In 1–2 sentences, describe the relationship between heat and thermal insulators.(2 points)
A baker uses oven mitts to open an oven, take a loaf of bread out, and place it on a plate. In 3–4 sentences, identify three examples of thermal energy transfer in the scenario.(4 points)

Answer:

A) Availability

Explanation:

Right on Edge 2021

Answer:

Availability

Explanation:

edge

The content of the esp register is 00 63 fb 60. If the push ebx instruction is executed, the content of the esp register will change and the new content will be 00 63 fb 5c.

When the instruction "push ebx" is executed, the contents of the ebx register are stored onto the stack, and the stack pointer (esp) is decremented by the size of the data being pushed, which in this case is 4 bytes for a 32-bit register.

In the given scenario, the initial content of the esp register is 00 63 fb 60. After executing the "push ebx" instruction, the value of ebx is pushed onto the stack, resulting in the new content of the esp register being 00 63 fb 5c.

This change occurs because the original value of esp (0x60) is decremented by 0x04 (4 in hexadecimal), leading to the updated value of esp being 0x5c.

Therefore, the content of the esp register after executing the "push ebx" instruction will be 00 63 fb 5c.

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Answer:

a.200 Newtons

Explanation:

Given the following data;

Mass = 20kg

Acceleration = 10m/s²

To find the force;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

\( F = ma\)

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Substituting into the equation, we have

\( Force = 20 * 10 \)

Force = 200 Newton.

The extensions of the middle and lower springs are 0.3209 m and 0.1988 m, respectively, from their unstretched lengths.

We can solve this problem using the concept of equilibrium and the equations of motion. In equilibrium, the weight of each mass is balanced by the force exerted by the spring, so we have:

m₁g = kx₁

m₂g = kx₂

m₃g = kx₃

where g is the acceleration due to gravity, k is the spring constant, and x₁, x₂, and x₃ are the extensions of the three springs from their unstretched lengths.

When the elevator is moving with constant velocity, the forces on the masses are still balanced, so the extensions of the springs are unchanged. However, when the elevator is accelerating, the forces on the masses are no longer balanced, and the extensions of the springs will change. We need to take into account the pseudo-force experienced by the masses due to the acceleration of the elevator.

The pseudo-force on each mass is given by:

F' = m × a

where m is the mass of the object and a is the acceleration of the elevator. For m₁, m₂, and m₃, the pseudo-forces are:

F₁' = m₁a = 3.3 kg × 4.8 m/s² = 15.84 N

F₂' = m₂a = 9.9 kg × 4.8 m/s² = 47.52 N

F₃' = m₃a = 6.6 kg × 4.8 m/s² = 31.68 N

To calculate the new extensions of the springs, we need to add the pseudo-forces to the weights of the masses and then divide by the spring constant. For the upper spring, which is attached to m₁, we have:

kx₁ = m₁g + F₁'

x₁ = (m₁g + F₁')/k

Substituting the values, we get:

x₁ = (3.3 kg × 9.81 m/s² + 15.84 N)/(229.57 N/m) = 0.1003 m

So the upper spring is extended by 0.1003 m from its unstretched length.

For the other two springs, we have:

x₂ = (m₂g + F₂')/k = (9.9 kg × 9.81 m/s² + 47.52 N)/(229.57 N/m) = 0.3209 m

x₃ = (m₃g + F₃')/k = (6.6 kg × 9.81 m/s² + 31.68 N)/(229.57 N/m) = 0.1988 m

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The angular acceleration of the potter's wheel is 0.067 rad/s².

The given parameters:

The angular acceleration of the potter's wheel is calculated as follows;

\(\alpha = \frac{\Delta \omega }{t} \\\\\alpha = (0.4\ rev/s \times \frac{2 \pi \ rad}{1 \ rev} ) \times \frac{1}{37.5 \ s} \\\\\alpha = 0.067 \ rad/s^2\)

Thus, the angular acceleration of the potter's wheel is 0.067 rad/s².

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Answer:

El delfín nada a una profundidad de 22 m

Explanation:

El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.

