In gm two-mode hybrid electric vehicle, the vehicle can be powered by electric power alone in the first mode. The first mode has a function like a regular full hybrid.
A two-mode vehicle is a hybrid model that functions in two ways. The first mode is fully hybrid. The second mode brings a difference. The second mode performs various functions by adjusting various amounts of engine and motor functions.
In the first mode, with a light load and at low speed, the engine can be powered alone on electric power. In this mode, the engine can be shut down, but all accessories can continue operating on electric power. The hybrid system can restart the engine at any time when required.
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what is the ratio of electrostatic force and the gravitational force between a proton and an electron?
Answer:
Explanation:
electron attraction between electron and nucleus = centripetal force of the orbiting electron
In fact, Bohr model depicts the atom as a nucleus surrounded by electrons in circular orbit around it, similar to the planets around the Sun. The centripetal force that keeps the electrons in circular motion around the nucles is provided by the electrostatic force between the electrons and the nucleus.
Answer:
Fg = G M m / R^2 the gravitational force (M proton, m electron)
Fe = K e^2 / R^2 the electrical force where K = 9 *10E9 and e = charge
Fe / Fg = K e^2 / (G M m)
Fe / Fg = 9 * 10E9 * (1.6 * 10E-19)^2 / (6.67 * 10E-11 * 1.67 * 10E-27 * 9.11 * 10E-31
9 * 1.6^2 / (6.67 * 1.67 * 9.11) * 10^-29 / 10^-69
= 2.27 * 10E39 for the ratio of the two forces
let a_2a 2 be recessive, let qq be the frequency of the a_2a 2 allele, and let there be selection against the a_2a_2a 2 a 2 genotype. in that case, q=1q=1 is a/an
Answer:If the a2a2 genotype experiences selection against it, then its frequency will decrease in subsequent generations. Assuming the selection is strong enough, the genotype may be eliminated from the population altogether.
In this scenario, q represents the frequency of the a2 allele, and q=1 would mean that the a1 allele has been fixed in the population. This implies that there are no more a2 alleles left in the gene pool, and all individuals are homozygous for the a1 allele.
Therefore, q=1 is an indication of complete fixation of the a1 allele in the population, and the a2 allele has been lost due to selection against the a2a2 genotype.
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what is the momentum of an animal with a mass of 72kg who is moving with a velocity of 2.2 m/s
Answer:
The answer is
158.4 kgm/sExplanation:
The momentum of an object when given it's mass and velocity can be found by using the formula
momentum = velocity × massFrom the question
velocity = 2.2 m/s
mass = 72 kg
The momentum is
momentum = 2.2 × 72
We have the final answer as
158.4 kgm/sHope this helps you
A 24 kg child sits on a 2.0-m-long rope swing. You are going to give the child a small, brief push at regular intervals.
time should you wait between pushes is 2.83 sec.
the question is incomplete, full statement is-
A 24 kg child sits on a 2.0-m-long rope swing. You are going to give the child a small, brief push at regular intervals. If you want to increase the amplitude of her motion as quickly as possible, how much time should you wait between pushes?
What is Amplitude?In physics, amplitude refers to the greatest displacement or distance that a point on a vibrating body or wave may move relative to its equilibrium location. It is equivalent to the vibration path's half-length.
regular interval - at similarly spaced intervals: having the same interval of time between occurrences From 4 a.m. to midnight, the buses operate at regular intervals. The boards are positioned at regular intervals, with an equal amount of space between each.
The length of swing, l = 2.1 m
The time between the pushes is nothing but the Time period
and is given by the formula,
\(T = 2\pi ( \frac{l}{g} )^{\frac{1}{2} }\)
= 2 * 3.14 ( 2.0/ 9.8 ) ^ (1/2)
= 2.83 sec
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What is the mass of an object traveling at 30. m/s if it has 33,750 J of energy?
Answer:
\(30 \div 33750 = 0.008888\)
Is it necessary to convert time in its S.I unit while solving acceleration and velocity numericals
Answer:
yes
Explanation:
In any calculation, we make sure we use all quantity in it simplest s.i unit
for better understandingfor a clearer work analysisHope this will help
Explain why cookies baked
near the turned-up edges of a cookie sheet receive
more energy than those baked near the center do.
