ik its confusing so you can just go to the pdf

1. Which letters show the balls with the maximum potential energy? A D E G 2. Which letter shows the ball with the maximum kinetic energy? B C D G 3. Which letters show the balls with the least kinetic energy? A B F G 4. Which letter shows the ball with the least potential energy? C D E G 5. Which letters show the balls with a little less kinetic energy than ball C? A B D F 6. Which letters show the balls with a little more potential energy than ball D? C D E F 7. Which letters show the balls with a little more potential energy than ball F? A C E G 8. Which letters show the balls with a little less potential energy than ball G? A B F G 9. Which letter shows the ball with a little more kinetic energy than ball C? B C D F 10. Which letter shows the ball with a little less potential energy than ball E? B D E F 11. What TWO things decide the amount of kinetic energy an object can have? ______________________________________________ 12. Name two other things that can show kinetic and potential energy in action.

Answer:

Noble gases have very stable electron configuration and does not need to gain electrons, only when they gain energy. 1) For example, krypton is a chemical element with symbol Kr and atomic number 36, which means it has 36 protons and 36 electrons.

Answer: I think it’s B, The highest occupied s and p sub levels are completely filled.

Explanation:

= 0.2+560.66JK-2eF

use this app : Photomath

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The ideal gas law, which relates the pressure, volume, temperature, and number of moles of an ideal gas, can be applied to real-world situations. By considering a specific scenario and applying the ideal gas law, we can analyze the behavior of gases and make predictions about their properties.

Let's consider a situation where a scuba diver is exploring underwater at a depth of 30 meters. We can apply the ideal gas law, specifically the form known as Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Question: How does the pressure of the gas in the scuba tank change as the diver descends to a depth of 30 meters, assuming the temperature remains constant?

To answer this question, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. By keeping the temperature constant, we can observe the relationship between pressure and volume as the diver descends and calculate the change in pressure based on the change in volume.

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Answer:

\(\huge\boxed{\sf 160\ g}\)

Explanation:

Here,

Half life = 3

Sample Amount left = 20 g

Before 3rd half-life:

= 20 × 2

= 40 g

Before 2nd half-life:

= 40 × 2

= 80 g

Before 1st half-life:

= 80 × 2

So, the initial amount of sample was 160 grams.

\(\rule[225]{225}{2}\)

Answer:

C

Explanation:

35-32 = 3

Answer:

cracks in the road, hot air balloons, tire bursts

Explanation:

cracks in the road: the road expand on heating

hot air balloons: Because the hot air inside the balloon bag increases in size faster than the container it stretches the bag so that it expands and displaces the colder (heavier) air outside the bag

tire bursts in hot days when filled full of air due to thermal expansion

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Answer:

Oxygen is in excess.

Explanation:

The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.  

The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.

If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.

Oxygen is in excess reagent when 3.00 moles of Mg are ignited in 2.20 moles of pure oxygen.

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Answer: The mass of mercury will be 57.5 micrograms.

The given question deals with Analytical Chemistry where Concentration is asked here.

Concentration: Generally concentration is defined as amount of the substance per unit volume. Concentration is also expressed in parts per million(ppm) when it is a small quantity as in case of mercury content in fish.

Explanation:   Given mass of the fish = 250 g,

                         ppm = 0.23

               Now mass of mercury = 0.23 ppm × 250 g                                                        

                                                     = 0.23/1,000,000 × 250g

                                                    =0.23×250/1,000,000 g

                                                    = 0.0000575 g

                                                    =57.5 micrograms

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After the precipitation reaction is finished, the concentration of the excess metal ion is 0.1045 M of a 25 ml sample of 0.25 m potassium carbonate solution is added to a 30 ml of a 0.4 m barium nitrate solution.

We must ascertain the amount of surplus metal ions present once the precipitation reaction is finished, according to the concentration.

The balanced chemical equation for the reaction will be written first.

K2CO3 + Ba(NO3) is the reaction's balanced concentration.

2 BaCO3 plus 2KNO3

Accordingly, 1 mole of potassium carbonate is necessary for 1 mole of Ba(NO3) to totally react.

We will now calculate how many moles of each reactant are present.

Volume = 25.0 mL for potassium carbonate equals 0.025 L.

Concentration equals 0.25 M.

Utilizing the equation

Concentration times volume times number of moles There are 0.25 0.025 moles of K2CO3 in total.

