cl = 60.7 % .

Determine the equilibrium constant, K, for the equilibrium below given the
equilibrium constants of the other equilibria under the same temperature.
CO(g) + H2O(g) = CO2(g) + H2(g)
h
K7 = ?
2H2(g) + O2(g) = 2H2009)
K2 = 1.22
200(g) + O2(g) = 2C02(g)
Kz = 5.39
= =
Pls help

Answers

Answer:

or reactions that are not at equilibrium, we can write a similar expression called the reaction quotient QQQ, which is equal to K_\text cK

c

K, start subscript, start text, c, end text, end subscript at equilibrium.

Explanation:

Jane is sitting in the family car. Her mother is driving her from their house to the library. Jane waves as she passes her friend Marina. Which of the following is not moving with respect to Jane?
A. Marina
B. The family car
C.The library
D. Jane’s house

Answers

Answer:

B) The family car

Explanation:

I hope this helps :)

a gas has an initial volume of 3,480 mL and an initial temperature of - 70.0 C. what must be the temperature of the gas in kelvin if its volume is reduced to 2,450 mL

Answers

The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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Ayuda plissss es para hoy

Ayuda plissss es para hoy

Answers

alimientos procesados:

cereales, queso ,verduras enlatadas, un pan bocadillos salados, como patatas fritas, panecillos de salchicha, tartas y empanadas productos cárnicos, como tocino, salchicha, jamón, salami y paté comidas para microondas o comidas preparadas pasteles y galletas bebidas, como leche o refrescos

alimientos naturales

1. Pescado · 2. Brócoli o cualquiera de las verduras crucíferas · 3. Remolacha · 4. Espinacas y otras verduras de hoja verde · 5. Col rizada · 6. Mantequilla de maní · 7. Almendras.pechugas de pollo, Cordero, Salmón, Camarón,Aceite de coco,Nueces y semillas

Answer:

what

Explanation:

PLEASE HELP GUYS

Express in moles:
a) 6.02.10²2 C₂H₂ molecules
b) 1.80-1024 nitrogen atoms
c) 3.01·10²³ NH3 molecules.

What is
the molar mass of these substances?

Answers

Answer:

expressed in moles

a)0.1 moles

b)2.99 moles

c)0.5 moles

molarmass of the substances

a)26g/mol

b)14g/mol

c)17g/mol

Explanation:

remember

1mole=6.02×10^23molecules

The expressions in moles are:

A) 0.1 moles for C₂H₂ molecules, B) 2.99 moles for nitrogen atomsC) 0.5 moles for NH3 molecules.

The molar masses of the substances are:

A) 26 g/mol for C₂H₂B) 14 g/mol for nitrogen atomsC) 17 g/mol for NH3

In more detail, the number of particles in a substance can be expressed in terms of moles. A mole is defined as the number of particles in a substance that contains Avogadro's number of particles, which is 6.02 x 10²³. To convert the number of particles in a substance to moles, we divide the number of particles by Avogadro's number.

The molar mass of a substance is the mass of one mole of the substance, expressed in grams. The molar mass of a substance can be calculated by summing up the atomic masses of all the atoms in the substance.

The Rationale For Expressions in Moles

A) 6.02 x 10²² C₂H₂ molecules:

1 mole = 6.02 x 10²² particles

0.1 moles = (6.02 x 10²² particles) / (6.02 x 10²³ particles/mole) = 6.02 x 10²² particles / 6.02 x 10²³ particles/mole = 1 mole / 6.02 x 10²³ = 0.1 moles

B) 1.80 x 10¯¹⁰²⁴ nitrogen atoms:

1 mole = 6.02 x 10²³ particles

2.99 moles = 1.80 x 10¯¹⁰²⁴ particles / (6.02 x 10²³ particles/mole) = 1.80 x 10¯¹⁰²⁴ particles / 6.02 x 10²³ particles/mole = 2.99 moles

c) 3.01 x 10²³ NH3 molecules

1 mole = 6.02 x 10²³ particles

0.5 moles = 3.01 x 10²³ particles / (6.02 x 10²³ particles/mole) = 3.01 x 10²³ particles / 6.02 x 10²³ particles/mole = 0.5 moles

The Rationale For the Molar Mass

The molar mass of C₂H₂ is calculated by summing up the atomic masses of carbon (12 g/mol) and hydrogen (1 g/mol) in the molecule.

