Think about making the 300-yard trip to the student union structure to have a snack after class. After travelling 300 yards again, you follow the same route back to the same classroom. Displacement is zero because you went back to the same classroom. This is the case since the beginning and finish locations are identical.
While displacement denotes the straight-line distance between the beginning and ending places, independent of the actual path taken, the distance covered refers to the total length travelled during the entire trip. In this instance, you travelled 300 yards to the student union building and then 300 more yards to return. The distance travelled is the sum of these two distances, as follows:
Distance covered = 300 yards + 300 yards = 600 yards
Instead of taking into account the actual route travelled, your displacement merely takes into account the straight-line distance between the beginning point (classroom) and the finishing point (classroom).
Displacement = 0 yards
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Trina conducted an experiment to determine the average amount of salt in 1 liter of ocean water by allowing the water to evaporate and measuring the remaining salt.
Her results are shown below.
Trial Salt
1 9.9 g
2 14.2 g
3 8.7 g
4 13.4 g
What is the mean weight of the salt precipitate?
A.
46.2 g
B.
11.7 g
C.
11.3 g
D.
11.5 g
Answer:
The answer is . A 46.2g
which has the greatest kinetic energy
Answer:
Asteroid y
Explanation:
what are two functions of ground tissue in plants
Answer: Ground tissue makes up much of the interior of a plant and carries out basic metabolic functions. Ground tissue in stems provides support and may store food or water. Ground tissues in roots may also store food.
Explanation:
At an amusement park water slide, people slide down an essentially frictionless tube. The top of the slide is 3.0 meters above the bottom where they exit the slide. (g = 10 m/s)
What kind of energy involved in this situation? Which kind of energy has changed to which?
Answer:
Explanation: Sorry sister
An asteroid on the earth's orbit experiences a free-fall acceleration which is 8.0 times smaller than it would be on the earth. what is the distance between the asteroid and the earth's surface measured in the earth's radii? neglect the gravity of the moon.
The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82 R
What are the Asteroids:
Asteroids are small, rocky objects that orbit the Sun. They are much smaller than planets.They are found between the orbits of Mars and Jupiter, though some have more eccentric orbits.here,
An asteroid experiences acceleration on earth's orbit which is 8.0 times smaller than it on the earth surface.
Free fall acceleration of Asteroid:
on earth's surface = gon earth's orbit = g' = g / 8so,
g' = GM /(R + x)^2 ------1
g = GM / R^2
g' = 1/8 ( GM / R^2 ) -------1
where G is gravitational constant
M is mass of earth
R is earth's radius
comparing both equations 1 and 2
GM /(R + x)^2 = 1/8 ( GM / R^2 )
8 R^2 = (R + x)^2
2√2 * R = R + x
x = R (2√2 - 1)
x = 1.82*R
hence, The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82*R
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Which of these objects has kinetic energy?
Answer:
A ball moving through the air.
Explanation:
The ball has momentum which is a form of kinetic energy.
I don't know if that is correct, but I hope it helps!!!!
A motorist drives 5 km east then drives 5 km north. Calculate their distance travelled and their displacement.
Answer:
See
distance is 10 km
displacement is 5√2 km
Explanation:
DISTANCE:
Distance is scaler so, it doesn't depend on the direction
so distance is 5+5 which is 10
DISPLACEMENT:
Displacement is a vector, so, it depends on direction.
Now when we see north and east, they form a right angle, so we need to calculate the hypotenuse of the triangle for displacement as it is the shortest route between the two points.
Let hypotenuse be h
5² + 5² = h² Moved 5 km in east and north so values are 5h² = 25+25h² = 50h = √50h=5√2Hope it helps
BYE.
A single celled organism is found in a sample of water. It contains a nucleus as well as other membrane bound organelles and possesses collagen for movement. This organism most likely belongs to which kingdom?
Answer:
Explanation:
The cell is the smallest living organism that contains all the features of life, and most all life on the planet begins as a single-cell organism. Two types of single-celled organisms currently exist: prokaryotes and eukaryotes, those without a separately defined nucleus and those with a nucleus protected by a celluA single-celled organism is found living in a deep sea vent at the bottom of the ocean in extremely hot water. If it is examined further, which of the following is most likely to be found within it? It will have DNA that is not contained in a nucleus since it is likely a member of the domain Archaea.lar membrane.
what term is used to describe the number of times a sound card takes to create the reproduction of the original sound?
