If your car goes from 0 mi/h to 80 mi/h in 5 s, what is your average acceleration?
Answer in units of miles/ h · s

Refraction would cause the red light to bend at the air/glass boundary.

While the question is unclear, I assume that you are trying to know something about the refraction of the red light across the air/glass boundary. I will tell you something about refraction!

Refraction is a phenomenon of light where it changes direction when it enters a medium with a different refractive index. Refractive index is a measure of how much a medium bends light that passes through it. When light passes from a medium with a lower refractive index to a medium with a higher refractive index, it bends towards the normal (an imaginary line perpendicular to the surface at the point of incidence). On the other hand, when light passes from a medium with a higher refractive index to a medium with a lower refractive index, it bends away from the normal.

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After plugging all the data into the equation, the result of the relative centrifugal force (RCF)  is measured in terms of g.

The relative centrifugal force (RCF) or the g force is the radial force generated by the spinning rotor as expressed relative to the earth's gravitational force.

RCF = ac/g

where;

\(RCF = \frac{\omega ^2 r}{g} = 1.118\times 10^{-5} \ (RPM)^2 r = 11.18r\ (RPM/1000)^2\)

where;

Find the maximum RCF of the JS-4.2 rotor can be obtained from its maximum speed (4200 rpm) and its rmax (250 mm);

\(RCF = 11.18 \times 25\ cm \times (\frac{4200 \ RPM}{1000} )^2 = 4,930.3 \times g\)

Thus, after plugging all the data into the equation, the result is measured in terms of g.

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Answer:

μs = 0.30

μk = 0.24

Explanation:

In order to calculate the kinetic friction and static friction between the block and the surface, you take into account that the kinetic friction is important when the block is moving and the static friction when the block is at rest.

You use the following formula to find the coefficient of static friction:

\(F_1=\mu_s Mg\)       (1)

F1 = 75N

μs: coefficient of static friction = ?

M: mass of the block = 25.0kg

g: gravitational acceleration = 9.8m/s^2

You solve for μs in the equation (1):

\(\mu_s=\frac{F_1}{Mg}=\frac{75N}{(25.0kg)(9.8m/s^2)}=0.30\)

For the coefficient of kinetic friction you have:

\(F_2=\mu_k Mg\)       (2)

F2 = 60N

μk: coefficient of kinetic friction = ?

You solve for μk in the equation (2):

\(\mu_k=\frac{F_2}{Mg}=\frac{60N}{(25.0kg)(9.8m/s^2)}=0.24\)

Then, you have:

coefficient of static friction = 0.30

coefficient of kinetic friction = 0.24

Answer:

117.06 A

Explanation:

V = IR

2650 = 66(R)

2650/66 = R

40.15 = R

V = IR

4700 = I(40.15)

4700/40.15 = I

117.06 = I

The average velocity is 127.27 m/s while the initial velocity is 14.55 m/s

According to Newton's law of motion:

s = [(v + u)/2]t

Where s is the distance moved = 1400 m, v is the final velocity = 240 m/s, u is the initial velocity, t is the time taken = 11 s, hence:

1400 = [(240 + u)/2)11

2800 = (240 + u)11

u + 240 = 254.55

u = 14.55 m/s

The average velocity = (v + u)/2 = (240 + 14.55)/2 = 127.27 m/s

Therefore the average velocity is 127.27 m/s while the initial velocity is 14.55 m/s

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19,600 Newtons (about 4,400 pounds).

On Earth only.

Different in other places.

If the force provided by the engine of a toy car decreases, the car will slow down and eventually come to a stop.

1. The force provided by the engine of a toy car is responsible for propelling it forward at a constant speed. This force overcomes any friction or resistance acting on the car.

2. When the force provided by the engine decreases, there is a reduction in the overall force acting on the car. As a result, the force can no longer counteract the resistance and friction effectively.

3. The resistance and friction acting on the toy car, such as air resistance and the friction between the wheels and the surface, start to have a greater impact on the car's motion.

4. With a reduced force from the engine, the car begins to slow down gradually. The deceleration occurs because the opposing forces now have a greater influence on the car's motion.

5. As the force continues to decrease, the opposing forces eventually surpass the remaining force from the engine. Consequently, the toy car slows down even more and eventually comes to a complete stop.

6. If the force provided by the engine becomes extremely low or nonexistent, the opposing forces will completely overpower the forward force, causing the toy car to stop moving altogether.

In summary, when the force provided by the engine of a toy car decreases, the car's speed decreases, and it eventually comes to a stop due to the increased influence of opposing forces.