C₂H₂: 12 g/mol + 12 g/mol + 1 g/mol + 1 g/mol = 26 g/mol

The molar mass of nitrogen is calculated based on the atomic mass of nitrogen (14 g/mol).

N: 14 g/mol

The molar mass of NH3 is calculated by summing up the atomic masses of nitrogen (14 g/mol), and hydrogen (1 g/mol) in the molecule.

NH3: 14 g/mol + 1 g/mol + 1 g/mol + 1 g/mol = 17 g/mol

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Why does CO2 have a higher boiling point than CH4 when they both possess dispersion forces?

Answers

CO₂ have a higher boiling point than CH₄ when they both possess dispersion forces because CO₂ consists of polar bonds between carbon and oxygen.

Intermolecular forces determine bulk properties, such as the melting points of solids and the boiling points of liquids.

Liquids boil when the molecules have enough thermal energy to overcome the intermolecular attractive forces that hold them together, thereby forming bubbles of vapor within the liquid.

CO₂ have a higher boiling point than CH₄ when they both possess dispersion forces because CO₂ consists of polar bonds between carbon and oxygen. The polarity increases the boiling point of the molecule.

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What mass of Fe(OH)3 will be obtained when 100. mL of 0.240 M FeCl3 is mixed with 200. mL of 0.182 M NaOH?

Answers

Answer:

648.68 mg

Explanation:

The reaction that takes place is:

FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

First we calculate how many moles of each reactant were added, using the given volumes and concentrations:

FeCl₃ ⇒ 100 mL * 0.240 M = 24 mmol FeCl₃NaOH ⇒ 100 mL * 0.182 M = 18.2 mmol NaOH

24 mmol of FeCl₃ would react completely with (24 * 3) 72 mmol of NaOH. There are not as many NaOH mmoles, so NaOH is the limiting reactant.

Now we calculate how many moles of Fe(OH)₃ are formed, using the moles of the limiting reactant:

18.2 mmol NaOH * \(\frac{1mmolFe(OH)_3}{3mmolNaOH}\) = 6.07 mmol Fe(OH)₃

Finally we convert 6.07 mmol Fe(OH)₃ to grams, using its molar mass:

6.07 mmol Fe(OH)₃ * 106.867 mg/mmol = 648.68 mg

The 129.6 g mass of Fe(OH)₃ will be obtained.

How we calculate mass or weight from moles?

Weight or mass of any substance can be calculated from mole as:

n = W/M.

Given chemical reaction is:

FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

According to the question:

Concentration of FeCl₃ = 0.240 M

Volume of FeCl₃ = 100 mL

Concentration of NaOH = 0.182 M

Volume of NaOH = 200 mL

Moles can be calculated by using the formula M = n/V mole/L 0r M = n×1000/V g/mL,

Moles of FeCl₃ = 0.240 × 100 = 0.024 mole

Moles of NaOH = 0.182 × 200 = 3.64 mole

From the stoichiometry of the reaction, it is clear that 3 mole of NaOH i.e. 109.2 moles of NaOH reacts with 1 mole of FeCl₃ to form product. So here NaOH is the limiting agent and responsible for the formation of product. Now we calculate how many moles of Fe(OH)₃ are formed, using the moles of the limiting reactant as follow:

Moles of Fe(OH)₃ = 1/3 × ( 3.64) = 1.21 mole

Finally we convert 12.1 mole Fe(OH)₃ to grams, using its molar mass:

W = 1.21 mole × 106.87 g/mole = 129.6 g

Hence, 129.6 gram of Fe(OH)₃ will be obtained.

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Is table salt a mixture ?


True

False

Answers

Answer:

True

Explanation:

Table sugar and table salt are pure substances....When elements chemically combine, they form compounds that have properties that are similar to those of the uncombined elements.

Molecules have ?

: A) both potential and kinetic energy. B) only kinetic energy. C) only potential energy. D) neither kinetic nor potential energy.

Answers

Answer:

C) only potential energy.

The pOH of a solution is 6.0. Which statement is correct?
Use pOH = -log[OH-] and PH+pOH = 14.
The pH of the solution is 20.0.
O The concentration of OH ions is 1.0 x 108 M.
The concentration of OH ions is 1.0 x 106 M.
O The pH of the solution is 8.0.
A

Answers

At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

those questions in pictures

those questions in pictures

Answers

For this section:

The acids that would be completely dissociated when dissolved in water are A, (H O)₂SO and B, (H O)IO₃.(i) pH of 7(ii) pH of 4.763I₂ + 2PBr₃ → 6IBr + P₂4LiH + GaCl₃ → 4LiCl + GaH₃NH₃ + BCl₃ → NH₃BCl₃

How to determine pH and products?