Esto se expresa como:

P=ρ⋅g⋅h

donde:

En este caso:

Reemplazando:

2.22*10⁵ Pa= 1,030 \(\frac{kg}{m^{3} }\) * 9.8 \(\frac{m}{s^{2} }\) * h

Resolviendo:

\(h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}\)

h= 21.993 m ≅ 22 m

El delfín nada a una profundidad de 22 m

Answer:

3,000 m/s

Explanation:

3,000 m/s

I am a field physicist and I perform QA measurements of various types of X-ray units. Due to recent changes in legal requirements in my country, we have to provide the radiation output value for each unit tube measured in m Gy MA's at 1 meter from focal spot) at filtration of 2,5 mm Al equivalent. a. True

This unfortunately cannot be directly achieved for interventional radiology units, some CTs and occasionally other types of X-ray units. A filter of 2 mm of aluminum will absorb the soft, or less penetrating, radiation. Aluminum is often used as a filter in radiography because it effectively absorbs low-energy, soft X-rays, while allowing more penetrating, higher-energy X-rays to pass through. This helps improve image quality and reduce patient exposure to unnecessary radiation.

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A circular coil of wire has 300 turns and an average radius of 2:00 cm. The coil is placed at a 60° angle to the uniform magnetic field between the two poles of a large electromagnet. The strength of the field changes at a rate of -0.300 T/s. The magnitude of the resulting induced emf in the circular coil is zero.

To calculate the magnitude of the resulting induced electromotive force (emf) in the circular coil, we can use Faraday's law of electromagnetic induction, which states that the emf induced in a circuit is equal to the rate of change of magnetic flux through the circuit.

The magnetic flux (Φ) through a coil of wire is given by the product of the magnetic field strength (B), the area of the coil (A), and the cosine of the angle (θ) between the magnetic field and the normal to the coil:

Φ = B * A * cos(θ)

In this case, the magnetic field strength (B) is changing at a rate of -0.300 T/s, the area of the coil (A) can be calculated using the formula for the area of a circle (A = π *\(r^2\)), and the angle (θ) is 60 degrees.

First, let's calculate the area of the coil:

A = π * \(r^2\)

A = π *\((0.02 m)^2\)

A =\(0.0012566 m^2\)

Next, let's calculate the rate of change of magnetic flux:

dΦ/dt = B * dA/dt * cos(θ)

dΦ/dt = (-0.300 T/s) * (0) * cos(60°)   (since the area does not change with time)

Finally, the induced emf (ε) is equal to the negative of the rate of change of magnetic flux:

ε = -dΦ/dt

ε = -0

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Answer:

16m/s

Explanation:

Mv=mv

5000x8=2500x v

V=5000x8/2500

V=40000/2500

= 16m/s

A third charge, Q = -8.3 µC, can be placed at approximately x = 0.96 m along the positive x-axis such that the resultant force on it is zero.

To determine the position along the positive x-axis where the resultant force on the third charge is zero, we need to consider the electric forces exerted by charges q1 and q2 on charge Q. The electric force between two charges is given by Coulomb's law: F = k * (|q1| * |q2|) / r^2, where k is the electrostatic constant, |q1| and |q2| are the magnitudes of the charges, and r is the distance between them.

First, we calculate the force exerted by q1 on Q. Since both charges have the same sign, the force is repulsive. The force exerted by q2 on Q is attractive due to the opposite signs of the charges. To cancel out these forces, the magnitudes of the forces must be equal. Therefore, we can set up the following equation:

(k * |q1| * |Q|) / r1^2 = (k * |q2| * |Q|) / r2^2,

where r1 is the distance between q1 and Q, and r2 is the distance between q2 and Q. By substituting the given values, we can solve for r2:

(9 * 10^9 N m^2/C^2 * 2.9 * 10^-6 C) / (r1^2) = (9 * 10^9 N m^2/C^2 * 7.3 * 10^-6 C) / ((0.20 + r1)^2).

Simplifying and solving this equation yields r1 ≈ 0.96 m. Therefore, a third charge, Q = -8.3 µC, can be placed at approximately x = 0.96 m along the positive x-axis to experience a net force of zero due to the balance of the forces exerted by q1 and q2.

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The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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Answer:

Ossicles

Explanation:

They send the sound waves to the inner ear and into the fluid-filled hearing organ (cochlea). Once the sound waves reach the inner ear, they are converted into electrical impulses.

The "hair cells" in the cochlea of the inner ear convert sound vibrations into electrical impulses.  Up to that point, it's all mechanical vibrations.

The answer to the question, "What is something that you use almost every day that is a polymer?" is:D) plastic
Plastic is the most common example of a polymer that we use daily in various forms, such as bags, bottles, and containers.