Answer:
It's all about the conduction between the pan and the cookies.
Explanation:
The cookies in the middle of the pan are not going to be cooked as much as the cookies touching both the bottom of the pan and the side of the pan due to the level of heat being given to those outside cookies. Lets try an example:
Lets say you're in a car in the middle of summer. You and your sibling sit on opposite sides of your other sibling, who is sitting in the middle seat. You and your other sibling are pressed up against the door of the car, making you heat up quicker since not only is it hot in the car, the sun is also on you. Meanwhile your other sibling isn't getting as much heat (but is still warm).
I hope this was able to help! There weren't any answers listed, so it may be the following:
- Conduction of heat
- Transfer of heat
- The pan heating up more of the cookie
- The conversion of more heat energy to the outside cookies
Good luck!
At what temperature does a process with [delta]h = 20. kj and [delta]s = 300. j become spontaneous? (give the answer in 3 sig figs)
The Temperature at a process with ΔH and ΔS become spontaneous is 66.6k
Gibbs free energy - It can be defined as that can be used to calculate the amount of work done performed by a closed system at constant temperature and pressure.
It's symbol is G.
Gibbs free energy equation is given as
ΔGΔH−TΔS
where
ΔG = Gibbs free energy.
ΔH = Enthalpy change.
T = Temperature in Kelvin.
ΔS = Entropy change.
ΔH= 20kJ = 20000J
ΔS= 300J/K
if ΔG<0, process is spontaneous
if ΔG>0, process is non spontaneous
if ΔG=0, process is in equilibrium
To find the temperature at which the given reaction becomes spontaneous, the minimum T value for which we obtain a negative value of the Gibbs free energy change is
ΔH−TΔS > 0
T > ΔH/ΔS
We have ΔH=20kJ=20000J
ΔS= 300J/K
T > 20000/300
T> 66.6K
The Temperature at a process with ΔH and ΔS become spontaneous is 66.6k
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A square nonconducting plate, 2a on a side, has a total charge Q uniformly spread over its surface. Calculate the electric field vector E at distance z above the plate's center. Use the electric field at a distance z above the midpoint of a line of charge of length 2L as a shortcut when solving.
Answer:
E' = Qa/4πε[√(a² + z²)]³
Explanation:
Since the non-conducting plate is symmetric, a small charge element dq generates an electric field dE at a distance R from itself and a distance z above the center of the plate. Since the plate is symmetric, we only have the vertical component of the electric field acting at the center so dE' = dEcosθ where θ is the angle between R and the plate.
So, dE' = dEcosθ = dqcosθ/4πεR²
Let σ represent the surface charge density of the plate. So, for a small elemental area dA, dq = σdA.
Substituting this into dE' we have
dE' = σdAcosθ/4πεR²
Also cosθ = a/R where a is half the length of side of the plate of side length, 2a.
So, dE' = σdAa/4πεR³
Also R² = a² + z²
R = √(a² + z²)
So, dE' = σdAa/4πε[√(a² + z²)]³
Now, dA = dxdy
dE' = σadxdy/4πε[√(a² + z²)]³
So, the total electric field at z is obtain by integrating dE'
E' = ∫dE' = ∫σadxdy/4πε[√(a² + z²)]³ = σa∫dxdy/4πε[√(a² + z²)]³
We integrate dx and dy from -a to a.
So,
E' = σa[2a][2a]/4πε[√(a² + z²)]³
E' = σa³/πε[√(a² + z²)]³
Since the total chare Q = σA where A is the are of the plate. A = (2a)² = 4a²
Q = σA = 4σa²
σ = Q/4a²
substituting σ into E', we have
E' = (Q/4a²)a³/πε[√(a² + z²)]³
E' = Qa/4πε[√(a² + z²)]³
the force on a dropped apple hitting the ground depends upon
Answer:
F=ma
Explanation:
Force = mass * acceleration
Which factors affect the flow of electric charge? select two options. Voltage ampere ohm resistance volt.