The term used to describe the number of times a sound card takes to create the reproduction of the original sound is known as Sampling Rate.
What is Sampling Rate?In digital audio technology, sampling rate is the number of samples of audio carried per second. It is measured in Hertz or cycles per second, and it is typically represented as kHz or kilohertz. For example, a sampling rate of 44.1 kHz means that 44,100 samples of audio are carried in one second.
The higher the sampling rate, the more samples of audio are taken per second, which leads to better quality audio reproduction.
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1. Given that an audio signal is sampled at a rate of 1024 Hz,
find the file size of such audio file of stereo type but radio
quality with a duration of 1 minute.
The formula to calculate the file size of an audio file is: File size = sample rate x bit depth x number of channels x duration in seconds.
Given that an audio signal is sampled at a rate of 1024 Hz, we can calculate the file size of such an audio file with the formula above. For a stereo type audio file, we have 2 channels. Radio quality audio files typically have a bit depth of 16 bits.
To calculate the duration in seconds for a 1 minute audio file, we have to multiply 1 minute by 60 seconds, which is equal to 60 x 1 = 60 seconds. File size = 1024 x 16 x 2 x 60 = 1,572,864 bits or 196,608 bytesTherefore, the file size of a stereo type but radio quality audio file with a duration of 1 minute and sampled at a rate of 1024 Hz is 1,572,864 bits or 196,608 bytes.
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what is the definition of physics?
A.the study of living organisms, divided into many specialized fields that cover their morphology, physiology, anatomy, behavior, origin, and distribution
B.the branch of science that deals with the identification of the substance of which matter is composed
C.the branch of science concerned with the nature and properties of matter and energy
D.the branch that deals with the relations of organisms to one another and to their physical surroundings
Answer:
your answer should be c
Answer:
D.the branch that deals with the relations of organisms to one another and to their physical surroundings
A 2-kg ball moving at 6 m/s rolls into sand and comes out of the sand rolling at 2 m/s
The velocity of the ball as it exits the sand is 6m/s.
Explanation and Calculation of the Velocity of the Ball in MotionWhen the ball rolls into the sand, it experiences a force of friction acting against its motion, which causes it to slow down. The amount of frictional force depends on the properties of the sand and the ball's velocity. Assuming that the ball rolls horizontally into the sand and comes out horizontally as well, the conservation of momentum applies, which means that the momentum of the ball before it enters the sand is equal to the momentum of the ball after it exits the sand.
We can use the equation for conservation of momentum to calculate the final velocity of the ball:
Initial momentum = Final momentum
mv1 = mv2
where m is the mass of the ball, v1 is the initial velocity of the ball, and v2 is the final velocity of the ball.
Substituting the given values, we get:
2 kg x 6 m/s = 2 kg x v2
12 kg m/s = 2 kg x v2
v2 = 6 m/s
Therefore, the final velocity of the ball as it exits the sand is 6 m/s.
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What rate do things fall to Earth?
Answer:
9.8 meters per square second
Explanation:
Free Falling Object. the value of g is 9.8 meters per square second on the surface of the earth. The gravitational acceleration g decreases with the square of the distance from the center of the earth. But for many practical problems, we can assume this factor to be a constant.
On a pirate map, “X” marks the spot. Does that “X” reference the position or the
displacement of the treasure?
Answer:
it References the position
Explanation:
Displacement is defined to be the change in position of an object.
And the treasure can't move by itself because its an object (and objects don't move).
If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?
m/s2
Answer:
2ms-2
Explanation:
F = ma
a = F/m
= 0.5 / 0.25
= 2ms-2
Answer 2m/s^2
Explanation:
mass=0.25kg
Force =0.5N
Acceleration=force/ mass
Acceleration=0.5/0.25
Acceleration=2
Acceleration =2m/s^2
Identify which portions of the electromagnetic spectrum are used in each of the devices listed. a. a microwave oven b. a television set c. a single-lens reflex camera
The portions of the electromagnetic spectrum are used in the television set. It is used in the picture tube in the old television set.
What is the electromagnetic spectrum ?The electromagnetic radiation distribution in accordance with the frequency or wavelength is known as the electromagnetic spectrum.
The portions of the electromagnetic spectrum are used in the television set. It is used in the picture tube in the old television set.
Hence, option b is correct.
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I do not understand how to find the GPE and KE without velocity.
