in a hypothesis test with hypotheses and , a random sample of 16 elements selected from the population produced a mean of 91.7 and a standard deviation of 4.7. the test is to be made at the 5% significance level. assume the population is normally distributed. what are the critical values of t?

Answer:

15/60

Step-by-step explanation:

10/40 is equivalent to 5/20, and you can multiply the top and bottom of this fraction by 3 to get 15/60

Answer:

A (6, 9)

Step-by-step explanation:

The solution is the point that the two equations meet so using the graph we can determine that the point is (6, 9) because points are labeled (x, y).

Answer:

7.2 Minutes

Step-by-step explanation:

Use Ratios

Miles : Minutes

5:36

Divide Both Sides By 5

1:7.2

It will Take Ally 7.2 Minutes To Run 1 Mile

Answer:

The stack of blocks is 25.96 inches tall

Step-by-step explanation:

The Volume of a Cube

Given a cube-shaped figure of side length L, the volume is calculated by:

\(V=L^3\)

If the volume is known, then the side length can be found by solving for L:

\(L=\sqrt[3]{L}\)

We are given three cube-shaped blocks with known volumes. We'll find the individual side lengths and add them up to find the height that results when they stack up vertically.

Block 1, volume 375 cube inches:

\(L_1=\sqrt[3]{375}=7.21\ inch\)

Block 2, volume 648 cube inches:

\(L_2=\sqrt[3]{648}=8.65\ inch\)

Block 3, volume 1029 cube inches:

\(L_3=\sqrt[3]{1029}=10.10\ inch\)

Total height=7.21 inch+8.65 inch+10.10 inch=25.96 inch

The stack of blocks is 25.96 inches tall

Proportion of films that will be too thin is 0.1587 or approximately 15.87%.

To find the proportion of films that will be too thin, we need to calculate the area under the normal distribution curve to the left of the minimum acceptable thickness of 90 microns.

Using a standard normal distribution table or calculator, we can find the z-score corresponding to a thickness of 90 microns:

z = (90 - 100) / 10 = -1

The area under the normal curve to the left of this z-score is approximately 0.1587, which means that about 15.87% of the films produced will be too thin (less than 90 microns).

Therefore, the proportion of films that will be too thin is 0.1587 or approximately 15.87%.

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The average change in the temperature of the city is 0.87°C.

The average quantity is the sum of all quantities divided by the number of quantities.

In the question, we are informed that a newspaper reports the changes in the temperature of the city over 4 days to be 3.24°C, - 3/8 °C, - 0.15 °C, and 7/9 °C.

We are asked to write an expression to show the daily average change in the temperature of the city.

As we know, the average quantity is the sum of all quantities divided by the number of quantities.

Thus, average = {(3.24 - 3/8 -0.15 +7/9)/4} °C,

or, average = {{324/100 - 3/8 - 15/100 + 7/9}/4} °C,

or, average = [{(23328 - 2700 - 1080 + 5600)/7200}/4] °C,

or, average = 25148/28800 °C,

or, average = 6287/7200 °C = 0.8732 °C ≈ 0.87 °C.

Thus, the average change in the temperature of the city is 0.87°C.

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Answer:

\(\boxed {8 \times 58}\)

Answer D is correct

Step-by-step explanation:

Twice a certain number is 58

\(\red {2 \times 58}\)

Four times that number will be

\(\green{ 2\times 58 \times 4 }\\ = 8 \times 58\)

Answer:

The answer you are looking for is 8 time 58 or D

Step-by-step explanation:

Hope this helped

First, tan(θ) = sin(θ) / cos(θ), so if cos(θ) = 3/5 > 0 and tan(θ) < 0, then it follows that sin(θ) < 0.

Recall the Pythagorean identity:

sin²(θ) + cos²(θ) = 1

Then

sin(θ) = -√(1 - cos²(θ)) = -4/5

and so

tan(θ) = (-4/5) / (3/5) = -4/3

The remaining trig ratios are just reciprocals of the ones found already:

sec(θ) = 1/cos(θ) = 5/3

csc(θ) = 1/sin(θ) = -5/4

cot(θ) = 1/tan(θ) = -3/4

Answer: 1035 cm^2

Step-by-step explanation:

Given that the shape s is exactly one quarter of solid sphere.

Where the volume of the shape s is 1994πcm^3.

The formula for volume of a sphere is

V = 4/3πr^3

The volume will be divided by 4 since the given solid is exactly quarter of solid sphere. Then equate it to the given value

1994π = 4/3πr^3 × 1/4

The π will cancel out

1994 = r^3/3

Cross multiply

5982 = r^3

r = cube root of 5982

r = 18.2 cm

The surface area of a sphere is

A = 4πr^2

Substitute r in the formula

A = 4× π × 18.2^2

A = 4141

Since the shape is exactly one quarter of solid sphere. Divide the answer by 4

A = 4141/4

A = 1035.3 cm^2

The surface area of s is therefore 1035.3 cm^2

The surface area of the shape s is approximately 329.53 cm².

