Im struggling pls help

Answer:

y=-2x+13

Step-by-step explanation:

slope equation= (y2-y1)/(x2-x1)

(9-3)/(-2-1)=(6/-3)=-2

slope changes by a factor of -2

y=mx+b ... find b, plug in values

9=-2(-2)+b

9+4=b

b=13

CHECK

9=-2(-2)+13

9=-4+13

9=9

CORRECT

Step-by-step explanation:

an odd number

3*3 =9

5*5= 25

7*7= 49

Answer:

x = number

add number = addition

square = ^2

x^2

Brainlist pls!

The 95% confidence interval for the average number of units that students in their college are enrolled in is (11.46,12.53)

We are given the number of students, n =  46, and  the mean of the sample which is x= 12.5, and the standard deviation of the sample which is s= 1.8 , the formula  we are referring to for calculating the confidence interval which is :

x ± t (s/√(n))

since for  this case, the degree of freedom is one less than the mean, which is 45, the critical value for the confidence of 95% with  the degree of freedom of 45 is 2.015

x + t(s/√(n)) = 12.5 +2.015*(1.8/6.78)=  12.53

x - t(s/√(n))= 12.5 -2.015*(1.8/6.78)= 11.46

The interval is (11.46,12.53)

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The equivalence classes of the equivalence relations in exercise 1 are the sets of elements that are related to each other under the given equivalence relation.

For example, if the equivalence relation is "x is related to y if x and y have the same remainder when divided by 3," then the equivalence classes would be:

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Answer:

The first one

Step-by-step explanation:

Its just playing with the signs, its not ____ and equal to so the last two arent it (because of the empty circle) and its greater than -1 so its number 1.

Answer:

Moshe made $1875 and Jamal made $5625

Step-by-step explanation:

divide it in half, then divde Moshe's half in half because he only made half as much,

hope this helps and remember to mark brainliest

Moshe furnishes $5000 and Jamal furnishes $2500 of the capital. Computed by solving the linear equation x + x/2 = 7500, where x is the capital furnished by Moshe.

Linear equations are an equation involving constants and variables, where variables are raised to a power of not greater than 1.

We are informed that Jamal and Moshe starts a business with a capital of $7500. Also, we are informed that Jamal furnishes half as much capital as Moshe does.

We will try to make a linear equation and solve for it to find the capital furnished by each of them.

Let the capital furnished by Moshe be $x.

Jamal furnishes half as much capital as Moshe does.

∴ Capital furnished by Jamal = 1/2 of Moshe's capital = 1/2 of $x.

∴ Jamal's capital + Moshe's capital = Total capital furnished

We know the total capital is $7500.

∴ Our linear equation is: 1/2 of $x + $x = $7500.

Now we solve this equation in the following ways:

or, (1/2)*x + x = 7500

or, x/2 + x = 7500

or, (x + 2x)/2 = 7500

or, 3x/2 = 7500

or, x = (7500*2)/3 = 15000/3 = 5000.

∴ x = 5000.

∴ Moshe's share = $x = $5000

Jamal's share = 1/2 of $x = 1/2 of $5000 = $2500.

∴ Moshe furnishes $5000 and Jamal furnishes $2500 of the capital. Computed by solving the linear equation x + x/2 = 7500, where x is the capital furnished by Moshe.

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Considering the situation described, the appropriate null hypothesis is given by:

\(H_0: p = 0.09\)

At the null hypothesis, it is tested if the proportion is the expected one, that is, of 9%, hence:

\(H_0: p = 0.09\)

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the proportion is above 9%, hence:

\(H_1: p > 0.1\).

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The correct option is option (C) .

Cluster Sampling is a type of probability sampling and other options are non- probability sampling examples .

Sampling :

Sampling is defined as a technique that selects individual members or subsets from a population to help determine characteristics of the population as a whole.

Croach and Housden postulate that a sample is a finite number taken from a large group for testing and analysis, and that the sample can be taken as representative of the group as a whole.

There are two main types of sampling:

i) probability sampling

ii) Non-probability sampling

A) probability sampling:

It is defined as the sampling technique which researchers use a related method to draw probability theory samples from a larger population.

The most important requirement for probabilistic sampling is that everyone in the population has a known equal chance of being selected.

Probability Samples:

1. Stratified Sampling: Stratified sampling is a type of sampling technique that divides the total population into smaller groups or strata to complete the sampling process. Hierarchies are formed based on some common characteristics of demographic data.

2. Cluster Sampling: Cluster sampling is a probabilistic sampling technique in which researchers divide a population into multiple groups (clusters) for research purposes. Researchers then select random groups using simple sampling techniques for data collection and data analysis.

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The electric potential energy of the charged particles can be ranked from highest to lowest as follows: 4, 2, 3, 1.

Given four point charges, each with a charge of +Q, placed at the corners of a square with sides of length d, we need to rank the electric potential energy of the charged particles from highest to lowest.

Let's consider the different charged particles:

Particle 1 is at one corner of the square.

Particle 2 and Particle 3 are at adjacent corners of the square.

Particle 4 is at the corner opposite Particle 1.

