Ill MARK BRAINLIST PLS HELP !!!

The total weight of the liquid in the tank is approximately 12,628 pounds.

To calculate the weight of the liquid, we need to determine the volume of the hemisphere and then multiply it by the density of the liquid. The formula for the volume of a hemisphere is V = (2/3)πr³, where r is the radius of the hemisphere.

In this case, the diameter of the tank is given as 24 feet, so the radius is half of that, which is 12 feet. Plugging this value into the formula, we get V = (2/3)π(12)³ ≈ 904.78 cubic feet.

Finally, we multiply the volume by the density of the liquid: 904.78 cubic feet * 92.5 pounds per cubic foot ≈ 12,628 pounds. Therefore, the total weight of the liquid in the tank is approximately 12,628 pounds.

In summary, to calculate the weight of the liquid in the tank, we first determine the volume of the hemisphere using the formula V = (2/3)πr³. Then, we multiply the volume by the density of the liquid.

By substituting the given diameter of 24 feet and using the appropriate conversions, we find that the total weight of the liquid is approximately 12,628 pounds.

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Answer:

Step-by-step explanation:

Use of formula:

According to above and based on given:

Answer: -2,2 -5,2 then the other translation gives you the answer of -2,2

Step-by-step explanation:

Answer:

The answer is (-2,2)

Step-by-step explanation:

(-5+3 , 4-2)

=(-2 , 2)

Answer:

(C) 7

Step-by-step explanation:

We can create an equation here.

We know that Zander has 38 texts. He sends 28 texts per day.

Let us represent x as the number of days.

This can be represented as an expression, \(38+28x\).

Same logic for Chloe.

52 texts already, 26 texts per day: \(52+26x\)

If their texts are equal, both expression are equivalent to each other.

\(38+28x = 52+26x\)

We can simplify this equation to get x on one side of it.

Subtract 38 from both sides:

\(28x = 14+26x\)

Subtract 26x from both sides:

\(2x =14\)

Divide both sides by 2:

\(x = 7\)

So, Chloe and Zander will have sent the same amount of texts after 7 days.

Hope this helped!

The multiple of 2, 5, and 7, such that the sum of the 3 digits is 10 is:

630

We want to find a number that is a multiple of 2, 5 and 7, such that the sum of the 3 digits is 10. (such that the number is not 280)

So our number N is of the form:

N = a*(2*5*7)

Where a is an integer.

N = a*70

Here we just need to find the value of a such that the sum of the 3 digits of the outcome is equal to 10.

For example, if a = 2 then:

N = 2*70 = 140

The sum gives 1 + 4 + 0 = 5

Now we jut need to keep trying values of a.

Eventually, we will get to:

if a = 9 then:

N = 9*70 = 630

The sum gives: 6 + 3 + 0 = 10

So this is our number.

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The distance between point P and line L is 16/9√(13).

To find the distance between point P and line L, we can use the formula for the distance between a point and a line in two-dimensional space. The formula is as follows:

Let P = (x1, y1) be the point and L be the line ax + by + c = 0. Then the distance between P and L is:

|ax1 + by1 + c|/√(a² + b²)

To find a, b, and c for the given line, we need to put it in slope-intercept form y = mx + b by solving for y.

2x - 3y = 12=> 2x - 12 = 3y=> (2/3)x - 4 = y

The slope of the line, m, is the coefficient of x, which is 2/3. Therefore, the line is:

y = (2/3)x - 4The values of a, b, and c are: a = 2/3b = -1c = -4

Now we can substitute the coordinates of P and the values of a, b, and c into the formula for the distance between a point and a line.

Let P = (3, 5).|a(3) + b(5) + c|/√(a² + b²)= |(2/3)(3) - 1(5) - 4|/√[(2/3)² + (-1)²]= |-4/3 - 4|/√(4/9 + 1)= 16/9√(13).

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The length of one of the sides of the square base is 6 inches.