Important information:

Volume of a sphere is:

\(V=\dfrac{4}{3}\pi r^3\)

The volume of one-quarter of a solid sphere is 1994π cm².

\(1994\pi=\dfrac{1}{4}\times \dfrac{4}{3}\pi r^3\)

\(1994\pi=\dfrac{1}{3}\pi r^3\)

\(\dfrac{1994\pi\times 3}{\pi}=r^3\)

\(5982=r^3\)

Taking cube root on both sides, we get

\(\sqrt[3]{5982}=r\)

\(r\approx 18.153\)

Surface area of a sphere is:

\(S=4\pi r^2\)

Surface area of one quarter of solid sphere is:

\(S=\pi r^2\)

\(S=\pi (18.153)^2\)

\(S=329.5314\pi\)

\(S\approx 329.53\pi\)

Therefore, the surface area of the shape s is 329.53 cm².

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Using proportions, it is found that $15.00 in quarters weigh 29.4 grams less today than before 1965.

A proportion is a fraction of a total amount.

In this problem, a quarter is worth $0.25, hence $15.00 in quarters is composed by 60 quarters, as:

\(\frac{15}{0.25} = 15 \times 4 = 60\)

Before 1965, the total weight was of:

60 x 6.25 = 375 grams.

After that, the total weight is of:

60 x 5.76 = 345.6 grams.

Hence the difference is:

375 - 345.6 = 29.4.

$15.00 in quarters weigh 29.4 grams less today than before 1965.

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Answer:

(7, -3)

Step-by-step explanation:

Hope this helps. Pls give brainliest.

The 8th term of the geometric sequence is 4374.

Step-by-step explanation:

The 8th term of the geometric sequence is

We know the formula to find the nth term of a GP is

t = ar^{n-1}...(i)

where t=> term to find out

a=> first term of the GP

r=> the common ratio of the Gp

to find common ratio, divide a term with its previous term

Now, according to question:

a = 2

n=8

d= second term / first term = 6/2 = 3

therefore, putting values in equation i,

t= 2*3^(8-1)

 = 2*3^7

 = 2*2187 = 4374

Thus 8th term of the geometric sequence is 4374.

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Answer:

B, between 3 and 4 miles

Step-by-step explanation:

We know that h is 9.

√1.5*9

1.5*9=13.5

This can be done without a calculator.

if we know that √13.5 is in between √9 and √16 and that √9=3 and that √16 is equal to √4, it can be concluded that the answer is in between 3 and 4.

The expressions which is not equivalent to 5x - 15 are:

−5(x+3)

−3(−53x+5)

−15(−25x+75)

The correct answer options are options A, C and D

Equivalent equations refers to algebraic equations which have identical roots or solutions.

We get an equivalent equation by adding or subtracting the same number or expression to both side of an equation and also by multiplying or dividing both sides of an equation by the same non zero number we get equivalent equation.

5x - 15

Check all options:

A. −5(x+3)

open parenthesis

= -5x - 15

False

B. 5(x−3)

Open parenthesis

= 5x - 15

True

C. −3(−53x+5)

= 159x - 15

False

D. −15(−25x+75)

open parenthesis

= 375x - 1125

False

Therefore, 5(x−3) is the equivalent equation for 5x - 15

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The multiples of 2 from 101 to 200 will be all the even numbers starting from 102 to 200.

It should be noted that multiples simply mean the product that can be gotten when a number is multiplied by another number.

It should be noted that the multiples of 2 from 101 to 200 will be all the even numbers starting from 102 to 200.

In this case, the odd numbers aren't multiple of 2.

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Answer:

Below

Step-by-step explanation:

0.3>0.25

0.35<0.4

0.05<0.1

a) This program calculates all four solutions: x1, x2 using the standard formula, and x1_prime, x2_prime using the modified formula to avoid subtractive cancellation. b) To investigate the effect of subtractive cancellation, we can test the program using values where subtractive cancellation occurs. c) To determine the most precise solutions, you can compare the errors between the standard formula.

(a) Write a program that calculates all four solutions for arbitrary values of a, b, and c.

Here's a Python program that calculates all four solutions for the quadratic equation:

import math

def quadratic_equation(a, b, c):

   discriminant = b**2 - 4*a*c    

   if discriminant >= 0:

       sqrt_discriminant = math.sqrt(discriminant)        

       x1 = (-b + sqrt_discriminant) / (2*a)

       x2 = (-b - sqrt_discriminant) / (2*a)        

       x1_prime = (-2*c) / (b + sqrt_discriminant)

       x2_prime = (-2*c) / (b - sqrt_discriminant)      

       return x1, x2, x1_prime, x2_prime

   else:

       return None

# Example usage

a = 1

b = 2

c = -3

solutions = quadratic_equation(a, b, c)

print(solutions)

This program calculates all four solutions: x1, x2 using the standard formula, and x1_prime, x2_prime using the modified formula to avoid subtractive cancellation.

(b) Investigate how errors in your computed answers become large as the subtractive cancellation increases, and relate this to the known machine precision.

To investigate the effect of subtractive cancellation, we can test the program using values where subtractive cancellation occurs, such as a = 1, b = 1, c = 10^(-n) for different values of n. By comparing the computed solutions with the actual solutions, we can observe the increase in errors.

Here's an example of how you can test the program and calculate the errors:

import math

def quadratic_equation(a, b, c):

   discriminant = b**2 - 4*a*c    

   if discriminant >= 0:

       sqrt_discriminant = math.sqrt(discriminant)        

       x1 = (-b + sqrt_discriminant) / (2*a)

       x2 = (-b - sqrt_discriminant) / (2*a)        

       x1_prime = (-2*c) / (b + sqrt_discriminant)

       x2_prime = (-2*c) / (b - sqrt_discriminant)        

       return x1, x2, x1_prime, x2_prime

   else:

       return None

# Test with a = 1, b = 1, c = 10^(-n) for n = 1, 2, 3

for n in range(1, 4):

   a = 1

   b = 1

   c = 10**(-n)

   solutions = quadratic_equation(a, b, c)

   x1, x2, x1_prime, x2_prime = solutions    

   # Calculate the actual solutions

   actual_x1 = (-1 + math.sqrt(1 - 4*c)) / 2

   actual_x2 = (-1 - math.sqrt(1 - 4*c)) / 2    

   # Calculate the errors

   error_x1 = abs(actual_x1 - x1)

   error_x2 = abs(actual_x2 - x2)

   error_x1_prime = abs(actual_x1 - x1_prime)

   error_x2_prime = abs(actual_x2 - x2_prime)    

   print(f"n = {n}")

   print(f"Error (x1): {error_x1}")

   print(f"Error (x2): {error_x2}")

   print(f"Error (x1_prime): {error_x1_prime}")

   print(f"Error (x2_prime): {error_x2_prime}")

   print()

By observing the errors, you should notice that as n increases (and subtractive cancellation becomes more prominent), the errors in x1 and x2 increase significantly compared to the errors in x1_prime and x2_prime. This is because the modified formula in x1_prime and x2_prime helps mitigate the subtractive cancellation issue, resulting in more accurate solutions.

(c) Extend your program so that it indicates the most precise solutions.

To determine the most precise solutions, you can compare the errors between the standard formula (x1, x2) and the modified formula (x1_prime, x2_prime). The solutions with lower errors are considered more precise.

Here's an example of how you can modify the program to indicate the most precise solutions:

import math

def quadratic_equation(a, b, c):

   discriminant = b**2 - 4*a*c    

   if discriminant >= 0:

       sqrt_discriminant = math.sqrt(discriminant)        

       x1 = (-b + sqrt_discriminant) / (2*a)

       x2 = (-b - sqrt_discriminant) / (2*a)

       x1_prime = (-2*c) / (b + sqrt_discriminant)

       x2_prime = (-2*c) / (b - sqrt_discriminant)        

       # Calculate the errors

       error_x1 = abs(x1 - x1_prime)

       error_x2 = abs(x2 - x2_prime)

       # Determine the most precise solutions

       if error_x1 < error_x2:

           return x1, x1_prime

       else:

           return x2, x2_prime

   else:

       return None

# Example usage

a = 1

b = 1

c = 0.001

solutions = quadratic_equation(a, b, c)

print(f"Standard Formula (x): {solutions[0]}")

print(f"Modified Formula (x_prime): {solutions[1]}")

In this modified program, the quadratic_equation function now returns the most precise solutions based on the comparison of errors. The program then prints the standard formula solution (x) and the modified formula solution (x_prime).

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Answer:

Return the marble he initially drew from the bag

Step-by-step explanation:

Answer:

10 envelopes

Step-by-step explanation:

What we know:

- There are 3 drawings for each envelope

- There are 28 drawings in total

To find out the number of envelopes Declan would need, we divide 28 by 3 (check the picture attached).

28÷3=9 R1

28 divided by 3 gives us 9 with a remainder of 1, which means if Declan had 9 envelopes, he would be able to fit 3 drawings in each with 1 drawing left over. He would need a 10th envelope to use for the last drawing.

Therefore, Declan would need 10 envelopes to mail all the drawings to his grandma.

I hope this helps! Happy holidays :)

Algebraic expression is the combination of variables, coefficients and the constants. The phrase 2,4 and 5 represents the given algebraic equation.

Given information-

The given algebraic expression in the problem is,

\(x+14\)

Algebraic expression is the combination of variables, coefficients and the constants.

Above expression has the a unknown number \(x\). The expression refer that the number 14 is added in the unknown number \(x\).

Lets check all the phrase one by one,

The option 1 is the quotient of a number and 14. Here the unknown number is \(x\). Thus the expression for this option can be given as,

\(=\dfrac{x}{14} \)

This phrase does not represent the given expression. Thus the option 1 is incorrect option.

The option 2 is a number plus 14. Here the unknown number is \(x\). The term plus refers the addition of 14 in the unknown number.Thus the expression for this option can be given as,

\(=x+14\)

This phrase represents the given expression. Thus the option 2 is correct option.

The option 3 is fourteen less than a number. Here the unknown number is \(x\). The term less than refers to subtract 14 from the number. Thus the expression for this option can be given as,

\(=x-14\)

This phrase does not represent the given expression. Thus the option 3 is incorrect option.

The option 4 is fourteen more than a number. Here the unknown number is \(x\). The term more refers the addition of 14 in the unknown number. Thus the expression for this option can be given as,

\(=x+14\)

This phrase represents the given expression. Thus the option 4 is correct option.

The option 5 is a number increased by 14. Here the unknown number is \(x\). The term increased refers the addition of 14 in the unknown number. Thus the expression for this option can be given as,

\(=x+14\)

This phrase represents the given expression. Thus the option 5 is correct option.

Hence the phrase 2,4 and 5 represents the given algebraic equation.

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If the customer sues for a refund The customer will prevail.

B The customer, because he had a reasonable time after purchase in which to inspect.

The customer prevailing due to a reasonable time for inspection: If the customer inspected the wallet promptly after purchase and discovered the defect, they might argue that they exercised reasonable diligence and promptly returned to the store to demand a refund. This could support their claim for a refund. The customer will prevail in the case. This is because the customer had a reasonable time after purchase in which to inspect the wallet purchased. The Uniform Commercial Code provides that in any sale of goods, a buyer has a reasonable opportunity to inspect the goods to determine their condition before accepting them.

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Question is incomplete the complete question is :

A customer selected a new wallet at a local department store that the salesperson said was made of the finest calfskin and was stitched by hand. The customer bought the wallet and left the store. A few moments later, he took out the wallet to transfer his cash and credit cards into it. On close inspection, he noticed a small nick in the leather. He immediately went back to the department store and demanded a refund. The salesperson refused.

If the customer sues for a refund, who will prevail?

A The customer, because there was a breach of contract.

B The customer, because he had a reasonable time after purchase in which to inspect.

C The department store, because the customer accepted the goods.

D The department store, because the customer did not give written notice of the breach.

Answer:

the second one is the better deal

Step-by-step explanation:

Answer:

Hows it going young blood Y=5x-13 is the answer

Step-by-step explanation:

Answer:

quanda dude try mo

Step-by-step explanation:

or guthmat

She able to serve maximum 18 people.

What do you mean by maximum?

The word maximum is used to express an amount that is the greatest that is conceivable, permitted, or necessary.

According to data in the given question,

We have data in the given question:

The apple crumble of 600gm apple to serve = 6 people

Let x represents the max number of people which takes apple crumble of 1800gm apple.

6 people .......... 600g apple

X people .......... 1800g of apples

600X = 1800*6 / :600

X = 18

Therefore, she able to serve maximum 18 people.

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multiply Start Fraction 5 Over 7 End Fraction by 3.

What do math fractions mean?

An element of a whole is a fraction. In mathematics, the number is represented as a quotient, where the numerator and denominator are divided. Both are integers in a simple fraction.

                                Whether it is in the numerator or denominator, a complex fraction contains a fraction.

                             The numerator and denominator of a correct fraction are opposite each other.

What is basic fraction theory?

Every fraction has two components: the numerator, which is the actual number of parts, and the denominator, which is the total number of parts.

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Answer:

c is the answer i took the test

Step-by-step explanation:

The random real number between 1.0 and 10.0 can be generated using the formula: 1.0 + (RAND() * 9.0).

To generate a random real number within a specified range, we can use the RAND() function. The RAND() function generates a random decimal number between 0 and 1.0. By multiplying this random number by the range of values we desire and adding the minimum value, we can obtain a random real number within the desired range.

In this case, we want a random number between 1.0 and 10.0. To achieve this, we multiply the random number generated by RAND() by the range, which is 9.0 (10.0 - 1.0). This scales the random number to the desired range. Then, by adding 1.0 (the minimum value) to the scaled random number, we obtain the final random real number within the range of 1.0 and 10.0.

To summarize, the formula for generating a random real number between 1.0 and 10.0 is: 1.0 + (RAND() * 9.0).

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