(d) To determine which acid would be completely dissociated when dissolved in water, consider the strength of the acid and its ability to ionize completely. Strong acids are those that ionize completely in water, while weak acids only partially dissociate.

Among the given options:

(H O)₂SO is sulfuric acid (H₂SO₄), which is a strong acid and completely dissociates in water.

(H O)IO₃ is iodic acid (HIO₃), which is also a strong acid and completely dissociates in water.

(H O)₂SO₂ is not a known acid and cannot be evaluated for dissociation.

HCO₂H is formic acid (HCOOH), which is a weak acid and only partially dissociates in water.

Therefore, the acids that would be completely dissociated when dissolved in water are (H O)₂SO and (H O)IO₃.

(e) To estimate the pH of the given solutions formed by titration, compare the moles of the acid and base used in the reaction.

(i) For the titration of 25.0 mL of 0.10 M aqueous NaOH with 25.0 mL of 0.10 M aqueous HCl, the reaction between a strong acid (HCl) and a strong base (NaOH) forms a neutral salt (NaCl) and water. The resulting solution would have a pH of 7, indicating neutrality.

(ii) For the titration of 25.0 mL of 0.10 M aqueous NaOH with 25.0 mL of 0.10 M aqueous acetic acid, consider the ionization of acetic acid and the formation of its conjugate base. The pKa of acetic acid is given as 4.76.

Since the volumes and concentrations of the acid and base are equal, we have a 1:1 mole ratio between them. This means that half of the acetic acid will be neutralized, and the remaining half will be in the form of the conjugate base (acetate ion, CH₃COO-). The resulting solution will be a buffer solution with a pH close to the pKa of acetic acid, which is 4.76.

(f) To predict the products formed from mixing the given reagents, we need to consider the reactions and the possible chemical reactions that occur.

(i) 3I₂ + PBr₃: This reaction involves the combination of iodine (I₂) with phosphorus tribromide (PBr₃). The balanced equation is:

3I₂ + 2PBr₃ → 6IBr + P₂

(ii) 4LiH + GaCl₃: This reaction involves the combination of lithium hydride (LiH) with gallium trichloride (GaCl₃). The balanced equation is:

4LiH + GaCl₃ → 4LiCl + GaH₃

(iii) NH₃ + BCl₃: This reaction involves the combination of ammonia (NH₃) with boron trichloride (BCl₃). The balanced equation is:

NH₃ + BCl₃ → NH₃BCl₃

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A solution with a pH of 8 is?

Answers

Answer:base

Explanation:

base

A solution with a pH of 8 is basic in nature.

pH is defined as the negative logarithm of H⁺ ion concentration.

pH is a measure of how acidic or basic a substance is. In our everyday routine, we encounter and drink many liquids with different pH. Water is a neutral substance. Soda and coffee are often acidic.

The pH is an important property, since it affects how substances interact with one another and with our bodies. In our lakes and oceans, pH determines what creatures are able to survive in the water.

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The density of Silver is 10.5 g/mL. How much mass would be present given a silver cube
with a volume of 25.0 mL?


PLEASE HELP ASAP

Answers

Answer:

m=dxv

= 10.5 x 965 = 10132.5 rounded off to 10100 g

Explanation:

The following balanced equation shows the formation of ammonia.

N2 + 3H2 Right arrow. 2NH3

How many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen?

Answers

Answer:

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

The chemical reaction for the formation of ammonia by nitrogen and hydrogen reaction has been as follows:

For the formation of 2 moles of ammonia, 3 moles of hydrogen, and 1 mole of nitrogen s required.

The utilization of 3 moles of hydrogen requires 1 mole of Nitrogen.

So, the utilization of 6.34 moles of hydrogen requires:

3 moles Hydrogen = 1 -mole Nitrogen

6.34 moles hydrogen =  moles of Nitrogen

6.34 moles of hydrogen requires = 2.11 moles of Nitrogen.

For completely converting 6.34 moles of hydrogen to ammonia, 2.11 moles of Nitrogen is required.