According to Ohm's law: V = IR
The rate of flow of charges will depend on the voltage supplied and the resistance in the wire.
ELECTRIC CHARGE
Current can be defined as the rate of flow of charges. Where charge is the product of current and time. This means that electric charge is proportional to electric current. The current in a conducting wire depends on;
Length of the wireCross sectional area of the wireNature of the wireThe voltage suppliedThe two factors that can affect the flow of electric charge in the given options are voltage and resistance
Because according to Ohm's law: V = IR
The rate of flow of charges will depend on the voltage supplied and the resistance in the wire.
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Answer:
A. and D.
Explanation: Identifying Factors That Affect Current
Which factors affect the flow of electric charge? Select two options.
[voltage]
ampere X
ohmX
[resistance]
volt X
The asteroid belt exists between the orbits of the planets ______ and ______.
The asteroid belt exists between the orbits of the planets Mars and Jupiter.
Between Mars and Jupiter's orbits is where the asteroid belt is located. It also has a few small planets and a lot of asteroids. In the past, the asteroid belt between Mars and Jupiter contained planets and their moons. They were wiped out by some sort of disease. The belt of asteroids may contain their fragmented remains. As a result, the asteroids' motion around Jupiter and Mars is accelerated by their combined gravitational pull. Asteroids go by many names, including Ceres, Vesta, Pallas, and Hygiea. Rock fragments from the early solar system are dispersed in orbits around the sun within the main asteroid belt.
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A lab team was collecting data on the amplitude and energy of a mechanical
wave, as shown in the data table. They forgot to record one data point.
Analyze the data to identify the mathematical relationship between amplitude
and energy. Calculate the missing data point.
Amplitude
6 units
7 units
8 units
9 units
10 units
OA. 158
B. 162
O O O
C.
164
OD. 160
Energy
72 units.
98 units.
128 units.
? units.
200 units
The missing data point is 162 units for Energy when the Amplitude is 9 units.
How do we calculate?The mathematical relationship between amplitude and energy of a mechanical wave is given by the equation below:
Energy = k * Amplitude^2
we have that k is a constant of proportionality.
We will solve for the missing data point by using the equation.
We can find the value of k by using two of the known data points:
k = Energy / Amplitude^2
k = 72 / 6^2 = 72 / 36 = 2
Therefore, the missing data point:
Energy = k * Amplitude^2 = 2 * 9^2 = 2 * 81 = 162 units
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PLEASE HELP ME, IM STUCK ON THIS QUESTION
Answer:
the correxct adnswer is d
Explanation:
lol
In this Assessment we will recreate one of the 20th Century's biggest astronomical discoveries: the unveiling of the first planet known to orbit a sunlike star other than our own. In 1995 two teams of astronomers published Doppler-wobble data for 51 Pegasi, a star in the constellation Pegasus that can be seen with the unaided eye on clear, dark nights. Let's analyze a Doppler-wobble plot for 51 Pegasi to learn what we can about its history-making companion. 51 Pegasi Experiment Procedure Measure the time (in hours) for two adjacent minima (or "valleys") in 51 Pegasi's Doppler plot. tleft = 36 Correct: Your answer is correct. hours tright = 140 Correct: Your answer is correct. hours From these values, calculate the orbital period, P, for 51 Pegasi's planet. (Enter your answer in hours.) 103.76 Correct: Your answer is correct. hours Convert this period into units of seconds. 373536 Correct: Your answer is correct. seconds Now measure the minimum and maximum velocity (in meters per second) from 51 Pegasi's Doppler plot. vmin = -57.24 Correct: answer is correct. m/s vmax = 63.38 Correct: Your answer is correct. m/s From these values, calculate the semiamplitude, K, of 51 Pegasi's velocity range. (Enter your answer in m/s.) 60.31 Correct: Your answer is correct. m/s Divide the period (in seconds) by the constant 4.19 ✕ 10−10 N · m2/kg2. Then take the cube root of that ratio. (Enter your answer in ((s · kg2)/(N · m2))1/3 .) 96200 Correct: Your answer is correct. s · kg2 N · m2 1/3 Take the 2/3 root of 51 Pegasi's mass. (Enter your answer in kg2/3.) 1.65 Incorrect: Your answer is incorrect. kg2/3 Calculate the product of the last three answers. This is the minimum mass of 51 Pegasi's planet (mP sin(i)), in kilograms. kg Divide your answer to the previous question by Jupiter's mass, mJ = 1.9 ✕ 1027 kg. mP sin(i) mJ = Which one of the following statements most accurately summarizes your findings? The star 51 Pegasi has a mass that is less than Jupiter's. The star 51 Pegasi has a planet whose minimum mass is less than Jupiter's. The star 51 Pegasi has a planet whose mass is less than Jupiter's.
