If you combine the relevant equations (Maxwell’s equations, continuity equation for electrons, force equation on electrons) when a magnetic field is present in the zero-order state, one ends up with the following dispersion relation:
ww2p = (w T wc) (w^2 - k^2c^2)

Answer:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

Explanation:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

To determine the longest and shortest pipes in a pipe organ that produce sound within the range of human hearing. Therefore, the shortest pipe in a pipe organ that produces sound at its fundamental frequency within the human hearing range is approximately 17.15 mm long.

λ = v/f

Where:

λ is the wavelength of the sound wave

v is the speed of sound (343 m/s)

f is the frequency of the sound wave

For the longest pipe, we want to find the fundamental frequency (lowest frequency) that corresponds to 20 Hz. Plugging in the values, we have:

λ = (343 m/s) / 20 Hz = 17.15 meters

Therefore, the longest pipe in a pipe organ that produces sound at its fundamental frequency within the human hearing range is approximately 17.15 meters long.

For the shortest pipe, we want to find the fundamental frequency (highest frequency) that corresponds to 20 kHz. Plugging in the values, we have:

λ = (343 m/s) / 20,000 Hz = 0.01715 meters or 17.15 mm

Therefore, the shortest pipe in a pipe organ that produces sound at its fundamental frequency within the human hearing range is approximately 17.15 mm long.

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Explanation:

As temperature increases additional heat energy is applied to the consituent part of a solid which cause additional molecular motion.

Answer:We can use the work-energy principle to find the total work done on the skateboarder between the top and the bottom of the hill. The principle states that the net work done on an object is equal to the change in its kinetic energy:

Net work = ΔKE

where ΔKE is the change in kinetic energy of the object.

The initial kinetic energy of the skateboarder at the top of the hill is:

KEi = 0.5 * m * vi^2 = 0.5 * 60.0 kg * (5.00 m/s)^2 = 750 J

The final kinetic energy of the skateboarder at the bottom of the hill is:

KEf = 0.5 * m * vf^2 = 0.5 * 60.0 kg * (10.0 m/s)^2 = 3000 J

Therefore, the change in kinetic energy is:

ΔKE = KEf - KEi = 3000 J - 750 J = 2250 J

So the net work done on the skateboarder between the top and the bottom of the hill is:

Net work = ΔKE = 2250 J

Therefore, the total work done on the skateboarder between the top and the bottom of the hill is 2250 J.

Explanation:

The total work done on the skateboarder between the top and the bottom of the hill is 2250 J (joules).

To find the total work done on the 60.0-kg skateboarder between the top and the bottom of the hill, we can use the work-energy theorem. The work-energy theorem states that the work done on an object is equal to its change in kinetic energy. Here's a step-by-step explanation:

1. Calculate the initial kinetic energy (KE1) at the top of the hill:
KE1 = 0.5 * mass * (initial velocity)^2
KE1 = 0.5 * 60.0 kg * (5.00 m/s)^2
KE1 = 0.5 * 60.0 kg * 25.0 m^2/s^2
KE1 = 750 J (joules)

2. Calculate the final kinetic energy (KE2) at the bottom of the hill:
KE2 = 0.5 * mass * (final velocity)^2
KE2 = 0.5 * 60.0 kg * (10.0 m/s)^2
KE2 = 0.5 * 60.0 kg * 100.0 m^2/s^2
KE2 = 3000 J (joules)

3. Find the total work done (W) using the work-energy theorem:
W = KE2 - KE1
W = 3000 J - 750 J
W = 2250 J (joules)

Thus, the total work done on the skateboarder is 2250 J (joules).

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Answer:

Generally, a solute dissolves faster in a warmer solvent than it does in a cooler solvent because particles have more energy of movement. For example, if you add the same amount of sugar to a cup of hot tea and a cup of iced tea, the sugar will dissolve faster in the hot tea.

