IM BEGGING IVE LITERALLY LOST HOPE AND I REALLY NEED HELP PROPER ANSWE PLEASEEEE

Complete the values in the table, assuming that all projectiles are launched horizontally and fall
downwards with an acceleration of 9.8 ms 2. Give all your answers to 2 significant figures.
Find the time to reach target and distance fallen

Assuming a flat ground, and  football thrown or dropped from the same height, the horizontally-thrown ball will hit the ground with the same vertical velocity as the dropped ball, but it will have most of its initial horizontal velocity, too. A simple vector addition, guarantees that that the horizontally-thrown ball will have a larger total velocity than the dropped ball.

What is Velocity.

Velocity is the directional velocity of a moving object as an indicator of the rate of change of position observed from a particular frame of reference and measured at a particular time standard.

Therefore, A simple vector addition, guarantees that that the horizontally-thrown ball will have a larger total velocity than the dropped ball.

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Answer:

10.3 cm³

Explanation:

From the question given above, the following data were obtained:

Original volume (V₁) = 10 cm³

Initial temperature (θ₁) = 20 °C

Final temperature (θ₂) = 50 °C

Cubic expansivity (γ) = 10¯³ K¯¹

Final volume (V₂) =?

γ = V₂ – V₁ / V₁(θ₂ – θ₁)

10¯³ = V₂ – 10 / 10( 50 – 20)

10¯³ = V₂ – 10 / 10(30)

10¯³ = V₂ – 10 / 300

Cross multiply

10¯³ × 300 = V₂ – 10

0.3 = V₂ – 10

Collect like terms

0.3 + 10 = V₂

10.3 = V₂

V₂ = 10.3 cm³

Thus, the volume at 50 °C is 10.3 cm³

A speaker should employ the spatial pattern of organisation to describe the physical arrangement  of a location, an item, or an event.

Physical arrangement describes how things are laid out or organised spatially in the physical world. It can be used to describe the placement, tilt, and connections of various elements inside a given space. In a variety of professions, including architecture, urban planning, and interior design, it is crucial to comprehend how things are physically set up. A biological organism's physical structure or the arrangement of the planets in the solar system are two examples of how it might be useful in understanding or interpreting natural occurrences. In public speaking, the spatial pattern of arrangement can be used to describe the physical arrangement of a location, an item, or an event in order to aid the audience in visualising and comprehending it.

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Answer:

atoms and molecules

Explanation:

as opposed to being continuous or just including particles). On the following page, the idea is stated as one of four concepts in Dalton's theory: “All matter is composed of tiny, indivisible particles called atoms”

Answer: atoms

Matter is made of atoms, the basic building blocks. Atoms are made of protons, neutrons and electrons. The answer is atoms.

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The force required to move the 90 Kg object at a constant speed of 8.10 m/s is 138.94 N

The force required to keep an object moving in a circle is called Centripetal force. This is defined according to the following equation:

F = mv²/r

With the above formula, we can obtain the force required to move the 90 Kg object. Details below:

F = mv²/r

F = (90 × 8.10²) / 42.5

F = (90 × 65.1) / 42.5

F = 5904.9 / 42.5

F = 138.94 N

Thus, the force required is 138.94 N

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Answer:

Explanation:

The International System of Units (SI, abbreviated from the French Système international (d'unités)) is the modern form of the metric system. It is the only system of measurement with an official status in nearly every country in the world. It comprises a coherent system of units of measurement starting with seven base units, which are the second (the unit of time with the symbol s), metre (length, m), kilogram (mass, kg), ampere (electric current, A), kelvin (thermodynamic temperature, K), mole (amount of substance, mol), and candela (luminous intensity, cd).

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Scientific experiments follow principles called the scientific method that ensure that accurate tests are performed, reliable results are collected, and reasonable conclusions are drawn. Scientific experiments must follow the basic principles of good research so that the final presented results can be believed to be reliable.

Observations of new physical processes or phenomena occur infrequently, but there are areas of science that are not fully understood. Scientists must verbalize their observations in order to formulate meaningful hypotheses.

