In a 'keep-fit' exercise, a student of mass 45 kg steps 40 times on and off a box of height 0.50 m. How much work does the student do to raise her body each time she steps on the box

Recall that neutrons have no charge whereas protons and alpha particles are charged particles.

The electrostatic force of these charged particles always wants to push them apart from each other and this force gets stronger the closer you put them together.

Neutrons, on the other hand, have no electric charge and hence cannot feel this force.

Therefore, it is easier to accomplish nuclear transformations using neutrons due to their uncharged property.

ANSWER:

5.0 m

STEP-BY-STEP EXPLANATION:

We must calculate the minimum distance and maximum distance to know which of these distances is correct.

We know that hearing a sound wave,

Speed = Wavelength x Frequency, therefore:

Maximum distance

Minimum distance:

The only answer choice between 17 meters and 0.017 meters is 5 meters.

Answer:

\(\boxed {\boxed {\sf a\approx -0.08 \ m/s^2}}\)

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

\(a=\frac{v_f-v_i}{t}\)

The final velocity is 3 meters per second. The initial velocity is 8 meters per second.

We need to convert the time to seconds.

So, we know that:

\(v_f=3 \ m/s \\v_i= 8 \ m/s\\t= 60 \ s\)

Substitute the values into the formula.

\(a=\frac{3 \ m/s - 8 \ m/s}{60 \ s}\)

Solve the numerator.

\(a=\frac{-5 \ m/s}{60 \ s}\)

Divide.

\(a=-0.0833333333 \ m/s/s\)

Let's round to the nearest hundredth.

The 3 in the thousandth place tells us to leave the 8 in the hundredth place.

\(a\approx -0.08 \ m/s^2\)

The cyclist's acceleration is about \(\boxed {-0.08 m/s^2}\)

A fox getting its energy from a mouse and a mouse getting its energy from the grass  shows evidence of the carbon cycle

The carbon cycle is a necessary component within the global interchange between living species and the environment.

Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.

Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.

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Answer:

I = 4.75 A

Explanation:

To find the current in the wire you use the following relation:

\(J=\frac{E}{\rho}\)      (1)

E: electric field E(t)=0.0004t2−0.0001t+0.0004

ρ: resistivity of the material = 2.75×10−8 ohm-meters

J: current density

The current density is also given by:

\(J=\frac{I}{A}\)        (2)

I: current

A: cross area of the wire = π(d/2)^2

d: diameter of the wire = 0.205 cm = 0.00205 m

You replace the equation (2) into the equation (1), and you solve for the current I:

\(\frac{I}{A}=\frac{E(t)}{\rho}\\\\I(t)=\frac{AE(t)}{\rho}\)

Next, you replace for all variables:

\(I(t)=\frac{\pi (d/2)^2E(t)}{\rho}\\\\I(t)=\frac{\pi(0.00205m/2)^2(0.0004t^2-0.0001t+0.0004)}{2.75*10^{-8}\Omega.m}\\\\I(t)=4.75A\)

hence, the current in the wire is 4.75A

It take 1.33 second to a Dalmatian to accelerate from rest to its top speed.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

given parameters:

initial speed, u = 0

final speed, v =16.5 m/s.

distance covered, s = 11 meters.

We have to find: time t = ?

We know that:

s = ut +(v-u)t/2

⇒ 11 = 0 + (16.5 -0)t/2

⇒ t = 22/16.5 second = 1.33 second.

So,  it take 1.33 second to a Dalmatian to accelerate from rest to its top speed.

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Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

Answer: Picture is too small I can’t see

From conservation of linear momentum, the final velocity is 15.7 m/s and the time taken is 1.6 s

Velocity can be defined as a distance travel in a specific direction per time taken. It is a vector quantity.

Given that 30kg metal ball is dropped from a height of 12.5 m.  

a.  Find the final velocity when the ball  hits the ground.

The maximum K.E of the ball at it final velocity will be equal to its maximum P.E at height 12.5 m. That is,

K.E = P.E

1/2mv² = mgh

Where

Substitute all the parameters

1/2 × 30 × v² = 30 × 9.8 × 12.5

v² = 245

v = √245

v = 15.65 m/s

b. The time it takes for the ball to hit the ground can be found through

h = ut + 1/2gt²

but u = 0

h = 1/2gt²

Substitute all the necessary parameters

12.5 = 1/2 × 9.8 × t²

12.5 = 4.9t²

t² = 12.5/4.9

t² = 2.55

t = √2.55

t = 1.6 s

Therefore, the final velocity when the ball hits the ground is 15.65 m/s and the time it takes for the ball to hit the ground is 1.6 s

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checlknthfd sissExplanation: 2+3 ls g g fg

Answer:

deductive reasoning usually follows steps .