Answer:

1)  energy = 15.6 kWh,  2)    total_cost = $ 2.03

Explanation:

1) The energy dissipated is the product of the power and the time of use In a month it was used t = 6.5 h and the power of the toaster is

P = 2400 W = 2,400 kW

       energy = P  t

       energy = 2,400  6.5

        energy = 15.6  kWh

using rounding to a decimal

        energy = 15.6 kWh

2) The cost of energy is unit_cost = $ 0.13 / kWh

so the total cost

         total_cost = energy    unit_cost

         total_cost = 15.6   0.13

         total_cost = $ 2.028  

rounding to two decimal places

         total_cost = $ 2.03

Answer:

both a and b have same pressure

The question is asking whether it is possible to find a magnetic vector potential for a given uniform surface current flowing in the xy plane and generating a magnetic field for different regions of space.

To determine whether it is possible to find a magnetic vector potential for the given scenario, we need to consider the conditions that must be satisfied. In general, a magnetic vector potential A can be found if the magnetic field B satisfies the condition ∇ × A = B. This is known as the magnetic vector potential equation.

In the given situation, the magnetic field is different for the regions above and below the xy plane. For z > 0, the magnetic field is described as B = MoK -î, and for z < 0, it is described as B = -MoK -î. To find the magnetic vector potential, we need to determine if there exists a vector potential A that satisfies the equation ∇ × A = B in each region.

By calculating the curl of A, we can check if it matches the given magnetic field expressions. If the curl of A matches the magnetic field expressions for both regions, then it is possible to find a magnetic vector potential for the given scenario. However, if the curl of A does not match the magnetic field expressions, then it is not possible to find a magnetic vector potential that satisfies the conditions.

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Answer:

तिकडी एकच

Explanation:

आप सल क्ल वल दन रव दंचंबी एक गम ok plz

The slope of the graph of the equation at the point (20, 2) is 1/8.

To find the slope of the graph of the equation at the given point (20, 2), we need to find the derivative of the equation with respect to x and evaluate it at x = 20. Let's differentiate the equation implicitly:

xy - 9y^2 = 4

To differentiate implicitly, we treat y as a function of x and apply the chain rule. Differentiating both sides of the equation with respect to x:

1 * y + x * dy/dx - 9 * 2y * dy/dx = 0

Simplifying this equation:

y + x * dy/dx - 18y * dy/dx = 0

Grouping the terms with dy/dx:

dy/dx * (x - 18y) = -y

Now, let's solve for dy/dx by dividing both sides by (x - 18y):

dy/dx = -y / (x - 18y)

Substituting the given point (20, 2) into the equation:

dy/dx = -2 / (20 - 18(2))

         = -2 / (20 - 36)

         = -2 / (-16)

         = 1/8

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Answer:

a flow of negatively charged electrons is an

electric current

Answer:

#2

Explanation:

Answer:

A. Speed

Explanation:

Speed is the magnitude of velocity, which is given in the question. Velocity is a vector quantity and therefore has both a magnitude and a direction. Only the former is implied in the question.

Mass is not required

\(\\ \rm\longmapsto W=Fscos\Theta\)

\(\\ \rm\longmapsto W=20(5)cos30\)

\(\\ \rm\longmapsto W=100\times \dfrac{\sqrt{3}}{2}\)

\(\\ \rm\longmapsto W=50\sqrt{3}J\)

Answer:

\(we \: have \\ w = fs \cos( \alpha ) \\ f = 20n \\ m = 2kg \\ s = 5m \\ \alpha = 30 \\ \\ then \: w = 20 \times 5 \times \cos(30) \\ 100 \cos(30) \\ = 100 \frac{ \sqrt{3} }{2} \\ = 50 \sqrt{3} \\ = 86.6 \: joule\\ thank \: yo\)

Answer:

-7.5

Explanation:

edge 2021

The kinematics to find the time to go from the office to the living room is: 2.81 s