The electric potential energy (PE) of a pair of charges can be calculated using the formula:

\(\[PE = k \left(\frac{|q_1q_2|}{r}\right)\]\)

where k is Coulomb's constant \((9 \times 10^9 N m^2 / C^2)\), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

The electric potential energy of the four pairs of charges can be calculated as follows:

Particle 1 and Particle 2:

The distance between Particle 1 and Particle 2 is d. Therefore,

\(\[PE_{1-2} = k \left(\frac{|+Q \times +Q|}{d}\right) = k \left(\frac{Q^2}{d}\right)\]\)

Particle 1 and Particle 3:

The distance between Particle 1 and Particle 3 is √2d. Therefore,

\(\[PE_{1-3} = k \left(\frac{|+Q \times +Q|}{\sqrt{2}d}\right) = k \left(\frac{Q^2}{2d}\right)\]\)

Particle 1 and Particle 4:

The distance between Particle 1 and Particle 4 is d√2. Therefore,

\(\[PE_{1-4} = k \left(\frac{|+Q \times +Q|}{d\sqrt{2}}\right) = k \left(\frac{Q^2}{2d}\right)\]\)

Particle 2 and Particle 3:

The distance between Particle 2 and Particle 3 is d. Therefore,

\(\[PE_{2-3} = k \left(\frac{|+Q \times +Q|}{d}\right) = k \left(\frac{Q^2}{d}\right)\]\)

Particle 2 and Particle 4:

The distance between Particle 2 and Particle 4 is √2d. Therefore,

\(\[PE_{2-4} = k \left(\frac{|+Q \times +Q|}{\sqrt{2}d}\right) = k \left(\frac{Q^2}{2d}\right)\]\)

Particle 3 and Particle 4:

The distance between Particle 3 and Particle 4 is d. Therefore,

\(\[PE_{3-4} = k \left(\frac{|+Q \times +Q|}{d}\right) = k \left(\frac{Q^2}{d}\right)\]\)

Therefore, the electric potential energy of the four pairs of charges can be ranked from highest to lowest as follows:

Particle 4 and Particle 2

Particle 1 and Particle 3

Particle 2 and Particle 3

Particle 1 and Particle 2

Particle 1 and Particle 4

Particle 3 and Particle 4

Thus, the electric potential energy of the charged particles can be ranked from highest to lowest as follows: 4, 2, 3, 1.

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The difference between the rate of change of the intervals: 1,2 and 2,4 is; 2

The average rate of change over the intervals (x₁, y₁) and (x₂, y₂) is given by the formula;

Average rate of change = (y₂ - y₁)/(x₂ - x₁)

Thus, the average rate of change between the intervals (1, 2) and (2, 4) is;

Average rate of change = (4 - 2)/(2 - 1)

Average rate of change = 2/1

Average rate of change = 2

That is the difference between the rate of change over the two given intervals.

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Answer:

Each banana would weigh ¼ of a pound

Step-by-step explanation:

If there are three bananas that all equal ¾ of a pound, then ¾÷3=¼

Answer:

c

Step-by-step explanation:

Answer:

360

Step-by-step explanation:

Answer:

B. perpendicular to a line at a point on the line

Step-by-step explanation:

that's how you would construct a perpendicular line to the point that is on the line

To eliminate the parameter t from the given parametric equations x = 4sin(3t) and y = 4cos(3t), we can use the trigonometric identity sin^2(t) + cos^2(t) = 1.

Squaring both equations, we get: x^2 = 16sin^2(3t) y^2 = 16cos^2(3t) Adding these two equations and using the trigonometric identity, we get: x^2 + y^2 = 16(sin^2(3t) + cos^2(3t)) x^2 + y^2 = 16 Taking the square root of both sides, we get: sqrt(x^2 + y^2) = 4 .

Therefore, the equation that represents the given parametric equations as a single equation in x and y is: x^2 + y^2 = 16 This is the equation of a circle with center at the origin and radius 4.  the equation becomes: (x/4)² + (y/4)² = 1 Finally, we can write the single equation in x and y as: x² + y² = 16.

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A statistical question that can result in numerical data such as C: how many pets do the students at your school have?.

This question C: "how many pets do the students at your school have?" can be used to obtain data in numerical form. Because this question asks about the number of pets for each child in one school, of course this data can be in the form of a number of the number of animals kept.

Quantitative data is also known as numerical data. Because it represents a numerical value i.e., how much, or how often. Numerical data provides information about the quantity of a particular thing.

Some examples of quantitative data are height, length, size, weight, and so on. Quantitative data can be classified into two types based on the data set.

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The probability of a woman having four girls in a row is 6.25%.

To calculate the probability that if a woman has four children, they will all be girls, you should use the rule of multiplication. This rule states that to calculate the probability of two or more independent events occurring together, you multiply the probability of each individual event. In this case, the probability of each child being a girl is 0.5 (assuming an equal chance of having a boy or girl), so you would calculate the probability as 0.5 x 0.5 x 0.5 x 0.5 = 0.0625 or 6.25%. Therefore, the probability of a woman having four girls in a row is 6.25%.