Polymers are materials made up of repeating units or monomers, and plastic is one of the most common types of polymers used in everyday life. Plastic can be found in items such as water bottles, food containers, and packaging materials. It is a versatile material that can be molded into various shapes and forms, making it a popular choice for many applications.

Plastic is a polymer, which means it's composed of long chains of molecules. Other options are incorrect because:

A) Metal is not a polymer; it's an element or an alloy of different elements.
B) Gas is a state of matter and not a polymer.
C) Water is a compound  and not a polymer.
E) Wood is a natural material mainly composed of cellulose, which is a natural polymer, but it is not a primary example of a polymer when compared to plastic.

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Answer:

The final velocity of the train and the moose after collision is approximately 19.51 m/s

Explanation:

The given mass of the moose, m₁ = 250 kg

The velocity of the moose, v₁ = 0

The mass of the oncoming train, m₂ = 10,000 kg

The velocity of the train, v₂ = 20 m/s

The velocity of the moose and the train after collision = v₃

By the principle of conservation of linear momentum, the total initial momentum before the collision = The total final momentum after collision

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Therefore, by substitution, we have;

250×0 + 10,000× 20 = (10,000 + 250) × v₃

200,000 = 10,250 × v₃

v₃ = 200,000/10,250 ≈ 19.51 m/s

The final velocity of the train and the moose after collision = v₃ ≈ 19.51 m/s

Answer:

2,450

400

Explanation:

Pls brainliest me

The carbon cycle involves both biotic (living) and abiotic (non-living) components.

Abiotic components of the carbon cycle include:

Atmosphere: The atmosphere is a major abiotic component of the carbon cycle. Carbon dioxide (CO2) is a greenhouse gas that makes up a small percentage of Earth's atmosphere (currently around 0.04%). Carbon dioxide is released into the atmosphere through processes such as respiration, combustion of fossil fuels, and volcanic eruptions. It can also be absorbed from the atmosphere through processes such as photosynthesis and dissolution in bodies of water.

Oceans: The world's oceans are a significant abiotic component of the carbon cycle. They act as a sink for carbon dioxide, absorbing large amounts of it from the atmosphere. Carbon dioxide dissolves in seawater to form carbonic acid, which can then undergo various chemical reactions to form bicarbonate ions and carbonate ions. These dissolved forms of carbon can be transported and stored in the deep ocean for long periods of time, a process known as oceanic carbon sequestration.

Soil: Soil is another abiotic component of the carbon cycle. Dead plant material and other organic matter that accumulates in soil can undergo decomposition by microorganisms, releasing carbon dioxide back into the atmosphere through a process called soil respiration. Additionally, carbon can be stored in soil as organic carbon, which can remain in the soil for years to centuries depending on environmental conditions.

Geological formations: Carbon can also be stored in abiotic reservoirs such as geological formations, including fossil fuels such as coal, oil, and natural gas. These fossil fuels are formed from ancient organic matter that has been buried and preserved in the Earth's crust over millions of years. When these fossil fuels are burned for energy, carbon is released into the atmosphere as carbon dioxide, contributing to the increase in atmospheric carbon dioxide concentrations.

These abiotic components of the carbon cycle play a crucial role in regulating the balance of carbon between the atmosphere, oceans, soil, and geological formations, and are important in understanding the overall carbon cycle and its impact on the Earth's climate.

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The bicycle will experience more force.

Force is the intensity by which an object is pushed or pulled.

Let the mass of the pedestrian = M kg

Let the mass of bicycle = m kg

Also M > m

The more the mass the more will be the force exerted on the opposite object.

Therefore the bicycle will experience more force when both of them collided in the street.

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Answer:  Radio waves, Microwaves infrared, optical ultraviolet, X-rays and gamma-rays

Answer:

A battery is a device that stores chemical energy and converts it to electrical energy.

The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit.

The flow of electrons provides an electric current that can be used to do work.

To balance the flow of electrons, charged ions also flow through an electrolyte solution that is in contact with both electrodes.

Different electrodes and electrolytes produce different chemical reactions that affect how the battery works, how much energy it can store and its voltage.

Based on the given diagram, the change of state that occurs when a gas is cooled is condensation.

