Answer:
a=v-u/t
Explanation:
use this formula and initial velocity is 0
Answer:
Acceleration (a) is 0.416666667 m/ s^2
Explanation:
Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation
a = Δv/Δt.
An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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Difference between Weightlessness in space and weightlessness during free fall.
Weightlessness in space and weightlessness during free fall may appear similar in terms of the sensation experienced, but they occur under different circumstances and have distinct underlying causes. Here are the key differences between the two:
1.Environment:
Space: Weightlessness in space refers to the state experienced by astronauts in orbit around the Earth or in deep space. They are in a microgravity environment, far away from any significant gravitational forces.
Free fall: Weightlessness during free fall occurs when an object is falling under the influence of gravity, experiencing zero-gravity conditions momentarily. This typically happens when an object is in a state of free fall, such as during skydiving or in an airplane during a parabolic flight.
2.Gravitational Forces:
Space: In space, weightlessness is the result of being in constant free fall around the Earth. Although gravity is still present, the gravitational forces are counterbalanced by the centrifugal force created by the orbiting motion. This results in a continuous state of free fall, giving the sensation of weightlessness.
Free fall: Weightlessness during free fall occurs due to the absence of support forces countering the force of gravity. When an object is in free fall, there are no contact forces pushing against it, leading to a sense of weightlessness.
3.Duration:
Space: Weightlessness in space can last for an extended period, as long as the object or person remains in orbit or deep space. Astronauts aboard the International Space Station (ISS), for example, experience weightlessness for months at a time.
Free fall: Weightlessness during free fall is relatively brief and temporary. It occurs during the duration of the free fall, which can last for a few seconds to a couple of minutes, depending on the specific circumstances.
4.Context:
Space: Weightlessness in space is a constant state for astronauts. They adapt to this environment and conduct various experiments, work on scientific research, and live aboard the spacecraft for extended periods.
Free fall: Weightlessness during free fall is typically experienced as part of a recreational activity or a specific scientific experiment. It is a brief moment of weightlessness within the context of a larger activity, such as skydiving, parabolic flights, or drop towers.
While both weightlessness in space and weightlessness during free fall share the absence of apparent gravity and the sensation of floating, they occur in different environments, are caused by different factors, and have varying durations and contexts.
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Fill in the blanks for the following nuclear reactions.
1. 32 S + 4 He → _____
2. ____ + 4 He → 40 Ca
3. 40 Ca + 4 He → ______
4. _____ + 4 He → 48 Cr
5. 48 Cr + 4 He → _____
select a synonym for the word necessity a advertisement b extra c requirement d superior
Answer
explanation
requirments
In your own words, discuss how energy conservation applies to a pendulum. Where is the potential energy the most? Where is the potential energy the least? Where is kinetic energy the most? Where is kinetic energy the least?
Answer:
Explanation:
Energy conservation applies to the swinging of pendulum . When the bob is at one extreme , it is at some height from its lowest point . So it has some gravitational potential energy . At that time since it remains at rest its kinetic energy is zero or the least . As it goes down while swinging , its potential energy decreases and kinetic energy increases following conservation of mechanical energy . At the At the lowest point , its potential energy is least and kinetic energy is maximum .
In this way , there is conservation of mechanical energy .
An electron has an initial speed of 8.06 x10^6 m/s in a uniform 5.60 x 10^5 N/C strength electic field.The field accelerates the electron in the direction opposite to its initial velocity.
(a) What is the direction of the electric field?
i. opposite
ii. direction to the electron's initial velocity
iii. same direction as the electron's initial velocity
iv. not enough information to decide
(b) How far does the electron travel before coming to rest? m
(c) How long does it take the electron to come to rest? s
(d) What is the electron's speed when it returns to its starting point?
Answer:
Explanation:
a)
The force on electron acts opposite to the velocity , and direction of force on electron is always opposite to direction of electric field .
Hence direction of electric field must be in the same in which electrons travels.