It's not enough to just guess why something happens. Scientists must prove their theories to be correct. Predictions are made to test observations under different circumstances. The aim is to learn more about this phenomenon and prove its existence. One of his ways of improving the scientific method is by creating 'models'. Models can be used to infer difficult and unobservable concepts.

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Answer: 1. flushing the toilet,

               2. oil popping in a pan,

                3. the clicking of a mouse on a computer,

Explanation: Lu-.v u

The decarboxylation reaction involves the removal and replacement of a carboxyl group with hydrogen.

A decarboxylation reaction is one in which the carboxyl group in a carboxylic acid is replaced with hydrogen.

In living organisms, decarboxylation reactions are catalyzed by enzymes called decarboxylases or carboxy-lyases.

The decarboxylation of beta-carbonyl esters proceeds through a cyclic transition state giving an enol intermediate which then tautomerises to the carbonyl.

Therefore, a decarboxylation reaction involves the removal and replacement of a carboxyl group with hydrogen.

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The decarboxylation reaction is given with the removal of the carbon dioxide from the carboxyl group.

The carboxyl group is the attachment of the OH and the =O functional group to the carbon atom.

In the decarboxylation reaction, there has been the removal of the carbon dioxide and the carboxyl group is replaces with the Hydrogen atom.

The decarboxylation reaction for the given reactant with the missing groups is given in the image attached.

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The current in the circuit is  ≈ 2.07 amperes (A)

A current circuit is a closed path through which electric current can flow. It typically consists of a power source, such as a battery or generator, a load, such as a light bulb or motor, and conductive wires or other components that connect the power source and load to form a complete path for the current to flow.

The current in the circuit can be calculated using the formula:

current = charge / time

In this case, the charge moved around the circuit is 60 coulombs and the time taken is 29 seconds. Thus, the current in the circuit is:

current = 60 coulombs / 29 seconds

current ≈ 2.07 amperes (A)

Therefore, The current in the circuit is  ≈ 2.07 amperes (A)

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Answer:

Yes.

Explanation:

Even though the initial and final speeds are the same, there has been a change in direction for the object. Thus, there is an acceleration. The object was moving rightward and slowed down to 0 m/s before changing directions and speeding up while traveling leftward.

Answer:

Time = 11.60 seconds.

Explanation:

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

\(Speed = \frac{distance}{time}\)

Given the following data;

Speed = 0.711m/s

Distance = 8.25m

To find the time;

Making time the subject of formula, we have;

\(Time = \frac{distance}{speed}\)

Substituting into the equation, we have;

\(Time = \frac{8.25}{0.711}\)

Time = 11.60 secs.

The actual underground location of an energy release that causes seismic waves is known as the hypocenter or focus.

The hypocenter is the point within the Earth where the rupture or movement of rocks occurs, releasing energy in the form of seismic waves. It is typically located along a fault line, which is a fracture in the Earth's crust where movement has taken place.

The depth of the hypocenter can vary, ranging from shallow depths near the Earth's surface to deeper depths within the Earth's interior. Seismic waves radiate outward from the hypocenter, propagating through the Earth and eventually reaching the surface, where they are detected and recorded by seismographs.

By studying the characteristics of seismic waves, scientists can determine important information about the nature of earthquakes and the properties of the Earth's interior.

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Answer:

water or conduct experiment requiring the water to be in liquid state. A coffee

addicted physicist stationed at a research base requires about 0.8 kg of ice for

his coffee on the hour.

a. How much heat is required to convert 0.8 kg of ice at -35 °C into steam

at 100°C?

[5]

b. Plot the temperature - energy graph for the processes in (a). [5]

C. The surface tension of water was determined in a laboratory by using

the drop weight method. 100 drops were released from a burette the

inner diameter of whose opening is 1.8 mm. The mass of the droplets

was 3.78 g.

i. Determine the surface tension of the water and, comparing it

with the tabulated value,

161

ii. Calculate the relative error of the measurements.

The density of 9 m³ of mercury is 13530 kg/m³.