Answer:
At point A;
GPE = 58800 J
KE = 0 J
At point B;
GPE = 44100 J
KE = 14700 J
At point C;
GPE = 0 J
KE = 58800 J
At point D;
GPE = 29400 J
KE = 29400 J
EPE = 29400 J.
Explanation:
The Gravitational Potential Energy, GPE, is given as follows;
GPE = The mass. m × The acceleration due to gravity, g × The elevation or height, h
∴ GPE = m × g × h
The Kinetic Energy, KE = 1/2 × The mass × The square of the velocity, v²
KE = 1/2 × m × v²
At point A;
The parameters are;
h = 100m, v = 0 (Starting point), Cart mass, m = 60 kg, we have;
GPE = m × g × h = 60 × 9.8 × 100 = 58800
GPE = 58800 J
KE = 1/2 × m × v² = 1/2 × 60 × 0² = 0
KE = 0 J
Mechanical Energy, ME = GPE + KE = 58800 + 0 = 58800 = Constant
ME = 58800 J
At point B;
GPE = 60 × 9.8 × 75 = 44100
GPE = 44100 J
KE = ME - GPE = 58800 - 44100 = 14700
KE = 14700 J
At point C;
GPE = 60 × 9.8 × 0 = 0 J
KE = ME - GPE = 58800 - 0 = 58800
KE = 58800 J
At point D;
v = 0, the Cart is brought to rest by the spring
GPE = 60 × 9.8 × 50 = 29400
GPE = 29400 J
KE = ME - GPE = 58800 - 29400 = 29400
KE = 29400 J
The Elastic Potential Energy EPE gained by the spring = KE = 29400
EPE = 29400 J.
if the temperature is constant and the pressure increases, then the volume will ____.
help i need it i don't understand
Answer:
John Newlands: arranged elements according to their atomic mass
Johann Wolfgang Döbereiner: created groups of three elements, each based on similar properties
Antoine Lavoisier: divided elements into four categories
Dmitri Mendeleev: used patterns to predict undiscovered elements
Explanation:
Read the following claim.
The chain reaction that produces thermonuclear bombs occurs rapidly.
Which sentence from the article provides the BEST support for the above statement?
A)Thermonuclear bombs and atomic bombs are both nuclear weapons, but they work differently at a basic level.
B)Thermonuclear bombs, on the other hand, get their power from combining nuclei together.
C)This mass loss is converted into energy, which is very intense and where fusion gets its explosive power.
D)The entire series of explosions in a thermonuclear bomb takes a fraction of a second to occur.
Answer:
D I'm pretty sure :)
Explanation:
hope this helps
Wires provide the pathway to carry the electricity from components to components. * 1 point true false
Answer:
true
Explanation:
as long as it is the right conductive material
As you walk to science class, you start out at a speed of 2 m/s, for a time of 120 seconds (you’re really excited to get to class). Then you see your friend and slow down to a speed of 0.5m/s for 30 seconds. You stop at your locker for 40 seconds (a speed of 0 m/s). You realize that you are about to be late so you hurry to class at a speed of 1 m/s and get to class just as the bell rings (4 minutes after your trip started). How far did you travel total?
The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
What is Speed?Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.
For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.
The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.
Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.
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Answer Questions below
Answer:
When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.
1) V= 60 volt
Total resistance R = R₁ + R₂
= 20 + 10
= 30 Ω
2) Ohms law states that,
\(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)
3) Voltage around 10 Ω resistor,
V₂ = I R₂
= 2 * 10
= 20 volt
___________________________________________________
4) Total current = 1 A
5) Total voltage = 8 volt
6) Voltage around R₁ is V₁
R₁ = 2 Ω ; I = 1 A
V₁ = IR₁
= 1 * 2
= 2 volt
7) Resistance 2:
Total resistance = R
Total voltage = V = 8 volt
Total current = I = 1 A
\(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)
R = 8 Ω
R₁ + R₂ = 8 Ω
2 + R₂ = 8
R₂ = 8 - 2
R₂ = 6 Ω
8)Voltage around R₂:
\(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)
V₂ = 6 volt
9) Total R = 8 Ω
_________________________________________________
10) Total V = 12 volt
11) Total R = 8 + 8
= 16 Ω
12) Total current I,
\(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)
13) Voltage at each resistor:
V₁ = I*R₁
= 0.75 * 8
= 6 volt
V₂ = I*R₂
= 0.75 * 8
= 6 volt
_______________________________________________________
14) Total R = 40 + 20
= 60 Ω
15) To find V₁, first find total voltage.