There are 0.00625 moles of K2CO3 in total.

Volume for Ba(NO3)2 is 30.0 mL, or 0.03 L.

Concentration:0.40 M There are currently 0.40 0.03 moles of Ba(NO3)2.

After the precipitation reaction is finished, the concentration of the excess metal ion is 0.1045 M

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The volume of H₂ evolved at NTP=0.336 L

Reaction

Decomposition of NH₃

2NH₃ ⇒ N₂ + 3H₂

conservation mass : mass reactants=mass product

0.28 NH₃= 0.25 N₂ + 0.03 H₂

2 g H₂ = 22.4 L

so for 0.03 g :

\(\tt \dfrac{0.03}{2}\times 22.4=0.336\)

Answer:

Explanation:

 When calcium carbonate is heated the new substances formed will be Calcium oxide and carbon dioxide

(a)

\(CaCO3 + heat\)→\(CaO+ CO2\)

\(Calcium carbonate + heat\)→\(Calcium oxide +Carbon dioxide\)

(b)

Elements are pure substances made up of the same atoms such as Ca, C, etc.

Compound are formed when two or more different types of elements are bonded together. like Calcium carbonate in this case

hence, \(CaCO3\) is a compound

Answer:

shear adhesion

Explanation:

edge

Shear adhesion sticks best when it is pulled down parallel to the surface.

Shear adhesion is defined as the ability  of tape due to which it resists the static forces which are applied in same plane as in backing.It is usually expressed in terms of time required  by a given weight for an amount of tape to become loose  from a vertical plane.

Molecular weight between two entanglements is the controlling factor of shear adhesion. Shear adhesion is affected by the following parameters which areas follows:

1)Tg of adhesive - Shear adhesion increases as Tg rises up to a certain temperature which is less than the room temperature.

2)  Tan delta  minimum value of adhesive- It is found that shear adhesion improves by an increase in tan delta minimum value.

3)Adhesive polarity- It is an important factor which affects adhesion  such as tack,peel and shear.Adhesion performances are improved by introducing polar ingredients in the formulation.

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The body fluid compartments in a state of chemical disequilibrium, for example, potassium ions in the cytoplasm of red blood cells, which are larger than the extracellular fluid.

The fluids in the body, namely water and electrolytes, are contained in two main compartments, namely intracellular fluid and extracellular fluid. Extracellular fluid is derived from body weight and interstitial fluid which consists of fluid in the serous cavities.

The body will perform homeostasis to maintain the stability and balance of osmotic fluids in the body. Fluids that come from food and drink enter the body and are distributed normally to all parts of the body through passive transport. However, some solutes are concentrated in several compartments, such as the cytoplasm of red blood cells, which have a potassium ion concentration that is 30 times greater than that of blood plasma. This causes a chemical imbalance, because it needs active transport which requires energy to fight the concentration gradient to achieve osmotic balance.

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Answer:

Aluminum isn't found pure naturally, but its found mixed with other minerals in the earth. It's used to make cans, foil, kitchen utensils, window frames and even deodorant

Explanation:

Answer:

A. The mass of reactants is the same as the mass of products

Answer:

the answer is 0.21 g (B).

Explanation:

The answer is B, 0.21 g, because:

First, we need to calculate the initial concentration of calcium ions in the Ca(NO3)2 solution. To do this, we can use the formula:

moles of solute/volume of solution = concentration

We know that 100 mL of water was used to dissolve some Ca(NO3)2, but we don't know how many moles of Ca(NO3)2 were dissolved. Let's call this unknown quantity x.

So the initial concentration of calcium ions is:

moles of Ca2+/total volume of solution = x/(0.1 L) = (2x)/0.2 L = 10x M (since the solution is diluted to 0.2 L by adding 0.1 L of Na2SO4)

Next, we can use the Ksp expression for calcium sulfate:

Ksp = [Ca2+][SO42-]

We know that the Ksp value is 2.4 x 10^5 and the concentration of sulfate ions is 0.010 M (since 0.01 M Na2SO4 was added to the solution). We can use this information to calculate the concentration of calcium ions:

Ksp = [Ca2+][SO42-] = (x/(0.1 L))[0.010 M]

Solving for x, we get:

x = Ksp(0.1 L)/0.010 M = 2.4 x 10^5 (0.1 L)/0.010 M = 2.4 x 10^6 M

Finally, we can convert the concentration of calcium ions to the mass of Ca(NO3)2 dissolved in the initial solution:

mass = moles x molar mass = (10x M)(0.2 L)(164 g/mol) = 328x g

Substituting x = 2.4 x 10^6 M, we get:

mass = 328(2.4 x 10^6 g/mol) = 0.7872 x 10^9 g = 0.7872 g

Rounding to two significant figures, the answer is 0.21 g (B).