Hence option iii is correct.
b )
deceleration a = force / mass
= qE / m
= 1.6 x 10⁻¹⁶ x 5.6 x 10⁵ / 9.1 x 10⁻³¹
= .98 x 10²⁰ m /s²
v² = u² - 2 a s
0 = (8.06 x 10⁶ )² - 2 x .98 x 10²⁰ s
s = 64.96 x 10¹² / 1.96 x 10²⁰
= 33.14 x 10⁻⁸ m
c ) time required
= 8.06 x 10⁶ / .98 x 10²⁰
= 8.22 x 10⁻¹² s .
d ) Its speed will be same as that in the beginning ie 8.06 x 10⁶ m/s .
Answer:
(a) Option (i)
(b) 6.6 x 10^-4 m
(c) 8.2 x 10^-11 s
Explanation:
initial velocity, u = 8 .06 x 10^6 m/s
Electric field, E = 5.6 x 10^5 N/C
(a) The direction of field is opposite.
Option (i).
(b) Let the distance is s.
Use third equation of motion
\(v^2 = u^2 + 2 a s \\\\0 = u^2 - 2 \times \frac{qE}{m}\times s\\\\8.06\times 10^6\times 8.06\times 10^6 = \frac {1.6\times 10^{-19}\times 5.6\times 10^5}{9.1\times 10^{-31}} s\\\\s = 6.6\times 10^{-4} m\)
(c) Let the time is t.
Use first equation of motion.
\(v = u + a t \\\\0 = u - \times \frac{qE}{m}\times t\\\\8.06\times 10^6 = \frac {1.6\times 10^{-19}\times 5.6\times 10^5}{9.1\times 10^{-31}} t\\\\t = 8.2\times 10^{-11} s\)
Which objects will likely have the smallest gravitational force between them?
A. Two tennis balls that are near each other
B. Two soccer balls that are near each other
C. Two tennis balls that are touching each other
D. Two soccer balls that are touching each other
Answer: A. Two tennis balls that are near each other
Explanation: The gravitational force between two objects depends on their masses and the distance between them. According to Newton's law of universal gravitation, the force of gravity is directly proportional to the product of the masses and inversely proportional to the square of the distance between the objects.
In this scenario and given the information provided, the tennis balls are near each other but not touching, the distance between them is small. Furthermore, tennis balls have relatively low mass and are smaller compared to soccer balls. So, the gravitational force between them will be relatively small.
Answer:
B. Two soccer balls that are near each other
Explanation:
You want to know the configuration of objects that has the least mutual gravitational attraction from ...
tennis balls near each othersoccer balls near each othertennis balls touchingsoccer balls touchingGravityNewton's law of universal gravitation says the force due to gravity between two objects is proportional to their masses and inversely proportional to the square of the distance between them.
This tells you that balls near each other will have less gravitational attraction than balls touching. This eliminates choices C and D.
Relative valueThe meaning of the word "near" each other comes into play here. If we assume that the geometry of concern has the balls at the same distance relative to their diameter, then we can look a the mass a and diameter of a soccer ball and a tennis ball to determine which pair will have less gravitational attraction.
Here are the relevant specifications:
soccer ball: 8.6-9" diameter, 400-450 g masstennis ball: 2.575-2.7" diameter, 56-59.4 g massThe fact that dimensions are mixed US and metric units is of no consequence. (The conversion factors will be the same in both cases.)
So, we can approximate the relative gravitational attraction with a "figure of merit" that is ...
fom = mass/diameter²
The attached calculator shows this figure of merit for the two ball types. The lesser value corresponds to the lesser force of gravity between soccer balls.
fom (soccer ball) ≈ 4.9
fom (tennis ball) ≈ 7.7
Two soccer balls near each other will have the smallest gravitational force.
Two equal forces act on two different objects, one of which has a mass ten times as large as the other. The larger object will have _________ acceleration that the less massive object.
Answer:
The larger object will have smaller acceleration that the less massive object.