Given Parameters

To find

Kinematics allows us to find the relationships between the position, velocity and acceleration of bodies, let's use the relationship  

             x = v₀ t + ½ a t²

Where x is the position, v₀ the initial velocity, at acceleration and t the time

In this case, as he leaves the office, the initial velocity is zero.

           x = ½ a t²

            t = \(\sqrt{\frac{2x}{a} }\)

Let's calculate

           t = \(\sqrt{\frac{2 \ 125}{4} }\)

          t = 2.81 s

In conclusion, using the kinematics, we find that the time to go from the office to the classroom is: 2.81 s

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Answer:

I think it's D!!

cuz protons are in the atoms

(a) the energy in joules of an x-ray photon with wavelength 3.30 ✕ 10−10 m is 6.03 x 10^-16 J.

(b) Convert the energy to electron volts = 3.75 keV

(c) If more penetrating x-rays are desired, should the wavelength be increased or decreased?  decreased

(d) Should the frequency be increased or decreased?   increased

(a) The energy in joules of an x-ray photon with wavelength of 3.30 x 10^-10 m can be calculated using the Planck's equation:

Planck's equation is given by:

E = hf

Where, E = Energy of a photon in Joules h = Planck's constant f = Frequency of the electromagnetic radiation λ = Wavelength of the electromagnetic radiation

Since the question provides the wavelength, we need to calculate the frequency of the electromagnetic radiation.

h = 6.626 x 10^-34 Js, and λ = 3.30 x 10^-10 m

Thus, f = c/λ, where c is the speed of light and is given by c = 3.0 x 10^8 m/s.

Therefore, f = 3 x 10^8/3.30 x 10^-10 = 9.09 x 10^17 Hz

Now, we can calculate the energy of the x-ray photon using Planck's equation.

E = hf = 6.626 x 10^-34 J s × 9.09 × 10^17 Hz= 6.03 x 10^-16 J

Therefore, the energy of the x-ray photon is 6.03 x 10^-16 J.

(b) The energy can be converted to electron volts using the equation:

1 eV = 1.602 x 10^-19 J

Thus, 6.03 x 10^-16 J = 6.03 x 10^-16 / (1.602 x 10^-19) eV = 3753 eV ≈ 3.75 keV

Therefore, the energy of the x-ray photon is approximately 3.75 keV.

(c) If more penetrating x-rays are desired, the wavelength should be decreased. This is because the energy of the x-ray photon is inversely proportional to the wavelength. As the wavelength decreases, the energy of the x-ray photon increases. This means that shorter wavelength x-rays are more energetic and can penetrate more deeply into materials.

(d) The frequency should be increased. This is because the energy of the x-ray photon is directly proportional to the frequency. As the frequency increases, the energy of the x-ray photon increases. Therefore, x-rays with higher frequencies are more energetic and can penetrate more deeply into materials.

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The slowing force of friction due to ice on the given sled on the ice is determined as 40 N.

The slowing force of friction due to ice can be determined by using Newton's second law of motion as follows;

F = ma

where;

F = 100 x 0.4

F = 40 N

Thus, the slowing force of friction due to ice on the given sled on the ice is determined as 40 N.

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Answer:

Once you have drawn the free-body diagram, you can use vector addition to find the net force acting on the object. We will consider three cases as we explore this idea:

Case 1: All forces lie on the same line.

If all of the forces lie on the same line (pointing left and right only, or up and down only, for example), determining the net force is as straightforward as adding the magnitudes of the forces in the positive direction, and subtracting off the magnitudes of the forces in the negative direction. (If two forces are equal and opposite, as is the case with the book resting on the table, the net force = 0)

Example: Consider a 1-kg ball falling due to gravity, experiencing an air resistance force of 5 N. There is a downward force on it due to gravity of 1 kg × 9.8 m/s2 = 9.8 N, and an upward force of 5 N. If we use the convention that up is positive, then the net force is 5 N - 9.8 N = -4.8 N, indicating a net force of 4.8 N in the downward direction.