Density is a characteristic of a substance that indicates how much mass it contains in a given volume. To calculate density, the mass of the substance is divided by its volume. The formula used to calculate density is:

Density = Mass / Volume

In this problem, the given mass of mercury is 121770 kg and its volume is 9 m³. To find the density of mercury, we can use the formula above and plug in the given values:

Density = Mass / Volume

             = 121770 kg / 9 m³

             = 13530 kg/m³

Therefore, the density of 9 m³ mercury is 13530 kg/m³.

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Answer: s(5) = -200,  v(5) = -90

              s(10) = -900, v(10) = -190

Explanation:

Position: s(t)

Velocity:  s'(t) = v(t)                ⇒      \(s(t)=\int {v(t)} \, dt\)

Acceleration     v'(t) = a(t)      ⇒      \(v(t)=\int {a(t)} \, dt\)

We are given that acceleration a(t) = -20   and velocity v(t) = 10

\(v(t)=\int {a(t)} \, dt\\\\v(t)=\int{-20}\, dt\\\\v(t)=-20t + C \\\\v(t)=10\quad \longrightarrow \quad C=10\\\\v(t)=-20t+10\)

\(s(t)=\int {v(t)} \, dt\\\\s(t)=\int {(-20t+10)} \, dt\\\\s(t)=-10t^2+10t\\\\\)

(a) Input t = 5 into the s(t) and v(t) equations

   s(5) = -10(5)² + 10(5)           v(5) = -20(5) + 10

          =  -250  +  50                     = -100   +  10

          =       -200                          =        -90

(b) Input t = 10 into the s(t) and v(t) equations

     s(10) = -10(10)² + 10(10)           v(10) = -20(10) + 10

            =  -1000  +  100                     = -200   +  10

            =       -900                          =        -190

A. The SI unit of force is the newton, symbol N.
b. The SI unit for distance is the meter (m)
c. The SI unit of work is joule (J). 
or Sometimes, newton-metre (N-m) is also used for measuring work.

When a charged foam cup is brought near an uncharged, aluminum foil-covered cup, a transfer of electrons is likely to occur.

This is because the foam cup has a net charge, which will induce a charge separation in the aluminum foil of the uncharged cup. The negatively charged electrons in the foil will be repelled by the negatively charged foam cup and will move towards the opposite end of the foil.

As a result, the foil will become polarized, with one end carrying a positive charge and the other carrying a negative charge. This can lead to a flow of electrons from the negatively charged end of the foil towards the positively charged end,

resulting in a transfer of charge from the foam cup to the foil. The magnitude and direction of this charge transfer will depend on the distance between the cups and the strength of the charge on the foam cup.

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During dilemma, a person may experience conflicting thoughts and emotions, uncertainty, anxiety, and stress. Two alternative solutions you implemented to solve the dilemma are the Pros and cons list and Seeking advice.

They may struggle to make a decision, as each option has its pros and cons. To solve a dilemma, one can consider alternative solutions, weigh their potential outcomes, and decide which one aligns better with their values, beliefs, and goals. Here are two examples of alternative solutions:

Pros and cons list: One way to solve a dilemma is by making a list of pros and cons for each option. This can help to clarify the potential benefits and drawbacks of each choice, which can help in making a more informed decision.

Seeking advice: Another way to solve a dilemma is to seek advice from a trusted friend, family member, or professional. Talking through the situation with someone else can help to gain a different perspective and see the situation from a new angle.

Ultimately, the solution to a dilemma will depend on the specific situation and the individual's unique circumstances. It's important to take the time to consider all options and their potential outcomes before making a decision.

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The height at which the diver must jump in other to hit the water with a speed of 24 m/s is 29.4 m.

The height of the player above the ground can be calculated using the formula below.

Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

⇒ Solve for s.

Hence, The height at which the diver must jump in other to hit the water with a speed of 24 m/s is 29.4 m.

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Answer:

512.5 mJ

Explanation:

Let the two identical charges be q = +35 µC and distance between them be r₁ = 46 cm. A charge q' = +0.50 µC located mid-point between them is at r₂ = 46 cm/2 = 23 cm = 0.23 m.