Explanation:
Generally force is mathematically represented as
\(F = ma\)
=> \(m = \frac{F}{a }\)
at constant force we have
\(m \ \alpha \ \frac{1}{a}\)
So if m is increasing a will be decreasing which means the object with the larger mass will have less acceleration
A. 101/ B. 20Hz If 25) is taken away by heat from a sys in internal energy of the system? A. SA B..SJ SJ The amount of damping force that allow shortest possible time is called
The amount of damping force that allow shortest possible time is called critical damping of the system.
What is critical damping?Critical damping is the threshold between overdamping and underdamping at which the oscillator returns to the position of equilibrium quickly as possible.
Critical damping is frequently desired because such a system returns to and maintains equilibrium quickly. Furthermore, a constant force applied to a critically damped system moves the system to a new equilibrium position as quickly as possible without overshooting or oscillating around the new position.
Critical damping thus provides the rapid approach to zero amplitude for a damped oscillator.
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A mass attached to a vertical spring has position function given by
ANSWER:
a) -11.4 in/s
b) -29.3 in/s^2
STEP-BY-STEP EXPLANATION:
We have the following function corresponding to the position at a given time:
\(s(t)=5\sin (3t)\)If we differentiate this function with respect to time, we obtain the velocity function, like this:
\(\begin{gathered} v(t)=s^{\prime}(t) \\ s^{\prime}(t)=\frac{d}{dt}(s(t)) \\ \frac{d}{\mathrm{d}t}(5\sin (3t))=15\cos (3t) \\ v(t)=15\cos (3t) \end{gathered}\)We calculate the velocity by replacing t = 5, just like this:
\(\begin{gathered} v(t)=15\cos (3\cdot5)=15\cos (15) \\ v(t)=-11.4\text{ in/s} \end{gathered}\)If we differentiate the function again, we obtain the acceleration function, as follows:
\(\begin{gathered} a(t)=v^{\prime}(t) \\ v^{\prime}(t)=\frac{d}{dt}(v(t)) \\ \frac{d}{dt}(15\cos (3t))=-45\sin \mleft(3t\mright) \\ a(t)=-45\sin (3t) \end{gathered}\)We calculate the acceleration by replacing t = 5, just like this:
\(\begin{gathered} v(t)=-45\sin (3\cdot5)=-45\sin (15) \\ v(t)=-29.3in/s^2 \end{gathered}\)give me 7 risk factors for heart attack
The seven risk factors for heart attack are Age, Tobacco usage, high blood pressure, high cholesterol level, obesity, diabetes and metabolic syndrome.
Some other risk factors for heart attack are:
Family history of heart attacksNot enough exerciseUnhealthy dietStressIllegal drug useHistory of preeclampsia An autoimmune conditionTo prevent heart attack, one must,
Follow a healthy lifestyleManage other health conditionsTake medications as directedTherefore, the seven risk factors for heart attack are Age, Tobacco usage, high blood pressure, high cholesterol level, obesity, diabetes and metabolic syndrome.
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The moon weighs 7x1022kg and we are about 380,000,000m away from the moon. If you weigh 50kg, how much gravitational force does the moon have on you? (G=6.7x10-¹¹)
The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:
F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².
Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.
The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.
Therefore, we have:
m₁ = 50 kg
m₂ = 7 × 10²² kg
r = 380,000,000 m
G = 6.7 × 10⁻¹¹ N m²/kg²
Substituting these values into the formula, we get:
F = (G × m₁ × m₂) / r²
F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²
F = 1.15 N
Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
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What is the net force on a rock that has a force of 4.9N down and 2.8N up applied to it7.7N up-7.7N down-2.1N down2.1N down
We will have the following:
\(F=4.9N-2.8\Rightarrow F=-2.1N\)So, it will have a force of -2.1 down.
You're driving a vehicle of mass 850 kg and you need to make a turn on a flat road. The radius of curvature of the turn is 80 m. The maximum horizontal component of the force that the road can exert on the tires is only 0.22 times the vertical component of the force of the road on the tires (in this case the vertical component of the force of the road on the tires is , the weight of the car, where as usual 9.8 N/kg, the magnitude of the gravitational field near the surface of the Earth). The factor 0.22 is called the "coefficient of friction" (usually written "", Greek "mu") and is large for surfaces with high friction, small for surfaces with low friction.(a) What is the fastest speed you can drive and still make it around the turn? Invent symbols for the various quantities and solve algebraically before plugging in numbers.
maximum speed = ____ m/s
(b) Which of the following statements are true about this situation?