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the frictional force on the broom has magnitude μ * m * g * cos(theta)

The frictional force on the broom can be determined using the equation:

F_friction = μ * F_norm

Where F_friction is the frictional force, μ is the coefficient of friction, and F_norm is the normal force. The normal force is equal to the force exerted on the broom perpendicular to the surface of the floor. Since the broom is being pushed across a horizontal surface, the normal force is equal to the force of gravity, which is equal to the mass of the broom (m) multiplied by the acceleration due to gravity (g).

F_norm = m * g

The force being applied to the broom is 7N and it is at angle theta with the horizontal. The component of this force perpendicular to the surface of the floor is the force that acts on the normal force.

F_norm = 7 * cos(theta)

Therefore,

F_friction = μ * m * g * cos(theta)

So, the frictional force on the broom has magnitude μ * m * g * cos(theta)

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Answer:

A.

Explanation:

\(1. the \ initial \ formula \ is\\ \ mgh=\frac{m(Vsin \theta)^2}{2}; \\ 2. \ finally, \\ h=\frac{V_0^2sin^2 \theta}{2g}.\)

Answer:

D

Explanation:

Mass is the amount of matter your body has ....does not change on the Moon.

there is less gravity .....so your WEIGHT would decrease

Answer:

See below

Explanation:

Gallileo is CORRECT in a vacuum where there is no air friction

  air friction affects same or different weight objects differently  and will cause same-weight   or different weight  objects to fall at different speeds

The maximum height to which the ball attain before falling back down is 1147.96 m

The following data were obtained from the question:

The maximum height reached by the ball can be obtained as illustrated below:

v² = u² – 2gh (since the ball is going against gravity)

0² = 150² – (2 × 9.8 × h)

0 = 22500 – 19.6h

Collect like terms

0 – 22500 = –19.6h

–22500 = –19.6h

Divide both side by –19.6

h = –22500 / –19.6

h = 1147.96 m

Thus, the maximum height reached by the ball is 1147.96 m

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.

Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.

At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.

The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.

Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.

At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.

It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.

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Answer:

Explanation:

D. Black holes play a role in the formation of galaxies that contain stars, which help planets form and (at least for Earth) support life; but they also can subsume celestial bodies and destroy life that passes the event horizon.

The black holes are considered the "destroyers and creators" of life because Black holes play a role in the formation of galaxies that contain stars, which help planets form and (at least for Earth) support life; but they also can subsume celestial bodies and destroy life that passes the event horizon. Option (A) is correct.

In space, a black hole is a region where gravity is so strong that even light cannot escape. Because the substance is compressed into such a small area, the gravity is extremely intense. When a star is dying, this may take place.

People cannot perceive black holes because no light can escape from them. They are undetectable. Specialized space telescopes can aid in the discovery of black holes. The unique instruments can observe how stars that are very near black holes behave differently from other stars.

Black holes can vary in size. The smallest black holes, according to scientists, are as small as a single atom. These tiny black holes have the bulk of a massive mountain despite their size.

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Answer:

c- reflect with the same displacement. (not inverted)

Explanation:

When a wave goes to an end that is free to move, the reflected wave will be equal to the initial wave but will go to the opposite direction. Since the end of the wave is free to move, the answer is

c- reflect with the same displacement. (not inverted)

The rocket travels a horizontal distance of 57.4 m before hitting the ground.

The initial speed of the rocket is v0=√(v0x^2+v0y^2)=7.28 m/s.

The rocket's velocity at the maximum height is zero, as it momentarily stops moving vertically and starts falling back down.

To solve this problem, we can use the kinematic equations of motion. Let's first find the velocity and position as a function of time:

vx(t) = v0x + ∫ax(t) dt = v0x + (1/3)αt^3

vy(t) = v0y + ∫ay(t) dt = v0y + βt - (1/2)γt^2

x(t) = ∫vx(t) dt = v0x t + (1/12)αt^4

y(t) = ∫vy(t) dt = v0y t + (1/2)βt^2 - (1/6)γt^3

Now, let's find the time t1 when the rocket reaches its maximum height:

ay(t1) = 0

β - γt1 = 0

t1 = β/γ = 6.43 s

At t1, the rocket's height is:

y(t1) = v0y t1 + (1/2)βt1^2 - (1/6)γt1^3

y(t1) = 7.00 m/s × 6.43 s + (1/2) × 9.00 m/s2 × (6.43 s)^2 - (1/6) × 1.40 m/s3 × (6.43 s)^3

y(t1) = 92.5 m

Now, let's find the time t2 when the rocket hits the ground. We can do this by solving for the positive root of the quadratic equation:

y(t) = 0

(1/2)γt^2 - βt - v0y = 0

Using the quadratic formula, we get:

t2 = (β + √(β^2 + 2γv0y))/γ = 8.01 s

Finally, let's find the horizontal distance traveled by the rocket:

x(t2) = v0x t2 + (1/12)αt2^4

x(t2) = 1.00 m/s × 8.01 s + (1/12) × 2.50 m/s4 × (8.01 s)^4

x(t2) = 57.4 m

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The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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De acuerdo con la información podemos inferir que la rapidez media de la anciana es de 0.03 km/min.