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Answer rating5.0

(20 votes)

How many mg of water are present in a 500. mg sample of 2.9 m/m% solution?

Report your answer to 3 significant figures and without units.

Answers


The answer is 14.5 mg.

To solve the problem, we need to first understand what a 2.9 m/m% solution means. "m/m%" stands for mass per mass percentage, which indicates the mass of the solute (in this case, water) divided by the total mass of the solution (water + solvent, which is not specified). Therefore, a 2.9 m/m% solution means that for every 100 grams of the solution, 2.9 grams are water.

To find the amount of water present in a 500 mg sample of this solution, we can set up a proportion:

2.9 g water/100 g solution = x g water/500 mg solution

Simplifying this proportion by converting units to milligrams, we get:

2.9 mg water/100 mg solution = x mg water/500 mg solution

Cross-multiplying and solving for x, we get:

x = 14.5 mg

Therefore, there are 14.5 mg of water present in a 500 mg sample of 2.9 m/m% solution.

A 3.0 L container holds 1.8 moles of a gas, what will the container expand to when it holds 2.4 moles of the same gas?

Answers

The container will expand to 4.0 L when it holds 2.4 moles of the same gas.

To answer your question, we will use the concept of Avogadro's law, which states that the volume of a gas is directly proportional to the number of moles (n) of the gas when the temperature and pressure remain constant.

Mathematically, it can be represented as:
V1/n1 = V2/n2

where,

V1 and n1 = initial volume and moles of the gas

V2 and n2 = final volume and moles of the gas

Given the initial conditions,

V1 = 3.0 L

n1 = 1.8 moles

The final condition,

n2 = 2.4 moles.

To find V2, Using the given values and rearranging the formula, we have:

V2 = V1 * (n2/n1)

V2 = 3.0 L * (2.4 moles / 1.8 moles)

V2 = 3.0 L * (1.3333)

V2 = 4.0 L

So, when the container holds 2.4 moles of the same gas, it will expand to a volume of 4.0 L. This is because the number of moles of the gas has increased, and according to Avogadro's law, the volume must also increase proportionally to maintain a constant temperature and pressure.

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A scientist claimed that he radiocarbon dated a fossilized skull of a dinosaur and found it to be about 63 million years old. Do you support his claim? Provide at least one scientifically based reason why you do or do not support the claim.

Answers

Answer:Since dinosaurs are thought to be over 65 million years old, the news is stunning - and more than some could tolerate.  After the AOGS-AGU conference in Singapore, the abstract was removed from the conference website by two chairmen because they could not accept the findings.  Unwilling to challenge the data openly, they erased the report from public view without a word to the authors.  When the authors inquired, they received this letter:

Explanation:

i do not own my copyrights


If you add 25 g of CaCl2 to 1000. mL of water, what would the concentration of the solution be in grams/liter?

Answers

If you add 25 g of CaCl2 to 1000. mL of water, what concentration of the solution would be 0. 225 grams/liter

What is molarity?

Molarity or molar concentration(M) is defined as the  amount of a substance in a given volume of solution.

It is also known as the moles of a solute in a liter of  the solution.

How to determine the concentration

Formula:

Concentration or molarity = number of moles ÷ volume

The number of moles is derived thus;

Number of moles = mass ÷ molar mass

mass of CaCl2 = 25g and molar mass = 110. 98 g/mol

Number of moles = 25 ÷ 110. 98 = 0. 225 mol

Given the volume = 1000 ml = 1 liter

Concentration = 0.225 ÷ 1 = 0. 225 grams/liter

Therefore, If you add 25 g of CaCl2 to 1000. mL of water, the concentration of the solution would be 0. 225 grams/liter

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A 0.15M solution of methylamine CH3NH2 contains an unknown concentration of methylamine chloride CH3NH3Cl. If the solution has a pH of10.20,what is the concentration of methylamine chloride in the solution? Kb for methylamine =4.6*10^-4f

Answers

The concentration of the methylamine chloride is 0.0000013 M.

What is the concentration of methylamine chloride in the solution?

We know that the concentration has to do with the amount of the substance that is present. Hence, the question is essentially trying to ask us to be able to find the  the concentration of methylamine chloride in the solution.