The star 51 Pegasi has a planet whose minimum mass is less than Jupiter's.
What is planet?A planet is a celestial body orbiting a star or stellar remnant that is massive enough to be rounded by its own gravity, is not massive enough to cause thermonuclear fusion, and has cleared its neighbouring region of planetesimals. The eight planets in the Solar System are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune. Historically, planets were thought to be divine bodies that governed fate and human affairs.
This statement is accurate because the calculation we performed yielded a minimum mass of 51 Pegasi's planet, mP sin(i), that is less than Jupiter's mass, mJ.
The calculation was done by taking the product of the cube root of the period in seconds divided by the constant 4.19 ✕ 10−10 N ·
m2/kg2, the 2/3 root of the mass of 51 Pegasi, and the semiamplitude, K, of the velocity range.
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coupling occurs when the energy released by an exergonic reaction is
Coupling occurs when the energy released by an exergonic reaction is used to drive an endergonic reaction.
Match the vocabulary words to its correct definitions.
Column A
2.
3.
पं
5.
6.
The combination of fat-free mass and fat mass
The ability of the heart, blood, blood vessels and
lungs to supply enough oxygen and necessary
fuel to the muscles during long periods of
physical activity
The muscles ability to move a joint through a
full range of motion
The ability of a muscle or muscles to repeat a
movement many times or hold a position
without stopping to rest
The ability of a muscle or muscles to push or
pull with its total force
An activity that places an additional force
against the muscle or muscle group
Column B
a. Muscular Endurance
b. Body composition
c. Flexibility
d. Muscular Strength
e. An activity that places an additional force against the
muscle or muscle group
f. Resistance Training
g. Cardiorespiratory Endurance
2. The ability of the heart, blood, blood vessels, and lungs to supply enough oxygen and necessary fuel to the muscles during long periods of physical activity - g. Cardiorespiratory Endurance.
What are the muscles?
Muscles are specialized tissues in the human body that are responsible for movement, stability, and maintaining posture. There are three types of muscles in the body: skeletal, cardiac, and smooth muscles.
3. The muscle's ability to move a joint through a full range of motion - c. Flexibility
पं - This word is not provided in the question.
4. The ability of a muscle or muscles to repeat a movement many times or hold a position without stopping to rest - a. Muscular Endurance
5. The ability of a muscle or muscles to push or pull with its total force - d. Muscular Strength
An activity that places an additional force against the muscle or muscle group - f. Resistance Training
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two uniform solid cylinders, each rotating about its central (longitudinal) axis at 235 rad/s, have the same mass of 1.25 kg but differ in radius. what is the rotational kinetic
The rotational kinetic of the two rotating solid cylinders is 44.2 (r₁²+r₂²). The result is obtained by inserting total inertia value in rotational kinetic equation.
How to get moment of inertia and rotational kinetic value?The moment of inertia of a solid cylinder can be expressed as
\(I = \frac{1}{2} mr^{2}\)
Where
I = moment of inertia (kg.m²)m = mass (kg)r = radius (m)If there are two of more cylinders, the total moment of inertia would be
\(I = I_{1} + I_{2} + ...\)
The kinetic energy of a rotating body can be expressed as
\(E_{rot} = \frac{1}{2} I \omega^{2}\)
Where
If given
ω = 235 rad/sm₁ = m₂ = m = 1.25 kgWhat is the rotational kinetic energy?