Case 2: All forces lie on perpendicular axes and add to 0 along one axis.

In this case, due to forces adding to 0 in one direction, we only need to focus on the perpendicular direction when determining the net force. (Though knowledge that the forces in the first direction add to 0 can sometimes give us information about the forces in the perpendicular direction, such as when determining frictional forces in terms of the normal force magnitude.)

Example: A 0.25-kg toy car is pushed across the floor with a 3-N force acting to the right. A 2-N force of friction acts to oppose this motion. Note that gravity also acts downward on this car with a force of 0.25 kg × 9.8 m/s2= 2.45 N, and a normal force acts upward, also with 2.45 N. (How do we know this? Because there is no change in motion in the vertical direction as the car is pushed across the floor, hence the net force in the vertical direction must be 0.) This makes everything simplify to the one-dimensional case because the only forces that don’t cancel out are all along one direction. The net force on the car is then 3 N - 2 N = 1 N to the right.

Case 3: All forces are not confined to a line and do not lie on perpendicular axes.

If we know what direction the acceleration will be in, we will choose a coordinate system where that direction lies on the positive x-axis or the positive y-axis. From there, we break each force vector into x- and y-components. Since motion in one direction is constant, the sum of the forces in that direction must be 0. The forces in the other direction are then the only contributors to the net force and this case has reduced to Case 2.

If we do not know what direction the acceleration will be in, we can choose any Cartesian coordinate system, though it is usually most convenient to choose one in which one or more of the forces lie on an axis. Break each force vector into x- and y-components. Determine the net force in the x direction and the net force in the y direction separately. The result gives the x- and y-coordinates of the net force.

Example: A 0.25-kg car rolls without friction down a 30-degree incline due to gravity.

We will use a coordinate system aligned with the ramp as shown. The free-body diagram consists of gravity acting straight down and the normal force acting perpendicular to the surface.

We must break the gravitational force in to x- and y-components, which gives:

F_{gx} = F_g\sin(\theta)\\ F_{gy} = F_g\cos(\theta)F

gx

​

=F

g

​

sin(θ)

F

gy

​

=F

g

​

cos(θ)

Since motion in the y direction is constant, we know that the net force in the y direction must be 0:

F_N - F_{gy} = 0F

N

​

−F

gy

​

=0

(Note: This equation allows us to determine the magnitude of the normal force.)

In the x direction, the only force is Fgx, hence:

F_{net} = F_{gx} = F_g\sin(\theta) = mg\sin(\theta) = 0.25\times9.8\times\sin(30) = 1.23 \text{ N}F

net

​

=F

gx

​

=F

g

​

sin(θ)=mgsin(θ)=0.25×9.8×sin(30)=1.23 N

Answer:

Velocity = 6.89 m/s

Explanation:

The equation for momentum: \(Momentum=(Mass)(Velocity)\)

Substitute the given information into the equation and solve for velocity.

\(239.5=34.75(Velocity)\\\frac{239.5}{34.75}=\frac{34.75(Velocity)}{34.75\\}\\6.89=Velocity\)

Answer

  96mph

Explanation:

You are given "144 miles in 90 minutes" and what you need to figure out is "144 km in X hours." To go from 90 min to hours, you can do 90 min * 1hr/60min = 1.5 hrs or 144 km in 1.5 hrs or 144 km per 1.5 hours. 144/1.5 = 96.

Answer:

sound is the answer, I'm not sure why I'd think it was because it creates a vacuum

Answer:

sound

Explanation:

Sound travels as waves of energy, but, unlike light, the waves transmit energy by changing the motion of particles.

Sin is the vertical component. So multiply sin 30 and 14. BOOM! You got the answer.

\( \sin(30) \times 14 \: = 7\)

To calculate the power consumed in a parallel circuit with a source voltage of 300 volts and a total circuit current of 4.2 amps, we need to first calculate the total resistance of the circuit.

In a parallel circuit, the total resistance is calculated using the formula:

1/RT = 1/R1 + 1/R2 + 1/R3 + ...

where RT is the total resistance and R1, R2, R3, ... are the individual resistances in the circuit.

Once we have calculated the total resistance, we can use the formula for power:

P = VI

where P is the power, V is the voltage, and I is the current.

So, let's calculate the total resistance:

Assuming we have three resistors R1, R2, and R3 in parallel, with values of 10 ohms, 15 ohms, and 20 ohms respectively, we can calculate the total resistance as:

1/RT = 1/R1 + 1/R2 + 1/R3

1/RT = 1/10 + 1/15 + 1/20

1/RT = 0.3

RT = 3.33 ohms

Now, we can calculate the power consumed in the circuit as:

P = VI

P = 300 * 4.2

P = 1260 watts

Therefore, the power consumed in the parallel circuit with a source voltage of 300 volts and a total circuit current of 4.2 amps, with three resistors in parallel with values of 10 ohms, 15 ohms, and 20 ohms, respectively, is 1260 watts.

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Despite their darkness, their lustrous dark fur coat can make them difficult, if not impossible, to spot. Panthers have small heads, powerful jaws, and emerald green eyes. Their hind legs are often larger and slightly longer than their front legs.

The ability to remain undetected is one of the main ways that panthers differ from other big cats. Panthers hunt at night since they are nocturnal.

Therefore, They can blend in with their surroundings thanks to their dark fur, and their keen eyesight and nose make it easier for them to find their prey.

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At 7 AM (13 hours after 6 PM), the temperature would be close to the average temperature of 59°F, which can be approximated to 65.9°F.

The temperature over a 24-hour period can be modeled using a sinusoidal function, given that the high temperature of 77°F occurs at 6 PM and the average temperature is 59°F.

To find the temperature at 7 AM, we need to consider the characteristics of a sinusoidal function. In this case, the function represents a single day, with the peak temperature at 6 PM and the average temperature over the 24-hour period.

Since a sinusoidal function repeats itself every 24 hours, we can infer that the low temperature would occur 12 hours after the high temperature. Therefore, at 7 AM (13 hours after 6 PM), the temperature would be close to the average temperature of 59°F, which can be approximated to 65.9°F.

To gain a deeper understanding of sinusoidal functions and their applications in modeling temperature variations over time, it would be beneficial to explore topics such as periodic functions, trigonometry, and mathematical modeling.

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Design of a Plywood Membrane Absorber with Resonance Frequencies from 45 to 65 Hz

In this design, we will create a panel absorber using plywood that meets the following criteria: resonance frequencies ranging from 45 to 65 Hz and a maximum extension of 10 inches from its packing surface.

The absorber will effectively dampen sound waves within this frequency range, providing efficient acoustic treatment.

Determine the dimensions: Let's assume a square-shaped plywood panel with a side length of 24 inches.

Calculate the thickness: To achieve the desired resonance frequencies, we can use the formula for the fundamental resonance frequency of a panel absorber:

f = 2000 * (sqrt(t / (L^2 * ρ))),

where f is the frequency in Hz, t is the thickness of the panel in inches, L is the side length in inches, and ρ is the density of the material in lbs/in^3.

Let's set the resonance frequency to 45 Hz:

45 = 2000 * (sqrt(t / (24^2 * ρ)))

Solving for t, we find:

t = (45^2 * 24^2 * ρ) / 2000^2

For a resonance frequency of 65 Hz, the equation would be the same, but with 65 instead of 45.

Material selection: Choose a plywood thickness that satisfies the above equations for both resonance frequencies. Additionally, ensure the plywood does not extend more than 10 inches from its packing surface.

By following the design specifications outlined above, we can create a plywood membrane absorber that meets the required criteria of resonance frequencies ranging from 45 to 65 Hz and a maximum extension of 10 inches from its packing surface.

This design will effectively dampen sound waves within the specified frequency range, providing efficient acoustic treatment.

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