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Answer:

16

Step-by-step explanation:

If they are parallel then the 2 angles are congruent, so

8x + 14 = 12x - 50

64 = 4x

16 = x

Answer:

x = 16

Step-by-step explanation:

For the 2 lines to be parallel, then

12x - 50 and 8x + 14 would be corresponding angles and congruent , so

12x - 50 = 8x + 14 ( subtract 8x from both sides )

4x - 50 = 14 ( add 50 to both sides )

4x = 64 ( divide both sides by 4 )

x = 16

Answer:

it would be 9/12

Step-by-step explanation:

if you want to get a denominator of 12 you would have to multiply by 3 from both and you should get 9/12. 3*3=9 and 4*3=12.

Answer:

9/12

Step-by-step explanation:

4x3=12

because we are multiplying the denominator we also have to multiply the numerator by the same number

3x3=9

Answer:

5 and 5/9

Step-by-step explanation:

First, you need to convert these mixed fractions to improper fractions. To do this, multiply the denominator by the whole number and add it to the numerator. Put it over the denominator. 2 and 8/9 becomes 26/9. 9 times 2 is 18 plus 8 is 26. 26/9. 2 and 2/3 is 8/3. Now find the common denominator (9). Do not change anything about the fraction, 26/9, because it already has 9 in the denominator. 8/3 becomes 24/9 because 3 times 3 is 9 and 8 times 3 is 24. Then, add them. 26/9 plus 24/9 is 50/9. Lastly, put this in simplest form. 50/9 is 5 5/9.

Answer: 5 5/9

Step-by-step explanation: This is just in my way of answering this: 2 8/9 and 2 2/3 need to be made into improper fractions, so 2 8/9 as an improper fraction is 26/9. 2 2/3 as an improper fraction is 8/3. To add these fractions, you must find the common denominator! The common denominator is 9, and since 26/9 already has the denominator 9, you need to make 8/3 have a denominator of 9. So, 3 x 3 is 9, and 8 x 3 is 24! 24/9 + 26/9 is 50/9. 50/9 needs to be converted back into a mixed number, so 50/9 will become 5 5/9! That's the answer! :)

The absolute value model |x - 30| = 10 represents the time required for Jack to fold his laundry. (Correct choice: D)

Absolute values are functions used in mathematics that represents the magnitude of a number, whose definition is summarized below:

In this case, we must determine an absolute value model that contains the maximum and minimum times required by Jack to fold his laundry, This is represented by the following model:

|x - a| = b

Where:

If we know that a = 30 min and b = 10 min, then the absolute value model is:

|x - 30| = 10

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The integral to be evaluated is given by:e−cos(2) dThe integration of exponential functions can be done by considering the following method.

if f(x) is a differentiable function of x, then∫f(x)e^xdx = f(x)e^x - ∫f'(x)e^xdx. Integrating e^x functions involves u-substitution, by which we let u be the inner function in the exponential e^u.

So we substitute u with cos2 to obtain the expression:∫e^(-cos2) d(cos2)

Solving this expression results which can be evaluated by using integration by substitution method as follows:∫e^(-cos2) d(cos2)Let u = cos 2, then du = -sin 2 d(cos 2).

Now, let us substitute u and du in the expression above:∫e^(-cos^2) d(cos 2) = - ∫e^(-u) du= -e^(-u) + C, where C is a constant of integration.

Now, substitute u with cos 2 to obtain:∫e^(-cos^2) d(cos 2) = -e^(-cos^2) + C

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Answer:

46

Step-by-step explanation:

because it is ...... maybe

Answer:.....

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Considering the situation, the hypotheses set that would determine if the proportion of households that support starting school earlier has changed this year is given by:

\(H_0: p = 0.65, H_\alpha: p \neq 0.65\)

At the null hypotheses, it is tested if there has been no change, that is, the proportion is still of 0.65 = 65%, hence:

\(H_0: p = 0.65\)

At the alternative hypotheses, it is tested if there has been a change, that is, the proportion is not of 0.65 = 65% anymore, hence:

\(H_\alpha: p \neq 0.65\)

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Answer: they had a bad reputation

Step-by-step explanation:

This equation provides us with the number of paintings Kaylani can complete in any given time T, assuming that her rate is constant.

P = (5 / 24) * T

Let us use the variables P and T from the problem statement.

We can deduce from the information provided that Kaylani can complete P paintings in T hours. As a result, her painting rate is:

R = P / T

We also know Kaylani can complete five paintings in 24 hours. Using the same rate formula, we may write:

R = 5 / 24

We can set the two equations for R equal to each other because Kaylani's pace of painting is the same in both cases:

P / T = 5 / 24

We can solve for P by multiplying both sides by T:

P = (5 / 24) * T

This equation provides us with the number of paintings Kaylani can complete in any given time T, assuming that her rate is constant.

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Answer:

yeah they are equivalent

Step-by-step explanation:

\(\\ \tt\longmapsto (-1)(-x)\)

\(\\ \tt\longmapsto x\)

Yes equal

Note that