We first calculate the moment of inertia of the two cylinders.
\(I = \frac{1}{2} m_{1} r_{1}^{2} + \frac{1}{2} m_{2}r_{2}^{2}\)
\(I = \frac{1}{2} m r_{1}^{2} + \frac{1}{2} mr_{2}^{2}\)
\(I = \frac{1}{2} m (r_{1}^{2} + r_{2}^{2})\)
\(I = \frac{1}{2} \times 1,25 (r_{1}^{2} + r_{2}^{2})\)
\(I = 0,625 (r_{1}^{2} + r_{2}^{2})\)
Then, the rotational kinetic energy is
\(E_{rot} = \frac{1}{2} I \omega^{2}\)
\(E_{rot} = \frac{1}{2} \times 0,625 (r_{1}^{2} + r_{2}^{2}) \times \omega^{2}\)
\(E_{rot} = \frac{1}{2} \times 0,625 (r_{1}^{2} + r_{2}^{2}) \times 235^{2}\)
\(E_{rot} = 117.5 \times 0.625 (r_{1}^{2} + r_{2}^{2}) \times 235\)
\(E_{rot} = 44.2 (r_{1}^{2} + r_{2}^{2}) Joule\)
Hence, the rotational kinetic energy of the two rotating solid cylinders is 44.2 (r₁²+r₂²).
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Elements grouped as a column on the periodic table belong to a ______.
a 0.4m rod of some material elongates 0.1 mm on heating from 30 to 118. determine the value of the linear coefficent of thermal expansion
The value of the linear coefficient of thermal expansion is : α= 2.841 * 10⁻⁶ (ºC)⁻¹
Li = 0.4m
ΔL = 0.1 mm = 0.0001m
T1 = 30ºC
T2 = 118ºC
ΔT = 88ºC
α =ΔL/(Li*ΔT)
α =0.0001m /(0.4m * 88ºC)
α = 2.841 * 10⁻⁶ (ºC)⁻¹
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please help with this
Answer:
it is
option A . Tuberculosis ✔
23 and 24 only please help!
Answer:
23: Acceleration 24:1m/s^2
Explanation:
\(a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2\)
A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact southeast with a force of . The sailboat travels the distance in 1.0 h. How much work was done by the wind? What was the wind’s power? Your response should include all of your work and a free-body diagram.
Given that the direction sailboat is north and the distance traveled is d = 10 km
The direction of the wind is southeast and the force is
\(F\text{ =2}\times10^4\text{ N}\)The sailboat travels the distance in time, t = 1 h
We have to find the work done by the wind and wind's power.
The diagram is shown below
The work done by the wind will be
\(\begin{gathered} W\text{ =Fdcos}\theta \\ =2\times10^4\times10\times10^3\times\cos (135^{\circ}) \\ =-1.414\times10^8\text{ J} \end{gathered}\)The power of the wind will be
\(\begin{gathered} P=\frac{W}{t} \\ =\frac{-1.414\times10^8}{1\times60\times60} \\ =-3.93\times10^4\text{ W} \end{gathered}\)
PLEASE HELP! I know the answer to this, but I need an explanation.
Let r be the distance between the man and point Q. He applies a torque of
(r i ) × ((-800 N) j ) = ((-800 N) r ) k
pointing "into the page" with magnitude (800 N) r.
Meanwhile, the rope applies a torque of
((3.0 m) i ) × ((500 N) j ) = (1500 N•m) k
pointing out of the "page" with mag. 1500 N•m
The beam is held in place in a horizontal position, so the torques cancel and
(800 N) r = 1500 N•m
r = (1500 N•m)/(800 N) = 1.875 m ≈ 1.9 m
if you drop a rock from a height of 17m, it accelerates at g and stikes the ground 1.86263s later. If you drop the same rock from half the height, what will be the acceleration?
If you drop the same rock from half the height, the acceleration will be 4.9 m/s².