I = 2 A ; R = 60 Ω
V = IR
= 2 * 60
= 120 V
V₁ + V₂ =V
V₁ + 80 = 120
V₁ = 120 - 80
V₁ = 40 volt
A tow rope pulls a 1450 kg truck, giving it an acceleration 1.25 m/s^2. What force does the rope exert?
A. 1810 N
B. 8690 N
C. 810 N
D. 6489 N
force=mass × acceleration
mass=force ÷ acceleration
acceleration=force ÷ mass
When a tow rope pulls a 1450 kg truck, giving it an acceleration 1.25 m/s², the rope exerts force of 1812.5 N.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force. A spring balance can be used to calculate the Force. The Newton is the SI unit of force.
mass of the truck = 1450 kg.
acceleration of the truck=1.25 m/s².
Hence, the rope exerts force of = mass × acceleration
= 1450 kg × 1.25 m/s²
= 1812.5 N.
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Below please discuss:
1. What is it about lithium that is so essential to devices such as iPhones and electric cars?
2. What is it about lithium mining methods that make it a particular environmental hazard?
3. If we have a benefit from greater uses of batteries--for example, more electric vehicles reducing CO2 emissions--what for you is the tipping point where the benefit of lithium outweighs its environmental costs?
Physical geology subject
Lithium is essential to devices such as iPhones and electric cars because of its unique properties that make it an ideal material for rechargeable batteries. Lithium-ion batteries, which are widely used in these devices, offer high energy density, lightweight design, and longer lifespan compared to other types of batteries.
The abundance of lithium ions allows for efficient energy storage and discharge, making it crucial for powering portable electronics and electric vehicles.
Lithium mining methods pose specific environmental hazards due to their extraction processes and the potential impact on local ecosystems. One common method of lithium extraction is through open-pit mining, which involves removing large amounts of topsoil and vegetation. This can lead to habitat destruction, soil erosion, and loss of biodiversity in the surrounding areas. Additionally, lithium mining requires significant water resources, potentially leading to water scarcity and pollution as chemicals are used in the extraction and purification processes. Improper disposal of mining waste can also result in soil and water contamination, affecting local ecosystems and potentially human health.
The tipping point where the benefit of lithium outweighs its environmental costs in the context of greater battery usage, such as in electric vehicles, is a complex and subjective consideration. It depends on various factors, including the scale of lithium extraction, the efficiency of recycling processes, the development of alternative battery technologies, and the overall environmental impact of the energy sources used for charging those batteries. To determine the tipping point, a comprehensive analysis is needed to evaluate the net environmental impact, considering the entire life cycle of lithium batteries from mining to disposal. This analysis should assess factors such as greenhouse gas emissions, land use, water consumption, waste management, and the potential for mitigating environmental impacts through sustainable mining practices, recycling initiatives, and renewable energy integration. Striking a balance between reaping the benefits of lithium in reducing CO2 emissions and minimizing its environmental costs requires careful consideration and the implementation of sustainable practices throughout the entire battery supply chain.
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Use Newton's laws to explain why a falling object dropped from a 57m tower accelerates initially but then reaches constant velocity. Discuss the forces acting on the object
Answer:
At the point of dropping the object, by Newton's first law due to gravitational force \(F_g\) = m × g, accelerates
By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)
As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out
The body then moves at a constant uniform motion down according to Newton's first law
Explanation:
At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g
As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force
Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.
A digital audio compact disc (CD) carries data along a continuous spiral track from the inner circumference of the disc to the outside edge. Each bit occupies 0.6 mm of the track. A CD player turns the disc to carry the track counterclockwise above a lens at a constant speed of 1.30 m/s. Find the required angular speed (a) at the beginning of the recording, where the spiral has a radius of 2.30 cm, and (b) at the end of the record-ing, where the spiral has a radius of 5.80 cm. (c) A full-length recording lasts for 74 min, 33 s. Find the average angular acceleration of the disc. (d) Assuming the acceleration is con-stant, find the total angular displacement of the disc as it plays. (e) Find the total length of the track.
(a) The required angular speed at the beginning of the recording is approximately 52.38 radians per second.
(b) The required angular speed at the end of the recording is approximately 20.95 radians per second.
(c) The average angular acceleration of the disc is approximately -0.000286 radians per second squared.
(d) Assuming constant acceleration, the total angular displacement of the disc as it plays is approximately -0.343 radians.
(e) The total length of the track is approximately 5.28 kilometers.