The net force is nonzero and points away from the center of the kissing circle.The momentum points toward the center of the kissing circle.The net force is nonzero and points toward the center of the kissing circle.The rate of change of the momentum is nonzero and points toward the center of the kissing circle.The centrifugal force balances the force of the road, so the net force is zero.The rate of change of the momentum is nonzero and points away from the center of the kissing circle.
(c) Look at your algebraic analysis and answer the following question. Suppose your vehicle had a mass 3 times as big (5250 kg). Now what is the fastest speed you can drive and still make it around the turn?
maximum speed = ____ m/s
(d) Look at your algebraic analysis and answer the following question. Suppose you have the original 1750 kg vehicle but the turn has a radius twice as large (166 m). What is the fastest speed you can drive and still make it around the turn?
maximum speed = ____m/s
Answer:
(a) v = 13.13 m/s
(b) The centrifugal force balances the force of the road, so net force is zero.
(c) v = 13.13 m/s
(d) v = 18.92 m/s
Explanation:
(a)
To make it around the turn without skidding the frictional force on cat must balance the centrifugal force. Therefore:
Frictional Force = Centrifugal Force
μR = mv²/r
where,
R = Normal Reaction = Weight of Car = mg
Therefore,
μmg = mv²/r
μg = v²/r
v = √μgr
where,
v = maximum possible velocity of car = ?
μ = coefficient of friction = 0.22
g = 9.8 m/s²
r = radius of curvature = 80 m
Therefore,
v = √[(0.22)(9.8 m/s²)(80 m)
v = 13.13 m/s
(b)
In order for the car to move without skidding around the turn, all the forces in horizontal direction must be equal. Hence, the centrifugal force and the frictional force (force of the road) must balance each other. So the true statement is:
The centrifugal force balances the force of the road, so net force is zero.
(c)
v = √μgr
Since the formula for speed is independent of mass. Therefore, the speed will remain same.
v = 13.13 m/s
(d)
v = √μgr
v = √[(0.22)(9.8 m/s²)(166 m)
v = 18.92 m/s
2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times
When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.
The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.
Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:
Mass of air = Mass of filled container - Mass of empty container
= 0.428 kg - 0.419 kg
= 0.009 kg
Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:
Volume of air = Volume of perplex box * Number of times air inside
= 1000 cm³ * 7.2
= 7200 cm³
Convert the volume of air to cubic meters (m³) by dividing by 1000000:
Volume of air = 7200 cm³ / 1000000
= 0.0072 m³
Calculate the density of air using the formula:
Density = Mass / Volume
Density = 0.009 kg / 0.0072 m³
≈ 1.25 kg/m³
Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.
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A horse has a kinetic energy of 29/400 J. If the horse has a mass of 300 kg.
what is the horse's speed?
OA. 98 m/s
OB. 33.1 m/s
O C. 14 m/s
OD. 9.9 m/s
SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?
The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
How to explain tje informationIsaac's force:
Magnitude: 255 N
Angle: 13 degrees North of East
x-component: 255*cos(13) = 245.1 N (Eastward)
y-component: 255*sin(13) = 58.1 N (Northward)
Newton's force:
Magnitude: 156 N
Angle: 34 degrees South of East
x-component: 156*cos(34) = 129.4 N (Westward)
y-component: 156*sin(34) = 86.5 N (Southward)
Now we can add the x- and y-components of the forces to find the net force:
Net force:
x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)
y-component: 58.1 N - 86.5 N = -28.4 N (Southward)
The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
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A plasma is a gas of ionized (charged) particles. When plasma is in motion, magnetic effects "squeeze" its volume, inducing inward pressure known as a pinch. Consider a cylindrical tube of plasma with radius R and length L moving with velocity v along its axis. If there are n ions per unit volume and each ion has charge q , we can determine the pressure felt by the walls of the cylinder.