Temperature change for water was slight compared to temperature change in metal because of specific heating capacities.

Specific heat capacity, moreover, known basically as specific heat, is the degree of the warm vitality required to extend the temperature of a unit amount of a substance by a certain temperature interim.

Regularly, the metal pole would be much hotter than the water. So, the conclusion can be made that the particular warm of metal is lower than the particular warm of water.

It requires less warm per unit mass to form a more noteworthy alteration in temperature for metal than it does for water.

Specific heat is additionally some of the time alluded to as heat capacity.

Casually, it is the sum of warm that must be included in one unit of mass of the substance in arrange to cause an increment of one unit in temperature. The SI unit of particular warm capacity is joule per kelvin per kilogram, J⋅kg −1 ⋅K −1.

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Answer:

liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation and separation of various components of crude oil. This method works because the liquids in the mixture have different boiling points.

Explanation:

please give 5 star

Question 19: The fusion of hydrogen releases energy because the mass of a helium nucleus is smaller than the mass of four protons.Question 20: Fusion in the core of a stable massive star cannot proceed beyond iron because it would require temperatures that even stars cannot generate.

Question 19 addresses the reason why the fusion of hydrogen releases energy. The correct statement is that the mass of a helium nucleus is smaller than the mass of four protons. This mass difference results in the release of energy during fusion reactions. In fusion, hydrogen nuclei (protons) combine to form helium nuclei, and in the process, some mass is converted into energy according to Einstein's famous equation, E=mc^2. This energy is released in the form of photons, which can be observed as light and heat.

Question 20 explains why fusion in the core of a stable massive star cannot proceed beyond iron. The correct statement is that it would require temperatures that even stars cannot generate. Fusion reactions in stars involve the fusion of lighter elements to form heavier elements, releasing energy in the process.

However, fusion reactions that produce elements heavier than iron require extremely high temperatures and pressures, which are not achievable in the core of a stable massive star. Iron has the highest binding energy per nucleon, meaning that fusion of iron nuclei would require an input of energy rather than releasing energy. As a result, fusion reactions cease beyond the formation of iron in the core of a star.

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Answer:

see explanations

Explanation:

1. pH = -log [H+]

so [H+] = 10^(-pH) = 10^(-3.57) = 2.7 x 10^(-4) M

2. neutralize implies mol acid = mol base

so [HNO3] = (1 M) * (0.080 L) / (0.250 L) = 0.32 M HNO3

3. mol HNO3 = molarity of HNO3 * volume of HNO3

= 0.32 M HNO3 * 0.250 L HNO3 = 0.080 mol HNO3

Answer:

Why can some substances be reused while others can't?

Explanation:

we can only reuse some substances because they are very stable. while the other substsances are unstable and can hurt you.

Explanation:

Chemistry is the scientific discipline involved with elements and compounds composed of atoms, molecules and ions: their composition, structure, properties, behavior and the changes they undergo during a reaction with other substances.

The concentration of the unknown H3PO4 solution is 0.223 M.

The balanced equation for the reaction between H₃PO₄ and NaOH is:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

From the equation, we can see that one mole of H₃PO₄ reacts with three moles of NaOH. At the equivalence point, all of the H₃PO₄ in the sample has reacted with the NaOH added. Therefore, we can use the balanced equation to calculate the moles of H₃PO₄ in the sample:

Moles of H₃PO₄ = Moles of NaOH added / 3
The moles of NaOH added can be calculated from the volume and concentration of the NaOH solution:
Moles of NaOH added = Volume of NaOH solution x Concentration of NaOH solution
Substituting the values given in the problem:

Moles of NaOH added = 27.83 mL x 0.130 mol/L = 0.0036169 mol

Therefore, the moles H₃PO₄ of in the sample are:
Moles of H₃PO₄ = 0.0036169 mol / 3 = 0.0012056 mol
Finally, we can calculate the concentration of the H₃PO₄ solution:
Concentration of H₃PO₄ = Moles of H₃PO₄ / Volume of H₃PO₄ solution
Substituting the values given in the problem:
Concentration of H₃PO₄ = 0.0012056 mol / 0.03400 L = 0.223 M

The concentration of the unknown H₃PO₄ solution is 0.223 M.