[H^+] = Antilog(-0.20) = 0.63 M

Ka = 1 * 10^-14/4.6*10^-4 = 2.22 * 10^-11

Let us first set up the ICE table as shown below;

            CH3NH2(aq)    +  H^+  ⇄  CH3NH3^+(aq)   + OH^-(aq)

I               0.15                   0.63         0                         0                      

C              -x                      -x              +x                        +x

E         0.15 - x                0.63 -x        x                          x

Ka = [CH3NH3^+] [OH^-]/[CH3NH2] [H^+]

2.22 * 10^-11= x^2/[0.15 - x] [0.63 -x ]

2.22 * 10^-11(0.09 -0.15x - 0.63x + x^2) = x^2

2.22 * 10^-11(0.09 - 0.48x +x^2) = x^2

1.9 * 10^-12 - 1.1 * 10^-11x + 2.22 * 10^-11x^2 = x^2

x^2 - 2.22 * 10^-11x^2 +  1.1 * 10^-11x  - 1.9 * 10^-12  = 0

x^2 +  1.1 * 10^-11x  - 1.9 * 10^-12  = 0

x =0.0000013 M

Concentration of the methylamine chloride = 0.0000013 M

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The electron was the first subatomic particle that was discovered (by Thomson.) Describe the evidence that was used to support the discovery of the electron. In your answer, explain why it was assumed that electrons exist within atoms instead of being created during the experiment

Answers

Answer:

j.j. thomasons experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons .

Explanation:

Thomson’s experiment with the cathode ray tube (CRT) was used to support the discovery of electron or the negatively charged subatomic particle.

What is Thomson’s Model of an atom?

William Thomson put forth the Thomson atomic model in 1900. J.J. In a cathode ray tube experiment, Thomson discovered a negatively charged particle. In 1897, this experiment was conducted. A vacuum tube is known as a cathode ray tube. The electron was the name given to the negative particle.

Thomson believed that each atom is composed of millions of electrons and assumed that an electron is 2,000 times lighter than a proton. He took into account atoms surrounded by a cloud that had both positive and negative charges in his concept of the atomic structure.He and Rutherford also performed the X-ray demonstration of the ionisation of air. They were the ones who initially showed it. In Thomson's model, the atom looks like plum pudding.

Hence, according to Thomson’s model of an atom, atoms are electrically neutral and an atom contains negatively charged particles known as electrons.

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 The electron was the first subatomic particle that was discovered (by Thomson.) Describe the evidence

15.0 L of an ideal gas at 298 K and 3.36 bar are heated to 350 K with a new pressure of 4.40 atm. What is the new volume in litres?

Answers

Answer:

13.3 L

Explanation:

Step 1: Given data

Initial pressure (P₁): 3.36 barInitial volume (V₁): 15.0 LInitial temperature (T₁): 298 KFinal pressure (P₂): 4.40 atmFinal volume (V₂): ?Final temperature (T₂): 350 K

Step 2: Convert P₁ to atm

We will use the conversion factor 1 atm = 1.01325 bar.

3.36 bar × (1 atm / 1.01325 bar) = 3.32 atm

Step 3: Calculate V₂

We will use the combined gas law.

P₁ × V₁/T₁ = P₂ × V₂/T₂

V₂ = P₁ × V₁ × T₂/T₁ × P₂

V₂ = 3.32 atm × 15.0 L × 350 K/298 K × 4.40 atm

V₂ = 13.3 L

exactly 149.6J will raise the temperature of 10.0g of a metal from 25.0C. what is the specific heat capacity of the metal

Answers

Exactly 149.6J will raise the temperature of 10.0g of a metal from 25.0C. The specific heat capacity of the metal is 5.984 J/g°C.

What is specific heat capacity?

The heat capacity of a sample of a substance divided by the mass of the sample yields the specific heat capacity (symbol c), also known as massic heat capacity. Informally, it is the quantity of heat that must be added to one unit of a substance's mass in order to raise its temperature by one unit. The specific heat capacity unit in the SI is the joule per kelvin per kilogram, or Jkg⁻¹K⁻¹. For instance, the specific heat capacity of water is 4184 J kg⁻¹K⁻¹, or the amount of energy needed to raise 1 kilogram of water by 1 K.

The specific heat capacity of the metal can be calculated using the equation Q = m × c ×ΔT.

Q = 149.6J

m = 10.0g

ΔT = (final Temperature - initial Temperature) = (25°C - 0°C) = 25°C

Plugging these values into the equation, we get:

149.6J = 10.0g × c ×25°C

Solving for c, we get:

c =  \(\frac{149.6J}{(10.0g *25C)}\)

c = 5.984 J/g°C

Therefore, the specific heat capacity of the metal is 5.984 J/g°C.