Required:
a. What is the volume charge density p in terms of n and q?
b. The thickness of the cylinder surface is n^1/3. What is the surface charge density σ in terms of n and q?
Answer:
a
The volume charge density is \(\rho = nq\)
b
The surface charge density is \(\sigma = n^{\frac{2}{3} } q\)
Explanation:
From the question we are told that
The radius is R
The length is L
The velocity is v
The number of ions per unit volume is n
The charge is q
The thickness of the cylinder surface is \(n^{\frac{1}{3} }\)
The volume charge density is mathematically represented as
\(\rho = nq\)
The surface charge density is mathematically represented as
\(\sigma = \rho n^{\frac{1}{3} }\)
substituting for \(\rho\)
\(\sigma = n * n^{\frac{1}{3} } q\)
\(\sigma = n^{\frac{2}{3} } q\)
Which elements are found in all four components of Earth?
Answer:
oxygen silicon aluminun iron
If the universe were to suddenly begin shrinking rather than continue expanding, how would it affect the cosmic microwave background radiation?
A. It would decrease in temperature.
B. It would blue-shift.
C. It would red-shift.
D. It would increase in temperature.
If the universe were to suddenly begin shrinking rather than continuing to expand, it would have a significant effect on the cosmic microwave background radiation (CMB).
The CMB is the afterglow of the Big Bang and is observed as a nearly uniform background radiation in all directions. It is thought to have been emitted when the universe was about 380,000 years old and had cooled enough for neutral atoms to form.
If the universe were to suddenly begin shrinking, the photons in the CMB would lose energy as they travel through the contracting space. This would cause the CMB radiation to shift to shorter wavelengths, which is known as blue-shifting.
Therefore, the correct answer is B. It would blue-shift.
If you had a rock with a volume of 237 ml and a density of 4.52 g/ml how much mass would it have?
Explanation:
Mass = Volume * Density
= 237ml * (4.52g/ml)
= 1071.2g.
Answer:
1071.24
Explanation:
density times volume= mass
237 * 4.52= 1071.24
The apparent weight of a passenger in an elevator is greater than his true weight. Which one of the following is true? The elevator is either moving upward with an increasing speed or moving downward with a decreasing speed. The elevator is either moving upward with a decreasing speed or moving downward with an increasing speed. The elevator is either moving upward with an increasing speed or moving downward with an increasing speed. The elevator is either moving upward with a decreasing speed or moving downward with a decreasing speed. The elevator is either moving upward with an increasing speed or moving upward with a decreasing speed.
Answer:
D
Explanation:
The elevator is either moving upwards with an increasing speed, or moving downwards with a a decreasing speed.
The statement above is true because the direction at which the elevator accelerates, or decelerates(which is negative acceleration anyway), is of paramount importance. If the acceleration is towards the upside, the apparent weight does becomes greater than the true weight. While on the other hand, if the acceleration points towards the downside, then the apparent weight does becomes less than the true weight.
In your own understanding what is psychology?
Answer:
psychology is the science of mind and behavior.psychology is the scientific discipline that studies mental states and processes and behaviour in humans and other animals.Answer:
The study of mind and behavior is known as psychology. Psychology is the scientific study of both conscious and unconscious events, as well as feelings and thoughts. It's a vast academic field that straddles the scientific and social sciences.
Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter
8.27 x 1013 meres is the orbital radius.
Additional details:-Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution
The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.
6.67 x 10⁻¹¹ N/m²kg
2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7
What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.