Let's denote the length of one of the sides of the square base by "s" and the height of the pyramid by "h". Then, the surface area of the pyramid can be expressed as:

Surface area = area of square base + sum of areas of four triangular faces

Surface area = s^2 + 4(1/2)(s)(h)

We know that the surface area is 116 in^2 and the sum of the areas of the four triangular faces is 80 in^2. So we can substitute these values into the equation:

116 = s^2 + 4(1/2)(s)(h)

80 = 4(1/2)(s)(h)

We can simplify the second equation to get:

20 = (1/2)(s)(h)

We can solve for h by substituting the value of (1/2)(s)(h) from the second equation into the first equation:

116 = s^2 + 4(20)

116 = s^2 + 80

s^2 = 36

s = 6

Therefore, the length of one of the sides of the square base is 6 inches.

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9514 1404 393

Answer:

  C.  161.459 square feet

Step-by-step explanation:

In feet, the dimensions of the pool are ...

  (5 m)(3.28084 ft/m) = 16.4042 ft

  (3 m)(3.28084 ft/m) = 9.84252 ft

Then the area of the pool is ...

  (16.4042 ft)(9.84252 ft) = 161.458666584 square feet

  about 161.459 square feet

_____

Additional comment

If you consider that a square meter is slightly less than 11 square feet, the pool area can be estimated to be (5 m)(3 m)(11 ft²/m²) = 165 ft². This is close enough to point you to the correct answer choice.

Answer:

t-2

Step-by-step explanation:

"less than a number t" read backwards

t-2

Answer:

2x

Step-by-step explanation:

5, 10, 20, 40, 80

each step is multiplying by 2, therefore the sequence is 2x

Answer:

the probability that a child is excluded from all rides is 0.5000 (rounded to three decimal places).

Step-by-step explanation:

We can use the standard normal distribution to solve this problem. We first need to standardize the height requirements using the population mean and standard deviation.

a) To find the probability that a child can go on all rides, we need to find the probability of getting a height of at least 54 inches.

z-score = (54 - 53) / 4 = 0.25

Using a standard normal table or calculator, we find that the probability of getting a z-score of 0.25 or greater is 0.4013.

Therefore, the probability that a child can go on all rides is 0.4013 (rounded to three decimal places).

b) To find the probability that a child can participate in only mild and moderate rides, we need to find the probability of getting a height between 42 inches and 48 inches.

First, we find the z-scores for each height requirement:

z-score for 42 inches = (42 - 53) / 4 = -2.75

z-score for 48 inches = (48 - 53) / 4 = -1.25

Using a standard normal table or calculator, we find that the probability of getting a z-score between -2.75 and -1.25 is 0.2375.

Therefore, the probability that a child can participate in only mild and moderate rides is 0.2375 (rounded to three decimal places).

c) To find the probability that a child can only go on mild rides, we need to find the probability of getting a height of less than 42 inches.

z-score = (42 - 53) / 4 = -2.75

Using a standard normal table or calculator, we find that the probability of getting a z-score of -2.75 or less is 0.0030.

Therefore, the probability that a child can only go on mild rides is 0.0030 (rounded to three decimal places).

d) To find the probability that a child is excluded from all rides, we need to find the probability of getting a height less than 42 inches or greater than 54 inches.

First, we find the z-scores for each height requirement:

z-score for 42 inches = (42 - 53) / 4 = -2.75

z-score for 54 inches = (54 - 53) / 4 = 0.25

Using a standard normal table or calculator, we find that the probability of getting a z-score of less than -2.75 or greater than 0.25 is 0.0987 + 0.4013 = 0.5000.

Therefore, the probability that a child is excluded from all rides is 0.5000 (rounded to three decimal places).

Answer:

7 1/2

Step-by-step explanation:

2 1/2 ÷ 1/3

Change to an improper fraction

(2*1+2)/2 ÷ 1/3

5/2 ÷1/3

Copy dot flip

5/2 * 3/1

15/2

Change to a mixed number

7 1/2

Answer:<2 and <3 are the two angles that are exterior angles!

Step-by-step explanation:

Hope this helped!