Answer:

D) 12 sodium, 4 phosphorus. 16 oxygen

Explanation:

there is a four in front of the full formula, so you multiply all of the sub numbers by 4

vf=vi+at

20=0+10.t

20=10t

t=2 s

The students didn't make it before the train leaves at exactly its scheduled time of 15:55 pm.

The given parameters;

The time spent by the bus during the first motion;

\(time = \frac{distance}{speed}\\\\time = \frac{2 \ km}{20 \ km/hr} \\\\time = 0.1 \ hr = 6 \min\)

total time = 6 min + 1 min spent waiting = 7 min

The time spent by the bus during the second motion;

\(time = \frac{4 \ km}{20 \ km/hr} \\\\time = 0.2 \ hr = 12 \min\)

The time spent by the students running to cover the remaining distance;

\(time = \frac{300 \ m}{5\ m/s} \\\\time = 60 \ s = 1 \min\)

The total time spent by the students before getting to the train station;

t = 7 min  +  12 min + 1 min = 20 min

The minimum time the students need to make it to the train station before the train leaves;

t' = 15:55 - 15:36 = (55 - 36) = 19 min

Thus, the students didn't make it before the train leaves at exactly its scheduled time of 15:55 pm.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Choice-A is the main reason that people use the thing in the picture.

Answer:

0.0512 kJ

Explanation:

From the given information, since the values were not given:

Then, Let assume that:

A set of 50 titanium rods is handled by the engineer, with 50cm length and 20g of mass.

The overhead walkway = 5.3 m

In this process, 12 rods roll of the walkway

We are to determine the change in the Gravitational P.E

Change in P.E = final P.E- initial P.E

Change in P.E = (50 mgh) - (0)

Change in P.E =  \((50\times \dfrac{20}{1000}\times 9.8 \times 5.3 )-0\)

Change in P.E =  51.94 Joules

Change in P.E = 0.05194 Joules

Change in P.E ≅ 0.0512 kJ

log 8 + log 16 - log 2 = log64, In order to get another number, a number should be raised to a certain power, which is known as a logarithm.

The correct answer is A

A number must be increased to a specific power, or logarithm, in order to obtain another number. For additional information on exponents, visit Figure 3.3 of this Math Review. As an example, the base 10 logarithm of the number ten raised to the power of two two is two, or log 100, which equals two.

Exponentiation is a mathematical operation, and the logarithm, simply log, is its inverse. In other words, the log of a number is the value that a fixed base must be increased to in order to produce the value. Although technically any base can be used, the term "log" often suggests that base 10 is being used.

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The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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Therefore, the frequency of oscillation when the spring is connected 1/5 of the way from the pivot to the end of the rod is approximately 1.34 Hz.

Since the rod is thin and uniform, its moment of inertia about the pivot point can be approximated as:

I = (1/3)ML^2

When the spring is connected 1/5 of the way from the pivot to the end of the rod, the effective length of the rod becomes:

l_eff = l/5 + (4/5)(l/2) = 9l/10

So, the frequency of oscillation is: 8.42 rad (after calculations)

The frequency of oscillation when the spring is connected 1/5 of the way from the pivot to the end of the rod is approximately 1.34 Hz.

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If a third resistor is added in SERIES, what changes happens to the....

When you add a third resistor in series, the total resistance of the circuit increases. This is because the current has to flow through all three resistors, so it has to overcome more resistance. The total voltage across the circuit stays the same, because the voltage of the battery is constant. However, the current decreases, because the same amount of current is now flowing through a larger resistance.

The voltage across each resistor also decreases, because the total voltage is divided among the three resistors. The current through each resistor also decreases, because the same current is now flowing through a larger resistance.

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Answer:

D

Explanation:

D - The total energy in the universe is constant

The first law of thermodynamics states that heat is also another form of energy, and that thermodynamic processes are as a result, subjected to the principle of conservation of energy. The principle of conservation of energy is another way of boldly saying that heat energy cannot be created and neither can heat energy be destroyed.

I hope that's clear enough

Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

Explanation:bkdbjkfej jf jfekjwniorigoexhndvgkj...............aplokdiuhyfgbv ..............................................

Answer:

I will guess c for your answer!

Explanation:

I don't know really how to explain my guess.

Answer:

I believe B

Explanation:

73 - 65 = 8

8 / 5 = 1.6

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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Answer:

The higher the energy, the shorter the wavelength.

Explanation: