In a group of rats, some individuals have a normal-sized body and others have a dwarf body. In this group, the gene for the body size trait has two alleles. The allele B is for a normal-sized body, and the alleles is for a dwarf body

Explanation:

Without even doing any calculations I would say that the 20 g HNO3 is limiting

But let us check if my opinion is correct

Balanced equation:

CaO(s) + 2HNO3 (aq) → Ca(NO3)2 (aq) + H2O(l)

1 mol CaO reacts with 2 mol HNO3

Molar mass CaO = 56 g/mol

Mol CaO in 615 g = 615 g / 56 g/mol = 10.98 mol

This will react with 10.98 * 2 = 21.96 mol HNO3

Molar mass HNO3 = 63 g/mol

Mol HNO3 in 20 g = 20 g / 63 g/mol = 0.317 mol

Clearly - my original idea correct - HNO3 is limiting .

The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants. Here the mass of calcium nitrate formed is 16.82 g.

Reagents that are entirely consumed by a chemical reaction are known as limiting reagents. They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.

The limiting reactant determines the maximum amount of product that can be formed from the reactants when reactants are not present in stoichiometric quantities.

Here the equation is:

CaO + 2HNO₃ → Ca (NO₃)₂ + H₂O

'n' of CaO = 15 / 56 = 0.267 mol

n of HNO₃ = 20 / 63 = 0.317 mol

1 mol of CaO 2 moles of HNO₃

0.267 mol = 0.267 × 2 = 0.534 mol

So HNO₃ is the limiting reactant.

0.267 mol CaO gives 0.267 mol Ca (NO₃)₂

Mass of HNO₃ = 0.267 × 63.01 = 16.82 g

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The ∆E for the surroundings is -154.0 kJ by first law of thermodynamics.

According to the first law of thermodynamics, the total energy change of the system and surroundings combined is zero. Therefore, if the system releases 199.0 kJ of heat and does 45.0 kJ of work on the surroundings, the surroundings must gain 244.0 kJ of energy in order to balance the energy change:

ΔE_system + ΔE_surroundings = 0

ΔE_surroundings = -ΔE_system

ΔE_surroundings = -(q - w)

ΔE_surroundings = -(199.0 kJ - 45.0 kJ)

ΔE_surroundings = -154.0 kJ

The negative sign indicates that the surroundings lose 154.0 kJ of energy. Therefore, the ∆E for the surroundings is -154.0 kJ.

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A coffee cup temperature  with a heat capacity of 6. 70 J/∘ C was used to measure the change in enthalpy of a precipitation reaction.The value of ΔHrxn was found to be 61.9 kJ/mol.

Calculate the enthalpy of reaction, ΔHrxn, per mole of precipitate formed (AgSCN). Assume the specific heat of the product solution is 4. 11 J / (g⋅∘C) and that the density of both the reactant solutions is 1. 00 g/mL.1. Calculation of Moles of precipitate formed from AgNO3:To find the value of ΔHrxn, we used the formula ΔHrxn = Qsolution/n, where Qsolution is the heat change produced by the solution process and n is the number of moles of AgSCN formed.

To find the value of n, we first calculated the number of moles of AgNO3 and KSCN used in the reaction using the formula n = M × V.To find the heat change produced by the solution process, we used the formula

Q = m × c × ∆T,

where Q is the heat change, m is the mass of the product solution, c is the specific heat capacity of the product solution, and ∆T is the change in temperature of the solution.The value of ΔHrxn was found to be 61.9 kJ/mol.

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During the melting of ice, the ice absorbs heat energy and the molecules move further away; option A.

Melting refers to the process by which a solid substance changes to liquid when heat is added to it.

The melting of pure substances occur at a definite temperature called the melting point of that substance.

The molecules of a substance move further apart when they melt as the attractive forces between them are weakened.

The melting of ice is an example of the process of melting.

During the melting of ice, the ice absorbs heat energy and the molecules move further away.

In conclusion, melting of solids occur when heat is added to the solid.

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It is not enough to just know the mass of each reactant to determine the limiting reagent in a chemical reaction. The limiting reagent is the reactant that gets completely consumed during a chemical reaction, which limits the amount of product that can be formed.

To determine the limiting reagent, you need to compare the amount (in moles) of each reactant present, rather than just the mass. This is because different reactants have different molar masses, and therefore the same mass of two different reactants would have different numbers of moles.

Once you have determined the amount (in moles) of each reactant present, you can use stoichiometry to calculate how much product can be formed from each reactant. The reactant that produces the smallest amount of product is the limiting reagent.

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Answer:

A is true NaCl

B is false K2Br

C is true

D false its only 0.03 percent

E is true

he Bohr model of the hydrogen atom states that the electron moves in a circular orbit with a radius of 5.3×10⁻¹¹m and a speed of 2.2×10⁶m/s.

In the Bohr model, electrons orbit the nucleus in specific energy levels. The radius of the orbit is determined by the energy level the electron occupies. In this case, the electron is in a specific energy level that corresponds to a circular orbit with a radius of 5.3×10⁻¹¹m. The speed of the electron in this orbit is 2.2×10⁶m/s. This means that the electron is moving at a very high speed around the nucleus.

The Bohr model helps us understand the quantized nature of electron energy levels and provides a simplified representation of the hydrogen atom. It is important to note that this model has limitations and is an approximation of the more complex behavior of electrons in atoms as described by quantum mechanics.

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The balanced equation in acidic conditions for the reaction between copper (Cu) and nitrate ion (NO3-) is as follows: Cu + 4H+ + 2NO3- → Cu2+ + 2NO2 + 2H2O.

To balance the equation in acidic conditions, we need to ensure that both the mass and charge are balanced on both sides of the equation. Here's how the equation is balanced:

Balance the copper atoms:

We start by placing a coefficient of 1 in front of Cu on the left side and a coefficient of 1 in front of Cu2+ on the right side.

Cu + ... → Cu2+ + ...

Balance the oxygen atoms:

Since nitrate ion (NO3-) contains three oxygen atoms, we need three molecules of NO3- to balance the oxygen atoms. This gives us:

Cu + 4H+ + 3NO3- → Cu2+ + ...

Balance the nitrogen atoms:

Since NO3- contains one nitrogen atom, we need one molecule of NO3- to balance the nitrogen atoms. This gives us:

Cu + 4H+ + 3NO3- → Cu2+ + NO + ...

Balance the hydrogen atoms:

To balance the hydrogen atoms, we place a coefficient of 4 in front of H+ on the left side:

Cu + 4H+ + 3NO3- → Cu2+ + NO + ...

Balance the charge:

To balance the charge, we place a coefficient of 2 in front of NO on the right side:

Cu + 4H+ + 3NO3- → Cu2+ + 2NO + ...

Balance the water molecules:

Finally, to balance the oxygen atoms and the hydrogen atoms, we add two water molecules on the right side:

Cu + 4H+ + 3NO3- → Cu2+ + 2NO + 2H2O

Now the equation is balanced in acidic conditions, with the same number of atoms and charge on both sides.

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Answer:

melting

Explanation:

An physical properly I believe

Explanation: characteristics such as melting point boiling point color ider colored stuff etc all have physical properties

The solution of ammonium acetate into 500 mL of water  contains NH₄⁺ and C₂H₃O₂ ions.(D)

When ammonium acetate is added to water, it dissociates into its constituent ions: NH₄⁺ and C₂H₃O₂⁻. These ions are then evenly distributed throughout the solution. The NH₄⁺ ion is a weak acid and can donate a proton (H⁺ ion) to water to create NH₃ and H₃O⁺ ions, which gives the solution a slightly acidic pH.

In summary, when ammonium acetate is added to water, it dissociates into NH₄⁺ and C₂H₃O₂⁻ ions, which are evenly distributed throughout the solution.

To prepare a solution containing soluble silver ions, a chemist can dissolve a soluble silver salt, such as silver nitrate (AgNO₃), in water. When AgNO₃ dissolves in water, it dissociates into Ag⁺ and NO₃⁻ ions, which are evenly distributed throughout the solution.

The resulting solution will contain soluble silver ions, which can be used for a variety of applications, including silver plating, electrochemistry, and analytical chemistry.(D)

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Answer:

yo what's the tool??

Explanation:

You have to give the tool. If this is from Edmentum, I'm also doing the same thing but with scissors.

Volumetric pipetts, volumetric flasks and burette are the most accurate, the glassware makers calibrate these to a high level of accurасу.

However, if we need exactly 25.0 ml to make up a 'standard' solution, only a volumetric flask would be appropriate

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Answer:

2 grinding of wheat is just a physical change

plz brainlist

(ANSWER)

AREA OF WALK = 444 SQUARE FEE

(EXPLANATION)

FIRST, CALCULATE THE AREA OF THE RECTANGULAR YARD.

♥ A = L × W where A equals area, L equals length, and W equals width.

ACCORDING TO YOUR STATED PROBLEM:

♥ A = 1519 square feet. <––– Area of Rectangular yard.

♥ NOW, ACCORDING TO YOUR STATED PROBLEM THERE IS A WALK THAT IS 3 FEET WIDE GOING ALL THE WAY ALONG THE FENCE (INSIDE).

♥ THEREFORE, YOU HAVE SIX FEET TO SUBTRACT FROM EACH OF THE VALUES ABOVE (31) AND (49).

WHY?

THREE FEET ON EACH SIDE, CORRECT?

A = L × W

A = 25 × 43

A = 1075 square feet <––––Area of new rectangle formed by allowing for three foot walk.

♥ NOW, SUBTRACT THE AREA OF THE NEW RECTANGLE FORMED FROM THE AREA OF THE ORIGINAL AREA. DOING SO, WILL GIVE YOU THE AREA OF THE WALK, CORRECT?

♥ ORIGINAL AREA = 1519 square feet

♥ NEW AREA = 1075 square feet

_____________________________________

Answer:

There is at least 2 ways. First, the isotopes are allowed to heat water into steam, and the steam turns a generator. 2nd, the isotopes are allowed to heat one end of a "thermopile", and the thermopile powers electronics

Hope this helped you!

Answer:

Proteins are made up of 20 amino acids. How an Isotope Technique Helps Determine Protein Quality. However be produced by the body and therefore are participated in the labelling process.

Explanation:

Answer:

By dehydrogenation of cyclohexane you may get Benzene as a product. We may use noble metals(Au, Ag, Pt etc.) to dehydration of cyclohexane. Consider following reaction which gives an idea about reaction.

Explanation:

I think it is the correct answer

i have read this in one of the book

"Hypotonic solution," refers to a solution with the highest water concentration due to its lower solute concentration compared to the other options, leading to water influx into cells.

A hypotonic solution would be most likely to have the highest water concentration. In a hypotonic solution, the solute concentration is lower than that inside the cell or compared to another solution. As a result, water tends to move into the cell or the solution to equalize the concentration.

When a cell is placed in a hypotonic solution, water molecules will move into the cell through the process of osmosis. This influx of water increases the water concentration inside the cell, leading to cell swelling or even bursting in extreme cases.

Compared to hypertonic and isotonic solutions, a hypotonic solution has a lower solute concentration, allowing for a higher concentration of water molecules. This results in a higher water concentration in the solution. It's important to note that the concept of tonicity is related to the relative solute concentrations between two solutions and their effect on cell osmosis. In this case, a hypotonic solution is characterized by a higher water concentration compared to the other options.

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Answer:

is aluminium prepared in thin metal leaves with a thickness less than 0.2 mm (7.9 mils); thinner gauges down to 6 micrometres (0.24 mils) are also commonly used.[1] In the United States, foils are commonly measured in thousandths of an inch or mils. Standard household foil is typically 0.016 mm (0.63 mils) thick, and heavy duty household foil is typically 0.024 mm (0.94 mils). The foil is pliable, and can be readily bent or wrapped around objects. Thin foils are fragile and are sometimes laminated with other materials such as plastics or paper to make them stronger and more useful. Aluminium foil supplanted tin foil in the mid 20th century.

Answer:

The key difference between rhombic and monoclinic sulphur is that the rhombic sulphur is the most stable allotropic form of sulphur that exists as rhombic octahedral crystals whereas the monoclinic sulphur exists as long, needle-shape prisms but, it is stable only at temperatures between 96◦C and 119◦C.

Explanation:

Thanks . I hope you got help

Answer:

a one rotation of the planet on its axis

Explanation:

The two types of motion that planets undergo are;

1) rotation of the planet about its axis

2) revolution of the planet around the sun.

In every planet there are days as shown in the image attached to the question. However, the length of day in each planet is determined by the time required for the planet to complete one rotation on its axis.

It takes the earth 1 earth day (24 hours) to complete rotation on its axis.

In water, sodium bicarbonate dissolves to form sodium and bicarbonate which makes the solution alkaline, which means it can neutralize acid.

An acid is described as a molecule or ion capable of either donating a proton, known as a Brønsted–Lowry acid, or forming a covalent bond with an electron pair, known as a Lewis acid.

sodium bicarbonate is less soluble in water because the density of the water is more than the density of the sodium bicarbonate.

Acids are known to produce hydrogen ions and bases accept hydrogen ions.

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Therefore, Δ∘ at 298 K for the reaction A + B ⟶ 2C is -685,682 J or -685.682 kJ. To calculate Δ∘ at 298 K for the reaction A + B ⟶ 2C, we can use Hess's Law.

Hess's Law states that if a reaction can be expressed as the sum of two or more reactions, the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the individual reactions.

Given reactions:

A + BC ⟶ 2D

2D ⟶ D

We need to find the enthalpy change for the reaction A + B ⟶ 2C. Let's break down the reaction into the given reactions:

A + B ⟶ A + BC (Step 1)

A + BC ⟶ 2D (Step 2)

2D ⟶ 2C (Step 3)

Now we can calculate the enthalpy change for the overall reaction by summing up the enthalpy changes of these individual steps.

Step 1:

Since A appears on both sides of the equation, its enthalpy change will cancel out, so we don't need to consider it in the calculations.

Step 2:

ΔH∘(Step 2) = ΔH∘(A + BC ⟶ 2D) = -685.3 kJ

Step 3:

ΔH∘(Step 3) = ΔH∘(2D ⟶ 2C) = 2 * ΔH∘(D) = 2 * (-191.0 J/K) = -382 J/K = -0.382 kJ

Now, we can sum up the enthalpy changes of all the steps to find the overall enthalpy change:

ΔH∘(A + B ⟶ 2C) = ΔH∘(Step 2) + ΔH∘(Step 3)

= -685.3 kJ + (-0.382 kJ)

= -685.3 kJ - 0.382 kJ

= -685.682 kJ

Since the enthalpy change is given at 298 K, we need to convert the enthalpy change from kJ to J:

ΔH∘(A + B ⟶ 2C) = -685.682 kJ * 1000 J/kJ

= -685,682 J

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According to kinetic theory of gases, when samples are heated from liquid to gas phase, particles move faster and spread out more. Hence, option a is correct.

According to kinetic theory of gases. Gaseous substances are made of tiny particles called molecules. The molecules within a container are in a state of random chaotic motion during which they collide with  each other.

At, a particular instant, different molecules in a sample of gas may have different velocities and hence, different kinetic energies.  The kinetic energy of molecules is directly proportional to the temperature.

Hence, the the sample  when heated, the molecules acquire higher kinetic energy and they will move apart. Therefore, option a is correct according to kinetic theory.

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Answer:

∆H= 3.92 kJ

∆S= 2.54 J

Explanation:

Hope It helps

Al(OH)3 has a molar solubility of about 2.2 1010 M in pure water, which is answer option (B).

Its solubility is the maximum amount of solute that may dissolve in a known volume of solvent at a specific temperature.

The solubility product expression for Al(OH)₃ is:

Ksp = [Al3+][OH-]³

Assuming that x is the molar solubility of Al(OH)₃ in pure water, then the equilibrium concentrations of Al³⁺ and OH⁻ in the solution are both equal to x. Therefore, we can write:

Ksp = x * (3x)³ = 27x⁴

Substituting the value of Ksp = 1.3 × 10⁻³³, we get:

27x^4 = 1.3 × 10⁻³³

Solving for x, we get:

x = (1.3 × 10⁻³³ / 27)\(^{(1/4)\) ≈ 2.2 × 10⁻¹⁰ M

Therefore, the molar solubility of Al(OH)₃ in pure water is approximately 2.2 × 10⁻¹⁰ M, which corresponds to answer choice (B).

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Al(OH)3 has a molar solubility of about 2.2 1010 M in pure water, which is answer option (B).

Its solubility is the maximum amount of solute that may dissolve in a known volume of solvent at a specific temperature.

The solubility product expression for Al(OH)₃ is:

Ksp = [Al3+][OH-]³

Assuming that x is the molar solubility of Al(OH)₃ in pure water, then the equilibrium concentrations of Al³⁺ and OH⁻ in the solution are both equal to x. Therefore, we can write:

Ksp = x * (3x)³ = 27x⁴

Substituting the value of Ksp = 1.3 × 10⁻³³, we get:

27x^4 = 1.3 × 10⁻³³

Solving for x, we get:

x = (1.3 × 10⁻³³ / 27) ≈ 2.2 × 10⁻¹⁰ M

Therefore, the molar solubility of Al(OH)₃ in pure water is approximately 2.2 × 10⁻¹⁰ M, which corresponds to answer choice (B).

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The electron will move to 2nd energy level as n = 2

An energy level (also called an electron shell) is a fixed distance from the nucleus at which an electron can exist. Electrons are small, negatively charged particles in atoms that move around a central, positive nucleus. Energy levels are a bit like stair steps. The energy emitted at a particular transition is equal to the energy difference between the two energy levels.

E(n) = −1/n² × 13.6eV

For the given case,

λ = 410.2 nm

h = 6.62 × 10⁻³⁴ j h⁻¹

c = 3 × 10⁸

E = hc/λ

E =  6.62 × 10⁻³⁴× 3 × 10⁸/410.2 × 10⁻⁹

E = 0.048 × 10⁻¹⁷ joules

E = 2.99 eV

E = -13.6 1/n²

Since, n = 6

E =  -13.6 1/6²

E = -0.38 eV

ΔE = E₂ - E₁

2.99 = -0.38 - E

-3.37 = E

-3.37 = -13.6 1/n²

n = 2

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