Para calcular la rapidez media, dividimos la distancia recorrida por el tiempo empleado. En este caso, la anciana caminó 0.30 km en 10 minutos. Para obtener la rapidez media, dividimos 0.30 km entre 10 minutos, lo que nos da un valor de 0.03 km/min. Por lo tanto, la anciana tiene una rapidez media de 0.03 km/min.

La rapidez media se expresa en unidades de distancia divididas por unidades de tiempo. En este caso, la anciana recorrió una distancia de 0.30 km en un tiempo de 10 minutos, lo que nos da una rapidez media de 0.03 km/min. Esto significa que en promedio, la anciana camina 0.03 kilómetros por minuto durante su recorrido alrededor del centro comercial.

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Answer:

30 m

Explanation:

Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

Answer:

magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

Explanation:

Given the data in the question;

Speed of carousel N = 24 rpm

From the diagram below, selected path direction defines the Axis of slip.

Hence, The Coriolis is acting along the axis of transmission

Now, we determine the angular speed ω of the carousel.

ω = 2πN / 60

we substitute in the value of N

ω = (2π × 24) / 60

ω = 2.5133 rad/s

Next, we convert the given velocity from mph to ft/s

we know that; 1 mph = 1.4667 ft/s

so

\(V_{slip\) = 6 mph = ( 6 × 1.4667 ) = 8.8002 ft/s

Now, we determine the magnitude of the Coriolis acceleration

\(a_c\) = 2( \(V_{slip\) × ω )

we substitute

\(a_c\) = 2( 8.8002 ft/s × 2.5133 rad/s )

\(a_c\) = 44.235 ft/s²

Hence, magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

Answer:

10 m/s south

Explanation:

From 18 m/s North to 12 m/s South is a total change of 30 m/s towards the South.

So, Change in velocity = 30 m/s South

Time = 3 s

30/3=10 so 10 m/s South

The magnitude of the acceleration  of the engine that must be produced is 0.068 m/s².

The magnitude of the acceleration of the engine is calculated by applying the following kinematic equation.

s = vt + ¹/₂at²

where;

The acceleration of the engine in x direction is calculated as follows;

( 3.71 x 10⁸ x cos 46 ) = ( 1670 x cos73 )(8.64 x 10⁴) + ¹/₂ (ax)(8.64 x 10⁴)²

2.58 x 10⁸ = 4.22 x 10⁷ + 3.73 x 10⁹ax

3.73 x 10⁹ax = 2.16 x 10⁸

ax = ( 2.16 x 10⁸ ) / ( 3.73 x 10⁹ )

ax = 0.058 m/s²

The acceleration of the engine in y direction is calculated as follows;

( 3.71 x 10⁸ x sin 46 ) = ( 1670 x sin73 )(8.64 x 10⁴) + ¹/₂ (ay)(8.64 x 10⁴)²

2.67 x 10⁸ = 1.38 x 10⁸ + 3.73 x 10⁹ay

3.73 x 10⁹ay = 1.29 x 10⁸

ay = ( 1.29 x 10⁸ ) / ( 3.73 x 10⁹ )

ay = 0.035 m/s²

The magnitude of the acceleration  of the engine that must be produced is calculated as;

a = √ ( ax² + ay² )

a = √ ( 0.035² + 0.058² )

a = 0.068 m/s²

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"Gauss's law gives the amount of electrical flux that passes through a surface that surrounds an electrical charge. gauss's law works, only if that surface is cube, sphere, and cylinder." The correct options are A, B,C.

The amount of charge present on a Gaussian surface is the only factor affecting the electric flux that passes through it; size or shape have no effect.

The electric field must be 0 at all locations of a Gaussian surface if there is no charge inside of it.

In accordance with Gauss's Law, the enclosed charge divided by the permittivity yields the total electric flux leaving a closed surface. The surface area projected in a plane perpendicular to the electric field is multiplied by the electric field to determine the electric flux in a given area.

Thus, for the Gauss Law to be applicable, the surface should be closed.

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Answer:

P = 4.5 watts

Explanation:

Given that,

EMF of the circuit, E = 3 volt

The resistance  of the resistors, R = 2 ohms

We need to find the power of this circuit. The relation between power, emf and resistance is given by the formula as follows :

\(P=\dfrac{V^2}{R}\)

Substitute all the values,

\(P=\dfrac{3^2}{2}\\\\P=4.5\ W\)

So, the power of this circuit is equal to 4.5 watts.