Condensation is the process in which a gas or vapor transitions into a liquid state due to a decrease in temperature. It is represented by the arrows pointing from the water vapor to the liquid drop in the diagram. Cooling the gas causes the vapor molecules to lose energy and come together to form liquid droplets. The change of state that occurs when a gas is cooled is condensation. In the given diagram, the arrows from right to left indicate the transition from water vapor (gas) to liquid drop, which represents condensation.

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The torque that will bring the balls to halt, t = 0.34 Nm

What is rotating?

In physics and mechanics, torque is the rotational equivalent of linear force. It is also referred to as the moment, moment of force, rotational force, or turning effect, depending on the field of study. It represents the capability of a force to produce a change in the rotational motion of the body.

Center of Mass of Rod = (1 * 0 + 2.0 * 1.1) /(1.0 + 2.0)

Center of Mass of Rod = 0.73 m

ω  = 21 rpm

ω = 21 * (2*pi)/60 rad/s

ω = 2.2 rad/s

Time to bring Halt = 5.2 s

Angular De-acceleration = 2.2/5.2 rad/s^2

α  =  0.423 rad/s^2

We know,

torque = (moment of inertia) * (angular acceleration)

t = I * α

Where

I = m1*r1^2 + m2*r2^2

I = 1kg * (0.73)^2 + 2kg * (1.1-0.73)^2

I = 0.8067 kg*m^2

Substituting Values -

torque = 0.8067  Kg*m^2 * 0.423 rad/s^2

torque = 0.34 N*m

The torque that will bring the balls to halt, t = 0.34 Nm

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Total angular velocity is 13.7 rad/s.

Given that an object is moving in a circular motion, we can infer that the system involving the athlete, the ball, and the rope is also moving in a round fashion.

We are informed that the athlete is 181 cm tall, has a 90 cm arm span, and will be using a 121 cm long ball and chain for the competition. With both arms hanging on to the ball and chain handle as the athlete starts to spin, their body becomes the centre of the action. The ball and chain's initial linear velocity is 29 m/s when it is released.

The radius of the path= 90 cm + 121 cm

                                    = 211cm or 2.11 m

Using;
linear velocity = radius * angular velocity

V = rω

ω = V/r

ω =  29m/s/2.11 m

ω = 13.7 rad/s

angular velocity of athlete is 13.7 rad/s

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(a) The torque on the flywheel is 117.6 N·m.

(b) The angular momentum of the flywheel after 2.5 s will depend on the rotational speed, which requires additional information.

(a) The torque on the flywheel can be calculated using the formula:

Torque = Force × Distance

The force acting on the flywheel is the weight of the load, which is given by:

Force = mass × gravity

Force = 2.0 kg × 9.8 m/s² = 19.6 N

The distance from the axis of rotation to the point where the force is applied is the radius of the flywheel, which is given as 50 cm or 0.5 m.

Torque = 19.6 N × 0.5 m = 9.8 N·m

Therefore, the torque on the flywheel is 9.8 N·m.

(b) To calculate the angular momentum after 2.5 seconds, we need to know the rotational speed of the flywheel. The angular momentum is given by:

Angular Momentum = Moment of Inertia × Angular Velocity

Since the moment of inertia is not given, we cannot calculate the angular momentum without additional information.

(a) The torque on the flywheel is 9.8 N·m.

(b) The calculation of the angular momentum after 2.5 seconds requires the knowledge of the rotational speed or the moment of inertia, which is not provided. Therefore, we cannot determine the exact value of the angular momentum without additional information.

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Answer:

The magma, molten rock under the surface, and lava (molten rock on the surface) harden into igneous rock. The igneous rock then breaks apart over time through the process of weathering.

Explanation:

If released from rest, the current loop will rotate counterclockwise. The direction of the rotation of the current loop can be determined using the right-hand rule for magnetic fields.

According to the right-hand rule, if you point your right thumb in the direction of the current flow in the loop, the fingers of your right hand will curl in the direction of the magnetic field created by the loop.

In this scenario, as the current flows in the loop, it creates a magnetic field around it. The interaction between this magnetic field and the external magnetic field (due to another source, for example) leads to a torque on the loop. The torque causes the loop to rotate.

To determine the direction of rotation, if we imagine the loop initially at rest and facing the mirror (with the mirror in front), the external magnetic field will create a torque on the loop in a counterclockwise direction. This torque will cause the loop to rotate counterclockwise.

Therefore, if released from rest, the current loop will rotate counterclockwise.

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