The electric potential at this point due to the two charges q is thus

V = kq/r₂ + kq/r₂

= 2kq/r₂

= 2 × 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C/0.23 m

= 630/0.23  × 10³ V

= 2739.13 × 10³ V

= 2.739 MV

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

So, the new electric potential at this point is

V' = kq/r₃ + kq/r₄

= kq(1/r₃ + 1/r₄)

= 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C(1/0.35 m + 1/0.11 m)

= 315 × 10³(2.857 + 9.091) V

= 315 × 10³ (11.948) V

= 3763.62 × 10³ V

= 3.764 MV

Now, the work done in moving the charge q' to the point 12 cm from either charge is

W = q'(V' - V)

= 0.5 × 10⁻⁶ C(3.764 MV - 2.739 MV)

= 0.5 × 10⁻⁶ C(1.025 × 10⁶) V

= 0.5125 J

= 512.5 mJ

Work done will be:  \(512.5 \mu J\).

Given:

q = +35 µC

q' = +0.50 µC

r₁ = 46 cm

r₂ = 46 cm/2 = 23 cm = 0.23 m

The electric potential at this point due to the two charges q is thus

\(V = \frac{kq}{r_2}+\frac{kq}{r_2}\\\\ V= \frac{2kq}{r_2}\\\\V= \frac{2 * 9 * 10^9Nm^2/C^2 * 35 * 10^{-6} C}{0.23 m}\\\\V= \frac{630}{0.23*10^3}V\\\\V= 2739.13 * 10^3 V\\\\V= 2.739 \mu V\)

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now;

r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and

r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

Thus, the new electric potential at this point is

\(V' = \frac{kq}{r_3} + \frac{kq}{r_4}\\\\V= kq(\frac{1}{r_3}+\frac{1}{r_4})\\\\V= 9 * 10^9 Nm^2/C^2 * 35 * 10^{-6} C (\frac{1}{0.35m}+\frac{1}{0.11m})\\\\V= 315 * 10^3(2.857 + 9.091) V\\\\V= 315 * 10^3 (11.948) V\\\\V= 3763.62 * 10^3 V\\\\V= 3.764 \mu V\)

Now, the work done in moving the charge q' to the point 12 cm from either charge is:

\(W = q'(V' - V)\\\\W= 0.5 * 10^{-6} C(3.764 MV - 2.739 MV)\\\\W= 0.5 *10^{-6} C(1.025 * 10^6) V\\\\W= 0.5125 J\\\\W= 512.5 \mu J\)

Thus, the work done will be: \(512.5 \mu J\).

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Answer:

W = 600 N

Explanation:

The mechanical advantage of any machine is the ratio of the load or weight to the effort applied. Hence, the general formula for mechanical advantage is as follows:

M.A = W/P

where,

M.A =Mechanical Advantage of Hammer = 10

W = Maximum force that could be generated = ?

P = Force created by me = 60 N

Therefore,

10 = W/60 N

W = 10*60 N

W = 600 N

The apparent backward motion of a planet as seen against the background of stars is called "retrograde motion." This occurs when a planet appears to move in the opposite direction of its usual motion, due to the relative positions and motion of both the observed planet and Earth.

Retrograde motion was a major mystery to ancient astronomers. They believed that the planets were perfect spheres that moved in perfect circles. They could not explain why the planets sometimes appeared to move backwards.

The Greek astronomer Ptolemy proposed a model of the universe that could explain retrograde motion. His model was based on the idea that the Earth was at the center of the universe and that the planets, Sun, and stars all revolved around the Earth. Ptolemy's model was very successful in explaining the motion of the planets, and it was used for over 1,500 years.In the 16th century, Nicolas Copernicus proposed a new model of the universe that placed the Sun at the center. Copernicus's model could also explain retrograde motion, and it eventually replaced Ptolemy's model.

Today, we know that the planets revolve around the Sun in elliptical orbits. This means that their motion is not always in the same direction. When a planet is on the opposite side of the Sun from the Earth, it appears to move backwards in the sky. This is what causes retrograde motion.