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The percentage of boys in the class and also the standard deviation of heights of all the students in the class are 78% and 9 cm respectively

Percentage of the boys in the class deals with a ratio of the boys to the number of students in the class

The given parameters that will help us to get the percentage are

Mean height of the class = 152 cm

Mean height of the boys = 158 cm

The standard deviation of the boys = 5 cm

Mean height of the girls = 148 cm

Standard deviation of the girls = 4 cm

(1) The percentage of boys in the class is

Total mean height = 158 +148 = 306

Percentage = 158/306 * 100 = 51.6%

Then the  percentages 51.6/100 * 152 = 78%

(2) The total standard deviation of all the students

Boys + girls = 5+4 = 9 cm

Therefore, the percentage of boys in the class and also the standard deviation of heights of all the students in the class are 78 students and 9 cm respectively

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Answer:

\(y=1-Ae^{\frac{1}{2}x^2-x}\)

Step-by-step explanation:

Given equation:

\(\dfrac{\text{d}y}{\text{d}x}=(1-x)(1-y)\)

Separate the variables by moving all the y terms to one side of the equation and all the x terms to the other side:

\(\implies \dfrac{1}{(1-y)}\;\text{d}y=(1-x)\;\text{d}x\)

Integrate both sides of the equation separately:

\(\implies \displaystyle \int \dfrac{1}{(1-y)}\;\text{d}y= \int (1-x)\;\text{d}x\)

\(\implies -\ln |1-y|+C=x-\dfrac{1}{2}x^2+D\)

\(\implies \ln |1-y|-C=\dfrac{1}{2}x^2-x-D\)

Write the two constants as one (a = -D + C):

\(\implies \ln |1-y|=\dfrac{1}{2}x^2-x+a\)

Take exponents of both sides:

\(\implies e^{\ln |1-y|}=e^{\frac{1}{2}x^2-x++a}\)

\(\textsf{As }\; e^{\ln y}=y:\)

\(\implies 1-y=e^{\frac{1}{2}x^2-x+a}\)

\(\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c:\)

\(\implies 1-y=e^{\frac{1}{2}x^2-x}e^{a}\)

As \(e^{a}\) is just a constant, replace it with A:

\(\implies 1-y=Ae^{\frac{1}{2}x^2-x}\)

Rearrange to make y the subject:

\(\implies y=1-Ae^{\frac{1}{2}x^2-x}\)

Answer:

x = - 1

Step-by-step explanation:

P = \(\frac{x-2}{x+1}\)

the denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that x cannot be.

x + 1 = 0 ( subtract 1 from both sides )

x = - 1

P is undefined when x = - 1

Step-by-step explanation:

the inside expression of an absolute value expression can be positive or negative, but the result is only the positive one.

therefore, for our example here the negative case would be

2.5x - 6.8 = -12.9

which gives us

2.5x = -6.1

x = -6.1/2.5 = -2.44

and the positive case would be

2.5x - 6.8 = 12.9

and that gives us

2.5x = 19.7

x = 19.7/2.5 = 7.88

Answer:

22.

\(rcos \theta = rsin \theta\)

23.

\((rcos \theta) ^{2} + (rsin \theta) ^{2} = 25\)

Step-by-step explanation:

To change the equation to polar form replace x with \( rcos\theta\)

and y with \( rsin\theta\)

Step-by-step explanation:

5x2=10 31/10=10 1/4 10 1/4 /3=3

So the answer is 3

Answer:

33m

Step-by-step explanation:

add up all of the sides

9+9=18

18+15=33

Answer:

9+9+15 = the perimeter.

Step-by-step explanation:

The perimeter is the length of the outside lines of the triangle.

9+9+15 = 33

Answer:

9

Step-by-step explanation:

Answer:

9 clients ran at least 2 laps

Step-by-step explanation:

5 clients ran 2 laps, and 4 clients ran 3 laps

Step-by-step explanation:

OUT of  35 spins   4 + 15 + 3  = 22   were blue or green or purple

 22/35 probability  = 63%

The perimeter and the area of the rectangle are 26 units and 42 square units, respectively.

A rectangle is a quadrilateral with all four interior angles 90°.

Given that, the vertices of the rectangle are (-3.5,3), (3.5,3), (3.5,-3), and (-3.5,-3).

The length of the  rectangle is:

l = 3.5 - (-3.5)

l = 3.5 + 3.5

l = 7

The width of the rectangle is:

w = 3-(-3)

w = 3 + 3

w = 6

The perimeter of the rectangle is given by:

P = 2 (l +w)

P = 2(7 + 6)

P = 26

The area of the rectangle is:
A = l × w

A = 7 × 6

A = 42

Hence, the perimeter and the area of the rectangle are 26 units and 42 square units, respectively.

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