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2- Calculate the pH of 0.1M HCl solution

Answers

Explanation:

Calculation:

The pH of a solution is calculated by the formula:

p

H

=

log

[

H

+

]

Now the dissociation reaction of HCl is:

(

0.1

M

)

H

C

l

(

0.1

M

)

H

+

+

(

0.1

M

)

C

l

Here one mole of HCl gives one mole of hydrogen ions. Therefore, the concentration of

H

+

ion is the same as the concentration of HCl, given that is 0.1 M.

Now substitute this value in the formula:

p

H

=

log

[

H

+

]

=

log

(

0.1

)

=

1

The figure below shows a walkway with a handrail. Angle is the angle between the walkway and the horizontal, while angle is the angle between the vertical posts of the handrail and the walkway. Use the figure below to work the problem. (Assume that the vertical posts are perpendicular to the horizontal.)

Are angles and complementary or supplementary angles?
complementary
supplementary

Answers

The angles as shown are supplementary angles because the add up to 180 degrees.

What are supplementary angles?

Two angles are said to be supplementary if they add up to 180 degrees. Now we know that the sum of angles on  straight line is 180 degrees. If we look at the image as shown in the image attached, we can see that the angles lie on a straight line.

As such, we can conclude that the angles as shown are supplementary angles because the add up to 180 degrees.

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The figure below shows a walkway with a handrail. Angle is the angle between the walkway and the horizontal,

At a certain temperature the vapor pressure of pure chloroform (CHCl3) is measured to be 91. torr. Suppose a solution is prepared by mixing 140. g of chloroform and 67.1 g of heptane (C,H16) of chloroform and 67.1 g of heptane (C7H16 Calculate the partial pressure of chloroform vapor above this solution.

Answers

Answer:

\(P_{CCl_4}=52.43torr\)

Explanation:

Hello there!

In this case, sine the solution of this problem require the application of the Raoult's law, assuming heptane is a nonvolatile solute, so we can write:

\(P_{CCl_4}=x_{CCl_4}P_{CCl_4}^{vap}\)

Thus, we first calculate the mole fraction of chloroform, by using the given masses and molar masses as shown below:

\(x_{CCl_4}=\frac{140/153.81}{140/153.81+67.1/100.21}=0.576\)

Therefore, the partial pressure of chloroform turns out to be:

\(P_{CCl_4}=0.576*91torr\\\\P_{CCl_4}=52.43torr\)

Regards!

A graduated cylinder contains 50.0 ml of water. A 23.5 g piece of unknown metal is carefully dropped into the cylinder. When
the metal is completely covered with water, the water rises to the 53.4 ml mark. What is the density of the unknown piece of
metal in g/ml?

Answers

To find the density of the unknown piece of metal, we can use the formula:

Density = mass / volume.

How to find the density ?The volume of the metal can be calculated by deducting the starting water volume (50.0 ml) from the final water volume (53.4 ml) after the metal is introduced. We know the mass of the unknown metal is 23.5 g.Volume of metal = 53.4 ml - 50.0 ml = 3.4 ml.Now we can substitute the values into the density formula: Density = 23.5 g / 3.4 ml = 6.9 g/ml.Therefore, the density of the unknown piece of metal is 6.9 g/ml.

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The following Lewis diagram represents the valence electron configuration of a main-group element.


This element is in group
.

According to the octet rule, this element would be expected to form an ion with a charge of
.

If is in period 5, the ion formed has the same electron configuration as the noble gas
.

The symbol for the ion is
.

Answers

This element is in group 1.

According to the octet rule, this element would be expected to form an ion with a charge of +1.

If X is in period 5, the ion formed has the same electron configuration as the noble gas Krypton

The symbol for the ion is Rb⁺

What is electronic configuration?

Electronic configuration refers to the arrangement of electrons in the orbitals of an atom or molecule, indicating the energy level of the electrons, the number of electrons in each energy level, and the number of electrons in each orbital.

Considering the given element:

It has one valence electron, hence it is in group 1. Group 1 elements form ions with a charge of +1.

Losing one electron will give the ion the same electron configuration as Kyrton since it is the noble gas in Period 4.

The element is rubidium and the ion is Rb⁺.

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The following Lewis diagram represents the valence electron configuration of a main-group element.This
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