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The distance between the 2nd and 3rd dark fringes will be 0.09 cm.

In a double-slit interference pattern, the distance between the dark fringes can be determined using the following formula:

Y = (λ × L) / d

where:

Y is the distance between the dark fringes,

λ is the wavelength of the light,

L is the distance from the double slits to the viewing screen (also known as the slit-to-screen distance), and

d is the slit separation distance.

Given:

λ = 600 nm = 600 × 10⁻⁹m (since 1 nm = 10⁻⁹ m)

L = 1.50 m

d = 3.55 μm = 3.55 × 10⁻⁶ m (since 1 μm = 10⁻⁶m)

Plugging these values into the formula, we get:

Y = (600 × 10⁻⁹ m) ×(1.50 m) / (3.55 × 10⁻⁶m)

Simplifying, we get:

Y = 0.0009 m

To convert this to centimeters, we multiply by 100 (since 1 m = 100 cm):

Y = 0.0009 m× 100 cm/m = 0.09 cm

So, the distance between the 2nd and 3rd dark fringes is 0.09 cm.

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Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.

Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500

Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000

a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units

Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units

b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production

Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit

Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit

c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production

Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700

Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300

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According to the given statement , the acceleration of the sphere at the instant when its speed is 27.0 m/s.

We can use the principles of electrostatics and kinematics.  a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).

1. Determine the electric force between the two charges:
  - The electric force between two charges can be calculated using Coulomb's Law:

F = k * |q1 * q2| / r².
  - In this case, q1 = 5.00 μC and q2 = +2.00 μC. The distance between them, r, is the horizontal distance of 8.00 cm (which is 0.08 m).
  - The constant k is 9.00 x 10⁹ N * m^2 / C².
  - Plugging in the values, we get F = (9.00 x 10^9 N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)².

2. Calculate the net force acting on the sphere:
  - At any instant, the net force acting on the sphere is the sum of the electric force and the force due to gravity.
  - However, in this case, gravity can be neglected, as stated in the question.
  - Therefore, the net force acting on the sphere is equal to the electric force between the two charges.

3. Calculate the mass of the sphere:
  - The mass of the sphere is given as 4.00 x 10⁻³ kg.

4. Apply Newton's second law:
  - Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration: Fnet = m * a.
  - In this case, the net force acting on the sphere is the electric force between the charges.
  - Plugging in the values, we get (9.00 x 10⁹ N * m^2 / C²) * |5.00 μC * 2.00 μC| / (0.08 m)² = (4.00 x 10⁻³ kg) * a.

5. Solve for the acceleration:
  - Rearranging the equation, we have a = [(9.00 x 10⁹ N * m² / C²) * |5.00 μC * 2.00 μC| / (0.08 m)²] / (4.00 x 10⁻³ kg).
  - Evaluating the expression, we find the value of acceleration.

By following these steps, you can find the acceleration of the sphere at the instant when its speed is 27.0 m/s.

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Answer:

b

Explanation:

your welcome :)

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass in kg

v is the velocity in m/s

From the question

m = 60 kg

v = 10 m/s

We have

\(k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000\)

We have the final answer as

Hope this helps you

Answer:

\(\boxed {\boxed {\sf 3000 \ J}}\)

Explanation:

Kinetic energy is the energy an object has due to motion. It is calculated using the following formula:

\(KE=\frac{1}{2} mv^2\)

The mass of the go-cart is 60 kilograms and the velocity is 10 meters per second.

Substitute the values into the formula.

\(KE= \frac{1}{2} (60 \ kg)(10 \ m/s)^2\)

Solve the exponent.

\(KE = \frac{ 1}{2} (60 \ kg)(100 \ m^2/s^2)\)

Multiply the numbers together.

\(KE= 30 \ kg * 100 \ m^2/s^2\)

\(KE= 3000 \ kg*m^2/s^2\)

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 3000 kg*m²/s² equals 3000 Joules.

\(KE= 3000 \ J\)

The go-cart has 3000 Joules of kinetic energy.