(a) To find the required angular speed at the beginning of the recording, we can use the relationship between linear speed, angular speed, and radius. The linear speed is given as 1.30 m/s, and the radius is 2.30 cm (or 0.023 m). The formula to relate these quantities is:
Linear Speed = Angular Speed * Radius
Solving for angular speed:
Angular Speed = Linear Speed / Radius
Plugging in the given values:
Angular Speed = 1.30 m/s / 0.023 m
Angular Speed ≈ 56.52 radians/second
Therefore, the required angular speed at the beginning of the recording is approximately 52.38 radians per second.
(b) Similarly, to find the required angular speed at the end of the recording, we use the same formula and plug in the linear speed of 1.30 m/s and the radius of 5.80 cm (or 0.058 m):
Angular Speed = 1.30 m/s / 0.058 m
Angular Speed ≈ 22.41 radians/second
Therefore, the required angular speed at the end of the recording is approximately 20.95 radians per second.
(c) To find the average angular acceleration, we can use the formula:
Average Angular Acceleration = (Final Angular Speed - Initial Angular Speed) / Time
The final angular speed is the angular speed at the end of the recording, which is approximately 20.95 radians per second. The initial angular speed is the angular speed at the beginning of the recording, which is approximately 52.38 radians per second. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.
Average Angular Acceleration = (20.95 radians/second - 52.38 radians/second) / 4473 seconds
Average Angular Acceleration ≈ -0.000286 radians/second squared
Therefore, the average angular acceleration of the disc is approximately -0.000286 radians per second squared.
(d) Assuming constant angular acceleration, we can use the formula to find the angular displacement:
Angular Displacement = Initial Angular Speed * Time + (1/2) * Average Angular Acceleration * Time^2
The initial angular speed is approximately 52.38 radians per second, and the average angular acceleration is approximately -0.000286 radians per second squared. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.
Angular Displacement = 52.38 radians/second * 4473 seconds + (1/2) * -0.000286 radians/second squared * (4473 seconds)^2
Angular Displacement ≈ -0.343 radians
Therefore, the total angular displacement of the disc as it plays is approximately -0.343 radians.
(e) To find the total length of the track, we need to calculate the arc length of each bit and sum them up. Each bit occupies 0.6 mm of the track, which is equivalent to 0.0006 m.
The total number of bits can be calculated by multiplying the circumference of the spiral track by the number of revolutions. The circumference is given by 2π times the average of the initial and final radii.
Circumference = 2π * (2.30 cm + 5.80 cm) / 2
Circumference ≈ 27.77 cm
Converting the circumference to meters:
Circumference = 27.77 cm * 0.01 m/cm
Circumference ≈ 0.2777 m
The number of revolutions can be calculated by dividing the track length by the length of each bit:
Number of Revolutions = Track Length / Length of Each Bit
Number of Revolutions = 0.2777 m / 0.0006 m
Number of Revolutions ≈ 462.83 revolutions
Finally, we can calculate the total length of the track:
Total Length of the Track = Number of Revolutions * Circumference
Total Length of the Track ≈ 462.83 revolutions * 0.2777 m/revolution
Total Length of the Track ≈ 128.53 m
Therefore, the total length of the track is approximately 5.28 kilometers (or 5280 meters).
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a cell of EMF 1.5 volt is connected in series with a resistor of Resistance 3 ohms a high resistance voltmeter connected across the cell registers 0.9 volt calculate the internal resistance of the cell
Answer:
0.6 resistance
What nuclear reaction is shown in the equation below?
A. Nuclear fusion
B. Nuclear fission
C. Positron emission
D. Beta decay
The carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.
What is a nuclear fusion?The term nuclear fusion refers to a kind of reaction in which two nuclei fuse together to give rise to a single nuclei with the evolution of energy.
We can see that the carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.
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Answer:
A. Nuclear fusion
Explanation:
got it right, trust
A car starts with a speed of 80 km/hr and slows to a rate of 50 km/hr in 5 sec
If the question is asking for acceleration,
To find acceleration, we have to find the change in velocity over the change in time
In this case, the change of velocity is -30 km/hr and the change in time is 5 seconds
We must convert the units of sec to hours to solve this question
5 sec * 1 min/60 seconds * 1 hour/60 min = .00138889 hours
acceleration = change in velocity / change in time = -30 km/hr / .00138889 hours = -21599.999 km/hr^2 = ~-21600 km/hr^2