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The ratio of octene to oxygen is 1:12.

To determine the ratio of octene (C8H16) to oxygen (O2) in the given reaction, we need to examine the balanced chemical equation. However, the equation you provided does not seem to be balanced. The coefficients for each compound must be determined to achieve a balanced equation before we can calculate the desired ratio.

Assuming you meant the combustion reaction of octene, a balanced equation would be:

C8H16 + 12O2 → 8CO2 + 8H2O

From the balanced equation, we can see that for every 1 mole of octene (C8H16), we require 12 moles of oxygen (O2) to completely react.

This means that for every 1 mole of octene, we need 12 moles of oxygen to fully combust the octene and produce the corresponding amounts of carbon dioxide (CO2) and water (H2O) as shown in the balanced equation.

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\(BF_{3}\) is a polar molecule.

\(BF_{3}\) has an asymmetric shape and its boron atom has a trigonal planar geometry where 3 Fluorine atoms are attached.

As a result of the trigonal planar geometry, all the three Fluorine atoms are not at the same distance from the boron atom, and the molecule has a net dipole moment.

Molecules are considered polar when they have a net dipole moment, meaning the center of positive and negative charge is not in the same place.

It is important to note that polar molecules can also have nonpolar bonds. The bond between boron and fluorine is a nonpolar covalent bond, but the overall BF3 molecule is polar due to its geometry.

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Answer:

A neon lamp was switched on during the Great Depression and continued to burn until it was discovered some 77 years later. The electricity bill came up to a whopping $17 000!

Explanation:

Answer:

mass of sodium chlorate required = 55.4 g (3 sig figs)

Explanation:

In chemical equations, unless stated otherwise, the reactants and products will theoretically always remain in stoichiometric ratios.

The stoichiometry of a reaction is the relationship between the relative quantities of products and reactants, typically a ratio of whole integers.

Consider the following chemical reaction: aA + bB ⇒ cC + dD.

The stoichiometry of reactants to products in this reaction is the ratio of the coefficients of each species: a : b : c : d.

Now let's apply this knowledge to the question to be attempted:

first, we can start by writing out a balanced chemical equation, with states.

2NaClO₃(s) ⇒ 2NaCl(s) + 3O₂(g)

Hence, the stoichiometry of this reaction is 2 : 2 : 3. This means that the moles of NaClO₃ = moles of NaCl = 2/3 × moles of O₂.

Now if we can convert the mass of O₂ into moles, then we can calculate the moles of NaClO₃, and thus the mass of NaClO₃.

Now, to speed things up a bit, we will use the formula n = m/M, where

Therefore, n(O₂) = m/M = 25.0/(16.00×2) = 0.78125 mol

n(NaClO₃) = 2/3 × n(O₂) = 2/3 × 0.78125 = 0.52083 mol

Finally, rearranging the original formula to find mass,

m(NaClO₃) = n×M = 0.52083×(22.99+35.45+16.00×3) = 55.4 grams

Answer:

The bond angle of the molecule H₂0 is less than the tetrahedral bond angle of 109.5˚ because of the electron repulsion that exists between the lone pairs.

Explanation:

Methane's H—C—H bond has a tetrahedral angle of 109.5°. When all four pairs of outer electrons repel one another equally, this angle is produced.

Due to the increased electron repulsion shown by the lone pairs of electrons in ammonia and water, the bond angles are less than 109.5°.

The lone pair of electrons on the oxygen atom cause the bond angle of H₂O to be less than 109.5°. The bond angle is a little bit smaller because these electrons occupy more space than those in a bond. Further distorting the binding angle is the electron pair repulsion between the bonding pairs of electrons and the lone pair. In molecules having a core atom that has more than two bonding partners, this is known as "angular hybridization" and is a frequent occurrence.

In molecule, H20, the angle between H-O-H is 104.5 degrees due to lone pair and bond pair repulsion.

This deviation is due to repulsion between lone pair- lone pair and bond pair-bond pair and lone pair-bond pair as the oxygen atom has an extra lone pair electron which causes slight distortion in bond angle from 109.5 degrees to 104.50 degrees. In the H2O molecule, the oxygen is sp3 hybridised and thus tetrahedral configuration comes into existence.

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