Acceleration of the object
The acceleration of the object dropped from half of the given height is calculated as follows;
h = vt + ¹/₂at²
where;
v is the initial velocity of the objecta is the acceleration of the objectt is time of motionh = 0 + ¹/₂at²
h = ¹/₂at²
2h = at²
a = 2h/t²
a = (2 x 0.5h)/t²
a = (h)/(t²)
a = (17 m) / (1.86263²)
a = 4.9 m/s²
Thus, if you drop the same rock from half the height, the acceleration will be 4.9 m/s².
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The Washington Monument is 169 meters tall.
A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the monument. A nickel with a mass of 0.005 kg is in her shirt pocket.
Q: If the nickel accidentally falls out of her pocket, what will happen to the gravitational potential energy (GPE) of the nickel as it falls to the ground?
The gravitational potential energy (GPE) of the nickel will increase as it falls to the ground due to the force of gravity acting on it.
When an object falls, it gains kinetic energy, which is the energy of motion. As an object falls, it gains kinetic energy at the expense of its potential energy.
The amount of GPE gained will be equal to the mass of the nickel multiplied by the acceleration due to gravity and the change in height from the worker's pocket to the ground. Specifically, the change in GPE = 0.005 kg \(* 9.8 m/s^2 * 169\)* m. As the nickel falls it will accelerate and its kinetic energy will increase as well. The nickel will convert the potential energy into kinetic energy and also will gain velocity as it falls, reaching a terminal velocity.
When the nickel reaches the ground, all of its potential energy will have been converted into kinetic energy.
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please help the picture is above !
Answer:
its C- 20
Explanation:
A 1,470.39 N rocket travels at constant speed for 1,522.64m in 2.11 seconds. What is the kinetic energy of the rocket?
Given data:
* The weight of the rocket is 1470.39 N.
* The distance traveled by the rocket is 1522.64 m.
* The time taken by the rocket is 2.11 seconds.
Solution:
The velocity of the rocket in terms of the distance and time is,
\(\begin{gathered} v=\frac{\text{distance}}{\text{time}} \\ v=\frac{1522.64}{2.11} \\ v=721.63\text{ m/s} \end{gathered}\)The mass of the rocket from the weight is,
\(\begin{gathered} mg=1470.39 \\ m=\frac{1470.39}{g} \end{gathered}\)where g is the acceleration due to gravity,
Substituting the known values,
\(\begin{gathered} m=\frac{1470.39}{9.8} \\ m=150.04\text{ kg} \end{gathered}\)The kinetic energy of the rocket in terms of mass and velocity of the rocket is,
\(\begin{gathered} K=\frac{1}{2}mv^2 \\ K=\frac{1}{2}\times150.04\times721.63^2 \\ K=39066654.26\text{ J} \\ K=39.07\times10^6\text{ J} \\ K=39.07\text{ MJ} \end{gathered}\)Thus, the kinetic energy of the rocket is 39.07 MJ.
An electron accelerates from 0 to 10 Ã 104 m/s in an electric field. Through what potential difference did the electron travel? The mass of an electron is 9. 11 Ã 10â31 kg, and its charge is â1. 60 Ã 10â19 C
According to the claim made, the electron moved across a potential difference of 2.84 * 10⁻² V.
Explain what the electric field is.Each spot in space has an electric field associated with it when there is charge current in any form. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the direction and intensity of the electromagnetic field.
Briefing:Given;
Velocity, v = 10 * 10⁴ m/s = 10⁵ m/s
Potential difference, V = ?
Mass of electron = 9.11 * 10⁻³¹ kg
Charge of electron, q = 1.60 * 10⁻¹⁹C
The KE of an electron is the amount of energy in an electric field.
Thus, qV = 1/2mv²
Therefore, V = mv²/2q
Putting Values,
V = 9.11 * 10⁻³¹ * 10⁵ * 10⁵/2 * 1.6 * 10⁻¹⁹
= 9.11 * 10⁻²¹/3.2 * 10⁻¹⁹
V = 2.84 * 10⁻²
Thus, Potential difference is 2.84 * 10⁻² V
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_SF4 + _H2O -> _H2SO3 + _HE
Answer:
SF4 + 3H2O → H2SO3 + 4HF
Explanation:
I found it