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g A thin-walled hollow cylinder and a solid cylinder, both have same mass 2.0 kg and radius 20 cm, start rolling down from rest at the top of an incline plane. The height of top of the incline plane is 1.2 m. Find translational speed of each cylinder upon reaching the bottom and determine which cylinder has the greatest translational speed upon reaching the bottom. Moment of inertia of hollow cylinder about its axis passing through the center is mr2 and for solid cylinder mr2/2
Answer:
a. i. 3.43 m/s ii. 2.8 m/s
b. The thin-walled cylinder
Explanation:
a. Find translational speed of each cylinder upon reaching the bottom
The potential energy change of each mass = total kinetic energy gain = translational kinetic energy + rotational kinetic energy
So, mgh = 1/2mv² + 1/2Iω² where m = mass of object = 2.0 kg, g =acceleration due to gravity = 9.8 m/s², h = height of incline = 1.2 m, v = translational velocity of object, I = moment of inertia of object and ω = angular speed = v/r where r = radius of object.
i. translational speed of thin-walled cylinder upon reaching the bottom
So, For the thin-walled cylinder, I = mr², we find its translational velocity, v
So, mgh = 1/2mv² + 1/2Iω²
mgh = 1/2mv² + 1/2(mr²)(v/r)²
mgh = 1/2mv² + 1/2mv²
mgh = mv²
v² = gh
v = √gh
v = √(9.8 m/s² × 1.2 m)
v = √(11.76 m²/s²)
v = 3.43 m/s
ii. translational speed of solid cylinder upon reaching the bottom
So, For the solid cylinder, I = mr²/2, we find its translational velocity, v'
So, mgh = 1/2mv'² + 1/2Iω²
mgh = 1/2mv² + 1/2(mr²/2)(v'/r)²
mgh = 1/2mv'² + mv'²
mgh = 3mv'²/2
v'² = 2gh/3
v' = √(2gh/3)
v' = √(2 × 9.8 m/s² × 1.2 m/3)
v' = √(23.52 m²/s²/3)
v' = √(7.84 m²/s²)
v' = 2.8 m/s
b. Determine which cylinder has the greatest translational speed upon reaching the bottom.
Since v = 3.43 m/s > v'= 2.8 m/s,
the thin-walled cylinder has the greatest translational speed upon reaching the bottom.
What is the force of gravity for a 12 kg turkey?
Please help asap
Answer: 117.6N
Explanation:
By the second Newton's law, we know that:
F = m*a
F = force
m = mass
a = acceleration
We know that in the surface of the Earth, the gravitational acceleration is g = 9.8m/s^2.
Then we just can input that acceleration in the above equation, and also replace m by 12kg, and find that the force due the gravity is:
F = 12kg*9.8m/s^2 = 117.6N
Why do bodies of water tend to moderate temperature swings from day to day?
A: bodies of water reduce insolation
B: The presence of water disrupts the Milankovitch cycle
C: Bodies of water deflect prevailing winds
D: Water has a high heat capacity
pls help
Answer: D: Water has a high heat capacity.
Explanation:
Bodies of water tend to moderate temperature swings from day to day primarily because water has a high heat capacity. Heat capacity refers to the amount of heat energy required to raise the temperature of a substance. Water has a relatively high heat capacity compared to land, meaning it can absorb and store a significant amount of heat energy without experiencing large temperature changes.
During the day, when the sun is shining, bodies of water absorb heat energy from the sunlight. As water has a high heat capacity, it can absorb a considerable amount of heat without experiencing a significant rise in temperature. This absorption of heat helps to keep the surrounding areas relatively cooler, moderating the temperature.
During the night, when the air temperature drops, bodies of water release the stored heat energy back into the atmosphere, which can help to warm up the surrounding areas. This release of heat helps to prevent rapid cooling and keeps the temperature relatively stable.
In contrast, land surfaces have a lower heat capacity, so they heat up and cool down more quickly compared to bodies of water. This is why areas located near bodies of water tend to experience milder and more stable temperatures, with less extreme temperature swings from day to day.
Therefore, the high heat capacity of water is the primary reason why bodies of water tend to moderate temperature swings from day to day.
A child of mass 35 kg sits on the swing as shown. What is the tension in each rope?
a. When throwing a ball vertically upward, my hand moves through a distance of about 1.0 m before the ball leaves my hand. The 0.80 kg ball reaches a maximum height of about 20 m above my hand. while the ball is in my hand after the ball leaves my hand
The required, it experiences a downward force due to gravity and a force due to air resistance.
What is the projectile motion?Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.
Here,
When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.
Learn more about projectile motion here:
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What will happen to an astronaut when the jets produce these four forces